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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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  • Filter list of phone numbers using php

    - by LiveEn
    I have a list of phone numbers that start with the below numbers and in different formats...i need to grab the numbers that start only with the below numbers/format using php...... 020 8 07974 +44 (0) 20 +44 0 440203 any help will be appreciated..

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  • Regular Expression for username

    - by neobie
    I need help on regular expression on the condition (4) below: Begin with a-z End with a-z0-9 allow 3 special characters like ._- The characters in (3) must be followed by alphanumeric characters, and it cannot be followed by any characters in (3) themselves. Not sure how to do this. Any help is appreciated, with the sample and some explanations.

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  • How Do I grep For non-ASCII Characters in UNIX

    - by Peter Conrey
    I have several very large XML files and I'm trying to find the lines that contain non-ASCII characters. I've tried the following: grep -e "[\x{00FF}-\x{FFFF}]" file.xml But this returns every line in the file, regardless of whether the line contains a character in the range specified. Do I have the syntax wrong or am I doing something else wrong? I've also tried: egrep "[\x{00FF}-\x{FFFF}]" file.xml (with both single and double quotes surrounding the pattern).

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  • Find and replace braced tags within a MySQL table

    - by Cy
    I have about 40000 records in that table that contains plain text and within the plain text, contains that kind of tags which its only characteristic is that they are braced between [ ] [caption id="attachment_2948" align="alignnone" width="480" caption="the caption goes here"] How could I remove those? (replace by nothing) I could also run a PHP program if necessary to do the cleanup.

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • Simple regular expression for decimal numbers?

    - by finch
    I know this may be the simplest question ever asked on Stack Overflow, but what is the regular expression for a decimal with a precision of 2? Valid examples: 123.12 2 56754 92929292929292.12 0.21 3.1 Invalid examples: 12.1232 2.23332 e666.76 Sorry for the lame question, but for the life of me I haven't been able to find anyone that can help! The decimal place may be option, and that integers may also be included.

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  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

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  • Regular expressions in python unicode

    - by Remy
    I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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  • String pattern matching in Javascript

    - by kwokwai
    Hi all, I am doing some self learning about Patern Matching in Javascript. I got a simple input text field in a HTML web page, and I have done some Javascript to capture the string and check if there are any strange characters other than numbers and characters in the string. But I am not sure if it is correct. Only numbers, characters or a mixture of numbers and characters are allowed. var pattern = /^[a-z]+|[A-Z]+|[0-9]+$/; And I have another question about Pattern Matching in Javascript, what does the percentage symbol mean in Pattern matching. For example: var pattern = '/[A-Z0-9._%-]+@[A-Z0-9.-]+\.[A-Z]{2,4}/';

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  • Why does this regular expression for sed break inside Makefile?

    - by jcrocholl
    I'm using GNU Make 3.81, and I have the following rule in my Makefile: jslint : java org.mozilla.javascript.tools.shell.Main jslint.js mango.js \ | sed 's/Lint at line \([0-9]\+\) character \([0-9]\+\)/mango.js:\1:\2/' This works fine if I enter it directly on the command line, but the regular expression does not match if I run it with "make jslint". However, it works if I replace \+ with \{1,\} in the Makefile: jslint : java org.mozilla.javascript.tools.shell.Main jslint.js mango.js \ | sed 's/Lint at line \([0-9]\{1,\}\) character \([0-9]\{1,\}\)/mango.js:\1:\2/' Is there some special meaning to \+ in Makefiles, or is this a bug?

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  • sed - trying to replace first occurrence after a match

    - by wakkaluba
    I am facing a situation that drives me nuts. I am setting up an update server which uses a json file. Don't ask why or how, it sucks and is my only possibility to achieve it. I have been trying and researching for HOURS (many) because I went ballistic and wanted to crack this on my own. But I have to realize I got stuck and need help. So sorry for this chunk but I think it is somewhat important to see... The file is a one liner and repeating the following sequence with changing values (of course). "plugin_name_foo_bar": {"buildDate": "bla", "dependencies": [{"name": "bla", "optional": true, "version": "1.00"}], "developers": [{"developerId": "bla", "email": "[email protected]", "name": "Bla bla2nd"}], "excerpt": "some text {excerpt} !bla.png|thumbnail,border=1! ", "gav": "bla", "labels": ["report", "scm-related"], "name": "plugin_name_foo_bar", "previousTimestamp": "bla", "previousVersion": "1.0", "releaseTimestamp": "bla", "requiredCore": "1", "scm": "github.com", "sha1": "ynnBM2jWo25ZLDdP3ybBOnV/Pio=", "title": "bla", "url": "http://bla.org", "version": "1.0", "wiki": "https://bla.org"}, "Exclusion": {"buildDate": "bla", "dependencies": [], and the next plugin block is glued straight afterwards. What I now want to do is to search for "plugin_foo_bar": {" as this is the unique identifier for a new plugin description block. I want to replace the first sha1 value occuring afterwards. That's where I keep failing. I always grab the first,last or any occurrence in the entire file and not the block :( "title" is the unique identifier after the sha1 value. So I tried to make the .* less greedy but it ain't working out. last attempt was heading towards: sed -i 's/("name": "plugin_name_foo_bar.*sha1": ")([a-zA-Z0-9!@#\$%^&*()\[\]]*)(", "title"\)/\1blablabla\2/1' default.json to find the sha1 value of that plugin but still no joy. I hope someone knows - preferably a simpler approach - before I now continue with trial and error until I have to puke and freakout. I am working with SED on Windows, so Unix approach might help me to figure out how to achieve this in batch but please make it as one-liner if possible. Scripts are a real pain to convert. And I just need SED and no other solution with other tools like AWK. That is absolutely out of discussion. Any help is appreciated :) Cheers Jan

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  • MySQL search a text from two columns

    - by I Like PHP
    i have a table (tbl_world) which look like this id | first_name | last_name | age | class | now i want to search the text which can be anywhere in first_name or in last_name i m using below mysql query "SELECT * FROM tbl_world WHERE REGEXP '".$word."' IN( first_name, last_name)"; where $word is user input (means if i search 'hell' then 'hello' as well as 'wellhell' also returned in result) above query display error, please suggest me optimize method for search in mysql. addition question: should i use LIKR or RLIKE?

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  • Regexs in Ruby getting filename

    - by user1290757
    i am extracting file names of html files using line: filename = File.basename(input_filename, ".*") which currently prints full file name excluding .html extension All files are stored in the form of http^x.x.edu^1^2 all file names begin with http^ and contain edu^ what i want is to extract 2 (which changes) but it is always the second element after .edu I have attempted destructive gsub! but i m weak with regular expressions.

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  • How can I match a match a null byte (0x00) in the Visual Studio binary editor with a find using a re

    - by Paul K
    Open a file in the Visual Studio binary editor that contains a null byte (0x00), then use the Quick Find feature (Ctrl +F) to find null bytes. I would have thought I could use a regular expression such as \x00 to match null bytes but it doesn't work. Searching for any other hex value using this method works fine. Is this a VS bug, 'feature', or am I just missing something? Is there a work around?

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  • regular expression for challenge value

    - by Salman
    Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

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  • glibc regexp performance

    - by Jack
    Anyone has experience measuring glibc regexp functions? Are there any generic tests I need to run to make such a measurements (in addition to testing the exact patterns I intend to search)? Thanks.

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  • A more elegant way to parse a string with ruby regular expression using variable grouping?

    - by i0n
    At the moment I have a regular expression that looks like this: ^(cat|dog|bird){1}(cat|dog|bird)?(cat|dog|bird)?$ It matches at least 1, and at most 3 instances of a long list of words and makes the matching words for each group available via the corresponding variable. Is there a way to revise this so that I can return the result for each word in the string without specifying the number of groups beforehand? ^(cat|dog|bird)+$ works but only returns the last match separately , because there is only one group.

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  • re.sub emptying list

    - by jmau5
    def process_dialect_translation_rules(): # Read in lines from the text file specified in sys.argv[1], stripping away # excess whitespace and discarding comments (lines that start with '##'). f_lines = [line.strip() for line in open(sys.argv[1], 'r').readlines()] f_lines = filter(lambda line: not re.match(r'##', line), f_lines) # Remove any occurances of the pattern '\s*<=>\s*'. This leaves us with a # list of lists. Each 2nd level list has two elements: the value to be # translated from and the value to be translated to. Use the sub function # from the re module to get rid of those pesky asterisks. f_lines = [re.split(r'\s*<=>\s*', line) for line in f_lines] f_lines = [re.sub(r'"', '', elem) for elem in line for line in f_lines] This function should take the lines from a file and perform some operations on the lines, such as removing any lines that begin with ##. Another operation that I wish to perform is to remove the quotation marks around the words in the line. However, when the final line of this script runs, f_lines becomes an empty lines. What happened? Requested lines of original file: ## English-Geek Reversible Translation File #1 ## (Moderate Geek) ## Created by Todd WAreham, October 2009 "TV show" <=> "STAR TREK" "food" <=> "pizza" "drink" <=> "Red Bull" "computer" <=> "TRS 80" "girlfriend" <=> "significant other"

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