Search Results

Search found 916 results on 37 pages for 'stdio'.

Page 11/37 | < Previous Page | 7 8 9 10 11 12 13 14 15 16 17 18  | Next Page >

• dose not name a type error in c++

  - by user985316

  #include <math.h> #include <stdlib.h> #include <stdio.h> #include <vector> #define IE 40 #define JE 40 #define KE 40 #define ia 7 #define ja 7 #define ka 7 #define NFREQS 3 using namespace std; main() float l,m,n,i,j,k,ic,jc,kc,nsteps,n_pml; float ddx,dt,T,epsz,muz,pi,eaf,npml; int ib,jb,kb; . . . . ic=IE*0.5 ; jc=JE*0.5 ; ....'ic'dose not name a type. ....'jc'dose not name a type.

  Read the article

• problem with the programme!!

  - by hopefulLLl

  kindly tell me what is the pblm with this function wont it help me find the sum of digits of a number?? #include<stdio.h> #include(math.h) void main() { int a,i=0,j=10,k,n=0,m; scanf("%d",&a); while((a%j!=0)&&i>=0) { m=pow(10,(i+1)); k=a%m; n=(a-(k*m)-n)/(m/10)+n; j=m*10; i++; } n=n+(n/(m/10)); printf("%d",n); } i know the parenthesis used with math.h are nt right..what else is the pblm..i need to use just while loop..or the for loop!

  Read the article

• snprintf and Visual Studio 2010

  - by Andrew

  I'm unfortunate enough to be stuck using VS 2010 for a project, and noticed the following code still doesn't build using the non-standards compliant compiler: #include <stdio.h> #include <stdlib.h> int main (void) { char buffer[512]; snprintf(buffer, sizeof(buffer), "SomeString"); return 0; } (fails compilation with the error: C3861: 'snprintf': identifier not found) I remember this being the case way back with VS 2005 and am shocked to see it still hasn't been fixed. Does any one know if Microsoft has any plans to move their standard C libraries into the year 2010?

  Read the article

• why does this code crashes even though everything is perfectly fine?

  - by ashish yadav

  why does this code crashes when executed even though everything is fine? is using strcat illegal on character pointers? #include <stdio.h> #include <string.h> int main() { char *s1 = "Hello, "; char *s2 = "world!"; char *s3 = strcat(s1, s2); printf("%s",s3); return 0; } it should work fine but it isn't. please give a proper way with referring to both array and pointers.

  Read the article

• Data loss between conversion

  - by Alex Brooks

  Why is it that I loose data between the conversions below even though both types take up the same amount of space? If the conversion was done bitwise, it should be true that x = z unless data is being stripped during the conversion, right? Is there a way to do the two conversions without losing data (i.e. so that x = z)? main.cpp: #include <stdio.h> #include <stdint.h> int main() { double x = 5.5; uint64_t y = static_cast<uint64_t>(x); double z = static_cast<double>(y) // Desire : z = 5.5; printf("Size of double: %lu\nSize of uint64_t: %lu\n", sizeof(double), sizeof(uint64_t)); printf("%f\n%lu\n%f\n", x, y, z); } Results: Size of double: 8 Size of uint64_t: 8 5.500000 5 5.000000

  Read the article

• Include headers in header file?

  - by Mohit Deshpande

  I have several libraries made by myself (a geometry library, a linked list library, etc). I want to make a header file to include them all in one lib.h. Could I do something like this: #ifndef LIB_H_ #define LIB_H_ #include <stdio.h> #include <stdlib.h> #include <linkedlist.h> #include <geometry.h> .... #endif Then I could just reference this one library and actually reference multiple libraries. Is this possible? If not, is there a way around it?

  Read the article

• checking whether 4 points in a plane define a square ??

  - by osabri

  how to check whether 4 points in the plane define a square? what's the function which given a point and a value of the area of a square as input parameters returns four squares(define a corresponding type) with sides parallel to the x axis and y axis this how i start: #include <stdio.h> #include<math.h> struct point{ float x; float y; } typedef struct point POINT; struct square{ struct point p1; struct point p2; struct point p3; struct point p4; } typedef struct square SQUARE; int main() { int point; printf("point coordinate"); printf("\n\n"); printf("enter data\n");

  Read the article

• C: Incompatible types?

  - by Airjoe

  #include <stdlib.h> #include <stdio.h> struct foo{ int id; char *bar; char *baz[6]; }; int main(int argc, char **argv){ struct foo f; f.id=1; char *qux[6]; f.bar=argv[0]; f.baz=qux; // Marked line return 1; } This is just some test code so ignore that qux doesn't actually have anything useful in it. I'm getting an error on the marked line, incompatible types when assigning to type ‘char *[6]’ from type ‘char **’ but both of the variables are defined as char *[6] in the code. Any insight?

  Read the article

• C++: Best text accumulator

  - by MInner

  Text gets accumulates piecemeal before being sent to client. Now we use own class that allocates memory for each piece as char massive. (Anyway, works like char[][] + std::list<char*>). Then we build the whole string, convert it into std::sting and then create boost::asio::streambuf using it. That's slow enough, I assume. Correct me if I'm wrong. I know, in many cases simple FILE type from stdio.h is used. How does it works? Allocates memory at every write into it. So, is it faster and is there any way to read into boost::asio::streambuf from FILE?

  Read the article

• Why freed struct in C still has data?

  - by kliketa

  When I run this code: #include <stdio.h> typedef struct _Food { char name [128]; } Food; int main (int argc, char **argv) { Food *food; food = (Food*) malloc (sizeof (Food)); snprintf (food->name, 128, "%s", "Corn"); free (food); printf ("%d\n", sizeof *food); printf ("%s\n", food->name); } I still get 128 Corn although I have freed food. Why is this? Is memory really freed?

  Read the article

• Linux c++ error: undefined reference to 'dlopen'

  - by lerax

  Hi all! I work in Linux with c++ (eclipse) and want to use a library. Eclipse shows me an error: undefined reference to 'dlopen' Do you know a solution? Here is my code. #include <stdlib.h> #include <stdio.h> #include <dlfcn.h> int main(int argc, char **argv) { void *handle; double (*desk)(char*); char *error; handle = dlopen ("/lib/CEDD_LIB.so.6", RTLD_LAZY); if (!handle) { fputs (dlerror(), stderr); exit(1); } desk= dlsym(handle, "Apply"); if ((error = dlerror()) != NULL) { fputs(error, stderr); exit(1); } dlclose(handle); }

  Read the article

• Can this example be done with pointers instead of global variable?

  - by Louise

  This is a simplified example of the problem I have: #include <stdio.h> #include <stdlib.h> void f2(int** a) { printf("a: %i\n", **a); } void f1(int* a) { f2(&a); } int main() { int a = 3; f1(&a); // prints "a: 3" f2(???); return 0; } The problem is that I would like to be able to use f2() both in main() and in f1(). Can that be done without using global variables?

  Read the article

• Why do i get segfault at the end of the application after everything's been done properly ?

  - by VaioIsBorn

  #include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char pass[] = "m4ak47"; printf("Vnesi password: \t"); scanf("%s", stole); if(strncmp(stole, pass, sizeof(pass)) != 0) { printf("wrong password!\n"); exit(0); } else printf("Password correct\n"); printf("some stuf here...\n\n"); return 0; } This program is working nice, but with one problem - if the password is correct then it DOES do the printing of 'some stuf here...' but it also shows me segmentation fault error at the end. Why ?

  Read the article

• C: switch case with logical operator

  - by Er Avinash Singh

  While I am new to c and want help in this program my code is : #include<stdio.h> #include<conio.h> void main(){ int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in turbo c and it shows no error and the output is helloI thought somebody Please, let me know how is this working ??? note :- here break is not the case as I intentionally left them.

  Read the article

• Behavior with primitive data types' value out of range & C99's PRI* macros

  - by Yktula

  Say we have an 8-bit unsigned integer n (UINT8_MAX=255); what is the behavior of the compiler for n=256? Where can I find a table of default behavior when the value of a data type is out of range for different data types? Is there a pattern to how they behave when set out of range? #include <stdio.h> #include <inttypes.h> uint8_t n = UINT8_MAX; int main() { printf("%hhu ",n++); printf("%hhu",n); return 0; } Compiling with gcc -std=c99 -Wall *.c, this prints: 255 0 Also, is it acceptable to use C99's PRI* macros? How are they named?

  Read the article

• About This Code

  - by the-ifl

  Hi Guys , well I have a simple and a stupid question !! in this code what is the role of the symbol "%3d"...I Now That % mean refer To Variable ...... This is The Code : #include <stdio.h> int main(void) { int t, i, num[3][4]; for(t=0; t<3; ++t) for(i=0; i<4; ++i) num[t][i] = (t*4)+i+1; /* now print them out */ for(t=0; t<3; ++t) { for(i=0; i<4; ++i) printf("%3d ", num[t][i]); printf("\n"); } return 0; }

  Read the article

• When should an array name be treated as a pointer and when does it just represent the array itself? [duplicate]

  - by user1087373

  This question already has an answer here: When is an array name or a function name 'converted' into a pointer ? (in C) 4 answers I just made a test program after reading the book and the result turned out confusing: #include <stdio.h> int main(void) { char text[] = "hello!"; printf("sizeof(text):%d sizeof(text+2):%d sizeof(text[0]):%d \n",(int)sizeof(text), sizeof(text+2), sizeof(text[0])); printf("text:%p sizeof(text):%d &text:%p sizeof(&text):%d \n",text, sizeof(text), &text, sizeof(&text)); printf("text+1:%p &text+1:%p \n", text+1, &text+1); return 0; } The result: sizeof(text):7 sizeof(text+2):4 sizeof(text[0]):1 text:0xbfc8769d sizeof(text):7 &text:0xbfc8769d sizeof(&text):4 text+1:0xbfc8769e &text+1:0xbfc876a4 What makes me feel confused are: why the value of 'sizeof(text)' is 7 whereas 'sizeof(text+2)' is 4 what's the difference between 'text' and '&text'?

  Read the article

• Printf is not printing anything to output? C++ SDL

  - by Qasim

  I am trying to use "printf" in my Visual C++ project however it is not working. Using Lazy Foo's tutorial, I set up SDL in my project, but when I play it, printf doesnt do anything. #include "SDL.h" #include <stdio.h> int main( int argc, char* args[] ) { printf("Testing"); return 0; } The output looks like this: The program '[4664] SDL Testing.exe: Native' has exited with code 0 (0x0). And that's about it. What could be wrong?

  Read the article

• WinMain not called before main (C/C++ Program Entry Point Issue)

  - by BT

  I was under the impression that this code #include <windows.h> #include <stdio.h> int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine, int iCmdShow) { printf("WinMain\n"); return 0; } int main() { printf("main\n"); return 0; } would output WinMain, but of course nothing ever works how you expects. Anyways, could somebody please tell me how to get this program to run WinMain first (I do have a reason for using both). I'm running windows 7 with mingw if that helps anything.

  Read the article

• Why would I get a bus error or segmentation fault when calling free() normally?

  - by chucknelson

  I have a very simple test program, running on Solaris 5.8: #include <stdio.h> #include <stdlib.h> int main(void) { char *paths; paths = getenv("PATH"); printf("Paths: %s\n", paths); free(paths); // this causes a bus error return 0; } If I don't call free() at the end, it displays the message fine and exits. If I include the free() call, it crashes with a bus error. I've had other calls to free(), in other programs, cause segmentation faults as well. Even if I allocate the memory for *paths myself, free() will cause a bus error. Is there some reason trying to free up the memory is causing a crash?

  Read the article

• Lua - initializing

  - by Ockonal

  Hello, I can't init lua correctly under Arch Linux. Lua - latest version. Here is my code: #include <stdio.h> extern "C" { #include <lua.h> #include <lauxlib.h> #include <lualib.h> } int main() { lua_State *luaVM = luaL_newstate(); if (luaVM == NULL) { printf("Error initializing lua!\n"); return -1; } luaL_openlibs(luaVM); lua_close(luaVM); return 0; } /tmp/cc0iJ6lW.o: In function main': test_lua.cpp:(.text+0xa): undefined reference toluaL_newstate' test_lua.cpp:(.text+0x34): undefined reference to `luaL_openlibs' test_lua.cpp:(.text+0x40): undefined reference to `lua_close' collect2: ld returned 1 exit status What's wrong?

  Read the article

• Avoid incompatible pointer warning when dealing with double-indirection

  - by fnawothnig

  Assuming this program: #include <stdio.h> #include <string.h> static void ring_pool_alloc(void **p, size_t n) { static unsigned char pool[256], i = 0; *p = &pool[i]; i += n; } int main(void) { char *str; ring_pool_alloc(&str, 7); strcpy(str, "foobar"); printf("%s\n", str); return 0; } ... is it possible to somehow avoid the GCC warning test.c:12: warning: passing argument 1 of ‘ring_pool_alloc’ from incompatible pointer type test.c:4: note: expected ‘void **’ but argument is of type ‘char **’ ... without casting to (void**) (or simply disabling the compatibility checks)? Because I would very much like to keep compatibility warnings regarding indirection-level...

  Read the article

• How does this iterative Tower of Hanoi work? C

  - by Nitesh Panchal

  Hello, while surfing google, i found this interesting solution to Tower Of Hanoi which doesn't even use stack. Can anybody explain me in brief, what is it actually doing? And this solution really acceptable? #include <stdio.h> #include <stdlib.h> int main() { int n, x; printf( "How many disks? " ); scanf( "%d", &n ); printf("\n"); for (x=1; x < (1 << n); x++) printf( "move from tower %i to tower %i.\n", (x&x-1)%3, ((x|x-1)+1)%3 ); return 0; }

  Read the article

• Question about variable definitions in functions.

  - by Kaan Tekelioglu

  Hi. #include <stdio.h> main() { int a; for(a=1; a<=4 && printf("%d ",a); a++) { int a; static int b=a; printf("%d ",(a++)-b); } getchar(); getchar(); } In this code, the printout is 1 0 2 1 3 2 4 3. I understand why the int a; part works differently then the int a which was defined outside the for function, and why static int b; is only defined once with the primary value of a ; but why does the (a++) part in printf affect proceeding values of a? Don't we redefine int a; each time the for function runs? Thanks in advance.

  Read the article

• emacs/Python: running python-shell in line buffered vs. block buffered mode

  - by Begbie00

  Hi all - In a related question and answer here, someone hypothesized that python-shell within emacs(23.2) was block-buffered instead of line-buffered. The recommended fix was to add sys.stdout.flush() to the spot in my script where I want stdio to flush its contents to the python-shell. Is there someway to trick python-shell (running in emacs 23.2 on Windows, not Linux) into either a) thinking it's attached to a TTY or b) using line-buffered instead of block-buffered mode? I don't see why I'd be able to do this in IDLE but not emacs. I'd rather customize emacs than add sys.stdout.flush() throughout my scripts. Call me lazy :-). Thanks, Mike

  Read the article

< Previous Page | 7 8 9 10 11 12 13 14 15 16 17 18  | Next Page >