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• correct way to implement auth/acl in mvc

  - by WiseStrawberry

  I am looking into making a correctly laid out MVC auth/acl system. I think I want the authentication of a user (and the session handling) to be seperate from the ACL system. (I don't know why but this seems a good idea from the things I've read) What does mvc have to do with this question you ask? Because I wish for the application to be well integrated with my acl. An example of a controller (CodeIgniter) <?php class forums extends MX_Controller { $allowed = array('users', 'admin'); $need_login = true; function __construct() { //example of checking if logged in. if($this->auth->logged_in() && $this->auth->is_admin()) { echo "you're logged in!"; } } public function add_topic() { if($this->auth->allowed('add_topic') { //some add topic things. } else { echo 'not allowed to add topic'; } } } ?> My thoughts $this->auth would be autoloaded in the system. I would like to check the $allowed array against the user currently (not) logged in and react accordingly. Is this a good way of doing things? I haven't seen much literature on mvc integration and auth. I want to make things as easy as possible.

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• Can't login to Unity 3d after enabling Xinerama for a short moment

  - by Amir Adar

  Today I connected a second monitor to my computer. I set it up using nVidia's control panel, and all was working quite well, so I figured it won't be a problem to try Xinerama, just to see the difference between that and twinview. After enabling Xinerama and restarting the X session, I saw that I was logged into a Unity 2d session. I thought it was a problem with Xinerama, so I switched back to twinview, but it still logged me into Unity 2d. I tried disconnecting the second monitor, no luck: still Unity 2d. I tried changing GPU drivers and installing drivers from a separate ppa, and still I was logged into Unity 2d. Up until this point, I didn't have any problem logging into Unity 3d. It only happened after I tried using Xinerama. I should note that I was doing all this while updates were going on in the background, so it could be something related to that, though I can't imagine what (I tried booting with another kernel, but no luck). So what exactly happened? Did changing the mode to Xinerama triggered some other changes that I'm not aware of? Did these updates cause a certain malfunction in the driver? Is it something else?

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• JQueryMobile - Problems with dialog boxes [closed]

  - by Richard van Hees

  I'm programming in JQueryMobile, but I can't seem to get some things as I want. First it's good to tell I am mostly programming in a multi-page template. I have a login function in the web based app. The idea is that the user sees he's not logged in and the user can click on the button to log in. A dialog box pops up, in which the user can enter his credentials. This dialog box is in front of the previous page, in my case just index.php. The page for profile is at profile.php#profile. In this case the url for the dialog box is index.php#profile&ui-state=dialog. Don't ask me why, that's how JQueryMobile works, I guess. Anyway, after the user clicks on 'Login' in the pop-up, I want a new dialog to pop-up in which it says you are logged in and I want the content of the page behind it (index.php#profile) to refresh. Of course I want this all to move very smooth and no refreshing of the whole page, to prevent loading time and thus a blank screen for a second. In short: User not logged in Clicks on login Dialog pops up with form Clicks login New dialog pops up with 'success' (or whatever) in the same style as the previous dialog Clicks ok Page behind the dialogues has been refreshed without user noticing Also another thing that doesn't really work out for me: I can't seem to get a dialog to pop up, triggered by an action in another dialog. It just appears as a normal page.

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• What is the correct way to implement Auth/ACL in MVC?

  - by WiseStrawberry

  I am looking into making a correctly laid out MVC Auth/ACL system. I think I want the authentication of a user (and the session handling) to be separate from the ACL system. (I don't know why but this seems a good idea from the things I've read.) What does MVC have to do with this question you ask? Because I wish for the application to be well integrated with my ACL. An example of a controller (CodeIgniter): <?php class forums extends MX_Controller { $allowed = array('users', 'admin'); $need_login = true; function __construct() { //example of checking if logged in. if($this->auth->logged_in() && $this->auth->is_admin()) { echo "you're logged in!"; } } public function add_topic() { if($this->auth->allowed('add_topic') { //some add topic things. } else { echo 'not allowed to add topic'; } } } ?> My thoughts $this->auth would be autoloaded in the system. I would like to check the $allowed array against the user currently (not) logged in and react accordingly. Is this a good way of doing things? I haven't seen much literature on MVC integration and Auth. I want to make things as easy as possible.

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• Update Boolean attributes from another controller

  - by sidonstackoverflow

  I have Users controller and session controller . I want to update one user attribute from session controller . How can i do that ?? I am currently using rails 4.0 . Users controller: class UsersController < ApplicationController def show if Spec.find_by_user_id params[:id] @user = User.find(params[:id]) @spec = Spec.find_by_user_id params[:id] else if params[:id] == session[:id] redirect_to spec_edit_path(params[:id]) else redirect_to(community_index_path, {:notice => "Sorry there was an error"}) end end end def index end def new @user = User.new end def create @user = User.new(user_params) if @user.save flash[:success] = "Welcome buddy !" redirect_to @user else render 'new' end end private def user_params params.require(:user).permit(:name, :email, :password, :password_confirmation) end end Sessions Controller : class SessionsController < ApplicationController def new end def create user = User.find_by(email: params[:session][:email]) if user && user.authenticate(params[:session][:password]) session[:user_id] = user.id User.update(user.status, 'true') redirect_to root_url, :notice => 'You successfully logged in ' else flash.now[:error] = 'Invalid email/password combination' # Not quite right! render 'new' end end def destroy session[:user_id] = nil redirect_to root_url, :notice => 'You successfully logged out ' end end In above code when User logged in i just want to update my boolean column status at users table from sessions controller , but i failed . I am thankful to whom would like to answer my question !

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• Managing access to multiple linux system

  - by Swartz

  A searched for answers but have found nothing on here... Long story short: a non-profit organization is in dire need of modernizing its infrastructure. First thing is to find an alternatives to managing user accounts on a number of Linux hosts. We have 12 servers (both physical and virtual) and about 50 workstations. We have 500 potential users for these systems. The individual who built and maintained the systems over the years has retired. He wrote his own scripts to manage it all. It still works. No complaints there. However, a lot of the stuff is very manual and error-prone. Code is messy and after updates often needs to be tweaked. Worst part is there is little to no docs written. There are just a few ReadMe's and random notes which may or may not be relevant anymore. So maintenance has become a difficult task. Currently accounts are managed via /etc/passwd on each system. Updates are distributed via cron scripts to correct systems as accounts are added on the "main" server. Some users have to have access to all systems (like a sysadmin account), others need access to shared servers, while others may need access to workstations or only a subset of those. Is there a tool that can help us manage accounts that meets the following requirements? Preferably open source (i.e. free as budget is VERY limited) mainstream (i.e. maintained) preferably has LDAP integration or could be made to interface with LDAP or AD service for user authentication (will be needed in the near future to integrate accounts with other offices) user management (adding, expiring, removing, lockout, etc) allows to manage what systems (or group of systems) each user has access to - not all users are allowed on all systems support for user accounts that could have different homedirs and mounts available depending on what system they are logged into. For example sysadmin logged into "main" server has main://home/sysadmin/ as homedir and has all shared mounts sysadmin logged into staff workstations would have nas://user/s/sysadmin as homedir(different from above) and potentially limited set of mounts, a logged in client would have his/her homedir at different location and no shared mounts. If there is an easy management interface that would be awesome. And if this tool is cross-platform (Linux / MacOS / *nix), that will be a miracle! I have searched the web and so have found nothing suitable. We are open to any suggestions. Thank you. EDIT: This question has been incorrectly marked as a duplicate. The linked to answer only talks about having same homedirs on all systems, whereas we need to have different homedirs based on what system user is currently logged into(MULTIPLE homedirs). Also access needs to be granted only to some machinees not the whole lot. Mods, please understand the full extent of the problem instead of merely marking it as duplicate for points...

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• Silverlight RIA Services - how to do Windows Authentication?

  - by Gustavo Cavalcanti

  I am building my first Silverlight 3 + RI Services application and need some help. It will be deployed in an controlled corporate intranet, 100% windows clients. I have started from the Silverlight Business Application template. These are my requirements: Upon launch the application needs to recognize the currently logged-in user. The application needs to have access to other properties of the user in AD, such as email, full name, and group membership. Group membership is used to grand certain features in the application. A "login as a different user" link is to be always available - Some machines are available throughout the enterprise, logged-in as a certain generic user (verified by the absence of certain membership groups). In this case one can enter credentials and log in (impersonate) to the application as a user different from the one already logged-into the machine. This user is to be used in service calls I have modified the following in the default Business Application template: App.xaml: appsvc:WindowsAuthentication instead of the default FormsAuthentication Web.config: authentication mode="Windows" With these modifications I resolve requirement #1 (get the currently logged-in user). But when I examine RiaContext.Current.User, I don't have access to other properties from AD, such as group memberships. How can I achieve my other requirements? Thanks for your help.

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• SQL Query: How to determine "Seen during N hour" if given two DateTime time stamps?

  - by efess

  Hello all. I'm writing a statistics application based off a SQLite database. There is a table which records when users Login and Logout (SessionStart, SessionEnd DateTimes). What i'm looking for is a query that can show what hours user have been logged in, in sort of a line graph way- so between the hours of 12:00 and 1:00AM there were 60 users logged in (at any point), between the hours of 1:00 and 2:00AM there were 54 users logged in, etc... And I want to be able to run a SUM of this, which is why I can't bring the records into .NET and iterate through them that way. I've come up with a rather primative approach, a subquery for each hour of the day, however this approach has proved to be slow and slow. I need to be able to calculate this for a couple hundred thousand records in a split second.. SELECT case when (strftime('%s',datetime(date(sessionstart), '+0 hours')) > strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+0 hours')) < strftime('%s',sessionend)) OR (strftime('%s',datetime(date(sessionstart), '+1 hours')) > strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+1 hours')) < strftime('%s',sessionend)) OR (strftime('%s',datetime(date(sessionstart), '+0 hours')) < strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+1 hours')) > strftime('%s',sessionend)) then 1 else 0 end as hour_zero, ... hour_one, ... hour_two, ........ hour_twentythree FROM UserSession I'm wondering what better way to determine if two DateTimes have been seen durring a particular hour (best case scenario, how many times it has crossed an hour if it was logged in multiple days, but not necessary)? The only other idea I had is have a "hour" table specific to this, and just tally up the hours the user has been seen at runtime, but I feel like this is more of a hack than the previous SQL. Any help would be greatly appreciated!

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• Have to login twice. PHP sessions and login troubles with Chrome and Opera.

  - by Robert

  The problem I am encountering is that for my login form I have to login twice for the session to register properly, but only in Chrome (my version is 4.0.249.89) and Opera (my version is 10.10). Here is the stripped down code that I am testing on: Login Page: session_start(); $_SESSION['user_id'] = 8; $_SESSION['user_name'] = 'Jim'; session_write_close(); header('Location: http://www.my-domain-name.com/'); exit(); Home Page: session_start(); if ( isset($_SESSION['user_id']) ) { echo "You are logged in!"; } else { echo "You are NOT logged in!"; } Logout Page: session_start(); session_unset(); session_destroy(); header('Location: http://www.my-domain-name.com/'); exit(); Currently, under a fresh load with no cookies, if I go to my-domain-name.com/login/ it will redirect to the home page and say "You are NOT logged in!" but if I go there again it will say "You are logged in!". Any ideas? Thanks for your help.

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• Cannot exit in CodeIgniter constructor

  - by gzg

  I'm basically trying a session control. If the user is logged in, it's ok to move on. But if he's not logged in, then it will show a log-in screen and then die. However, when I use die or exit in the constructor, it does not show the log-in screen; it immediately dies. The code is as following: private $username = null; private $mongoid = null; private $neoid = null; public function __construct(){ parent::__construct(); // session to global $this->username = $this->session->userdata( 'username'); $this->mongoid = $this->session->userdata( 'mongoid'); $this->neoid = $this->session->userdata( 'neoid'); // check if user is logged in if( $this->username == "" || empty( $this->username)){ $this->load->view( 'access/login'); die; } } It shows the log-in page if die is not written there, but with die, it does not show. Why do I want to use die? Because if I don't use, it moves on the index function and I don't want it to execute index function if the user is not logged in. What is wrong here? What should I use to stop executing?

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• I have a problem with mysql and php

  - by neo skosana

  Hi I have a problem, this is my code: $db = new mysqli("localhost", "root", "", "blah"); $result1 = $db-query("select * from c_register where email = '$eml' and password = '$pass'"); if($result1-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'client'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result2 = $db-query("select * from b_register where email = '$eml' and password = '$pass'"); if($result2-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'business'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result3 = $db-query("select * from g_register where email = '$eml' and password = '$pass'"); if($result3-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'employee'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result4 = $db-query("select * from k_register where email = '$eml' and password = '$pass'"); if($result4-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'super'; promptUser("You have successfully logged in!!!","index.php"); } else { promptUser("Username/Password do not match. Please try again!!!",""); } Funny enough this code works, but I no that I went about it the wrong way. I am new with php and mysql, so please help. I also tried e.gresult4->free(); for all the variable that save the data, and I got this error: Fatal error: Call to a member function free() on a non-object in...

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• Saving form values to database after a user logs in

  - by redfalcon

  Hi. We have a form with ratings to submit for a certain restaurant. After the user has entered some values and wants to submit them, we check whether the user is logged in or not. If not, we display a login form and let the user put in his account data and redirect him to the restaurant he wanted to submit a rating for. The problem is, that after he successfully logged in himself, the submitted values are not saved to the database (which works fine if the user is already logged in). So I wondered if it is possible, to somehow save the data although the user is not logged in. I thought of maybe saving the filled values in a variable and have then automatically re-entered after we redirected the user. But I guess this wont work because we use before_filter :login_required, :only => [ :create ] So we couldnt even access the filled in values, since we display the login-form before the method has processed the values in the form, right? Any idea how we can make rails to save the values or at least have them automatically re-entered to the form? Thanks!

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• How to use ULS in SharePoint 2010 for Custom Code Exception Logging?

  - by venkatx5

  What is ULS in SharePoint 2010? ULS stands for Unified Logging Service which captures and writes Exceptions/Logs in Log File(A Plain Text File with .log extension). SharePoint logs Each and every exceptions with ULS. SharePoint Administrators should know ULS and it's very useful when anything goes wrong. but when you ask any SharePoint 2007 Administrator to check log file then most of them will Kill you. Because read and understand the log file is not so easy. Imagine open a plain text file of 20 MB in NotePad and go thru line by line. Now Microsoft developed a tool "ULS Viewer" to view those Log files in easily readable format. This tools also helps to filter events based on exception priority. You can read on this blog to know in details about ULS Viewer . Where to get ULS Viewer? ULS Viewer is developed by Microsoft and available to download for free. URL : http://code.msdn.microsoft.com/ULSViewer/Release/ProjectReleases.aspx?ReleaseId=3308 Note: Eventhought this tool developed by Microsoft, it's not supported by Microsoft. Means you can't support for this tool from Microsoft and use it on your own Risk. By the way what's the risk in viewing Log Files?! How to use ULS in SharePoint 2010 Custom Code? ULS can be extended to use in user solutions to log exceptions. In Detail, Developer can use ULS to log his own application errors and exceptions on SharePoint Log files. So now all in Single Place (That's why it's called "Unified Logging"). Well in this article I am going to use Waldek's Code (Reference Link). However the article is core and am writing container for that (Basically how to implement the code in Detail). Let's see the steps. Open Visual Studio 2010 -> File -> New Project -> Visual C# -> Windows -> Class Library -> Name : ULSLogger (Make sure you've selected .net Framework 3.5)   In Solution Explorer Panel, Rename the Class1.cs to LoggingService.cs   Right Click on References -> Add Reference -> Under .Net tab select "Microsoft.SharePoint"   Right Click on the Project -> Properties. Select "Signing" Tab -> Check "Sign the Assembly".   In the below drop down select <New> and enter "ULSLogger", uncheck the "Protect my key with a Password" option.   Now copy the below code and paste. (Or Just refer.. :-) ) using System; using System.Collections.Generic; using System.Linq; using System.Text; using Microsoft.SharePoint; using Microsoft.SharePoint.Administration; using System.Runtime.InteropServices; namespace ULSLogger { public class LoggingService : SPDiagnosticsServiceBase { public static string vsDiagnosticAreaName = "Venkats SharePoint Logging Service"; public static string CategoryName = "vsProject"; public static uint uintEventID = 700; // Event ID private static LoggingService _Current; public static LoggingService Current {  get   {    if (_Current == null)     {       _Current = new LoggingService();     }    return _Current;   } }private LoggingService() : base("Venkats SharePoint Logging Service", SPFarm.Local) {}protected override IEnumerable<SPDiagnosticsArea> ProvideAreas() { List<SPDiagnosticsArea> areas = new List<SPDiagnosticsArea>  {   new SPDiagnosticsArea(vsDiagnosticAreaName, new List<SPDiagnosticsCategory>    {     new SPDiagnosticsCategory(CategoryName, TraceSeverity.Medium, EventSeverity.Error)    })   }; return areas; }public static string LogErrorInULS(string errorMessage) { string strExecutionResult = "Message Not Logged in ULS. "; try  {   SPDiagnosticsCategory category = LoggingService.Current.Areas[vsDiagnosticAreaName].Categories[CategoryName];   LoggingService.Current.WriteTrace(uintEventID, category, TraceSeverity.Unexpected, errorMessage);   strExecutionResult = "Message Logged"; } catch (Exception ex) {  strExecutionResult += ex.Message; } return strExecutionResult; }public static string LogErrorInULS(string errorMessage, TraceSeverity tsSeverity) { string strExecutionResult = "Message Not Logged in ULS. "; try  {  SPDiagnosticsCategory category = LoggingService.Current.Areas[vsDiagnosticAreaName].Categories[CategoryName];  LoggingService.Current.WriteTrace(uintEventID, category, tsSeverity, errorMessage);  strExecutionResult = "Message Logged";  } catch (Exception ex)  {   strExecutionResult += ex.Message;   } return strExecutionResult;  } } }   Just build the solution and it's ready to use now. This ULS solution can be used in SharePoint Webparts or Console Application. Lets see how to use it in a Console Application. SharePoint Server 2010 must be installed in the same Server or the application must be hosted in SharPoint Server 2010 environment. The console application must be set to "x64" Platform target.   Create a New Console Application. (Visual Studio -> File -> New Project -> C# -> Windows -> Console Application) Right Click on References -> Add Reference -> Under .Net tab select "Microsoft.SharePoint" Open Program.cs add "using Microsoft.SharePoint.Administration;" Right Click on References -> Add Reference -> Under "Browse" tab select the "ULSLogger.dll" which we created first. (Path : ULSLogger\ULSLogger\bin\Debug\) Right Click on Project -> Properties -> Select "Build" Tab -> Under "Platform Target" option select "x64". Open the Program.cs and paste the below code. using System; using System.Collections.Generic; using System.Linq; using System.Text; using Microsoft.SharePoint.Administration; using ULSLogger; namespace ULSLoggerClient {  class Program   {   static void Main(string[] args)     {     Console.WriteLine("ULS Logging Started.");     string strResult = LoggingService.LogErrorInULS("My Application is Working Fine.");      Console.WriteLine("ULS Logging Info. Result : " + strResult);     string strResult = LoggingService.LogErrorInULS("My Application got an Exception.", TraceSeverity.High);     Console.WriteLine("ULS Logging Waring Result : " + strResult);      Console.WriteLine("ULS Logging Completed.");      Console.ReadLine();     }   } } Just build the solution and execute. It'll log the message on the log file. Make sure you are using Farm Administrator User ID. You can play with Message and TraceSeverity as required. Now Open ULS Viewer -> File -> Open From -> ULS -> Select First Option to open the default ULS Log. It's Uls RealTime and will show all log entries in readable table format. Right Click on a row and select "Filter By This Item". Select "Event ID" and enter value "700" that we used in the application. Click Ok and now you'll see the Exceptions/Logs which logged by our application.   If you want to see High Priority Messages only then Click Icons except Red Cross Icon on the Toolbar. The tooltip will tell what's the icons used for.

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• Login box not shown on Ubuntu

  - by Alexandre

  Hi, I've installed Ubuntu 10.04 (64bit) as a guest OS in VirtualBox, using Windows7 Professional (64bit) as host. After Ubuntu install, I did installed Xfce4 (sudo apt-get install xfce4). Logged in using a Xfce session, and when I logged out, I couldn't see the login box anymore, only the regular gnome background from login screen. Then I restarted the virtual machine, and now I'm not able to see the login box anymore, only the gnome background. Does someone knows how to solve this? Thanks in advance

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• nginx 404 logs to all virtualhosting logs

  - by Dr.D

  I am using nginx and i have two sites running: site1 = /1/access.log site2 = /2/access.log when a user get 404 images not found on site2 nginx writes to access.log of site1 & site2 reporting the not found error, i tried everything to get separated logs without luck, i want everything that happen on site1 logged on /1/access.log and everything that happens on site2 logged on /2/access.log any help ?

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• Log requests in apache upon arrival

  - by Patrick Cornelissen

  Is it possible to log requests in the apache when they arrive not when they have been processed? We have a pretty big web based application and the way it's currently logged is sometimes confusing to read, because each request with it's subrequests is logged "upside down", because apache logs the request after it has been processed, so the initial request is the last entry for this "query". We're wondering if there is a chance to log on arrival?!

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• Why would Gwibber feeds be stale?

  - by JohnMcG

  After I installed Ubuntu 10.4, I tried out Gwibber and liked it very much. Next time I logged in, I had the same messages that were there when I logged off, and nothing I did (e.g. unsubscribing/re-subsribing) helped. Anyone know what I could be doing wrong?

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• Windows server 2008 r2 unlimiting the allowed number of logon to a single user

  - by Hipno

  Hello, i got a server running windows server 2008, and i got a user which everyone can connect to via Remote desktop! when 2 users a are logged to the user, it's fine. but when the 3 is logged on, it says one of the other 2 should loggoff! my question is, how i disable the limitation of concurrent logons to a single users? Thank you, i must say this is a great site.

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• Postfix / Dovecot and Email Retrieval

  - by Eric J.

  I have setup Postfix and Dovecot on an Ubuntu box following the instructions http://www.exratione.com/2012/05/a-mailserver-on-ubuntu-1204-postfix-dovecot-mysql/ I can see that email is being delivered to and accepted by the server, but the email is not available for retrieval via POP3. What could be missing in my configuraton? It seems that email is not being properly handed off to Dovecot. Here are what I believe are the relevant /var/log/mail.log entries for an attempt to send email from another domain (hosted by Gmail) to the domain I have setup: Logged during SMTP connection postfix/smtpd[14689]: connect from mail-vb0-f50.google.com[209.85.212.50] postfix/smtpd[14689]: Anonymous TLS connection established from mail-vb0-f50.google.com[209.85.212.50]: TLSv1 with cipher ECDHE-RSA-RC4-SHA (128/128 bits) postfix/smtpd[14689]: 5782740ACF: client=mail-vb0-f50.google.com[209.85.212.50] postfix/cleanup[14696]: 5782740ACF: message-id=<CAEjmKcjHnTY4yk=3QXoNrD76=04g-s9utPguTFB02Fx53GMPmw@mail.gmail.com> postfix/qmgr[14687]: 5782740ACF: from=<[email protected]>, size=1947, nrcpt=1 (queue active) postfix/smtpd[14702]: connect from mail.destinationdomain.com[127.0.0.1] postfix/smtpd[14702]: 2940A41AA9: client=mail.destinationdomain.com[127.0.0.1] postfix/cleanup[14696]: 2940A41AA9: message-id=<CAEjmKcjHnTY4yk=3QXoNrD76=04g-s9utPguTFB02Fx53GMPmw@mail.gmail.com> postfix/qmgr[14687]: 2940A41AA9: from=<[email protected]>, size=2450, nrcpt=1 (queue active) amavis[21309]: (21309-02) Passed CLEAN, [209.85.212.50] <[email protected]> -> <[email protected]>, Message-ID: <CAEjmKcjHnTY4yk=3QXoNrD76=04g-s9utPguTFB02Fx53GMPmw@mail.gmail.com>, mail_id: W52ZB8FAAA+8, Hits: -0.101, size: 1946, queued_as: 2940A41AA9, [email protected], 784 ms postfix/smtpd[14702]: disconnect from mail.destinationdomain.com[127.0.0.1] postfix/smtp[14698]: 5782740ACF: to=<[email protected]>, relay=127.0.0.1[127.0.0.1]:10024, delay=1.1, delays=0.29/0.01/0/0.79, dsn=2.0.0, status=sent (250 2.0.0 from MTA([127.0.0.1]:10025): 250 2.0.0 Ok: queued as 2940A41AA9) postfix/qmgr[14687]: 5782740ACF: removed dovecot: lda([email protected]): msgid=<CAEjmKcjHnTY4yk=3QXoNrD76=04g-s9utPguTFB02Fx53GMPmw@mail.gmail.com>: saved mail to INBOX postfix/pipe[14703]: 2940A41AA9: to=<[email protected]>, relay=dovecot, delay=0.08, delays=0.02/0.02/0/0.04, dsn=2.0.0, status=sent (delivered via dovecot service) postfix/qmgr[14687]: 2940A41AA9: removed Logged during POP3 retrieval attempts dovecot: pop3-login: Login: user=<[email protected]>, method=PLAIN, rip=209.85.220.135, lip=10.195.83.10, mpid=14706 dovecot: pop3([email protected]): Disconnected: Logged out top=0/0, retr=1/2557, del=1/1, size=2540 postfix/smtpd[14689]: disconnect from mail-vb0-f50.google.com[209.85.212.50] dovecot: pop3-login: Login: user=<[email protected]>, method=PLAIN, rip=209.85.212.31, lip=10.195.83.10, mpid=14708 dovecot: pop3([email protected]): Disconnected: Logged out top=0/0, retr=0/0, del=0/0, size=0

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• finger for Windows

  - by tearman

  Ok probably a bit of an odd question, but is there a way to enable "finger" like functionality on a Windows network? we'd basically like the ability to find out where a user is logged in on a network and possibly which users are logged onto a workstation if possible. We're currently on AD2003 functional level, with the intent of going to AD2008 very soon, so compatibility in that arena is preferable.

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• Clearing cmd.exe memory or cache

  - by Abs

  The main question is how do I clear the command prompts memory or cache. I ran this on cmd.exe svn info <URL> Which prompted me a for a username and password which I entered. I then logged off and logged back in immediately and I entered that same command and I wasn't asked for a username and password. I want to clear this to test something without restarting my server! How can I do this?

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• How to force disconnect users from a box?

  - by LikeToCode

  how do you disconnect an active user logged in to a box? There should be a command line tool that comes with Windows, but I forgot it's name. It lists all the users logged in to a box and you can force disconnect of some, because, for example, you want to Remote Desktop to it and there's too many users.

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• Induce Mac graphical login from SSH

  - by Ben Alpert

  The title says it all. Is there a way to make the loginwindow process start a user session by running a command when remotely logged in via SSH as an admin on Mac OS X? When the machine is at the login window (no user is currently logged in), I want it to open up a user's session as if I had clicked on the username and entered a password. Solutions that don't involve scripting the GUI are highly preferred, but this Apple KB page may be of interest for those who go that route.

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• How to remote desktop into a sleeping workstation?

  - by Jake

  If an office workstation is turned on, either in wake/sleep/logged off/logged in mode, is it possible to remote desktop into that workstation given that I have full admin priviledge to the Windows Server and Active Directory governing the authentication? What settings is required to check the status of the workstation as well as remote desktop sucessfully? Thanks. NB: There is no one in office. I connect via VPN to the Windows Sever.

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• Logging commands executed by remote shell scripts

  - by user145836

  I've noticed that when running a script that connects to a number of our servers (to essentially run batch commands) that the commands aren't logged in the user's .sh_history or .bash_history files. Is there a place where this is logged (assuming the script itself isn't doing the logging and I'm not tee'ing the output anywhere)? I'm talking specifically about AIX, but I would assume this question applies to all the *nix flavors. Thanks!

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