Search Results

Search found 91862 results on 3675 pages for 'new account'.

Page 127/3675 | < Previous Page | 123 124 125 126 127 128 129 130 131 132 133 134  | Next Page >

  • Does Java have a .new operator?

    - by chickeninabiscuit
    I came across this code today whilst reading Accelerated GWT (Gupta) - page 151. public static void getListOfBooks(String category, BookStore bookStore) { serviceInstance.getBooks(category, bookStore.new BookListUpdaterCallback()); } public static void storeOrder(List books, String userName, BookStore bookStore) { serviceInstance.storeOrder(books, userName, bookStore.new StoreOrderCallback()); } What are those new operators doing there? I've never seen such syntax, can anyone explain?

    Read the article

  • Create new or update existing entity at one go with JPA

    - by Alex R
    A have a JPA entity that has timestamp field and is distinguished by a complex identifier field. What I need is to update timestamp in an entity that has already been stored, otherwise create and store new entity with the current timestamp. As it turns out the task is not as simple as it seems from the first sight. The problem is that in concurrent environment I get nasty "Unique index or primary key violation" exception. Here's my code: // Load existing entity, if any. Entity e = entityManager.find(Entity.class, id); if (e == null) { // Could not find entity with the specified id in the database, so create new one. e = entityManager.merge(new Entity(id)); } // Set current time... e.setTimestamp(new Date()); // ...and finally save entity. entityManager.flush(); Please note that in this example entity identifier is not generated on insert, it is known in advance. When two or more of threads run this block of code in parallel, they may simultaneously get null from entityManager.find(Entity.class, id) method call, so they will attempt to save two or more entities at the same time, with the same identifier resulting in error. I think that there are few solutions to the problem. Sure I could synchronize this code block with a global lock to prevent concurrent access to the database, but would it be the most efficient way? Some databases support very handy MERGE statement that updates existing or creates new row if none exists. But I doubt that OpenJPA (JPA implementation of my choice) supports it. Event if JPA does not support SQL MERGE, I can always fall back to plain old JDBC and do whatever I want with the database. But I don't want to leave comfortable API and mess with hairy JDBC+SQL combination. There is a magic trick to fix it using standard JPA API only, but I don't know it yet. Please help.

    Read the article

  • Is there a way to use template specialization to separate new from new[]?

    - by Marlon
    I have an auto pointer class and in the constructor I am passing in a pointer. I want to be able to separate new from new[] in the constructor so that I can properly call delete or delete[] in the destructor. Can this be done through template specialization? I don't want to have to pass in a boolean in the constructor. template <typename T> class MyAutoPtr { public: MyAutoPtr(T* aPtr); }; // in use: MyAutoPtr<int> ptr(new int); MyAutoPtr<int> ptr2(new int[10]);

    Read the article

  • XAML get new width and height for Canvas

    - by Jack Navarro
    I have searched through many times but have not seen this before. Probably really simple question but can't wrap my head around it. Wrote a VSTO add-in for Excel that draws a Grid dynamically. Then launches a new window and replaces the contents of the Canvas with the generated Grid. The problem is with printing. When I call the print procedure the canvas.height and canvas.width returned is the old value prior to replacing it with the grid. Sample: string="<Grid Name=\"CanvasGrid\" xmlns=\"http://schemas.microsoft.com/winfx/2006/xaml/presentation\">..Lots of stuff..</Grid>"; // Launch new window and replace the Canvas element WpfUserControl newWindow = new WpfUserControl(); newWindow.Show(); //To test MessageBox.Show(myCanvas.ActualWidth.ToString()); //return 894 Grid testGrid = myCanvas.FindName("CanvasGrid") as Grid; MessageBox.Show("Grid " + testGrid.ActualWidth.ToString()); //return 234 StringReader stringReader = new StringReader(LssAllcChrt); XmlReader xmlReader = XmlReader.Create(stringReader); Canvas myCanvas = newWindow.FindName("GrphCnvs") as Canvas; myCanvas.Children.Clear(); myCanvas.Children.Add((UIElement)XamlReader.Load(xmlReader)); //To test MessageBox.Show(myCanvas.ActualWidth.ToString()); //return 894 but should be much larger the Grid spans all three of my screens Grid testGrid = myCanvas.FindName("CanvasGrid") as Grid; MessageBox.Show("Grid " + testGrid.ActualWidth.ToString()); //return 234 but should be much larger the Grid spans all three of my screens //Run code from WpfUserControl.cs after it loads from button click Grid testGrid = canvas.FindName("CanvasGrid") as Grid; MessageBox.Show("Grid " + testGrid.ActualWidth.ToString()); //return 234 but should be much larger the Grid spans all three of my screens So basically I have no way of telling what my new width and height are.

    Read the article

  • New interesting languages

    - by wvd
    Hello all, I've been programming for 4 years now and I feel it's time for a new language. I've been doing Python, Java and some C++/Erlang/Haskell along those 4 years but I'm looking for a new language. I'm mainly looking for one which I could use later when I'm getting hired, but it also needs to be relatively new. Any ideas? Thanks, William van Doorn

    Read the article

  • How to add a new custom resource to routes Rails 3

    - by Jeroen janssen
    How do I add a custom route for a new resource in the Rails 3 routes? I know how to do it for collections and members but this style doesn't seem to be working for new resources. Is this a bug or am I doing something wrong? So these work: collection do get :wish end member do get :wish end But this doesn't work: new do get :wish end

    Read the article

  • Error creating new user by Admin

    - by rahul
    I am creating a web application using Form Authentication of Asp.Net with C# and back end Sql Server. Here in my application administrator login and creates new users. I am using the create user wizard under login controls. My problem is when the new user is created by Admin he is automatically logged out and logged in with new user credentials which he has just created. Any help would be highly appreciated.

    Read the article

  • create a new model instance version instead of update

    - by pablo
    Hi, I have a model with a version field - autocreate timestamp. When a model instance is being saved I want to create a new instance with a new timestamp instead of updating the old model instance. Is it possible? I thought of overriding the model save() method but I don't know how to create a new instance without creating a infinite save() loop. Thanks

    Read the article

  • manyToOne is creating new products

    - by user788721
    I am trying to implement Sylius Cart Bundle, but every time I add a product to the cart, a new product is created. This is probably link to my line: cascade: ["persist", "remove"] In my YAML File: Pharmacie\FrontBundle\Entity\CartItem: type: entity table: app_cart_item manyToOne: produit: targetEntity: Pharmacie\FrontBundle\Entity\Product cascade: ["persist", "remove"] joinColumn: name: product_id referencedColumnName: id But if take it off, I get an error: A new entity was found through the relationship 'Pharmacie\FrontBundle\Entity\CartItem#produit' that was not configured to cascade persist operations for entity: 3test2. To solve this issue: Either explicitly call EntityManager#persist() on this unknown entity or configure cascade persist this association in the mapping for example @ManyToOne(..,cascade={"persist"}) According to the doctrine doc, this error occurs when you set a new object. But I am only getting an existing object By ID: $product = $this->getProductRepository()->find($productId); $item->setProduit($product); //this generates the error $item->setUnitPrice(5); //this works fine I don't understand why it's save as a new object. If I use merge instead of persist, I get the same error: A new entity was found through the relationship...

    Read the article

  • how to tackle a new project

    - by stevo
    Hi, I have a question about best practice on how to tackle a new project, any project. When starting a new project how do you go about tackling the project, do you split it into sections, start writing code, draw up flow diagrams. I'm asking this question because I'm looking for advice on how I can start new projects so I can get going on them quicker. I can have it planned, designed and starting coding with everything worked out. Any advice? Thanks Stephen

    Read the article

  • Use cases of [ordered], the new PowerShell 3.0 feature

    - by Roman Kuzmin
    PowerShell 3.0 CTP1 introduces a new feature [ordered] which is somewhat a shortcut for OrderedDictionary. I cannot imagine practical use cases of it. Why is this feature really useful? Can somebody provide some useful examples? Example: this is, IMHO, rather demo case than practical: $a = [ordered]@{a=1;b=2;d=3;c=4} (I do not mind if it is still useful, then I am just looking for other useful cases). I am not looking for use cases of OrderedDictionary, it is useful, indeed. But we can use it directly in v2.0 (and I do a lot). I am trying to understand why is this new feature [ordered] needed in addition. Collected use cases from answers: $hash = [ordered]@{} is shorter than $hash = New-Object System.Collections.Specialized.OrderedDictionary N.B. ordered is not a real shortcut for the type. New-Object ordered does not work. N.B. 2: But this is still a good shortcut because (I think, cannot try) it creates typical for PowerShell case insensitive dictionary. The equivalent command in v2.0 is too long, indeed: New-Object System.Collections.Specialized.OrderedDictionary]([System.StringComparer]::OrdinalIgnoreCase)

    Read the article

  • c# list<int> how to insert a new value in between two values

    - by gdubs
    so i have a list where i need to add new values constantly but when i do i need to increment it and insert it in between two values. List<int> initializers = new List <int>(); initializers.Add(1); initializers.Add(3); so initializers would have 1, 3 values. i would then process a new set of numbers. the initializers will need to have the values. 1, 5, 3, 7 and if i process another set of numbers it should become 1, 9, 5, 13, 3, 11, 7, 15 i know how to properly generate the new values inserted, i just need some help on inserting it in between the existing values of the initializers without having to add 2 or 3 more loops to move the values' positions.

    Read the article

  • New cryptographic algorithms ?

    - by redbull
    I was wondering about new trends in cryptography. Which algorithms are new ? Which are improved and which died beacuse of the time that past ? For example EEC ( Elliptic Curve Cryptography ) is quite new approach, but definitly not the only one. Could you name some of them ?

    Read the article

  • Unwanted automated creation of new instances of an activity class

    - by Marko
    I have an activity (called Sender) with the most basic UI, only a button that sends a message when clicked. In the onClickListener I only call this method: private void sendSMS(String msg) { PendingIntent pi = PendingIntent.getActivity(this, 0, new Intent(this, Sender.class), 0); PendingIntent pi = PendingIntent.getActivity(this, 0, myIntent, 0); SmsManager sms = SmsManager.getDefault(); sms.sendTextMessage("1477", null, msg, pi, null); } This works ok, the message is sent but every time a message is sent a new instance of Sender is started on top of the other. If I call sendSMS method three times, three new instances are started. I'm quite new to android so I need some help with this, I only want the same Sender to be on all the time

    Read the article

  • How to make this open a webbrowser inside a new form

    - by user335932
    private void button5_Click(object sender, EventArgs e) { if (domainUpDown2.Text == "Battlefield: Bad Company 2") { Form2 form2 = new Form2(); form2.ShowDialog(); } } All that does is open a new blank form, but i need it to open a new form with a webbrowser in it so i can set it url dependent on the if statement..

    Read the article

  • In C# VS2008 how to replace new SqlParameter("@values", SqlDbType.SomeType, 1500)) to ("@values", Sq

    - by CodeYun
    In C# VS2008 how to replace new SqlParameter("@Description", SqlDbType.NChar, 1500) or new SqlParameter("@IsRequired", SqlDbType.Bit) to "@Description", SqlDbType.NChar, 1500 or "@IsRequired", SqlDbType.B the idea is to remove new SqlParameter() and leave the parameters inside it. I have thounds of lines code have this pattern. I just want to pass compile by using some regular expression.

    Read the article

  • Rails RESTful routs without #new, rspec trouble

    - by pdkl95
    I'm currently writing a Rails app, and hit a somewhat strange quirk. I have a controller PermissionsController, which is mainly for display purposes at the moment. So my routing is locked down: map.resources :permissions, :only => [:index, :show] Unfortunately, when writing the tests, one of the routing tests fails: it "does not recognize #new" do { :get => "/permissions/new" }.should_not be_routable end with the error: Expected 'GET /permissions/new' to fail, but it routed to {"action"=>"show", "id"=>"new", "controller"=>"permissions"} instead Obviously, the #show action's route is matching with /permissions/:id, which also gives the expected error Couldn't find Permission with ID=new if you actually browse to that URL. This is not a serious error, as it is correctly raising an exception with the bad :id parameter, but it's kind of ugly. Is there any way to actually make Rails reject that route? Some trick in the routing options that I'm missing? I suppose I should just leave that test out and ignore it, or maybe remove the whole RESTful idea altogether and go back to a simpler map.connect 'permissions/:id' style. I strongly suspect I'll be expanding this in the future, though, and kind of wanted to keep my controllers consistent with each other. Just having to add occasional :only or :except rules made routes.rb nice and clean...

    Read the article

< Previous Page | 123 124 125 126 127 128 129 130 131 132 133 134  | Next Page >