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  • Adding days to NSDate

    - by karthick
    I want add days to a date, I got many codes for this but none of them are working for me below shown is my code,please somebody help me to fix this issue int daysToAdd=[[appDlegateObj.selectedSkuData objectForKey:@"Release Time"] intValue]; NSTimeInterval secondsForFollowOn=daysToAdd*24*60*60; NSString *dateStr=[contentDic objectForKey:@"Date"]; NSDateFormatter *dateFormatter=[[NSDateFormatter alloc]init]; [dateFormatter setDateFormat:@"yyyy-MM-dd"]; NSDate *dateFromString=[[NSDate alloc]init]; dateFromString=[dateFormatter dateFromString:dateStr]; [dateFormatter release]; NSDate *date=[dateFromString dateByAddingTimeInterval:secondsForFollowOn];

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  • bat script to delete file older than 7 days

    - by Jessie
    hi guys i have a bat script in which gets all files in a folder and then converts this folder with its contents into a one RAR file. This script also adds the current date once it makes a copy and moves it this file into a backup folder, i am planning to have this bat file run by a windows scheduler task every day. My question is there a way to add into this cript to also delete all rar files older than 7 days in the backup folder? for /f "delims==" %%D in ('DIR D:\scripts /A /B /S') do ( "C:\Program Files\WinRAR\WinRAR.EXE" a -agyyyy-MM-dd -r "c:\backup\scripts.rar" "%%D" )

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  • Curl download image only if not older than 2 days

    - by mark
    I want to download a image from a remote server only if it is not older than 2 days. I have the constructing as below now. Is this right? I want to now the last_modified data first before downloading. $ch = curl_init($file_source); // the file we are downloading curl_setopt($ch, CURLOPT_TIMEOUT, 20); curl_setopt($ch, CURLOPT_FILE, $wh); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_FILETIME, true); curl_exec($ch); $headers = curl_getinfo($ch); $last_modified = $headers['filetime']; if ($last_modified != -1) { // unknown echo date("Y-m-d", $last_modified); //etc } curl_close($ch); fclose($wh);

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  • SQL finding overlapping of times pass midnight (across 2 days)

    - by janechii
    Hi everyone, I know there are lots of these types of questions, but i didn't see one that was similar enough to my criteria. So i'd like to ask for your help please. The fields i have are just start and end which are of time types. I cannot involve any specific dates in this. If the time ranges don't go pass midnight across day, i'd just compare two tuples as such: end1 > start2 AND start1 < end2 (end points touching are not considered overlapped here.) But when I involve time range that pass (or at) midnight, this obviously doesn't work. For example, given: start | end --------+-------- 06:00PM | 01:00AM 03:00PM | 09:00PM Without involving dates, how can i achieve this, please. My assumption is, if end is less than start, then we're involving 2 days. I'm trying to do this in plain standard SQL, so just a simple and concise logic in the WHERE clause. Thank you everyone!

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  • r -- finding difference between business days

    - by acesnap
    I have several years of data (only for business days (no weekends or holidays)) in an [r] data frame and would like to find the difference between the data on the 2nd and 5th business day of each month. So the solution needs to go thru the list, determine the 2nd and 5th business day, get the data for the corresponding dates and then find the difference. the data looks like: 1/19/1990 1.22 1/20/1990 1.25 1/23/1990 1.26 (Gap in date is weekend) ... 2/1/1990 1.34 2/2/1990 1.36 2/5/1990 1.22 (Gap in date is weekend) I have tried using dateTime() but it doesn't handicap for weekends and holidays. Any suggestions would be appreciated, thanks.

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  • Solita Oy Achieves Oracle PartnerNetwork Specialization

    - by michaela.seika(at)oracle.com
    Helsinki, February 2, 2011 - Solita Oy, a member of the Oracle® PartnerNetwork (OPN), is the first Finnish enterprise to achieve OPN Specialized status for customer-specific systems integration and software solutions.To achieve a Specialized status, Oracle partners are required to meet a stringent set of requirements that are based on the needs and priorities of the customer and partner community. By achieving a Specialized distinction, Solita Oy has been recognized by Oracle for its expertise in customer-specific systems integration and software solutions, achieved through competency development and demonstrated by the company's business results and proven success in implementing customer projects. "Solita and Oracle have cooperated for a long time, and we have been an Oracle partner for many years. We believe that the renewed partner program and the new partnership level that we have achieved will open up new opportunities for a closer collaboration with Oracle. Our increased focus on systems integration solutions and the stepping up of our specialized knowledge of SOA will enable us to provide even better solutions for our customers," said Jari Niska, Chief Executive Officer, Solita Oy. "Solita has shown trust and belief in Oracle's technology and in the business opportunities arising with it. They have contributed to building our cooperation in a consistent and systematic way. Achieving a Specialized status in our partner program is a natural further step in our close and committed cooperation. It strengthens our trust in our ability to be able to increase both turnover and profitability together," said Juha Kaskirinne, Alliances and Channel Leader, Oracle Finland Oy.  About Oracle PartnerNetwork Oracle PartnerNetwork (OPN) Specialized is the latest version of Oracle's partner program that provides partners with tools to better develop, sell and implement Oracle solutions. OPN Specialized offers resources to train and support specialized knowledge of Oracle products and solutions and has evolved to recognize Oracle's growing product portfolio, partner base and business opportunity. Key to the latest enhancements to OPN is the ability for partners to differentiate through Specializations. Specializations are achieved through competency development, business results, expertise and proven success. To find out more visit http://www.oracle.com/partners or connect with the Oracle Partner community at OPN on Twitter, OPN on Facebook, OPN on LinkedIn, and OPN on YouTube. About Solita Oy Solita Oy is a Finnish company dedicated to developing demanding information system solutions and IT professional services. Solita's customers include prominent Finnish companies and public organizations. Solita's turnover in 2010 was about 17 million euros. The company was founded in 1996 and has over 170 employees. Further information: www.solita.fiFurther information Jari Niska, CEO, Solita Oy, tel. +358 40 524 6400, [email protected] Kaskirinne, A&C Leader Finland, Oracle Finland Oy, tel. +358 40 506 3592, [email protected]

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  • Enablement 2.0 Get Specialized!

    - by michaela.seika(at)oracle.com
      Check the new OPN Certified Specialist Exam Study Guides – your quick reference to the training options to guide partners pass OPN Specialist Exams! What are the advantages of the Exam Study Guides? Cover the Implementation Specialist Exams that count towards OPN Specialization program. Capture Exam Topics, Exam Objectives and Training Options. Define the Exam Objectives by learner or practitioner level of knowledge: Learner-level: questions require the candidate to recall information to derive the correct answer Practitioner-level: questions require the candidate to derive the correct answer from an application of their knowledge. Map by each Exam Topic the alternative training options that are available at Oracle. Where to find the Exam Study Guides? On Enablement 2.0 > Spotlight On each Knowledge Zone > Implement On each Specialist Implementation Guided Learning Path For More Information Oracle Certification Program Beta Exams OPN Certified Specialist Exams OPN Certified Specialist FAQ Contact Us Please direct any inquiries you may have to Oracle Partner Enablement team at [email protected].

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  • EAIESB is pleased to announce the release of book “Oracle Service Bus (OSB) in 21 days: A hands on guide for OSB”.

    - by JuergenKress
    It is available for order and signed copies are available through our website. For more information, Visit the below links. http://www.eaiesb.com/OSBin21daysbook.html http://eaiesb.com/OSBin21days.html For more information, visit the below links. http://www.eaiesb.com/OSBin21daysbook.html & http://eaiesb.com/OSBin21days.html. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit  www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Technorati Tags: OSB,EAIESB,OSB 21 days,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • jQuery UI Datepicker - Disable specific days

    - by Sam
    Is there any (easy) way to set the jQuery UI Datepicker to disallow selection of specific, predetermined days? I was able to get this approach working, however, it produces a null error which prevents it from displaying in IE. 'natDays[...].0' is null or not an object Thanks in advance! UPDATE: Might help if I included some code, right? Anyway, most of this was taken straight from the aforementioned thread: natDays = [ [7, 23], [7, 24], [8, 13], [8, 14], ]; function nationalDays(date) { for (i = 0; i < natDays.length; i++) { if (date.getMonth() == natDays[i][0] - 1 && date.getDate() == natDays[i][1]) { return [false, natDays[i][2] + '_day']; } } return [true, '']; } function noWeekendsOrHolidays(date) { var noWeekend = $.datepicker.noWeekends(date); if (noWeekend[0]) { return nationalDays(date); } else { return noWeekend; } } $(function() { $("#datepicker").datepicker({ inline: true, minDate: new Date(2009, 6, 6), maxDate: new Date(2009, 7, 14), numberOfMonths: 2, hideIfNoPrevNext: true, beforeShowDay: $.datepicker.noWeekends, altField: '#alternate', }); }); Thanks again!

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  • Jquery UI Datepicker disabling wrong days

    - by Nazariy
    I have run in to issue that days that have to be disabled are shifted to the next day. The idea is that day that does not exist in our booking object or have a value less than 1 should be disabled on calendar. here is simplified version of my script and demonstration on jsfiddle: var bookings = { "2012-09-01": 24, "2012-09-03": 31, "2012-09-05": 27, "2012-09-06": 9, "2012-09-07": 18, "2012-09-08": 0, "2012-09-10": 20, "2012-09-12": 19, "2012-09-13": 0, "2012-09-14": 9, "2012-09-15": 24, "2012-09-17": 19, "2012-09-19": 28, "2012-09-20": 15, "2012-09-21": 12, "2012-09-22": 25, "2012-09-24": 19, "2012-09-26": 0, "2012-09-27": 0, "2012-09-28": 0, "2012-09-29": 0 }; function MyEvent(date) { bookings = bookings || {}; this.date = date.toISOString().substr(0, 10); this.display = (typeof bookings[this.date] == 'number' && bookings[this.date] > 0); return this; } MyEvent.prototype.toArray = function () { return [this.display, null, null]; }; $(function () { $('#eventCalendar').datepicker({ dateFormat: "yy-mm-dd", firstDay: 1, defaultDate: "2012-09-24", beforeShowDay: function (date) { return new MyEvent(date).toArray(); } } ); }); Can some one suggest me what am I doing wrong or is it a bug?

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  • how to convert minutes to days,hours,minutes

    - by tuxou
    hi how to convert minutes into days hours and minutes in java public String timeConvert(int time){ String t = ""; int h = 00; int m = 00; // h= (int) (time / 60); // m = (int) (time % 60); // if(h>=24) h=00; if((time>=0) && (time<=24*60)){ h= (int) (time / 60); m = (int) (time % 60); }else if((time>24*60) && (time<=24*60*2)){ h= (int) (time / (1440)); m = (int) (time % (1440)); }else if((time>24*60*2) && (time<=24*60*3)){ h= (int) (time / (2880)); m = (int) (time % (2880)); }else if((time>24*60*3) && (time<=24*60*4)){ h= (int) (time / (2880*2)); m = (int) (time % (2880*2)); }else if((time>24*60*4) && (time<=24*60*5)){ h= (int) (time / (2880*3)); m = (int) (time % (2880*3)); }else if((time>24*60*5) && (time<=24*60*6)){ h= (int) (time / (2880*4)); m = (int) (time % (2880*4)); }else if((time>24*60*6) && (time<=24*60*7)){ h= (int) (time / (2880*5)); m = (int) (time % (2880*5)); } t =h+":"+m ; return t; } I tried this but it dont work thanks

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  • Problem finding the difference in days between two dates

    - by James
    I have been using a tidy little routine that I found here to calculate the difference in days between two dates in AS3. I am getting some strange results and I am wondering if any of you inter-codal-mega-lords can shed some light? Why is Q1 of 2010 coming up one day short, when in all other cases the routine is performing fine? Many thanks in advance to anyone who can help! function countDays( startDate:Date, endDate:Date ):int { var oneDay:int = 24*60*60*1000; // hours*minutes*seconds*milliseconds var diffDays:int = Math.abs((startDate.getTime() - endDate.getTime())/(oneDay)); return diffDays; } countDays( new Date( 2010, 00, 01 ), new Date( 2011, 00, 01 ) ); // returns 365, which is correct countDays( new Date( 2010, 00, 01 ), new Date( 2010, 03, 01 ) ); // returns 89, which is 1 day short countDays( new Date( 2010, 03, 01 ), new Date( 2010, 06, 01 ) ); // returns 91, which is correct countDays( new Date( 2010, 06, 01 ), new Date( 2010, 09, 01 ) ); // returns 92, which is correct countDays( new Date( 2010, 09, 01 ), new Date( 2011, 00, 01 ) ); // returns 92, which is correct

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  • Loop to check all 14 days in the pay period

    - by Rachel Ann Arndt
    Name: Calc_Anniversary Input: Pay_Date, Hire_Date, Termination_Date Output: "Y" if is the anniversary of the employee's Hire_Date, "N" if it is not, and "T" if he has been terminated before his anniversary. Description: Create local variables to hold the month and day of the employee's Date_of_Hire, Termination_Date, and of the processing date using the TO_CHAR function. First check to see if he was terminated before his anniversary. The anniversary could be on any day during the pay period, so there will be a loop to check all 14 days in the pay period to see if one was his anniversary. CREATE OR replace FUNCTION Calc_anniversary( incoming_anniversary_date IN VARCHAR2) RETURN BOOLEAN IS hiredate VARCHAR2(20); terminationdate VARCHAR(20); employeeid VARCHAR2(38); paydate NUMBER := 0; BEGIN SELECT Count(arndt_raw_time_sheet_data.pay_date) INTO paydate FROM arndt_raw_time_sheet_data WHERE paydate = incoming_anniversary_date; WHILE paydate <= 14 LOOP SELECT To_char(employee_id, '999'), To_char(hire_date, 'DD-MON'), To_char(termination_date, 'DD-MON') INTO employeeid, hiredate, terminationdate FROM employees, time_sheet WHERE employees.employee_id = time_sheet.employee_id AND paydate = pay_date; IF terminationdate > hiredate THEN RETURN 'T'; ELSE IF To_char(SYSDATE, 'DD-MON') = To_char(hiredate, 'DD-MON')THEN RETURN 'Y'; ELSE RETURN 'N'; END IF; END IF; paydate := paydate + 1; END LOOP; END; Tables I am using CREATE TABLE Employees ( EMPLOYEE_ID INTEGER, FIRST_NAME VARCHAR2(15), LAST_NAME VARCHAR2(25), ADDRESS_LINE_ONE VARCHAR2(35), ADDRESS_LINE_TWO VARCHAR2(35), CITY VARCHAR2(28), STATE CHAR(2), ZIP_CODE CHAR(10), COUNTY VARCHAR2(10), EMAIL VARCHAR2(16), PHONE_NUMBER VARCHAR2(12), SOCIAL_SECURITY_NUMBER VARCHAR2(11), HIRE_DATE DATE, TERMINATION_DATE DATE, DATE_OF_BIRTH DATE, SPOUSE_ID INTEGER, MARITAL_STATUS CHAR(1), ALLOWANCES INTEGER, PERSONAL_TIME_OFF FLOAT, CONSTRAINT pk_employee_id PRIMARY KEY (EMPLOYEE_ID), CONSTRAINT fk_spouse_id FOREIGN KEY (SPOUSE_ID) REFERENCES EMPLOYEES (EMPLOYEE_ID)) / CREATE TABLE Arndt_Raw_Time_Sheet_data ( EMPLOYEE_ID INTEGER, PAY_DATE DATE, HOURS_WORKED FLOAT, SALES_AMOUNT FLOAT, CONSTRAINT pk_employee_id_pay_date_time PRIMARY KEY (EMPLOYEE_ID, PAY_DATE), CONSTRAINT fk_employee_id_time FOREIGN KEY (EMPLOYEE_ID) REFERENCES EMPLOYEES (EMployee_ID)); error FUNCTION Calc_Anniversary compiled Warning: execution completed with warning

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  • What reasons are there to reduce the max-age of a logo to just 8 days? [closed]

    - by callum
    Most websites set max-age=31536000 (1 year) on the Cache-control headers of static assets such as logo images. Examples: YouTube Yahoo Twitter BBC But there is a notable exception: Google's logo has max-age=691200 (8 days). I've checked the headers on the Google logo in the past, and it definitely used to be 1 year. (Also, it used to be part of a sprite, and now it is a standalone logo image, but that's probably another question...) What could be valid technical reasons why they would want to reduce its cache lifetime to just 8 days? Google's homepage is one of the most carefully optimised pages in the world, so I imagine there's a good reason. Edit: Please make sure you understand these points before answering: Nobody uses short max-age lifetimes to allow modifying a static asset in future. When you modify it, you just serve it at a different URL. So no, it's nothing to do with Google doodles. Think about it: even if Google didn't understand this basic trick of HTTP, 8 days still wouldn't be appropriate, as only those users who don't have the original logo cached would see the doodle on doodle-day – and then that group of users would go on seeing the doodle for the following 8 days after Google changed it back :) Web servers do not worry about "filling up" the caches of clients (or proxies). The client manages this by itself – when it hits its own storage limit, it just starts dropping the lowest priority items to make space for new items. The priority score is based on the question "How likely am I to benefit from having cached this URL?", which is nothing to do with what max-age value the server sent when the URL was originally requested; it's a heuristic based on the "frecency" of requests for that URL. The max-age simply lets the server set a cut-off point – the time at which the client is supposed to discard the item regardless of how often it's being re-used. It would be very nice and trusting of a downstream client/proxy to rely on all origin servers "holding back" from filling up their caches, but I don't think we live in that world ;)

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  • How to deal with a ten days debugging session? [on hold]

    - by smonff
    Ten days ago, I fixed a bug on a large application and the hot fix has created a disappearing of some data from the user point of view. Data are not deleted, but have been set to hidden status. It could be possible to get the data back, but the thing seems to be hard: I've already spent 10 days to understand and reproduce the problem (mostly with complex SQL queries but sometimes it is necessary to update the database to test the application logic). Is 10 days a normal amount of time for these kind of problems? Should we keep on and retrieve the data or should we tell these users sorry for the loss, but your data have disappeared? Any advice on when to stop searching how to solve the issue?

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  • Memory leaks with UIWebView and NSURL: already spent several days trying to solve them

    - by Sander de Jong
    I have already found a lot of information about how to solve memory leaks for iPhone Obj C code. The last two leaks keep me puzzled, I'm probably overlooking something. Maybe you can spot it. Instruments reports 2 leaks for the following code (part of a UIViewController subclass): (1) UIWebView *webView = [[UIWebView alloc] initWithFrame:CGRectMake(0.0, 0.0, self.view.bounds.size.width, self.view.bounds.size.height - LOWER_VERT_WINDOW_MARGIN)]; (2) webView.scalesPageToFit = YES; (3) webView.dataDetectorTypes = UIDataDetectorTypeNone; (4) (5) NSURL *url = [NSURL fileURLWithPath:self.fullPathFileName isDirectory:NO]; (6) NSMutableURLRequest *urlRequest = [[NSMutableURLRequest alloc] initWithURL:url]; (7) [webView loadRequest:urlRequest]; (8) [urlRequest release], urlRequest = nil; (9) [self.view addSubview:webView]; (10) [webView release], webView = nil; Instruments claims 128 bytes are leaking in line 1, as well as 256 bytes in line 4. No idea if it means line 3 or line 5. Does anybody have a clue what I'm overlooking?

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  • Oracle OpenWorld and JavaOne 2014 - Early Bird Registration

    - by Cinzia Mascanzoni
      #OOW14 Sponsor Oracle OpenWorld » Exhibit at Oracle OpenWorld » Don’t Miss Out on Early Bird Savings Oracle OpenWorld 2014 is several months away. So why register now, partners? Savings. And availability. Register early and you can secure your spot and hotel room for the world’s largest business and technology conference. Plus, you’ll save on sessions, keynotes, entertainment, and networking opportunities. Register Now Just What You'd Expect from Oracle OpenWorld. And More. You’re probably attending the conference for the IT programs and networking opportunities. You’ll find a wide selection. And that’s just the start. Because Oracle OpenWorld is more than just IT. Check out and benefit from all the conference activities, including benefits specific for Oracle PartnerNetwork (OPN) at OPN Central @ OpenWorld, including: Oracle OpenWorld Keynote OPN Keynote OPN General Sessions OPN AfterDark Reception OPN Central @ OpenWorld OPN Lounge Access Save Even More As a Group Are you planning to register five or more people for Oracle OpenWorld 2014? If so, take advantage of our Group Pass Purchase. Register a Group Today! SponsorOracle OpenWorld Get maximum exposure for your brand Find out how » Exhibit atOracle OpenWorld Meet your customers and prospects face-to-face. Reserve a booth now » Register for Oracle OpenWorld Today Learn more about Oracle OpenWorld   #OOW14 Copyright © 2014, Oracle Corporation and/or its affiliates. All rights reserved. Contact Us | Legal Notices and Terms of Use | Privacy Statement

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  • How to use Linq to group DateTime by month and days calculation

    - by Daoming Yang
    Hi all, I have two questions: First one: I have a order list and want to group them by the created month for the reports. Each order's created datetime will be like "2010-03-13 11:17:16.000" How can I make them only group by date like "2010-03"? Note: the DateCreated is the DateTime tpye The following code is not correct. var items = orderList.GroupBy(t => t.DateCreated.Month) .Select(g => new Order() { DateCreated = g.Key }) .OrderByDescending(x => x.OrderID).ToList(); Second one: Output the full months between two dates in C# If an user choose 2010-04-08 and 2010-06-04, I want to output the 2010-04-01 and 2010-06-30. I can always get the first day and last day of the months, but I want to find out some other options Many thanks. Many thanks.

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  • SQL to get list of dates as well as days before and after without duplicates

    - by Nathan Koop
    I need to display a list of dates, which I have in a table SELECT mydate AS MyDate, 1 AS DateType FROM myTable WHERE myTable.fkId = @MyFkId; Jan 1, 2010 - 1 Jan 2, 2010 - 1 Jan 10, 2010 - 1 No problem. However, I now need to display the date before and the date after as well with a different DateType. Dec 31, 2009 - 2 Jan 1, 2010 - 1 Jan 2, 2010 - 1 Jan 3, 2010 - 2 Jan 9, 2010 - 2 Jan 10, 2010 - 1 Jan 11, 2010 - 2 I thought I could use a union SELECT MyDate, DateType FROM ( SELECT mydate - 1 AS MyDate, 2 AS DateType FROM myTable WHERE myTable.fkId = @MyFkId; UNION SELECT mydate + 1 AS MyDate, 2 AS DateType FROM myTable WHERE myTable.fkId = @MyFkId; UNION SELECT mydate AS MyDate, 1 AS DateType FROM myTable WHERE myTable.fkId = @MyFkId; ) AS myCombinedDateTable This however includes duplicates of the original dates. Dec 31, 2009 - 2 Jan 1, 2009 - 2 Jan 1, 2010 - 1 Jan 2, 2010 - 2 Jan 2, 2010 - 1 Jan 3, 2010 - 2 Jan 9, 2010 - 2 Jan 10, 2010 - 1 Jan 11, 2010 - 2 How can I best remove these duplicates? I am considering a temporary table, but am unsure if that is the best way to do it. This also appears to me that it may provide performance issues as I am running the same query three separate times. What would be the best way to handle this request?

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  • Find missing birth days in Apple Addressbook

    - by Felix Ogg
    I am trying to clean the holes out of my Mac address book. As a first step I want to ask all my friends for their birth day, to be able to congratulate them with cheesy Hallmark cards. I need a "group" in my address book, to mailmerge personalized messages from. This is the Applescript I came up with: tell application "Address Book" make new group with properties {name:"No Birthday"} set birthdayPeople to (get every person whose birth date is greater than date "Monday, January 1, 1900 12:00:00 AM") repeat with i from 1 to number of items in people set thePerson to item i of people if not (birthdayPeople contains thePerson) then add thePerson to group "No Birthday" end if end repeat save end tell It breaks, but from the error messages I cannot deduce what is wrong: Result: error "Can’t make «class azf4» id \"05F770BA-7492-436B-9B58-E24F494702F8:ABPerson\" of application \"Address Book\" into type vector." number -1700 from «class azf4» id "05F770BA-7492-436B-9B58-E24F494702F8:ABPerson" to vector (BTW: Did I mention this is my first AppleScript code, EVER? So, if this code can be simplified, or made more elegant, that is welcome too.)

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  • Finding days between two dates

    - by Ram
    I need to get all the dates between two dates For example Start date : 04/06/2010 End Date : 10/06/2010 Then, it has to list out 05/06/2010 06/06/2010 07/06/2010 08/06/2010 09/06/2010 Thanks

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  • diff between two days, in hours

    - by Cristian Boariu
    Hi, I do not uderstand why the result of: (DateTime.Now.Subtract(user.created_time.Value.Date)).Hours is 23. where: DateTime.Now is:{3/30/2010 12:00:00 AM} and user.created_time.Value.Date is : {3/24/2010 12:00:00 AM} Does it make sense for anybody? ps: I want to select all users created in last 72 hours so i suppose that is the way i should do...

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