Search Results

Search found 24121 results on 965 pages for 'display driver'.

Page 130/965 | < Previous Page | 126 127 128 129 130 131 132 133 134 135 136 137  | Next Page >

  • how to display two li in time intervel using jquery

    - by abc
    <html> <head> <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.4.js"></script> <style type="text/css"> body { color:green; } </style> <script type="text/javascript"> $(document).ready(function() { setInterval(findYellow,1000); function findYellow() { $("ul").each(function() { var $this = $(this); if($this.css("color") != "green") { $this.css("color", "green"); $this.text("abcd blue"); } else { $this.css("color", "blue"); $this.text("abcd green"); } }); } }); </script> </head> <body> <ul>This is a sample set <li>1</li> <li>3</li> <li>5</li> <li>7</li> <li>9</li> </ul> </body> </html>

    Read the article

  • oracle display for every stored procedure the execution time

    - by CC
    Hi all. I'm working on a stored procedure. Inside this one, there are many call to the other stored procedures. There are a bunch of them. I was wondering if there is a option to be able to have the execution time of every stored procedure involved, every function (with a start and end time, ior something like that). The idea is that I need to optimise it and I should touch every part, and since I not sure where is the longest execution time, is a bit difficult. And after a modification I would like the see the hole process if it's shorter or not. If I call the procedure from unix, using sql plus, I have no log. If I call it from TOAD, it's blocked until the end. Any idea? I'm not a dba, so I don't have many rights on the database, I'm just a regular user. Thanks for any advice. C.C.

    Read the article

  • java gui image problem : doesn't display in the background

    - by thegamer
    Hello, i have a query about why is my image not being displayed in my background of my program. I mean i did all the steps necessary and still it would'nt be displayed. The code runs perfectly but without having the image displayed. The directory is written in the good location of the image. I am using java with gui. If anyone could help me solve my problem, i would appreciate :) here is the code below: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class hehe extends JPanel{ public hehe(){ setOpaque(false); setLayout(new FlowLayout()); } public static void main (String args[]){ JFrame win = new JFrame("yooooo"); // it is automaticcally hidden JPanel mainPanel = new JPanel(new BorderLayout()); win.add(mainPanel); JLabel titleLabel = new JLabel("title boss"); titleLabel.setFont(new Font("Arial",Font.BOLD,18)); titleLabel.setForeground(Color.blue); mainPanel.add(titleLabel,BorderLayout.NORTH); win.setSize(382,269); // the dimensions of the image win.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); win.setVisible(true); } public void paint(Graphics g) { Image a = Toolkit.getDefaultToolkit().getImage("C:\\Users\\andrea\\Desktop\\Gui\\car"); // car is the name of the image file and is in JPEG g.drawImage(a,0,0,getSize().width,getSize().height,this); super.paint(g); } }

    Read the article

  • Display problem after deletion in linked list in C

    - by LuckySlevin
    Hi, actually this was another problem but it changed so I decided to open a new question. My code is typedef struct inner_list { int count; char word[100]; inner_list*next; } inner_list; typedef struct outer_list { char word [100]; inner_list * head; int count; outer_list * next; } outer_list; void delnode(outer_list **head,char num[100])//thanks to both Nir Levy and Jeremy P. { outer_list *temp, *m; m=temp=*head; /*FIX #1*/ while(temp!=NULL) { if(strcmp(temp->word,num)==0) { if(temp==*head) { delinner(temp->head); /* FIX#2 */ *head=temp->next; free(temp); return; } else { delinner(temp->head); /* FIX#2 */ m->next=temp->next; free(temp); return; } } else { m=temp; temp= temp->next; } } printf(" ELEMENT %s NOT FOUND ", num); } void delinner(inner_list *head) { /* FIX#2 */ inner_list *temp; temp=head; while(temp!=NULL) { head=temp->next; free(temp); temp=head; } } void delnode2(outer_list *up,inner_list **head,char num[100]) { inner_list *temp2,*temp, *m; outer_list *p; p = up; while(p!=NULL){m=temp=temp2=p->head; while(temp!=NULL) { if(strcmp(temp->word,num)==0) { if(temp==(*head)) { *head=temp->next; free(temp); return; } else { m->next=temp->next; free(temp); return; } } else { m=temp; temp= temp->next; } } p=p->next; } printf(" ELEMENT %s NOT FOUND ", num); } void print_node(outer_list *parent_node) { while(parent_node!=NULL){ printf("%s\t%d\t", parent_node->word, parent_node->count); inner_list *child_node = parent_node->head; printf("list: "); if(child_node ==NULL){printf("BUARADA");} while (child_node != NULL) { printf("%s-%d", child_node->word,child_node->count); child_node = child_node->next; if (child_node != NULL) { printf("->"); } } printf("\n"); parent_node = parent_node->next; } } While deleting an element from outer list I am also trying the delete the same element from inner_list too. For example: - Let's say aaa is an element of outer_list linked list and let's point it with outer_list *p - This aaa can also be in an inner_list linked list too. (it can be in p-head or another innerlist.) Now, the tricky part again. I tried to apply the same rules with outer_list deletion but whenever i delete the head element of inner_list it gives an error. Where is the wrong thing in print_node or delnode2?

    Read the article

  • PHP, MySQL: Display only required parts of my website in sister website

    - by Devner
    Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

    Read the article

  • How to display CodeRush menu item in VS ?

    - by drasto
    I just installed CodeRush to my VS and when I run VS for the first time after installation it showed me a dialog asking if I'm experienced user. While the dialog was visible I could see that there was new menu item in VS named DevExpress. There was a small check box on that dialog saying something about menu items that I probably should have checked. As I did not the menu items disappeared just after I clicked OK. I cannot make that menu item reappear. Can somebody help me with this ?

    Read the article

  • Load page for validation but do not display it to user in ASP.NET

    - by Kevin
    We have a site requiring users pay $2 to view the details of a record. We occasionally get complaints because we send them to the payment page, and once they pay it turns out the record isn't valid, or it was lost, or the data couldn't be generated. So we want to add in a check to ensure the page constructs properly before the user is required to pay for it. However, we don't want the user to have access to the page until they pay for it. Is there anything in ASP.NET 3.5 or just general web design that would allow something like this? The data on the record is real time and computed on a backend server before sent to the client. Occasionally this computation fails for whatever reason. Our alternative is to call all of the loading methods and validate the data, then redirect them to the payment page. The problem is A) this will be a relatively involved process rewriting all of these methods to return validation information, and B) it still doesn't guarentee us the page will load properly. Any thoughts?

    Read the article

  • Image display permissions in PHP/Apache

    - by Randy
    I have a PHP site with a login system, and am trying to make a feature where only specific usernames can view particular images. I think what I'm trying to do is more involved than merely changing the .htaccess file, because a) this won't help discern between users that are/aren't allowed to view the image, and b) if someone enters the exact URL of the image ("directory/images/photos/230ru0q0238rn230nd_asdi0nqn8.jpg") they can still view the image (since it's a physical file in the directory, and not text in a DB, etc.). Again, restricting via .htaccess would restrict the directory as a whole, or all files in it, so I can't figure out how it would work. Ideally, all images would be blocked by trying to access them directly through their direct URL, and the image would only appear between <img> tags if the user's session/username is valid, else they get an error message. I've heard the term ACL but I'm not sure this is related to what I'm trying to do.

    Read the article

  • Display number of retweets of a blog post

    - by Clint
    Hi, I was wondering if anyone has a link to any information regarding building in Twitter Mention functionality into a website like here, http://paul.boagworld.com/?page=2, where each post dispays the number of times it has been mentioned on twitter. Many thanks, C

    Read the article

  • webgl adding projection doesnt display object

    - by dazed3confused
    I am having a look at web gl, and trying to render a cube, but I am having a problem when I try to add projection into the vertex shader. I have added an attribute, but when I use it to multiple the modelview and position, it stops displaying the cube. Im not sure why and was wondering if anyone could help? Ive tried looking at a few examples but just cant get this to work vertex shader attribute vec3 aVertexPosition; uniform mat4 uMVMatrix; uniform mat4 uPMatrix; void main(void) { gl_Position = uPMatrix * uMVMatrix * vec4(aVertexPosition, 1.0); //gl_Position = uMVMatrix * vec4(aVertexPosition, 1.0); } fragment shader #ifdef GL_ES precision highp float; // Not sure why this is required, need to google it #endif uniform vec4 uColor; void main() { gl_FragColor = uColor; } function init() { // Get a reference to our drawing surface canvas = document.getElementById("webglSurface"); gl = canvas.getContext("experimental-webgl"); /** Create our simple program **/ // Get our shaders var v = document.getElementById("vertexShader").firstChild.nodeValue; var f = document.getElementById("fragmentShader").firstChild.nodeValue; // Compile vertex shader var vs = gl.createShader(gl.VERTEX_SHADER); gl.shaderSource(vs, v); gl.compileShader(vs); // Compile fragment shader var fs = gl.createShader(gl.FRAGMENT_SHADER); gl.shaderSource(fs, f); gl.compileShader(fs); // Create program and attach shaders program = gl.createProgram(); gl.attachShader(program, vs); gl.attachShader(program, fs); gl.linkProgram(program); // Some debug code to check for shader compile errors and log them to console if (!gl.getShaderParameter(vs, gl.COMPILE_STATUS)) console.log(gl.getShaderInfoLog(vs)); if (!gl.getShaderParameter(fs, gl.COMPILE_STATUS)) console.log(gl.getShaderInfoLog(fs)); if (!gl.getProgramParameter(program, gl.LINK_STATUS)) console.log(gl.getProgramInfoLog(program)); /* Create some simple VBOs*/ // Vertices for a cube var vertices = new Float32Array([ -0.5, 0.5, 0.5, // 0 -0.5, -0.5, 0.5, // 1 0.5, 0.5, 0.5, // 2 0.5, -0.5, 0.5, // 3 -0.5, 0.5, -0.5, // 4 -0.5, -0.5, -0.5, // 5 -0.5, 0.5, -0.5, // 6 -0.5,-0.5, -0.5 // 7 ]); // Indices of the cube var indicies = new Int16Array([ 0, 1, 2, 1, 2, 3, // front 5, 4, 6, 5, 6, 7, // back 0, 1, 5, 0, 5, 4, // left 2, 3, 6, 6, 3, 7, // right 0, 4, 2, 4, 2, 6, // top 5, 3, 1, 5, 3, 7 // bottom ]); // create vertices object on the GPU vbo = gl.createBuffer(); gl.bindBuffer(gl.ARRAY_BUFFER, vbo); gl.bufferData(gl.ARRAY_BUFFER, vertices, gl.STATIC_DRAW); // Create indicies object on th GPU ibo = gl.createBuffer(); gl.bindBuffer(gl.ELEMENT_ARRAY_BUFFER, ibo); gl.bufferData(gl.ELEMENT_ARRAY_BUFFER, indicies, gl.STATIC_DRAW); gl.clearColor(0.0, 0.0, 0.0, 1.0); gl.enable(gl.DEPTH_TEST); // Render scene every 33 milliseconds setInterval(render, 33); } var mvMatrix = mat4.create(); var pMatrix = mat4.create(); function render() { // Set our viewport and clear it before we render gl.viewport(0, 0, canvas.width, canvas.height); gl.clear(gl.COLOR_BUFFER_BIT | gl.DEPTH_BUFFER_BIT); gl.useProgram(program); // Bind appropriate VBOs gl.bindBuffer(gl.ARRAY_BUFFER, vbo); gl.bindBuffer(gl.ELEMENT_ARRAY_BUFFER, ibo); // Set the color for the fragment shader program.uColor = gl.getUniformLocation(program, "uColor"); gl.uniform4fv(program.uColor, [0.3, 0.3, 0.3, 1.0]); // // code.google.com/p/glmatrix/wiki/Usage program.uPMatrix = gl.getUniformLocation(program, "uPMatrix"); program.uMVMatrix = gl.getUniformLocation(program, "uMVMatrix"); mat4.perspective(45, gl.viewportWidth / gl.viewportHeight, 1.0, 10.0, pMatrix); mat4.identity(mvMatrix); mat4.translate(mvMatrix, [0.0, -0.25, -1.0]); gl.uniformMatrix4fv(program.uPMatrix, false, pMatrix); gl.uniformMatrix4fv(program.uMVMatrix, false, mvMatrix); // Set the position for the vertex shader program.aVertexPosition = gl.getAttribLocation(program, "aVertexPosition"); gl.enableVertexAttribArray(program.aVertexPosition); gl.vertexAttribPointer(program.aVertexPosition, 3, gl.FLOAT, false, 3*4, 0); // position // Render the Object gl.drawElements(gl.TRIANGLES, 36, gl.UNSIGNED_SHORT, 0); } Thanks in advance for any help

    Read the article

  • Using Html.LabelFor to display human readable label?

    - by Shay Friedman
    I'm using ASP.NET MVC 2 and I'm struggling to understand how can I use the Html.LabelFor helpet method. Assuming I have a model: public class Person { public string FirstName { get; set; } } In my view, if I write: <%: Html.LabelFor(model => model.FirstName) %> What I get on the page is "FirstName". But I don't want that because it's now user-friendly. I want it to be "First Name". How do I achieve that? Thanks.

    Read the article

  • Gridview display multiple tables?

    - by Shawn
    I have a gridview setup that gets its data from a SQL database stored procedure. This procedure will return one of several different tables. The gridview complains if the table is different than the one previously displayed. How do I work around this?

    Read the article

  • Django - Static content display based on URL

    - by Steven Potter
    I'm working on a Django site with a basic three column design. Left column navigation, center column content and right column URL specific content blocks. My question is about the best method of controlling the URL specific content blocks in the right column. I am thinking of something along the lines of the Flatpages app that will make the content available to the template context if the URL matches a pre-determined pattern (perhaps regex?). Does anyone know if such an app already exists? If not, I am looking for some advice about the best way to implement it. Particularly in relation to the matching of patterns to the current URL. Is there any good way to re-use parts of the Django URL dispatcher for this use?

    Read the article

  • i want to display this listview on scrolling

    - by Sasil
    I'm completely stumped on this one. I have three different lists that need to be displayed on the screen. I've tried using a ScrollView with a LinearLayout child, and putting my ListViews in the LinearView, but all of the ListViews lock to a fixed height with scroll bars. Using other kinds of Layouts means no scrolling.

    Read the article

  • how to display numbers without garbage numbers?

    - by Medeti Naveen Kumar
    Hi friends, whenever i press the numbers in text filed upto 9 numbers my textfield has taken right values but i press 10 th number.i have found duplicate number. in my header file i declare a pressnumber is "long long int" -(IBAction)press:(id)sender{ pressNumber = pressNumber*10 + (int)[sender tag]; phonenumber.text = [NSString stringWithFormat:@"%d",currentNumber]; } i want to enter a phone number in my textfiled but it is not taken 10 right numbers. Thanking you,

    Read the article

  • How do Hex editors display data so quickly?

    - by user146780
    I'v created a Notepad-like application and if I load a 1MB file into the textbox, it takes about 1 minute. The Visual Studio Binary editor displays lines, Hex, and ascii versions in a fraction of a second. How do they get the data into the textbox so quickly? Thanks

    Read the article

  • display an array in html table

    - by Davi
    I have this array: Array ( [page] => Array ( [0] => add [1] => edit [2] => delete [3] => search ) [category] => Array ( [0] => add [1] => edit [2] => export ) ) And I want it to be displayed as a html table like this: Page - Category add - add edit - edit delete - export search search I tryed in many ways but didn't work, any solutions? Thank you

    Read the article

  • Display rows from MySQL where a datetime is within the next hour

    - by alex
    I always have trouble with complicated SQL queries. This is what I have $query = ' SELECT id, name, info, date_time FROM acms_events WHERE date_time = DATE_SUB(NOW(), INTERVAL 1 HOUR) AND active = 1 ORDER BY date_time ASC LIMIT 6 '; I want to get up to 6 rows that are upcoming within the hour. Is my query wrong? It does not seem to get events that are upcoming within the next hour when I test it. What is the correct syntax for this? Thanks

    Read the article

  • display image and run script for fifteen seconds

    - by Ryan Max
    This is very similar to a question I asked the other day but my page code has become significantly more complicated and I need to revisit it. I've been using the following code: $('#myLink').click(function() { $('#myImg').attr('src', 'newImg.jpg'); setTimeout(function() { $('#myImg').attr('src', 'oldImg.jpg'); }, 15000); }); To replace an image for a set period of time (15 seconds) when the link is clicked, then after 15 seconds, revert to the original image. However now, I'd like to run a snippet of javascript as well when the link is clicked (in addition to replacing the image), and only when the link is clicked (it's related to the 15 second image) and then have the js code disappear as well after the 15 seconds...however I'm not sure how to have jquery send js code into the page...Basically I just want jQuery to "echo" this code onto the page underneath the 15 second while I am there, but I don't know how jquery formats this "echo". Does this question make sense? interval = 500; imgsrc = "webcam/image.jpg"; function Refresh() { tmp = new Date(); tmp = "?" + tmp.getTime(); document.images["image1"].src = imgsrc + tmp; setTimeout("Refresh()", interval); } Refresh(); It's script for a webcam. Basically it takes a new picture every half a second and replaces it on the page. You must forgive me, I'm new to jquery, I don't know how to make this script work in a jquery context. i'm sorry, I'm explaining badly. This is what I need to happen, step by step: 1) User comes to the page and there is a static image that says "Click here to view webcam" 2) User clicks image 3) Image is replaced by live webcam image, which is refreshed every .5 seconds by the second script in my question. 4) After 15 seconds the live webcam reverts back to the static image saying "click here to view webcam" It is ONLY during that 15 second interval that I wan the webcam refresh script running, otherwise it's wasting bandwidth on an element that isn't even shown. Sorry for the confusion.

    Read the article

< Previous Page | 126 127 128 129 130 131 132 133 134 135 136 137  | Next Page >