Search Results

Search found 13256 results on 531 pages for 'password policy'.

Page 125/531 | < Previous Page | 121 122 123 124 125 126 127 128 129 130 131 132  | Next Page >

• How do i completely remove phpmyadmin?

  - by blade19899

  I messed up my phpmyadmin, I haven't logged in, in phpmyadmin, in a while, and as a result i forgot my password, so i purged it like so: sudo apt-get purge phpmyadmin. I did get some error messages asking for my password but i forgot that, so i just pressed ignore, after that i installed phpmyadmin again like so: sudo apt-get install phpmyadmin. This time i wont be forgetting my password. But now, when i logging my phpmyadmin I get a 404 not found error page!? Question: How do i completely remove phpmyadmin and as a result get phpmyadmin working again Note: I am running Ubuntu 12.10(AMD64)

  Read the article

• Login - check database if user exists... (c#)

  - by SAMIR BHOGAYTA

  I have managed to do the following... string connectionString = "datasource=localhost;username=xxx;password=xxx;database=xxx"; MySqlConnection mySqlConnection = new MySqlConnection(connectionString); string selectString = "SELECT username, password " + "FROM forum_members " + "WHERE username = '" + frmUsername.Text + "' AND password = '" + frmPassword.Text + "'"; MySqlCommand mySqlCommand = new MySqlCommand(selectString, mySqlConnection); mySqlConnection.Open(); String strResult = String.Empty; strResult = (String)mySqlCommand.ExecuteScalar(); mySqlConnection.Close(); if (strResult.Length == 0) { Label1.Text = "INCORRECT USER/PASS!" //could redirect to register page } else { Label1.Text = "YOU ARE LOGGED IN!"; //set loggin in sessions variables }

  Read the article

• Is it possible to get a Proxy Authentication Dialog with Ubuntu Server?

  - by Johnny Bigoode

  I've got a VM Virtual Box with Ubuntu Server. I'set the http_proxy variable using export http_proxy="http://1234:linux@proxy:8080" The problem is that Ubuntu will constantly try to connect to the internet, even when I'm not logged in my company's account, so everyday I need to reset my password since Ubuntu will constantly try to access the internet. Also, it's always a problem when I need to authenticate the proxy with a different user/password. Can't I just set it to make a small prompt when it tries to connect to the proxy and fails? Like Firefox, Chrome and every app I have installed with Windows 7? I get this small dialog box that asks for a username and password when it can't access the internet. The Ubuntu Server doesn't need constant internet connection, specially since it's only online for tests over LAN.

  Read the article

• Can't get vnc to connect

  - by Thom

  I have a server and my laptop. I want to be able to start vnc server on the server and then connect from my laptop. Both are running ubuntu 11.10 64 bit desktop On my server, i installed x11vnc. I set it up with a password, no view only password. I ssh to the box and typed vncserver :42 Now on my laptop, I installed gtkvncviewer and ran it. It popped up a box. I entered the picard:42 (the name of the server in my /etc/hosts file) and the password. I tried with and without the user. It always disconnects immediately. Can anyone point out what I'm doing wrong? Is it because I'm not running a GUI session currently on picard? If so, how can I start the Xwindows session remotely to connect with vncserver?

  Read the article

• How to disable automatic login?

  - by iammilind

  I was playing around with "User accounts" and somehow set automatic login. Now, when I start my PC, it just has one button named as "login". Clicking that button, directly logs me in to my PC. There is no music or no asking for password while logging in. As a side effect, it asks me separately for keyring password How to disable auto login and make login/keyring password unified again like before? NOTE: Attempting to disable Automatic Login from System Settings User Accounts does not work. This is the content of my /etc/lightdm/lightdm.conf (where I have commented the autologin for my username mgandhi): [SeatDefaults] greeter-session=unity-greeter user-session=ubuntu #autologin-user=mgandhi

  Read the article

• How to setup passwordless SSH access for root user

  - by Cerin

  I need to configure a machine so software installation can be automated remotely via SSH. Following the wiki, I was able to setup SSH keys so my user can access the machine without a password, but I still need to manually enter my password when I use sudo, which obviously an automated process shouldn't have to do. Although my /etc/ssh/sshd_config has PermitRootLogin yes, I can't seem to be able to login as root, presumably because it's not a "real" account with a separate password. How do I configure SSH keys, so a process can remotely login as root on Ubuntu?

  Read the article

• How do I set a system wide proxy?

  - by armando Armandiano

  I'm trying to set a system wide proxy, and I'm specifically having difficulties with apt-get for installing applications on my Ubuntu. I'm in a university using a proxy server with username/password. I'm aware of setting a proxy with username and password in the following manner: http://username:[email protected]:8080/ But it fails, as a critical example with apt-get. Username contains backslash( \ ) in it and I'm wondering whether that could be a problem for failing. I'd be grateful with any input on this. P.S I'm on Ubuntu 11.04

  Read the article

• forward sudo verification

  - by Timo Kluck

  I often use the following construct for building and installing a tarball: sudo -v && make && sudo make install which will allow me to enter my password immediately and have everything done unattended. This works well except in the rare case that building takes longer than the sudo timeout, which may happen on my rather slow machine with large projects (even when using make -j4). But when the build takes a long time, that's exactly when doing things unattended has a great advantage. Can anyone think of a shell construct that allows me to input my password immediately, and which has make executing under normal permissions and make install under elevated permissions? For security reasons, I don't want to configure my user to use sudo without password. A viable option is to set the timeout to very long, but I'm hoping for something more elegant.

  Read the article

• Copying an SSH Public Key to a Server

  - by Nathan Arthur

  I'm attempting to setup a git repository on my Dreamhost web server by following the "Setup: For the Impatient" instructions here. I'm having difficulty setting up public key access to the server. After successfully creating my public key, I ran the following command: cat ~/.ssh/[MY KEY].pub | ssh [USER]@[MACHINE] "mkdir ~/.ssh; cat >> ~/.ssh/authorized_keys" ...replacing the appropriate placeholders with the correct values. Everything seemed to go through fine. The server asked for my password, and, as far as I can tell, executed the command. There is indeed a ~/.ssh/authorized_keys file on the server. The problem: When I try to SSH into the server, it still asks for my password. My understanding is that it shouldn't be asking for my password anymore. What am I missing?

  Read the article

• How do I start Nautilus as root?

  - by Pho swan

  I got problem with nautilus in Ubuntu 12.04 LTS when i run command "gksu nautilus /" password ask box appear and I type my super-user password , than password box is disappear and nautilus is not open. . when i try to open nautilus via normal user in command box . "nautilus" the folder is open up. when i try in terminal ... $sudo nautilus I got following error $ sudo nautilus / ** (nautilus:8523): WARNING **: Command line `dbus-launch --autolaunch=2c8ce9b7da2257c2609b749700000007 --binary-syntax --close-stderr' exited with non-zero exit status 1: Autolaunch error: X11 initialization failed.\n Could not parse arguments: Cannot open display: how can i fix this error..

  Read the article

• User Already Exists in the Current Database - SQL Server

  - by bullpit

  I was moving a lot of databases from one SQL Server to another, and my applications were giving me errors saying "Login failed for <user>". The user was already in the database with appropriate rights to allowed objects in the database. I tried mapping the user to the database and that's when I got this message: "User Already Exists in the Current Database"... I googled and found this very useful post about orphaned users when moving databases. These are the steps you should take to fix this issue: First, make sure that this is the problem. This will lists the orphaned users: EXEC sp_change_users_login 'Report' If you already have a login id and password for this user, fix it by doing: EXEC sp_change_users_login 'Auto_Fix', 'user' If you want to create a new login id and password for this user, fix it by doing: EXEC sp_change_users_login 'Auto_Fix', 'user', 'login', 'password'

  Read the article

• Are two database trips reasonable for a login system?

  - by Randolph Potter

  I am designing a login system for a project, and have an issue about it requiring two trips to the database when a user logs in. User types in username and password Database is polled and password hash is retrieved for comparative purposes (first trip) Code tests hash against entered password (and salt), and if verified, resets the session ID New session ID and username are sent back to the database to write a row to the login table, and generate a login ID for that session. EDIT: I am using a random salt. Does this design make sense? Am I missing something? Is my concern about two trips unfounded? Comments and suggestions are welcome.

  Read the article

• How does Requiring users to Periodically Change their Passwords Improve Security? [closed]

  - by Bob Kaufman

  I've had the same password for some sites for years with no regrets. Meanwhile, at work, I find myself being forced to change passwords every two to three months. My thinking is that if a password gets compromised, requiring that I change it several weeks out isn't going to protect me or the network very much. Moreover, I find that by being required to change passwords frequently, I degenerate into a predictable password pattern (e.g., BearsFan111, BearsFan222, ...) which results in easier to remember and easier to guess passwords. Is there a sound argument for requiring that passwords be changed periodically?

  Read the article

• auth_mysql and php [migrated]

  - by user1052448

  I have a directory with auth_mysql in a virtualhost file password protected using a mysql user/pass combo. The problem I have is one file inside that directory needs to be accessed without a user/pass. Is there a way I can pass the user/pass within the php file? Or excluse the one file? What would I put between the code below? <Location /password-protected> ...mysql password protection require valid-user </Location>

  Read the article

• Is it possible for an application (written in Mono C#) to run a console command?

  - by Razick

  I am wondering if a Mono C# application can somehow run a terminal command. For example, could the user give the program his or her password and then have the application run sudo apt-get install application-name (console requests password) password (console requests confirmation) y Preferably, this would be done without actually opening a terminal visible to the user, so that the application could provide the necessary feedback and manage the whole operation cleanly with as little user interaction as possible. Is there a way to do that? Let me know if clarification is needed. Thank you!

  Read the article

• Xfce session will not login from login prompt. Why?

  - by hydroparadise

  Well, not sure how I did it, but for some reason I am unable to get past the login screen on Xfce. What's odd is that I had set the machine up (from install) to login automatically. Then when I finish rebooting after installing sudo apt-get install openssh-server and sudo apt-get install vnc4server all the sudden I am getting prompted for my password. I proceed to type my password (successfully might I add) to login, the screen goes black for a second, then brings me right back to the same password prompt. I am able ssh in(now), but I get no love from workstation login. Maybe vnc4server is the culprit? What did I do? And can I fix it? EDIT: The guest account, however will let me login no problem. What gives? I have a sneaking feeling that this could be permission issue.

  Read the article

• How can I have my VPN connect automatically when the wireless connects?

  - by ams

  I have a working VPN connection using NetworkManager, OpenConnect, and the network-manager-openconnect-gnome package, but I have to start it manually every time I connect to a network, and I have to enter my password manually each time. How can I get it to connect automatically, and remember my password (securely)? I have checked the 'Connect Automatically' box on the Configure VPN page, but this seems to have no effect. I've also got the 'Start connecting automatically' box checked in the pop-up box, and that does avoid the need to press the connect button in that window, but seems to have no part in kicking off the whole process in the first place. There is no option to remember the password in the window, but maybe there's one somewhere else?

  Read the article

• Encrypted Ubuntu Partition HELP!

  - by user207984

  I had Zorin 7 Encrypted. I accidentally deleted important GRUB data trying to make more room in the boot folder i think? So the computer would no longer boot up. Anyways, I installed a second Linux OS on the same laptop, but I am unable to access all of my important information that is still on the encrypted partition. When i go to mount it to access everything, it asks for the encryption password... however, it tells me the password is incorrect, which I know 100% that it is the correct password. Someone please help me! Inform me how I can access this encrypted partition or restore the data so that I can boot the computer in Zorin 7 again.

  Read the article

• I can't log-in to WinSCP using username "root"

  - by Jessyle Ivy

  I can't log-in to WinSCP using username "root". I already change the password of "root" in Ubuntu, and I successfully log-in there. But in WinSCP, it goes like this Search for host... Connecting to host... Authenticating... Using username "root" Authenticating with pre-entered password. Access Denied. and I am need to re-type the password again. By the way I'm using VMware Player for Ubuntu. Thanks!

  Read the article

• 407 Proxy Authentication Required

  - by user38507

  When I try to install a software using Ubuntu Software center I get: Failed to download repository information Check Your Internet connection When I try to do a apt get-install something, I get: 407 Proxy Authentication Required I use a proxy server that requires a user-name and a password. I have set my systems proxy manually, by plugging in the required numbers in the Networks proxy and applied it system wide. I guess the problem now is plugging in my user-name and password. When I use INTERNET via Mozilla, it specifically asks me for my user-name and password.

  Read the article

• Nashorn ?? JDBC ? Oracle DB ?????·?? 3

  - by Homma

  ???? Nashorn ?? JavaScript ??????? JDBC ? Oracle DB ???????????????????? Oracle DB ????? SQL ??????????????? ???????????????????????????????? ????????? URL ? https://blogs.oracle.com/nashorn_ja/entry/nashorn_jdbc_3 ??? JDBC ??????????????? JDBC ????????????????? Nashorn ????? JavaScript ????????????? ???????? JDBC OCI ???????????????????????????????? ????? ?? Java ??????????????? Nashorn ? JavaScript ???????????????? // Invoke jjs with -scripting option. /* * This sample can be used to check the JDBC installation. * Just run it and provide the connect information. It will select * "Hello World" from the database. */ var OracleDataSource = Java.type("oracle.jdbc.pool.OracleDataSource"); function main() { // Prompt the user for connect information print("Please enter information to test connection to the database"); var user, password, database; user = readLine("user: "); slash_index = user.indexOf('/'); if (slash_index != -1) { password = user.substring(slash_index + 1) user = user.substring(0, slash_index); } else password = readLine("password: "); database = readLine("database(a TNSNAME entry): "); java.lang.System.out.print("Connecting to the database..."); java.lang.System.out.flush(); print("Connecting..."); // Open an OracleDataSource and get a connection var ods = new OracleDataSource(); ods.setURL("jdbc:oracle:oci:@" + database); ods.setUser(user); ods.setPassword(password); var conn = ods.getConnection(); print("connected."); // Create a statement var stmt = conn.createStatement(); // Do the SQL "Hello World" thing var rset = stmt.executeQuery("select 'Hello World' from dual"); while (rset.next()) print(rset.getString(1)); // close the result set, the statement and the connection rset.close(); stmt.close(); conn.close(); print("Your JDBC installation is correct."); } main(); oracle.jdbc.pool.OracleDataSource ? Java.type() ?????Nashorn ??????????????????????????? Java ? System.out.println() ? System.out.flush() ? java.lang. ???????????????? Java ?????????? readEntry() ????? Nashorn ? readLine() ???????????? Java ????????????????????????JavaScript ?????????????????? ?? Java ??????????????????????????? Java ???????????????? JavaScript ?????????????????? ???????? JDBC OCI ???????????????? LD_LIBRARY_PATH ????????????????? ???Nashorn ? readLine() ??????????jjs ????? -scripting ????????????????? $ export LD_LIBRARY_PATH=${ORACLE_HOME}/lib $ jjs -scripting -cp ${ORACLE_HOME}/jdbc/lib/ojdbc6.jar JdbcCheckup.js Please enter information to test connection to the database user: test password: test database(a TNSNAME entry): orcl Connecting to the database...Connecting... connected. Hello World Your JDBC installation is correct. JDBC OCI ????????????????? "select 'Hello World' from dual" ??? SQL ?????????????? ?????????????????database ???? :: ??????????? ??? ??? Oracle DB ????? SQL ???????????????? Java ? JDBC ??????????????????????????? Nashorn ??????????????????????????????????

  Read the article

• Silverlight and clientaccesspolicy.xml

  - by JerA

  I have a silverlight app hosted on "dev.system-engine.com" which creates an tcp connection connecting to "dev.system-engine.com" the silverlight app and the policy file are on the "dev.system-engine.com" webserver. "system-engine.com" and "dev.system-engine.com" are separate servers. I cannot seem to get it to work. I have been struggling with the policyfile. <?xml version="1.0" encoding="utf-8" ?> <access-policy> <cross-domain-access> <policy> <allow-from> <domain uri="http://dev.system-engine.com:80"/> </allow-from> <grant-to> <domain uri="http://dev.system-engine.com:80"/> <socket-resource port="80" protocol="tcp"/> <resource path="/" include-subpaths="true"/> </grant-to> </policy>

  Read the article

• Java RMI AccessControlException: access denied

  - by Gwilym

  Hey im getting a AccessControlException: access denied when attempting to start up a RMI app im writing, I cant work out why I get this exception if I open it on the default port 1099, or on another dynamic port, my policy file currently grants everything (will change when app is finished). I am stuck as to where It is going wrong, any help would but of great use My code public class Main { /** * @param args the command line arguments */ public static void main(String[] args) throws RemoteException, AlreadyBoundException, MalformedURLException { if (System.getSecurityManager() == null) { System.setSecurityManager ( new RMISecurityManager() ); } CreditCardServer ccs = new CreditCardServer(); int port = 1099; try { port = Integer.valueOf(args[0]); } catch (Exception e) { System.out.println("Invlaid Port"); } if (((port <= 65535) && (port >= 49152)) || port ==1099) { System.out.println("Valid Port"); } else { port = 1099; System.out.println("Port not in Dynamic Range 49152<-->65535"); } System.out.println(port); LocateRegistry.createRegistry(port); LocateRegistry.getRegistry().bind("CreditCardServer", ccs); while (true) { //hum? } } } The Stack Trace vega3 [ia32.linux] 23% java -Djava.security.policy=wideopen.policy -jar "BookStore-CreditCardServer.jar 65000" Valid Port 65000 Exception in thread "main" java.security.AccessControlException: access denied (java.net.SocketPermission 127.0.0.1:1099 connect,resolve) at java.security.AccessControlContext.checkPermission(AccessControlContext.java:342) at java.security.AccessController.checkPermission(AccessController.java:553) at java.lang.SecurityManager.checkPermission(SecurityManager.java:549) at java.lang.SecurityManager.checkConnect(SecurityManager.java:1051) at java.net.Socket.connect(Socket.java:536) at java.net.Socket.connect(Socket.java:492) at java.net.Socket.<init>(Socket.java:389) at java.net.Socket.<init>(Socket.java:203) at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirectSocketFactory.java:40) at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMasterSocketFactory.java:146) at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:613) at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:216) at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:202) at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:340) at sun.rmi.registry.RegistryImpl_Stub.bind(Unknown Source) at bookstorecreditcardserver.Main.main(Main.java:56) My Policy File grant { // Allow everything for now permission java.security.AllPermission; };

  Read the article

• How do I code Citrix web sites to use a Secure Gateway (CSG)?

  - by RAVolt

  I'm using Citrix's sample code as a base and trying to get it to generate ICA files that direct the client to use their Secure Gateway (CSG) provider. My configuration is that the ICA file's server address is replaced with a CSG ticket and traffic is forced to go to the CSG. The challenge is that both the Citrix App Server (that's providing the ICA session on 1494) and the CSG have to coordinate through a Secure Ticket Authority (STA). That means that my code needs to talk to the STA as it creates the ICA file because STA holds a ticket that the CSG needs embedded into the ICA file. Confusing? Sure! But it's much more secure. The pre-CSG code looks like this: AppLaunchInfo launchInfo = (AppLaunchInfo)userContext.launchApp(appID, new AppLaunchParams(ClientType.ICA_30)); ICAFile icaFile = userContext.convertToICAFile(launchInfo, null, null); I tried to the SSLEnabled information to the ICA generation, but it was not enough. here's that code: launchInfo.setSSLEnabled(true); launchInfo.setSSLAddress(new ServiceAddress("CSG URL", 443)); Now, it looks like I need to register the STA when I configure my farm: ConnectionRoutingPolicy policy = config.getDMZRoutingPolicy(); policy.getRules().clear(); //Set the Secure Ticketing Authorities (STAs). STAGroup STAgr = new STAGroup(); STAgr.addSTAURL(@"http://CitrixAppServerURL/scripts/ctxsta.dll"); //creat Secure Gateway conenction SGConnectionRoute SGRoute = new SGConnectionRoute(@"https://CSGURL"); SGRoute.setUseSessionReliability(false); SGRoute.setGatewayPort(80); SGRoute.setTicketAuthorities(STAgr); // add the SGRoute to the policy policy.setDefault(SGRoute); This is based on code I found on the Citrix Forums; however, it breaks my ability to connect with the Farm and get my application list! Can someone point me to an example of code that works? Or a reference document?

  Read the article

• Find does not work in Expect Send command

  - by Sharjeel Sayed

  I run this bash command to display contents of somefile.cf in a Weblogic domain directory. find $(/usr/ucb/ps auwwx | grep weblogic | tr ' ' '\n' | grep security.policy | grep domain | awk -F'=' '{print $2}' | sed -e 's/weblogic.policy//' -e 's/security\///' -e 's/dep\///' | awk -F'/' '{print "/"$2"/"$3"/"$4"/somefile.cf"}' | sort | uniq) 2> /dev/null -exec ls {} \; -exec cat {} \; I tried incorporating this in an expect script and also escaped some special characters which would throw an error in expect but its still not working. send "echo ; echo 'Weblogic somefile.cf:' ; find \$(/usr/ucb/ps auwwx | grep weblogic | tr ' ' '\n' | grep security.policy | grep domain | awk -F'=' '{print \$2}' | sed -e 's/weblogic.policy//' -e 's/security\\///' -e 's/dep\\///' | awk -F'/' '{print "/"\$2"/"\$3"/"\$4"/somefile.cf"}' | sort | uniq) 2> /dev/null -exec ls {} \\; -exec cat {} \\; ; echo\r" I guess it needs some more escaping of special characters or probably I dint escape the existing ones correctly. Any help would be appreciated.

  Read the article

< Previous Page | 121 122 123 124 125 126 127 128 129 130 131 132  | Next Page >