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  • What percentage of revenue would be fair for app stores to take? [closed]

    - by Tyler Collier
    Apple takes 30% of revenue from app sales on the iPhone app store. Now Apple does the same with the Mac app store. Google also takes a 30% cut in the Android Market. These seem pretty steep. What percentage do you think would be fair and good for both you as a developer/vendor and Apple/Google? What's a happier middle ground? 20%? If the answer you give is less than 30% but you are selling apps in the app store or android market, please explain why you are willing to, and what benefits Apple and Google would see from reducing their cuts.

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  • High Salaried Investment Banking Jobs for Developers — What are the pitfalls?

    - by Jaywalker
    This question might make more sense to somebody having multi-threaded programming experience in Java/ C++ with some job experience in London / Singapore. There is a huge market of Investment Banking development jobs with astonishingly high salaries (sometimes more than 100K pounds per year). Can someone with experience as a front office/trading developer tell what are the requirements to land this type job? What are the downside that i should be ready for?

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  • Report: Systems Engineer Is Best IT Job

    San Francisco-based research and analysis group, Focus, has named systems engineer as the "best job in America."...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Delete Job by Name

    - by Derek D.
    When scripting out jobs using ssms (sql server management studio) the default script for a drop statement is to drop the job according to it’s job_id. This is not beneficial however when pushing code to different environments. Job_id’s are specific to the windows environment in which they are created. To get around [...]

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  • Advice for a getting a job in algorithmic trading - writing faster code

    - by Alex
    I am currently an intermediate Java developer working in the financial industry. I am considering trying to get into an algorithmic trading developer position. I am looking for any advice/resources that may help me obtain such a job. My naive initial thoughts are to concentrate on learning how to write faster, more memory efficient code whilst maintaining readability. Can anyone point me in the right direction of some useful resources for what I am aiming to achieve?

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  • Algorithm for Shortest Job First with Preemption

    - by Shray
    I want to implement a shortest job first routine using C# or C++. Priority of Jobs are based on their processing time. Jobs are processed using a binary (min) heap. There are three types of jobs. Type 1 is when jobs come in between every 4-6 seconds, with processing times between 4-6. Type 2 job comes in between 8-12 seconds, with processing times between 8-12. Type 3 job comes in between 24-26 seconds, with processing times between 14-16. So far, I have written the binary heap functionality, but Im kinda confused on how to start processing spawn and also the processor. #include <iostream> #include <stdlib.h> #include <time.h> using namespace std; int timecounting = 20; struct process{ int atime; int ptime; int type; }; class pque{ private: int count; public: process pheap[100]; process type1[100]; process type2[100]; process type3[100]; process type4[100]; pque(){ count = 0; } void swap(int a, int b){ process tempa = pheap[a]; process tempb = pheap[b]; pheap[b] = tempa; pheap[a] = tempb; } void add(process c){ int current; count++; pheap[count] = c; if(count > 0){ current = count; while(pheap[count/2].ptime > pheap[current].ptime){ swap(current/2, current); current = current/2; } } } void remove(){ process temp = pheap[1]; // saves process to temporary pheap[1] = pheap[count]; //takes last process in heap, and puts it at the root int n = 1; int leftchild = 2*n; int rightchild = 2*n + 1; while(leftchild < count && rightchild < count) { if(pheap[leftchild].ptime > pheap[rightchild].ptime) { if(pheap[leftchild].ptime > pheap[n].ptime) { swap(leftchild, n); n = leftchild; int leftchild = 2*n; int rightchild = 2*n + 1; } } else { if(pheap[rightchild].ptime > pheap[n].ptime) { swap(rightchild, n); n = rightchild; int leftchild = 2*n; int rightchild = 2*n + 1; } } } } void spawn1(){ process p; process p1; p1.atime = 0; int i = 0; srand(time(NULL)); while(i < timecounting) { p.atime = rand()%3 + 4 + p1.atime; p.ptime = rand()%5 + 1; p1.atime = p.atime; p.type = 1; type1[i+1] = p; i++; } } void spawn2(){ process p; process p1; p1.atime = 0; srand(time(NULL)); int i = 0; while(i < timecounting) { p.atime = rand()%3 + 9 + p1.atime; p.ptime = rand()%5 + 6; p1.atime = p.atime; p.type = 2; type2[i+1] = p; i++; } } void spawn3(){ process p; process p1; p1.atime = 0; srand(time(NULL)); int i = 0; while(i < timecounting) { p.atime = rand()%3 + 25 + p1.atime; p.ptime = rand()%5 + 11; p1.atime = p.atime; p.type = 3; type3[i+1] = p; i++; } } void spawn4(){ process p; process p1; p1.atime = 0; srand(time(NULL)); int i = 0; while(i < timecounting) { p.atime = rand()%6 + 30 + p1.atime; p.ptime = rand()%5 + 8; p1.atime = p.atime; p.type = 4; type4[i+1] = p; i++; } } void processor() { process p; process p1; p1.atime = 0; int n = 1; int n1 = 1; int n2 = 1; for(int i = 0; i<timecounting;i++) { if(type1[n].atime == i) { add(type1[n]); n++; } if(type2[n1].atime == i) { add(type1[n1]); n1++; } if(type3[n2].atime == i) { add(type1[n2]); n2++; } /* if(pheap[1].atime <= i) { while(pheap[1].atime != 0){ pheap[1].atime--; i++; } remove(); }*/ } } };

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  • How To find A Job Online: What You Need To Do

    Before the advent of internet, job seekers depended of newspapers, magazines, posters and the electronic media to get to know about employment opportunities. But now the internet has emerged as one o... [Author: Ryan Fyfe - Computers and Internet - April 23, 2010]

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  • How does rc job work / order of (contradicting) "start on ..." and "stop on ..." stanzas

    - by Binarus
    Hi, I just can't understand how Upstart's rc job definition in Natty 11.04 works. To illustrate the problem, here is the definition (empty lines and comments are left out): start on runlevel [0123456] stop on runlevel [!$RUNLEVEL] export RUNLEVEL export PREVLEVEL console output env INIT_VERBOSE task exec /etc/init.d/rc $RUNLEVEL Let's suppose we currently are in runlevel 2 and the rc job is stopped (that is exactly the situation after booting my box and logging in via SSH). Now, let's assume that the system switches to runlevel 3, for example due to a command like "telinit 3" given by root. What will happen to the rc job? Obviously, the rc job will be started since it is currently stopped and the event runlevel 3 is matching the start events. But from now on, things are unclear to me: According to the manual $RUNLEVEL evaluates to the new runlevel when the job is started (that means 3 in our example). Therefore, the next stanza "stop on runlevel [!$RUNLEVEL]" translates to "stop on runlevel [!3]"; that means we have a first stanza which will trigger the job, but the second stanza will never stop the job and seems to be useless. Since I know that the Ubuntu / Upstart people won't do useless things, I must be heavily misunderstanding something. I would be grateful for any explanation. While trying to understand this, an additional question came to my mind. If I had contradicting start and stop triggers, for example start on foo stop on foo what would happen? I swear I never will do that, but I am nevertheless very interested in how Upstart handles that on the theoretical level. Thank you very much! Editing the question as a reaction on geekosaur's first answer: I can see the parallelism, but it is not that easy (at least, not to me). Let's assume the job aurrently is still running, and a new runlevel event comes in (of course, the new runlevel is different from the current one). Then, the following should happen: 1) The job is single instance. That means that "start on ..." won't be triggered since the job is currently running; $RUNLEVEL is not touched. 2) "stop on ..." will be triggered since the new runlevel is different from $RUNLEVEL, so the job will be aborted. 3) Now, the job is stopped and waiting. I can't see how it is restarted with the new runlevel. AFAIK, initctl emits events only once, so "start on ..." won't be triggered and the new runlevel won't be entered. I know that I still misunderstanding something, and I am grateful for explanations. Thank you very much!

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  • Join the SPARC Go To Market Webinar on June 21st

    - by swalker
    Please join the World Wide webinar focused on SPARC, and designed to provide insights and selling guidance, at 5 p.m. CET on Thursday, June 21. The speaker, Bud Koch, Sr Principal Product Marketing Director will focus on SPARC / T4 Marketing: with a review of current assets and where we are going into FY13.  Details about the meeting can be found here. Please plan on joining 10 minutes before the scheduled start time. If you are not able to participate in real time, a replay will be available shortly afterward.

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  • Join the SPARC Go To Market Webinar on June 21st

    - by Cinzia Mascanzoni
    Please join the World Wide webinar focused on SPARC, and designed to provide insights and selling guidance, at 5 p.m. CET on Thursday, June 21. The speaker, Bud Koch, Sr Principal Product Marketing Director will focus on SPARC / T4 Marketing: with a review of current assets and where we are going into FY13.  Details about the meeting can be found here. Please plan on joining 10 minutes before the scheduled start time. If you are not able to participate in real time, a replay will be available shortly afterward.

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  • Upstart: How does rc job work / order of (contradicting) "start on ..." and "stop on ..." stanzas

    - by Binarus
    Hi, I just can't understand how Upstart's rc job definition in Natty 11.04 works. To illustrate the problem, here is the definition (empty lines and comments are left out): start on runlevel [0123456] stop on runlevel [!$RUNLEVEL] export RUNLEVEL export PREVLEVEL console output env INIT_VERBOSE task exec /etc/init.d/rc $RUNLEVEL Let's suppose we currently are in runlevel 2 and the rc job is stopped (that is exactly the situation after booting my box and logging in via SSH). Now, let's assume that the system switches to runlevel 3, for example due to a command like "telinit 3" given by root. What will happen to the rc job? Obviously, the rc job will be started since it is currently stopped and the event runlevel 3 is matching the start events. But from now on, things are unclear to me: According to the manual $RUNLEVEL evaluates to the new runlevel when the job is started (that means 3 in our example). Therefore, the next stanza "stop on runlevel [!$RUNLEVEL]" translates to "stop on runlevel [!3]"; that means we have a first stanza which will trigger the job, but the second stanza will never stop the job and seems to be useless. Since I know that the Ubuntu / Upstart people won't do useless things, I must be heavily misunderstanding something. I would be grateful for any explanation. While trying to understand this, an additional question came to my mind. If I had contradicting start and stop triggers, for example start on foo stop on foo what would happen? I swear I never will do that, but I am nevertheless very interested in how Upstart handles that on the theoretical level. Thank you very much! Editing the question as a reaction on geekosaur's first answer: I can see the parallelism, but it is not that easy (at least, not to me). Let's assume the job aurrently is still running, and a new runlevel event comes in (of course, the new runlevel is different from the current one). Then, the following should happen: 1) The job is single instance. That means that "start on ..." won't be triggered since the job is currently running; $RUNLEVEL is not touched. 2) "stop on ..." will be triggered since the new runlevel is different from $RUNLEVEL, so the job will be aborted. 3) Now, the job is stopped and waiting. I can't see how it is restarted with the new runlevel. AFAIK, initctl emits events only once, so "start on ..." won't be triggered and the new runlevel won't be entered. I know that I still misunderstanding something, and I am grateful for explanations. Thank you very much!

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  • How Microsoft Market DotNet?

    - by Fendy
    I just read an Joel's article about Microsoft's breaking change (non-backwards compatibility) with dot net's introduction. It is interesting and explicitly reflected the condition during that time. But now almost 10 years has passed. The breaking change It is mainly on how bad is Microsoft introducing non-backwards compatibility development tools, such as dot net, instead of improving the already-widely used asp classic or VB6. As much have known, dot net is not natively embedded in windows XP (yes in vista or 7), so in order to use the .net apps, you need to install the .net framework of over 300mb (it's big that day). However, as we see that nowadays many business use .net as their main development tools, with asp.net or mvc as their web-based applications. C# nowadays be one of tops programming languages (the most questions in stackoverflow). The more interesing part is, win32api still alive even there is newer technology out there (and still widely used). Imagine if microsoft does not introduce the breaking change, there will many corporates still uses asp classic or vb-based applications (there still is, but not that much). There are many corporates use additional services such as azure or sharepoint (beside how expensive is it). Please note that I also know there are many flagships applications (maybe adobe's and blizzard's) still use C-based or older language and not porting to newer high-level language. The question How can Microsoft persuade the users to migrate their old applications into dot net? As we have known it is very hard and give no immediate value when rewrite the applications (netscape story), and it is very risky. I am more interested in Microsoft's way and not opinion such as "because dot net is OOP, or dot net is dll-embedable, etc". This question may be constructive, as the technology is vastly changes over times lately. As we can see, Microsoft changes Asp.Net webform to MVC, winform is legacy now, it is starting to change to use windows store rather than basic-installment, touchscreen and later on we will have see-through applications such as google class. And that will be breaking changes. We will need to account portability as an issue nowadays. We will need other than just mere technology choice, but also migration plans. Even maybe as critical as we might need multiplatform language compiler, as approached by Joel's Wasabi. (hey, I read his articles too much!)

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  • Flash Analytics and the Increased Market Demand

    Before you set your mind on knowing flash analytics, it is essential to understand what gave rise to its importance. Information technology has always been one of the most powerful pillars of the de... [Author: Abel Nickson - Computers and Internet - April 05, 2010]

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