Search Results

Search found 23939 results on 958 pages for 'block size'.

Page 111/958 | < Previous Page | 107 108 109 110 111 112 113 114 115 116 117 118  | Next Page >

  • Why <textarea> and <textfield> not taking font-family and font-size from body?

    - by metal-gear-solid
    Why Textarea and textfield not taking font-family and font-size from body? See live example here http://jsbin.com/ucano4 Code <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>texearea font</title> <style type="text/css"> body { font-family: Verdana, Geneva, sans-serif; font-size:16px } </style> </head> <body> <form action="" method="get"> <textarea name="" cols="20" rows="4"></textarea> <input name="" type="text" /> </form> <p>some text here</p> </body> </html> If it's a usual behavior then should i write in css like this. i need same style in all body,textarea,input { font-family: Verdana, Geneva, sans-serif; font-size:16px } And how many other elements in XHTML which will not take font styling from body {....}?

    Read the article

  • How to iteratively generate k elements subsets from a set of size n in java?

    - by Bea Metitiri
    Hi, I'm working on a puzzle that involves analyzing all size k subsets and figuring out which one is optimal. I wrote a solution that works when the number of subsets is small, but it runs out of memory for larger problems. Now I'm trying to translate an iterative function written in python to java so that I can analyze each subset as it's created and get only the value that represents how optimized it is and not the entire set so that I won't run out of memory. Here is what I have so far and it doesn't seem to finish even for very small problems: public static LinkedList<LinkedList<Integer>> getSets(int k, LinkedList<Integer> set) { int N = set.size(); int maxsets = nCr(N, k); LinkedList<LinkedList<Integer>> toRet = new LinkedList<LinkedList<Integer>>(); int remains, thresh; LinkedList<Integer> newset; for (int i=0; i<maxsets; i++) { remains = k; newset = new LinkedList<Integer>(); for (int val=1; val<=N; val++) { if (remains==0) break; thresh = nCr(N-val, remains-1); if (i < thresh) { newset.add(set.get(val-1)); remains --; } else { i -= thresh; } } toRet.add(newset); } return toRet; } Can anybody help me debug this function or suggest another algorithm for iteratively generating size k subsets? EDIT: I finally got this function working, I had to create a new variable that was the same as i to do the i and thresh comparison because python handles for loop indexes differently.

    Read the article

  • Pickled my dictionary from ZODB but i got a less in size one?

    - by Someone Someoneelse
    I use ZODB and i want to copy my 'database_1.fs' file to another 'database_2.fs', so I opened the root dictionary of that 'database_1.fs' and I (pickle.dump) it in a text file. Then I (pickle.load) it in a dictionary-variable, in the end I update the root dictionary of the other 'database_2.fs' with the dictionary-variable. It works, but I wonder why the size of the 'database_1.fs' not equal to the size of the other 'database_2.fs'. They are still copies of each other. def openstorage(store): #opens the database data={} data['file']=filestorage data['db']=DB(data['file']) data['conn']=data['db'].open() data['root']=data['conn'].root() return data def getroot(dicty): return dicty['root'] def closestorage(dicty): #close the database after Saving transaction.commit() dicty['file'].close() dicty['db'].close() dicty['conn'].close() transaction.get().abort() then that's what i do:- import pickle loc1='G:\\database_1.fs' op1=openstorage(loc1) root1=getroot(op1) loc2='G:database_2.fs' op2=openstorage(loc2) root2=getroot(op2) >>> len(root1) 215 >>> len(root2) 0 pickle.dump( root1, open( "save.txt", "wb" )) item=pickle.load( open( "save.txt", "rb" ) ) #now item is a dictionary root2.update(item) closestorage(op1) closestorage(op2) #after I open both of the databases #I get the same keys in both databases #But `database_2.fs` is smaller that `database_2.fs` in size I mean. >>> len(root2)==len(root1)==215 #they have the same keys True Note: (1) there are persistent dictionaries and lists in the original database_1.fs (2) both of them have the same length and the same indexes.

    Read the article

  • Is there any way static block is executed more than once? if so then how?

    - by learner
    My Understanding Static block is executed during class loading, If a class is already loaded then there is no way to load the class other than class reloading Doubt/Question 1) Is there any time JVM reloads the class? My Understanding In Class Loading JVM loads source of the Java file, so it can not keep all thousands files source is a memory, it should discard the rarely used code and reload again when it is necessary and during reload JVM is not initializing static variables and locks again(may be using some tracking mechanism) Doubt/Question 2) If my above understanding is incorrect then please correct me

    Read the article

  • How to Block images (img tags) from an iFrame?

    - by ramayac
    Hello, Im searching for ideas to solve the following problem: I'm loading an URL (any for that matter) into an iFrame, and then block (server side) all image tags, o object tags before sending the page to the client. -- What I was thinking to do is: fetching the URL, and then manipulating the fetched content using a Java library (any recomendation on that matter?). And after that, send the modify content to que client. Would that be the best approach to solve this problem? suggestions are wellcome :)

    Read the article

  • C++: getting the address of the start of an std::vector ?

    - by shoosh
    Sometimes it is useful to use the starting address of an std::vector and temporarily treat that address as the address of a regularly allocated buffer. For instance replace this: char* buf = new char[size]; fillTheBuffer(buf, size); useTheBuffer(buf, size); delete[] buf; With This: vector<char> buf(size); fillTheBuffer(&buf[0], size); useTheBuffer(&buf[0], size); The advantage of this is of course that the buffer is deallocated automatically and I don't have to worry about the delete[]. The problem I'm having with this is when size == 0. In that case the first version works ok. An empty buffer is "allocated" and the subsequent functions do nothing size they get size == 0. The second version however fails if size == 0 since calling buf[0] may rightly contain an assertion that 0 < size. So is there an alternative to the idiom &buf[0] that returns the address of the start of the vector even if the vector is empty? I've also considered using buf.begin() but according to the standard it isn't even guaranteed to return a pointer.

    Read the article

  • Other than using `split`, is there a way around the Apache 2.0 maximum file size limit of 2GB?

    - by warren
    I have some ISOs that need to be available across a WAN, so we are using an http server to host them (allows for non-authenticated, read-only access (beyond being on the VPN) to the data store). The server the ISOs reside on is running CentOS 4, and Apache 2.0.58. Is there a way around the 2GB filesize limit with Apache 2.0 without using the split utility to chunk the ISOs down to a less-than-2GB size?

    Read the article

  • How do I block safari users from my website?

    - by user360322
    I would like to block all users of Safari from visiting my flash game web site. I would like them to see a picture of someone being punched in the face instead of the games. My understanding is that you can use javascript to do it, but I don't want to use some heavy framework like JQuery. Is there a way to do it in like a single line or two of javascript?

    Read the article

  • How to block writing in pipes, until the read has taken place ? (in C)

    - by user492194
    Hi everyone :) I'm currently working on some C program, and I'd like to know if there's any chance to block writing in the writer process (until the read is done) ? i.e. I have 3 pipes between the parent process and the children processes (the parent writes and the children read), I'd like to let the parent to write only to the process that finishes its reading :) I hope it's clear.. Thanks in advance.

    Read the article

  • How much slower is a try/catch block? [closed]

    - by Euclid
    Possible Duplicate: What is the real overhead of try/catch in C#? how much slower is a try catch block than a conditional? eg try { v = someArray[10]; } catch { v = defaultValue; } or if (null != someArray) { v = someArray[10]; } else { v = defaultValue; } is there much in it or isn't there a definative performance differance?

    Read the article

  • Why your Netapp is so slow...

    - by Darius Zanganeh
    Have you ever wondered why your Netapp FAS box is slow and doesn't perform well at large block workloads?  In this blog entry I will give you a little bit of information that will probably help you understand why it’s so slow, why you shouldn't use it for applications that read and write in large blocks like 64k, 128k, 256k ++ etc..  Of course since I work for Oracle at this time, I will show you why the ZS3 storage boxes are excellent choices for these types of workloads. Netapp’s Fundamental Problem The fundamental problem you have running these workloads on Netapp is the backend block size of their WAFL file system.  Every application block on a Netapp FAS ends up in a 4k chunk on a disk. Reference:  Netapp TR-3001 Whitepaper Netapp has proven this lacking large block performance fact in at least two different ways. They have NEVER posted an SPC-2 Benchmark yet they have posted SPC-1 and SPECSFS, both recently. In 2011 they purchased Engenio to try and fill this GAP in their portfolio. Block Size Matters So why does block size matter anyways?  Many applications use large block chunks of data especially in the Big Data movement.  Some examples are SAS Business Analytics, Microsoft SQL, Hadoop HDFS is even 64MB! Now let me boil this down for you.  If an application such MS SQL is writing data in a 64k chunk then before Netapp actually writes it on disk it will have to split it into 16 different 4k writes and 16 different disk IOPS.  When the application later goes to read that 64k chunk the Netapp will have to again do 16 different disk IOPS.  In comparison the ZS3 Storage Appliance can write in variable block sizes ranging from 512b to 1MB.  So if you put the same MSSQL database on a ZS3 you can set the specific LUNs for this database to 64k and then when you do an application read/write it requires only a single disk IO.  That is 16x faster!  But, back to the problem with your Netapp, you will VERY quickly run out of disk IO and hit a wall.  Now all arrays will have some fancy pre fetch algorithm and some nice cache and maybe even flash based cache such as a PAM card in your Netapp but with large block workloads you will usually blow through the cache and still need significant disk IO.  Also because these datasets are usually very large and usually not dedupable they are usually not good candidates for an all flash system.  You can do some simple math in excel and very quickly you will see why it matters.  Here are a couple of READ examples using SAS and MSSQL.  Assume these are the READ IOPS the application needs even after all the fancy cache and algorithms.   Here is an example with 128k blocks.  Notice the numbers of drives on the Netapp! Here is an example with 64k blocks You can easily see that the Oracle ZS3 can do dramatically more work with dramatically less drives.  This doesn't even take into account that the ONTAP system will likely run out of CPU way before you get to these drive numbers so you be buying many more controllers.  So with all that said, lets look at the ZS3 and why you should consider it for any workload your running on Netapp today.  ZS3 World Record Price/Performance in the SPC-2 benchmark ZS3-2 is #1 in Price Performance $12.08ZS3-2 is #3 in Overall Performance 16,212 MBPS Note: The number one overall spot in the world is held by an AFA 33,477 MBPS but at a Price Performance of $29.79.  A customer could purchase 2 x ZS3-2 systems in the benchmark with relatively the same performance and walk away with $600,000 in their pocket.

    Read the article

  • Problems with 3D Array for Voxel Data

    - by Sean M.
    I'm trying to implement a voxel engine in C++ using OpenGL, and I've been working on the rendering of the world. In order to render, I have a 3D array of uint16's that hold that id of the block at the point. I also have a 3D array of uint8's that I am using to store the visibility data for that point, where each bit represents if a face is visible. I have it so the blocks render and all of the proper faces are hidden if needed, but all of the blocks are offset by a power of 2 from where they are stored in the array. So the block at [0][0][0] is rendered at (0, 0, 0), and the block at 11 is rendered at (1, 1, 1), but the block at [2][2][2] is rendered at (4, 4, 4) and the block at [3][3][3] is rendered at (8, 8, 8), and so on and so forth. This is the result of drawing the above situation: I'm still a little new to the more advanced concepts of C++, like triple pointers, which I'm using for the 3D array, so I think the error is somewhere in there. This is the code for creating the arrays: uint16*** _blockData; //Contains a 3D array of uint16s that are the ids of the blocks in the region uint8*** _visibilityData; //Contains a 3D array of bytes that hold the visibility data for the faces //Allocate memory for the world data _blockData = new uint16**[REGION_DIM]; for (int i = 0; i < REGION_DIM; i++) { _blockData[i] = new uint16*[REGION_DIM]; for (int j = 0; j < REGION_DIM; j++) _blockData[i][j] = new uint16[REGION_DIM]; } //Allocate memory for the visibility _visibilityData = new uint8**[REGION_DIM]; for (int i = 0; i < REGION_DIM; i++) { _visibilityData[i] = new uint8*[REGION_DIM]; for (int j = 0; j < REGION_DIM; j++) _visibilityData[i][j] = new uint8[REGION_DIM]; } Here is the code used to create the block mesh for the region: //Check if the positive x face is visible, this happens for every face //Block::VERT_X_POS is just an array of non-transformed cube verts for one face //These checks are in a triple loop, which goes over every place in the array if (_visibilityData[x][y][z] & 0x01 > 0) { _vertexData->AddData(&(translateVertices(Block::VERT_X_POS, x, y, z)[0]), sizeof(Block::VERT_X_POS)); } //This is a seperate method, not in the loop glm::vec3* translateVertices(const glm::vec3 data[], uint16 x, uint16 y, uint16 z) { glm::vec3* copy = new glm::vec3[6]; memcpy(&copy, &data, sizeof(data)); for(int i = 0; i < 6; i++) copy[i] += glm::vec3(x, -y, z); //Make +y go down instead return copy; } I cannot see where the blocks may be getting offset by more than they should be, and certainly not why the offsets are a power of 2. Any help is greatly appreciated. Thanks.

    Read the article

  • nokia cell phone not accepting IP from dnsmasq dhcp server

    - by samix
    Hello, I having problem connecting a NOkia cell phone to my home wifi network. The wifi network is provided by a wireless card in a machine running Debian Testing and 2.6.26-2-686 kernel. The cars is D-Link DWL-G520 working in ap mode and has WPA encryption enabled. The wireless network is provided by hostapd using madwifi driver. Windows and Mac machines work properly with this wifi network. When I try to get the Nokia phone to connect to the wifi network, I get these lines in my dnsmasq log (to see lines without wrapping, here is the pastebin link for convenience - http://pastebin.com/m466c8fd2): Oct 27 13:25:21 red hostapd: ath0: STA 11:22:33:44:55:66 IEEE 802.11: disassociated Oct 27 13:25:21 red hostapd: ath0: STA 11:22:33:44:55:66 IEEE 802.11: associated Oct 27 13:25:21 red hostapd: ath0: STA 11:22:33:44:55:66 RADIUS: starting accounting session 4AE664FA-00000036 Oct 27 13:25:21 red hostapd: ath0: STA 11:22:33:44:55:66 WPA: pairwise key handshake completed (WPA) Oct 27 13:25:21 red hostapd: ath0: STA 11:22:33:44:55:66 WPA: group key handshake completed (WPA) Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 Available DHCP range: 192.168.5.150 -- 192.168.5.199 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 DHCPDISCOVER(ath0) 0.0.0.0 11:22:33:44:55:66 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 DHCPOFFER(ath0) 192.168.5.21 11:22:33:44:55:66 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 requested options: 12:hostname, 6:dns-server, 15:domain-name, Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 requested options: 1:netmask, 3:router, 28:broadcast, 120:sip-server Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 tags: known, ath0 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 next server: 192.168.5.1 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 1 option: 53:message-type 02 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 54:server-identifier 192.168.5.1 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 51:lease-time 00:00:46:50 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 58:T1 00:00:23:28 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 59:T2 00:00:3d:86 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 1:netmask 255.255.255.0 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 28:broadcast 192.168.5.255 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 3:router 192.168.5.1 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 4 option: 6:dns-server 192.168.5.1 Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 8 option: 15:domain-name home.pvt Oct 27 13:25:21 red dnsmasq-dhcp[11451]: 3875439214 sent size: 3 option: 12:hostname NokiaCellPhone Anybody know the problem might be? If I switch off dnsmasq dhcp queries logging, i.e. if I decrease the verbosity of the log, all I see are two lines of DHCPDISCOVER(ath0) and DHCPOFFER(ath0) repeatedly in the log with no acceptance by the cell phone. It appears as though the phone is not accepting the dhcp offer. However, if I give the phone a static IP address in its configuration, it works properly on the wifi network. So it appears as though the problem is dhcp related. Hints? Suggestions? Installed stuff: $ dpkg -l dnsmasq hostap* | grep ^i ii dnsmasq 2.50-1 A small caching DNS proxy and DHCP/TFTP server ii dnsmasq-base 2.50-1 A small caching DNS proxy and DHCP/TFTP server ii hostapd 1:0.6.9-3 user space IEEE 802.11 AP and IEEE 802.1X/WPA/ Thanks. PS: Here is the DHCP tcp dump for more information (with mac addresses changed): $ sudo dhcpdump -i ath0 -h ^11:22:33:44:55:66 TIME: 2009-10-30 12:15:32.916 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 0 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:32.918 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 0 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:32.918 IP: 192.168.5.1 (a:bb:cc:dd:ee:ff) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 2 (BOOTPREPLY) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 0 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 192.168.5.21 SIADDR: 192.168.5.1 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 2 (DHCPOFFER) OPTION: 54 ( 4) Server identifier 192.168.5.1 OPTION: 51 ( 4) IP address leasetime 18000 (5h) OPTION: 58 ( 4) T1 9000 (2h30m) OPTION: 59 ( 4) T2 15750 (4h22m30s) OPTION: 1 ( 4) Subnet mask 255.255.255.0 OPTION: 28 ( 4) Broadcast address 192.168.5.255 OPTION: 3 ( 4) Routers 192.168.5.1 OPTION: 6 ( 4) DNS server 192.168.5.1 OPTION: 15 ( 8) Domainname home.pvt OPTION: 12 ( 3) Host name Nokia_E63 TIME: 2009-10-30 12:15:34.922 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 2 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:34.922 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 2 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:34.923 IP: 192.168.5.1 (a:bb:cc:dd:ee:ff) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 2 (BOOTPREPLY) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 2 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 192.168.5.21 SIADDR: 192.168.5.1 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 2 (DHCPOFFER) OPTION: 54 ( 4) Server identifier 192.168.5.1 OPTION: 51 ( 4) IP address leasetime 18000 (5h) OPTION: 58 ( 4) T1 9000 (2h30m) OPTION: 59 ( 4) T2 15750 (4h22m30s) OPTION: 1 ( 4) Subnet mask 255.255.255.0 OPTION: 28 ( 4) Broadcast address 192.168.5.255 OPTION: 3 ( 4) Routers 192.168.5.1 OPTION: 6 ( 4) DNS server 192.168.5.1 OPTION: 15 ( 8) Domainname home.pvt OPTION: 12 ( 3) Host name Nokia_E63 TIME: 2009-10-30 12:15:38.919 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 6 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:38.920 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 6 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:38.921 IP: 192.168.5.1 (a:bb:cc:dd:ee:ff) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 2 (BOOTPREPLY) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: c3f93d53 SECS: 6 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 192.168.5.21 SIADDR: 192.168.5.1 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 2 (DHCPOFFER) OPTION: 54 ( 4) Server identifier 192.168.5.1 OPTION: 51 ( 4) IP address leasetime 18000 (5h) OPTION: 58 ( 4) T1 9000 (2h30m) OPTION: 59 ( 4) T2 15750 (4h22m30s) OPTION: 1 ( 4) Subnet mask 255.255.255.0 OPTION: 28 ( 4) Broadcast address 192.168.5.255 OPTION: 3 ( 4) Routers 192.168.5.1 OPTION: 6 ( 4) DNS server 192.168.5.1 OPTION: 15 ( 8) Domainname home.pvt OPTION: 12 ( 3) Host name Nokia_E63 TIME: 2009-10-30 12:15:46.944 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: ccafe769 SECS: 14 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:46.944 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: ccafe769 SECS: 14 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 0.0.0.0 SIADDR: 0.0.0.0 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 1 (DHCPDISCOVER) OPTION: 50 ( 4) Request IP address 0.0.0.0 OPTION: 61 ( 7) Client-identifier 01:11:22:33:44:55:66 OPTION: 55 ( 7) Parameter Request List 12 (Host name) 6 (DNS server) 15 (Domainname) 1 (Subnet mask) 3 (Routers) 28 (Broadcast address) 120 (SIP Servers DHCP Option) OPTION: 57 ( 2) Maximum DHCP message size 576 TIME: 2009-10-30 12:15:46.945 IP: 192.168.5.1 (a:bb:cc:dd:ee:ff) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 2 (BOOTPREPLY) HTYPE: 1 (Ethernet) HLEN: 6 HOPS: 0 XID: ccafe769 SECS: 14 FLAGS: 7f80 CIADDR: 0.0.0.0 YIADDR: 192.168.5.21 SIADDR: 192.168.5.1 GIADDR: 0.0.0.0 CHADDR: 11:22:33:44:55:66:00:00:00:00:00:00:00:00:00:00 SNAME: . FNAME: . OPTION: 53 ( 1) DHCP message type 2 (DHCPOFFER) OPTION: 54 ( 4) Server identifier 192.168.5.1 OPTION: 51 ( 4) IP address leasetime 18000 (5h) OPTION: 58 ( 4) T1 9000 (2h30m) OPTION: 59 ( 4) T2 15750 (4h22m30s) OPTION: 1 ( 4) Subnet mask 255.255.255.0 OPTION: 28 ( 4) Broadcast address 192.168.5.255 OPTION: 3 ( 4) Routers 192.168.5.1 OPTION: 6 ( 4) DNS server 192.168.5.1 OPTION: 15 ( 8) Domainname home.pvt OPTION: 12 ( 3) Host name Nokia_E63 TIME: 2009-10-30 12:15:48.952 IP: 0.0.0.0 (1:22:33:44:55:66) 255.255.255.255 (ff:ff:ff:ff:ff:ff) OP: 1 (BOOTPREQUEST) HTYPE: 1 (Ethernet) HLEN: 6 ... and so on ...

    Read the article

  • Can Visual Studio track the "size" or "severity" of my changes in TFS?

    - by anaximander
    I'm working on a sizeable project using VS2012 and TFS (also 2012, I think - I didn't set up the server). A lot of my recent tasks have required making very small changes to a lot of files, so I'm quite used to seeing a lot of items in my Pending Changes list. Is there a way to have VS and/or TFS track how much has been changed and let me know when the differences are becoming significant? Similarly, is there a way to quickly highlight where the major changes are when you get the latest version from TFS? It'd really help with tracking down where certain changes have been made without having to go through and compare every file - the difference highlighting tool might be nice, but when you have to use it on a dozen files to find the block you're looking for, you start to wonder if there's a faster way...

    Read the article

  • Using a type parameter and a pointer to the same type parameter in a function template

    - by Darel
    Hello, I've written a template function to determine the median of any vector or array of any type that can be sorted with sort. The function and a small test program are below: #include <algorithm> #include <vector> #include <iostream> using namespace::std; template <class T, class X> void median(T vec, size_t size, X& ret) { sort(vec, vec + size); size_t mid = size/2; ret = size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid]; } int main() { vector<double> v; v.push_back(2); v.push_back(8); v.push_back(7); v.push_back(4); v.push_back(9); double a[5] = {2, 8, 7, 4, 9}; double r; median(v.begin(), v.size(), r); cout << r << endl; median(a, 5, r); cout << r << endl; return 0; } As you can see, the median function takes a pointer as an argument, T vec. Also in the argument list is a reference variable X ret, which is modified by the function to store the computed median value. However I don't find this a very elegant solution. T vec will always be a pointer to the same type as X ret. My initial attempts to write median had a header like this: template<class T> T median(T *vec, size_t size) { sort(vec, vec + size); size_t mid = size/2; return size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid]; } I also tried: template<class T, class X> X median(T vec, size_t size) { sort(vec, vec + size); size_t mid = size/2; return size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid]; } I couldn't get either of these to work. My question is, can anyone show me a working implementation of either of my alternatives? Thanks for looking!

    Read the article

  • merging UIImagePickerController image with cameraOverlayView

    - by GameDev
    Im really in the need for some help and advice. Spent the last week on this and have now just become frustrated as i cant get it to work! Basically, im trying to merge two images into one image to display/save. First the user picks an image from album, it goes to edit image screen where user can move and scale the image. On this screen is an overlay image (320x480) for the person to align there eyes in. Once aligned I want to save this image (edited and overlay) into one and pass the image onto my next screen. It works fine when the image is filling the edit/crop box, but when the image is widescreen with top and bottom not filling the box, then when i save the image the coords of the overlay dont get saved correctly! Heres my code, ive tried various ways of doing this but have failed at every attempt :( - (void) imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info { // Access the cropped image from info dictionary UIImage *image = [info objectForKey:@"UIImagePickerControllerEditedImage"]; // Combine image with overlay before saving!! image = [self addOverlayToImage:image]; overlayGraphicView.image = nil; // Take the picture image to the post picture view controller postPictureView = [[PostPictureViewController alloc] init:image Company:companyName withLink:buyButtonLink]; [picker pushViewController:postPictureView animated:YES]; [picker release],picker = nil; } The problem is that the image picked (originalImage) could be of any height, my overlayImage is however always 320x480, its almost all transparent with just two eye images in center which i want to save over the original images eyes! - (UIImage*) addOverlayToImage:(UIImage*)originalImage { CGRect cgRect =[[UIScreen mainScreen] bounds]; CGSize size = cgRect.size; UIGraphicsBeginImageContext(size); [originalImage drawInRect:CGRectMake(0, 0, size.width, size.height)]; UIImage* overlayImage = [UIImage imageNamed:overlayGraphicName]; [(UIImage *)overlayImage drawInRect:CGRectMake(0, 0, size.width, size.height)]; UIImage *finalImage = UIGraphicsGetImageFromCurrentImageContext(); [finalImage retain]; UIGraphicsEndImageContext(); return finalImage; } I wish there was just an easy way to take a screenshot of whatever is in the edit crop box :( Please if someone could help me with this ASAP as I need to finish this in 1-2 days time! Thank you. EDIT:- I should also mention that with this I get the correct center of the screen and placement of the overlay on my next screen: [(UIImage *)overlayImage drawInRect:CGRectMake(0, 0, size.width, size.height)]; However, I am unable to work out the correct position of the main image especially as the height is different for every image if not fullscreen! I tried this to center it into the correct position but it doesnt work: [originalImage drawInRect:CGRectMake(0,(size.height/2 - originalImage.size.height/2), originalImage.size.width, originalImage.size.height)];

    Read the article

  • PHP image resize and rounded image corners dynamically

    - by Dan
    I'm working of a script that dynamically ads rounded edges to an image then crops it down to a certain size. At the moment the script ads the rounded edges to the picture but i cannot get it so the original image is resized to fit within the dimensons of the final outputted image (140px x 120px) The problem is that the orginal uploaded image depending on it's orginal dimensions change the size it is in the final PNG { $image_file = $_FILES['image']['tmp_name']; $corner_radius = isset($_GET['radius']) ? $_GET['radius'] : 20; // The default corner radius is set to 20px $topleft = (isset($_GET['topleft']) and $_GET['topleft'] == "no") ? false : true; // Top-left rounded corner is shown by default $bottomleft = (isset($_GET['bottomleft']) and $_GET['bottomleft'] == "no") ? false : true; // Bottom-left rounded corner is shown by default $bottomright = (isset($_GET['bottomright']) and $_GET['bottomright'] == "no") ? false : true; // Bottom-right rounded corner is shown by default $topright = (isset($_GET['topright']) and $_GET['topright'] == "no") ? false : true; // Top-right rounded corner is shown by default $imagetype=$_FILES['image']['type']; $endsize=$corner_radius; $startsize=$endsize*3-1; $arcsize=$startsize*2+1; if (($imagetype=='image/jpeg') or ($imagetype=='jpg')) { $image = imagecreatefromjpeg($image_file); } else { if (($imagetype=='GIF') or ($imagetype=='gif')) { $image = imagecreatefromgif($image_file); } else { $image = imagecreatefrompng($image_file); } } $forecolor ='#ffffff'; $size = getimagesize($image_file); // Top-left corner $background = imagecreatetruecolor($size[0],$size[1]); imagecopymerge($background, $image, 0, 0, 0, 0, $size[0], $size[1], 100); $startx=$size[0]*2-1; $starty=$size[1]*2-1; $im_temp = imagecreatetruecolor($startx,$starty); imagecopyresampled($im_temp, $background, 0, 0, 0, 0, $startx, $starty, $size[0], $size[1]); $bg = imagecolorallocate($im_temp, 255,255,255); $fg = imagecolorallocate($im_temp, 255,255,255); if ($topleft == true) { if(!imagearc($im_temp, $startsize, $startsize, $arcsize, $arcsize, 180,270,$bg))echo "nope"; imagefilltoborder($im_temp,0,0,$bg,$bg); } // Bottom-left corner // Top-right corner if ($topright == true) { imagearc($im_temp, $startx-$startsize, $startsize,$arcsize, $arcsize, 270,360,$bg); imagefilltoborder($im_temp,$startx,0,$bg,$bg); } $image = imagecreatetruecolor(140,120); imagecopyresampled($image, $im_temp, 0, 0, 0, 0, $size[0],$size[1],$starty+1310,$startx+1500); // Output final image if(!imagepng($image,'hello.png')) echo "boo"; if(!imagedestroy($image)) echo "2"; if(!imagedestroy($background)) echo "3"; if(!imagedestroy($im_temp)) echo "4"; } EDIT: My question is how to get the orginal image reized so it fits into the 140 x 120 image that is processed with the rounded edges?

    Read the article

< Previous Page | 107 108 109 110 111 112 113 114 115 116 117 118  | Next Page >