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  • HTTP Basic authentication using Authlogic or authenticate_or_request_with_http_basic for API call?

    - by Gaius Parx
    I have a Rails 2.3.x app that implements the act_as_authentic in User model and a UserSession model as per Authlogic Github example. I am implementing an API to allow access from iPhone. Will be using HTTP Basic authentication via https (will not implement single access token). Each API call requires a username/password for the access. I am able to access the API by calling http://username:password@localhost:3000/books.xml for example. Authlogic will not persist if using the single access token. But I am using HTTP Basic which I think Authlogic will create session for the API calls, which is not used for my API methods. So for each API call I made, new session object is created. Thus appear to me that this would load up the server resource pretty quickly. Sounds like a bad idea. The alternative is to use the Rails authenticate_or_request_with_http_basic for API controllers. Example adding a before_filter: def require_http_auth_user authenticate_or_request_with_http_basic do |username, password| if @current_user = User.find_by_email(username) @current_user.valid_password?(password) else false end end end This will bypass the Authlogic UserSession and just use the User model. But this will involve using separate authentication codes in the app. Anyone has any comments and can share their experience? Thanks

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  • C# Switch-case Loop for Datagridview cells

    - by Nail Yener
    Hi, I am working on a form with datagridview and webbrowser controls. I have three columns as URL, username and password in datagridview. What I want to do is to automate the login for some websites that I use frequently. For that reason I am not sure if this is the right approach but I created the below code. The problem is with the argument of switch. I will click the row on datagridview and then click the login_button so that the username and password info will be passed to the related fields on the webpage. Why I need a switch-case loop is because all the webpages have different element IDs for username and password fields. As I said, I am not sure if datagridview allows switch-case, I searched the net but couldn't find any samples. private void login_button_Click(object sender, EventArgs e) { switch (dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString()) { case "http://www.website1.com": webBrowser1.Document.GetElementById("username").InnerText = dataGridView1.Rows[3].Cells[3].Value.ToString(); webBrowser1.Document.GetElementById("password").InnerText = dataGridView1.Rows[3].Cells[4].Value.ToString(); return; case "http://www.website2.com": webBrowser1.Document.GetElementById("uname").InnerText = dataGridView1.Rows[4].Cells[3].Value.ToString(); webBrowser1.Document.GetElementById("pswd").InnerText = dataGridView1.Rows[4].Cells[4].Value.ToString(); return; } HtmlElementCollection elements = this.webBrowser1.Document.GetElementsByTagName("Form"); foreach (HtmlElement currentElement in elements) { currentElement.InvokeMember("Login"); } }

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  • how to display the decrypted and splited Strings in order?

    - by sebby_zml
    Hi everyone, i need some help and guidance in displaying the splitted Strings in order. let say, i have username, password, nonceInString. i had successfully encrypted and decrypted those. then i split the decrypted data. it was done, too. i want to display the decrypted data in order. something like this. userneme: sebastian password: harrypotter nonce value: sdgvay1saq3qsd5vc6dger9wqktue2tz* i tried the following code, but it didn't display like i wish to. pls help. thanks a lot in advance. String codeWord = username + ";" + password + ";" + nonceInString; String encryptedData = aesEncryptDecrypt.encrypt(codeWord); String decryptedData = aesEncryptDecrypt.decrypt(encryptedData); String[] splits = decryptedData.split(";"); String[] variables = {"username", "password", "nonce value"}; for (String data : variables){ for (String item : splits){ System.out.println( data + ": "+ item); } }

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  • MySQL Access denied error

    - by dancingbush
    I am trying to install mySQL on a Mac OS 10.8 and set up a user account. NOTE I am a abs beginner when it comes to using the command line in Terminal window. I used these instructions to install: http://www.macminivault.com/mysql-mountain-lion/ I set my own password for all users here: GRANT ALL ON *.* TO 'root'@'localhost' IDENTIFIED BY 'mypass' WITH GRANT OPTION; quit Every time i try to execute mySQL as a root user on the command line i get this: Ciarans-MacBook-Pro:~ callanmooneys$ mysql -u root ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) I read around on the net and tried various things including tried this to change password: mysqladmin -u root -pyourcurrentmysqlrootpassword password yournewmysqlrootpassword, it returns -> -> USE mysql -> If i simply type 'mysql' and launch the mySQL monitor then try to crete a user account: mysql> USE mysql ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'mysql' mysql> Also tried answers on forum: access is denied for user 'root'@localhost mysql error 1045 returned '[email protected] command not found And MySQL - ERROR 1045 - Access denied: Ciarans-MacBook-Pro:~ callanmooneys$ mysqld_safe --skip-grant-tables 131105 21:44:41 mysqld_safe Logging to '/usr/local/mysql/data/Ciarans-MacBook-Pro.local.err'. 131105 21:44:41 mysqld_safe Starting mysqld daemon with databases from /usr/local/mysql/data /usr/local/mysql/bin/mysqld_safe: line 129: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied /usr/local/mysql/bin/mysqld_safe: line 166: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied 131105 21:44:41 mysqld_safe mysqld from pid file /usr/local/mysql/data/Ciarans-MacBook-Pro.local.pid ended /usr/local/mysql/bin/mysqld_safe: line 129: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied Ciarans-MacBook-Pro:~ callanmooneys$ mysql -u root ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2) Ciarans-MacBook-Pro:~ callanmooneys$ Feedback appreciated.

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  • Problem between Glassfish and Spring Security Basic Authentication

    - by Raspayu
    Hi! I am enabling a simple HTTP Basic Authentication with Spring security in my project. My environment is an Glassfish Server (bundled with Netbeans), and almost everything works perfect: I have set up it to just ask for authentication with the POST method, with hardcoded users with "user-service", and it works with user names with no special characters. The problem comes when I set up an user with "@" or "." Here is the spring-security related part of my servlet.xml: <security:http> <security:intercept-url method="POST" pattern="/**" access="ROLE_USER" /> <security:http-basic/> </security:http> <security:authentication-manager alias="authenticationManager"> <security:authentication-provider user-service-ref="uservice"/> </security:authentication-manager> <security:user-service id="uservice"> <security:user name="[email protected]" password="pswd1" authorities="ROLE_USER" /> <security:user name="[email protected]" password="pswd2" authorities="ROLE_USER" /> <security:user name="pepe" password="pepito" authorities="ROLE_USER" /> </security:user-service> I have looked also for what did the browser send to the listening port, and it sends right the par "username:password" in base 64, so i think the problem is in my server(Glassfish v3). Does anyone have any idea? Thanks in advance! Raspayu

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  • Odd behaviour with PHP's in_array function.

    - by animuson
    I have a function that checks multiple form items and returns either boolean(true) if the check passed or the name of the check that was run if it didn't pass. I built the function to run multiple checks at once, so it will return an array of these results (one result for each check that was run). When I run the function, I get this array result: Array ( [0] => 1 [1] => password [2] => birthday ) // print_r array(3) { [0]=> bool(true) [1]=> string(8) "password" [2]=> string(8) "birthday" } // var_dump The 'username' check passed and the 'password' and 'birthday' checks both failed. Then I am using simple in_array statements to determine which ones failed, like so: $results = $ani->e->vld->simulate("register.php", $checks); die(var_dump($results)); // Added after to see what array was being returned if (in_array("username", $results)) // do something if (in_array("password", $results)) // do something if (in_array("birthday", $results)) // do something The problem I'm having is that the 'username' line is still executing, even those 'username' is not in the array. It executes all three statements as if they were all true for some reason. Why is this? I thought maybe that the bool(true) was automatically causing the function to return true for every result without checking the rest of the array, but I couldn't find any documentation that would suggest that very odd functionality.

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  • Wordpress - Set Published Date

    - by danit
    Using this function: function wpPostXMLRPC($title,$body,$rpcurl,$username, $password,$category,**$pubdate**,$keywords='',$encoding='UTF-8') { $title = htmlentities($title,ENT_NOQUOTES,$encoding); $keywords = htmlentities($keywords,ENT_NOQUOTES,$encoding); $content = array( 'title'=>$title, 'description'=>$body, 'mt_allow_comments'=>1, // 1 to allow comments 'mt_allow_pings'=>0, // 1 to allow trackbacks 'post_type'=>'post', 'post_status' => 'draft', **'post_date' =>$pubdate,** 'mt_keywords'=>$keywords, 'categories'=>array($category) ); $params = array(0,$username,$password,$content,true); $request = xmlrpc_encode_request('metaWeblog.newPost',$params); $ch = curl_init(); curl_setopt($ch, CURLOPT_POSTFIELDS, $request); curl_setopt($ch, CURLOPT_URL, $rpcurl); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_TIMEOUT, 1); $results = curl_exec($ch); curl_close($ch); return $results; } My Code: $title = $correctdataandtime; $body = '<a href="' . $links['alternate'] . '" />' . '<img src="' . $links['image'] . '" />' . '</a>'; $pubdate = date("Y-m-d H:i:s", $datetime); //Default Settings $rpcurl = 'http://vl3.co.uk/xmlrpc.php'; $username = 'admin'; $password = '3cdsbvre'; $category = '1'; //default is 1, enter a number here. $keywords = 'Twitter';//keywords comma seperated. $encoding ='UTF-8';//utf8 recommended wpPostXMLRPC($title,$body,$rpcurl,$username,$password,$pubdate,$category,$keywords,$encoding); Output of $pubdate is: 2010-04-05 19:25:31 However it still sets the published date as the date and time when i run the script.

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  • AES Encryption Java Invalid Key length

    - by wuntee
    I am trying to create an AES encryption method, but for some reason I keep getting a 'java.security.InvalidKeyException: Key length not 128/192/256 bits'. Here is the code: public static SecretKey getSecretKey(char[] password, byte[] salt) throws NoSuchAlgorithmException, InvalidKeySpecException{ SecretKeyFactory factory = SecretKeyFactory.getInstance("PBEWithMD5AndDES"); // NOTE: last argument is the key length, and it is 256 KeySpec spec = new PBEKeySpec(password, salt, 1024, 256); SecretKey tmp = factory.generateSecret(spec); SecretKey secret = new SecretKeySpec(tmp.getEncoded(), "AES"); return(secret); } public static byte[] encrypt(char[] password, byte[] salt, String text) throws NoSuchAlgorithmException, InvalidKeySpecException, NoSuchPaddingException, InvalidKeyException, InvalidParameterSpecException, IllegalBlockSizeException, BadPaddingException, UnsupportedEncodingException{ SecretKey secret = getSecretKey(password, salt); Cipher cipher = Cipher.getInstance("AES"); // NOTE: This is where the Exception is being thrown cipher.init(Cipher.ENCRYPT_MODE, secret); byte[] ciphertext = cipher.doFinal(text.getBytes("UTF-8")); return(ciphertext); } Can anyone see what I am doing wrong? I am thinking it may have something to do with the SecretKeyFactory algorithm, but that is the only one I can find that is supported on the end system I am developing against. Any help would be appreciated. Thanks.

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  • Android accessibility focus - clicking a view changes focus to previous view

    - by benkdev
    I'm using android TalkBack to test my application for accessibility use. When I swipe to select a view and double tap, the focus returns the the view above it. Usually when swiping to a view and double clicking it, onClick is called. What am I doing wrong? <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@color/all_white" > <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/header" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/green_bar" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/blue_bar" android:scaleType="center" /> <EditText android:id="@+id/username" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/username" android:focusable="true" android:nextFocusDown="@id/password" /> <EditText android:id="@+id/password" android:inputType="textPassword" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/password" android:focusable="true" android:nextFocusUp="@id/username" android:nextFocusDown="@id/login" /> <Button android:id="@+id/login" android:onClick="doLogin" android:focusable="true" android:layout_width="325dp" android:layout_height="wrap_content" android:text="@string/login" android:nextFocusUp="@id/password" android:nextFocusDown="@id/create_trial_account" /> <Button android:id="@+id/create_trial_account" android:layout_width="100dip" android:layout_height="wrap_content" android:text="@string/new_user" android:onClick="createAccount" android:focusable="true" android:nextFocusUp="@id/login" /> <TextView android:id="@+id/copyright" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/copyright" /> <TextView android:id="@+id/buildNumber" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout>

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  • Flex - Issues retrieving an XMLList

    - by BS_C3
    Hello! I'm having a problem retrieving a XMLList and I don't understand why. I have an application that is running properly. It uses some data from two xml files called division.xml and store.xml. I noticed that I have some data in division.xml that should be in store.xml, so I did a copy/paste of the data from one file to the other. This is the data I copied: <stores> <store> <odeis>101</odeis> <name></name> <password></password> <currency></currency> <currSymbol></currSymbol> </store> <store> <odeis>102</odeis> <name></name> <password></password> <currency></currency> <currSymbol></currSymbol> </store> </stores> In the application, I list all odeis codes and I need to retrieve the block store corresponding to the selected odeis code. Before moving the data into store.xml, this is how I retrieved the block: var node:XMLList = divisionData.division.(@name==HomePageData.instance.divisionName).stores.store.(odeis == HomePageData.instance.storeCodeOdeis) This is how I retrieve it after copying the data into store.xml: var node:XMLList = storeData.stores.(@name==HomePageData.instance.divisionName).store.(odeis == HomePageData.instance.storeCodeOdeis) And I'm currently getting the following error: ReferenceError: Error #1065: The variable odeis is not defined. Could anyone enlighten me? Cause I really have no clue of why it is not working... Thanks for any tips you can give. Regards, BS_C3

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  • Use SQL Result to Query second time and grab more results via php

    - by maxwell
    I am grabbing a list of school names from a database. When the user clicks on the school name, i want the code to fetch 2-3 other attributes related to the school name that the user has clicked on. My code for the single school name list: $query = mysql_query("Select schoolname, product, username, password from credentials c join products p on p.productid = c.productid join schools s on s.schoolid = c.schoolid join icons i on i.productid = p.productid order by s.schoolname"); echo '<ul>'; while($row = mysql_fetch_array($query)) { echo "<li> <a href='#'>" . $row['schoolname'] . "</a> </li>"; } echo ''; Current Output: School A School A School B School B School B School C School C Expected Output: School name displayed only once (distinct won't work because each school name has 2-3 product credentials School A School B School C Ability for User to click on a school. then the school names underneath will move down (toggle effect) and user can see product, username and password displayed for the school clicked (for example: user clicked on School A) School A productname1, username, password productname2, username, password School B School C

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  • Help with SOAP request using PHP

    - by mptre
    I'm having a SOAP related problem in PHP. I'm trying to create arbitrary SOAP request using Nusoap_client class. The complete request including headers should look like the example below. Ofcourse the placeholders (string) should be replaced with actual values. POST /services/RecipeCouponAPI11.asmx HTTP/1.1 Host: example.com Content-Type: text/xml; charset=utf-8 Content-Length: length SOAPAction: "http://www.example.com/services/GetCouponAll" <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Header> <RCAuthenticator xmlns="http://www.example.com/services/"> <UserName>string</UserName> <Password>string</Password> </RCAuthenticator> </soap:Header> <soap:Body> <GetCouponAll xmlns="http://www.example.com/services/"> <campaignCode>string</campaignCode> </GetCouponAll> </soap:Body> </soap:Envelope> I tried the following code with no luck. Seems like the request isn't formated correctly. Any ideas on how to get his working? <?php $client = new Nusoap_client('http://www.example.com/services/RecipeCouponAPI11.asmx'); $headers = new SoapHeader( 'http://www.example.com/services/', 'RCAuthenticator', (object)array( 'UserName' => 'username', 'Password' => 'password' ), false ); $client->setHeaders(array($headers)); $response = $client->call( 'GetCouponAll', array('campaignCode' => 'campaigncode'), null, 'http://www.example.com/services/GetCouponAll' ); ?> Thanks in advantage!

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  • Athentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "string0826" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • Crystal Reports Failed Database Login

    - by Marlon
    Hello, After spending a good 3 to 4 hours on google trying to find any solution to my problem I haven't had much luck. Basically, we use crystal reports for our .NET applications with a sql server back end, we have many clients each with their own server and so our reports need to have their connections dynamically set. Up until a week ago this worked fine. However a few days ago a client reported they were getting a database login prompt for a report (only one report, the rest worked fine). We were quite stumped but we managed to reproduce it on a netbook which didn't have visual studio or sql server installed. In the end the dev decided to reproduce the report in the hope it was just an oddity in that particular report. Unfortunately a new client today also experienced the same problem, but this time for every crystal report they had - and also they worked on the netbook, so we are really quite lost here. Below is a screenshot of what our clients get presented with - and here is the code that I use to set the connection information in the report cI.ServerName = (string)builder["Data Source"]; cI.DatabaseName = (string)builder["Initial Catalog"]; cI.UserID = (string)builder["User ID"]; cI.Password = (string)builder["Password"]; foreach (IConnectionInfo info in cryRpt.DataSourceConnections) { info.SetConnection(cI.ServerName, cI.DatabaseName, cI.UserID, cI.Password); } foreach (ReportDocument sub in cryRpt.Subreports) { foreach (IConnectionInfo info in sub.DataSourceConnections) { info.SetConnection(cI.ServerName, cI.DatabaseName, cI.UserID, cI.Password); } } As always, any help much appreciated.

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  • Problem with cruise control and visual svn

    - by Andrew
    Hi Wonder if anyone can help, I am experiencing a strange issue with my configuration of cruisecontrol.net and visual svn. I am setting the current ccnet.config <sourcecontrol type="svn"> <trunkUrl>https://bladerunner.azullo.local:8443/svn/application/trunk</trunkUrl> <executable>C:\Program Files (x86)\VisualSVN Server\bin\svn.exe</executable> <username>test</username> <password>test</password> <workingDirectory>D:\Development\Build\application\</workingDirectory> </sourcecontrol> <publishers> <xmllogger/> </publishers> <modificationDelaySeconds>10</modificationDelaySeconds> </project> When I run this I expect it to go to https://bladerunner.azullo.local:8443/svn/application/trunk, however i get the following ThoughtWorks.CruiseControl.Core.CruiseControlException: Source control operation failed: svn: OPTIONS of 'http://bladerunner.azullo.local:8080/svn/application/trunk': could not connect to server (http://bladerunner.azullo.local:8080) . Process command: C:\Program Files (x86)\VisualSVN Server\bin\svn.exe update D:\Development\build\application\ --username test --password ** --no-auth-cache --non-interactive at ThoughtWorks.CruiseControl.Core.Sourcecontrol.ProcessSourceControl.Execute(ProcessInfo processInfo) at ThoughtWorks.CruiseControl.Core.Sourcecontrol.Svn.UpdateSource(IIntegrationResult result) at ThoughtWorks.CruiseControl.Core.IntegrationRunner.Build(IIntegrationResult result) at ThoughtWorks.CruiseControl.Core.IntegrationRunner.Integrate(IntegrationRequest request) So for some reason it goes to 'http://bladerunner.azullo.local:8080/svn/application/trunk' If I remove the username and password elements in the ccnet.config. It goes to the correct url. I dont understand this behaviour. I have configured visual svn with a certificate using Active directory Certificate Services, if this was the problem I would expect it to show an error regarding the certificate instead of changing the url. I have cleared our state etc Any Ideas

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  • Possible to recover mysql root pass with sudo server access?

    - by jonathonmorgan
    I've inherited development for a website on vps hosting, and have login info for a user with sudo privileges, but don't have the password for the mysql root user. After digging around a little, it looks like the only way to fix this is to stop mysql (something like this: http://waoewaoe.wordpress.com/2010/02/03/recover-reset-mysql-root-password/). But because the website it's serving is currently in production, I'm hoping you guys can enlighten me to any potential consequences (or let me know if there's typically a file where the password would be accessible). a) during the time mysql is stopped, information in the database won't be accessible, right -- even by other users? b) will resetting the root password have any impact on other users after mysql has restarted? Will their username/passwords still be valid? The current application is using an account with limited privileges to read/write to the database, and while 5min downtime in the middle of the night would probably go unnoticed, half a day while I tie up loose ends/figure out what I screwed up will land in me hot water. Thanks in advance for your help!

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  • Access problems with System.Diagnostics.Process in webservice

    - by Martin
    Hello everyone. I have problems with executing a process in a webservice method on a Windows Server 2003 machine. Here is the code: Dim target As String = "C:\dnscmd.exe" Dim fileInfo As System.IO.FileInfo = New System.IO.FileInfo(target) If Not fileInfo.Exists Then Throw New System.IO.FileNotFoundException("The requested file was not found: " + fileInfo.FullName) End If Dim startinfo As New System.Diagnostics.ProcessStartInfo("C:\dnscmd.exe") startinfo.UseShellExecute = False startinfo.Arguments = "\\MYCOMPUTER /recordadd mydomain.no " & dnsname & " CNAME myhost.mydomain.no" startinfo.UserName = "user1" Dim password As New SecureString() For Each c As Char In "secretpassword".ToCharArray() password.AppendChar(c) Next startinfo.Password = password Process.Start(startinfo) I know the process is being executed because i use processmonitor.exe on the server and it tells me that c:\dnscmd.exe is called with the right parameters Full command line value from procmon is: "C:\dnscmd.exe" \MYCOMPUTER /recordadd mydomain.no mysubdomain CNAME myhost.mydomain.no The user of the created process on the server is NT AUTHORITY\SYSTEM. BUT, the dns entry will not be added! Here is the weird thing: I KNOW the user (user1) I authenticate with has administrative rights (it's the same user I use to log on the machine with), but the user of the process in procmon says NT AUTHORITY\SYSTEM (which is not the user i use to authenticate). Weirdest: If i log on to the server, copy the command line value read from the procmon logging, and paste it in a command line window, it works! Reading procmon after this shows that user1 owns the dnscmd process. Why doesn't user1 become owner of the process started with system.diagnostics.process? Is the reason why the command doesn't work?

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  • java Properties - to expose or not to expose?

    - by ring bearer
    This might be an age old problem and I am sure everyone has their own ways. Suppose I have some properties defined such as secret.user.id=user secret.password=password website.url=http://stackoverflow.com Suppose I have 100 different classes and places where I need to use these properties. Which one is good (1) I create a Util class that will load all properties and serve them using a key constant Such as : Util is a singleton that loads all properties and keeps up on getInstance() call. Util myUtil = Util.getInstance(); String user = myUtil.getConfigByKey(Constants.SECRET_USER_ID); String password = myUtil.getConfigByKey(Constants.SECRET_PASSWORD); .. //getConfigByKey() - inturns invokes properties.get(..) doSomething(user, password) So wherever I need these properties, I can do steps above. (2) I create a meaningful Class to represent these properties; say, ApplicationConfig and provide getters to get specific properties. So above code may look like: ApplicationConfig config = ApplicationConfig.getInstance(); doSomething(config.getSecretUserId(), config.getPassword()); //ApplicationConfig would have instance variables that are initialized during // getInstance() after loading from properties file. Note: The properties file as such will have only minor changes in the future. My personal choice is (2) - let me hear some comments?

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  • Sending email through a Google Apps account is working locally, but not on my web server...

    - by Janis Baldwin
    Related: Send Email via C# through Google Apps account My question is the same so I implemented Koistya's solution as follows. The heartbreak is that it works beautifully on my dev laptop but when ported to web server it times out with no explanation. My SMTP config is in my web.config file. I made mods based on Koistya's answer: <mailSettings> **Changed** <smtp from="[email protected]"> <network host="smtp.gmail.com" password="[password]" port="587" userName="[email protected]"/> </smtp> **Original** <!--<smtp from="[email protected]"> <network host="mail.domain.com" password="[password]" port="25" userName="[email protected]"/> </smtp>--> </mailSettings> My .Net C# code (before & after removed): SmtpClient mSmtpClient = new SmtpClient(); mSmtpClient.EnableSsl = true; mSmtpClient.Send(message); As I said this works great on my dev environment but not on web. Can anyone help? Thanks.

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  • Eclipselink update existing tables

    - by javydreamercsw
    Maybe I got it wrong but i though that JPA was able to update an existing table (model changed adding a column) but is not working in my case. I can see in the logs eclipselink attempting to create it but failing because it already exists. Instead of trying an update to add the column it keeps going. (Had to remove some < so it displays) property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/jwrestling"/ property name="javax.persistence.jdbc.password" value="password"/ property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/ property name="javax.persistence.jdbc.user" value="user"/ property name="eclipselink.ddl-generation" value="create-tables"/ property name="eclipselink.logging.logger" value="org.eclipse.persistence.logging.DefaultSessionLog"/ property name="eclipselink.logging.level" value="INFO"/ And here's the table with the change (online column added) [EL Warning]: 2010-05-31 14:39:06.044--ServerSession(16053322)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.1.0.v20100517-r7246): org.eclipse.persistence.exceptions.DatabaseException Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Table 'account' already exists Error Code: 1050 Call: CREATE TABLE account (ID INTEGER NOT NULL, USERNAME VARCHAR(32) NOT NULL, SECURITY_KEY VARCHAR(255) NOT NULL, EMAIL VARCHAR(64) NOT NULL, STATUS VARCHAR(8) NOT NULL, TIMEDATE DATETIME NOT NULL, PASSWORD VARCHAR(255) NOT NULL, ONLINE TINYINT(1) default 0 NOT NULL, PRIMARY KEY (ID)) Query: DataModifyQuery(sql="CREATE TABLE account (ID INTEGER NOT NULL, USERNAME VARCHAR(32) NOT NULL, SECURITY_KEY VARCHAR(255) NOT NULL, EMAIL VARCHAR(64) NOT NULL, STATUS VARCHAR(8) NOT NULL, TIMEDATE DATETIME NOT NULL, PASSWORD VARCHAR(255) NOT NULL, ONLINE TINYINT(1) default 0 NOT NULL, PRIMARY KEY (ID))") [EL Warning]: 2010-05-31 14:39:06.074--ServerSession(16053322)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.1.0.v20100517-r7246): org.eclipse.persistence.exceptions.DatabaseException After this it continues with the following. Am I doing something wrong or is a bug?

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  • chrome extension login security with iframe

    - by Weaver
    I should note, I'm not a chrome extension expert. However, I'm looking for some advice or high level solution to a security concern I have with my chrome extension. I've searched quite a bit but can't seem to find a concrete answer. The situation I have a chrome extension that needs to have the user login to our backend server. However, it was decided for design reasons that the default chrome popup balloon was undesirable. Thus I've used a modal dialog and jquery to make a styled popup that is injected with content scripts. Hence, the popup is injected into the DOM o the page you are visiting. The Problem Everything works, however now that I need to implement login functionality I've noticed a vulnerability: If the site we've injected our popup into knows the password fields ID they could run a script to continuously monitor the password and username field and store that data. Call me paranoid, but I see it as a risk. In fact,I wrote a mockup attack site that can correctly pull the user and password when entered into the given fields. My devised solution I took a look at some other chrome extensions, like Buffer, and noticed what they do is load their popup from their website and, instead, embed an iFrame which contains the popup in it. The popup would interact with the server inside the iframe. My understanding is iframes are subject to same-origin scripting policies as other websites, but I may be mistaken. As such, would doing the same thing be secure? TLDR To simplify, if I embedded an https login form from our server into a given DOM, via a chrome extension, are there security concerns to password sniffing? If this is not the best way to deal with chrome extension logins, do you have suggestions with what is? Perhaps there is a way to declare text fields that javascript can simply not interact with? Not too sure! Thank you so much for your time! I will happily clarify anything required.

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  • Authentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • Ruby script/console and Ruby script/server using two different DBs?

    - by aronchick
    Has anyone seen where script/console and script/server load two different databases (though both report using the same)? Here's the first output $ script/server => Booting WEBrick => Rails 2.3.5 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server [2010-03-21 15:54:05] INFO WEBrick 1.3.1 [2010-03-21 15:54:05] INFO ruby 1.8.7 (2010-01-10) [i386-mingw32] [2010-03-21 15:54:05] INFO WEBrick::HTTPServer#start: pid=7148 port=3000 No errors. I then run my standard code for entering a form - no problems. Checking the Dev Database (.yml at bottom): mysql> select * from books; [...] | 712 | Book | Book Name | 2010-03-21 22:29:22 | 2010-03-21 22:29:22 | [...] 712 rows in set (0.00 sec) The code CLEARLY saved it seconds ago And now here's the output of script/console: $ script/console Loading development environment (Rails 2.3.5) >> Books.all => [] Nothing. Further, upon further inspection, it's using the production database, but I can't figure out why. Any thoughts here? All consoles have been closed and reopened. UPDATE: Requested .yml file (can't see how it'd be helpful (user name and password are all the same for each)) - development: adapter: mysql database: BooksDBdev username: <user name> password: <long string> timeout: 5000 # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql database: BooksDBtest username: <user name> password: <long string> timeout: 5000 production: adapter: mysql database: BooksDB username: <user name> password: <long string> timeout: 5000

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  • What is the best way to extend restful_authentication/AuthLogic to support lazy logins by an anonymo

    - by Kevin Elliott
    I'm building an iPhone application that talks to a Ruby on Rails backend. The Ruby on Rails application will also service web users. The restful_authentication plugin is an excellent way to provide quick and customizable user authentication. However, I would like users of the iPhone application to have an account created automatically by the phone's unique identifier ([[UIDevice device] uniqueIdentifier]) stored in a new column. Later, when users are ready to create a username/password, the account will be updated to contain the username and password, leaving the iPhone unique identifier intact. Users should not be able to access the website until they've setup their username/password. They can however, use the iPhone application, since the application can authenticate itself using it's identifier. What is the best way to modify restful_authentication to do this? Create a plugin? Or modify the generated code? What about alternative frameworks, such as AuthLogic. What is the best way to allow iPhones to get a generated auth token locked to their UUID's, but then let the user create a username/password later?

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  • Unit Testing (xUnit) an ASP.NET Mvc Controller with a custom input model?

    - by Danny Douglass
    I'm having a hard time finding information on what I expect to be a pretty straightforward scenario. I'm trying to unit test an Action on my ASP.NET Mvc 2 Controller that utilizes a custom input model w/ DataAnnotions. My testing framework is xUnit, as mentioned in the title. Here is my custom Input Model: public class EnterPasswordInputModel { [Required(ErrorMessage = "")] public string Username { get; set; } [Required(ErrorMessage = "Password is a required field.")] public string Password { get; set; } } And here is my Controller (took out some logic to simplify for this ex.): [HttpPost] public ActionResult EnterPassword(EnterPasswordInputModel enterPasswordInput) { if (!ModelState.IsValid) return View(); // do some logic to validate input // if valid - next View on successful validation return View("NextViewName"); // else - add and display error on current view return View(); } And here is my xUnit Fact (also simplified): [Fact] public void EnterPassword_WithValidInput_ReturnsNextView() { // Arrange var controller = CreateLoginController(userService.Object); // Act var result = controller.EnterPassword( new EnterPasswordInputModel { Username = username, Password = password }) as ViewResult; // Assert Assert.Equal("NextViewName", result.ViewName); } When I run my test I get the following error on my test fact when trying to retrieve the controller result (Act section): System.NullReferenceException: Object reference not set to an instance of an object. Thanks in advance for any help you can offer!

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