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  • VBScript Regular Expressions to check IP address validity with some adtional characters

    - by yael
    How to create VB script Irregular expression syntax to check the VPparam (IP address validity) When the last octatat of the IP address is a range between ip's (x-y) and between each IP we can put the "," separator in order to add another IP example of VBparam VBparam=172.17.202.1-20 VBparam=172.17.202.1-10,192.9.200.1-100 VBparam=172.17.202.1-10,192.9.200.1-100,180.1.1.1-20 THX yael

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  • Named Function Expressions in IE, part 2

    - by Polshgiant
    I asked this question a while back and was happy with the accepted answer. I just now realized, however, that the following technique: var testaroo = 0; (function executeOnLoad() { if (testaroo++ < 5) { setTimeout(executeOnLoad, 25); return; } alert(testaroo); // alerts "6" })(); returns the result I expect. If T.J.Crowder's answer from my first question is correct, then shouldn't this technique not work?

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  • Regular expressions .net

    - by Tony
    I have the following function that I am using to remove the characters \04 and nulls from my xmlString but I can't find what do I need to change to avoid removing the \ from my ending tags. This is what I get when I run this function <ARR>20080625<ARR><DEP>20110606<DEP><PCIID>626783<PCIID><NOPAX>1<NOPAX><TG><TG><HASPREV>FALSE<HASPREV><HASSUCC>FALSE<HASSUCC> Can anybody help me find out what do I need to change in my expression to keep the ending tag as </tag> Private Function CleanInput(ByVal inputXML As String) As String ' Note - This will perform better if you compile the Regex and use a reference to it. ' That assumes it will still be memory-resident the next time it is invoked. ' Replace invalid characters with empty strings. Return Regex.Replace(inputXML, "[^><\w\.@-]", "") End Function

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  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • typesafe NotifyPropertyChanged using linq expressions

    - by bitbonk
    Form Build your own MVVM I have the following code that lets us have typesafe NotifyOfPropertyChange calls: public void NotifyOfPropertyChange<TProperty>(Expression<Func<TProperty>> property) { var lambda = (LambdaExpression)property; MemberExpression memberExpression; if (lambda.Body is UnaryExpression) { var unaryExpression = (UnaryExpression)lambda.Body; memberExpression = (MemberExpression)unaryExpression.Operand; } else memberExpression = (MemberExpression)lambda.Body; NotifyOfPropertyChange(memberExpression.Member.Name); } How does this approach compare to standard simple strings approach performancewise? Sometimes I have properties that change at a very high frequency. Am I safe to use this typesafe aproach? After some first tests it does seem to make a small difference. How much CPU an memory load does this approach potentially induce?

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  • matching files with regular expressions

    - by Javier
    Dear all, I have an input file with a list of movies (Note that there might be some repeated entries): American_beauty__1h56mn38s_ As_Good_As_It_Gets As_Good_As_It_Gets _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ Capote_EN_DVDRiP_XViD-GeT-AW _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ I would to find the corresponding match (line number) from another reference file for each of the entries in the first file: American beauty.(1h56mn38s) As Good As It Gets Capote.EN.DVDRiP.XViD-GeT-AW [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) Quills (2000)(7.4) The desired output would be something like (Reference Movie + Line number from the Reference File): American beauty.(1h56mn38s) 1 As Good As It Gets 2 As Good As It Gets 2 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Capote.EN.DVDRiP.XViD-GeT-AW 3 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Basically, the difference between the entries in both files is that some characters such as: blank spaces, parenthesis, points, etc. have been replaced by underscores. Does anybody could shed some light on it? Best wishes, Javier

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  • .NET equivalent to Perl regular expressions

    - by r_honey
    I need to convert a Perl script to VB.NET. I have managed almost the entire conversion, but some Perl (seemingly simple) regex are causing an headache. Can someone suggest me .NET equivalent of the following perl regex: 1) $letter =~ s/Users //,; $letter =~ s/Mailboxes //,; if($letter =~ m/$first_char/i){ 2) unless($storegroup =~ /Recovery/ || $storegroup =~ /Users U V W X Y Z/ || $storegroup =~ /Users S T/ || $storegroup =~ /Users Q R/){ The regex look simple to me. I tried to wade through perl.org but understanding a langugae regex takes sometime and I need to complete the conversion quickly.

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  • SQL: Recursively get parent records using Common Table Expressions

    - by Martijn B
    Hi there, Suposse you have to following tables where a sale consists of products and a product can be placed in multiple categories. Whereby categories have a hierachly structure like: Man Shoes Sport Casual Watches Women Shoes Sport Casual Watches Tables: Sale: id name 1 Sale1 Product: id saleidfk name 1 1 a 2 1 b 3 1 c 4 1 d 5 1 e ProductCategory : productid categoryid 1 3 2 3 3 4 4 5 5 10 Category: id ParentCategoryIdFk name 1 null Men 2 1 Shoes 3 2 Sport 4 2 Casual 5 1 Watches 6 null Women 7 6 Shoes 8 7 Sport 9 7 Casual 10 6 Watches Question: Now on my website I want to create a control where only the categories are shown of a certain sale and where the categories are filled with the products of the sale. I also want to include the hierachly structure of the categories. So if we have a leave node, recusivly go up to the top node. So with sale1 I should have a query with the following result: Men Shoes Sport Casual Watches Women Watches This thing is driving me crazy :-) Thanks in advance! Gr Martijn

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  • Understanding evaluation of expressions containing '++' and '->' operators in C.

    - by Leif Ericson
    Consider this example: struct { int num; } s, *ps; s.num = 0; ps = &s; ++ps->num; printf("%d", s.num); /* Prints 1 */ It prints 1. So I understand that it is because according to operators precedence, -> is higher than ++, so the value ps->num (which is 0) is firstly fetched and then the ++ operator operates on it, so it increments it to 1. struct { int num; } s, *ps; s.num = 0; ps = &s; ps++->num; printf("%d", s.num); /* Prints 0 */ In this example I get 0 and I don't understand why; the explanation of the first example should be the same for this example. But it seems that this expression is evaluated as follows: At first, the operator ++ operates, and it operates on ps, so it increments it to the next struct. Only then -> operates and it does nothing because it just fetches the num field of the next struct and does nothing with it. But it contradicts the precedence of operators, which says that -> have higher precedence than ++. Can someone explain this behavior? Edit: After reading two answers which refer to a C++ precedence tables which indicate that a prefix ++/-- operators have lower precedence than ->, I did some googling and came up with this link that states that this rule applies also to C itself. It fits exactly and fully explains this behavior, but I must add that the table in this link contradicts a table in my own copy of K&R ANSI C. So if you have suggestions as to which source is correct I would like to know. Thanks.

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  • Merging two Regular Expressions to Truncate Words in Strings

    - by Alix Axel
    I'm trying to come up with the following function that truncates string to whole words (if possible, otherwise it should truncate to chars): function Text_Truncate($string, $limit, $more = '...') { $string = trim(html_entity_decode($string, ENT_QUOTES, 'UTF-8')); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)~su', '$1', $string); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{' . intval($limit) . '}).*~su', '$1', $string); } $string .= $more; } return trim(htmlentities($string, ENT_QUOTES, 'UTF-8', true)); } Here are some tests: // Iñtërnâtiônàlizætiøn and then the quick brown fox... (49 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn and then the quick brown fox jumped overly the lazy dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); // Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_... (50 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); They both work as it is, however if I drop the second preg_replace() I get the following: Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.... I can't use substr() because it only works on byte level and I don't have access to mb_substr() ATM, I've made several attempts to join the second regex with the first one but without success. Please help S.M.S., I've been struggling with this for almost an hour. EDIT: I'm sorry, I've been awake for 40 hours and I shamelessly missed this: $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)?~su', '$1', $string); Still, if someone has a more optimized regex (or one that ignores the trailing space) please share: "Iñtërnâtiônàlizætiøn and then " "Iñtërnâtiônàlizætiøn_and_then_" EDIT 2: I still can't get rid of the trailing whitespace, can someone help me out?

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  • VBScript + Regular Expressions

    - by Karthik
    Dim sString sString = "John;Mary;Anne;Adam;Bill;Ester" Is there a regex I can use to retrieve the following from the above list: John (; at the end of the name) Anne (; at the beginning and end) Ester (; at the beginning) I am currently using the following regex for each: 1. Joh.* 2. .*An.* 3. .*st.* But, the above retrieves the entire string instead of the values I want. How can I get the correct values? Code: Dim oRegex : Set oRegex = New RegExp oRegex.Global = False oRegex.IgnoreCase = False 'John oRegex.Pattern = "Joh.*" Set oMatch = oRegex.Execute(sString) sName = oMatch(0) The above code retrieves the entire string, instead of only John. Same issue with the others :(

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  • Is there a compelling reason to use quantifiers in Perl regular expressions instead of just repeatin

    - by Morinar
    I was performing a code review for a colleague and he had a regular expression that looked like this: if ($value =~ /^\d\d\d\d$/) { #do stuff } I told him he should change it to: if ($value =~ /^\d{4}$/) { #do stuff } To which he replied that he preferred the first for readability (I find the second more readable, but that's a religious debate I'll save for another day). My question: is there an actual benefit to one over the other?

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  • Converting F# Quotations into LINQ Expressions

    - by forki23
    Hi, I can convert a quotation of type Expr<'a -> 'b> to a Linq expression via the following snippet: /// Converts a F# Expression to a LINQ Lambda let toLambda (exp:Expr) = let linq = exp.ToLinqExpression() :?> MethodCallExpression linq.Arguments.[0] :?> LambdaExpression /// Converts a Lambda quotation into a Linq Lamba Expression with 1 parameter let ToLinq (exp : Expr<'a -> 'b>) = let lambda = toLambda exp Expression.Lambda<Func<'a, 'b>>(lambda.Body, lambda.Parameters) Now I want to convert a quotation of type Expr<'a * 'b -> 'c> or maybe even Expr<'a -> 'b -> 'c> to a Linq Lambda Expression of type Expression<Func<'a,'b'c>>. How can I do this? Regards, forki

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  • Regular Expressions, Checking for a range of occurrences

    - by gmcalab
    I have a phone number I want to match against a regular expression. The format of the phone number must match this: (123) 123-4567 x12345 The extension is optional. Also the extension must contain 1-5 numbers. Below is a regular expression I wrote that works. ^\(\d{3}\) \d{3}-\d{4}( x\d\d?\d?\d?\d?)?$ I was wondering if there is a better way to check for the extension instead of x\d\d?\d?\d?\d? Can I say 1-5 occurrences of \d instead of the above some how ?

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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • Destructuring assignment in generator expressions and array comprehensions

    - by Eli Grey
    Why does for ([] in object); work fine but [void 0 for ([] in object)] or (void 0 for ([] in object)) throw a syntax error for invalid left-hand assignment? For example, I would expect the following code to work, but it doesn't (the assertion isn't even done due to the syntax error): let ( i = 0, arr = [1, 2, 3, 4], gen = (i for (i in arr) if (arr.hasOwnProperty(i)) ) { for ([] in gen) i++; console.assertEquals([void 0 for ([] in gen)].length, i); }

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  • Regular expressions help

    - by Michael
    If I had the following HTML: <li><a href="aaa"> Thisislink1</a></li> <li><a href="abcdef"> Thisisanotherlink</a></li> <li><a href="12345"> Onemorelink</a></li> Where each link will be different in length and value. How can I search for the values inside the link (IE: Thisislink1, Thisisanotherlink and Onemorelink) with a search phrase, say 'another'. So in this example, only 'Thisisanotherlink' would be returned, but if I changed the search phrase to 'link', then all 3 values will be returned.

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  • When should you use intermediate variables for expressions?

    - by froadie
    There are times that one writes code such as this: callSomeMethod(someClass.someClassMethod()); And other times when one would write the same code like this: int result = someClass.someClassMethod(); callSomeMethod(result); This is just a basic example to illustrate the point. My question isn't if you should use an intermediate variable or not, as that depends on the code and can sometimes be a good design decision and sometimes a terrible one. The question is - when would you choose one method over the other? What factors would you consider when deciding whether to use an intermediate step? (I'd assume length and understandability of the fully inlined code would have something to do with it...)

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  • boost::lambda bind expressions can't get bind to string's empty() to work

    - by navigator
    Hi, I am trying to get the below code snippet to compile. But it fails with: error C2665: 'boost::lambda::function_adaptor::apply' : none of the 8 overloads could convert all the argument types. Sepcifying the return type when calling bind does not help. Any idea what I am doing wrong? Thanks. #include <boost/lambda/lambda.hpp> #include <boost/lambda/bind.hpp> #include <string> #include <map> int main() { namespace bl = boost::lambda; typedef std::map<int, std::string> types; types keys_and_values; keys_and_values[ 0 ] = "zero"; keys_and_values[ 1 ] = "one"; keys_and_values[ 2 ] = "Two"; std::for_each( keys_and_values.begin(), keys_and_values.end(), std::cout << bl::constant("Value empty?: ") << std::boolalpha << bl::bind(&std::string::empty, bl::bind(&types::value_type::second, _1)) << "\n"); return 0; }

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  • Regular expressions and matching question marks in URLs

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • Problem with nested lambda expressions.

    - by Lehto
    Hey I'm trying to do a nested lambda expression like to following: textLocalizationTable.Where( z => z.SpokenLanguage.Any( x => x.FromCulture == "en-GB") ).ToList(); but i get the error: Member access 'System.String FromCulture' of 'DomainModel.Entities.SpokenLanguage' not legal on type 'System.Data.Linq.EntitySet`1[DomainModel.Entities.SpokenLanguage]. TextLocalization has this relation to spokenlanguage: [Association(OtherKey = "LocalizationID", ThisKey = "LocalizationID", Storage = "_SpokenLanguage")] private EntitySet<SpokenLanguage> _SpokenLanguage = new EntitySet<SpokenLanguage>(); public EntitySet<SpokenLanguage> SpokenLanguage { set { _SpokenLanguage = value; } get { return _SpokenLanguage; } } Any idea what is wrong?

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  • php array code with regular expressions

    - by user551068
    there are few mistakes which it is showing as Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in array 4,9,10,11,12... can anyone resolve them <?PHP $hosts = array( array("ronmexico.kainalopallo.com/","beforename=$F_firstname%20$F_lastname&gender=$F_gender","Your Ron Mexico Name is ","/the ultimate disguise, is <u><b>([^<]+)<\/b><\/u>/s"), array("www.fjordstone.com/cgi-bin/png.pl","gender=$F_gender&submit=Name%20Me","Your Pagan name is ","/COLOR=#000000 SIZE=6> *([^<]*)<\/FONT>/"), array("rumandmonkey.com/widgets/toys/mormon/index.php","gender=$F_gender&firstname=$F_firstname&surname=$F_lastname","Your Mormon Name is ","/<p>My Mormon name is <b>([^<]+)<\/b>!<br \/>/s"), array("cyborg.namedecoder.com/index.php","acronym=$F_firstname&design=edox&design_click-edox.x=0&design_click-edox.y=0&design_click-edox=edo","","Your Cyborg Name is ","/<p>([^<]+)<\/p>/"), array("rumandmonkey.com/widgets/toys/namegen/10/","nametype=$brit&page=2&id=10&submit=God%20save%20the%20Queen!&name=$F_firstname%20$F_lastname","Your Very British Name is ","/My very British name is \&lt\;b\&gt;([^&]+)\&lt;\/b\&gt;\.\&lt;br/"), array("blazonry.com/name_generator/usname.php","realname=$F_firstname+$F_lastname&gender=$F_gender","Your U.S. Name is ","/also be known as <font size=\'\+1\'><b>([^<]+)<\/b>/s"), array("www.spacepirate.org/rogues.php","realname=$F_firstname%20$F_lastname&formentered=Yes&submit=Arrrgh","Your Space Pirate name is ","/Your pirate name is <font size=\'\+1\'><b>([^<]+)<\/b><\/font>/s"), array("rumandmonkey.com/widgets/toys/ghetto/","firstname=$F_firstname&lastname=$F_lastname","Your Ghetto Name is ","/<p align=\"center\" style=\"font-size: 36px\">\s*<br \/>\s*([^<]*)<br \/>/"), array("www.emmadavies.net/vampire/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Find+My+Vampire+Name","","Your Vampire Name is ","/<i class=\"vampirecontrol vampire name\">([^<]*)<\/i>/"), array("www.emmadavies.net/fairy/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Seek+Fairy","","Your Fairy Name is ","/<i class=\'ng fairy name\'>([^<]*)<\/i>/"), array("www.irielion.com/israel/reggaename.html","phase=3&oldname=$F_firstname%20$F_lastname&gndr=$reggender","","Your Rasta Name is ","/Yes I, your irie new name is ([^\n]*)\n/"), array("www.ninjaburger.com/fun/games/ninjaname/ninjaname.php","realname=$F_firstname+$F_lastname","Your Ninja Burger Name is ","/<BR>Ninja Burger ninja name will be<BR><BR><FONT SIZE=\'\+1\'>([^<]*)<\/FONT>/"), array("gangstaname.com/pirate_name.php","sex=$F_gender&name=$F_firstname+$F_lastname","Your Pirate Name is ","/<p><strong>We\'ll now call ye:<\/strong><\/p> *<h2 class=\"newName\">([^<]*)<\/h2>/"), array("www.xach.com/nerd-name/","name=$F_firstname+$F_lastname&gender=$F_gender","Your Nerd Name is ","/<p><div align=center class=\"nerdname\">([^<]*)<\/div>/"), array("rumandmonkey.com/widgets/toys/namegen/5941/","page=2&id=5941&nametype=$dj&name=$F_firstname+$F_lastname","Your DJ Name is ","/My disk spinnin nu name is &lt\;b&gt\;([^<]*)&lt\;\/b&gt\;\./"), array("pizza.sandwich.net/poke/pokecgi.cgi","name=$F_firstname%20$F_lastname&color=black&submit=%20send%20","Your Pokename is ","/Your Pok&eacute;name is: <h1>([^<]*)<\/h1>/") ); return $hosts; ?>

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