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  • calculate business days including holidays

    - by ran
    i need to calculate the business days between two dates. ex : we have holiday(in USA) on july4th. so if my dates are date1 = 07/03/2012 date2 = 07/06/2012 no of business days b/w these dates should be 1 since july4th is holiday. i have a below method to calclulate the business days which will only counts week ends but not holidays. is there any way to calculate holidays also....please help me on this. public static int getWorkingDaysBetweenTwoDates(Date startDate, Date endDate) { Calendar startCal; Calendar endCal; startCal = Calendar.getInstance(); startCal.setTime(startDate); endCal = Calendar.getInstance(); endCal.setTime(endDate); int workDays = 0; //Return 0 if start and end are the same if (startCal.getTimeInMillis() == endCal.getTimeInMillis()) { return 0; } if (startCal.getTimeInMillis() > endCal.getTimeInMillis()) { startCal.setTime(endDate); endCal.setTime(startDate); } do { startCal.add(Calendar.DAY_OF_MONTH, 1); if (startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SATURDAY && startCal.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY) { ++workDays; } } while (startCal.getTimeInMillis() < endCal.getTimeInMillis()); return workDays; }

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  • Java Days & Bookings

    - by sys_debug
    Ok this is an extension of a question I asked about earlier yet this is the next step that is unclear to me. Everything else will be ready and this part is driving me mad! some members provided great help and I already made progress with that info, but this is just another obstacle. I am creating a booking object (as was suggested) that will have a start date and end date. each booking will also have a number of seats associated with it (that I require to reserve). The total available number of seats any given day 46 (as the total capacity of the hall is 46 seats). so in assumption that I have a booking to be made in the system, and start date is 1st jan and end date is 10th jan. The question is how can I check the remaining seats in all those days between the range to see if requested number could be hosted or not? and then when the second booking is made, it will have to see that the days in this range already have less than 46 and decrement further if possible to host the reservation. one of the members, and I appreciate his effort, gladly contributed a method to compare if this booking is after or before the existing bookings. The code provided is here: public boolean overlapsWithExisting(Booking booking) { final Date early = booking.getStart(); final Date late = booking.getEnd(); for(Booking existing : existingBookings) { if(!(early.isAfter(existing.getEnd() || late.isBefore(existing.getStart())) return true; } return false; } I just want to know how to associate 46 with each day and keep record of days that are decremented by bookings. Thanks and reallllllly appreciated :D

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  • Difference between two PHP times as years, months and days for PHP version 5.2

    - by Dominor Novus
    Forward: I've scanned through the existing questions/answers on this matter. This is not a duplicitous question; I cannot find a working solution from the accepted answers. The main questions/answers I've reviewed can be found here: How to calculate the difference between two dates using PHP? What I need: A calucalation of the difference between two dates expressed as years, months and days that works with PHP version: 5.2. <?php $current_date = date('d-M-Y'); $future_date = '2012-11-01'; ?> What I've tried: Most answers I find online don't seem to exact in that they don't factor in leap years. This highly rated answer won't work because DateTime-diff() is php 5.3+. This accepted answer results in (i.e. the second block of code aimed at PHP 5.2) results in the following being parsed: Array ( [y] = 25 [m] = 11 [d] = 7 [h] = 3 [i] = 15 [s] = 19 [invert] = 0 [days] = 9473 ) Array ( [y] = 25 [m] = 11 [d] = 7 [h] = 3 [i] = 15 [s] = 19 [invert] = 1 [days] = 9473 ) I can't tell if I've incorrectly applied the code or it's simply a case of me not knowing how to manipulate the array.

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  • Small standalone SQL database similar to access in the old days(ie file database)

    - by Ian
    Hi, I am looking for a easy to use and deploy sql type database i can ship with a desktop application. This will be a small application user's can download from my website. In the vb6 days, access was the common database for small desktop apps, what is my option these days? Looking at SQL CE it seems to have a quite a few limitations such as count(distinct) etc SQL express needs to be installed and running as a service (could i include the SQL express deployments in my deployment so the user doesn't even know its been installed? I assume size would then be an issue) SQL 2005/2008 is not an option due to size and licensing restrictions. I would like to use c#, wpf and entity framework. What would seem to be the best options based on your knowledge and experience? Thanks

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  • number of days in a period that fall within another period

    - by thomas
    I have 2 independent but contiguous date ranges. The first range is the start and end date for a project. Lets say start = 3/21/10 and end = 5/16/10. The second range is a month boundary (say 3/1/10 to 3/31/10, 4/1/10 to 4/30/10, etc.) I need to figure out how many days in each month fall into the first range. The answer to my example above is March = 10, April = 30, May = 16. I am trying to figure out an excel formula or VBA function that will give me this value. Any thoughts on an algorithm for this? I feel it should be rather easy but I can't seem to figure it out. I have a formula which will return TRUE/FALSE if ANY part of the month range is within the project start/end but not the number of days. That function is below. return month_start <= project_end And month_end >= project_start

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  • SQL Query That Should Return Least two days record

    - by Aryans
    I have a table "abc" where i store timestamp having multiple records let suppose 1334034000 Date:10-April-2012 1334126289 Date:11-April-2012 1334291399 Date:13-April-2012 I want to build a sql query where I can find at first attempt the records having last two day values and so second time the next two days . . . Example: Select *,dayofmonth(FROM_UNIXTIME(i_created)) from notes where dayofmonth(FROM_UNIXTIME(i_created)) > dayofmonth(FROM_UNIXTIME(i_created)) -2 order by dayofmonth(FROM_UNIXTIME(i_created)) this query returns all the records date wise but we need very most two days record. Please suggest accordingly. Thanks in advance

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  • Getting number of days between [NSDate date] and string @"2010-11-12"

    - by grobald
    Hello i have a question. in short: i need a function which receives [NSDate date] and string @"2010-11-12" and returns the amount of days between those two dates. more explanation: I need to store a date from a server in the format @"2010-11-12" in my NSUserdefaults. The meaning of this date is the expireDate of a feature in an iPhone App. Everytime i press on a button for this feature i need to check if the difference in days between the current time-[NSDate date] and @"2010-11-12" is greater than 0. That means tahat the feature is disabled. its making me crazy mabey its to dead simple.

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  • Run a pc on battery for 3 days?

    - by Zen 8000k
    I am looking for a low power, low end pc able to run 24/7 without overheating and a way to support it in case of power failure. Power failures can be up to 72 hours. The pc dosen't need a monitor or keyboard. A modem must also be protected in case of power failure. When i say low end, i don't mean crap. The cpu needs to be x86 and have at least 1k cpu in this chart: http://www.cpubenchmark.net/index.php What's the best way to do this?

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  • SOA &amp; BPM Integration Days February 23rd &amp; 24th 2011 D&uuml;sseldorf Germany

    - by Jürgen Kress
    The key German SOA Experts will present at the SOA & BPM Integration Days 2011 for all German SOA users it’s the key event in 2001, make sure you register today! Speakers include: Torsten Winterberg OPITZ Hajo Normann HP Guido Schmutz Trivadis Dirk Krafzig SOAPARK Niko Köbler OPITZ Clemens Utschig-Utschig Boehringer Ingelheim Nicolai Josuttis IT communication Bernd Trops SOPERA   Berthold Maier Oracle Deutschland Jürgen Kress Oracle EMEA The agenda is exciting for all SOA and BPA experts! See you in Düsseldorf Germany!   Es ist soweit: Die Entwickler Akademie und das Magazin Business Technology präsentieren Ihnen die ersten SOA, BPM & Integration Days! Das einzigartige Trainingsevent versammelt für Sie die führenden Köpfe im deutschsprachigen Raum rund um SOA,  BPM und Integration.  Zwei Tage lang erhalten Sie ohne Marketingfilter wertvolle Informationen, Erkenntnisse und  Erfahrungen aus der täglichen Projektarbeit. Sie müssen sich nur noch entscheiden, welche persönlichen Themenschwerpunkte Sie setzen möchten. Darüber hinaus bietet sich Ihnen die einmalige Chance, ihre Fragen und Herausforderungen mit den Experten aus der Praxis zu diskutieren. In den SOA, BPM & Integration Days profitieren Sie von der geballten Praxiserfahrung der Autorenrunde des SOA Spezial Magazins (Publikation des Software & Support Verlags), bekannter Buchautoren und langjährigen Sprechern der JAX-Konferenzen. Dieses Event sollten Sie auf keinen Fall verpassen!  Details und Anmeldung unter: www.soa-bpm-days.de For more information on SOA Specialization and the SOA Partner Community please feel free to register at www.oracle.com/goto/emea/soa (OPN account required) Blog Twitter LinkedIn Mix Forum Wiki Website Technorati Tags: SOA & BPM Integration Days,SOA,BPM,Hajo Normnn,Torsten Winterberg,Clemens Utschig-Utschig,Berthold Maier,Bernd Trops,Guido Schmutz,Nicolai Josuttis,Niko Köbler,Dirk Krafzig,Jürgen Kress,Oracle,Jax,Javamagazin,entwickler adademiem,business technology

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  • Postfix spool on ext3 optimiziations in >=linux-2.6.34 days

    - by Luke404
    Given the very specific nature of the subject (we're not talking about mailboxes, just the spool; we're not talking about other filesystems, just ext3; and so on...) and the maturity of the softwares involved (linux kernel, ext3fs, postfix) I'd think there should be a more or less agreed on set of best practices to filesystem related tuning. I'm trying to get a roundup of them: data=journal became the default in recent kernels (somewhere around 2.6.30 IIRC) so we should be ok with that Wietse Venema says atime must be on, but Postfix documentation recommendsnoatime while talking about the Incoming Queue. Does that mean that postfix needs atime on just for some queue directories and will benefit from noatime on the others? can we use noatime if we just don't use ETRN? filesystem can be mounted nodev,noexec,nosuid - no* won't prevent you from setting attributes (postfix uses exec attr) they just won't have any effect (we don't run anything from the spool) the fsync() issue cited by Wietse and/or the chattr -S are probably linked to sync/async options of ext3fs but I do not understand them enough. Mouting the filesystem with async option is equivalent to chattr -R -S the whole fs? Seems like it will increase performance, but will that pose a risk of "loss of mail after a system crash" or is it really "safe on /var/spool/postfix" ? would you tune anything else on postfix-2.6.x to work better on ext3 or do you leave defaults everywhere? is there a "best" linux I/O scheduler for this kind of workload (namely CFQ or deadline?) or that's something that will vary too much based on hardware configuration? would you tune anything else in the filesystem or in the kernel? anything else? References: Postfix Performance here on SF Postfix documentation about the Incoming Queue Wietse Venema in Best file system on [email protected] here Postfix and ext3 on [email protected] here and there

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  • Adding a date every few days

    - by Luke
    I have some code that generates fixtures, I am looking to add a fixture date to the code. $totalRounds = $teams - 1; $matchesPerRound = $teams / 2; $rounds = array(); for ($i = 0; $i < $totalRounds; $i++) { $rounds[$i] = array(); } for ($round = 0; $round < $totalRounds; $round++) { for ($match = 0; $match < $matchesPerRound; $match++) { $home = ($round + $match) % ($teams - 1); $away = ($teams - 1 - $match + $round) % ($teams - 1); // Last team stays in the same place while the others // rotate around it. if ($match == 0) { $away = $teams - 1; } $rounds[$round][$match] = "$user[$home]~$team[$home]@$user[$away]~$team[$away]"; } } $team is the amount of teams in the league. I want to add a variable for every 4 days, and for every round of fixtures generated, I want to add 4 days onto the previous round. For example, if today is 3rd may, i want 3rd may for first fixture, 7th may for second fixture, 11th may for third fixture. By fixture i mean round which includes a set of fixtures!

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  • Calculating a date when a date has been chosen by the number of days

    - by Andy
    I have three selection drop downs in a form comprising of day, month, year. Pretty standard. Ive omitted all the individual select options for the purposes of this question. <label for="start_date">Start Date<font class="required">*</font>:</label> <select name="place_booking[day_val]"> <select name="place_booking[month_val]"> <select name="place_booking[year_val]"> Underneath this i have a selection for the number of days the client wishes to stay at the letting. <label for="number_of_days">Number of Days<font class="required">*</font>:</label> <select name="place_booking[number_of_days]"> Underneath there is a space to display the departure date based on there two selections above. <label for="departure_date">Departure Date<font class="required">*</font>:</label> ? - this bit i would like to display the calculated date after the above is selected Any help would be grealty appreciated.

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  • count how many days within a date range are within another date range

    - by joko13
    From October 1st to March 31 the fee is $1 (season 1). From April 1st to September 30 the fee is $2 (season 2). How can I calculate the total fee of a given date range (user input) depending on how many days of this date range fall into season 1 and season 2? The following gives me the number of days of the user´s date range, but I have no idea how to test against season 1 or season 2: $user_input_start_date = getdate( $a ); $user_input_end_date = getdate( $b ); $start_date_new = mktime( 12, 0, 0, $user_input_start_date['mon'], $user_input_start_date['mday'], $user_input_start_date['year'] ); $end_date_new = mktime( 12, 0, 0, $user_input_end_date['mon'], $user_input_end_date['mday'], $user_input_end_date['year'] ); return round( abs( $start_date_new - $end_date_new ) / 86400 ); Thanks for your help! EDIT: Given that a date range starts and ends in 2012 or starts in 2012 and ends in 2013 alone gives me 10 different possibilities of in which season a date range can start and where it can end. There must be a better solution than iterating if/else and comparing dates over and over again for the following conditions: Date range is completely within season 1 Date range starts in season 1 and ends in season 2 Date range starts in season 1, spans across season 2 and ends in the second part of season 1 ... and so forth with "Starts in season 2", etc

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  • An array with values 4 days apart

    - by Luke
    I have a piece of code that generates soccer/football fixtures. The idea is that for every round of fixtures, the date will be 4 days further than the last round. So round one will be 3rd may, round two will be 7th may, round three 11th may, etc. I am not sure how to do this? The code that currently makes the fixtures are as follows: $totalRounds = $teams - 1; $matchesPerRound = $teams / 2; $rounds = array(); for ($i = 0; $i < $totalRounds; $i++) { $rounds[$i] = array(); } for ($round = 0; $round < $totalRounds; $round++) { for ($match = 0; $match < $matchesPerRound; $match++) { $home = ($round + $match) % ($teams - 1); $away = ($teams - 1 - $match + $round) % ($teams - 1); // Last team stays in the same place while the others // rotate around it. if ($match == 0) { $away = $teams - 1; } $rounds[$round][$match] = "$user[$home]~$team[$home]@$user[$away]~$team[$away]"; } } The teams would be the total users in the league. So if there are 8 teams, there will be 7 rounds. And i will want each round 4 days apart. And that date will be within each fixture within each round. Any further information needed just ask! Thanks, really stuck on this

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  • Disable Days in Jquery FullCalendar

    - by user297561
    I'm using FullCalendar as a large date picker with added features, and need to disable all Sundays and various other days throughout the year. Jquery UI date picker allows you to create methods for disabling dates. Is there a similar setup for FullCalendar?

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  • calculate number of working days on a rails form

    - by ash34
    I have two fields, 'from_date' and 'to_date' on my rails form. When a user enters the dates I have to display the number of working days i.e, exclude (sat, sun and a list of other official holidays in a database table). Is this something that should be done in the client side javascript Or is this something that should be done by making an ajax request to rails. Can you tell me how I can accomplish this. thanks much.

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