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  • Spring 3, Java EE 6

    - by arg20
    I'm learning Java EE 6. I've seen how much progress it has achieved in this release of the umbrella specification. EJBs 3.1 are far easier and more lightweight than previous versions, and CDI is amazing. I'm not familiar with Spring, but I often read that it offered some neat features that the Java EE stack didn't. Yet I also read now that JEE has caught up, and can now fully compete with Spring. I know that choosing from both depends on many factors, but if we only focus on features, say the latest trends etc. Which one has the leading edge?. Can Spring 3 offer some assets The JAVA EE 6 stack can't? Also, what about Seam framework? From what I read it's like java ee 6 but with some additions?

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  • What is the accepted way to replace java.util.Date(year,month,day)

    - by dagw
    I'm trying to do something really simple, but starting to realize that dates in Java are a bit of minefield. All I want is to get passed groups of three ints ( a year, a month and a date) create some Date objects, do some simple test on them (along the lines of as date A before date B and after January 1 1990), convert them to java.sql.Date objects and pass them off to the database via JDBC. All very simple and works fine using the java.util.Date(int year,int month,int day) constructor. Of course that constructor is depreciated, and I'd like to avoid using depreciated calls in new code I'm writing. However all the other options to solve this simple problem seem stupidly complicated. Is there really no simple way to do what I want without using depreciated constructors? I know the standard answer to all Java date related questions is "use joda time", but I really don't want to start pulling in third party libraries for such a seemingly trivial problem.

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  • Java - Confused by the one class per file rule

    - by Mark
    The one class per file rule in Java has me a bit confused. I writing an Android app and trying to implement the accepted answer to this question: Common class for AsyncTask in Android? which calls for an interface definition which class A implements and class B accepts as an argument to its constructor. So I need an A.java and a B.java, but where does the interface go? Does it need a separate java file itself? Do I have to define it inside both A and B? If not how to import it? Also I will have about 10 different AsyncTask classes, but I don't want to bother creating a new file for each one. What would you recommend? Is there a way to put all 10 classes in one file? Or should I create a big if/then block inside the class and pass an argument telling it which of the 10 different tasks I want it to do?

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  • Java: Looking for hack to deal with Windows file paths in Linux

    - by Chase Seibert
    Say you have a large legacy ColdFusion on top of Java on Windows application. File access is done both via java.io.File and by CFFILE (which in turn also uses java.io.File), but not centralised in any way into a single file access library. Further, say you have file paths both hard-coded in the code, and also in a database. In other words, assume the file paths themselves cannot change. They could be either local or remote Windows file paths: c:\temp\file.txt \\server\share\file.txt Is there a way to run this application on Linux with minimal code changes? I'm looking for creative solutions that do not involve touching the legacy code. Some ideas: Run it on WINE. This actually works, because WINE will translate the local paths, and has a samba client for the remote paths. Is there a way to override java.io.File to perform the file path translation with custom code? In this case, I would translate the remote paths to a mount point.

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  • Concatenate, sort and swap array in Java

    - by sblck
    I am trying to concatenate two arrays into new array, sort in order, and swap two values of index. I'm kind of new to java and only use C before so having a hard time handling an Object. In main method it declares two object arrays IntVector vector = new IntVector(3); and IntVector vector2 = new IntVector(3); I can only do this if the types are int[], but I want to use as an object How should I code the concat, sort, and swap method? public class IntVector { private int[] items_; private int itemCount_; private IntVector(int[] data, int n) { items_ = data.clone(); itemCount_ = n; } public IntVector(int itemSize) { itemCount_ =0; if(itemSize<1) itemSize =10; items_ = new int[itemSize]; } public void push(int value) { if(itemCount_ + 1 >= items_.length) overflow(); items_[itemCount_++] = value; } public void log() { for (int i=0 ; i<itemCount_; ++i) { System.out.print(items_[i]); if(i<itemCount_ -1) System.out.println(); } } public void overflow() { int[] newItems = new int[items_.length * 2]; for(int i=0 ; i<itemCount_; ++i) { newItems[i] = items_[i]; } items_=newItems; } public int getValue(int index) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return 0; } return items_[index]; } public void setValue(int index, int value) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return ; } items_[index] = value; } public IntVector clone() { return new IntVector(items_, itemCount_); } public IntVector concat() { return null; } public IntVector sort() { return null; } public IntVector swap() { return null; } public static void main(String[] args) { IntVector vector = new IntVector(3); IntVector vector2 = new IntVector(3); vector.push(8); vector.push(200); vector.push(3); vector.push(41); IntVector cloneVector = vector.clone(); vector2.push(110); vector2.push(12); vector2.push(7); vector2.push(141); vector2.push(-32); IntVector concatResult = vector.concat(vector2); IntVector sortResult = concatResult.sort(); IntVector swapResult = sortResult.clone(); //swapResult.swap(1,5); System.out.print("vector : "); vector.log(); System.out.print("\n\ncloneVector : "); cloneVector.log(); System.out.print("\n\nvector2 : "); vector2.log(); System.out.print("\n\nconcatvector : "); concatResult.log(); System.out.print("vector : "); vector.log(); System.out.print("vector : "); vector.log(); } }

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  • java beginner wants to learn Hibernate

    - by Ashwath
    I am a java beginner and so far have completed learning the core java concepts except io chapter. I also want to finish up the j2ee material and other stuffs like hibernate, springs and struts . At present I have good knowledge of Java . please guide me that how can i finish up studying Hibernate, Springs and Struts in 2 days without going through J2ee in detail .Since I am preparing for the interview ? thanks for the help..

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  • Java - Image encoding in XML

    - by Hoopla
    Hi everyone, I thought I would find a solution to this problem relatively easily, but here I am calling upon the help from ye gods to pull me out of this conundrum. So, I've got an image and I want to store it in an XML document using Java. I have previously achieved this in VisualBasic by saving the image to a stream, converting the stream to an array, and then VB's xml class was able to encode the array as a base64 string. But, after a couple of hours of scouring the net for an equivalent solution in Java, I've come back empty handed. The only success I have had has been by: import it.sauronsoftware.base64.*; import java.awt.image.BufferedImage; import org.w3c.dom.*; ... BufferedImage img; Element node; ... java.io.ByteArrayOutputStream os = new java.io.ByteArrayOutputStream(); ImageIO.write(img, "png", os); byte[] array = Base64.encode(os.toByteArray()); String ss = arrayToString(array, ","); node.setTextContent(ss); ... private static String arrayToString(byte[] a, String separator) { StringBuffer result = new StringBuffer(); if (a.length > 0) { result.append(a[0]); for (int i=1; i<a.length; i++) { result.append(separator); result.append(a[i]); } } return result.toString(); } Which is okay I guess, but reversing the process to get it back to an image when I load the XML file has proved impossible. If anyone has a better way to encode/decode an image in an XML file, please step forward, even if it's just a link to another thread that would be fine. Cheers in advance, Hoopla.

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  • Why is the Java VM so popular?

    - by sdudo
    There are more and more programming languages (Scala, Clojure,...) coming out that are made for the Java VM and are therefore compatible with the Java Byte-Code. I'm beginning to ask myself: Why the Java VM? What makes it so powerful or popular that there are new programming languages, which seem gaining popularity too, created for it? Why don't they write a new VM for a new language?

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  • Considering moving from Java/Spring MVC to Grails

    - by MDS
    I'm currently using Java & Spring (MVC) to create a webapp, and I'm considering moving to Grails. I'd appreciate feedback/insight on the following: I have multiple application contexts in the current Java/Spring webapp that I load through the web.xml ContextLoaderListener; is it possible to have multiple application contexts in Grails? If, yes, how? This webapp extensively uses a CXF restful web service and the current Java/Spring webapp uses the bundled CXF HTTP client. Can I continue to use the (Java) CXF HTTP Client in Grails? I implemented Spring Security using a custom implementation of UserDetails and UserDetailsService, can I re-use these implementations in Grails "as is" or must I re-implement them? There is an instance where I've relied on Spring's jdbc template (rather than the available ORM) and an additional data source I defined in app context, can I re-use this in Grails? I plan on using Maven as the project management tool; are there any issues of using Maven with Grails where there is a combination of groovy and java?

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  • Why isn't the pathspec magic :(exclude) excluding the files I specify from git log's output?

    - by Jubobs
    This is a follow-up to Ignore files in git log -p and is also related to Making 'git log' ignore changes for certain paths. I'm using Git 1.9.2. I'm trying to use the pathspec magic :(exclude) to specify that some patches should not be shown in the output of git log -p. However, patches that I want to exclude still show up in the output. Here is minimal working example that reproduces the situation: cd ~/Desktop mkdir test_exclude cd test_exclude git init mkdir testdir echo "my first cpp file" >testdir/test1.cpp echo "my first xml file" >testdir/test2.xml git add testdir/ git commit -m "added two test files" Now I want to show all patches in my history expect those corresponding to XML files in the testdir folder. Therefore, following VonC's answer, I run git log --patch -- . ":(exclude)testdir/*.xml" but the patch for my testdir/test2.xml file still shows up in the output: commit 37767da1ad4ad5a5c902dfa0c9b95351e8a3b0d9 Author: xxxxxxxxxxxxxxxxxxxxxxxxx Date: Mon Aug 18 12:23:56 2014 +0100 added two test files diff --git a/testdir/test1.cpp b/testdir/test1.cpp new file mode 100644 index 0000000..3a721aa --- /dev/null +++ b/testdir/test1.cpp @@ -0,0 +1 @@ +my first cpp file diff --git a/testdir/test2.xml b/testdir/test2.xml new file mode 100644 index 0000000..8b7ce86 --- /dev/null +++ b/testdir/test2.xml @@ -0,0 +1 @@ +my first xml file What am I doing wrong? What should I do to tell git log -p not to show the patch associated with all XML files in my testdir folder?

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  • Is it possible to log the first line of the response in apache?

    - by Jeppe Mariager
    Hey, We have an Tomcat server where we're trying to log the HTTP version which the response is sent with. We've seen a few times that it seems to be HTTP/0.9, which kills the content (not supported I guess?). We would like to get some stats on this by using the access log in apache. However, since the header line for this isn't prefixed by anything, we cannot use the %{xxx}o logging. Is there a way to get this? An example: Response is: HTTP/1.1 503 This application is not currently available Server: Apache-Coyote/1.1 Content-Type: text/html;charset=utf-8 Content-Length: 1090 Date: Wed, 12 May 2010 12:53:16 GMT Connection: close And we'd like the catch HTTP/1.1 (alternatively, HTTP/1.1 503 This application is not currently available. Is this possible? We do not have access to the application being served, so we need to do this either as a Java filter, or in the tomcat access log - Preferably in the access log.

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  • Large amount of constants in Java

    - by Lars D
    I need to include about 1 MByte of data in a Java application, for very fast and easy access in the rest of the source code. My main background is not Java, so my initial idea was to convert the data directly to Java source code, defining 1MByte of constant arrays, classes (instead of C++ struct) etc., something like this: public final/immutable/const MyClass MyList[] = { { 23012, 22, "Hamburger"} , { 28375, 123, "Kieler"} }; However, it seems that Java does not support such constructs. Is this correct? If yes, what is the best solution to this problem?

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  • Java or C# + XNA for some simple animations?

    - by lala
    I want to make a program that will involve some faces with various facial expressions. They will change from one facial expression to another based on their "mood" as influenced by user input. I know some java but I have done pretty much nothing with graphics. A friend tells me that it will be easier to do this in C# with XNA than to do it in java. I have about a month to do this, so I was hoping you folks would help me make a decision. Would I be better off figuring out how to do this in java, or learning C# and XNA and doing it in C#? Is it so much easier to do this in C# that it would be quicker to learn C# than to struggle with doing it in java? Will it probably come out looking much better if it is in C#?

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  • Change the default output folder for a java command when executed by php

    - by jax
    I am trying to run a java command like this in a PHP Joomla Component. It works, however, the files generated from the command are written to /administrator and I want them to be written to the location where the Java command resides ie. /administrator/com_mycomponent/java/MyJavaApp.jar //run the command $javaCommand = "$javaCommand -jar $keyGeneratorFile $appName"; $response = exec($javaCommand); if(empty($response)) { JError::raiseError(500, "Key Generation failed for command: $javaCommand"); } What can I do? Is there some sort of option I can use with the java command?

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  • java app behind proxy to use http_proxy variable in linux

    - by rbbeltran
    hello java guys, im thinking of a simple java app (command line) that connects to the internet to download xml file, the problem is that my ubuntu is using a proxy to connect to internet with username and password (tru http_proxy ="http://:@:" ). So My question is, could it be possible to write a java app to use http_proxy variable? instead of programmatically setting http proxy and host in every app i will write.

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