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  • Communication between two applications running on two different versions of Tomcat

    - by Saurabh
    I have two web application running on two different versions of Tomcat. App1 is on Tomcat5 and App2 is on Tomcat6. Is there any way, so that I can make a communication among these two. For example - If there is a JavaScript file in App2/js/mycode.js, then I would like to refer this from App1/page/mypage.jsp. For both applications I have defined context as - App1.xml (Tomcat5\conf\Catalina\localhost) <Context path="/App1" docBase="C:/eclipse/workspace/App1" debug="0"> </Context> App2.xml (Tomcat6\conf\Catalina\localhost) <Context path="/App2" docBase="C:/eclipse/workspace/App2" debug="0"> </Context>

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  • ATI Radeon 5850 video card one analog, one digital and one tv connected to hdmi, unable to run all 3

    - by McLovin
    I have one analog monitor connected through dvi adapter one digital monitor connected through dvi tv connected through hdmi I'm unable to run all 3 at the same time, when I try to extend desktop it asks me to disable one of the monitors so I can only have 2 at one time. I tried finding solution but according to some forums I should be able to achieve it since one is analog I should be able to run 3 outputs with hdmi that way. Does any one have any suggestions? Thank you.

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  • Hibernate - why use many-to-one to represent a one-to-one?

    - by aberrant80
    I've seen people use many-to-one mappings to represent one-to-one relationships. I've also read this in a book by Gavin King and on articles. For example, if a customer can have exactly one shipping address, and a shipping address can belong to only one customer, the mapping is given as: <class name="Customer" table="CUSTOMERS"> ... <many-to-one name="shippingAddress" class="Address" column="SHIPPING_ADDRESS_ID" cascade="save-update" unique="true"/> ... </class> The book reasons as (quoting it): "You don't care what's on the target side of the association, so you can treat it like a to-one association without the many part." My question is, why use many-to-one and not one-to-one? What is it about a one-to-one that makes it a less desirable option to many-to-one? Thanks.

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  • What subject do you discuss with your manager during a one-on-one?

    - by Martin
    Every week, I have a 30 minutes meeting scheduled with my manager to talk about pretty much anything. So far, I haven't taken those one-on-one very seriously. As a new year resolution, I would like to take more seriously my one-on-ones with my manager. One way I though I could do that is to plan in advance (come up with a list of questions and/or agenda) my one-on-one. With the exception of the status report, what subject do you discuss with your manager during a one-on-one? Have you ever seen an agenda for one-on-one?

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  • two's complement, why the name "two"

    - by lenatis
    i know unsigned,two's complement, ones' complement and sign magnitude, and the difference between these, but what i'm curious about is: why it's called two's(or ones') complement, so is there a more generalize N's complement? in which way did these genius deduce such a natural way to represent negative numbers?

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  • Storing Preferences/One-to-One Relationships in Database

    - by LnDCobra
    What is the best way to store settings for certain objects in my database? Method one: Using a single table Table: Company {CompanyID, CompanyName, AutoEmail, AutoEmailAddress, AutoPrint, AutoPrintPrinter} Method two: Using two tables Table Company {CompanyID, COmpanyName} Table2 CompanySettings{CompanyID, utoEmail, AutoEmailAddress, AutoPrint, AutoPrintPrinter}

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  • Android Bottombar with two buttons having different backgrounds and a common background for two butt

    - by cppdev
    Hi, I have a linear layout in my main.xml which has a listview. Now I want to create a bottom bar below listview. Bottombar has a background image and two buttons with their individual background images. I want to put these two buttons on common background image. I have read that this can be achieved using FrameLayout. But since I am using LinearLayout as base layout in my main.xml, is there any way to this design using linearlayout ?

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  • Update one-to-many EntityKey using Foreign Key

    - by User.Anonymous
    To use by the easiest way Entity Framework, I use partial class to add Foreign Key on most important Entities Model. For example, I have an Entity "CONTACT" which have "TITLE", "FUNCTION" and others. When I update a CONTACT, with this code, Foreign Key are automatically updated : public int? TitId { get { if (this.TITLE_TIT != null) return TITLE_TIT.TIT_ID; return new Nullable<int>(); } set { this.TITLE_TITReference.EntityKey = new System.Data.EntityKey("Entities.TITLE_TIT", "TIT_ID", value); } } But I have a join with ACTIVITY, that can have many CONTACT, and I don't know how to update EntityKey on setters. public IEnumerable<EntityKeyMember> ActId { get { List<EntityKeyMember> lst = new List<EntityKeyMember>(); if (this.ACT_CON2 != null) { foreach (ACT_CON2 id in this.ACT_CON2.ToList()) { EntityKeyMember key = new EntityKeyMember(id.CON_ID.ToString(),id.ACT_ID); lst.Add(key); } } return lst; } set { this.ACT_CON2.EntityKey = new System.Data.EntityKey("Entities.ACT_CON2", value); } } How set many EntityKey ? Thank you.

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  • Initialization of an ArrayList in one line.

    - by Macarse
    I am willing to create a list of options to test something. I was doing: ArrayList<String> places = new ArrayList<String>(); places.add("Buenos Aires"); places.add("Córdoba"); places.add("La Plata"); I refactor the code doing: ArrayList<String> places = new ArrayList<String>(Arrays.asList("Buenos Aires", "Córdoba", "La Plata")); Is there a better way of doing this? Thanks for reading!

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  • Two entities with @ManyToOne should join the same table

    - by Ivan Yatskevich
    I have the following entities Student @Entity public class Student implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Teacher @Entity public class Teacher implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Task @Entity public class Task implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "student_id") }) private Student author; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "teacher_id") }) private Teacher curator; //getters and setters } Consider that author and curator are already stored in DB and both are in the attached state. I'm trying to persist my Task: Task task = new Task(); task.setAuthor(author); task.setCurator(curator); entityManager.persist(task); Hibernate executes the following SQL: insert into student_task (teacher_id, id) values (?, ?) which, of course, leads to null value in column "student_id" violates not-null constraint Can anyone explain this issue and possible ways to resolve it?

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  • Two entities with @ManyToOne joins the same table

    - by Ivan Yatskevich
    I have the following entities Student @Entity public class Student implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Teacher @Entity public class Teacher implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; //getter and setter for id } Task @Entity public class Task implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "student_id") }) private Student author; @ManyToOne(optional = false) @JoinTable(name = "student_task", inverseJoinColumns = { @JoinColumn(name = "teacher_id") }) private Teacher curator; //getters and setters } Consider that author and curator are already stored in DB and both are in the attached state. I'm trying to persist my Task: Task task = new Task(); task.setAuthor(author); task.setCurator(curator); entityManager.persist(task); Hibernate executes the following SQL: insert into student_task (teacher_id, id) values (?, ?) which, of course, leads to null value in column "student_id" violates not-null constraint Can anyone explain this issue and possible ways to resolve it?

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  • Many-to-one relationship in SQLAlchemy

    - by Arrieta
    This is a beginner-level question. I have a catalog of mtypes: mtype_id name 1 'mtype1' 2 'mtype2' [etc] and a catalog of Objects, which must have an associated mtype: obj_id mtype_id name 1 1 'obj1' 2 1 'obj2' 3 2 'obj3' [etc] I am trying to do this in SQLAlchemy by creating the following schemas: mtypes_table = Table('mtypes', metadata, Column('mtype_id', Integer, primary_key=True), Column('name', String(50), nullable=False, unique=True), ) objs_table = Table('objects', metadata, Column('obj_id', Integer, primary_key=True), Column('mtype_id', None, ForeignKey('mtypes.mtype_id')), Column('name', String(50), nullable=False, unique=True), ) mapper(MType, mtypes_table) mapper(MyObject, objs_table, properties={'mtype':Relationship(MType, backref='objs', cascade="all, delete-orphan")} ) When I try to add a simple element like: mtype1 = MType('mtype1') obj1 = MyObject('obj1') obj1.mtype=mtype1 session.add(obj1) I get the error: AttributeError: 'NoneType' object has no attribute 'cascade_iterator' Any ideas?

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  • Rails: associate model with two of its kind

    - by Patrick Oscity
    hi all, im trying to do this: class Event < ActiveRecord::Base belongs_to :previous_event has_one :event, :as => :previous_event, :foreign_key => "previous_event_id" belongs_to :next_event has_one :event, :as => :next_event, :foreign_key => "next_event_id" end because i want to enable the user to repeat events and change multiple oncoming events at the same time. what am i doing wrong, or is there another way of doing this? somehow i need to know about the previous and the next event, don't i? when i'm testing this in the consolewith Event.all[1].previous_event, i get the following error: NameError: uninitialized constant Event::PreviousEvent from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.5/lib/active_support/dependencies.rb:105:in `const_missing' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2199:in `compute_type' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.5/lib/active_support/core_ext/kernel/reporting.rb:11:in `silence_warnings' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:2195:in `compute_type' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/reflection.rb:156:in `send' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/reflection.rb:156:in `klass' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations/belongs_to_association.rb:49:in `find_target' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations/association_proxy.rb:239:in `load_target' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations/association_proxy.rb:112:in `reload' from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1250:in `previous_event' from (irb):2 what is going wrong here? thanks a ton for your help.

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  • jQuery: Inserting li items one by one?

    - by Legend
    I wrote the following (part of a jQuery plugin) to insert a set of items from a JSON object into a <ul> element. ... query: function() { ... $.ajax({ url: fetchURL, type: 'GET', dataType: 'jsonp', timeout: 5000, error: function() { self.html("Network Error"); }, success: function(json) { //Process JSON $.each(json.results, function(i, item) { $("<li></li>") .html(mHTML) .attr('id', "div_li"+i) .attr('class', "divliclass") .prependTo("#" + "div_ul"); $(slotname + "div_li" + i).hide(); $(slotname + "div_li" + i).show("slow") } } }); } }); }, ... Doing this maybe adding the <li> items one by one theoretically but when I load the page, everything shows up instantaneously. Instead, is there an efficient way to make them appear one by one more slowly? I'll explain with a small example: If I have 3 items, this code is making all the 3 items appear instantaneously (at least to my eyes). I want something like 1 fades in, then 2 fades in, then 3 (something like a newsticker perhaps). Anyone has a suggestion?

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  • When destroying one record, another one gets destroyed

    - by normalocity
    Products (like an iPod Classic) :has_many = :listings, :dependent = :destroy Listings (like "My name is Joe, and I have an iPod for sale) :belongs_to = :product So, if I delete a given Product, all the listings that point to it get deleted. That makes sense, and is by design. However, I am writing a "merge" function, where you merge two Products into one, and combine their Listings. So, let's say my two products are "iPod Color" and "iPod Classic", and I want to merge the two. What I want to do is say, "iPod Color, merge into iPod Classic", and result should be that: All the iPod Color Listings are re-pointed to the iPod Classic product After the product_id change, the Listing(s) are saved I then delete the "iPod Color" product Well, that should all work fine, without deleting any Listings. However, I've got this controller, and for whatever reason when I destroy the "iPod Color" Product, even after confirming that the Listings have been moved to "iPod Classic" and saved to the database, the Listings that were previously pointed to "iPod Color" get destroyed as well, and I can't figure out why. It's as if they are retaining some kind of link to the destroyed product, and therefore begin destroyed themselves. What painfully obvious thing am I missing? def merge merging_from = Product.find(params[:id]) merging_to = Product.find_by_model(params[:merging_to]) unless merging_to.nil? unless merging_from.nil? unless merging_from == merging_to # you don't want to merge something with itself merging_from.listings.each do |l| l.product = merging_to l.save end # through some debugging, I've confirmed that my missing Listings are disappearing as a result of the following destroy call merging_from.destroy end end end

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  • computer shows up twice, connection unknown

    - by Thomas G. Seroogy
    added two computers to Ubuntu One. One machine is windows. The windows version seems to work fine, and I started syncing a folder by placing it into the Ubuntu One folder. All files and folders are visible when I go to my account online. On Ubuntu machine. I selected to sync the Download folder. Shortly thereafter, I realized that one folder exceeded my storage max. I tried to un-sync the folder, but Ubuntu One and the Stop Syncing This Folder were not visible in the menu. Per Ubuntu instructions, I removed my Ubuntu computer from the list of syncing computers. Per Ubuntu instructions, I re-added the Ubuntu computer. However, I find that two computers by the same name are added on both the desktop app and on the web. Plus, I the connection is "unknown." I have removed and re-added the computer several times with the same results. In all cases, I remove the computers using the Ubuntu One desktop app, then removing them from my account on the web, removing the Ubuntu One password, and restart the Ubuntu One app. Problem remains. Thanks in advance for any replies and help.

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  • Can all-in-one desktops be good developer machines?

    - by user6900
    I was just going through some all-in-one desktop PCs (Dell Studio One, HP Touch Smart, Lenovo IdeaCenter, etc.) and their specs really look good (4 GB RAM, 2.x GHz Core 2 Duo, etc.) Are there any disadvantages of such PCs as a developer machine? I mostly do Java (Eclipse + MySQL + Tomcat / JBoss) or .NET (Visual Studio + MsSQL) development. Edit: One common question I could see is harddrive size and that's around 320 GB 7200 RPM.

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  • Ruby on Rails: having two xmlbuilder templates per action , one for errors one for regular output

    - by randombits
    What's the best way to handle having two templates (or should it be one, DRY?) for xml builder templates? I'm building a web api with Rails and wanted to see an example of how to have a view that does regular output vs one that does error output. I've been using @obj.to_xml for a while, but my requirements have changed and require me building my own error templates. do you typically have both views in one with a condition above for errors such as app/views/myresource/create.xml.builder unless @myobj.errors.empty? // xml for errors here? end // regular xml view

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  • Copy / Move One SAP Client From One System to another System

    - by JonH
    We have one SAP system in the US (lets call it TKIJVPL1), this system has an SAP Client, client 241. We have another SAP system in Germany (lets call it Lockweiler). We need to move this client 241 from our TKIJVPL1 server to this new server. Can I simply use transaction SCC8? It says client export, but when I look at the options it says Source client : 241 (which is good), it says Profile Name SAP_ALL (which is also good as I need all data), but Target System all that is coming up is PL1 / QL1. What is the easiest way to export one client from one system to another system in SAP?

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  • Making invisible table rows visible one by one

    - by Roland
    I have the following situation I have a couple of table rows within a table eg <tr><td>One</td></tr> <tr><td>Two</td></tr> <tr><td>Three</td></tr> <tr><td>Four</td></tr> <tr><td>Five</td></tr> Say all of them are invisible Then I have a button to make them visible one by one, so if row 1 is invisible and I press the button then row 1 should be visible, if I press it again it sees that row 1 is already visible then it makes row 2 visible and so it goes on and on and on. How can I do this in Jquery so that jquery can accomplish this task for me. Is it possible?

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  • Why does the Java Collections Framework offer two different ways to sort?

    - by dvanaria
    If I have a list of elements I would like to sort, Java offers two ways to go about this. For example, lets say I have a list of Movie objects and I’d like to sort them by title. One way I could do this is by calling the one-argument version of the static java.util.Collections.sort( ) method with my movie list as the single argument. So I would call Collections.sort(myMovieList). In order for this to work, the Movie class would have to be declared to implement the java.lang.Comparable interface, and the required method compareTo( ) would have to be implemented inside this class. Another way to sort is by calling the two-argument version of the static java.util.Collections.sort( ) method with the movie list and a java.util.Comparator object as it’s arguments. I would call Collections.sort(myMovieList, titleComparator). In this case, the Movie class wouldn’t implement the Comparable interface. Instead, inside the main class that builds and maintains the movie list itself, I would create an inner class that implements the java.util.Comparator interface, and implement the one required method compare( ). Then I'd create an instance of this class and call the two-argument version of sort( ). The benefit of this second method is you can create an unlimited number of these inner class Comparators, so you can sort a list of objects in different ways. In the example above, you could have another Comparator to sort by the year a movie was made, for example. My question is, why bother to learn both ways to sort in Java, when the two-argument version of Collections.sort( ) does everything the first one-argument version does, but with the added benefit of being able to sort the list’s elements based on several different criteria? It would be one less thing to have to keep in your mind while coding. You’d have one basic mechanism of sorting lists in Java to know.

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  • UITableView having one Cell with multiple UITextFields (some of them in one row) scrolling crazy

    - by Allisone
    I have a UITableView (grouped). In that tableview I have several UITableViewCells, some custom with nib, some default. One Cell (custom) with nib has several UITextfields for address information, thus also one row has zip-code and city in one row. When I get the keyboard the tableview size seems to be adjusted automatically (vs. another viewController in the app with just a scrollview where I had to code this functionality on my own) so that i can scroll to the bottom of my tableview (and see it) even though the keyboard is up. That's good. BUT when I click on a textfield the tableview gets either scrolled up, or down, I can't figure out the logic. It seems to be rather random up/down scrolling / contentOffset setting. So I have bound the Editing Did Begin events of the textfields to a function that has this code. - (IBAction)textFieldDidBeginEditing:(UITextField *)textField { CGPoint pt; CGRect rc = [textField bounds]; rc = [textField convertRect:rc toView:self.tableView]; pt = rc.origin; pt.x = 0; [self.tableView setContentOffset:pt animated:YES]; ... } This, well, it seems to work most of the time, BUT it doesn't work if I click the first textfield (the view jumps so that the second row gets to the top and the first row is out of the current visible view frame) AND it also doesn't work if I first select the zip textfield and next the city textfield (both in one row) or vice versa. If I do so, the tableview seems to jump to the (grouped tableview) top of my viewForHeaderInSection(this section with this mentioned cell with all my textfields) What is is going on ? Why is this happening ? How to fix this ? Edit This on the other hand behaves as expected (for the two Textviews wit same origin.y) if (self.tableView.contentOffset.y == pt.y) { pt.y = pt.y + 1; [self.tableView setContentOffset:pt animated:YES]; }else { [self.tableView setContentOffset:pt animated:YES]; } But this is a stupid solution. I wouldn't like to keep it that way. And this also doesn't fix the wrong jumping, when clicking the first textfield at first.

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  • android: having two listviews in two listactivities didn't work

    - by Yang
    I guess my previous question wasn't clear enough (http://stackoverflow.com/questions/2549585/android-failed-to-setcontentview-when-switching-to-listactivity), so I explain as follows. In my app I have two listactivities which uses two different listviews: public class Activity1 extends ListActivity { @Override public void onCreate(Bundle savedInstanceState) { try{ super.onCreate(savedInstanceState); setContentView(R.layout.listview1); } public class Activity2 extends ListActivity { @Override public void onCreate(Bundle savedInstanceState) { try{ super.onCreate(savedInstanceState); setContentView(R.layout.listview2); } } As required by android, listview must have an ID which is exactly "@android:id/list". If I set the listview in both listview1 and listview2 with the same ID, then they will end up using the same format of listview, which is not what I want. But if I set one of the IDs to be sth like "@+id/listview2", android gave me the error: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' How do I handle this dilema?

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  • MYSQL Inner Join two table over two keys

    - by bertsisterwanda
    I am doing a query to return all users shopping carts, stored in the sb_carts table. The product information stored in sb_carts is referenced over two keys product_sku and school_id. It needs to reference both to return a unique product with unique stock levels etc. When I execute the following query it returns one row, I am expecting 3 rows. I have tried breaking the inner join into two separate joins but this still returns only 1 result. joining only on one key has the desired result, but may be retuning the wrong product. A left join returns 3 rows but some data is missing product specific Here is a simplified example of what I am doing SELECT sb_carts.product_sku FROM sb_carts INNER JOIN sb_products ON sb_products.sku = sb_carts.product_sku AND sb_products.school_id = sb_carts.school_id WHERE sb_carts.order_id = 0 AND sb_carts.user_id = 2 GROUP BY sb_carts.cart_id

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