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  • Load different levels in XML

    - by Anearion
    my question is more about a theoretical gener than a pratical way to make things happen. I'm about start developing a game for android, text based so i won't need sprites or animation, nor a game engine. Let's say is similar to a sudoku game, where each level is an harder version of sudoku and each level has some question to be asnwered over the sudoku itself. I was wondering if the better way is to have only one XML and then inside all the different levels, each one with his meta-tags, or if the different approach of making n xml files where each one is a level is preferred. At the moment a level should have those tags: <level> <question>Question_1</question> <hint1>what does it do?</hint1> <hint2>where...</hint2> .... <hintN>how...</hintN> </level> So each level could have some items to read and that's what made me think that maybe different files are better cuz if i have to load lvl 10 i can read only the 10.xml file. I hope my question isn't too stupind. Thanks in advance

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  • XML Serialization and Soap Serialization

    - by Costa
    Hi I think even if we will not need interoperability between applications, and even we do not communicate with web services, it is easier to serialize using SoapFormatter than XmlSerializer because SOAP will serialize the private members by default, while XmlSerializer will work on public properties and fields. actually I cannot find a reason for using XmlSerializer, do I miss something? what is disadvantages of SoapFormatter. or what is advantage of XML serialization over Soap? (xsd) thanks

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  • working python xml

    - by ricardo
    hello all, my question is the following, which is the best way of working XML (kml) with python?, especially script serializable. thanks for your attention and answers

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  • Linq-to-XML query to select specific sub-element based on additional criteria

    - by BrianLy
    My current LINQ query and example XML are below. What I'd like to do is select the primary email address from the email-addresses element into the User.Email property. The type element under the email-address element is set to primary when this is true. There may be more than one element under the email-addresses but only one will be marked primary. What is the simplest approach to take here? Current Linq Query (User.Email is currently empty): var users = from response in xdoc.Descendants("response") where response.Element("id") != null select new User { Id = (string)response.Element("id"), Name = (string)response.Element("full-name"), Email = (string)response.Element("email-addresses"), JobTitle = (string)response.Element("job-title"), NetworkId = (string)response.Element("network-id"), Type = (string)response.Element("type") }; Example XML: <?xml version="1.0" encoding="UTF-8"?> <response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Account Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Alice</full-name> <network-id>79629</network-id> <stats> <followers>2</followers> <updates>4</updates> <following>3</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>alice</name> <web-url>https://www.yammer.com/domain.com/users/alice</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089943</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089943</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Office Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Bill</full-name> <network-id>79629</network-id> <stats> <followers>3</followers> <updates>1</updates> <following>1</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>bill</name> <web-url>https://www.yammer.com/domain.com/users/bill</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089920</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089920</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> </response>

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  • How to add XML elements into the toolbox in Visual Studio 2010 RC

    - by Alex Marshall
    I'm trying to edit an XML schema in Visual Studio 2010 Ultimate RC, but when I go to the toolbox (with the schema open and focused) there's absolutely nothing in the Toolbox view, even when every tutorial out there that I've read tells me that there should be. I've tried using the context menu option for resetting the Toolbox to no effect. Is there something I'm missing ? Something I need to install to get this feature of Visual Studio going ?

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  • c# linq to xml dynamic query

    - by David Archer
    Right, bit of a strange question; I have been doing some linq to XML work recently (see my other recent posts here and here). Basically, I want to be able to create a query that checks whether a textbox is null before it's value is included in the query, like so: XDocument db = XDocument.Load(xmlPath); var query = (from vals in db.Descendants("Customer") where (if(textbox1.Text != "") {vals.Element("CustomerID") == Convert.ToInt32(textbox1.Text) } || if(textbox2.Text != "") {vals.Element("Name") == textbox2.Text}) select vals).ToList();

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  • Specify XML schema data type of decimal or blank

    - by Jeremy Stein
    Is there a way in an XML schema to specify that an element may contain either an empty string or a decimal? If I specify the type as xs:decimal like this: <xs:element name="Sample" type="xs:decimal" /> then a blank value would not pass validation: <Sample/> (I realize that the best way to indicate no value would be to not include the element, but I was wondering if there was a way to allow blank or decimal.)

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  • How to generate following xml

    - by Mohsan
    hi. i want to generate XML for the following tree type structure. i attached picture. generated xml should be <services> <service> <name>Service 1</name> <categories> <category> <name>Cateogry 1</name> <methods> <method> <name>Method 1</name> </method> </methods> </category> </categories> </service> <service> <name>Service 2</name> <categories> <category> <name>Cateogry 1</name> <methods> <method> <name>Method 1</name> </method> </methods> </category> </categories> </service> <service> <name>Service 3</name> <categories> <category> <name>Cateogry 1</name> <methods> <method> <name>Method 1</name> </method> </methods> </category> </categories> </service> </services>

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  • Digitally Sign Parts of a XML document

    - by Eros
    I have an XML document having structure similar to the following <envelop> <header>blaa</header> <message>blaa blaa</message> <footer></footer> </envelop> I want to digitally sign the header and message elements and add the signature to the footer element. How can I sign the elements and then later verify the signature (using .net c#) ?

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  • Serialize a message format to xml

    - by anijhaw
    I have a python list as [ (A,{'a':1,'b':2,'c':3,'d':4}), B,{'a':1,'b':2,'c':3,'d':4}), ... ] I want to know if there is a standard library of serializing this kind of list to xml or should I hand code it to a file.

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  • Dataset -> XML Document - Load DataSet into an XML Document - C#.Net

    - by NLV
    Hello I'm trying to read a dataset as xml and load it into an XML Document. XmlDocument contractHistoryXMLSchemaDoc = new XmlDocument(); using (MemoryStream ms = new MemoryStream()) { //XmlWriterSettings xmlWSettings = new XmlWriterSettings(); //xmlWSettings.ConformanceLevel = ConformanceLevel.Auto; using (XmlWriter xmlW = XmlWriter.Create(ms)) { xmlW.WriteStartDocument(); dsContract.WriteXmlSchema(xmlW); xmlW.WriteEndDocument(); xmlW.Close(); using (XmlReader xmlR = XmlReader.Create(ms)) { contractHistoryXMLSchemaDoc.Load(xmlR); } } } But I'm getting the error - "Root Element Missing". Any ideas? Update When i do xmlR.ReadInnerXML() it is empty. Does anyone know why? NLV

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  • WCF Method is returning xml fragment but no xml UTF-8 header

    - by horls
    My method does not return the header, just the root element xml. internal Message CreateReturnMessage(string output, string contentType) { // create dictionaryReader for the Message byte[] resultBytes = Encoding.UTF8.GetBytes(output); XmlDictionaryReader xdr = XmlDictionaryReader.CreateTextReader(resultBytes, 0, resultBytes.Length, Encoding.UTF8, XmlDictionaryReaderQuotas.Max, null); if (WebOperationContext.Current != null) WebOperationContext.Current.OutgoingResponse.ContentType = contentType; // create Message return Message.CreateMessage(MessageVersion.None, "", xdr); } However, the output I get is: <Test> <Message>Hello World!</Message> </Test> I would like the output to render as: <?xml version="1.0" encoding="utf-8" standalone="yes"?> <Test> <Message>Hello World!</Message> </Test>

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  • how to merge xml string to main xml document object

    - by CliffC
    how can i merge the following xml string <employee> <name>cliff</name> </employee> to my existing xml document object XmlDocument xmlDoc = new XmlDocument(); XmlElement xmlCompany = xmlDoc.CreateElement("Company"); the final output should look like <Company> <employee> <name>cliff</name> </employee> </Company> thanks

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  • Convert XML attributes to a Dictionary in Linq to XML

    - by NateD
    I've got a program that needs to convert two attributes of a particular tag to the key and value of an Dictionary<int,string>. The XML looks like this: (fragment) <startingPoint coordinates="1,1" player="1" /> and so far my LINQ looks something like this: XNamespace ns = "http://the_namespace"; var startingpoints = from sp in xml.Elements(ns+"startingPoint") from el in sp.Attributes() select el.Value; Which gets me a nice IEnumerable full of things like "1,1" and "1", but there should be a way to adapt something like this answer to do attributes instead of elements. Little help please? Thank you!

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  • VB.NET add an element to the XML document with LINQ to XML

    - by Bayonian
    Hi, I'm adding an element to existing XML doc with the following code: Dim theXMLSource As String = Server.MapPath("~/Demo/") & "LabDemo.xml" Dim nodeElement As XElement Dim attrAndValue As XElement = _ <LabService> <ServiceType> <%= txtServiceType.Text.Trim %> </ServiceType> <Level> <%= txtLevel.Text.Trim %> </Level> </LabService> nodeElement.Add(New XElement(attrAndValue)) nodeElement.Save(theXMLSource) It makes error like this: System.NullReferenceException: Object reference not set to an instance of an object. Object reference not set to an instance of an object. Error line: nodeElement.Add(New XElement(attrAndValue)) I debugged it but I couldn't get the error yet. Can you show what the problem is? Thank you

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  • Need Simple way to access XML in VB.Net - Pain with Linq-to-Xml

    - by aiart
    Dim myXDoc As XDocument = _ I want to access this in a simple way in VB.Net - Like: Dim Integer SizeXStr = CInt(MyZDoc.Cameras(1).Camera_Desc.@SizeX) ' where (1) is an index Why isn't this implemented in VB.Net? Better yet, type the values with a Schema and eliminate the conversion. Is this so hard? How do I access, in a simple way, data in XML - this would be VERY VERY useful! I have been using Query to try to get the values - when I use MsgBox() to display results, they display, but my main Windows Form is Trashed - changed colors, etc. The system has Bugs. Instead, I have to create an elaborate structure of arrays of objects and read the XML line-by-line and do the same for saving - this is the dark ages. Art

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  • Reading xml within xml as String in flex/AS3

    - by duder
    I'm getting XML input that looks like this <?xml version="1.0" encoding="utf-8"?> <data1>this is data 1</data1> <data2>this is data 2</data2> <data3> <3a>this is data 3a</3a> <3b>this is data 3b</3b> <3c> <TextFlow xmlns="http://ns.adobe.com/textLayout/2008"> <p direction="ltr" > <span>some text</span> <span>some additional text</span> </p> <p direction="ltr"> <span>some text</span> <span>some additional text</span> </p> </TextFlow> </3c> </data3> I can read <data1> with event.result.data1 which outputs a string this is data1 But when I do the same thing to event.result.data3.3c, it prints object [object] so I guess it's trying to dig deeper into the tree. But I need the actual string text (not xml tree) starting from and including <TextFlow></TextFlow> to be stored and printed as a string. Any idea what's the syntax for this? The string I'm looking for would look like this: <TextFlow xmlns="http://ns.adobe.com/textLayout/2008"> <p direction="ltr" > <span>some text</span> <span>some additional text</span> </p> <p direction="ltr"> <span>some text</span> <span>some additional text</span> </p> </TextFlow>

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  • how to read value of an xml node (single) using linq to xml

    - by Wondering
    Hi All, I have a xml structure similar to below one: <test> <test1>test1 value</test1> </test> Now I am reading the value of node using below LINQ to xml code. var test = from t in doc.Descendants("test") select t.Element("test1").Value; Console.WriteLine("print single node value"); Console.WriteLine(test); above code works fine, but here I have one single node, but to retrive value I am using foreach loop, which I dont think is good..any better way of doing the same thing without a foreach loop Thanks.

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  • Is this __import__ functionality correct?

    - by Jason Baker
    I have a package named jiva_tasks, which I'm trying to import via celery (using the CELERY_IMPORTS attribute of celeryconfig. The import statement that celery is using is this: __import__(module, [], [], ['']) Oddly enough, when this syntax is used, the module gets imported twice, once as jiva_tasks and another time as jiva_tasks. (with a period at the end). Now, chances are good that celery should be passing in globals rather than an empty list, but this seems broken to me. It seems odd that even if given the wrong arguments, __import__ would import something that isn't a valid python module name. I know that the way to fix this is to pass in globals, but I want to understand why I'm getting this result. Is this a bug, or is there something I don't understand about how __import__ is working? Update: It also seems to be working fine if I use importlib.

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  • How to import a module from a directory?

    - by Roman
    On my system I have two versions of Python (to call them I type python and python2 in the command line). When I use the first version of Python, I cannot import sklearn module but I can do it in the second version of Python. I would like to use the first version of python (because other modules are available there) and, at the same time, I would like to be able to import sklearn from this version of Python. My solution was to use: import sys sys.path.append('location_of_the_sklearn_module') To find the location of the sklearn module I started a python session (using the second version of python, in which sklearn works). The I type: import sklearn sklearn.__file__ As a result I got: /home/name/my_name/numpy/local/lib/python2.7/site-packages/sklearn/__init__.pyc In the session of the first version of Python I tried: import sys sys.path.append('/home/name/my_name/numpy/local/lib/python2.7/site-packages/sklearn') import sklearn Unfortunately it did not work. As a result I got: ImportError: No module named sklearn Does anybody know what I am doing wrong and if it is possible to reach the goal in the way I try?

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