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Search found 916 results on 37 pages for 'stdio'.

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  • Strange behaviour with fputs and a loop.

    - by Jonathan
    When running the following code I get no output but I cannot work out why. # include <stdio.h> int main() { fputs("hello", stdout); while (1); return 0; } Without the while loop it works perfectly but as soon as I add it in I get no output. Surely it should output before starting the loop? Is it just on my system? Do I have to flush some sort of buffer or something? Thanks in advance.

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  • static, define, and const in C

    - by yCalleecharan
    Hi, I've read that static variables are used inside function when one doesn't want the variable value to change/initialize each time the function is called. But what about defining a variable static in the main program before "main" e.g. #include <stdio.h> static double m = 30000; int main(void) { value = m * 2 + 3; } Here the variable m has a constant value that won't get modified later in the main program. In the same line of thought what difference does it make to have these instead of using the static definition: const double m = 30000; or #define m 30000 //m or M and then making sure here to use double operations in the main code so as to convert m to the right data type. Thanks a lot...

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  • WinMain not called before main (C/C++ Program Entry Point Issue)

    - by BT
    I was under the impression that this code #include <windows.h> #include <stdio.h> int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance, PSTR szCmdLine, int iCmdShow) { printf("WinMain\n"); return 0; } int main() { printf("main\n"); return 0; } would output WinMain, but of course nothing ever works how you expects. Anyways, could somebody please tell me how to get this program to run WinMain first (I do have a reason for using both). I'm running windows 7 with mingw if that helps anything.

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  • Why the output for "a" is -80?

    - by Abhi
    #include<stdio.h> #include<conio.h> #define ABC 20 #define XYZ 10 #define XXX ABC - XYZ void main() { int a; a = XXX * 10; printf("\n %d \n", a); getch(); } I thought the output should be 100 but when i saw the result i found o/p as -80. when i put bracket as #define XXX (ABC-XYZ) then i get output as 100 but without bracket i get o/p as -80.

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  • emacs/Python: running python-shell in line buffered vs. block buffered mode

    - by Begbie00
    Hi all - In a related question and answer here, someone hypothesized that python-shell within emacs(23.2) was block-buffered instead of line-buffered. The recommended fix was to add sys.stdout.flush() to the spot in my script where I want stdio to flush its contents to the python-shell. Is there someway to trick python-shell (running in emacs 23.2 on Windows, not Linux) into either a) thinking it's attached to a TTY or b) using line-buffered instead of block-buffered mode? I don't see why I'd be able to do this in IDLE but not emacs. I'd rather customize emacs than add sys.stdout.flush() throughout my scripts. Call me lazy :-). Thanks, Mike

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  • usage of 2 charectors in single qoutes in c

    - by user1632141
    #include<stdio.h> int main() { char ch = 'A'; printf("%d\n",'ag'); printf("%d\n",'a'); printf("%d, %d, %d, %d", sizeof(ch), sizeof('a'), sizeof('Ag'), sizeof(3.14f)); return 0; } I used to have many doubts on the output of this question while running on g++ and gcc. But I have cleared almost all the doubts by referring these links: Single and double quotes in C/C++ Single quotes vs. double quotes in C I still need to understand one thing about the output of this question. Can someone please explain the output of printf("%d\n",'ag'); mentioned above in the program. How is it actually stored in the memory? The output for the program on the Linux/GCC platform is: 24935 97 1, 4, 4, 4

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  • An easy way to replace fread()'s with reading from a byte array?

    - by Sam Washburn
    I have a piece of code that needs to be run from a restricted environment that doesn't allow stdio (Flash's Alchemy compiler). The code uses standard fopen/fread functions and I need to convert it to read from a char* array. Any ideas on how to best approach this? Does a wrapper exist or some library that would help? Thanks! EDIT: I should also mention that it's reading in structs. Like this: fread(&myStruct, 1, sizeof(myStruct), f);

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  • Can a pointer ever point to itself?

    - by eSKay
    This question was mentioned here. My doubt is: If a pointer variable has the same address as its value, is it really pointing to itself? For example - in the following piece of code, is a a pointer to itself? #include<stdio.h> int main(){ int* a; int b = (int)&a; a = b; printf("address of a = %d\n", &a); printf(" value of a = %d\n", a); } If a is not a pointer to itself, then the same question poses again: Can a pointer point to itself? Also, how is a self pointing pointer useful?

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  • How can a FILE* (pointer to a struct) be tested (if == NULL)?

    - by m4design
    I was playing around with C, anyways I was thinking how can file pointer (which points to a struct type), be tested if NULL as for instant: FILE *cfPtr; if ( ( cfPtr = fopen( "file.dat", "w" ) ) == NULL ) I tried to do that myself, but an error occurs. struct foo{ int x; }; struct foo bar = {0}; if (bar == NULL) puts("Yay\n"); else puts("Nay"); error C2088: '==' : illegal for struct Here's the FILE deceleration in the stdio.h file: struct _iobuf { char *_ptr; int _cnt; char *_base; int _flag; int _file; int _charbuf; int _bufsiz; char *_tmpfname; }; typedef struct _iobuf FILE;

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  • how free of memory happen in this case???

    - by Riyaz
    #include <stdio.h> void func(int arr[],int xNumOfElem) { int j; for(j=0; j<xNumOfElem; j++) { arr[j] = j + arr[j]; printf("%d\t",arr[j]); } printf("\n"); } int main() { int *a,k; a = (int*) malloc(sizeof(int)*10); for(k = 0; k<10; k++) { a[k] = k; printf("%d\t",a[k]); } printf("\n"); func(a,10); //Func call free(a); } Inside the the function "func" who will allocate/deallocate memory for dynamic array "arr". arr is an function argument.

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  • strstr whole string match

    - by clay
    I'm trying to match the whole string and not just part of it. For instance, if the needle is 2, I would like to match just the string 2 and not 20, 02, or 22 or anything related. I'm using strstr as: #include <stdio.h> #include <string.h> int main(int argc, char *argv[]) { FILE *file; char l[BUFSIZ]; int linenumber = 1; char term[6] = "2"; file = fopen(argv[1], "r"); if(file != NULL) { while(fgets(l, sizeof(l), file)){ if(strstr(l, term) != NULL) { printf("Search Term Found at %d!\n", linenumber); } ++linenumber; } } else { perror(argv[1]); } fclose(file); return 0; }

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  • C : Memory layout of C program execution

    - by pavun_cool
    Hi All , I wanted know how the kernel is providing memory for simple C program . For example : #include<stdio.h> #include<malloc.h> int my_global = 10 ; main() { char *str ; static int val ; str = ( char *) malloc ( 100 ) ; scanf ( "%s" , str ) ; printf( " val:%s\n",str ) ; } See, In this program I have used static , global and malloc for allocating dynamic memory So , how the memory lay out will be ... ? Any one give me url , which will have have details information about this process..

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  • Using pow() for large number

    - by g4ur4v
    I am trying to solve a problem, a part of which requires me to calculate (2^n)%1000000007 , where n<=10^9. But my following code gives me output "0" even for input like n=99. Is there anyway other than having a loop which multilplies the output by 2 every time and finding the modulo every time (this is not I am looking for as this will be very slow for large numbers). #include<stdio.h> #include<math.h> #include<iostream> using namespace std; int main() { unsigned long long gaps,total; while(1) { cin>>gaps; total=(unsigned long long)powf(2,gaps)%1000000007; cout<<total<<endl; } }

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  • Is there any way to pass an anonymous array as an argument in C++?

    - by Jeremy Friesner
    Hi all, I'd like to be able to declare an array as a function argument in C++, as shown in the example code below (which doesn't compile). Is there any way to do this (other than declaring the array separately beforehand)? #include <stdio.h> static void PrintArray(int arrayLen, const int * array) { for (int i=0; i<arrayLen; i++) printf("%i -> %i\n", i, array[i]); } int main(int, char **) { PrintArray(5, {5,6,7,8,9} ); // doesn't compile return 0; }

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  • assignment makes pointer from integer without a cast

    - by mrblippy
    hi, i am trying to make a linked list and create some methods. but i am getting the error assignment makes pointer from integer without a cast. #include <stdio.h> #include <stdlib.h> #include "students.h" node_ptr create(void) { node_ptr students = (node_ptr) malloc(sizeof(struct node)); students->ID = 0; students->name = NULL; students->next = NULL; return students; } void insert_in_order(int n, node_ptr list) { node_ptr before = list; node_ptr new_node = (node_ptr) malloc(sizeof(struct node)); new_node->ID = n;//error is here i think while(before->next && (before->next->ID < n)) { before = before->next; } new_node->next = before->next; before->next = new_node; }

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  • problem with threads

    - by Nadeem
    i want to be done for 10 times!!, to scan teh number and print it again!!, how i can do that #include <stdio.h> #include <pthread.h> #include <semaphore.h> sem_t m; int n; void *readnumber(void *arg) { scanf("%d",&n); sem_post(&m); } void *writenumber(void *arg) { //int x =3; //while(x>0) //{ //x = x-1; sem_wait(&m); printf("%d",n); //} } int main(){ pthread_t t1, t2; sem_init(&m, 0, 0); pthread_create(&t2, NULL, writenumber, NULL); pthread_create(&t1, NULL, readnumber, NULL); pthread_join(t2, NULL); pthread_join(t1, NULL); sem_destroy(&m); return 0; }

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  • cannot convert ‘mcontext_t*’ to ‘sigcontext*’ in assignment

    - by user353573
    i have checked asm/ucontext.h it should be sigcontext, but why pop up the error message cannot convert ‘mcontext_t*’ to ‘sigcontext*’ in assignment #include <stdio.h> #include <signal.h> #include <asm/ucontext.h> static unsigned long target; void handler(int signum, siginfo_t *siginfo, void *uc0){ struct ucontext *uc; struct sigcontext *sc; uc = (struct ucontext *)uc0; sc = &uc->uc_mcontext; sc->eip = target; } struct ucontext { unsigned long uc_flags; struct ucontext *uc_link; stack_t uc_stack; struct sigcontext uc_mcontext; sigset_t uc_sigmask; /* mask last for extensibility */ };

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  • stack of a c program

    - by ckarthickit
    how the stack would look like for the following program if I give input as 5. #include <stdio.h> int fibonacci(int number) { int retval; if (0 == number){ return 0; } if (1 == number){ return 1; } return(fibonacci(number-1) + fibonacci(number-2)); } int main() { int number = 0; int fibvalue = 1; while (1){ printf("please enter the number\n"); scanf("%d", &number); fibvalue = fibonacci(number); printf("computed fibonacci value %d\n", fibvalue); } return 1; } also give me links where i can learn about it

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  • What are the implications of using static const instead of #define?

    - by Simon Elliott
    gcc complains about this: #include <stdio.h> static const int YY = 1024; extern int main(int argc, char*argv[]) { static char x[YY]; } $ gcc -c test1.c test1.c: In function main': test1.c:5: error: storage size of x' isn't constant test1.c:5: error: size of variable `x' is too large Remove the “static” from the definition of x and all is well. I'm not exactly clear what's going on here: surely YY is constant? I had always assumed that the "static const" approach was preferable to "#define". Is there any way of using "static const" in this situation?

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  • Why this C program outputs a negative number?

    - by JMSA
    I have assigned the complement value in an unsigned variable. Then why this C program outputs a negative number? #include<stdio.h> #include<conio.h> int main() { unsigned int Value = 4; /* 4 = 0000 0000 0000 0100 */ unsigned int result = 0; result = ~ Value; /* -5 = 1111 1111 1111 1011 */ printf("result = %d", result); /* -5 */ getch(); return 0; }

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  • How to create custom filenames in C?

    - by eSKay
    Please see this piece of code: #include<stdio.h> #include<string.h> #include<stdlib.h> int main() { int i = 0; FILE *fp; for(i = 0; i < 100; i++) { fp = fopen("/*what should go here??*/","w"); //I need to create files with names: file0.txt, file1.txt, file2.txt etc //i.e. file{i}.txt } }

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  • Why would you precede the main() function in C with a data type?

    - by Milktrader
    Many are familiar with the hello world program in C #include <stdio.h> main () { printf ("hello world"); return 0; } Why do some precede the main () function with int as in: int main() Also, I've seen the word 'void' entered inside the () as in: int main(void) It seems like extra typing for nothing, but maybe it's a best practice that pays dividends in other situations? Also, why precede main() with an int if you're returning a character string? If anything, one would expect: char main(void) I'm also foggy about why we return 0 at the end of the function.

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  • Segmentation fault when using files C++

    - by Popa Mihai
    I am using ubuntu 12.04. I have been trying a few IDE's for simple C++ school projects. However, with codelite, anjuta and kdevelop I encountered a problem: when I am trying to read / write in files I get segmentation fault: core dumped. I am using a basic source: #include<stdio.h> FILE*f=fopen("test.in","r"); FILE*g=fopen("test.out","w"); int main () { int a,b; fscanf(f,"%d %d",&a,&b); fprintf(g,"%d\n",a+b); fclose(f); fclose(g); return 0; } I have to say that programs with stdin/stdout work well. Thank you,

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  • C string program

    - by mrblippy
    Hi, i have been given a task to do ar school that must read three strings in, store the third string in dynamically allocated memory and print out the last 4 letters of the first word alphabetically. Here is the program i have so far but the strings are all stored in different variables, making them hard to sort. if anyone could give me a hand and help me finish this program i would be very grateful. thanks #include <stdio.h> #include <stdlib.h> #include <string.h> int main() { char word1[101]; char word2[101]; char* word3; char buffer[101]; scanf("%s", word1); scanf("%s", word2); scanf("%s", buffer); word3 = (char *) malloc(strlen(buffer)+1); strcpy(word3, buffer); return 0; }

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  • Hex to bin after logical operations

    - by user355926
    I want: 111 || 100 ---> 111, not 1 100 && 100 ---> 100, not 1 101 && 010 ---> 000, not 0 Broken code #include <stdio.h> main(void){ string hexa = 0xff; strig hexa2 = 0xf1; // CONVERT TO INT??? cast int hexa3 = hexa || hexa2; int hexa4 = hexa && hexa2; puts(hexa3); puts(hexa4); }

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