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  • Replace a div content with PHP

    - by Zakaria
    hi everybody, yesterday, I posted a question about "Hom to change a DIV id with a php function" and someone found the right answer with a regular expression. The problem is that I wanted to use this answer to aplly the method on other same problems. But, as I'm very bad at regular expressions, I couldn't. So the problem is that I upload some videos with FCKEditor and put the video script in my database and the result is like that: <div id="player959093-parent" style="text-align: center;float: left;"> <div style="border-style: none; height: 160px; width: 270px; overflow: hidden; background-color: rgb(220, 220, 220); background-image: url(http://localhost/fckeditor/editor/plugins/flvPlayer/flvPlayer.gif); background-repeat:no-repeat; background-position:center;"><script src="http://localhost/fckeditor/editor/plugins/flvPlayer/swfobject.js" type="text/javascript"></script> <div id="player959093"><a href="http://www.macromedia.com/go/getflashplayer">Get the Flash Player</a> to see this player. <div id="player959093-config" style="display: none;visibility: hidden;width: 0px;height:0px;overflow: hidden;">url=/editeur/images/flash/FOO.flv width=270 height=160 loop=false play=false downloadable=false fullscreen=true displayNavigation=true displayDigits=true align=left dispPlaylist=none playlistThumbs=false</div> </div> <script type="text/javascript"> var s1 = new SWFObject("http://localhost/editeur/javascript/fckeditor/editor/plugins/flvPlayer/mediaplayer.swf","single","270","160","7"); s1.addVariable("width","270"); s1.addVariable("height","160"); s1.addVariable("autostart","false"); s1.addVariable("file","/editeur/images/flash/FOO.flv"); s1.addVariable("repeat","false"); s1.addVariable("image",""); s1.addVariable("showdownload","false"); s1.addVariable("link","/editeur/images/flash/FOO.flv"); s1.addParam("allowfullscreen","true"); s1.addVariable("showdigits","true"); s1.addVariable("shownavigation","true"); s1.addVariable("logo",""); s1.write("player959093"); </script></div> </div> When I echo this content once in my PHP page, It works great. More than once, the videos doesn't appear. Which is obvious because of the unique ID. As you can see, the content has these ids: div id="player959093-parent" div id="player959093" div id="player959093-config s1.write("player959093"); So my question is: Is there a function that can replace the string "player959093" or concatenate it with some other string to resolve the display problem? Thank you very much, Regards.

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  • Lighttpd rewriting files and directories

    - by Ronald
    I'm trying to do url rewriting with Lighttpd. I have what I need partially working. Right now I have this: http://domain.com/name/a/123 which rewrites to http://domain.com/name/a.php?pid=123 I do this with this rewrite-once rule: "^/name/a/([^/]+)"= "/name/a.php?pid=$1" That php page has external resources that are not getting rewritten such as the JavaScript and CSS files. Is there a way I can also have the rewrite do the following? http://domain.com/name/a/js/file.js = http://domain.com/name/js/file.js

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  • multi-line pattern matching in pyhon

    - by Horace Ho
    A periodic computer generated message (simplified): Hello user123, - (604)7080900 - 152 - minutes Regards Using python, how can I extract "(604)7080900", "152", "minutes" (i.e. any text following a leading "- " pattern) between the two empty lines (empty line is the \n\n after "Hello user123" and the \n\n before "Regards"). Even better if the result string list are stored in an array. Thanks!

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  • Backslashes in gsub (escaping and backreferencing)

    - by polygenelubricants
    Consider the following snippet: puts 'hello'.gsub(/.+/, '\0 \\0 \\\0 \\\\0') This prints (as seen on ideone.com): hello hello \0 \0 This was very surprising, because I'd expect to see something like this instead: hello \0 \hello \\0 My argument is that \ is an escape character, so you write \\ to get a literal backslash, thus \\0 is a literal backslash \ followed by 0, etc. Obviously this is not how gsub is interpreting it, so can someone explain what's going on? And what do I have to do to get the replacement I want above?

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  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

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  • Remove unmatched HTML tags in a string

    - by Freeman
    Folks does anyone knows of a PHP function to remove unmatched HTML tags from a string. for example<div> This is a string <b> with an unmatched bold tag </div>. If there isnt one then help me buld one, maybe I can have a function that counts the number of opening tags and matching closing tags. If they are not even then remove the first opening tag or if closing tags are more, it removes the last tag?

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  • Multiple calls to preg_replace alters result

    - by Hurpe
    I have a bunch of files that were named in a somewhat standard format. The standard form is basically this: [integer]_word1_word2_word3_ ... _wordn where a word could really be anything, but all words are separated by an underscore. There is really only 3 things I want to do to the text: 1.) I want to modify the integer, which is always at the beginning, so that something like "200" would become $ 200.00. 2.) replace any "words" of the form "with", "With", "w/", or "W/" with "with". 3.) Replace all underscores with a space. I wrote three different preg_replace calls to do the trick. They are as follows: 1.) $filename = preg_replace("/(^[0-9]+)/","$ $1.00",$filename) 2.) $filename = preg_replace("/_([wW]|[wW]ith)_/"," with ",$filename) 3.) $filename = preg_replace("/_/"," ",$filename); Each replacement works as expected when run individually, but when all three are run, the 2nd replacement is ignored. Why would something like that occur? Thanks for the help!

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • Match groups in Python

    - by Curd
    Is there a way in Python to access match groups without explicitely creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the question: Following perl code if ($statement =~ /I love (\w+)/) { print "He loves $1\n"; } elsif ($statement =~ /Ich liebe (\w+)/) { print "Er liebt $1\n"; } elsif ($statement =~ /Je t\'aime (\w+)/) { print "Il aime $1\n"; } translated into Python m = re.match("I love (\w+)", statement) if m: print "He loves",m.group(1) else: m = re.match("Ich liebe (\w+)", statement) if m: print "Er liebt",m.group(1) else: m = re.match("Je t'aime (\w+)", statement) if m: print "Il aime",m.group(1) looks very awkward (if-else-cascade, match object creation).

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  • regular expression search in python

    - by Richard
    Hello all, I am trying to parse some data and just started reading up on regular Expressions so I am pretty new to it. This is the code I have so far String = "MEASUREMENT 3835 303 Oxygen: 235.78 Saturation: 90.51 Temperature: 24.41 DPhase: 33.07 BPhase: 29.56 RPhase: 0.00 BAmp: 368.57 BPot: 18.00 RAmp: 0.00 RawTem.: 68.21" String = String.strip('\t\x11\x13') String = String.split("Oxygen:") print String[1] String[1].lstrip print String[1] What I am trying to do is to do is remove the oxygen data (235.78) and put it in its own variable using an regular expression search. I realize that there should be an easy solution but I am trying to figure out how regular expressions work and they are making my head hurt. Thanks for any help Richard

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  • Basic Profanity Filter in Objective C for iPhone

    - by David van Dugteren
    How have you like minded individuals tackled the basic challenge of filtering profanity, obviously one can't possibly tackle every scenario but it would be nice to have one at the most basic level as a first line of defense. In Obj-c I've got NSString *tokens = [text componentsSeparatedByString:@" "]; And then I loop through each token to see if any of the keywords (I've got about 400 in a list) are found within each token. Realising False positives are also a problem, if the word is a perfect match, its flagged as profanity otherwise if more than 3 words with profanity are found without being perfect matches it is also flagged as profanity. Later on I will use a webservice that tackles the problem more precisely, but I really just need something basic. So if you wrote the word penis it would go yup naughty naughty, bad word written.

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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  • Apache RewriteRule: it is possible to 'detect' the first and second path segment?

    - by DaNieL
    Im really really a newbie in regexp and I can’t figure out how to do that. My goal is to have the RewriteRule to 'slice' the request URL path in 3 parts: example.com/foo #should return: index.php?a=foo&b=&c= example.com/foo/bar #should return: index.php?a=foo&b=bar&c= example.com/foo/bar/baz #should return: index.php?a=foo&b=bar&c=baz example.com/foo/bar/baz/bee #should return: index.php?a=foo&b=bar&c=baz/bee example.com/foo/bar/baz/bee/apple #should return: index.php?a=foo&b=bar&c=baz/bee/apple example.com/foo/bar/baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters #should return: index.php?a=foo&b=bar&c=baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters In short, the first segment in the URL path (foo) should be given to a, the second segment (bar) to b, and the rest of the string in c I wroted this one <IfModule mod_rewrite.c> RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_URI} !=/favicon.ico RewriteRule ^(([a-z0-9/]))?(([a-z0-9/]+))?(([a-z0-9]+))(.*)$ index.php?a=$1&b=$2&c=$3 [L,QSA] </IfModule> But obviously doesn’t work, and I don’t even know if what I want is possible. Any suggestion? EDIT: After playing with coach manager, I got this one working too: RewriteRule ^([^/]*)?/?([^/]*)?/?(.*)?$ index.php?a=$1&b=$2&c=$3 [L,QSA]

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  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

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  • Finding an open and closing tag in Regexp

    - by Rixius
    Is there a way to find custom tags in regexp I.e. match {a}sometext{/a} As well as {c=#fff}sometext{/c} So that it finds the entire block of inner content? The problem is the sometext could have another tag as in: {a=http://www.google.com}{b}Hello, world{/b}{/a} The only solutions I can come up with would match from {a... to .../b} when I want {a... to .../a} is there a single regexp solution, or would it be best to match the start, and then use another method to find the end from the back up, and grab it out that way? I'm using PHP 5.2 so I have all the options that entails.

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  • Validating javascript decimal numbers

    - by Click Upvote
    I'm using the following regexp to validate numbers in my javascript file: var valid = (val.match(/^\d+$/)); It works fine for whole numbers like 100, 200, etc, however for things like 1.44, 4.11, etc, it returns false. How can I change it so numbers with a decimal are also accepted?

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  • This regx does not work only in Chrome

    - by Deeptechtons
    Hi i just put up a validation function in jScript to validate filename in fileupload control[input type file]. The function seems to work fine in FF and sometimes in ie but never in Chrome. Basically the function tests if File name is atleast 1 char upto 25 characters long.Contains only valid characters,numbers [no spaces] and are of file types in the list. Could you throw some light on this function validate(Uploadelem) { var objRgx = new RegExp(/^[\w]{1,25}\.*\.(jpg|gif|png|jpeg|doc|docx|pdf|txt|rtf)$/); objRgx.ignoreCase = true; if (objRgx.test(Uploadelem.value)) { document.getElementById('moreUploadsLink').style.display = 'block'; } else { document.getElementById('moreUploadsLink').style.display = 'none'; } }

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  • pattern for the following condition in java

    - by zahir hussain
    hi i want to know how to write pattern.. for example : the word is "AboutGoogle AdWords Drive traffic and customers to your site. Pay through Cheque, Net Banking or Credit Card. Google Toolbar Add a search box to your browser. Google SMS To find out local information simply SMS to 54664. Gmail Free email with 7.2GB storage and less spam. Try Gmail today. Our ProductsHelp Help with Google Search, Services and ProductsGoogle Web Search Features Translation, I'm Feeling Lucky, CachedGoogle Services & Tools Toolbar, Google Web APIs, ButtonsGoogle Labs Ideas, Demos, ExperimentsFor Site OwnersAdvertising AdWords, AdSenseBusiness Solutions Google Search Appliance, Google Mini, WebSearchWebmaster Central One-stop shop for comprehensive info about how Google crawls and indexes websitesSubmit your content to Google Add your site, Google SitemapsOur CompanyPress Center News, Images, ZeitgeistJobs at Google Openings, Perks, CultureCorporate Info Company overview, Philosophy, Diversity, AddressesInvestor Relations Financial info, Corporate governanceMore GoogleContact Us FAQs, Feedback, NewsletterGoogle Logos Official Logos, Holiday Logos, Fan LogosGoogle Blog Insights to Google products and cultureGoogle Store Pens, Shirts, Lava lamps©2010 Google - Privacy Policy - Terms of Service" I have to search some word... for example "google insights" so how to write the code in java... i just write small code... check my code and answer my question... that code only use for find the search word, where is that. but i need to display some words front of search word and display some words rear of search workd... similar to google search... my code is Pattern p = Pattern.compile("(?i)(.*?)"+search+""); Matcher m = p.matcher(full); String title=""; while (m.find() == true) { title=m.group(1); System.out.println(title); } the full is orignal content, search s search word... thanks and advance

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  • data in mysql show after barcode split and matches character

    - by klox
    i need some code for the next step..this my first step: <script> $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.matches(/EE|[EJU]).*(D)/i); }); </script> after matches..i want the result can connect to data base then show data from table inside <div id="value">...how to do that?

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  • Regexp for selecting spaces between digits and decimal char

    - by Tirithen
    I want to remove spaces from strings where the space is preceeded by a digit or a "." and acceded by a digit or ".". I have strings like: "50 .10", "50 . 10", "50. 10" and I want them all to become "50.10" but with an unknown number of digits on either side. I'm trying with lookahead/lookbehind assertions like this: $row = str_replace("/(?<=[0-9]+$)\s*[.]\s*(?=[0-9]+$)/", "", $row); But it does not work...

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