I am sorting a hash in Perl. I encountered an Out of memory error when running my Perl Script:
foreach $key (sort (keys(%hash))) {
....
}
How do I sort a hash that has tons of data?
Explain which algorithm you would use to implement a function that takes an array of integers and returns the maximum integer in the collection, assuming that the length of the array is less than 1000. Would you use Bubble Sort or Merge Sort and Why?
Also, what happens to the above algorithm choice, if the array length is greater than 1000?
Currently when sorting in a flex grid, the sort arrow that shows whether the column is sorted ascending or descending is right aligned to the column. Is there anyway to change the position of the sort arrow, such as applying padding?
I have NSMutableArray of NSMutableDictionary(NSString objects). One of NSString object is actually a date, and i need to sort NSMutableArray based on that date and I don't want it to sort dates as strings. How can i make it?
I'm trying to sort a GLibc hash table by id that looks something like:
key - id
{
"Red", 2,
"BLue", 4,
"Yellow", 5,
"Orange", 8
}
I'm just not sure how to approach this because GLibc does not have a sort method. I was thinking to use qsort or GCompareFunc
Any ideas will be appreciate it!
I have an array of structs in ColdFusion. I'd like to sort this array based on one of the attributes in the structs. How can I achieve this? I've found the StructSort function, but it takes a structure and I have an array.
If this is not possible purely in ColdFusion, is it possible in Java somehow (maybe using Arrays.sort(Object[], Comparator))?
Is there a way to sort Devexpress QuantumGrid rows on data from a different column other than the one whose header has been clicked? For example, when the header of column A is clicked the rows of the grid are sorted on the data from column B. Visually it should still appear that it is column A that has been sorted as the sort glyphys will be shown in column A's header.
Is there a way to sort Devexpress QuantumGrid rows on data from a different column other than the one whose header has been clicked? For example, when the header of column A is clicked the rows of the grid are sorted on the data from column B. Visually it should still appear that it is column A that has been sorted as the sort glyphys will be shown in column A's header.
How can I efficiently and easily sort a list of tuples without being sensitive to case?
For example this:
[('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)]
Should look like this once sorted:
[('a', 5), ('a', 'a'), ('A', 'b'), ('a', 'c')]
The regular lexicographic sort will put 'A' before 'a' and yield this:
[('A', 'b'), ('a', 5), ('a', 'a'), ('a', 'c')]
I am trying to sort an ArrayList of Strings that represent card values. So, some cards contain letters ("King") and some contain Strings containing only a number ("7"). I know to use Collections.sort, but it only sorts Strings that contain letters. How do I get the ArrayList to be sorted by number as well as alphabetically?
Is strcmp() appropriate for comparing ICU collator sort keys in PHP?
The sort keys I'm asking about are from collator_get_sort_key() which are described in ICU documentation.
Hi
I have found this code in the internet and it was for arrays ,I want to change it for doubly linked list(instead of index we should use pointer) would you please help me that how can i change merge method(I have changed sort method by myself) also this is not my home work ,I love working with linked list!!
public class MergeSort {
private DoublyLinkedList LocalDoublyLinkedList;
public MergeSort(DoublyLinkedList list) {
LocalDoublyLinkedList = list;
}
public void sort() {
if (LocalDoublyLinkedList.size() <= 1) {
return;
}
DoublyLinkedList listOne = new DoublyLinkedList();
DoublyLinkedList listTwo = new DoublyLinkedList();
for (int x = 0; x < (LocalDoublyLinkedList.size() / 2); x++) {
listOne.add(x, LocalDoublyLinkedList.getValue(x));
}
for (int x = (LocalDoublyLinkedList.size() / 2) + 1; x < LocalDoublyLinkedList.size`(); x++) {`
listTwo.add(x, LocalDoublyLinkedList.getValue(x));
}
//Split the DoublyLinkedList again
MergeSort sort1 = new MergeSort(listOne);
MergeSort sort2 = new MergeSort(listTwo);
sort1.sort();
sort2.sort();
merge(listOne, listTwo);
}
private void merge(DoublyLinkedList a, DoublyLinkedList b) {
int x = 0;
int y = 0;
int z = 0;
while (x < first.length && y < second.length) {
if (first[x] < second[y]) {
a[z] = first[x];
x++;
} else {
a[z] = second[y];
y++;
}
z++;
}
//copy remaining elements to the tail of a[];
for (int i = x; i < first.length; i++) {
a[z] = first[i];
z++;
}
for (int i = y; i < second.length; i++) {
a[z] = second[i];
z++;
}
}
}
I have:
L1 = ['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8']
this is a list of strings, right?
I need to make it a list of integers as follows:
L2 = [11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8]
finally I will sort it like below:
L3 = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] by L2.sort()
please let me know how I can get to L3 from L1
Following this post jQuery table sort (github link: https://github.com/padolsey/jQuery-Plugins/blob/master/sortElements/jquery.sortElements.js), I am successfully sort columns, however it does not work in the case of rowspan: For example, case like this
Grape 3,096,671M
1,642,721M
Apple 2,602,750M
3,122,020M
When I click on the second column, it try to sort
Apple 2,602,750M
1,642,721M
Grape 3,096,671M
3,122,020M
which as you can see is not correct, please any jQuery guru help me fix this problem. Here is my code
var inverse = false;
function sortColumn(index){
index = index + 1;
var table = jQuery('#resultsTable');
table.find('td').filter(function(){
return jQuery(this).index() == index;
}).sortElements(function(a, b){
a = convertToNum($(a).text());
b = convertToNum($(b).text());
return (
isNaN(a) || isNaN(b) ?
a > b : +a > +b
) ?
inverse ? -1 : 1 :
inverse ? 1 : -1;
},function(){
return this.parentNode;
});
inverse = !inverse;
}
function convertToNum(str){
if(isNaN(str)){
var holder = "";
for(i=0; i<str.length; i++){
if(!isNaN(str.charAt(i))){
holder += str.charAt(i);
}
}
return holder;
}else{
return str;
}
}
Question:
1.How do I sort this with rowspan. THE NUMBER OF ROWSPAN IS NOT ALWAYS THE SAME. The above example both Grape and Apple have rowspan of 2, but this is not always the case.
2.Can any explain this syntax:
return (
isNaN(a) || isNaN(b) ?
a > b : +a > +b
) ?
inverse ? -1 : 1 :
inverse ? 1 : -1;
So I can see that if either a or b is not a number, then do string comparison otherwise do number comparison, but I dont understand the
inverse ? -1 : 1 :
inverse ? 1 : -1;
I'm using the jquery autocomplete plugin that comes with the symfony sfFormExtra plugin.
/*
* jQuery Autocomplete plugin 1.1
*
* Copyright (c) 2009 Jörn Zaefferer
*
* Dual licensed under the MIT and GPL licenses:
* http://www.opensource.org/licenses/mit-license.php
* http://www.gnu.org/licenses/gpl.html
*
* Revision: $Id: jquery.autocomplete.js 15 2009-08-22 10:30:27Z joern.zaefferer $
*/
It does seem to sort json results according to the key, but I can't find any mention of sort options in the code.
I would like the results sorted like returned from the server.
How can I achieve this?
I have the field receiptno, which is a varchar holding a numeric value, and want to sort this. Sorting as a string gives me the wrong ordering. I'd like to try sorting it as an integer. Is there anyway to converting to integer in the order by clause so I can sort by integer in the query itself.
It seems that I can sort an std::vector<std::pair<int, std::string>>, and it will sort based on the int value. Is this a well defined thing to do? Does std::pair have a default ordering based on it's elements?
Hi, I have a groovy list of lists i.e.
list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]]
I would like sort it by order of the first element, then second, then third.
Expected
assert list == [[1, 0, 3], [1, 5, 2], [2, 0, 1]]
I started with list = list.sort{ a,b -> a[0] <=> b[0] } but that only sorts the first element. How do you finish?
Thanks
Before you stone me for being a heretic, There is a sort that proclaims to be O(1), called "Bead Sort" (http://en.wikipedia.org/wiki/Bead_sort) , however that is pure theory, when actually applied I found that it was actually O(N * M), which is pretty pathetic.
That said, Lets list out some of the fastest sorts, and their best case and worst case speed in Big O notation.
~~ FlySwat ~~
Is there an alphanumeric sort for R?
Say I had a character vector like so:
> seq.names <- c('abc21', 'abc2', 'abc1', 'abc01', 'abc4', 'abc201', '1b', '1a')
I'd like to sort it aphanumerically, so I get back this:
c('1a', '1b', 'abc1', 'abc01', 'abc2', 'abc4', 'abc21', 'abc201')
Does this exist somewhere, or should I start coding? Thanks,
-chris
Hi
I want to sort a doubly linked list with its pointer and using merge sort,would you please help me that how can i do that? is there any link that have such a code? thanks
Sample Data :
input : "abcdacdc"
Output : "cadb"
here we have to sort strings in order of count of characters.
If the count is same for characters. maintain the original order of
the characters from input string.
my approach: i have used array of 26 for maintaining occurrence of all characters and sort it then print it.But while doing so i am not able to maintain order in case if two characters have same count.
please suggest any improvement or any other algo.
example some array {2,8,9,10,21,32,1,6,3...}
first child take (data size / 2) and sort
second chile take (data size / 2) and sort after combine 2 child data and give us a sorted full data, is it possible with some algorithms?