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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • strange behavior in vim with negative look-behind

    - by João Portela
    So, I am doing this search in vim: /\(\(unum\)\|\(player\)=\)\@<!\"1\" and as expected it does not match lines that have: player="1" but matches lines that have: unum="1" what am i doing wrong? isn't the atom to be negated all of this: \(\(unum\)\|\(player\)=\) naturally just doing: /\(\(unum\)\|\(player\)=\) matches unum= or player=.

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  • Convert regular expression to CFG

    - by user242581
    How can I convert some regular language to its equivalent Context Free Grammar(CFG)? Whether the DFA corresponding to that regular expression is required to be constructed or is there some rule for the above conversion? For example, considering the following regular expression 01+10(11)* How can I describe the grammar corresponding to the above RE?

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  • Not-quite-JSON string deserialization in Python

    - by cpharmston
    I get the following text as a string from an XML-based REST API 'd':4 'ca':5 'sen':1 'diann':2,6,8 'feinstein':3,7,9 that I'm looking to deserialize into a pretty little Python dictionary: { 'd': [4], 'ca': [5], 'sen': [1], 'diann': [2, 6, 8], 'feinstein': [3, 7, 9] } I'm hoping to avoid using regular expressions or heavy string manipulation, as this format isn't documented and may change. The best I've been able to come up with: members = {} for m in elem.text.split(' '): m = m.split(':') members[m[0].replace("'", '')] = map(int, m[1].split(',')) return members Obviously a terrible approach, but it works, and that's better than anything else I've got right now. Any suggestions on better approaches?

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  • Regexp that matches user-agents of end-user browsers but NOT crawlers with >90 % accuracy

    - by knorv
    I'm trying to construct a regexp that will evaluate to true for User-Agent:s of "browsers navigated by humans", but false for bots. Needless to say the matching will not be exact, but if it gets things right in say 90 % of cases that is more than good enough. My approach so far is to target the User-Agent string of the the five major desktop browsers (MSIE, Firefox, Chrome, Safari, Opera). Specifically I want the regexp NOT to match if the user-agent is a bot (Googlebot, msnbot, etc.). Currently I'm using the following regexp which appears to achieve the desired precision: ^(Mozilla.*(Gecko|KHTML|MSIE|Presto|Trident)|Opera).*$ I've observed small number of false negatives which are mostly mobile browsers. The exceptions all match: (BlackBerry|HTC|LG|MOT|Nokia|NOKIAN|PLAYSTATION|PSP|SAMSUNG|SonyEricsson) My question is: Given the desired accuracy level, how would you improve the regexp? Can you think of any major false positives or false negatives to the given regexp? Please note that the question is specifically about regexp-based User-Agent matching. There are a bunch of other approaches to solving this problem, but those are out of the scope of this question.

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  • Transforming a string to a valid PDO_MYSQL DSN

    - by Alix Axel
    What is the most concise way to transform a string in the following format: mysql:[/[/]][user[:pass]@]host[:port]/db[/] Into a usuable PDO connection/instance (using the PDO_MYSQL DSN), some possible examples: $conn = new PDO('mysql:host=host;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user', 'pass'); I've been trying some regular expressions (preg_[match|split|replace]) but they either don't work or are too complex, my gut tells me this is not the way to go but nothing else comes to my mind. Any suggestions?

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  • stripping a query string with php (preg_replace)

    - by pg
    http://www.chuckecheese.com/rotator.php?cheese=4&id=1 I want to take out the id, leaving the cheese to stand alone. I tried: $qs = preg_replace("[^&id=*]" ,'',$_SERVER[QUERY_STRING]); But that said I was using an improper modifier. I want to remove "$id=" and whatever number comes after it. Are regexp really as hard as they seem for me?

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  • JavaScript: Given an offset and substring length in an HTML string, what is the parent node?

    - by Bungle
    My current project requires locating an array of strings within an element's text content, then wrapping those matching strings in <a> elements using JavaScript (requirements simplified here for clarity). I need to avoid jQuery if at all possible - at least including the full library. For example, given this block of HTML: <div> <p>This is a paragraph of text used as an example in this Stack Overflow question.</p> </div> and this array of strings to match: ['paragraph', 'example'] I would need to arrive at this: <div> <p>This is a <a href="http://www.example.com/">paragraph</a> of text used as an <a href="http://www.example.com/">example</a> in this Stack Overflow question.</p> </div> I've arrived at a solution to this by using the innerHTML() method and some string manipulation - basically using the offsets (via indexOf()) and lengths of the strings in the array to break the HTML string apart at the appropriate character offsets and insert <a href="http://www.example.com/"> and </a> tags where needed. However, an additional requirement has me stumped. I'm not allowed to wrap any matched strings in <a> elements if they're already in one, or if they're a descendant of a heading element (<h1> to <h6>). So, given the same array of strings above and this block of HTML (the term matching has to be case-insensitive, by the way): <div> <h1>Example</a> <p>This is a <a href="http://www.example.com/">paragraph of text</a> used as an example in this Stack Overflow question.</p> </div> I would need to disregard both the occurrence of "Example" in the <h1> element, and the "paragraph" in <a href="http://www.example.com/">paragraph of text</a>. This suggests to me that I have to determine which node each matched string is in, and then traverse its ancestors until I hit <body>, checking to see if I encounter a <a> or <h_> node along the way. Firstly, does this sound reasonable? Is there a simpler or more obvious approach that I've failed to consider? It doesn't seem like regular expressions or another string-based comparison to find bounding tags would be robust - I'm thinking of issues like self-closing elements, irregularly nested tags, etc. There's also this... Secondly, is this possible, and if so, how would I approach it?

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  • Regular expression for email

    - by Nadeem
    I tried the reg expression ^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+ for the email validation. Since I want the user to allow submitting even with the empty email address. So I changed the reg ex to (^([a-zA-Z0-9_.-])+@([a-zA-Z0-9_.-])+\.([a-zA-Z])+([a-zA-Z])+)? But this expression accepts any email address without any validation.

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • Invert regexp in vim

    - by Chris J
    There's a few "how do I invert a regexp" questions here on stackoverflow, but I can't find one for vim (if it does exist, by goggle-fu is lacking today). In essence I want to match all non-printable characters and delete them. I could write a short script, or drop to a shell and use tr or something similar to delete, but a vim solution would be dandy :-) Vim has the atom \p to match printable characters, however trying to do this :s/[^\p]//g to match the inverse failed and just left me with every 'p' in the file. I've seen the (?!xxx) sequence in other questions, and vim seems to not recognise this sequence. I've not found seen an atom for non-printable chars. In the interim, I'm going to drop to external tools, but if anyone's got any trick up their sleeve to do this, it'd be welcome :-) Ta!

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  • Regexp: Replace only in specific context

    - by blinry
    In a text, I would like to replace all occurrences of $word by [$word]($word) (to create a link in Markdown), but only if it is not already in a link. Example: [$word homepage](http://w00tw00t.org) should not become [[$word]($word) homepage](http://w00tw00t.org). Thus, I need to check whether $word is somewhere between [ and ] and only replace if it's not the case. Can you think of a preg_replace command for this?

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  • postgres - regex_replace in distinct clause?

    - by n00b0101
    Ok... changing the question here... I'm getting an error when I try this: SELECT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', '', 'g'), regexp_replace(na_lname, '\\s*', '', 'g')) FROM masterfile; Is it possible to use regexp in a distinct clause like this? The error is this: WARNING: nonstandard use of \\ in a string literal LINE 1: ...CT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', ''...

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  • Cleaning strings in R: add punctuation w/o overwriting last character

    - by spearmint
    I'm new to R and unable to find other threads with a similar issue. I'm cleaning data that requires punctuation at the end of each line. I am unable to add, say, a period without overwriting the final character of the line preceding the carriage return + line feed. Sample code: Data1 <- "%trn: dads sheep\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Data2 <- gsub("[^[:punct:]]\r\n\\*", ".\r\n\\*", Data1) The contents of Data2: [1] "%trn: dads shee.\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Notice the "p" of sheep was overwritten with the period. Any thoughts on how I could avoid this?

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  • How do I convert CamelCase into human-readable names in Java?

    - by Frederik
    I'd like to write a method that converts CamelCase into a human-readable name. Here's the test case: public void testSplitCamelCase() { assertEquals("lowercase", splitCamelCase("lowercase")); assertEquals("Class", splitCamelCase("Class")); assertEquals("My Class", splitCamelCase("MyClass")); assertEquals("HTML", splitCamelCase("HTML")); assertEquals("PDF Loader", splitCamelCase("PDFLoader")); assertEquals("A String", splitCamelCase("AString")); assertEquals("Simple XML Parser", splitCamelCase("SimpleXMLParser")); assertEquals("GL 11 Version", splitCamelCase("GL11Version")); }

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  • Pulling out two separate words from a string using reg expressions?

    - by Marvin
    I need to improve on a regular expression I'm using. Currently, here it is: ^[a-zA-Z\s/-]+ I'm using it to pull out medication names from a variety of formulation strings, for example: SULFAMETHOXAZOLE-TRIMETHOPRIM 200-40 MG/5ML PO SUSP AMOX TR/POTASSIUM CLAVULANATE 125 mg-31.25 mg ORAL TABLET, CHEWABLE AMOXICILLIN TRIHYDRATE 125 mg ORAL TABLET, CHEWABLE AMOX TR/POTASSIUM CLAVULANATE 125 mg-31.25 mg ORAL TABLET, CHEWABLE Amoxicillin 1000 MG / Clavulanate 62.5 MG Extended Release Tablet The resulting matches on these examples are: SULFAMETHOXAZOLE-TRIMETHOPRIM AMOX TR/POTASSIUM CLAVULANATE AMOXICILLIN TRIHYDRATE AMOX TR/POTASSIUM CLAVULANATE Amoxicillin The first four are what I want, but on the fifth, I really need "Amoxicillin / Clavulanate". How would I pull out patterns like "Amoxicillin / Clavulanate" (in fifth row) while missing patterns like "MG/5 ML" (in the first row)?

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  • How to split a space separated file?

    - by simplesimon
    Hi I am trying to import this: http://en.wikipedia.org/wiki/List_of_countries_by_continent_%28data_file%29 which is of the format like: AS AF AFG 004 Afghanistan, Islamic Republic of EU AX ALA 248 Åland Islands EU AL ALB 008 Albania, Republic of AF DZ DZA 012 Algeria, People's Democratic Republic of OC AS ASM 016 American Samoa EU AD AND 020 Andorra, Principality of AF AO AGO 024 Angola, Republic of NA AI AIA 660 Anguilla if i do <? explode(" ",$data"); ?> that works fine apart from countries with more than 1 word. how can i split it so i get the first 4 bits of data (the chars/ints) and the 5th bit of data being whatever remains? this is in php thank you

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  • How to remove a tab attribute in ASP .NET AJAX Toolkit using Regular Expression

    - by Nassign
    I have tried to remove the following tag generated by the AJAX Control toolkit. The scenario is our GUI team used the AJAX control toolkit to make the GUI but I need to move them to normal ASP .NET view tag using MultiView. I want to remove all the __designer: attributes Here is the code <asp:TextBox ID="a" runat="server" __designer:wfdid="w540" /> <asp:DropdownList ID="a" runat="server" __designer:wfdid="w541" /> ..... <asp:DropdownList ID="a" runat="server" __designer:wfdid="w786" /> I tried to use the regular expression find replace in Visual Studio using: Find: :__designer\:wfdid="w{([0-9]+)}" Replace with empty space Can any regular expression expert help?

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