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  • basic javascript question on geolocation and googlemaps

    - by ade
    hello all, Im hoping that somebody can help me out on what i feel is an easy answer but I just cant get it to work out. Im trying to trap the geolocation lat and long and place it into the google maps api so far i have var myOptions = { zoom:7, trips:1, mapTypeId: google.maps.MapTypeId.ROADMAP } var map = new google.maps.Map(document.getElementById("map"), myOptions); directionsDisplay.setMap(map); var request = { origin: 'newyork' destination: 'deleware', travelMode: google.maps.DirectionsTravelMode.DRIVING }; this works fine for what i want. how ever I want to be able to change Origin to the users lat long using the following script from google.maps.api. their code is: if(navigator.geolocation) { navigator.geolocation.getCurrentPosition(function(position) { initialLocation = new google.maps.LatLng(position.coords.latitude,position.coords.longitude); var placeMarker = new google.maps.Marker({ position: initialLocation, map: map, }); map.setCenter(initialLocation); }, function() { handleNoGeolocation(browserSupportFlag); }); } else { // Browser doesn't support Geolocation handleNoGeolocation(); } function handleNoGeolocation() { initialLocation = newyork; map.setCenter(initialLocation); } I want to pull out the navigator.geolocation.getCurrentPosition(function(position) { initialLocation = new google.maps.LatLng(position.coords.latitude,position.coords.longitude); and allocate it two 2 varibles, myLat and myLong. I then want to be able to change my orignal script from var request = { origin: 'newyork' destination: 'deleware', travelMode: google.maps.DirectionsTravelMode.DRIVING }; to var request = { origin: myLat,myLong destination: 'deleware', travelMode: google.maps.DirectionsTravelMode.DRIVING }; Does this make sense..? Im currently having a pig with it and as im not a JS developer its what i think should be a simple bit of coding that im losing the battle with.. any thoughts..?

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  • hover effect jQuery

    - by Ori Cohen
    I have a bunch of li elements that I want to alternate in color using odds and evens, and then highlight based on mouse hover. In order to un-highlight I need to keep track of what the color used to be, odd or even. To do this when I apply the highlight color, I first set an arbitrary attribute to it. Are there any downsides to doing it this way? Is there a better way? Here's the code: <script type="text/javascript"> var init = function(event){ $("li:odd").css({'background-color' : '#eeeeee', 'font-weight' : 'bold'}); $("li:even").css('background-color', '#cccccc'); //initial colors setup $("li").hover( function () //hover over { var current = $(this); current.attr('old-background', current.css('background-color')); current.css('background-color', '#ffee99'); } , function() //hover out { var current = $(this); current.css('background-color', current.attr('old-background')); }) } $(document).ready(init); </script> So is there a better way to do this?

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  • Generics with constraints hierarchy

    - by devoured elysium
    I am currently facing a very disturbing problem: interface IStateSpace<Position, Value> where Position : IPosition // <-- Problem starts here where Value : IValue // <-- and here as I don't { // know how to get away this // circular dependency! // Notice how I should be // defining generics parameters // here but I can't! Value GetStateAt(Position position); void SetStateAt(Position position, State state); } As you'll down here, both IPosition, IValue and IState depend on each other. How am I supposed to get away with this? I can't think of any other design that will circumvent this circular dependency and still describes exactly what I want to do! interface IState<StateSpace, Value> where StateSpace : IStateSpace where Value : IValue { StateSpace StateSpace { get; }; Value Value { get; set; } } interface IPosition { } interface IValue<State> where State : IState { State State { get; } } Basically I have a state space IStateSpace that has states IState inside. Their position in the state space is given by an IPosition. Each state then has one (or more) values IValue. I am simplifying the hierarchy, as it's a bit more complex than described. The idea of having this hierarchy defined with generics is to allow for different implementations of the same concepts (an IStateSpace will be implemented both as a matrix as an graph, etc). Would can I get away with this? How do you generally solve this kind of problems? Which kind of designs are used in these cases? Thanks

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  • How to do OrderBY on XML column in SQL SERVER 2008

    - by Rohit
    I am creating a comma seperated values of columns specified in dbName attribute of below xml. Now i want to concatenate those columns on the basic of Position attribute. DECLARE @varXML AS XML = '<gridFormat> <column property="FacilityInternalID" dbName="Pname" HeaderText="TAT Health" IsVisible="1" Position="1" /> <column property="FacilityInternalID" dbName="Priority" HeaderText="Priority" IsVisible="1" Position="2" /> <column property="FacilityInternalID" dbName="JobID" HeaderText="Job Number" IsVisible="1" Position="3" /> <column property="FacilityInternalID" dbName="Status" HeaderText="Status" IsVisible="1" Position="6" /> <column property="FacilityInternalID" dbName="name" HeaderText="Customer" IsVisible="1" Position="4" /> <column property="FacilityInternalID" dbName="sname" HeaderText="Facility " IsVisible="1" Position="5" /> </gridFormat>' PRINT @varXML This is the query by which I am generating CSV of columns. I have to use it is select list. SELECT @ColumnsToDisplay = LEFT(MyCsvList, LEN(MyCsvList) - 1) FROM ( SELECT ( SELECT row.value('@property', 'varchar(200)') + ', ' AS [text()] FROM @varXML.nodes('gridFormat/column') AS d ( row ) FOR XML PATH('') ) AS MyCsvList ) AS MyCsvListFinal SET @SQL = 'SELECT ' + @ColumnsToDisplay + ' FROM JobListingDetails' Result should be select Pname,Priority,JobID,name,sname,status FROM JobListingDetails. Please help.

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  • How to get the "real" colors when exporting a GDI drawing to bmp

    - by Rodrigo
    Hi guys I'm developing a ASP.Net web handler that returns images making a in-memory System.Windows.Forms.Control and then exports the rendered control as a bitmap compressed to PNG, using the method DrawToBitmap(). The classes are fully working by now, except for a problem with the color assignment. By example, this is a Gauge generated by the web handler. The colors assigned to the inner parts of the gauge are red (#FF0000), yellow (#FFFF00) and green (#00FF00) but I only get a dully version of each color (#CB100F for red, #CCB70D for yellow and #04D50D for green). The background is a bmp file containing the color gradient. The color loss happens whether the background is a gradient as the sample, a black canvas, a white canvas, a transparent canvas, even when there is not a background set. With black background With transparent background With a white background Without a background set With pixel format in Format32bppArgb I've tried multiple bitmap color deeps, output formats, compression level, etc. but none of them seems to work. Any ideas? This is a excerpt of the source code: Bitmap bmp = new Bitmap(w, h, System.Drawing.Imaging.PixelFormat.Format32bppPArgb); Image bgimage = (Image) HttpContext.GetGlobalResourceObject("GraphicResources", "GaugeBackgroundImage"); Canvas control_canvas = new Canvas(); .... //the routine that makes the gauge .... control_canvas.DrawToBitmap(bmp, new Rectangle(0, 0, w, h));

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  • Pong: How does the paddle know where the ball will hit?

    - by Roflcoptr
    After implementing Pacman and Snake I'm implementing the next very very classic game: Pong. The implementation is really simple, but I just have one little problem remaining. When one of the paddle (I'm not sure if it is called paddle) is controlled by the computer, I have trouble to position it at the correct position. The ball has a current position, a speed (which for now is constant) and a direction angle. So I could calculate the position where it will hit the side of the computer controlled paddle. And so Icould position the paddle right there. But however in the real game, there is a probability that the computer's paddle will miss the ball. How can I implement this probability? If I only use a probability of lets say 0.5 that the computer's paddle will hit the ball, the problem is solved, but I think it isn't that simple. From the original game I think the probability depends on the distance between the current paddle position and the position the ball will hit the border. Does anybody have any hints how exactly this is calculated?

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  • Python: deleting rows in a text file

    - by Jenny
    A sample of the following text file i have is: > 1 -4.6 -4.6 -7.6 > > 2 -1.7 -3.8 -3.1 > > 3 -1.6 -1.6 -3.1 the data is separated by tabs in the text file and the first column indicates the position. I need to iterate through every value in the text file apart from column 0 and find the lowest value. once the lowest value has been found that value needs to be written to a new text file along with the column name and position. Column 0 has the name "position" Column 1 "fifteen", column 2 "sixteen" and column 3 "seventeen" for example the lowest value in the above data is "-7.6" and is in column 3 which has the name "seventeen". Therefore "7.6", "seventeen" and its position value which in this case is 1 need to be written to the new text file. I then need a number of rows deleted from the above text file. E.G. the lowest value above is "-7.6" and is found at position "1" and is found in column 3 which as the name "seventeen". I therefore need seventeen rows deleted from the text file starting from and including position 1 so the the column in which the lowest value is found denotes the amount of rows that needs to be deleted and the position it is found at states the start point of the deletion

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  • How to tell if you touched a CCLabel? (Cocos2d Question)

    - by RexOnRoids
    How to tell if you touched a CCLabel? The following code obviously does not work well enough because it only tests for point equality. Naturally touch point will not necessarily be equal to the position property of the CCLabel (CCNode). How to I tell if a Touch point has fallen within the "rectangle?" of the CCLabel? - (void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { for( UITouch *touch in touches ) { CGPoint location = [touch locationInView: [touch view]]; location = [[CCDirector sharedDirector] convertToGL:location]; self.myGraphManager.isSliding = NO; if(CGPointEqualToPoint(location, label1.position)){ NSLog(@"Label 1 Touched"); }else if(CGPointEqualToPoint(location, label2.position)){ NSLog(@"Label 2 Touched"); }else if(CGPointEqualToPoint(location, label3.position)){ NSLog(@"Label 3 Touched"); }else if(CGPointEqualToPoint(location, label4.position)){ NSLog(@"Label 4 Touched"); }else if(CGPointEqualToPoint(location, label5.position)){ NSLog(@"Label 5 Touched"); }else if(CGPointEqualToPoint(location, label6.position)){ NSLog(@"Label 6 Touched"); } NSLog(@"Touch Made!"); } }

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  • error in a pygame code

    - by mekasperasky
    # INTIALISATION import pygame, math, sys from pygame.locals import * screen = pygame.display.set_mode((1024, 768)) car = pygame.image.load('car.png') clock = pygame.time.Clock() k_up = k_down = k_left = k_right = 0 speed = direction = 0 position = (100, 100) TURN_SPEED = 5 ACCELERATION = 2 MAX_FORWARD_SPEED = 10 MAX_REVERSE_SPEED = ­5 BLACK = (0,0,0) while 1: # USER INPUT clock.tick(30) for event in pygame.event.get(): if not hasattr(event, 'key'): continue down = event.type == KEYDOWN # key down or up? if event.key == K_RIGHT: k_right = down * ­5 elif event.key == K_LEFT: k_left = down * 5 elif event.key == K_UP: k_up = down * 2 elif event.key == K_DOWN: k_down = down * ­2 elif event.key == K_ESCAPE: sys.exit(0) # quit the game screen.fill(BLACK) # SIMULATION # .. new speed and direction based on acceleration and turn speed += (k_up + k_down) if speed > MAX_FORWARD_SPEED: speed = MAX_FORWARD_SPEED if speed < MAX_REVERSE_SPEED: speed = MAX_REVERSE_SPEED direction += (k_right + k_left) # .. new position based on current position, speed and direction x, y = position rad = direction * math.pi / 180 x += ­speed*math.sin(rad) y += ­speed*math.cos(rad) position = (x, y) # RENDERING # .. rotate the car image for direction rotated = pygame.transform.rotate(car, direction) # .. position the car on screen rect = rotated.get_rect() rect.center = position # .. render the car to screen screen.blit(rotated, rect) pygame.display.flip() enter code here the error i get is this Non-ASCII character '\xc2' in file race1.py on line 13, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details Not able to understand what the error is and how to get rid of it?

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  • Web service performing asynchronous call

    - by kornelijepetak
    I have a webservice method FetchNumber() that fetches a number from a database and then returns it to the caller. But just before it returns the number to the caller, it needs to send this number to another service so instantiates and runs the BackgroundWorker whose job is to send this number to another service. public class FetchingNumberService : System.Web.Services.WebService { [WebMethod] public int FetchNumber() { int value = Database.GetNumber(); AsyncUpdateNumber async = new AsyncUpdateNumber(value); return value; } } public class AsyncUpdateNumber { public AsyncUpdateNumber(int number) { sendingNumber = number; worker = new BackgroundWorker(); worker.DoWork += asynchronousCall; worker.RunWorkerAsync(); } private void asynchronousCall(object sender, DoWorkEventArgs e) { // Sending a number to a service (which is Synchronous) here } private int sendingNumber; private BackgroundWorker worker; } I don't want to block the web service (FetchNumber()) while sending this number to another service, because it can take a long time and the caller does not care about sending the number to another service. Caller expects this to return as soon as possible. FetchNumber() makes the background worker and runs it, then finishes (while worker is running in the background thread). I don't need any progress report or return value from the background worker. It's more of a fire-and-forget concept. My question is this. Since the web service object is instantiated per method call, what happens when the called method (FetchNumber() in this case) is finished, while the background worker it instatiated and ran is still running? What happens to the background thread? When does GC collect the service object? Does this prevent the background thread from executing correctly to the end? Are there any other side-effects on the background thread? Thanks for any input.

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  • Why does my Google maps api v3 and side panel not fill my page upon resizing?

    - by Gavin
    I'm developing a web page and I have a side panel on the left with a search bar and a Google maps api v3 filling the rest of the page to the right. When I make the browser very small vertically, there is a white space between the side panel and the map, and the bottom of the browser. However, the text continues to the bottom of the browser. It looks like: Here's my css code: <style type="text/css"> body {margin:0;} #panel {height:100%; width:300px; position:absolute; padding:0;background-color:#8C95A0;} #header {padding:2px; text-align:center} #address_instruction {position:relative; top:7%; padding:2px; text-align:center} #geocoder {position:relative; top:8%; padding:2px; text-align:center} #toggle_instruction {position:relative; top:22%; padding:2px; text-align:center} #layers {position:relative; top:25%; padding:2px; text-align:center} #layer0 {padding:2px; text-align:center} #layer1 {padding:2px; text-align:center} #layer2 {padding:2px; text-align:center} #link {top:50%; position:relative; padding:2px; text-align:center} #map_canvas {height:100%; left:300px; right:0px; position:absolute; padding:0;} </style> The IDs within #panel refer to the items on the left hand side in the panel. Why don't the side panel background color and map extend to the bottom of the browser?

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  • Efficient mapping of game entity positions in Java

    - by byte
    In Java (Swing), say I've got a 2D game where I have various types of entities on the screen, such as a player, bad guys, powerups, etc. When the player moves across the screen, in order to do efficient checking of what is in the immediate vicinity of the player, I would think I'd want indexed access to the things that are near the character based on their position. For example, if player 'P' steps onto element 'E' in the following example... | | | | | | | | | |P| | | | |E| | | | | | | | | ... would be to do something like: if(player.getPosition().x == entity.getPosition().x && entity.getPosition.y == thing.getPosition().y) { //do something } And thats fine, but that implies that the entities hold their positions, and therefor if I had MANY entities on the screen I would have to loop through all possible entities available and check each ones position against the player position. This seems really inefficient especially if you start getting tons of entities. So, I would suspect I'd want some sort of map like Map<Point, Entity> map = new HashMap<Point, Entity>(); And store my point information there, so that I could access these entities in constant time. The only problem with that approach is that, if I want to move an entity to a different point on the screen, I'd have to search through the values of the HashMap for the entity I want to move (inefficient since I dont know its Point position ahead of time), and then once I've found it remove it from the HashMap, and re-insert it with the new position information. Any suggestions or advice on what sort of data structure / storage format I ought to be using here in order to have efficient access to Entities based on their position, as well as Position's based on the Entity?

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  • CSS Square Div with an Inward Oval Shape

    - by user2813099
    I am trying to create a div in css with an inward oval shape to it like this. At the moment, I have a shape that is outward instead of inward (JS Fiddle Link). .shape { float: left; width: 100px; height: 50px; border: none; background: #CC0000; border-radius: 0 90px 0 0; -moz-border-radius: 0 90px 0 0; -webkit-border-radius: 0 90px 0 0; background-image: -webkit-gradient( linear, left top, right bottom, color-stop(0, #520C0C), color-stop(1, #CC0000) ); background-image: -o-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -moz-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -webkit-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: -ms-linear-gradient(right bottom, #520C0C 0%, #CC0000 100%); background-image: linear-gradient(to right bottom, #520C0C 0%, #CC0000 100%); } Any ideas on how to go about this?

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  • CSS Sprite for images which have vertical as well as horizontal repeats

    - by Rachel
    I have four images, one of which has background repeat property in horizontal direction and three of which have background repeat in vertical direction. I have different CSS classes which currently uses this images as under: .sb_header_dropdown { background: url(images/shopping_dropdown_bg.gif) repeat-y top left; padding: 8px 3px 8px 15px; } .shopping_basket_dropdown .sb_body { background: url(images/shopping_dropdown_body_bg.png) repeat-y top left; margin: 0; padding: 5px 9px 5px 8px; position: relative; z-index: 99999; } .checkout_cart .co_header_left { background: url(images/bg.gif) repeat-x 0 -150px; overflow: hidden; padding-left: 3px; } .sb_dropdown_footer { background: url(images/shopping_dropdown_footer_bg.png) repeat-y top left; clear: both; height: 7px; font-size: 0; } So here am making 4 HTTP Request and I want to implement CSS Sprite for all 4 images such that I can reduce the number of HTTP Request from 4 to 1, also thing to keep in mind is that here we have background repeat for all 4 images, either on x-direction or on y-direction and so how should sprite be created and how it can be used in the CSS to reduce the number of HTTP request. I hope this question is clear.

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  • XAML PixelGrid to Prevent Blurry Text

    - by Bodekaer
    Hi, Just wanted to share a small Grid I created, which can help prevent blurry text etc. as it adjusts the margin of the Grid to ensure a pixel perfect position and size of the grid. Works great e.g. for inside StackPanels with auto height Labels/TextBlocks. Here is the code: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Windows; using System.Windows.Controls; using System.Windows.Media; namespace Controls { class PixelGrid : Grid { protected override void OnRenderSizeChanged(SizeChangedInfo sizeInfo) { // POSITION Vector position = VisualTreeHelper.GetOffset(this); double targetX = Math.Round(position.X, MidpointRounding.ToEven); double targetY = Math.Round(position.Y, MidpointRounding.ToEven); double marginLeft = targetX - position.X; double marginTop = targetY - position.Y; // SIZE double targetHeight = Math.Round(sizeInfo.NewSize.Height, MidpointRounding.ToEven); double targetWidth = Math.Round(sizeInfo.NewSize.Width, MidpointRounding.ToEven); double marginBottom = targetHeight - sizeInfo.NewSize.Height; double marginRight = targetWidth - sizeInfo.NewSize.Width; // Adjust margin to ensure pixel width this.Margin = new Thickness(marginLeft, marginTop, marginRight, marginBottom); base.OnRenderSizeChanged(sizeInfo); } } }

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  • On counting pairs of words that differ by one letter

    - by Quintofron
    Let us consider n words, each of length k. Those words consist of letters over an alphabet (whose cardinality is n) with defined order. The task is to derive an O(nk) algorithm to count the number of pairs of words that differ by one position (no matter which one exactly, as long as it's only a single position). For instance, in the following set of words (n = 5, k = 4): abcd, abdd, adcb, adcd, aecd there are 5 such pairs: (abcd, abdd), (abcd, adcd), (abcd, aecd), (adcb, adcd), (adcd, aecd). So far I've managed to find an algorithm that solves a slightly easier problem: counting the number of pairs of words that differ by one GIVEN position (i-th). In order to do this I swap the letter at the ith position with the last letter within each word, perform a Radix sort (ignoring the last position in each word - formerly the ith position), linearly detect words whose letters at the first 1 to k-1 positions are the same, eventually count the number of occurrences of each letter at the last (originally ith) position within each set of duplicates and calculate the desired pairs (the last part is simple). However, the algorithm above doesn't seem to be applicable to the main problem (under the O(nk) constraint) - at least not without some modifications. Any idea how to solve this?

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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • Binary Search Tree, cannot do traversal

    - by ihm
    Please see BST codes below. It only outputs "5". what did I do wrong? #include <iostream> class bst { public: bst(const int& numb) : root(new node(numb)) {} void insert(const int& numb) { root->insert(new node(numb), root); } void inorder() { root->inorder(root); } private: class node { public: node(const int& numb) : left(NULL), right(NULL) { value = numb; } void insert(node* insertion, node* position) { if (position == NULL) position = insertion; else if (insertion->value > position->value) insert(insertion, position->right); else if (insertion->value < position->value) insert(insertion, position->left); } void inorder(node* tree) { if (tree == NULL) return; inorder(tree->left); std::cout << tree->value << std::endl; inorder(tree->right); } private: node* left; node* right; int value; }; node* root; }; int main() { bst tree(5); tree.insert(4); tree.insert(2); tree.insert(10); tree.insert(14); tree.inorder(); return 0; }

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  • Extend footer wrap to width of page.

    - by hawkeye126
    I've made a footer wrap outside the content wrap (which everything else is in). I would like to make the footer wrap extend to fill the width of the page and I would like it to be fixed on the bottom. Here's the code: footerWrap { background-color:#000; width: auto; } footer { margin: auto; text-align:center; width:965px; height:150px; background-color:#000; border:#000 inset medium; } The website is item9andthemadhatters.com please let me know if you need any other code or info. Thanks!! update: html { padding:0; height:100%; width: 100%; } body{ margin: -1px 0 0 0; background-color:#FFF; font-family: calibri; background-image:url(images/item9HeaderSideFiller.gif); background-repeat: repeat-x; padding:0; height:100%; width: 100%; } wrap { width: 965px; margin:auto auto; min-height:462px; max-height:4000 px; footerWrap { background-color:#000; position:absolute; bottom:0; width:100% } footer { margin: auto; text-align:center; width:965px; height:150px; background-color:#000; } }

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  • bounding a sprite in cocos2d

    - by Srinivas
    am making a canon to fire objects. back of the canon the plunger is attached. plunger acts for set speed and angle. canon rotates 0-90 degree and plunger moves front and back for adjust speed. when am rotates the canon by touches moved its working fine. when plunger is pull back by touches moved and it rotates means the plunger is bounds outside of the canon. how to control this:- my code for plunger and canon rotation on touches moved. ( para3 is the canon , para6 is my plunger):- CGPoint touchLocation = [self convertTouchToNodeSpace:touch]; CGPoint oldTouchLocation = [touch previousLocationInView:touch.view]; oldTouchLocation = [[CCDirector sharedDirector] convertToGL:oldTouchLocation]; oldTouchLocation = [self convertToNodeSpace:oldTouchLocation]; if (CGRectContainsPoint(CGRectMake(para6.position.x-para6.contentSize.width/2, para6.position.y-para6.contentSize.height/2, para6.contentSize.width, para6.contentSize.height), touchLocation) && (touchLocation.y-oldTouchLocation.y == 0)) { CGPoint diff = ccpSub(touchLocation, oldTouchLocation); CGPoint currentpos = [para6 position]; NSLog(@"%d",currentpos); CGPoint destination = ccpAdd(currentpos, diff); if (destination.x < 90 && destination.x >70) { [para6 setPosition:destination]; speed = (70 + (90-destination.x))*3.5 ; } } if(CGRectIntersectsRect((CGRectMake(para6.position.x-para6.contentSize.width/8, (para6.position.y+30)-para6.contentSize.height/10, para6.contentSize.width, para6.contentSize.height/10)),(CGRectMake(para3.position.x-para3.contentSize.width/2, para3.position.y-para3.contentSize.height/2, para3.contentSize.width, para3.contentSize.height)))) { [para3 runAction:[CCSequence actions: [CCRotateTo actionWithDuration:rotateDuration angle:rotateDiff], nil]]; CGFloat plungrot = (rotateDiff); CCRotateTo *rot = [CCRotateTo actionWithDuration:rotateDuration angle:plungrot]; [para6 runAction:rot]; } }

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  • How to add Editext and Button to Efficent Adapter which has a Icon and text

    - by jayanthgande
    Hi, I want to create a layout in such a way that on top edittext and button should be there in one row. The search text I enter in editext and click on search button. Then I want to display a custom list view where each row contains image and text.(As per the API demos example list14 I have tried). But when I run the application, button and edittext are being added to each row (i.e., Each row contains a image, text, editext, button. Can Any one guide how to resolve this issue. Below is my xml file: <!-- <FrameLayout android:layout_width="wrap_content" android:layout_height="0dip" android:layout_weight="1"></FrameLayout> --> <ImageView android:id="@+id/icon" android:layout_width="48dip" android:layout_height="48dip" /> <TextView android:id="@+id/text" android:layout_gravity="center_vertical" android:layout_width="0dip" android:layout_weight="1.0" android:layout_height="wrap_content" /> <!-- <EditText android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/prdsearchtb" android:text="@string/tb_prd_search_lbl"></EditText> --> <!-- <TableLayout android:id="@+id/TableLayout01" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TableRow> --> <Button android:id="@+id/prdsrcbutton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/btn_lbl_prd_search" android:layout_x="2px" android:layout_y="410px"></Button> <!-- </TableRow> </TableLayout> -- and Java File: /** * */ package org.techdata.activity; import android.app.AlertDialog; import android.app.ListActivity; import android.content.Context; import android.content.Intent; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.util.Log; import android.view.LayoutInflater; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.Button; import android.widget.EditText; import android.widget.ImageView; import android.widget.ListView; import android.widget.TextView; /** * @author jayanthg * */ public class ProductSearch extends ListActivity { private static class ProductSearchAdapter extends BaseAdapter { private LayoutInflater mInflater; private Bitmap mIcon1; private Bitmap mIcon2; public ProductSearchAdapter(Context context) { mInflater = LayoutInflater.from(context); // Icons bound to the rows. mIcon1 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_1); mIcon2 = BitmapFactory.decodeResource(context.getResources(), R.drawable.icon48x48_2); } @Override public int getCount() { return DATA.length; } @Override public Object getItem(int position) { return position; } @Override public long getItemId(int position) { return position; } @Override public View getView(final int position, View convertView, ViewGroup parent) { ViewHolder holder; Button btn=null; if (convertView == null) { convertView = mInflater.inflate(R.layout.productsearch, null); // Creates a ViewHolder and store references to the two children // views // we want to bind data to. holder = new ViewHolder(); holder.text = (TextView) convertView.findViewById(R.id.text); holder.icon = (ImageView) convertView.findViewById(R.id.icon); btn=(Button)convertView.findViewById(R.id.prdsrcbutton); convertView.setTag(holder); } else { // Get the ViewHolder back to get fast access to the TextView // and the ImageView. holder = (ViewHolder) convertView.getTag(); } // Bind the data efficiently with the holder. holder.text.setText(DATA[position]); holder.icon.setImageBitmap((position & 1) == 1 ? mIcon1 : mIcon2); holder.icon.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("image", " u clicked on icon Position" + position); } }); holder.text.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Text", " u clicked on text Position" + position); } }); btn.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Log.i("Button","U clicked on button"); } }); return convertView; } static class ViewHolder { TextView text; ImageView icon; } private static final String[] DATA = { "Abbaye de Belloc", "Abbaye du Mont des Cats" }; } ListView product_search_list; Button srch_btn; EditText srch_text; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setListAdapter(new ProductSearchAdapter(this)); // setContentView(R.layout.productsearch); // getListView().setEmptyView(findViewById(R.id.text)); // srch_text = (EditText)findViewById(R.id.prdsearchtb); // srch_btn = (Button) findViewById(R.id.prdsearchtb); // srch_btn.setOnClickListener(new View.OnClickListener() { // // @Override // public void onClick(View v) { // callProductSearchAdapter(); // // } // }); } void callProductSearchAdapter() { setListAdapter(new ProductSearchAdapter(this)); } private void createDialog(String title, String text, final Intent i) { if (i == null) { AlertDialog ad = new AlertDialog.Builder(this).setIcon( R.drawable.alert_dialog_icon).setPositiveButton("Ok", null) .setTitle(title).setMessage(text).create(); ad.show(); } } } Regards: Jayanth

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  • Sort latitude and longitude coordinates into clockwise ordered quadrilateral

    - by Dave Jarvis
    Problem Users can provide up to four latitude and longitude coordinates, in any order. They do so with Google Maps. Using Google's Polygon API (v3), the coordinates they select should highlight the selected area between the four coordinates. Solutions and Searches http://www.geocodezip.com/map-markers_ConvexHull_Polygon.asp http://softsurfer.com/Archive/algorithm_0103/algorithm_0103.htm http://stackoverflow.com/questions/2374708/how-to-sort-points-in-a-google-maps-polygon-so-that-lines-do-not-cross http://stackoverflow.com/questions/242404/sort-four-points-in-clockwise-order http://en.literateprograms.org/Quickhull_%28Javascript%29 Graham's scan seems too complicated for four coordinates Sort the coordinates into two arrays (one by latitude, the other longitude) ... then? Jarvis March algorithm? Question How do you sort the coordinates in (counter-)clockwise order, using JavaScript? Code Here is what I have so far: // Ensures the markers are sorted: NW, NE, SE, SW function sortMarkers() { var ns = markers.slice( 0 ); var ew = markers.slice( 0 ); ew.sort( function( a, b ) { if( a.position.lat() < b.position.lat() ) { return -1; } else if( a.position.lat() > b.position.lat() ) { return 1; } return 0; }); ns.sort( function( a, b ) { if( a.position.lng() < b.position.lng() ) { return -1; } else if( a.position.lng() > b.position.lng() ) { return 1; } return 0; }); var nw; var ne; var se; var sw; if( ew.indexOf( ns[0] ) > 1 ) { nw = ns[0]; } else { ne = ns[0]; } if( ew.indexOf( ns[1] ) > 1 ) { nw = ns[1]; } else { ne = ns[1]; } if( ew.indexOf( ns[2] ) > 1 ) { sw = ns[2]; } else { se = ns[2]; } if( ew.indexOf( ns[3] ) > 1 ) { sw = ns[3]; } else { se = ns[3]; } markers[0] = nw; markers[1] = ne; markers[2] = se; markers[3] = sw; } What is a better approach? The recursive Convex Hull algorithm is overkill for four points in the data set. Thank you.

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  • Collapse span when input button is hidden

    - by Evan
    I have a style that wraps around an input button, so the button can be styled very creatively. When the button is hidden in .Net, i would like the style to collapse so it renders like its hidden as well. What the style does, as a result of no value in the button or its hidden, is it keeps a small shape. Click to see a demo: http://media.apus.edu/it/evan-testing/button.htm <style> .button { cursor:pointer; text-decoration:none; background:url(button_bg.gif) no-repeat right top; padding-right:10px; display:inline-block; line-height:29px; height:29px; font-size:12px; color:#FFFFFF; font-weight:bold; } span.button { vertical-align: middle; } .button span { background:url(button_bg.gif) no-repeat left top; padding-left:10px; line-height:20px; height:29px; display:inline-block; } .button span span { background:transparent; padding:0; font-size:12px; } .button span input { cursor:pointer; font-weight:bold; background:transparent; border:0; padding-top:.4em; font-size:12px; font-family:verdana; color:#FFFFFF; } .button:hover { background-position:right -39px; } .button:hover span { background-position:left -39px; } .button:active { background-position:right -78px; } .button:active span { background-position:left -78px; } </style> Input button wrapped in a span with no value: <span class="button"><span><input type="button" value=""></span></span> <P> Input button wrapped in a span with a value: <span class="button"><span><input type="button" value="test"></span></span> <P> Span with no data value: <span class="button"><span></span>

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  • How can I move the close button to the top-right corner of the box in slimbox (jQuery)

    - by janoChen
    I want to have my button in the top-right corner, I tried position: absolute, but I think the position of the box is not relative so I can't use top: 0;. Any suggestions? CSS: /* SLIMBOX */ #lbOverlay { position: fixed; z-index: 9999; left: 0; top: 0; width: 100%; height: 100%; background-color: #000; cursor: pointer; } #lbCenter, #lbBottomContainer { position: absolute; z-index: 9999; overflow: hidden; background-color: #fff; } .lbLoading { background: #fff url(slimbox2/loading.gif) no-repeat center; } #lbImage { position: absolute; left: 0; top: 0; border: 10px solid #fff; background-repeat: no-repeat; } #lbPrevLink, #lbNextLink { display: block; position: absolute; top: 0; width: 50%; outline: none; } #lbPrevLink { left: 0; } #lbPrevLink:hover { background: transparent url(slimbox2/prevlabel.gif) no-repeat 0 15%; } #lbNextLink { right: 0; } #lbNextLink:hover { background: transparent url(slimbox2/nextlabel.gif) no-repeat 100% 15%; } #lbBottom { font-family: Verdana, Arial, Geneva, Helvetica, sans-serif; font-size: 10px; color: #666; line-height: 1.4em; text-align: left; border: 10px solid #fff; border-top-style: none; } #lbCloseLink { display: block; float: right; width: 31px; height: 32px; background: transparent url(slimbox2/closelabel.gif) no-repeat center; margin: 5px 0; outline: none; } #lbCloseLink:hover { background: transparent url(slimbox2/closelabel_hover.gif) no-repeat center; border-bottom: 0px; } #lbCaption, #lbNumber { margin-right: 71px; } #lbCaption { font-weight: bold; }

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  • Does webkit-scrollbar work with webkit-transition?

    - by Trev
    I want a custom webkit-scrollbar to animate a different background color for the hover state. The code below changes the color on hover but doesn't animate anything. It works on a div so I suspect webkit-scrollbar doesn't play nice with transitions. ::-webkit-scrollbar-thumb { background-color: #a8a8a8; -webkit-transition: background-color 1s linear; } ::-webkit-scrollbar-thumb:hover { background-color: #f6f6f6; }

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