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  • Regular expression problem (PHP)

    - by Marcos
    Hello all. I have a little problem with my regular expression, that I use in PHP. My code identify all tags of my content and add a link in this image. My code is working when I use dinamycally, without any defined image. When I try with a imapge path, the code does not work. How can I solve this problem? Working code: $content = preg_replace('/(<img .*?src="(.+?)".*?>)/','<a class="nyromodal foto" href="'.$imagem_wordpress.'">\1</a>', $content); Problem code: $content = preg_replace('/(<img .*?src="ttp://mysite.com/files/2010/04/bac-gallery-site-matters-saline-project1.jpg".*?>)/','<a class="nyromodal foto" href="'.$imagem_wordpress.'">\1</a>', $content);

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  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

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  • Confusion in RegExp Reluctant quantifier? Java

    - by Dusk
    Hi, Could anyone please tell me the reason of getting an output as: ab for the following RegExp code using Relcutant quantifier? Pattern p = Pattern.compile("abc*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group()); // ab and getting empty indices for the following code? Pattern p = Pattern.compile(".*?"); Matcher m = p.matcher("abcfoo"); while(m.find()) System.out.println(m.group());

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  • php preg_replace, regexp

    - by Michael
    I'm trying to extract the postal codes from yell.com using php and preg_replace. I successfully extracted the postal code but only along with the address. Here is an example $URL = "http://www.yell.com/ucs/UcsSearchAction.do?scrambleSeed=17824062&keywords=shop&layout=&companyName=&location=London&searchType=advance&broaderLocation=&clarifyIndex=0&clarifyOptions=CLOTHES+SHOPS|CLOTHES+SHOPS+-+LADIES|&ooa=&M=&ssm=1&lCOption32=RES|CLOTHES+SHOPS+-+LADIES&bandedclarifyResults=1"; //get yell.com page in a string $htmlContent = $baseClass-getContent($URL); //get postal code along with the address $result2 = preg_match_all("/(.*)/", $htmlContent, $matches); print_r($matches); The above code ouputs something like Array ( [0] = Array ( [0] = 7, Royal Parade, Chislehurst, Kent BR7 6NR [1] = 55, Monmouth St, London, WC2H 9DG .... the problem that I have is that I don't know how to extract the the postal code because it doesn't have an exact number of digits (sometimes it has 6 digits and sometimes has only 5 times). Basically I should extract the lasted 2 words from each array . Thank you in advance for any help !

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  • Regular Expression to find the job id in a string

    - by Jamie
    Hi all, Please could someone help me, i will be forever appreciative. I'm trying to create a regular expression which will extract 797 from "Your job 797 ("job_name") has been submitted" or "Your Job 9212 ("another_job_name") has been submitted" etc. Any ideas? Thanks guys!

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  • javascript split() array contains

    - by Mahesha999
    While learning JavaScript, I did not get why the output when we print the array returned of the Sting.split() method (with regular expression as an argument) is as explained below. var colorString = "red,blue,green,yellow"; var colors = colorString.split(/[^\,]+/); document.write(colors); //this print 7 times comma: ,,,,,,, However when I print individual element of the array colors, it prints an empty string, three commas and an empty string: document.write(colors[0]); //empty string document.write(colors[1]); //, document.write(colors[2]); //, document.write(colors[3]); //, document.write(colors[4]); //empty string document.write(colors[5]); //undefined document.write(colors[6]); //undefined Then, why printing the array directly gives seven commas. Though I think its correct to have three commas in the second output, I did not get why there is a starting (at index 0) and ending empty string (at index 4). Please explain I am screwed up here.

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  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

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  • RegularExpressionValidator - Windows ID Validation

    - by Albert
    I'd like to setup a RegularExpressionValidator to ensure users are entering valid windows IDs in a textbox. Specifically, I'd like to ensure it's any three capital letters (for our range of domains), followed by a backslash, followed by any number of letters and numbers. Does anyone know where I can find some examples of this type of validation...or can somebody whip one up for me? :)

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  • How to find which delimiter was used during string split (VB.NET)

    - by typoknig
    Hi all, lets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question? Dim linePunctuation as Integer = 0 Dim myString As String = "some text. with punctuation! in it?" For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "." Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "!" Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "?" Then linePunctuation += 1 Next Dim delimiters(3) As Char delimiters(0) = "." delimiters(1) = "!" delimiters(2) = "?" currentLineSplit = myString.Split(delimiters) Dim sentenceArray(linePunctuation) As String Dim count As Integer = 0 While linePunctuation > 0 sentenceArray(count) = currentLineSplit(count)'Here I want to add what ever delimiter was used to make the split back onto the string before it is stored in the array.' count += 1 linePunctuation -= 1 End While

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  • Is there an easy method to combine two relative paths in C# ?

    - by Ioannis
    I want to combine two relative paths in C#. For example: string path1 = "/System/Configuration/Panels/Alpha"; string path2 = "Panels/Alpha/Data"; I want to return string result = "/System/Configuration/Panels/Alpha/Data"; I can implement this by splitting the second array and compare it in a for loop but I was wondering if there is something similar to Path.Combine available or if this can be accomplished with regular expressions or Linq? Thanks

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  • PHP regular expression for positive number with 0 or 2 decimal places

    - by Peter
    Hi I am trying to use the following regular expression to check whether a string is a positive number with either zero decimal places, or 2: ^\d+(\.(\d{2}))?$ When I try to match this using preg_match, I get the error: Warning: preg_match(): No ending delimiter '^' found in /Library/WebServer/Documents/lib/forms.php on line 862 What am I doing wrong?

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  • I am using a regex snippet query string path

    - by Shelby Poston
    Using the following to load images base on two ids one is the and bookid and the out is the client. My folder structures is this. root path = flipbooks subfolders under flipbooks are books and clients in subfolder books I have and .net page title tablet. the tablet code behind checks the bookid of client and render a the tablet page with images in a flipbook fashion. because we have over 15000 records and flipbooks already created and stored in the database. I don't move the client folder under the books subfolders. I need the code below to get to the client subfolder in the query string and help to change this would be helpful. The result now is http://www.somewebsite.com/books/client/images/someimage1.jpg[^] I need the results to be http://www.somewebsite.com/client/images/someimage1.jpg[^]. I tried moving the tablet.aspx file to the root flipbooks and it works but i have provide a user name and password each time. This need to be access by the public and my root is protected. Don't want to have to change permission. I am trying to remove the /books function getParameterByName(name) { var results = RegExp('[?&]' + name + '=([^&]*)').exec(window.location.search); return results ? decodeURIComponent(results[1].replace(/\+/g, ' ')) : null; } Thanks Mission Critical

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  • jquery sortable with regexp

    - by Chris Lively
    I am trying to figure out the right regexp to match on list item id's. For example: <ul id="MyList" class="connectedSortable"> <li id="id=1-32">Item 1</li> <li id="id=2_23">Item 2</li> <li id="id=3">Item 3</li> <li id="id=4">Item 4</li> <li id="id=5">Item 5</li> <li id="id=6">Item 6</li> </ul> On the serialize method, I want it to pull everything after the equal sign (=) $(function () { $("#MyList, #OtherList").sortable({ connectWith: '.connectedSortable', update: function () { $("#MyListOrder").val($("#MyList").sortable('serialize', { regexp: '/(.+)[=](.+)/)' })); } }).disableSelection(); }); I tried the above, but that didn't quite work. My regexp expression is wrong and I don't know what it should be. Ideas?

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  • How to get N random string from a {a1|a2|a3} format string?

    - by Pentium10
    Take this string as input: string s="planets {Sun|Mercury|Venus|Earth|Mars|Jupiter|Saturn|Uranus|Neptune}" How would I choose randomly N from the set, then join them with comma. The set is defined between {} and options are separated with | pipe. The order is maintained. Some output could be: string output1="planets Sun, Venus"; string output2="planets Neptune"; string output3="planets Earth, Saturn, Uranus, Neptune"; string output4="planets Uranus, Saturn";// bad example, order is not correct Java 1.5

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  • Writing a PHP web crawler using cron

    - by Horse
    Hi all I have written myself a web crawler using simplehtmldom, and have got the crawl process working quite nicely. It crawls the start page, adds all links into a database table, sets a session pointer, and meta refreshes the page to carry onto the next page. That keeps going until it runs out of links That works fine however obviously the crawl time for larger websites is pretty tedious. I wanted to be able to speed things up a bit though, and possibly make it a cron job. Any ideas on making it as quick and efficient as possible other than setting the memory limit / execution time higher?

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  • Dreamweaver regular expression substitution followed by number

    - by mark
    Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

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  • Regular expression to retrieve everything before first slash

    - by alex
    I need a regular expression to basically get the first part of a string, before the first slash (). For example in the following: C:\MyFolder\MyFile.zip The part I need is "C:" Another example: somebucketname\MyFolder\MyFile.zip I would need "somebucketname" I also need a regular expression to retrieve the "right hand" part of it, so everything after the first slash (excluding the slash.) For example somebucketname\MyFolder\MyFile.zip would return MyFolder\MyFile.zip.

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  • regexp target last main li in list

    - by veilig
    I need to target the starting tag of the last top level LI in a list that may or may-not contain sublists in various positions - without using CSS or Javascript. Is there a simple/elegant regexp that can help with this? I'm no guru w/ them, but it appears the need for greedy/non-greedy selectors when I'm selecting all the middle text (.*) / (.+) changes as nested lists are added and moved around in the list - and this is throwing me off. $pattern = '/^(<ul>.*)<li>(.+<\/li><\/ul>)$/'; $replacement = '$1<li id="lastLi">$3'; Perhaps there is an easier approach?? converting to XML to target the LI and then convert back? ie: Single Element <ul> <li>TARGET</li> </ul> Multiple Elements <ul> <li>foo</li> <li>TARGET</li> </ul> Nested Lists before end <ul> <li> foo <ul> <li>bar</li> </ul> <li> <li>TARGET</li> </ul> Nested List at end <ul> <li>foo</li> <li> TARGET <ul> <li>bar</li> </ul> </li> </ul>

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  • Java Regular Expression. Check if String contains ONLY Letters

    - by user69514
    How do I check if a String contains only letters in java? I want to write an if statement that will return false if there is a white space, a number, a symbol or anything else other than a-z A-Z. My string must contain ONLY letters. I thought I could do it this way, but I'm doing it wrong: if( ereg("[a-zA-Z]+", $myString)) return true; else return false;

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  • Regular Expression to isolate an html tag

    - by orit cohen
    I'm looking for a regular expression to isolate an html tag. This includes the TAG the ATTRIBUTES and the CONTNET inside. Let's say I have this: <html> <body> aajsdfkjaskd <TAGNAME name="bla" context="non">hfdfhdj </TAGNAME> </body> </html> I need a regular expression that would return: <TAGNAME name="bla" context="non">hfdfhdj </TAGNAME> Thank, Joe

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  • Jakarta Regexp 1.5 Backreferences?

    - by Matt Smith
    Why does this match: String str = "099.9 102.2" + (char) 0x0D; RE re = new RE("^([0-9]{3}.[0-9]) ([0-9]{3}.[0-9])\r$"); System.out.println(re.match(str)); But this does not: String str = "099.9 102.2" + (char) 0x0D; RE re = new RE("^([0-9]{3}.[0-9]) \1\r$"); System.out.println(re.match(str)); The back references don't seem to be working... What am I missing?

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