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  • Any cloud storage service that lets us to authenticate the file when we serve the file to our visito

    - by TORr0t
    Lets say, i want to restrict a file to my visitors. I mean , i have an xx.avi file to be streamed/downloaded, and the visitor paid me for the bandwidth and the size of the file. In amazon s3, i cant control the file at all .(there is a very basic control thing which is not ok for me) Only way is my server can proxy the file, like it fetches the file from amazon s3 storagenode and send it to the owner with authentication approval by a php script. But this way i would double up the bandwidth usage and again there would be latency problem since my server needs to get the file from amazon s3. So i was wondering if there is a better solution or any cloud storage service that lets us to control the file restriction to my visitors. Thanks

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  • windows symbolic file links arn't followed through network access

    - by fpdragon
    I have a server with win7 and a big share on C:\share In this share there are many symbolic links to files on other local disks like C:\share\file.txt(symlink) <- D:\file.txt I can access the file over: C:\share\file.txt \server\share\file.txt but if I try to access from an other pc I can't open the file. I'm able to delete, rename ... the link but it seems that the symbolic link isn't processed by the server. Can I change something with cifs to make this work? I already checked the acls of the link and the file and set them to allow everybody everything. I also can access the file with d$. Hope there is a solution...

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  • Move hibernate file to a different drive

    - by Kamarey
    Is it possible to move a Windows hibernate file to a different drive? E.g. if I have Windows installed on C, I want it's hibernate file be on D. Eee... just thought that I wanted to ask this question about hibernate file, not the page file. Don't know where the page file came from. Sorry:) So the question is about hibernate file. But no problems with all answers about page file. (Edit: The original question title was "Move page file to a different drive")

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  • creating objects from trivial graph format text file. java. dijkstra algorithm.

    - by user560084
    i want to create objects, vertex and edge, from trivial graph format txt file. one of programmers here suggested that i use trivial graph format to store data for dijkstra algorithm. the problem is that at the moment all the information, e.g., weight, links, is in the sourcecode. i want to have a separate text file for that and read it into the program. i thought about using a code for scanning through the text file by using scanner. but i am not quite sure how to create different objects from the same file. could i have some help please? the file is v0 Harrisburg v1 Baltimore v2 Washington v3 Philadelphia v4 Binghamton v5 Allentown v6 New York # v0 v1 79.83 v0 v5 81.15 v1 v0 79.75 v1 v2 39.42 v1 v3 103.00 v2 v1 38.65 v3 v1 102.53 v3 v5 61.44 v3 v6 96.79 v4 v5 133.04 v5 v0 81.77 v5 v3 62.05 v5 v4 134.47 v5 v6 91.63 v6 v3 97.24 v6 v5 87.94 and the dijkstra algorithm code is Downloaded from: http://en.literateprograms.org/Special:Downloadcode/Dijkstra%27s_algorithm_%28Java%29 */ import java.util.PriorityQueue; import java.util.List; import java.util.ArrayList; import java.util.Collections; class Vertex implements Comparable<Vertex> { public final String name; public Edge[] adjacencies; public double minDistance = Double.POSITIVE_INFINITY; public Vertex previous; public Vertex(String argName) { name = argName; } public String toString() { return name; } public int compareTo(Vertex other) { return Double.compare(minDistance, other.minDistance); } } class Edge { public final Vertex target; public final double weight; public Edge(Vertex argTarget, double argWeight) { target = argTarget; weight = argWeight; } } public class Dijkstra { public static void computePaths(Vertex source) { source.minDistance = 0.; PriorityQueue<Vertex> vertexQueue = new PriorityQueue<Vertex>(); vertexQueue.add(source); while (!vertexQueue.isEmpty()) { Vertex u = vertexQueue.poll(); // Visit each edge exiting u for (Edge e : u.adjacencies) { Vertex v = e.target; double weight = e.weight; double distanceThroughU = u.minDistance + weight; if (distanceThroughU < v.minDistance) { vertexQueue.remove(v); v.minDistance = distanceThroughU ; v.previous = u; vertexQueue.add(v); } } } } public static List<Vertex> getShortestPathTo(Vertex target) { List<Vertex> path = new ArrayList<Vertex>(); for (Vertex vertex = target; vertex != null; vertex = vertex.previous) path.add(vertex); Collections.reverse(path); return path; } public static void main(String[] args) { Vertex v0 = new Vertex("Nottinghill_Gate"); Vertex v1 = new Vertex("High_Street_kensignton"); Vertex v2 = new Vertex("Glouchester_Road"); Vertex v3 = new Vertex("South_Kensignton"); Vertex v4 = new Vertex("Sloane_Square"); Vertex v5 = new Vertex("Victoria"); Vertex v6 = new Vertex("Westminster"); v0.adjacencies = new Edge[]{new Edge(v1, 79.83), new Edge(v6, 97.24)}; v1.adjacencies = new Edge[]{new Edge(v2, 39.42), new Edge(v0, 79.83)}; v2.adjacencies = new Edge[]{new Edge(v3, 38.65), new Edge(v1, 39.42)}; v3.adjacencies = new Edge[]{new Edge(v4, 102.53), new Edge(v2, 38.65)}; v4.adjacencies = new Edge[]{new Edge(v5, 133.04), new Edge(v3, 102.53)}; v5.adjacencies = new Edge[]{new Edge(v6, 81.77), new Edge(v4, 133.04)}; v6.adjacencies = new Edge[]{new Edge(v0, 97.24), new Edge(v5, 81.77)}; Vertex[] vertices = { v0, v1, v2, v3, v4, v5, v6 }; computePaths(v0); for (Vertex v : vertices) { System.out.println("Distance to " + v + ": " + v.minDistance); List<Vertex> path = getShortestPathTo(v); System.out.println("Path: " + path); } } } and the code for scanning file is import java.util.Scanner; import java.io.File; import java.io.FileNotFoundException; public class DataScanner1 { //private int total = 0; //private int distance = 0; private String vector; private String stations; private double [] Edge = new double []; /*public int getTotal(){ return total; } */ /* public void getMenuInput(){ KeyboardInput in = new KeyboardInput; System.out.println("Enter the destination? "); String val = in.readString(); return val; } */ public void readFile(String fileName) { try { Scanner scanner = new Scanner(new File(fileName)); scanner.useDelimiter (System.getProperty("line.separator")); while (scanner.hasNext()) { parseLine(scanner.next()); } scanner.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } } public void parseLine(String line) { Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s*,\\s*"); vector = lineScanner.next(); stations = lineScanner.next(); System.out.println("The current station is " + vector + " and the destination to the next station is " + stations + "."); //total += distance; //System.out.println("The total distance is " + total); } public static void main(String[] args) { /* if (args.length != 1) { System.err.println("usage: java TextScanner2" + "file location"); System.exit(0); } */ DataScanner1 scanner = new DataScanner1(); scanner.readFile(args[0]); //int total =+ distance; //System.out.println(""); //System.out.println("The total distance is " + scanner.getTotal()); } }

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  • File Encryption Operation

    - by kiruthika
    Hi All, I have doubt in gpg command operation . Actually we are using gpg command for encrypting the file . File.txt has following things. Testing hello world My security things. Now I am doing the file encryption for File.txt gpg --symmetric File.txt Now I got File.txt.gpg file , which is encrypted. My doubt, if some open that file and did someone changes in that I am not able get file content . It says my following things. $ gpg --decrypt File.txt.gpg gpg: no valid OpenPGP data found. gpg: decrypt_message failed: eof I want my file content , even though some body has done changes in that . what should I do for this problem....?

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  • Compile a binary file for linking OSX

    - by Satpal
    I'm trying to compile a binary file into a MACH_O object file so that it can be linked it into a dylib. The dylib is written in c/c++. On linux the following command is used: ld -r -b binary -o foo.o foo.bin I have tried various option on OSX but to no avail: ld -r foo.bin -o foo.o gives: ld: warning: -arch not specified ld: warning: ignoring file foo.bin, file was built for unsupported file format which is not the architecture being linked (x86_64) An empty .o file is created ld -arch x86_64 -r foo.bin -o foo.o ld: warning: ignoring file foo.bin, file was built for unsupported file format which is not the architecture being linked (x86_64) Again and empty .o file is created. Checking the files with nm gives: nm foo.o nm: no name list The binary file is actually, firmware that will be downloaded to an external device. Thanks for looking

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  • Java: Looking for hack to deal with Windows file paths in Linux

    - by Chase Seibert
    Say you have a large legacy ColdFusion on top of Java on Windows application. File access is done both via java.io.File and by CFFILE (which in turn also uses java.io.File), but not centralised in any way into a single file access library. Further, say you have file paths both hard-coded in the code, and also in a database. In other words, assume the file paths themselves cannot change. They could be either local or remote Windows file paths: c:\temp\file.txt \\server\share\file.txt Is there a way to run this application on Linux with minimal code changes? I'm looking for creative solutions that do not involve touching the legacy code. Some ideas: Run it on WINE. This actually works, because WINE will translate the local paths, and has a samba client for the remote paths. Is there a way to override java.io.File to perform the file path translation with custom code? In this case, I would translate the remote paths to a mount point.

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  • How to determinate file in Perl

    - by rodnower
    Hello, I use File::Find - find(\&f, $directory) for find some file with some content. Relevant part of my delegate looks like: sub f { my $file = $File::Find::name; return unless -f $file; return unless $file =~ /$file_pattern/; etc... but the problem is that, that this code returns every time where $file not exist in current directory. For example for file ./test it fine, but for file ./dir/test this return... Is there some better way to know if $file is file?

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  • How to grant write permissions in Samba?

    - by Eric Fossum
    I'm having trouble with read/write permissions on my Samba server, how do I fix my smb.conf and file permissions to have a more unified access? smb.conf [global] workgroup = workgroup netbios name = LnxNAS server string = %h wins support = no dns proxy = no security = user encrypt passwords = yes panic action = /usr/share/samba/panic-action %d [homes] comment = Home Directories [Video] path = /data/eric/Videos [Music] path = /data/eric/Music [Pictures] path = /data/eric/Pictures [data] path = /data my ls -l of /data/eric/Pictures drwxrwxrwx 2 ericfoss root 4096 2011-03-13 22:09 Android Projs drwxrwxrwx 3 ericfoss root 4096 2011-03-13 22:09 Automotive -rwxrwxrwx 1 ericfoss root 2439 2010-12-17 17:03 BDD reduction.png -rwxrwxrwx 1 ericfoss root 2722 2010-12-17 16:55 BDD Tree.png -rwxrwxrwx 1 ericfoss root 7341 2010-12-17 16:46 BDD Tree.xcf -rwxrwxrwx 1 ericfoss root 72421 2007-11-22 22:59 Bum Ninja.jpg -rwxrwxrwx 1 ericfoss root 32152 2010-12-17 21:25 cell transition.png -rwxrwxrwx 1 ericfoss root 40212 2010-12-17 17:55 control graph.png drwxrwxrwx 2 ericfoss root 4096 2011-03-13 22:09 Crap -rwxrwxrwx 1 ericfoss root 82 2010-09-20 17:18 desktop.ini ericfoss@SERVER:~$ If I try to delete \Server\Pictures\Crap it says permission denied, but \Server\data\eric\Pictures\crap can be deleted... I thought security = user took care of this?

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  • Share files - Ubuntu 12.4 and Windows 7 - one network - password not accepted

    - by gotqn
    I ask this question in SuperUser but no one helps me. I hope to get more attention here. I have three computers connected in one network by modem. I want to share files in this network in the most easy way (I have read about solutions using Samba). So, I have three machines: One with Windows 7 One with Windows XP One with Ubuntu 12.04 and I have the following situation: The windows PCs can share files between each other. The windows PCs can see that Ubuntu's one is in the network The PC with Ubuntu can see only the PC with Windows 7, but when I click on a folder it ask to enter the network password and it is not accepting it (I am 100% sure it's the correct one) Is there to fix this situation a little bit - at least to enable the file sharing between the Ubuntu and Windows 7 PCs or I should choose a different approach (please advice).

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  • How to design a replay system

    - by daddz
    So how would I design a replay system? You may know it from certain games like Warcraft 3 or Starcraft where you can watch the game again after it has been played already. You end up with a relatively small replay file. So my questions are: How to save the data? (custom format?) (small filesize) What shall be saved? How to make it generic so it can be used in other games to record a time period (and not a complete match for example)? Make it possible to forward and rewind (WC3 couldn't rewind as far as I remember)

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  • Ogre3D : seeking advices about game files management

    - by Tibor
    I'm working on a new game, and its related level editor, based on Ogre3D. I was thinking about how i could manage the game files, knowing that Ogre use .mesh files for models, .material for materials/texture information etc... . At first i thought about a common .zip folder decompressed at runtime (the same way Torchlight and Ogre samples do). But this way the game assets become a monolithic archive, loading takes time, and could be difficult to eventually patch them. So, let's say i have a game object named "Cube" i want to load in my program. Going for modularity, what if i create a compressed file (using zlib compression routines) named Cube.extname, containing its sub-files Cube.mesh, Cube.material and so on ? Are there any alternatives or should i stick with compressed objects? PS: Just to clear things, the answer is unrelated to my program code, at the moment i'm using "resources.cfg" pointing to the OgreSDK media directory.

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  • Extremely slow transfer speed ubuntu -> Windows

    - by Hailwood
    I have two laptops, One is running Ubuntu 12.04 (EXT4) the other is running Windows 7 (NTFS). I am copying over 40gb of data (one file) from the Ubuntu laptop to the Windows Laptop. (Browse the shared folder on Ubuntu using Windows copy/paste) But I am getting transfer speeds topping out at ~700kb/s Surely this is not right. I am transferring via wifi on both laptops. My download speeds can reach 7-8mb/s on both laptops, so I know it is not the wifi cards or the router topping out. wlan0 Link encap:Ethernet HWaddr 84:4b:f5:db:b4:85 inet addr:192.168.1.66 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::864b:f5ff:fedb:b485/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:11941185 errors:0 dropped:0 overruns:0 frame:0 TX packets:11306693 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:10087111370 (10.0 GB) TX bytes:7843524888 (7.8 GB)

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  • Error : Could not display "obex://" when paired with a Nokia 3110c

    - by MobileDev123
    Hi, I have paired my nokia 3110c via bt on my pc, I can receive a file from my pc to the phone, but I can not browse the contents of phone from my computer. Here is the error message Error: Did not receive a reply. Possible causes include: the remote application did not send a reply, the message bus security policy blocked the reply, the reply timeout expired, or the network connection was broken. Please select another viewer and try again. How can I transfer contents from my phone to my computer?

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  • bluetooth between ubuntu 10.10 and nokia error : Could not display "obex://"

    - by MobileDev123
    Hi, I have paired my nokia 3110c via bt on my pc, I can receive a file from my pc to the phone, but I can not browse the contents of phone from my computer. Here is the error message Error: Did not receive a reply. Possible causes include: the remote application did not send a reply, the message bus security policy blocked the reply, the reply timeout expired, or the network connection was broken. Please select another viewer and try again. How can I transfer contents from my phone to my computer?

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  • How to setup Ubuntu as a backup server for my Windows computer?

    - by derek
    I took my old computer (AMD 5600+, 2GB RAM, 880gt, 250GB SATA, etc) and decided to jump and try Ubuntu for the first time. I have very very little knowledge (Red Hat when I was younger) with Linux in general. My main desktop is Windows 7 and my plan is to use the Ubuntu computer as a file server sort of speak. I want to be able to setup back up schedules from my Windows PC to the Ubuntu PC (plan on leaving this on 24/7 to double as a Seedbox) How do I go on to doing this?

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  • Any pre-rolled System.IO abstraction libraries out there for Unit Testing?

    - by Binary Worrier
    To test methods that use the file system we need to basically put System.IO behind a set of interfaces that we can then mock, I do this with a DiskIO class and interface. As my DiskIO code gets larger (and the grumblings from the we're unconvinced about this TDD thing crowd here in work get louder), I went looking for a comprehensive open source library that already does this and found . . . nothing. I may be looking in the wrong place or have approached this problem in completely the wrong way. I can't be the only idiot in this position, do these libraries exist, if so where are they? Any you've used and would recommend? Thanks P.S. I'm happy with my current approach i.e. starting with what we need, and adding only when the need arises. Unfortunately the we're unconvinced about this TDD thing crowd remain unconvinced, and think that I can't be right.

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  • Difference between '\n' and '\r\n'

    - by sukhbir
    Yes yes, I am aware that '\n' writes a newline in UNIX while for Windows there is the two character sequence: '\r\n'. All this is very nice in theory, but my question is why? Why the carriage return character is extra in Windows? If UNIX can do it in \n why does it take Windows two characters to do this? I am reading David Beazley's Python book and he says: For example, on Windows, writing the character '\n' actually outputs the two- character sequence '\r\n' (and when reading the file back, '\r\n' is translated back into a single '\n' character). Why the extra effort? I will be honest. I have known the difference for a long time but have never bothered to ask WHY. I hope that is answered today. Thanks for your time.

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  • How can I get the camera to follow a moving object from behind in C++ and openGL [closed]

    - by user1324894
    I am trying to get the camera to follow an object that moves around my environment using the gluLookAt function. This is my code for the object moving in the direction that it faces: Xtri += -Vtri*cos((90+heading)*(PI/180.0f)); Ztri += Vtri*sin((90+heading)*(PI/180.0f)); I then render the object: glPushMatrix(); glTranslatef(Xtri,0,Ztri); glRotatef(heading,0,1,0); drawTriangle(); glPopMatrix(); All heading is is a spin variable so that if I press left or right it spins in that direction. When you press up on the arrows it moves forward and if you press down it moves backwards in the direction that it is facing. To try and get it so the camera follows I am using the gluLookAt function like this: gluLookAt(Xtri,0,(Ztri+20), Xtri,0,Ztri, 0,1,0); So that it follows the car from a distance and should follow it around. However, the object doesn't even move at all now all it can do is rotate still but not move forwards or backwards and when it spins it doesn't follow the spin instead it just watches it turn still fixed to the same position. Where is it that I am going wrong? UPDATE: I have updated the gluLookAt function so now it is: gluLookAt((Xtri+Vtri),0,((Ztri+20)), (Xtri+Vtri),0,(Ztri), 0,1,0); This seems to move the object around. I have a stationary terrain so I can see that the object is now moving and in the direction that it is facing. However, I want the camera to follow the object when it spins as well so it is always viewing the object from behind.

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  • Help with debugging COM errors? (.mdi to .pdf file conversions using Microsoft Office Document Imagi

    - by RyanW
    I thought I had a working solution for converting .mdi files to PDF using the Microsoft Office Document Imaging object model. The solution is in a Windows Service, but now I'm running into some errors that I'm having trouble tracking down info on. The exception I get is: The server threw an exception. (Exception from HRESULT: 0x80010105 (RPC_E_SERVERFAULT)) System.Runtime.InteropServices.COMException (0x80010105): The server threw an exception. (Exception from HRESULT: 0x80010105 (RPC_E_SERVERFAULT)) at MODI.DocumentClass.Create(String FileOpen) at DocumentStore.Mdi2PDF(String path, String newPath) Then, in the Event Viewer there is the following Application error: Faulting application MyWindowsServiceName.exe, version 1.0.0.0, time stamp 0x4b97f185, faulting module mso.dll, version 12.0.6425.1000, time stamp 0x49d65443, exception code 0xc0000005, fault offset 0x0000bd8e, process id 0xa5c, application start time 0x01cac08cf032914b. Here's the method that is doing the conversion: private int? Mdi2PDF(String path, String newPath) { int? pageCount = null; string tmpTif = Path.GetTempFileName(); MODI.Document mdiDoc = new MODI.Document(); mdiDoc.Create(path); mdiDoc.SaveAs(tmpTif, MODI.MiFILE_FORMAT.miFILE_FORMAT_TIFF_LOSSLESS, MODI.MiCOMP_LEVEL.miCOMP_LEVEL_HIGH); mdiDoc.Close(false); pageCount = Tiff2PDF(tmpTif, newPath); if (File.Exists(tmpTif)) File.Delete(tmpTif); return pageCount; } I removed all threading from the service invoking this, so that only the primary thread was initializing the MODI object, but still got the error, so it doesn't appear to be threading related. I also built a a console apps converting hundreds of documents and DID NOT get the exception. So, it seems to be caused by creating too many instances of the MODI object, but only instantiated within a Service? Doesn't quite make sense. Anybody have any clues about these errors and how to debug them further?

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  • How to launch multiple Internet Explorer windows/tabs from batch file?

    - by TheZenker
    I would like a batch file to launch two separate programs then have the command line window close. Actually, to clarify, I am launching Internet Explorer with two different URLs. So far I have something like this: start "~\iexplore.exe" "url1" start "~\iexplore.exe" "url2" What I get is one instance of Internet Explorer with only the second URL loaded. Seems the second is replacing the second. I seem to remember a syntax where I would load a new command line window and pass the command to execute on load, but can't find the reference. As a second part of the question: what is a good reference URL to keep for the times you need to write a quick batch file? Edit: I have marked an answer, because it does work. I now have two windows open, one for each URL. (thanks!) The funny thing is that without the /d approach using my original syntax I get different results based on whether I have a pre-existing Internet Explorer instance open. If I do I get two new tabs added for my two URLs (sweet!) If not I get only one final tab for the second URL I passed in.

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  • Image File In Text Editor - What Are The Characters? What's the Process?

    - by TheDarkIn1978
    i'm currently in the process of conceptualizing an art piece for a gallery show next year, so this bizarre question of mine is more than just simple curiosity. if i open up an image file (a .PNG) with Text Edit or Note Pad, the file is presented in textual characters. something like this except: æº"í=™?0Ù:Ã,ÏI8^?K¯pmDHƒÃ?;wÔlD DDF›ä™èÜE[E˜ƒê?¯ƒºäeèçã?'ów+æ1ï‡ê0òHõñ?ò$úîù¥{WÎn}2*Ÿ!y(Ö!%2e9U2µ i4Õ(?=ù(›7}:É?##„G¶VfcVñ[÷D6gvrˆvéZN›=Ù=ó{púp…p?Ók‹oÃvŒÛ»{ùœóüôøW†W–VH\P?P$VTPt^lQ‹_B_S=Q™\Z[Ü)s/{]Œ_û]~¯¿¯Awu˜ùä’JÖ Í*tï[’ÎáÔ=<Æ6?~ZCWSÛpVµ?±ØŒ?nÆ^¨æ??™¡?a¥ë£1µÒÁ#?Gè)G<^mRl™m?jˆj~€"“R–Úª’?u?çO-•m˜â?ìéväˆàˆOä5ùXùûù”]¬]?]›V›œ{X{Óˆ|Ô’Èm{J?4‰Èáæõ}??~Á?óºYáœåüuRFÆ>W|^3Ñ5‰94=,<ú?|1b=2< >ö:?sÃ`¨{úf<f|ÛÖ?ãÊ íâ–âè/_÷O¬}Â?Í›§Ãd’kÃkØ?sSíS? ??øy;-6]ˆ?÷ÌÌÙåËLÈ,l÷uvzNtÆt6Ô6?O ?P?_t_|°N¸]Ÿ{ƒ{è˜3KK> ?x~ò[ñ\ÆXA?x?Ãî?X? ?…°”¸™‘jÂzÕkm~]jObµ·p1°Y‚s?&b”}s?ãËóí-»ñ”÷‰?‡v?ˆ˜WõØ£??æe~;¸n?Ooáa'aÁÎÌ-ª$ª!ª~ ?¨‹CÏpÏO/Á›œ/?80<Ë<§8 can anyone explain what is happening here? are the characters some form translation of pixel data by the text editor? maybe it is completely meaningless / an error? if not, is there a name for this type of data conversion or process?

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  • How can I load txt file from internet into my jsf app?

    - by Elena
    Hi all! It's me again) I have another problem. I want to load file (for example - txt) from web. I tried to use the next code in my managed bean: public void run() { try { URL url = new URL(this.filename); URLConnection connection = url.openConnection(); bufferedReader = new BufferedReader(new InputStreamReader(connection.getInputStream())); if (bufferedReader == null) { return; } System.out.println("wwwwwwwwwwwwwwwwwwwww"); String str = bufferedReader.readLine(); System.out.println("qqqqqqqqqqqqqqqqqqqqqqq = " + str); while (bufferedReader.readLine() != null) { System.out.println("---- " + bufferedReader.readLine()); } } catch(MalformedURLException mue) { System.out.println("MalformedURLException in run() method"); mue.printStackTrace(); } catch(IOException ioe) { System.out.println("IOException in run() method"); ioe.printStackTrace(); } finally { try { bufferedReader.close(); } catch(IOException ioe) { System.out.println("UOException wile closing BufferedReader"); ioe.printStackTrace(); } } } public String doFileUpdate() { String str = FacesContext.getCurrentInstance().getExternalContext().getRequestServletPath(); System.out.println("111111111111111111111 str = " + str); str = "http://narod.ru/disk/20957166000/test.txt.html";//"http://localhost:8080/sfront/files/test.html"; System.out.println("222222222222222222222 str = " + str); FileUpdater fileUpdater = new FileUpdater(str); fileUpdater.run(); return null; } But the BufferedReader returns the html code of the current page, where i am trying to call managed bean's method. It's very strange thing - I have googled and none have had this problem. Maybe I do something wrong, maybe there us a simplest way to load file into web (jsf) app not using net API. Any ideas? Thanks very much for help! With best wishes)

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  • problem writing xml to file with .net mvc - timeout?

    - by Mark
    Hey, so having an issue with writing out to an xml file. Works fine for single requests via the browser, but when I use something like Charles to perform 5-10 repeated requests concurrently several of them will fail. The trace simply shows a 500 error with no content inside, basically I think they start timing out waiting for write access or something... This method is inside my repository class, have also attempted to have repository instance as a singleton but doesn't appear to make any difference.. Any help would be much appreciated. Cheers public void Add(Request request) { try { XDocument requests; XmlReader xmlReader; using (xmlReader = XmlReader.Create(_requestsFilePath)) { requests = XDocument.Load(xmlReader); XElement xmlRequest = new XElement("request", new XElement("code", request.code), new XElement("date", request.date), new XElement("email", new XCData(request.email)), new XElement("name", new XCData(request.name)), new XElement("recieveOffers", request.recieveOffers) ); requests.Root.Element("requests").Add(xmlRequest); xmlReader.Close(); } requests.Save(_requestsFilePath); } catch (Exception ex) { HttpContext.Current.Trace.Warn("Error writing to file: "+ex); } }

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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