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  • curious about the cached old domain

    - by jogesh_p
    i am a bit curious about my new Domain, actually i had a domain before let say http://example.com before expiration of that domain i bought a new one, with the name http://another-domain.com i uploaded all of my content on the second domain, but now when i search in google about some query related to my another-domain.com then i also find my old domain that is http://example.com is this provide the dulplicate content error to my http://another-domain.com ?? or any kind of penalty by Google

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  • A Great Idea I Never Had. Better Elevator Automation, no Buttons in Elevator.

    After my second year at engineering school (Cornell University), I spent the summer working in a dream job as an intern at the world famous Ford Design Center in Dearborn Michigan.  The group I worked in was an elite group of engineers whose responsibilities were to figure out better ways to build the cars that [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Get rid of 0.5s latency when playing audio over Bluetooth with A2DP

    - by brillout.com
    As described in the title I experience a half a second delay when playing audio over Bluetooth with A2DP. This makes watching movies not possible as the sound is not synchronised with the video. I'm not sure if the delay is caused by the Bluetooth connection, the A2PD protocol, or the A2DP implementation on my Ubuntu 12.04. Anyways, is this a normal lag? Is there a way to play audio over Bluetooth without any latency?

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  • Java - Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • Criteria for selecting timeout value?

    - by stijn
    Situation: a piece of software reads frames of data from a file in a seperate thread and puts it on a queue, emptied by another thread. That second thread periodically checks on the queue and fails rather gracefully, by showing an error message stating the read timed out, if no data is available within a certain amount of time. Initially this timeout was set to 200mSec. There was no real reasoning behind that constant though, but it worked fine. We measured on a couple of machines and for large data frames, larger than what would be used by customers, a read took like 20mSec whith no other load on the machine. However one customer now gets timeout errors now and then (on the second try all is fine, probably the file is in cache or the virus scanner leaves it alone). The programmers are like 'well, yeah, but that customer's machine is full of cruft, virus scanners, tons of unneeded background processes etc'. Of course the customer is like 'hey this should just work, shouldn't it'? While the programers have a point, since the software is heavy enough to validate the need for a dedicated machine, that does not make the customer happy. Increasing the timeout to 2 seconds, for example, solves the problem. But I'd like to make a proper decision now instead of just randomly pick some magic constant that is probably ok in 99% of cases. What criteria should be used for that? We could just pick a large number, but that feels wrong. (and then we end up with a program that has the horrible bahaviour of hanging when trying to read from a disconnected drive for instance, whereas we'd rather make it show an error right away). Or we could make the timeout value a user setting, but then we need to ducument it clearly and even then not all customers are tech savy enough to really understand what it does. Or we could try and wait until another customer reports timeouts and increase the value again. And again. Until we find something ok for 99.99% of the cases.. Any good practice for this type of situation?

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  • Time Capsule With Raspberry Pi

    - by Richard Jones
    So I have a Raspberry PI, with an 1TB external USB HD plugged into it. I have Debian Wheezy installed to which I added the NetaTalk package. Following this guide which is on Ubuntu, but was easy enough to understand - http://kremalicious.com/ubuntu-as-mac-file-server-and-time-machine-volume/ I was even able to change the icon to look like an X-Serve :-) Next step to add a second HD that will backup my Windows 8 laptop as well.

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  • Delete button in Ubuntu One Notes

    - by Jean MC13
    For the whishlist... The 'delete button' in Ubuntu One Notes is exactly in the same place as the 'save' button. So I saved a long note, but as my finger clicked two times on the save button, the second click was on the 'delete' one ! Lost without return possible. <:-(( This annoying feature could easily be changed : - put the delete button in another place - before deleting : ask for confirmation - offer a way to cancel ('undelete' function)

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  • Simple rendering produces minor stutter

    - by Ben
    For some reason, this game loop renders the movement of a simple rectangle with no stuttering. double currTime; double prevTime = System.nanoTime() / NANO_TO_SEC; double FPSTIMER = System.nanoTime(); double maxTimeDiff = 100.0 / 1000.0; double delta = 1.0 / 60.0; int processes = 0, frames = 0; while(true){ currTime = System.nanoTime() / NANO_TO_SEC; if(currTime - prevTime > maxTimeDiff) prevTime = currTime; if(currTime >= prevTime){ process(); processes++; prevTime += delta; if(currTime < prevTime){ render(); frames++; } } else{ try{ Thread.sleep((long) (1000 * (prevTime - currTime))); } catch(Exception e){} } if(System.nanoTime() - FPSTIMER > 1000000000.0){ System.out.println("Process: " + (1000 / processes) + "ms FPS: " + (1000 / frames) + "ms"); processes = frames = 0; FPSTIMER += 1000000000.0; } } But for this game loop, I get really minor stuttering where the movement does not look smooth. long prevTime = System.currentTimeMillis(); long prevRenderTime = 0; long currRenderTime = 0; long delta = 0; long msPerTick = 1000 / 60; int frames = 0; int ticks = 0; double FPSTIMER = System.currentTimeMillis(); while (true){ long currTime = System.currentTimeMillis(); delta += (currTime - prevTime) / msPerTick; prevTime = currTime; while (delta >= 1){ ticks++; process(); delta -= 1; } prevRenderTime = System.currentTimeMillis(); render(); frames++; currRenderTime = System.currentTimeMillis(); try{ Thread.sleep((long) ((1000 / FPS) - (currRenderTime - prevRenderTime))); } catch(Exception e){} if(System.currentTimeMillis() - FPSTIMER > 1000.0){ System.out.println("Process: " + (1000.0 / ticks) + "ms FPS: " + (1000.0 / frames) + "ms"); ticks = frames = 0; FPSTIMER += 1000.0; } Is there any critical difference that I'm missing here? The one thing I noticed is that if I uncap the fps for the second game loop, the stuttering goes away. It doesn't make sense to me. Also, the second game loop came from Notch's Minicraft code with just my thread sleeping code added in.

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  • How to save and retrieve data as key-value pairs or files in isolated storage?

    - by kaleidoscope
    One can use isolated storage to store data locally on the user's computer. There are two ways to use isolated storage. The first way is to save or retrieve data as key/value pairs by using the IsolatedStorageSettings class. The second way is to save or retrieve files by using the IsolatedStorageFile class. More details can be found at http://silverlight.net/learn/quickstarts/isolatedstorage/   Rituraj, J

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  • Set-based Speed Phreakery: The FIFO Stock Inventory SQL Problem

    The SQL Speed Freak Challenge is a no-holds-barred competition to find the fastest way in SQL Server to perform a real-life database task. It is the programming equivalent of drag racing, but without the commentary box. Kathi has stepped in to explain what happened with the second challenge and why some SQL ran faster than others.

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  • Car brands and models licensing

    - by Ju-v
    We are small team which working on car racing game but we don't know about licensing process for branded cars like Nissan, Lamborghini, Chevrolet and etc. Do we need to buy any licence for using real car brand names, models, logos,... or we can use them for free? Second option we think about using not real brand with real models is it possible? If someone have experience with that, fell free to share it. Any information about that is welcome.

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  • Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • Windows 8 Initial User Experience

    - by Kevin Shyr
    Today is the second day I'm using a Windows 8 laptop.  Load up time is fast, and changing applications is very smooth.  However, I keep finding myself hitting the windows key (double-clicking a PDF file, and, what?  How do I get back?)Other than that, the experience has been fine.  So far this has not been any worse than other windows upgrade experience I had so far.  No bad news is good news here.

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  • How can I optimize Apache to use 1GB of RAM on my website? [closed]

    - by Markon
    My VPS plan gives me 1GB of RAM burstable to 2GB. Of course I cannot use 2 GB, nor 1 GB, everyday, so I'm planning to optimize the performance of my webserver. The average of hits-per-hour is about 8'000-10'000. This means about 2 connections-per-second. Max hits-per-hour reached until now is about 60'000. That means about 16 connections-per-second. Unluckily my current apache configuration uses too much memory (when there are not connected clients - usually during the night - it uses about 1GB) so I've tried to customize the apache installation to fit to my needs. I'm using Ubuntu, kernel 2.6.18, with apache2-mpm-worker, since I've read it requires less memory, and fcgid ( + PHP). This is my /etc/apache2/apache2.conf: Timeout 45 KeepAlive on MaxKeepAliveRequests 100 KeepAliveTimeout 10 <IfModule mpm_worker_module> StartServer 2 MinSpareThreads 25 MaxSpareThreads 75 MaxClients 100 MaxRequestsPerChild 0 </IfModule> This is the output of ps aux: www-data 9547 0.0 0.3 423828 7268 ? Sl 20:09 0:00 /usr/sbin/apache2 -k start root 17714 0.0 0.1 76496 3712 ? Ss Feb05 0:00 /usr/sbin/apache2 -k start www-data 17716 0.0 0.0 75560 2048 ? S Feb05 0:00 /usr/sbin/apache2 -k start www-data 17746 0.0 0.1 76228 2384 ? S Feb05 0:00 /usr/sbin/apache2 -k start www-data 20126 0.0 0.3 424852 7588 ? Sl 19:24 0:02 /usr/sbin/apache2 -k start www-data 24260 0.0 0.3 424852 7580 ? Sl 19:42 0:01 /usr/sbin/apache2 -k start while this is ps aux for php5: www-data 7461 2.9 2.2 142172 47048 ? S 19:39 1:39 /usr/lib/cgi-bin/php5 www-data 23845 1.3 1.7 135744 35948 ? S 20:17 0:15 /usr/lib/cgi-bin/php5 www-data 23900 2.0 1.7 136692 36760 ? S 20:17 0:22 /usr/lib/cgi-bin/php5 www-data 27907 2.0 2.0 142272 43432 ? S 20:00 0:43 /usr/lib/cgi-bin/php5 www-data 27909 2.5 1.9 138092 40036 ? S 20:00 0:53 /usr/lib/cgi-bin/php5 www-data 27993 2.4 2.2 142336 47192 ? S 20:01 0:50 /usr/lib/cgi-bin/php5 www-data 27999 1.8 1.4 135932 31100 ? S 20:01 0:38 /usr/lib/cgi-bin/php5 www-data 28230 2.6 1.9 143436 39956 ? S 20:01 0:54 /usr/lib/cgi-bin/php5 www-data 30708 3.1 2.2 142508 46528 ? S 19:44 1:38 /usr/lib/cgi-bin/php5 As you can see it use a lot of memory. How can I reduce it to fit to just 1GB of RAM? PS: I also think about the switch to nginx, if Apache can't fit to my needs...

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  • Menus intermittantly take two clicks

    - by heynnema
    Intermittently, when I left-click on the Applications/Places/System menus, the first click does nothing, and it takes a second click to drop the menu. I've also noticed that hiarchial menus sometimes don't show their expanded menus unless I move the mouse pointer away to another menu item, and then come back into the hiarchial menu. And lately, I've even noticed that in some applications, menus are acting the same way. Any ideas? Cheers, Al

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  • Yahoo media player not working with Ruby on rails

    - by luca590
    I have a yahoo media player embedded in my webpage. I am currently using Ruby on Rails to create/edit my web page. When i click the play button next to a track the YMP waits a while and then goes to the next track without playing the first one. I then get a warning on my second (last) track that its file could not be found. Does anyone has a better recommendation for an audio player or a way to fix this one?

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  • The Science of Creating a Money Making Keyword List

    Creating a money making keyword list is the foundation of your website marketing strategy. If your keyword list contains the right words or phrases then you will see plenty of traffic finding your site. If the keywords are not specific enough or are too general then your traffic will suffer and those that do happen to find your site may just look around a second or two and then move on.

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  • The Science of Creating a Money Making Keyword List

    Creating a money making keyword list is the foundation of your website marketing strategy. If your keyword list contains the right words or phrases then you will see plenty of traffic finding your site. If the keywords are not specific enough or are too general then your traffic will suffer and those that do happen to find your site may just look around a second or two and then move on.

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  • Desktop Fun: Moonlit Nights Wallpaper Collection Series 2

    - by Asian Angel
    Last year we shared a gorgeous collection of Moonlit Nights wallpapers with you and today we are back with more Lunar goodness. Turn your desktop into a night-time paradise with the second in our series of Moonlit Nights Wallpaper collections. HTG Explains: What Is Windows RT and What Does It Mean To Me? HTG Explains: How Windows 8′s Secure Boot Feature Works & What It Means for Linux Hack Your Kindle for Easy Font Customization

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  • Terrain square loading

    - by AndroidXTr3meN
    Games like Skyrim, Morrowind, and more are using quads or square to divide the terrain if im correct. The player is always at #5 1 | 2 | 3 4 | 5 | 6 7 | 8 | 9 So whenever you cross the border you unload and load the new "areas" But if the user goes just over the edge and then the second after goes back previous area a lot of unnecessary loading and unloading is done. Is there a general approach to this because I dont think games like skyrim have this issue? Cheers!

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  • How can I change the "timeout" duration for Nautilus "find the filename as you type" feature?

    - by fred.bear
    I often get stalled by the long timeout while typeing the first few letters of a file name in Nautilus... The current timeout seems to be 5 seconds. I'd prefer 1 second ...(as per item 2 on this page about Response Times) I don't use the mouse much, which means I either wait, or press Escape, when I don't find the file... I realize that this is a feature to some, but I'd rather not wait. Is there any way to change this timeout behaviour?

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  • WebCenter Content Web Search Performance: Do you really need that folder path info?

    - by Nicolas Montoya
    End-users want content at their fingertips at the speed of thought if possible. When running search operations in the WebCenter Conter Web Interface every second or fraction of a second improvement does matter. When doing some trace analysis on the systemdatabase tracing on a customer environment, we came across some SQL queries that were unnecessarily being triggered! These were related to determining the folder path for every entry part of the search result set. However, this folder path was not even being used as part of the displayed information in the user interface.Why was the folder path information being collected when it was not even displayed in the UI? We found that the configuration parameter 'FolderPathInSearchResults' was set to 'true' under Administration > Admin Server > General Configuration > Additional Configuration Variables as shown below:When executing a quicksearch by keyword we were getting 100 out of 2280 entries in the first page of the result set.When thera 'FolderPathInSearchResults' configuration parameter is set to 'true', the following queries appear in the systemdatabase tracing:100 executions for a query on the FolderFiles table for each of the documents displayed in the first page:>systemdatabase/6       12.13 11:17:48.188      IdcServer-199   1.45 ms. SELECT * FROM FolderFiles WHERE dDocName='SLC02VGVUSORAC140641' AND fLinkRank=0[Executed. Returned row(s): true]382 executions for a query of the folders tables - most of the documents that match the keyword criteria are at a folder depth level of three or four:>systemdatabase/6       12.13 11:17:48.114      IdcServer-199   2.57 ms. SELECT FolderFolders.*,FolderMetaDefaults.* FROM FolderFolders,FolderMetaDefaults WHERE FolderFolders.fFolderGUID=FolderMetaDefaults.fFolderGUID(+) AND((FolderFolders.fFolderGUID = '1EB8E527E19B09ED3FE82EE310AEA13A' ) )[Executed.Returned row(s): true]By setting this 'FolderPathInSearchResults' configuration parameter to 'false', the above queries were no longer reported in the Server Output System Audit Information.Now, let's consider a practical scenario:Search result set page = 100Average folder depth der document in the search result set: 5The number of folder path related queries will be: 100 + 5*500 = 600If each query takes slightly over 3 ms. You would have 2000 ms (2 seconds) spent in server time to get this information.The overall performance impact goes beyond seerver time execution, as this information needs to travel from the server to the browser. If the documents are further nested into the folder hierarchy, additional hundreds of queries may be executed. If folder path is not being displayed in the end-user interface profile, your system may be better of with the 'FolderPathInSearchResults' configuration parameter disabled.

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