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  • Rails CSS not Loading using Heroku

    - by eWizardII
    I have the following site set up here on Heroku - http://www.peerinstruction.net/users/sign_up the issue is that I have updated the css yet it is not being actively reflected on the site, it just shows a textbox, with some edited/custom fonts. I have attached the css file in the following gist - https://gist.github.com/f74b626c54ecbb60bbde The signup page controller: !!! Strict %html %head %title= yield(:title) || "Untitled" = stylesheet_link_tag 'application', 'web-app-theme/base', 'web-app-theme/themes/activo/style', 'web-app-theme/override' = javascript_include_tag :defaults = csrf_meta_tag = yield(:head) %body #container #header %h1 %a{:href => "/"} Peer Instruction Network #user-navigation %ul.wat-cf %li .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => session_path(resource_name), :html => { :class => "form login" }) do |f| .group.wat-cf .left= f.label :email, :class => "label right" .right= f.text_field :email, :class => "text_field" .group.wat-cf .left= f.label :password, :class => "label right" .right= f.password_field :password, :class => "text_field" .group.wat-cf .right %button.button{ :type => "submit" } Login /= link_to "Sign In", destroy_user_session_path #box = yield The signup pages haml file: %h2 .block .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| = devise_error_messages! %div = f.label :firstname %br/ = f.text_field :firstname %div = f.label :middlename %br/ = f.text_field :middlename %div = f.label :lastname %br/ = f.text_field :lastname %div = f.label :email %br/ = f.email_field :email %div = f.label :password %br/ = f.password_field :password %div = f.label :academic %br/ = f.text_field :academic %div= f.submit "Continue" = render :partial => "devise/shared/links" I used web-app-theme to create an activo theme and then modify it.

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  • Sending basic authentication information via form

    - by VolatileStorm
    I am working on a site that currently uses a basic authentication dialog box login system, that is the type of dialog that you get if you go here: http://www.dur.ac.uk/vm.boatclub/password/index.php I did not set this system up and am not in a position to easily/quickly work around it, but it DOES work. The issue however is that the dialog box is not very helpful in telling you what login information you have to use (that is which username and password combination), and so I would like to replace it with a form. I had been thinking that this wasn't possible but I wanted to ask in order to find out. Is it possible to set up an HTML form that sends the data to the server such that it accepts it in the same way that it would using this dialog box? Alternatively is it possible to set up a PHP script that would take normal form data and process it somehow passing it to the server such that it logs in? Edit: After being told that this is basic authentication I went around and have managed to find a way that works and keeps the user persistently logged in. However, this does not work in internet explorer. The solution was simply to redirect the user to: http://username:[email protected]/vm.boatclub/password/index.php But Internet Explorer removed it due to phishing uses about 3 years ago. Is there a way to use javascript to get the browser to access the site in this way? Or will I have to simply change my UI?

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  • ASP.NET MVC: How do I validate a model wrapped in a ViewModel?

    - by Deniz Dogan
    For the login page of my website I would like to list the latest news for my site and also display a few fields to let the user log in. So I figured I should make a login view model - I call this LoginVM. LoginVM contains a Login model for the login fields and a List<NewsItem> for the news listing. This is the Login model: public class Login { [Required(ErrorMessage="Enter a username.")] [DisplayName("Username")] public string Username { get; set; } [Required(ErrorMessage="Enter a password.")] [DataType(DataType.Password)] [DisplayName("Password")] public string Password { get; set; } } This is the LoginVM view model: public class LoginVM { public Login login { get; set; } public List<NewsItem> newsItems { get; set; } } This is where I get stuck. In my login controller, I get passed a LoginVM. [HttpPost] public ActionResult Login(LoginVM model, FormCollection form) { if (ModelState.IsValid) { // What? In the code I'm checking whether ModelState is valid and this would work fine if the view model was actually the Login model, but now it's LoginVM which has no validation attributes at all. How do I make LoginVM "traverse" through its members to validate them all? Am I doing something fundamentally wrong using ModelState in this manner?

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  • Problems setting up AuthLogic

    - by sscirrus
    Hi all, I'm trying to set up a simple login using AuthLogic into my User table. Every time I try, the login fails and I don't know why. I'm sure this is a simple error but I've been hitting a brick wall with it for a while. #user_sessions_controller def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" else flash[:notice] = "We couldn't log you in. Please try again!" redirect_to :controller => "index", :action => "index" end end #_user_login.html.erb (this is the partial from my index page where Users log in) <% form_tag user_session_path do %> <p><label for="login">Login:</label> <%= text_field_tag "login", nil, :class => "inputBox", :id => "login", </p> <p><label for="password">Password: </label> <%= password_field_tag "password", nil, :class => "inputBox", :id => "password", </p> <p><%= submit_tag "submit", :class => "submit" %></p> <% end %> I had Faker generate some data for my user table but I cannot log in! Every time I try it just redirects to index. Where am I going wrong? Thanks everybody.

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  • automating hudson builds with ant throwing 403

    - by Christopher Dancy
    We have a hudson server which deploys builds. We have a few services which we want to be able to remotely tell hudson to deploy a certain build ... these services are using ant. So I'm trying to get it working but keeping getting a 403 response when giving a build number like so... <ac:post to="http://hostname:8080/hudson/job/test_release_indexes/build?" verbose="true" wantresponse="true"> <prop name="token" value="indexes"/> <prop name="BUILDNUMBER" value="0354"/> </ac:post> this throws the 403. I've also tried passing it props for the username and password like so ... <ac:post to="http://srulesre2:8080/hudson/job/test_dartmouth_indexes/build?" verbose="true" wantresponse="true"> <prop name="token" value="indexes"/> <prop name="BUILDNUMBER" value="0354"/> <prop name="username" value="test"/> <prop name="password" value="test"/> </ac:post> I've tried a hundred different variations on username and password ... like j_username and j_password or user and pass ... but nothing is working ... keep getting the same 403. And the username and password are valid because I can manually log in with admin privileges. Any ideas would be great

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  • How to add custom header to ASMX web service call using jquery?

    - by Mike
    I have a web service with the following contract: POST /Service/service.asmx HTTP/1.1 Host: xxx.xxx.xxx Content-Type: text/xml; charset=utf-8 Content-Length: length SOAPAction: "xxx.xxx.xxx/Service/Method" <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Header> <Request xmlns="xxx.xxx.xxx/Service/"> <transactiontype>string</transactiontype> <username>string</username> <password>string</password> </Request> </soap:Header> <soap:Body> <Method xmlns="xxx.xxx.xxx/Service/"> <xml>xml</xml> </Method> </soap:Body> </soap:Envelope> And I am trying to call the service using jquery. This is my code: $.ajax({ url: serverUrl + 'Method', type: "POST", dataType: "xml", data: { xml: "xml" }, beforeSend: function (req) { req.setRequestHeader('Header', '<Request xmlns="xxx.xxx.xxx/Service/">' +'<transactiontype>4</transactiontype>' +'<agencyName>name</agencyName>' +'<username>user</username>' +'<password>pass</password>' +'</Request>'); }, success: function (data) { alert(data.text); }, error: function (request, status, errorThrown) { alert(status); } }); However, the header content is not passed to the web service? How would I go about passing the header credentials to my web service call?

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  • Javascript check of a form, not waiting for ajax response

    - by Y.G.J
    this is a part of the check in my form function check(theform) { var re = /^\w[0-9A-Za-z]{5,19}$/; if (!re.test(theform.username.value)) { alert("not valid username"); theform.username.focus(); return false; } $.ajax({ type: "POST", url: "username.asp", data: "username="+theform.username.value, success: function(msg){ username = msg; if (!username) { alert("username already in use"); return false; } } }); var re = /^\w[0-9A-Za-z]{5,19}$/; if (!re.test(theform.password.value)) { alert("not valid password"); theform.password.focus(); return false; } } for some reason of sync... it check the username then duplicated username with the ajax and not waiting for respond and jump to the password check. i don't want to insert the rest of the code to isreadystate (or what ever it is) because i might move the username duplicate check to the end... and then the function will end before the ajax anyway what should i do?

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  • Using ZLib unit to compress files vs using ZipForge

    - by user193655
    There are many questions on zipping in Delphi, anyway this is not a duplicate. I am using ZipForge for zip/unzip capability in my application. Currently I use 2 features of ZipForge: 1) zip and unzip (!) 2) password protect the archives Now I am removing the password from all the archives so I need only to zip and unzip files. I zip them just for minimizing bandwith when uploading/downloading files from the server. So my idea is to process all files once for unzipping them (with password) and rezipping them without password. I have nothing against ZipForge, anyway it is an extra component, every time I upgrade to a newest Delphi version I have to wait for the new IDE support and moreover the more components the more problems during the installation. So since what I do is very simple I'd like to replace ZipForge with 2 simple functinos using the ZLib unit. I found (and tested) the functions here on Torry's. What do you think of using Zlib unit? Do you see any potential problem that I would not have with ZipForge? Can you comment on speed?

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  • Comparing textbox.text value to value in SQL Server

    - by Anicho
    Okay so I am trying to compare a login textbox password and username with a custom validator using linq to get information from the database it always returns false though on the validator could someone please tell me where my code below is going wrong. This will be very much appreciated... thank you in advanced... protected void LoginValidate(object source, ServerValidateEventArgs args) { TiamoDataContext context = new TiamoDataContext(); var UsernameCheck = from User in context.Users where User.Username == TextBoxLoginUsername.Text && User.Password == TextBoxLogInPassword.Text select User.Username; var PasswordCheck = from User in context.Users where User.Username == TextBoxLoginUsername.Text && User.Password == TextBoxLogInPassword.Text select User.Password; String test1 = PasswordCheck.ToString(); String test2 = UsernameCheck.ToString(); if (test1 == TextBoxLogInPassword.Text && test2 == TextBoxLoginUsername.Text) { args.IsValid = true; Session["Username"] = TextBoxLoginUsername; Response.Redirect("UserProfile.aspx"); } else { args.IsValid = false; } } I dont know where I am going wrong I know its most probably some sort of silly mistake and me being inexperienced at this...

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  • Trying to use HttpWebRequest to load a page in a file.

    - by Malcolm
    Hi, I have a ASP.NET MVC app that works fine in the browser. I am using the following code to be able to write the html of a retrieved page to a file. (This is to use in a PDF conversion component) But this code errors out continually but not in the browser. I get timeout errors sometimes asn 500 errors. Public Function GetPage(ByVal url As String, ByVal filename As String) As Boolean Dim request As HttpWebRequest Dim username As String Dim password As String Dim docid As String Dim poststring As String Dim bytedata() As Byte Dim requestStream As Stream Try username = "pdfuser" password = "pdfuser" docid = "docid=inv12154" poststring = String.Format("username={0}&password={1}&{2}", username, password, docid) bytedata = Encoding.UTF8.GetBytes(poststring) request = WebRequest.Create(url) request.Method = "Post" request.ContentLength = bytedata.Length request.ContentType = "application/x-www-form-urlencoded" requestStream = request.GetRequestStream() requestStream.Write(bytedata, 0, bytedata.Length) requestStream.Close() request.Timeout = 60000 Dim response As HttpWebResponse Dim responseStream As Stream Dim reader As StreamReader Dim sb As New StringBuilder() Dim line As String = String.Empty response = request.GetResponse() responseStream = response.GetResponseStream() reader = New StreamReader(responseStream, System.Text.Encoding.ASCII) line = reader.ReadLine() While (Not line Is Nothing) sb.Append(line) line = reader.ReadLine() End While File.WriteAllText(filename, sb.ToString()) Catch ex As Exception MsgBox(ex.Message) End Try Return True End Function

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  • curl cookie not creating on success

    - by Bin
    Hi I'm using cUrl(PHP) to post a login request and store response in cookie file. In my second request I'm passing cookie in header and post data to verify it. Issue is that cookie file is not created in first succesful request results in failure for second request. Please suggest me where I'm doing wrong. $cookiefile="/var/www/html/dimdim/cook.txt"; $url_log="http://my.dimdim.com/api/auth/login"; $p_log='request={"account":"bin6k","password":"password","group":"all"}'; $url_ver="http://my.dimdim.com/api/auth/verify"; $p_ver='request={"account":"bin6k","password":"password","group":"all"}'; $ch = curl_init(); //curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_log); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); ob_start(); // prevent any output $retval=curl_exec ($ch); // execute the curl command ob_end_clean(); // stop preventing output curl_close ($ch); //print_r($retval); unset($ch); $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_ver); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); $buf2 = curl_exec ($ch); curl_close ($ch); echo "".htmlentities($buf2);

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  • autologin component doesn't work on remote server

    - by user606521
    I am using autologin component from http://milesj.me/code/cakephp/auto-login (v 3.5.1). It works on my localhost WAMP server but fails on remote server. I am using this settings in beforeFilter() callback: $this->AutoLogin->settings = array( // Model settings 'model' => 'User', 'username' => 'username', 'password' => 'password', // Controller settings 'plugin' => '', 'controller' => 'users', // Cookie settings 'cookieName' => 'rememberMe', 'expires' => '+1 month', // Process logic 'active' => true, 'redirect' => true, 'requirePrompt' => true ); On remote server it simply doesn't autolog users after the browser was closed. I can't figure out what may cause the problem. -------------------- edit I figured out what is causing the problem but I don't know how to fix this. First of all cookie is set like this: $this->Cookie->write('key',array('username' => 'someusername', 'hash' => 'somehash', ...) ); Then it's readed like this: $cookie = $this->Cookie->read('key'); On my WAMP server $cookie is array('username' => 'someusername', 'hash' => 'somehash', ...) and on remote server returned $cookie is string(159) "{\"username\":\"YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t\",\"password\":\"YWxlazc3ODEy\",\"hash\":\"aa15bffff9ca12cdcgfgb351d8bfg2f370bf458\",\"time\":1339923926}" and it should be: array( 'username' => "YWxlay5iYXJzsdsdZXdza2ldssd21haWwuY29t", 'password' => "YWxlazc3ODEy", ...) Why the retuned cookie is string not array?

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Apache is looking for htaccess and htpasswd files that aren't there

    - by user1094092
    Having an issue where Apache is requesting authentication, and looking for an .htpasswd file, based on instructions from an .htaccess file that's no longer in DocumentRoot. Background: In my DocumentRoot, I'd previously copied an .htaccess and .htpasswd file from another machine (along with all of the other website files). .htaccess contents: AuthType Basic AuthName "Password is required" AuthUserFile /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd Require valid-user Here's the catch: I moved .htaccess and .htpasswd out of DocumentRoot and even renamed the files. There is no longer an .htaccess file in DocumentRoot at all. But, when I try to access localhost from a browser, I am prompted to enter the login and password. When I enter the login and password (from the old, not-in-DocumentRoot .hpasswd file), I get a 500 Internal Server error and the log shows: [error] [client 127.0.0.1] (2)No such file or directory: Could not open password file: /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd This has been quite a puzzle, because there's no longer a .htaccess or .htpasswd file anywhere in DocumentRoot !! Have tried several apache restarts and also tried using a blank .htaccess file in the DocumentRoot. Even grepped the entire machine for references to AuthType Basic to see if I missed anything. httpd.conf looks normal enough...I can post that if needed, but this question seems long enough as it is :) Thanks for any assistance you can provide

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  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • SharePoint webpart with button to auto-login to 3rd party website

    - by JCdowney
    I have been tasked with creating a SharePoint 2007 webpart that logs the user directly into our website (which uses forms authentication). Most likely the username and password will be same in the SharePoint account as in our website. Ideally we would like it to be fully integrated in that the webpart looks up the SP login & password, somehow encodes that using SHA1, MD5 or similar encryption, then passes that along to our login page on the query string. However given we have little experience with SharePoint, and that it's probably impossible to programmatically access the SP username/password from a webpart we realize this isn't very likely to be possible and if so would probably require a lot of development time. Another option would be to load a login form from the website within an iframe in the webpart, which would show the login & password first but store a "remember me" cookie after the first login, and on each subsequent load display just a button that logs them in directly using the cookie. Has anyone done something similar before? I'm in over my head, any guidance would be much appreciated! :)

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Can I get the amount of time for which a key is pressed on a keyboard

    - by Adi
    Dear all, I am working on a project in which I have to develop bio-passwords based on user's keystroke style. Suppose a user types a password for 20 times, his keystrokes are recorded, like holdtime : time for which a particular key is pressed. digraph time : time it takes to press a different key. suppose a user types a password " COMPUTER". I need to know the time for which every key is pressed. something like : holdtime for the above password is C-- 200ms O-- 130ms M-- 150ms P-- 175ms U-- 320ms T-- 230ms E-- 120ms R-- 300ms The rational behind this is , every user will have a different holdtime. Say a old person is typing the password, he will take more time then a student. And it will be unique to a particular person. To do this project, I need to record the time for each key pressed. I would greatly appreciate if anyone can guide me in how to get these times. Editing from here.. Language is not important, but I would prefer it in C. I am more interested in getting the dataset.

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  • Android Dev: The constructor Intent(new View.OnClickListener(){}, Class<DrinksTwitter>) is undefined

    - by Malcolm Woods Spark
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Set Click Listener btnLogin.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(this, DrinksTwitter.class); //error on this line startActivity(i); // lblResult.setText("Login successful."); } else { lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); } }

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • How can I spec out an authlogic sessions controller using using a stub?

    - by Dave
    I want to test my User Session Controller testing that a user session is first built then saved. My UserSession class looks like this: class UserSession < Authlogic::Session::Base end The create method of my UserSessionsController looks like this: def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Successfully logged in." redirect_back_or_default administer_home_page_url else render :new end end and my controller spec looks like this: describe UserSessionsController do it "should build a new user session" do UserSession.stub!(:new).with(:email, :password) UserSession.should_receive(:new).with(:email => "[email protected]", :password => "foobar") post :create, :user_session => { :email => "[email protected]", :password => "foobar" } end end I stub out the new method but I still get the following error when I run the test: Spec::Mocks::MockExpectationError in 'UserSessionsController should build a new user session' <UserSession (class)> received :new with unexpected arguments expected: ({:password=>"foobar", :email=>"[email protected]"}) got: ({:priority_record=>nil}, nil) It's although the new method is being called on UserSession before my controller code is getting called. Calling activate_authlogic makes no difference.

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