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  • reading a string with spaces with sscanf

    - by SDLFunTimes
    For a project I'm trying to read an int and a string from a string. The only problem is sscanf appears to break reading an %s when it sees a space. Is there anyway to get around this limitation? Here's an example of what I'm trying to do: #include<stdio.h> #include<stdlib.h> int main(int argc, char** argv) { int age; char* buffer; buffer = malloc(200 * sizeof(char)); sscanf("19 cool kid", "%d %s", &age, buffer); printf("%s is %d years old\n", buffer, age); return 0; } What it prints is: "cool is 19 years old" where I need "cool kid is 19 years old". Does anyone know how to fix this?

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  • Why unsigned int contained negative number

    - by Daziplqa
    Hi All, I am new to C, What I know about unsigned numerics (unsigned short, int and longs), that It contains positive numbers only, but the following simple program successfully assigned a negative number to an unsigned int: 1 /* 2 * ===================================================================================== 3 * 4 * Filename: prog4.c 5 * 6 * ===================================================================================== 7 */ 8 9 #include <stdio.h> 10 11 int main(void){ 12 13 int v1 =0, v2=0; 14 unsigned int sum; 15 16 v1 = 10; 17 v2 = 20; 18 19 sum = v1 - v2; 20 21 printf("The subtraction of %i from %i is %i \n" , v1, v2, sum); 22 23 return 0; 24 } The output is : The subtraction of 10 from 20 is -10

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  • gcc does not generate debugger info when using -g, -ggdb, -g3, or -ggdb3

    - by CJJ
    I'm using GCC 4.4.1 and GDB 7.0-ubuntu on Ubuntu 9.10. However, GCC won't generate debugger info when using any of the following switches: -g, -g3, -ggdb, or -ggdb3. So when I run the program with GDB, its as if there was no debugger information generated. I have created very simple test source files in a new, empty folder. Here is one example: #include <stdlib.h> #include <stdio.h> int main (int argc, char **argv) { char msg[4]; // allocate 4 bytes on the stack strcpy (msg, "hello world"); // overflow printf ("%s\n", msg); return 0; }

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  • Something is wrong with this C code to reverse string, but I dont know what ? please help

    - by Harbhag
    Hi all, I am beginnner to programming. I wrote this little program to reverse a string. But if I try to reverse a string which is less than 5 characters long then it gives wrong output. I cant seem to find whats wrong. #include<stdio.h> #include<string.h> int main() { char test[50]; char rtest[50]; int i, j=0; printf("Enter string : "); scanf("%s", test); int max = strlen(test) - 1; for ( i = max; i>=0; i--) { rtest[j] = test[i]; j++; } printf("Reversal is : %s\n", rtest); return 0; }

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  • how to check if there is a division by zero in c

    - by user244775
    #include<stdio.h> void function(int); int main() { int x; printf("Enter x:"); scanf("%d", &x); function(x); return 0; } void function(int x) { float fx; fx=10/x; if(10 is divided by zero)// I dont know what to put here please help printf("division by zero is not allowed"); else printf("f(x) is: %.5f",fx); }

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  • flex and bison: wrong output

    - by user2972227
    I am doing a homework using flex and bison to make a complex number calculator. But my program cannot give a correct output. .lex file: %option noyywrap %{ #include<stdio.h> #include<stdlib.h> #include "complex_cal.h" #define YYSTYPE complex #include "complex_cal.tab.h" void RmWs(char* str); %} /* Add your Flex definitions here */ /* Some definitions are already provided to you*/ ws [ \t]+ digits [0-9] number (0|[1-9]+{digits}*)\.?{digits}* im [i] complexnum {ws}*[-]*{ws}*{number}{ws}*[+|-]{ws}*{number}{ws}*{im}{ws}* op [-+*/()] %% {complexnum} {RmWs(yytext); sscanf(yytext,"%lf %lf",&(yylval.real),&(yylval.img)); return CNUMBER;} {ws} /**/ {op} return *yytext; %% /* function provided to student to remove */ /* all the whitespaces from a string. */ void RmWs(char* str){ int i=0,j=0; char temp[strlen(str)+1]; strcpy(temp,str); while (temp[i]!='\0'){ while (temp[i]==' '){i++;} str[j]=temp[i]; i++; j++; } str[j]='\0'; } .y file: %{ #include <stdio.h> #include <stdlib.h> #include "complex_cal.h" /* prototypes of the provided functions */ complex complex_add (complex, complex); complex complex_sub (complex, complex); complex complex_mul (complex, complex); complex complex_div (complex, complex); /* prototypes of the provided functions */ int yylex(void); int yyerror(const char*); %} %token CNUMBER %left '+' '-' %left '*' '/' %nonassoc '(' ')' %% /* start: Add your grammar rules and actions here */ complexexp: complexexp '+' complexexpmultidiv {$$=complex_add($1, $3);} | complexexp '-' complexexpmultidiv {$$=complex_sub($1, $3);} | complexexpmultidiv {$$.real=$1.real;$$.img=$1.img;} ; complexexpmultidiv: complexexpmultidiv '*' complexsimple {$$=complex_mul($1, $3);} | complexexpmultidiv '/' complexsimple {$$=complex_div($1, $3);} | complexsimple {$$.real=$1.real;$$.img=$1.img;} ; complexsimple: '(' complexexp ')' {$$.real=$2.real;$$.img=$2.img;} | '(' CNUMBER ')' {$$.real=$2.real;$$.img=$2.img;} ; /* end: Add your grammar rules and actions here */ %% int main(){ return yyparse(); } int yyerror(const char* s){ printf("%s\n", s); return 0; } /* function provided to do complex addition */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of addition in c3 */ complex complex_add (complex c1, complex c2){ /* c1 + c2 */ complex c3; c3.real = c1.real + c2.real; c3.img = c1.img + c2.img; return c3; } /* function provided to do complex subtraction */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of subtraction in c3 */ complex complex_sub (complex c1, complex c2){ /* c1 - c2 */ complex c3; c3.real = c1.real - c2.real; c3.img = c1.img - c2.img; return c3; } /* function provided to do complex multiplication */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of multiplication in c3 */ complex complex_mul (complex c1, complex c2){ /* c1 * c2 */ complex c3; c3.real = c1.real*c2.real - c1.img*c2.img; c3.img = c1.img*c2.real + c1.real*c2.img; return c3; } /* function provided to do complex division */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of c1/c2 in c3 */ complex complex_div (complex c1, complex c2){ /* c1 / c2 (i.e. c1 divided by c2 ) */ complex c3; double d; /*divisor calculation using the conjugate of c2*/ d = c2.real*c2.real + c2.img*c2.img; c3.real = (c1.real*c2.real + c1.img*c2.img)/d; c3.img = (c1.img*c2.real - c1.real*c2.img)/d; return c3; } .h file: #include <string.h> /* struct for holding a complex number */ typedef struct { double real; double img; } complex; /* define the return type of FLEX */ #define YYSTYPE complex Script for compiling the file: bison -d -v complex_cal.y flex -ocomplex_cal.lex.yy.c complex_cal.lex gcc -o complex_cal complex_cal.lex.yy.c complex_cal.tab.c ./complex_cal Some correct sample run of the program: input:(5+6i)*(6+1i) output:24.000000+41.000000i input:(7+8i)/(-3-4i)*(5+7i) output:-11.720000-14.040000i input:(7+8i)/((-3-4i)*(5+7i)) output:-0.128108+0.211351i But when I run this program, the program only give an output which is identical to my input. For example, when I input (5+6i)(6+1i), it just gives (5+6i)(6+1i). Even if I input any other things, for example, input "abc" it just gives "abc" and is not syntax error. I don't know where the problem is and I hope to know how to solve it.

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  • array iteration strstr in c

    - by lex0273
    I was wondering if it's safe to do the following iteration to find the first occurrence of str within the array or if there is a better way. Thanks #include <stdio.h> #include <string.h> const char * list[] = {"One","Two","Three","Four","Five"}; char *c(char * str) { int i; for (i = 0; i < 5; i++) { if (strstr(str, list[i]) != NULL) return list[i]; } return "Not Found"; } int main() { char str[] = "This is a simple string of hshhs wo a char"; printf("%s", c(str)); return 0; }

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  • error: ‘struct mcontext_t’ has no member named ‘eip’

    - by user353573
    original is struct sigcontext *sc; after changing to struct mcontext_t, error occur. How to fix it? error: ‘struct mcontext_t’ has no member named ‘eip’ #include <stdio.h> #include <signal.h> #include <asm/ucontext.h> static unsigned long target; void handler(int signum, siginfo_t *siginfo, void *uc0){ struct ucontext *uc; mcontext_t *sc; uc = (struct ucontext *)uc0; sc = &uc->uc_mcontext; sc->eip = target; }

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  • How to format a function pointer?

    - by Longpoke
    Is there any way to print a pointer to a function in ANSI C? Of course this means you have to cast the function pointer to void pointer, but it appears that's not possible?? #include <stdio.h> int main() { int (*funcptr)() = main; printf("%p\n", (void* )funcptr); printf("%p\n", (void* )main); return 0; } $ gcc -ansi -pedantic -Wall test.c -o test test.c: In function 'main': test.c:6: warning: ISO C forbids conversion of function pointer to object pointer type test.c:7: warning: ISO C forbids conversion of function pointer to object pointer type $ ./test 0x400518 0x400518 It's "working", but non-standard...

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  • gcov and switch statements

    - by Matt
    I'm running gcov over some C code with a switch statement. I've written test cases to cover every possible path through that switch statement, but it still reports a branch in the switch statement as not taken and less than 100% on the "Taken at least once" stat. Here's some sample code to demonstrate: #include "stdio.h" void foo(int i) { switch(i) { case 1:printf("a\n");break; case 2:printf("b\n");break; case 3:printf("c\n");break; default: printf("other\n"); } } int main() { int i; for(i=0;i<4;++i) foo(i); return 0; } I built with "gcc temp.c -fprofile-arcs -ftest-coverage", ran "a", then did "gcov -b -c temp.c". The output indicates eight branches on the switch and one (branch 6) not taken. What are all those branches and how do I get 100% coverage?

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  • Embedding binary blobs using gcc mingw

    - by myforwik
    I am trying to embed binary blobs into an exe file. I am using mingw gcc. I make the object file like this: ld -r -b binary -o binary.o input.txt I then look objdump output to get the symbols: objdump -x binary.o And it gives symbols named: _binary_input_txt_start _binary_input_txt_end _binary_input_txt_size I then try and access them in my C program: #include <stdlib.h> #include <stdio.h> extern char _binary_input_txt_start[]; int main (int argc, char *argv[]) { char *p; p = _binary_input_txt_start; return 0; } Then I compile like this: gcc -o test.exe test.c binary.o But I always get: undefined reference to _binary_input_txt_start Does anyone know what I am doing wrong?

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  • how to compile a program with gtkmozembed.h

    - by ganapati hegde
    Hi, i have written a program under ubuntu, in which i include gtkmozembed.h. I am facing a problem in compiling the program.Below is the simplest form of a program which uses gtkmozembed. #include <gtk/gtk.h> #include <stdio.h> #include <gtkmozembed.h> int main(){ GtkWidget *mozEmbed; mozEmbed = gtk_moz_embed_new(); return 0; } Eventhough, the above program is doing nothing, compiling that program is a lot for me... I am trying to comile the above program like below gcc `pkg-config --libs --cflags gtk+-2.0` test.c -o test and it is giving the following error... error: gtkmozembed.h: No such file or directory I can understand, something else has to be added to the above gcc line,so that the compiler can find the gtkmozembed.h, but not getting what is that, 'something'...Looking for someone's help..Thank you...

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  • 0 not a valid FILE* when provided as a template argument

    - by Seva Alekseyev
    The following code #include <stdio.h> template <typename T, T v> class Tem { T t; Tem() { t = v; } }; typedef Tem<FILE*,NULL> TemFile; when compiled in a .mm file (Objective C++) by Xcode on MacOS X, throws the following error: error: could not convert template argument '0' to 'FILE*'. What's going on, please? The code in question compiled fine under MSVC. Since when is the 0 constant not a valid pointer to anything? Is this an artifact of Objective C++ (as opposed to vanilla C++)?

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  • C: How come an array's address is equal to its value?

    - by Alexandre
    In the following bit of code, pointer values and pointer addresses differ as expected. But array values and addresses don't! How can this be? Output my_array = 0022FF00 &my_array = 0022FF00 pointer_to_array = 0022FF00 &pointer_to_array = 0022FEFC ... #include <stdio.h> int main() { char my_array[100] = "some cool string"; printf("my_array = %p\n", my_array); printf("&my_array = %p\n", &my_array); char *pointer_to_array = my_array; printf("pointer_to_array = %p\n", pointer_to_array); printf("&pointer_to_array = %p\n", &pointer_to_array); printf("Press ENTER to continue...\n"); getchar(); return 0; }

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  • How do you printf an unsigned long long int?

    - by superjoe30
    #include <stdio.h>int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt); return 0;} Output: My number is 8 bytes wide and its value is 285212672l. A normal number is 0. I assume this unexpected result is from printing the unsigned long long int. How do you printf an unsigned long long int?

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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Why does gcc add symbols to non-debug build?

    - by Matt Holgate
    When I do a release build with gcc (i.e. I do not specify -g), I still seem to end up with symbols in the binary, and have to use strip to remove them. In fact, I can still breakpoint functions and get backtraces in gdb (albeit without line numbers). This surprised me - can anyone explain why this happens? e.g. #include <stdio.h> static void blah(void) { printf("hello world\n"); } int main(int argc, char *argv[]) { blah(); return 0; } gcc -o foo foo.c nm foo | grep blah: 08048374 t blah

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  • Linker library for OpenMP for Snow Leopard?

    - by unknownthreat
    Currently, I am trying out OpenMP on XCode 3.2.2 on Snow Leopard: #include <omp.h> #include <iostream> #include <stdio.h> int main (int argc, char * const argv[]) { #pragma omp parallel printf("Hello from thread %d, nthreads %d\n", omp_get_thread_num(), omp_get_num_threads()); return 0; } I didn't include any linking libraries yet, so the linker complains: "_omp_get_thread_num", referenced from: _main in main.o "_omp_get_num_threads", referenced from: _main in main.o OK, fine, no problem, I take a look in the existing framework, looking for keywords such as openmp or omp... here comes the problem, where is the linking library? Or should I say, what is the name of the linking library for openMP? Is it dylib, framework or what? Or do I need to get it from somewhere first?

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  • Long Double in C

    - by reubensammut
    I've been reading the C Primer Plus book and got to this example #include <stdio.h> int main(void) { float aboat = 32000.0; double abet = 2.14e9; long double dip = 5.32e-5; printf("%f can be written %e\n", aboat, aboat); printf("%f can be written %e\n", abet, abet); printf("%f can be written %e\n", dip, dip); return 0; } After I ran this on my macbook I was quite shocked at the output: 32000.000000 can be written 3.200000e+04 2140000000.000000 can be written 2.140000e+09 2140000000.000000 can be written 2.140000e+09 So I looked round and found out that the correct format to display long double is to use %Lf. However I still can't understand why I got the double abet value instead of what I got when I ran it on Cygwin, Ubuntu and iDeneb which is roughly -1950228512509697486020297654959439872418023994430148306244153100897726713609 013030397828640261329800797420159101801613476402327600937901161313172717568.0 00000 can be written 2.725000e+02 Any ideas?

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  • nul terminating a int array

    - by robUK
    Hello, gcc 4.4.4 c89 I was just experimenting with a int array. And something just came to my mind. Can I nul terminate it. For example, I am using a 0 to nul terminate. However, 0 could well be a valid value in this array. The code below will terminate after the 5. Even though I mean 0 to be a valid number. However, I could specify the size of the array. But in this case, I don't want to this as I am just interested in this particular problem. Many thanks for any advice, #include <stdio.h> static void test(int *p); int main(void) { int arr[] = {30, 450, 14, 5, 0, 10, '\0'}; test(arr); return 0; } static void test(int *p) { while(*p) { printf("Array values [ %d ]\n", *p++); } }

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  • undefined C struct forward declaration

    - by robUK
    Hello, I have a header file port.h, port.c, and my main.c I get the following error: 'ports' uses undefined struct 'port_t' I thought as I have declared the struct in my .h file and having the actual structure in the .c file was ok. I need to have the forward declaration as I want to hide some data in my port.c file. In my port.h I have the following: /* port.h */ struct port_t; port.c: /* port.c */ #include "port.h" struct port_t { unsigned int port_id; char name; }; main.c: /* main.c */ #include <stdio.h> #include "port.h" int main(void) { struct port_t ports; return 0; } Many thanks for any suggestions,

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  • Logic differences in C and Java

    - by paragjain16
    Compile and run this code in C #include <stdio.h> int main() { int a[] = {10, 20, 30, 40, 50}; int index = 2; int i; a[index++] = index = index + 2; for(i = 0; i <= 4; i++) printf("%d\n", a[i]); } Output : 10 20 4 40 50 Now for the same logic in Java class Check { public static void main(String[] ar) { int a[] = {10, 20, 30, 40, 50}; int index = 2; a[index++] = index = index + 2; for(int i = 0; i <= 4; i++) System.out.println(a[i]); } } Output : 10 20 5 40 50 Why is there output difference in both languages, output is understandable for Java but I cannot understand output in C One more thing, if we apply the prefix ++ operator, we get the same result in both languages, why?

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  • Why am I not getting the expected results with fread() in C?

    - by mauvehead
    Here is my code: #include <stdio.h> int main(void) { FILE *fp; unsigned int i; char bytes[512]; fp = fopen("myFile","r"); for(i = 0;i <= 512;i++) { fread(&bytes, sizeof(bytes), 1, fp); printf("bytes[%d]: %x\n", i, bytes[i]); } } Here is the expected output $ hexdump myFile 0000000 aa55 aa55 0060 0000 0a17 0000 b1a5 a2ea 0000010 0000 0000 614c 7563 616e 0000 0000 0000 0000020 0000 0000 0a68 0000 1001 421e 0000 0000 0000030 f6a0 487d ffff ffff 0040 0000 002f 0000 But here is what I see from my program bytes[0]: 55 bytes[1]: 8 bytes[2]: ffffffc8 bytes[3]: ffffffdd bytes[4]: 22 bytes[5]: ffffffc8 bytes[6]: ffffff91 bytes[7]: 63 bytes[8]: ffffff82 My obvious guess is that I'm either addressing something incorrectly and receiving the wrong data back or I am printing it incorrectly and viewing it the wrong way.

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  • for loop in #define

    - by hspim
    #include <stdio.h> #define UNITS {'*', '#', '%', '!', '+', '$', '=', '-'} #define PrintDigit(c, d) (for (i=0; i < c ; i++)putchar(unit[d]);) char unit[] = UNITS; //void PrintDigit(c, element) { // int i; // for (i=0; i < c ; i++) // putchar(unit[element]); //} int main( ) { int i, element=4; PrintDigit(10, element); putchar('\n'); return 0; } I have the function here PrintDigit() which works as expected. When attempting to turn the function into a #define however gcc keeps throwing a syntax error on the for loop. Any idea what the problem is?

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  • long integer problem

    - by hopefulLLl
    hello friends,, m a beginner at c language.. m using turbo c ++ compiler 16 bit. nw the max answer obtained by me is aaround 32000.. nw if i want a number larger that that then i use long int.. if i execute the following programme.. #include <stdio.h> void main() { long int x; x=40000; printf("%d", x); } then i get error that constant value is long in function main().. kindly tell me how to get an answer more that 32000 by getting rid of this error! thnx..

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