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• Mozilla publie une démonstration de la vidéoconférence sans plugins avec WebRTC et HTML 5

  Mozilla publie une démonstration de la vidéoconférence sans plug-ins avec WebRTC et HTML 5 Mozilla travaille sur le support en natif de la vidéoconférence dans son navigateur Firefox. L'organisme a publié récemment une démonstration de la vidéoconférence sans plug-ins en utilisant uniquement HTML5, JavaScript et l'API WebRTC à l'occasion d'une conférence de l'IETF (Internet Engineering Task Force). WebRTC est un framework de communications audio et vidéo open source publié par Google. Il intègre le codec vocal à large et très large spectre iSAC (internet Speech Audio Codec) et codec VP8. Il prend aussi en...

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• Website (X)HTML Code Change Detection [closed]

  - by 0pt1m1z3

  I am looking for an enterprise-grade service or a tool that can be used to scan / fingerprint websites and notify when major XHTML code changes are detected. The tool should be able to continuously scan thousands of websites and determine the percentage of HTML code that has been modified since the last run. And then either save the data where it can be easily accessed or send periodic notifications. I know of services like ChangeDetect.com, but they don't do markup only changes and instead focus on everything, including content. We don't really care about presentation content, because a lot of sites we need to cover are updated frequently with content.

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• Change from static HTML file to meta tag for Google Webmaster verification

  - by Wilfred Springer

  I started verifying the server by putting a couple of static HTMLs in place. Then I noticed that Google wants you to keep these files in place. I didn't want to keep the static HTMLs in, so I want to switch to an alternative verification mechanism, and include the meta tags on the home page. Unfortunately, once your site is verified, you never seem to be able to change to an alternative way of verification. I tried removing the HTML pages. No luck whatsoever. Google still considers the site to be 'verified'. Does anybody know how to undo this? All I want to do is switch to the meta tag based method of site ownership verification.

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• HTML Manifest for Content Folios

  - by Kyle Hatlestad

  I recently worked on a project to create a custom content folio renderer in WebCenter Content. It needed to output the native files in the folio along with a manifest file in HTML format which would list the contents of the folio along with any designated metadata and a relative link to the file within the download.  This way a person could hand someone the folio download and it would be a self-contained package with all of the content and a single file to display the information on the contents.  The default Zip rendition of the folio will output the web-viewable version of the file with an HDA formatted file for each one. And unless you are fluent in HDA or have a tool to read them, they are difficult to consume. [Read More]

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• Testez vos connaissances : premier quizz (X)HTML de la série, de niveau facile

  Nouveauté ! Prêt à tester vos connaissances ? L'équipe de la rédaction Web a le plaisir de vous annoncer son premier quizz ! Au fil des semaines à venir, diverses séries de quizz vous seront proposés afin que vous puissiez vous testez et connaître un peu mieux votre niveau en HTML et CSS. Ces questionnaires à choix multiples sont classés par niveau en commençant par du facile et se terminant par du difficile. Des "numéros hors série" vous seront aussi proposé dont le niveau sera plus ardu encore. Les trois séries de quizz sont les suivantes :facile : questions d'ordre général faisant appel aux ...

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• Will Google follow HTML refresh?

  - by yasar11732

  I want to move my current Tumblr blog to static HTML blog. Currently I am using a custom domain, I am planning on doing the move when Google sees domain name change. I am considering two options: Buying a hosting service Using GitHub pages Buying a hosting service would probably mean I am going to pay for lots of things that I don't need like PHP, MySQL, e-mail service etc. On the other hand, if I use GitHub pages, I can't use .htaccess file to make 301 redirects. I want to change my URL structure and this is important to me. I was wondering if I use: <meta http-equiv=refresh content="0; url=http://example.com/newurl" /> Would Google see it as 301 redirect, so that I won't use my search engine value?

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• Html Element search in Firebug 13 !

  - by Anirudha

  Originally posted on: http://geekswithblogs.net/anirugu/archive/2013/10/26/html-element-search-in-firebug-13.aspxFirebug 13 are currently in development process. In firebug 13 you can search the element the way we do in CSS. This is much better and save time. Now just put your selector in search bar and now you are moving to your code.   In this picture I demo how I search a element of stackoverflow.com this is example of how this feature will work. If you want to use Firebug 13 then follow this blog post to get it https://blog.getfirebug.com/2013/10/25/firebug-1-13-alpha-4/

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• Actionscript 3 and nested lists

  - by Hanpan

  Hi, I have the following code in my XML (EDIT:) which I am trying to show in a RichText using htmlText. <ul> <li>List Item 1 <ul> <li>List Item 2</li> </ul> </li> </ul> Unfortunately, Flash doesn't seem to support nested lists, and I am getting output which looks like this: List item 1 List item 2 Where I want the second ul to be indented further. Any ideas would be much appreciated! Cheers

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• Python 3: unpack inner lists in list comprehension

  - by Beau Martínez

  I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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• python: how to convert list of lists into a single nested list

  - by Bhuski

  I have a python list of lists as shown below: mylist=[ [['orphan1', ['some value1']]], [['parent1', ['child1', ['child', ['some value2']]]]], [['parent1', ['child2', ['child', ['some value3']]]]] ] I need to convert the above list to some thing like this: result=[ ['orphan1', ['some value1']], ['parent1', ['child1', ['child', ['some value2']]], ['child2', ['child', ['some value3']]]] ] Kindly help me approach this problem. I have given only simple list. In actual scenario here, in my list, even grand parents/grand childs are there. How much ever deep the input nested list is, I need to convert it to a single nested list, with common list elements (parents and grand parents) appearing only once. (but the next to innermost list element('child' in above example) should appear as many times it occurs in the input list. I have been trying to do this last two days, but did not end up with working solution :(. I need to use the output in django template filter: unordered_list so that the resultant nested list appears as a nested unordered list in my html page ..

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• JQuery - Ajax saving sortables in connected lists when sortable item is moved

  - by Ben Sinclair

  I have multiple JQuery sortable lists that connect with each other... They allow you to assign users to certain roles. Basically what I want to do is when a user is dragged from one list to another, I want JQuery to pick up the first list that the user was moved from so that I can send an AJAX request to delete it from that list in my database. I tried the following but every time you move the user over a list and haven't even dropped it within a list, it sends this request which means I'll be sending multiple AJAX requests... Does that make sense? $( ".selector" ).sortable({ out: function(event, ui) { ... } }); From my testing, I can use the following code to just update the list that user has been moved to so I've got the second half covered: $( ".selector" ).sortable({ receive: function(event, ui) { ... } }); Hopefully I am making sense :)

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• Using ObjectBindingDatasource to bind to object exposing Lists, cant drag and drop fields onto repor

  - by SKM

  Hey Guys Ive used the ObjectBindingDatasource to bind to a class Ive called "ReportViewModel" which contains properties such as List Companies {get; set;} List Managers {get; set;} in its constructor Im just calling a method to populate with dummy data Managers = new ReportDataRepository().GetManagers(); Companies = new ReportDataReposiroty().GetCompanies(); ... When i create the new Datasource , it shows the ReportViewModel class with the Lists under it. I expand the Companies object and attempt draging and dropping fields onto the report designer and it works. Though doesnt allow me to drag and drop for any other List. Any guidance would be really appreciated.

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• Objective C -- property lists or text files?

  - by William Jockusch

  I need to import a list of about 40,000 words into my Iphone app. The list will be the same every time the app starts. It seems that property lists and text files are reasonable options. Any reason to prefer one over the other? For reasons I don't understand, finder says the property list on my mac is 1MB, while the text file is only 328K. The property list is an NSMutableArray of NSMutableArrays of NSStrings. The text file is a plain txt file. But amount of time the app takes to start up is also important. If I read in a text file, my app would have to do some simple processing on it each time it starts. Thanks.

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• Using Large Lists

  - by cam

  In an Outlook AddIn I'm working on, I use a list to grab all the messages in the current folder, then process them, then save them. First, I create a list of all messages, then I create another list from the list of messages, then finally I create a third list of messages that need to be moved. Essentially, they are all copies of eachother, and I made it this way to organize it. Would it increase performance if I used only one list? I thought lists were just references to the actual item.

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• Python sys.argv lists and indexes

  - by Fred Gerbig

  In the below code I understand that sys.argv uses lists, however I am not clear on how the index's are used here. def main(): if len(sys.argv) >= 2: name = sys.argv[1] else: name = 'World' print 'Hello', name if __name__ == '__main__': main() If I change name = sys.argv[1] to name = sys.argv[0] and type something for an argument it returns: Hello C:\Documents and Settings\fred\My Documents\Downloads\google-python-exercises \google-python-exercises\hello.py Which kind of make sense. Can someone explain how the 2 is used here: if len(sys.argv) >= 2: And how the 1 is used here: name = sys.argv[1]

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• Algorithm - combine multiple lists, resulting in unique list and retaining order

  - by hitch

  I want to combine multiple lists of items into a single list, retaining the overall order requirements. i.e.: 1: A C E 2: D E 3: B A D result: B A C D E above, starting with list 1, we have ACE, we then know that D must come before E, and from list 3, we know that B must come before A, and D must come after B and A. If there are conflicting orderings, the first ordering should be used. i.e. 1: A C E 2: B D E 3: F D result: A C B D E F 3 conflicts with 2, therefore requirements for 2 will be used. If ordering requirements mean an item must come before or after another, it doesn't matter if it comes immediately before or after, or at the start or end of the list, as long as overall ordering is maintained. This is being developed using VB.Net, so a LINQy solution (or any .Net solution) would be nice - otherwise pointers for an approach would be good.

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• Comparing two collection lists

  - by Eric

  I've been at this for few hors now and can't seem to find a solution. I have 2 invnetory lists, one a spreadsheet and the other data table. I need to match the spreadsheet agains the data table to find out if I have missing inventory. The spreadsheet should match with what I have in the db, ie the spreadsheet is like a master so when I have missing inventory in DB I need to add it an list and build a report. I thought by looping throught the spreadsheet and for each inventory in the spreadsheet loop through the data table I can achieve my goal but that proved to be wrong. Any ideas how I would do this? Thanks, Eric

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• Splitting lists inside list haskell

  - by user3713267

  Hi I need to split list by an argument in Haskell. I found function like this group :: Int -> [a] -> [[a]] group _ [] = [] group n l | n > 0 = (take n l) : (group n (drop n l)) | otherwise = error "Negative n" But what if lists that I want to divide are contained by another list? For example group 3 [[1,2,3,4,5,6],[2,4,6,8,10,12]] should return [[[1,2,3],[4,5,6]],[[2,4,6],[8,10,12]]] Is there any way to do that ?

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• Transform Two Lists into One Different List

  - by Ngu Soon Hui

  I have two lists of double List<double> X List<double> Y And I have a destination object: public class PointD { public double X {get;set;} public double Y {get;set;} } How to transform them into a single list? public static List<PointD> Transform(List<double> X, List<double> Y) { } All the errors checking must be there.

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• python conditional list creation from 2D lists

  - by dls

  Say I've got a list of lists. Say the inner list of three elements in size and looks like this: ['apple', 'fruit', 1.23] The outer list looks like this data = [['apple', 'fruit', 1.23], ['pear', 'fruit', 2.34], ['lettuce', 'vegetable', 3.45]] I want to iterate through the outer list and cull data for a temporary list only in the case that element 1 matches some keyword (aka: 'fruit'). So, if I'm matching fruit, I would end up with this: tempList = [('apple', 1.23), ('pear', 2.34)] This is one way to accomplish this: tempList = [] for i in data: if i[1] == 'fruit': tempList.append(i[0], i[2]) is there some 'Pythonic' way to do this in fewer lines?

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• Filter across 2 lists using LINQ

  - by Ajit Goel

  I have two lists: a. requestedAmenities b. units with amenities. I want to filter those units that have any one of the "requested amenities". I have tried to achieve the same result using foreach loops but I believe it should be much easier using LINQ. Can someone please help\advice? UnitAmenities unitSearchRequestAmenities = unitSearchRequest.Amenities; var exactMatchApartmentsFilteredByAmenities= new Units(); IEnumerable<string> requestAmenitiesIds = unitSearchRequestAmenities.Select(element => element.ID); foreach (var unitCounter in ExactMatchApartments) { IEnumerable<string> unitAmenities = unitCounter.Amenities.Select(element => element.ID); foreach (var requestAmenityId in requestAmenitiesIds) { foreach (var unitAmenity in unitAmenities) { if (requestAmenityId == unitAmenity) { exactMatchApartmentsFilteredByAmenities.Add(unitCounter); //break to the outmost foreach loop } } } }

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• Find common nodes from two linked lists using recursion

  - by Dan

  I have to write a method that returns a linked list with all the nodes that are common to two linked lists using recursion, without loops. For example, first list is 2 - 5 - 7 - 10 second list is 2 - 4 - 8 - 10 the list that would be returned is 2 - 10 I am getting nowhere with this.. What I have been think of was to check each value of the first list with each value of the second list recursively but the second list would then be cut by one node everytime and I cannot compare the next value in the first list with the the second list. I hope this makes sense... Can anyone help?

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• Intersection of two lists in Bash

  - by User1

  I'm trying to write a simple script that will list the contents found in two lists. To simplify, let's use ls as an example. Imagine "one" and "two" are directories. one=`ls one` two=`ls two` intersection $one $two I'm still quite green in bash, so feel free to correct how I am doing this. I just need some command that will print out all files in "one" and "two". They must exist in both. You might call this the "intersection" between "one" and "two".

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• Subtracting two lists in Python

  - by wich

  In Python, How can one subtract two non-unique, unordered lists? Say we have a = [0,1,2,1,0] and b = [0, 1, 1] I'd like to do something like c = a - b and have c be [2, 0] or [0, 2] order doesn't matter to me. This should throw an exception if a does not contain all elements in b. Note this is different from sets! I'm not interested in finding the difference of the sets of elements in a and b, I'm interested in the difference between the actual collections of elements in a and b. I can probably work this out with a for loop, looking up the first element of b in a and then removing the element from b and from a, etc. But this doesn't appeal to me, I'd like to do this with list comprehension in a nice and easy way. Is this possible?

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• Merge two lists of objects which hold different data

  - by C.McAtackney

  I have an object "Project" which has a number of fields, one of which is "Name". I have one spreadsheet of projects which contains some of these fields, and another which contains the rest. However, Both spreadsheets have the "Name" field. I've read them in and populated two List, only populating the available fields from that particular source. E.g. a Project from List 1 looks like; {Name="MyProj", Type="Form", Priority=NULL}, whereas a Project from List 2 {Name="MyProj", Type=NULL, Priority="High"}. Now, I want to merge these two lists into one in which each Project object has all of its fields populated, with the Name field being used to match the elements. How can I achieve this? Are there any nice ways of doing this concisely? Thanks

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