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  • How to download all file content from a folder using wget and http

    - by user1526912
    I am trying to use wget and http to download all contents from folderAA below to directory /root/sstest wget -r --directory-prefix="/root/sstest" -o /root/sstest2.log http://site.com/folder1/folder2/folderAA/ When I submit the above command nothing is downloaded. If I submit a wget request for a specific file from folderAA the file is actually downloaded to /root/sstest: wget -r --directory-prefix="/root/sstest" -o /root/sstest2.log http://site.com/folder1/folder2/folderAA/file.txt Can someone tell me why I cannot download all file content from folderAA at once using the first wget request?

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  • input file cannot be found

    - by Eric Smith
    I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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  • help merging perl code routines together for file processing

    - by jdamae
    I need some perl help in putting these (2) processes/code to work together. I was able to get them working individually to test, but I need help bringing them together especially with using the loop constructs. I'm not sure if I should go with foreach..anyways the code is below. Also, any best practices would be great too as I'm learning this language. Thanks for your help. Here's the process flow I am looking for: -read a directory -look for a particular file -use the file name to strip out some key information to create a newly processed file -process the input file -create the newly processed file for each input file read (if i read in 10, I create 10 new files) Sample Recs: col1,col2,col3,col4,col5 [email protected],[email protected],8,2009-09-24 21:00:46,1 [email protected],[email protected],16,2007-08-18 22:53:12,33 [email protected],[email protected],16,2007-08-18 23:41:23,33 Here's my test code: Target Filetype: `/backups/test/foo101.name.aue-foo_p002.20110124.csv` Part 1: my $target_dir = "/backups/test/"; opendir my $dh, $target_dir or die "can't opendir $target_dir: $!"; while (defined(my $file = readdir($dh))) { next if ($file =~ /^\.+$/); #Get filename attributes if ($file =~ /^foo(\d{3})\.name\.(\w{3})-foo_p(\d{1,4})\.\d+.csv$/) { print "$1\n"; print "$2\n"; print "$3\n"; } print "$file\n"; } Part 2: use strict; use Digest::MD5 qw(md5_hex); #Create new file open (NEWFILE, ">/backups/processed/foo$1.name.$2-foo_p$3.out") || die "cannot create file"; my $data = ''; my $line1 = <>; chomp $line1; my @heading = split /,/, $line1; my ($sep1, $sep2, $eorec) = ( "^A", "^E", "^D"); while (<>) { my $digest = md5_hex($data); chomp; my (@values) = split /,/; my $extra = "__mykey__$sep1$digest$sep2" ; $extra .= "$heading[$_]$sep1$values[$_]$sep2" for (0..scalar(@values)); $data .= "$extra$eorec"; print NEWFILE "$data"; } #print $data; close (NEWFILE);

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  • URI scheme is not "file"

    - by Ankur
    I get the exception: "URI scheme is not file" The url I am playing with is ... and it very much is a file http://local.wasp.uwa.edu.au/~pbourke/miscellaneous/domefisheye/ladybug/fish4.jpg What I am doing is trying to get the name of a file and then save that file (from another server) onto my computer/server from within a servlet. I have a String called "url", from thereon here is my code: url = Streams.asString(stream); //gets the URL from a form on a webpage System.out.println("This is the URL: "+url); URI fileUri = new URI(url); File fileFromUri = new File(fileUri); onlyFile = fileFromUri.getName(); URL fileUrl = new URL(url); InputStream imageStream = fileUrl.openStream(); String fileLoc2 = getServletContext().getRealPath("pics/"+onlyFile); File newFolder = new File(getServletContext().getRealPath("pics")); if(!newFolder.exists()){ newFolder.mkdir(); } IOUtils.copy(imageStream, new FileOutputStream("pics/"+onlyFile)); } The line causing the error is this one: File fileFromUri = new File(fileUri); I have added the rest of the code so you can see what I am trying to do.

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  • Reading a file with a supplied name in C++

    - by Cosmina
    I must read a file with a given name (it's caled "hamlet.txt"). The class used to read the file is defined like this #ifndef READWORDS_H #define READWORDS_H /** * ReadWords class. Provides mechanisms to read a text file, and return * capitalized words from that file. */ using namespace std; #include <string> #include <fstream> class ReadWords { public: /** * Constructor. Opens the file with the default name "text.txt". * Program exits with an error message if the file does not exist. */ ReadWords(); /** * Constructor. Opens the file with the given filename. * Program exits with an error message if the file does not exist. * @param filename - a C string naming the file to read. */ ReadWords(char *filename); My definition of the members of the classis this: #include<string> #include<fstream> #include<iostream> #include "ReadWords.h" using namespace std; ReadWords::ReadWords() { wordfile.open("text.txt"); if( !wordfile ) { cout<<"Errors while opening the file!"<<endl; } } ReadWords::ReadWords(char *filename) { wordfile.open(filename); if ( !wordfile ) { cout<<"Errors while opening the file!"<<endl; } wordfile>>nextword; } And the main to test it. using namespace std; #include #include #include "ReadWords.h" int main() { char name[30]; cout<<"Please input a name for the file that you wish to open"; cin>>name; ReadWords x( name[] ); } When I complie it gives me the error: main.cpp:14: error: expected primary-expression before ']' token I know it's got something to do with the function ReadWords( char *filename), but I do not know what. Any help please?

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  • UI not updated while using ProgressMonitorInputStream in Swing to monitor compressed file decompress

    - by Bozhidar Batsov
    I'm working on swing application that relies on an embedded H2 database. Because I don't want to bundle the database with the app(the db is frequently updated and I want new users of the app to start with a recent copy), I've implemented a solution which downloads a compressed copy of the db the first time the application is started and extracts it. Since the extraction process might be slow I've added a ProgressMonitorInputStream to show to progress of the extraction process - unfortunately when the extraction starts, the progress dialog shows up but it's not updated at all. It seems like to events are getting through to the event dispatch thread. Here is the method: public static String extractDbFromArchive(String pathToArchive) { if (SwingUtilities.isEventDispatchThread()) { System.out.println("Invoking on event dispatch thread"); } // Get the current path, where the database will be extracted String currentPath = System.getProperty("user.home") + File.separator + ".spellbook" + File.separator; LOGGER.info("Current path: " + currentPath); try { //Open the archive FileInputStream archiveFileStream = new FileInputStream(pathToArchive); // Read two bytes from the stream before it used by CBZip2InputStream for (int i = 0; i < 2; i++) { archiveFileStream.read(); } // Open the gzip file and open the output file CBZip2InputStream bz2 = new CBZip2InputStream(new ProgressMonitorInputStream( null, "Decompressing " + pathToArchive, archiveFileStream)); FileOutputStream out = new FileOutputStream(ARCHIVED_DB_NAME); LOGGER.info("Decompressing the tar file..."); // Transfer bytes from the compressed file to the output file byte[] buffer = new byte[1024]; int len; while ((len = bz2.read(buffer)) > 0) { out.write(buffer, 0, len); } // Close the file and stream bz2.close(); out.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException ex) { ex.printStackTrace(); } try { TarInputStream tarInputStream = null; TarEntry tarEntry; tarInputStream = new TarInputStream(new ProgressMonitorInputStream( null, "Extracting " + ARCHIVED_DB_NAME, new FileInputStream(ARCHIVED_DB_NAME))); tarEntry = tarInputStream.getNextEntry(); byte[] buf1 = new byte[1024]; LOGGER.info("Extracting tar file"); while (tarEntry != null) { //For each entry to be extracted String entryName = currentPath + tarEntry.getName(); entryName = entryName.replace('/', File.separatorChar); entryName = entryName.replace('\\', File.separatorChar); LOGGER.info("Extracting entry: " + entryName); FileOutputStream fileOutputStream; File newFile = new File(entryName); if (tarEntry.isDirectory()) { if (!newFile.mkdirs()) { break; } tarEntry = tarInputStream.getNextEntry(); continue; } fileOutputStream = new FileOutputStream(entryName); int n; while ((n = tarInputStream.read(buf1, 0, 1024)) > -1) { fileOutputStream.write(buf1, 0, n); } fileOutputStream.close(); tarEntry = tarInputStream.getNextEntry(); } tarInputStream.close(); } catch (Exception e) { } currentPath += "db" + File.separator + DB_FILE_NAME; if (!currentPath.isEmpty()) { LOGGER.info("DB placed in : " + currentPath); } return currentPath; } This method gets invoked on the event dispatch thread (SwingUtilities.isEventDispatchThread() returns true) so the UI components should be updated. I haven't implemented this as an SwingWorker since I need to wait for the extraction anyways before I can proceed with the initialization of the program. This method get invoked before the main JFrame of the application is visible. I don't won't a solution based on SwingWorker + property changed listeners - I think that the ProgressMonitorInputStream is exactly what I need, but I guess I'm not doing something right. I'm using Sun JDK 1.6.18. Any help would be greatly appreciated.

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  • Print the file name with another extension (Batch-program)

    - by Semyon Perepelitsa
    Batch-program launchs with 1 parameter (full path to file) program.cmd "C:\Path\To\File\Filename.txt" Now, this program consists of 1 command: echo %1 And it just prints an argument: C:\Path\To\File\Filename.txt for the upper example. But I want it to print an argument (full path) with another extension, e.g. .exe. For the upper example, I want it to print C:\Path\To\File\Filename.exe. How to make it do that?

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  • how to compare the checksums in a list corresponding to a file path with the file path in the operat

    - by surab
    Hi all, how to compare the checksums in a list corresponding to a file path with the file path in the operating system In Python? import os,sys,libxml2 files=[] sha1s=[] doc = libxml2.parseFile('files.xml') for path in doc.xpathEval('//File/Path'): files.append(path.content) for sha1 in doc.xpathEval('//File/Hash'): sha1s.append(sha1.content) for entry in zip(files,sha1s): print entry the files.xml contains <Files> <File> <Path>usr/share/doc/dialog/samples/form1</Path> <Type>doc</Type> <Size>1222</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>49744d73e8667d0e353923c0241891d46ebb9032</Hash> </File> <File> <Path>usr/share/doc/dialog/samples/form3</Path> <Type>doc</Type> <Size>1294</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>f30277f73e468232c59a526baf3a5ce49519b959</Hash> </File> </Files> I need to compare the sha1 checksum in between tags corresponding to the file specified in between the tags, with the same file path in base Operating system.

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  • Java: constructing a file from a URI?

    - by AP257
    I need to obtain a File object from a URI, working in Java, but keep getting a length of zero - though I know the file size is not zero. I need the File object to pass to another constructor. I'm not sure if it's because I'm constructing it in the wrong way? Here's my code: File videoFile = new File(videoURI.getPath()); if (videoFile == null) { Log.d(LOG_TAG, "File not found!"); return false; } Log.d(LOG_TAG, "about to upload, filepath: " + videoFile.getPath()); Log.d(LOG_TAG, "File length: " + String.valueOf(videoFile.length())); The log output doesn't spit out 'File not found!', and prints a non-null path, but shows a length of 0.

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  • Is it possible for a directory to get unlinked while its contained files remain?

    - by Walkerneo
    I used to wonder why deleting directories via PHP or shell wasn't as easy as it was in Windows with just clicking delete. I realize now that deleting is simply unlinking files from the file allocation table, so to delete a directory, you must unlink all the files inside it. Is it ever possible for the directory's entry to be removed, but not those of the files inside it? Do operating systems periodically check for files that can't be reached in the file system?

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  • Create kickstart configuration file from existing configuration.

    - by ÜMineiro
    Is there a script or another way to automatically generate a kickstart configuration file from the system state of an existing server so that the file can be use to replicate (not clone) the configuration of the system in another install? I know that the anaconda-ks.cfg file is stored on the /root dir. but the system in question have been extensively changed since it's installation, and the file is of no use now.

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  • Descending list ordered by file modification time

    - by user62367
    How can i generate a list of files in a directory [e.g.: "/mnt/hdd/PUB/"] ordered by the files modification time? [in descending order, the oldest modified file is at the lists end] ls -A -lRt would be great: https://pastebin.com/raw.php?i=AzuSVmrJ but if a file is changed in a directory it lists the full directory...so the pastebined link isn't good [i don't want a list ordered by "directories", i need a "per file" ordered list] os: openwrt..[no perl - not enough space for it :( + no "stat", or "file" command] Thank you!

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  • Descending list ordered by file modification time

    - by LanceBaynes
    How can I generate a list of files in a directory [for example, "/mnt/hdd/PUB/"] ordered by the files modification time? [in descending order, the oldest modified file is at the lists end] ls -A -lRt would be great: https://pastebin.com/raw.php?i=AzuSVmrJ But if a file is changed in a directory, it lists the full directory, so the pastebined link isn't good [I don't want a list ordered by "directories", I need a "per file" ordered list] OS: OpenWrt [no Perl - not enough space for it :( + no "stat", or "file" command].

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  • loading data from a flat file to table using informatica, having both english and foreign language c

    - by Manish
    I am loading data from a flat file to table using informatica, the file has both english and foreign language characters like chinese, and others. The foreign language characters are not getting displayed properly after loading. How can this problem be solved ? I could solve it by using code page UTF - 16 Encoding of Unicode Platform Endian, earlier i was using different code page UTF-8.

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  • PowerShell: Read text, regex sort, write output to file and formatting

    - by Bill Hunter
    I am a Powershell novice and have run into a challenge in reading, sorting, and outputting a csv file. The input csv has no headers, the data is as follows: 05/25/2010,18:48:33,Stop,a1usak,10.128.212.212 05/25/2010,18:48:36,Start,q2uhal,10.136.198.231 05/25/2010,18:48:09,Stop,s0upxb,10.136.198.231 I use the following piping construct to read the file, sort and output to a file: (Get-Content d:\vpnData\u62gvpn2.csv) | %{,[regex]::Split($, ",")} | sort @{Expression={$[3]}},@{Expression={$_[1]}} | out-file d:\vpnData\u62gvpn3.csv The new file is written with the following format: 05/25/2010 07:41:57 Stop a0uaar 10.128.196.160 05/25/2010 12:24:24 Start a0uaar 10.136.199.51 05/25/2010 20:00:56 Stop a0uaar 10.136.199.51 What I would like to see in the output file is a similar format to the original input file with comma dilimiters: 05/25/2010,07:41:57,Stop,a0uaar,10.128.196.160 05/25/2010,12:24:24,Start,a0uaar,10.136.199.51 05/25/2010,20:00:56,Stop,a0uaar,10.136.199.51 But I can't quite seem to get there. I'm almost of the mind that I'll have to write another segment to read the newly produced file and reset its contents to the preferred format for further processing. Thoughts?

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  • Removing files with strange names

    - by pythonic metaphor
    Somehow I ended up with a file named "-r". How do I remove it? rm -r doesn't work. I tried 'rm -i `ls -a`' to step through the file names, but it didn't prompt me to delete this one. Edit A very hacky approach was to use python's os.unlink function. That worked, but I'm curious to hear other ways.

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  • How do I remove the Never-Ending Dropbox Folder?

    - by KronoS
    I don't know if this is an error with eclipse or dropbox, but I seem to be unable to delete a file folder within my dropbox folder. Somehow, there was a creation of over 8300 file folders, all duplicates of the previous folder. I tried deleting from both command line, and explorer but get the same error: I've also deleted the share from the dropbox website, and it deleted correctly from there, but during the sync from the client (my pc) to the site there is an error: Any ideas of what to do?

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  • .bat script doesn't work by using window scheduler

    - by user332640
    i created a .bat script to perform daily folder compression. it is working fine when i double click the .bat file. However, it doesnt work when i include it in window scheduler. Below is the script: rem **************************** rem ** To create back up file ** rem **************************** "C:\Program Files\WinZip\WINZIP32.EXE" -a -r -p "E:\Backup\Daily\sst.zip" "P:\SST\*.*" When i run it via window scheduler, the status is always "running" but nothing is generated. Can someone explain the situation?

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  • Connection to VPN using command line

    - by plurby
    I've wrote a simple batch file to connect to a specific VPN connection using RASDIAL rasdial MyVPNConnection but it always returned the error 691 Access denied because username and/or password is invalid on the domain. Remote Access Service (RAS) Error Code List then i tried pointing to my Remote Access Phonebook (Rasphone.pbk) and see what happens rasdial MyVPNConnection /phonebook:%userprofile%\AppData\Roaming\Microsoft\Network\Connections\Pbk\rasphone.pbk and still there was an error 691. I've then unchecked the following but still the same problem was reported when executing my batch file.

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  • Executing batch file from sql server job

    - by uzay95
    I want to create backup job on sql server. And i want to execute batch file in job. I just wonder the part of executing batch file from sql job. Do you have any idea? Any help would appreciated. use MyDb go BACKUP DATABASE MyDb TO DISK = 'C:\BackUps\MyDb.bak' WITH differential go -- Call my batch file (which will zip MyDb.bak file)

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  • Executing batch file from sql server job

    - by uzay95
    I want to create backup job on sql server. And i want to execute batch file in job. I just wonder the part of executing batch file from sql job. Do you have any idea? Any help would appreciated. use MyDb go BACKUP DATABASE MyDb TO DISK = 'C:\BackUps\MyDb.bak' WITH differential go -- Call my batch file (which will zip MyDb.bak file)

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  • Create all directories up to a point?

    - by Stefan Kendall
    I need to be able to build all directories up to and including the directory specified by my File object. For example, suppose I have something like this: File file = new File( "/var/a/b/c/d/" ); But only /var/ exists. I need a method that builds up to d, and I was wondering if there was a method in a java io library somewhere that does this already.

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  • Getting the names of all files in a directory with PHP

    - by Greelmo
    For some reason, I keep getting a '1' for the file names with this code: if (is_dir($log_directory)) { if ($handle = opendir($log_directory)) { while($file = readdir($handle) !== FALSE) { $results_array[] = $file; } closedir($handle); } } When I echo each element in $results_array, I get a bunch of '1's, not the name of the file. How do I get the name of the files?

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