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  • Is it possible to cache JSP bytecode to avoid recompiles w/ Tomcat?

    - by Computer Guru
    Hi, Is there any way of caching the bytecode for JSP webapps/ In particular, using Tomcat as the Java servlet? I'm getting really fed up of Tomcat taking up all the CPU for 10 minutes while it compiles 4 different webapps every time I restart it.... I'm already using Jikes to "speed up" the compiles, but it's really killing me. The code does not change unless the webapp is upgraded (very rarely), and I cannot believe that there is no way to cache the compiled java bytecode instead of recompiling it each and every time. I'd appreciate any advice on the matter!

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  • ASP.Net: Is it possible to cache the js-proxies generated by scriptmanager?

    - by AndreasKnudsen
    We have the following code: <asp:ScriptManager runat="server"> ... <Services> <asp:ServiceReference Path="~/JSONServices/ProfileService.svc" /> </Services> ... This results in a Javascript proxy found in /JSONServices/ProfileService.svc/js. This Javascript has content expiry set to the same time it was called (so it is never cached on the client). Is it possible to have the clients cache these proxies for some time?

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  • Cache an FTP connection via session variables for use via AJAX?

    - by Chad Johnson
    I'm working on a Ruby web Application that uses the Net::FTP library. One part of it allows users to interact with an FTP site via AJAX. When the user does something, and AJAX call is made, and then Ruby reconnects to the FTP server, performs an action, and outputs information. Every time the AJAX call is made, Ruby has to reconnect to the FTP server, and that's slow. Is there a way I could cache this FTP connection? I've tried caching in the session hash, but "We're sorry, but something went wrong" is displayed, and a TCP dump is outputted in my logs whenever I attempt to store it in the session hash. I haven't tried memcache yet. Any suggestions?

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  • Is it possible to evaluate a JSP only once per session, and cache it after that?

    - by Bears will eat you
    My site has a nav menu that is dynamically built as a separate JSP, and included in most pages via <jsp:include />. The contents and styling of the menu are determined by which pages the user does and doesn't have access to. The set of accessible pages is retrieved from the database when a user logs in, and not during the course of a session. So, there's really no need to re-evaluate the nav menu code every time the user requests a page. Is there an easy way to generate the markup from the JSP only once per session, and cache/reuse it during the session?

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  • How John Got 15x Improvement Without Really Trying

    - by rchrd
    The following article was published on a Sun Microsystems website a number of years ago by John Feo. It is still useful and worth preserving. So I'm republishing it here.  How I Got 15x Improvement Without Really Trying John Feo, Sun Microsystems Taking ten "personal" program codes used in scientific and engineering research, the author was able to get from 2 to 15 times performance improvement easily by applying some simple general optimization techniques. Introduction Scientific research based on computer simulation depends on the simulation for advancement. The research can advance only as fast as the computational codes can execute. The codes' efficiency determines both the rate and quality of results. In the same amount of time, a faster program can generate more results and can carry out a more detailed simulation of physical phenomena than a slower program. Highly optimized programs help science advance quickly and insure that monies supporting scientific research are used as effectively as possible. Scientific computer codes divide into three broad categories: ISV, community, and personal. ISV codes are large, mature production codes developed and sold commercially. The codes improve slowly over time both in methods and capabilities, and they are well tuned for most vendor platforms. Since the codes are mature and complex, there are few opportunities to improve their performance solely through code optimization. Improvements of 10% to 15% are typical. Examples of ISV codes are DYNA3D, Gaussian, and Nastran. Community codes are non-commercial production codes used by a particular research field. Generally, they are developed and distributed by a single academic or research institution with assistance from the community. Most users just run the codes, but some develop new methods and extensions that feed back into the general release. The codes are available on most vendor platforms. Since these codes are younger than ISV codes, there are more opportunities to optimize the source code. Improvements of 50% are not unusual. Examples of community codes are AMBER, CHARM, BLAST, and FASTA. Personal codes are those written by single users or small research groups for their own use. These codes are not distributed, but may be passed from professor-to-student or student-to-student over several years. They form the primordial ocean of applications from which community and ISV codes emerge. Government research grants pay for the development of most personal codes. This paper reports on the nature and performance of this class of codes. Over the last year, I have looked at over two dozen personal codes from more than a dozen research institutions. The codes cover a variety of scientific fields, including astronomy, atmospheric sciences, bioinformatics, biology, chemistry, geology, and physics. The sources range from a few hundred lines to more than ten thousand lines, and are written in Fortran, Fortran 90, C, and C++. For the most part, the codes are modular, documented, and written in a clear, straightforward manner. They do not use complex language features, advanced data structures, programming tricks, or libraries. I had little trouble understanding what the codes did or how data structures were used. Most came with a makefile. Surprisingly, only one of the applications is parallel. All developers have access to parallel machines, so availability is not an issue. Several tried to parallelize their applications, but stopped after encountering difficulties. Lack of education and a perception that parallelism is difficult prevented most from trying. I parallelized several of the codes using OpenMP, and did not judge any of the codes as difficult to parallelize. Even more surprising than the lack of parallelism is the inefficiency of the codes. I was able to get large improvements in performance in a matter of a few days applying simple optimization techniques. Table 1 lists ten representative codes [names and affiliation are omitted to preserve anonymity]. Improvements on one processor range from 2x to 15.5x with a simple average of 4.75x. I did not use sophisticated performance tools or drill deep into the program's execution character as one would do when tuning ISV or community codes. Using only a profiler and source line timers, I identified inefficient sections of code and improved their performance by inspection. The changes were at a high level. I am sure there is another factor of 2 or 3 in each code, and more if the codes are parallelized. The study’s results show that personal scientific codes are running many times slower than they should and that the problem is pervasive. Computational scientists are not sloppy programmers; however, few are trained in the art of computer programming or code optimization. I found that most have a working knowledge of some programming language and standard software engineering practices; but they do not know, or think about, how to make their programs run faster. They simply do not know the standard techniques used to make codes run faster. In fact, they do not even perceive that such techniques exist. The case studies described in this paper show that applying simple, well known techniques can significantly increase the performance of personal codes. It is important that the scientific community and the Government agencies that support scientific research find ways to better educate academic scientific programmers. The inefficiency of their codes is so bad that it is retarding both the quality and progress of scientific research. # cacheperformance redundantoperations loopstructures performanceimprovement 1 x x 15.5 2 x 2.8 3 x x 2.5 4 x 2.1 5 x x 2.0 6 x 5.0 7 x 5.8 8 x 6.3 9 2.2 10 x x 3.3 Table 1 — Area of improvement and performance gains of 10 codes The remainder of the paper is organized as follows: sections 2, 3, and 4 discuss the three most common sources of inefficiencies in the codes studied. These are cache performance, redundant operations, and loop structures. Each section includes several examples. The last section summaries the work and suggests a possible solution to the issues raised. Optimizing cache performance Commodity microprocessor systems use caches to increase memory bandwidth and reduce memory latencies. Typical latencies from processor to L1, L2, local, and remote memory are 3, 10, 50, and 200 cycles, respectively. Moreover, bandwidth falls off dramatically as memory distances increase. Programs that do not use cache effectively run many times slower than programs that do. When optimizing for cache, the biggest performance gains are achieved by accessing data in cache order and reusing data to amortize the overhead of cache misses. Secondary considerations are prefetching, associativity, and replacement; however, the understanding and analysis required to optimize for the latter are probably beyond the capabilities of the non-expert. Much can be gained simply by accessing data in the correct order and maximizing data reuse. 6 out of the 10 codes studied here benefited from such high level optimizations. Array Accesses The most important cache optimization is the most basic: accessing Fortran array elements in column order and C array elements in row order. Four of the ten codes—1, 2, 4, and 10—got it wrong. Compilers will restructure nested loops to optimize cache performance, but may not do so if the loop structure is too complex, or the loop body includes conditionals, complex addressing, or function calls. In code 1, the compiler failed to invert a key loop because of complex addressing do I = 0, 1010, delta_x IM = I - delta_x IP = I + delta_x do J = 5, 995, delta_x JM = J - delta_x JP = J + delta_x T1 = CA1(IP, J) + CA1(I, JP) T2 = CA1(IM, J) + CA1(I, JM) S1 = T1 + T2 - 4 * CA1(I, J) CA(I, J) = CA1(I, J) + D * S1 end do end do In code 2, the culprit is conditionals do I = 1, N do J = 1, N If (IFLAG(I,J) .EQ. 0) then T1 = Value(I, J-1) T2 = Value(I-1, J) T3 = Value(I, J) T4 = Value(I+1, J) T5 = Value(I, J+1) Value(I,J) = 0.25 * (T1 + T2 + T5 + T4) Delta = ABS(T3 - Value(I,J)) If (Delta .GT. MaxDelta) MaxDelta = Delta endif enddo enddo I fixed both programs by inverting the loops by hand. Code 10 has three-dimensional arrays and triply nested loops. The structure of the most computationally intensive loops is too complex to invert automatically or by hand. The only practical solution is to transpose the arrays so that the dimension accessed by the innermost loop is in cache order. The arrays can be transposed at construction or prior to entering a computationally intensive section of code. The former requires all array references to be modified, while the latter is cost effective only if the cost of the transpose is amortized over many accesses. I used the second approach to optimize code 10. Code 5 has four-dimensional arrays and loops are nested four deep. For all of the reasons cited above the compiler is not able to restructure three key loops. Assume C arrays and let the four dimensions of the arrays be i, j, k, and l. In the original code, the index structure of the three loops is L1: for i L2: for i L3: for i for l for l for j for k for j for k for j for k for l So only L3 accesses array elements in cache order. L1 is a very complex loop—much too complex to invert. I brought the loop into cache alignment by transposing the second and fourth dimensions of the arrays. Since the code uses a macro to compute all array indexes, I effected the transpose at construction and changed the macro appropriately. The dimensions of the new arrays are now: i, l, k, and j. L3 is a simple loop and easily inverted. L2 has a loop-carried scalar dependence in k. By promoting the scalar name that carries the dependence to an array, I was able to invert the third and fourth subloops aligning the loop with cache. Code 5 is by far the most difficult of the four codes to optimize for array accesses; but the knowledge required to fix the problems is no more than that required for the other codes. I would judge this code at the limits of, but not beyond, the capabilities of appropriately trained computational scientists. Array Strides When a cache miss occurs, a line (64 bytes) rather than just one word is loaded into the cache. If data is accessed stride 1, than the cost of the miss is amortized over 8 words. Any stride other than one reduces the cost savings. Two of the ten codes studied suffered from non-unit strides. The codes represent two important classes of "strided" codes. Code 1 employs a multi-grid algorithm to reduce time to convergence. The grids are every tenth, fifth, second, and unit element. Since time to convergence is inversely proportional to the distance between elements, coarse grids converge quickly providing good starting values for finer grids. The better starting values further reduce the time to convergence. The downside is that grids of every nth element, n > 1, introduce non-unit strides into the computation. In the original code, much of the savings of the multi-grid algorithm were lost due to this problem. I eliminated the problem by compressing (copying) coarse grids into continuous memory, and rewriting the computation as a function of the compressed grid. On convergence, I copied the final values of the compressed grid back to the original grid. The savings gained from unit stride access of the compressed grid more than paid for the cost of copying. Using compressed grids, the loop from code 1 included in the previous section becomes do j = 1, GZ do i = 1, GZ T1 = CA(i+0, j-1) + CA(i-1, j+0) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) S1 = T1 + T4 - 4 * CA1(i+0, j+0) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 enddo enddo where CA and CA1 are compressed arrays of size GZ. Code 7 traverses a list of objects selecting objects for later processing. The labels of the selected objects are stored in an array. The selection step has unit stride, but the processing steps have irregular stride. A fix is to save the parameters of the selected objects in temporary arrays as they are selected, and pass the temporary arrays to the processing functions. The fix is practical if the same parameters are used in selection as in processing, or if processing comprises a series of distinct steps which use overlapping subsets of the parameters. Both conditions are true for code 7, so I achieved significant improvement by copying parameters to temporary arrays during selection. Data reuse In the previous sections, we optimized for spatial locality. It is also important to optimize for temporal locality. Once read, a datum should be used as much as possible before it is forced from cache. Loop fusion and loop unrolling are two techniques that increase temporal locality. Unfortunately, both techniques increase register pressure—as loop bodies become larger, the number of registers required to hold temporary values grows. Once register spilling occurs, any gains evaporate quickly. For multiprocessors with small register sets or small caches, the sweet spot can be very small. In the ten codes presented here, I found no opportunities for loop fusion and only two opportunities for loop unrolling (codes 1 and 3). In code 1, unrolling the outer and inner loop one iteration increases the number of result values computed by the loop body from 1 to 4, do J = 1, GZ-2, 2 do I = 1, GZ-2, 2 T1 = CA1(i+0, j-1) + CA1(i-1, j+0) T2 = CA1(i+1, j-1) + CA1(i+0, j+0) T3 = CA1(i+0, j+0) + CA1(i-1, j+1) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) T5 = CA1(i+2, j+0) + CA1(i+1, j+1) T6 = CA1(i+1, j+1) + CA1(i+0, j+2) T7 = CA1(i+2, j+1) + CA1(i+1, j+2) S1 = T1 + T4 - 4 * CA1(i+0, j+0) S2 = T2 + T5 - 4 * CA1(i+1, j+0) S3 = T3 + T6 - 4 * CA1(i+0, j+1) S4 = T4 + T7 - 4 * CA1(i+1, j+1) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 CA(i+1, j+0) = CA1(i+1, j+0) + DD * S2 CA(i+0, j+1) = CA1(i+0, j+1) + DD * S3 CA(i+1, j+1) = CA1(i+1, j+1) + DD * S4 enddo enddo The loop body executes 12 reads, whereas as the rolled loop shown in the previous section executes 20 reads to compute the same four values. In code 3, two loops are unrolled 8 times and one loop is unrolled 4 times. Here is the before for (k = 0; k < NK[u]; k++) { sum = 0.0; for (y = 0; y < NY; y++) { sum += W[y][u][k] * delta[y]; } backprop[i++]=sum; } and after code for (k = 0; k < KK - 8; k+=8) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (y = 0; y < NY; y++) { sum0 += W[y][0][k+0] * delta[y]; sum1 += W[y][0][k+1] * delta[y]; sum2 += W[y][0][k+2] * delta[y]; sum3 += W[y][0][k+3] * delta[y]; sum4 += W[y][0][k+4] * delta[y]; sum5 += W[y][0][k+5] * delta[y]; sum6 += W[y][0][k+6] * delta[y]; sum7 += W[y][0][k+7] * delta[y]; } backprop[k+0] = sum0; backprop[k+1] = sum1; backprop[k+2] = sum2; backprop[k+3] = sum3; backprop[k+4] = sum4; backprop[k+5] = sum5; backprop[k+6] = sum6; backprop[k+7] = sum7; } for one of the loops unrolled 8 times. Optimizing for temporal locality is the most difficult optimization considered in this paper. The concepts are not difficult, but the sweet spot is small. Identifying where the program can benefit from loop unrolling or loop fusion is not trivial. Moreover, it takes some effort to get it right. Still, educating scientific programmers about temporal locality and teaching them how to optimize for it will pay dividends. Reducing instruction count Execution time is a function of instruction count. Reduce the count and you usually reduce the time. The best solution is to use a more efficient algorithm; that is, an algorithm whose order of complexity is smaller, that converges quicker, or is more accurate. Optimizing source code without changing the algorithm yields smaller, but still significant, gains. This paper considers only the latter because the intent is to study how much better codes can run if written by programmers schooled in basic code optimization techniques. The ten codes studied benefited from three types of "instruction reducing" optimizations. The two most prevalent were hoisting invariant memory and data operations out of inner loops. The third was eliminating unnecessary data copying. The nature of these inefficiencies is language dependent. Memory operations The semantics of C make it difficult for the compiler to determine all the invariant memory operations in a loop. The problem is particularly acute for loops in functions since the compiler may not know the values of the function's parameters at every call site when compiling the function. Most compilers support pragmas to help resolve ambiguities; however, these pragmas are not comprehensive and there is no standard syntax. To guarantee that invariant memory operations are not executed repetitively, the user has little choice but to hoist the operations by hand. The problem is not as severe in Fortran programs because in the absence of equivalence statements, it is a violation of the language's semantics for two names to share memory. Codes 3 and 5 are C programs. In both cases, the compiler did not hoist all invariant memory operations from inner loops. Consider the following loop from code 3 for (y = 0; y < NY; y++) { i = 0; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += delta[y] * I1[i++]; } } } Since dW[y][u] can point to the same memory space as delta for one or more values of y and u, assignment to dW[y][u][k] may change the value of delta[y]. In reality, dW and delta do not overlap in memory, so I rewrote the loop as for (y = 0; y < NY; y++) { i = 0; Dy = delta[y]; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += Dy * I1[i++]; } } } Failure to hoist invariant memory operations may be due to complex address calculations. If the compiler can not determine that the address calculation is invariant, then it can hoist neither the calculation nor the associated memory operations. As noted above, code 5 uses a macro to address four-dimensional arrays #define MAT4D(a,q,i,j,k) (double *)((a)->data + (q)*(a)->strides[0] + (i)*(a)->strides[3] + (j)*(a)->strides[2] + (k)*(a)->strides[1]) The macro is too complex for the compiler to understand and so, it does not identify any subexpressions as loop invariant. The simplest way to eliminate the address calculation from the innermost loop (over i) is to define a0 = MAT4D(a,q,0,j,k) before the loop and then replace all instances of *MAT4D(a,q,i,j,k) in the loop with a0[i] A similar problem appears in code 6, a Fortran program. The key loop in this program is do n1 = 1, nh nx1 = (n1 - 1) / nz + 1 nz1 = n1 - nz * (nx1 - 1) do n2 = 1, nh nx2 = (n2 - 1) / nz + 1 nz2 = n2 - nz * (nx2 - 1) ndx = nx2 - nx1 ndy = nz2 - nz1 gxx = grn(1,ndx,ndy) gyy = grn(2,ndx,ndy) gxy = grn(3,ndx,ndy) balance(n1,1) = balance(n1,1) + (force(n2,1) * gxx + force(n2,2) * gxy) * h1 balance(n1,2) = balance(n1,2) + (force(n2,1) * gxy + force(n2,2) * gyy)*h1 end do end do The programmer has written this loop well—there are no loop invariant operations with respect to n1 and n2. However, the loop resides within an iterative loop over time and the index calculations are independent with respect to time. Trading space for time, I precomputed the index values prior to the entering the time loop and stored the values in two arrays. I then replaced the index calculations with reads of the arrays. Data operations Ways to reduce data operations can appear in many forms. Implementing a more efficient algorithm produces the biggest gains. The closest I came to an algorithm change was in code 4. This code computes the inner product of K-vectors A(i) and B(j), 0 = i < N, 0 = j < M, for most values of i and j. Since the program computes most of the NM possible inner products, it is more efficient to compute all the inner products in one triply-nested loop rather than one at a time when needed. The savings accrue from reading A(i) once for all B(j) vectors and from loop unrolling. for (i = 0; i < N; i+=8) { for (j = 0; j < M; j++) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (k = 0; k < K; k++) { sum0 += A[i+0][k] * B[j][k]; sum1 += A[i+1][k] * B[j][k]; sum2 += A[i+2][k] * B[j][k]; sum3 += A[i+3][k] * B[j][k]; sum4 += A[i+4][k] * B[j][k]; sum5 += A[i+5][k] * B[j][k]; sum6 += A[i+6][k] * B[j][k]; sum7 += A[i+7][k] * B[j][k]; } C[i+0][j] = sum0; C[i+1][j] = sum1; C[i+2][j] = sum2; C[i+3][j] = sum3; C[i+4][j] = sum4; C[i+5][j] = sum5; C[i+6][j] = sum6; C[i+7][j] = sum7; }} This change requires knowledge of a typical run; i.e., that most inner products are computed. The reasons for the change, however, derive from basic optimization concepts. It is the type of change easily made at development time by a knowledgeable programmer. In code 5, we have the data version of the index optimization in code 6. Here a very expensive computation is a function of the loop indices and so cannot be hoisted out of the loop; however, the computation is invariant with respect to an outer iterative loop over time. We can compute its value for each iteration of the computation loop prior to entering the time loop and save the values in an array. The increase in memory required to store the values is small in comparison to the large savings in time. The main loop in Code 8 is doubly nested. The inner loop includes a series of guarded computations; some are a function of the inner loop index but not the outer loop index while others are a function of the outer loop index but not the inner loop index for (j = 0; j < N; j++) { for (i = 0; i < M; i++) { r = i * hrmax; R = A[j]; temp = (PRM[3] == 0.0) ? 1.0 : pow(r, PRM[3]); high = temp * kcoeff * B[j] * PRM[2] * PRM[4]; low = high * PRM[6] * PRM[6] / (1.0 + pow(PRM[4] * PRM[6], 2.0)); kap = (R > PRM[6]) ? high * R * R / (1.0 + pow(PRM[4]*r, 2.0) : low * pow(R/PRM[6], PRM[5]); < rest of loop omitted > }} Note that the value of temp is invariant to j. Thus, we can hoist the computation for temp out of the loop and save its values in an array. for (i = 0; i < M; i++) { r = i * hrmax; TEMP[i] = pow(r, PRM[3]); } [N.B. – the case for PRM[3] = 0 is omitted and will be reintroduced later.] We now hoist out of the inner loop the computations invariant to i. Since the conditional guarding the value of kap is invariant to i, it behooves us to hoist the computation out of the inner loop, thereby executing the guard once rather than M times. The final version of the code is for (j = 0; j < N; j++) { R = rig[j] / 1000.; tmp1 = kcoeff * par[2] * beta[j] * par[4]; tmp2 = 1.0 + (par[4] * par[4] * par[6] * par[6]); tmp3 = 1.0 + (par[4] * par[4] * R * R); tmp4 = par[6] * par[6] / tmp2; tmp5 = R * R / tmp3; tmp6 = pow(R / par[6], par[5]); if ((par[3] == 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp5; } else if ((par[3] == 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp4 * tmp6; } else if ((par[3] != 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp5; } else if ((par[3] != 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp4 * tmp6; } for (i = 0; i < M; i++) { kap = KAP[i]; r = i * hrmax; < rest of loop omitted > } } Maybe not the prettiest piece of code, but certainly much more efficient than the original loop, Copy operations Several programs unnecessarily copy data from one data structure to another. This problem occurs in both Fortran and C programs, although it manifests itself differently in the two languages. Code 1 declares two arrays—one for old values and one for new values. At the end of each iteration, the array of new values is copied to the array of old values to reset the data structures for the next iteration. This problem occurs in Fortran programs not included in this study and in both Fortran 77 and Fortran 90 code. Introducing pointers to the arrays and swapping pointer values is an obvious way to eliminate the copying; but pointers is not a feature that many Fortran programmers know well or are comfortable using. An easy solution not involving pointers is to extend the dimension of the value array by 1 and use the last dimension to differentiate between arrays at different times. For example, if the data space is N x N, declare the array (N, N, 2). Then store the problem’s initial values in (_, _, 2) and define the scalar names new = 2 and old = 1. At the start of each iteration, swap old and new to reset the arrays. The old–new copy problem did not appear in any C program. In programs that had new and old values, the code swapped pointers to reset data structures. Where unnecessary coping did occur is in structure assignment and parameter passing. Structures in C are handled much like scalars. Assignment causes the data space of the right-hand name to be copied to the data space of the left-hand name. Similarly, when a structure is passed to a function, the data space of the actual parameter is copied to the data space of the formal parameter. If the structure is large and the assignment or function call is in an inner loop, then copying costs can grow quite large. While none of the ten programs considered here manifested this problem, it did occur in programs not included in the study. A simple fix is always to refer to structures via pointers. Optimizing loop structures Since scientific programs spend almost all their time in loops, efficient loops are the key to good performance. Conditionals, function calls, little instruction level parallelism, and large numbers of temporary values make it difficult for the compiler to generate tightly packed, highly efficient code. Conditionals and function calls introduce jumps that disrupt code flow. Users should eliminate or isolate conditionls to their own loops as much as possible. Often logical expressions can be substituted for if-then-else statements. For example, code 2 includes the following snippet MaxDelta = 0.0 do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) if (Delta > MaxDelta) MaxDelta = Delta enddo enddo if (MaxDelta .gt. 0.001) goto 200 Since the only use of MaxDelta is to control the jump to 200 and all that matters is whether or not it is greater than 0.001, I made MaxDelta a boolean and rewrote the snippet as MaxDelta = .false. do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) MaxDelta = MaxDelta .or. (Delta .gt. 0.001) enddo enddo if (MaxDelta) goto 200 thereby, eliminating the conditional expression from the inner loop. A microprocessor can execute many instructions per instruction cycle. Typically, it can execute one or more memory, floating point, integer, and jump operations. To be executed simultaneously, the operations must be independent. Thick loops tend to have more instruction level parallelism than thin loops. Moreover, they reduce memory traffice by maximizing data reuse. Loop unrolling and loop fusion are two techniques to increase the size of loop bodies. Several of the codes studied benefitted from loop unrolling, but none benefitted from loop fusion. This observation is not too surpising since it is the general tendency of programmers to write thick loops. As loops become thicker, the number of temporary values grows, increasing register pressure. If registers spill, then memory traffic increases and code flow is disrupted. A thick loop with many temporary values may execute slower than an equivalent series of thin loops. The biggest gain will be achieved if the thick loop can be split into a series of independent loops eliminating the need to write and read temporary arrays. I found such an occasion in code 10 where I split the loop do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do into two disjoint loops do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) end do end do do i = 1, n do j = 1, m C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do Conclusions Over the course of the last year, I have had the opportunity to work with over two dozen academic scientific programmers at leading research universities. Their research interests span a broad range of scientific fields. Except for two programs that relied almost exclusively on library routines (matrix multiply and fast Fourier transform), I was able to improve significantly the single processor performance of all codes. Improvements range from 2x to 15.5x with a simple average of 4.75x. Changes to the source code were at a very high level. I did not use sophisticated techniques or programming tools to discover inefficiencies or effect the changes. Only one code was parallel despite the availability of parallel systems to all developers. Clearly, we have a problem—personal scientific research codes are highly inefficient and not running parallel. The developers are unaware of simple optimization techniques to make programs run faster. They lack education in the art of code optimization and parallel programming. I do not believe we can fix the problem by publishing additional books or training manuals. To date, the developers in questions have not studied the books or manual available, and are unlikely to do so in the future. Short courses are a possible solution, but I believe they are too concentrated to be much use. The general concepts can be taught in a three or four day course, but that is not enough time for students to practice what they learn and acquire the experience to apply and extend the concepts to their codes. Practice is the key to becoming proficient at optimization. I recommend that graduate students be required to take a semester length course in optimization and parallel programming. We would never give someone access to state-of-the-art scientific equipment costing hundreds of thousands of dollars without first requiring them to demonstrate that they know how to use the equipment. Yet the criterion for time on state-of-the-art supercomputers is at most an interesting project. Requestors are never asked to demonstrate that they know how to use the system, or can use the system effectively. A semester course would teach them the required skills. Government agencies that fund academic scientific research pay for most of the computer systems supporting scientific research as well as the development of most personal scientific codes. These agencies should require graduate schools to offer a course in optimization and parallel programming as a requirement for funding. About the Author John Feo received his Ph.D. in Computer Science from The University of Texas at Austin in 1986. After graduate school, Dr. Feo worked at Lawrence Livermore National Laboratory where he was the Group Leader of the Computer Research Group and principal investigator of the Sisal Language Project. In 1997, Dr. Feo joined Tera Computer Company where he was project manager for the MTA, and oversaw the programming and evaluation of the MTA at the San Diego Supercomputer Center. In 2000, Dr. Feo joined Sun Microsystems as an HPC application specialist. He works with university research groups to optimize and parallelize scientific codes. Dr. Feo has published over two dozen research articles in the areas of parallel parallel programming, parallel programming languages, and application performance.

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  • Remove partition for failed installation

    - by kapitanluffy
    i tried installing ubuntu alongside windows 7 Installing Ubuntu alongside Windows and i failed so i decided to go with wubi again. after installing it, i noticed a separate hard disk. i investigated and found out that this hard disk is actually for the failed installation. i don't know where to find it inside the windows system. can anyone please teach me how to remove the 'failed' hard disk. here's a screenshot the left side is the current filesystem. the right side on the other hand is the 'failed' harddisk. i verified that it is the failed one because the wubi installation will provide a 'host' folder for the current partition it is currently installed. i tried looking for the 'failed' one using the windows' commandline but i don't know where to look for the 'failed' disk. (i used the cmd coz i don't want root.disk to mysteriously disappear again.) see http://ubuntu-with-wubi.blogspot.com/2011/01/mystery-of-disappearing-rootdisk.html

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  • remove failed ubuntu installation

    - by kapitanluffy
    i tried installing ubuntu alongside windows 7 Installing Ubuntu alongside Windows and i failed so i decided to go with wubi again. after installing it, i noticed a separate hard disk. i investigated and found out that this hard disk is actually for the failed installation. i don't know where to find it inside the windows system. can anyone please teach me how to remove the 'failed' hard disk. here's a screenshot the left side is the current filesystem. the right side on the other hand is the 'failed' harddisk. i verified that it is the failed one because the wubi installation will provide a 'host' folder for the current partition it is currently installed. i tried looking for the 'failed' one using the windows' commandline but i don't know where to look for the 'failed' disk. (i used the cmd coz i don't want root.disk to mysteriously disappear again.) see http://ubuntu-with-wubi.blogspot.com/2011/01/mystery-of-disappearing-rootdisk.html

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  • Error MSB4019: The imported project "C:\Program Files\MSBuild\Microsoft\VisualStudio\v10.0\WebApplications\Microsoft.WebApplication.targets" was not found. Confirm that the path in the <Import> declaration is correct, and that the file exists on disk

    - by Tim Huffam
    This error occurred on our TFS2008 build server which we had upgraded to cater for VS2010 projects (by installing VS2010 on the build server - see this article). Error MSB4019: The imported project "C:\Program Files\MSBuild\Microsoft\VisualStudio\v10.0\WebApplications\Microsoft.WebApplication.targets" was not found. Confirm that the path in the <Import> declaration is correct, and that the file exists on disk. However - although we had installed VS2010 on the build server - we had not installed the web development components (Visual Web Developer) - this is what caused the error. To fix - simply add the web development components: Go into Control Panel - Add or Remove Programs Select Microsoft Visual Studio 2010, and click on Change/Remove In the VS Maintenance Mode screens, select Add or Remove Features In the Setup - Options page make sure 'Visual Web Developer' is checked. Click on Update.   You shouldn't need to restart your build service. HTH Tim

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  • Installing Ubuntu 12.04.1 x64 with Fake RAID 1 [SOLVED]

    - by Arkadius
    I had: Software: Dual boot with Windows XP Ubuntu 10.04 LTS x32 Hardware Fake RAID 1 (mirroring) with 2x1 TB: Partition 1 - Windows Partition 2 - SWAP Partition 3 - / (root) Partition 4 - Extended Partition 5 - /home Partition 6 - /data arek@domek:/var/log/installer$ sudo fdisk -l Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de1b9 Device Boot Start End Blocks Id System /dev/sda1 * 63 524297339 262148638+ 7 HPFS/NTFS/exFAT /dev/sda2 524297340 528506369 2104515 82 Linux swap / Solaris /dev/sda3 528506370 570468149 20980890 83 Linux /dev/sda4 570468150 1953118439 691325145 5 Extended /dev/sda5 570468213 675340469 52436128+ 83 Linux /dev/sda6 675340533 1953118439 638888953+ 83 Linux Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de1b9 Device Boot Start End Blocks Id System /dev/sdb1 * 63 524297339 262148638+ 7 HPFS/NTFS/exFAT /dev/sdb2 524297340 528506369 2104515 82 Linux swap / Solaris /dev/sdb3 528506370 570468149 20980890 83 Linux /dev/sdb4 570468150 1953118439 691325145 5 Extended /dev/sdb5 570468213 675340469 52436128+ 83 Linux /dev/sdb6 675340533 1953118439 638888953+ 83 Linux arek@domek:/var/log/installer$ ls -l /dev/mapper/ total 0 crw------- 1 root root 10, 236 Oct 7 20:17 control lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha -> ../dm-0 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha1 -> ../dm-1 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha2 -> ../dm-2 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha3 -> ../dm-3 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha4 -> ../dm-4 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha5 -> ../dm-5 lrwxrwxrwx 1 root root 7 Oct 7 20:17 pdc_jhjbcaha6 -> ../dm-6 I wanted to upgrade from 10.04 x32 to 12.04 x64 using FRESH installation. So, run installation of Ubuntu 12.04.1 x64 LTS using alternate CD. During the installation I selected manual partitioning and to: - Use and Format / (root) - Use and Format SWAP - Use and Keep data on /home - Use and Keep data on /data After I clicked "Continue" I get error creating and formatting SWAP partition. I go to terminal with Alt + F2 (?) and hit enter. I discovered that there was visible RAID as only disk with NO partitions. Something like this: arek@domek:/var/log/installer$ ls -l /dev/mapper/ lrwxrwxrwx 1 root root 7 Oct 7 20:17 /dev/mapper/pdc_jhjbcaha -> ../dm-0 arek@domek:/var/log/installer$ ls -l /dev/dm* brw-rw---- 1 root disk 252, 0 Oct 7 20:17 /dev/dm-0 So I switched to log console Alt+F3 (?) and saw errors like below: Oct 7 14:02:45 check-missing-firmware: /dev/.udev/firmware-missing does not exist, skipping Oct 7 14:02:45 check-missing-firmware: /run/udev/firmware-missing does not exist, skipping Oct 7 14:02:45 check-missing-firmware: no missing firmware in /dev/.udev/firmware-missing /run/udev/firmware-missing Oct 7 14:02:45 anna-install: Installing dmraid-udeb Oct 7 14:02:45 anna[12599]: DEBUG: retrieving dmraid-udeb 1.0.0.rc16-4.1ubuntu8 Oct 7 14:02:49 anna[12599]: DEBUG: retrieving libdmraid1.0.0.rc16-udeb 1.0.0.rc16-4.1ubuntu8 Oct 7 14:02:49 anna[12599]: DEBUG: retrieving kpartx-udeb 0.4.9-3ubuntu5 Oct 7 14:02:49 disk-detect: Serial ATA RAID disk(s) detected. Oct 7 14:02:55 disk-detect: Enabling dmraid support. Oct 7 14:02:55 disk-detect: RAID set "pdc_jhjbcaha" was activated Oct 7 14:02:55 HERE --> dmraid-activate: ERROR: Cannot retrieve RAID set information for pdc_jhjbcaha Oct 7 14:02:56 check-missing-firmware: /dev/.udev/firmware-missing does not exist, skipping Oct 7 14:02:56 check-missing-firmware: /run/udev/firmware-missing does not exist, skipping Oct 7 14:02:56 check-missing-firmware: no missing firmware in /dev/.udev/firmware-missing /run/udev/firmware-missing Oct 7 14:02:57 main-menu[428]: DEBUG: resolver (libnewt0.52): package doesn't exist (ignored) Oct 7 14:02:57 main-menu[428]: DEBUG: resolver (ext2-modules): package doesn't exist (ignored) Oct 7 14:02:57 main-menu[428]: INFO: Menu item 'partman-base' selected Oct 7 14:02:57 kernel: [ 316.512999] NTFS driver 2.1.30 [Flags: R/O MODULE]. Oct 7 14:02:57 kernel: [ 316.523221] Btrfs loaded Oct 7 14:02:57 kernel: [ 316.534781] JFS: nTxBlock = 8192, nTxLock = 65536 Oct 7 14:02:57 kernel: [ 316.554749] SGI XFS with ACLs, security attributes, realtime, large block/inode numbers, no debug enabled Oct 7 14:02:57 kernel: [ 316.555336] SGI XFS Quota Management subsystem Oct 7 14:02:58 md-devices: mdadm: No arrays found in config file or automatically Oct 7 14:02:58 partman: No matching physical volumes found Oct 7 14:02:58 partman: No volume groups found Oct 7 14:02:58 partman: Reading all physical volumes. This may take a while... Oct 7 14:02:58 partman-lvm: No volume groups found Oct 7 14:02:58 partman: Error running 'tune2fs -l /dev/mapper/pdc_jhjbcaha' Oct 7 14:02:58 partman: Error running 'tune2fs -l /dev/mapper/pdc_jhjbcaha' Oct 7 14:02:58 partman: Error running 'tune2fs -l /dev/mapper/pdc_jhjbcaha' Oct 7 14:06:11 HERE --> partman: mkswap: can't open '/dev/mapper/pdc_jhjbcaha2': No such file or directory Oct 7 14:07:28 init: starting pid 401, tty '/dev/tty2': '-/bin/sh' Oct 7 14:15:00 net/hw-detect.hotplug: Detected hotpluggable network interface eth0 Oct 7 14:15:00 net/hw-detect.hotplug: Detected hotpluggable network interface lo As You can see there are 2 errors Oct 7 14:02:55 dmraid-activate: ERROR: Cannot retrieve RAID set information for pdc_jhjbcaha and Oct 7 14:06:11 partman: mkswap: can't open '/dev/mapper/pdc_jhjbcaha2': No such file or directory I looked in the internet and try to run command "dmraid -ay" and get something like that: dmraid -ay /dev/mapper/pdc_jhjbcaha -> Already activated /dev/mapper/pdc_jhjbcaha1 -> Successfully activated /dev/mapper/pdc_jhjbcaha2 -> Successfully activated /dev/mapper/pdc_jhjbcaha3 -> Successfully activated /dev/mapper/pdc_jhjbcaha4 -> Successfully activated /dev/mapper/pdc_jhjbcaha5 -> Successfully activated /dev/mapper/pdc_jhjbcaha6 -> Successfully activated Then I returned to installer with Alt+F1 (?) and click "Return" to return to partitioning menu. I did NOT change anything just selected again "Continue" and everything goes smoothly. I hope this will help someone. arkadius

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  • How do I take an image/backup of Ubuntu partition and restore to VirtualBox VM

    - by whizkid
    I have Ubuntu 10.04 installed on an older hard disk. I recently bought a new disk and already installed Windows 7. I dont want to use the older disk anymore, and I would like to keep on using Ubuntu in a virtual machine on the new disk(to avoid the possible mess-ups of dual boot and I found VirtualBox is the best free tool for this). I wish to keep the exact same data\programs\configurations\settings I had been using in Ubuntu for so long, and avoid the tedious part of having to reconfigure so many things. How do I backup\restore Ubuntu to another disk? I would prefer a free tool to do the backup\restore.

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  • How to use more than 3 virtual disks in Linux using CentOS and XenServer

    - by 010110110101
    I've attached 5 virtual disks to a Virtual Machine in Citrix XenServer. The VM has the xs-tools installed. Initially it said that it couldn't add so many disks. After I installed the xs-tools, it let me add all the disks. But /dev doesn't show all the disks. It shows these: /dev/xvda /dev/xvdb /dev/xvdc /dev/cdrom Perhaps it is bound by the limits of an IDE bus? (3 disks + CD-ROM) If so, how does one change the VM to use SCSI? Edit: According to the documentation: 2.6.3. VM Block Devices In the PV Linux case, block devices are passed through as PV devices. XenServer does not attempt to emulate SCSI or IDE, but instead provides a more suitable interface in the virtual environment in the form of xvd* devices. It is also possible to get an sd* device using the same mechanism, where the PV driver inside the VM takes over the SCSI device namespace. This is not desirable so it is best to use xvd* where possible for PV guests (this is the default for Debian and RHEL). For Windows or other fully virtualized guests, XenServer emulates an IDE bus in the form of an hd* device. When using Windows, installing the Citrix Tools for Virtual Machines installs a special PV driver that works in a similar way to Linux, except in the fully virtualized environment. Still, with 5 virtual disks attached, I don't see the other xvd devices. Edit #2: (attached requested info) Host Machine: XenServer 6.1 Linux version 2.6.32.43-0.4.1.xs1.6.10.777.170770xen (geeko@buildhost) (gcc version 4.1.2 20080704 (Red Hat 4.1.2-51)) #1 SMP Wed Apr 17 05:52:03 EDT 2013 Guest Machine: CentOS release 6.4 (Final) Linux version 2.6.32-358.6.2.el6.x86_64 ([email protected]) (gcc version 4.4.7 20120313 (Red Hat 4.4.7-3) (GCC) ) #1 SMP Thu May 16 20:59:36 UTC 2013 Output of 'fdisk -l' on Guest Machine: Note, the disk beyond the first 3 attached are not displaying -- there should be 4 100GB disks. (There are a total of 5 disks displayed in XenCenter -- 16GB, 100GB, 100GB, 100GB, 100GB) Disk /dev/xvdb: 107.4 GB, 107374182400 bytes 255 heads, 63 sectors/track, 13054 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xfb6c95b9 Device Boot Start End Blocks Id System /dev/xvdb1 1 13054 104856223+ 83 Linux Disk /dev/xvda: 17.2 GB, 17179869184 bytes 255 heads, 63 sectors/track, 2088 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000e5f41 Device Boot Start End Blocks Id System /dev/xvda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/xvda2 64 2089 16264192 8e Linux LVM Disk /dev/xvdc: 107.4 GB, 107374182400 bytes 255 heads, 63 sectors/track, 13054 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xed249ced Device Boot Start End Blocks Id System /dev/xvdc1 1 13054 104856223+ 83 Linux Disk /dev/mapper/vg_blue-lv_root: 14.6 GB, 14571012096 bytes 255 heads, 63 sectors/track, 1771 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/vg_blue-lv_swap: 2080 MB, 2080374784 bytes 255 heads, 63 sectors/track, 252 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 I see that the Linux versions say SMP. The Guest VM doesn't say "xen" in the name. However, I have already run yum install kernel-xen. Could be a clue?

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  • Removing mdadm array and converting to regular disks while preserving data

    - by Jeffrey Kevin Pry
    I have a 6 disk (2TB each) mdadm RAID 5 volume created in Ubuntu 12.04 Server. However, I'm moving to a different solution and want to "unraid" my disks but keep the data. Only 50% is in use. From what I can surmise I basically have to do this recursively for each physical disk. Fail the disk Format the failed disk Move a portion of files to the new disk. Reshape the array Shrink the logical volume md0 This seems like a very time consuming process. Is there an easier way to do this (automatically perhaps) without buying new disks to temporarily hold the data? I am also aware that during this processing my RAID volume will be degraded and vulnerable the entire time. I am not too concerned about this and will be using battery backup and moving the most important files off first. Thank you for your help!

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  • I/O errors are reported when I try to install Ubuntu, but the SMART data is good. Is my hard disk dying?

    - by James
    When I try to install linux, it tells me there is an input output error on dev sda. I have tried both Ubuntu and Mint on two different computers. So that narrows it down to the hdd. After hours of googling and trying different things I tried making the hardrive ext4 with gparted but that comes up with an error. This makes me think that the hdd is bad. There are a few reasons I think the hdd isn't bad. I can use the hdd in windows fully. Windows and gparted disk health checks both say it is fine. Its SMART data is all good. So... help?

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  • Why don't I have the option ''Install Ubuntu alongside with them''

    - by almqgh
    Why dont I have this option? here are my disk sudo fdisk -l Disk /dev/sda: 640.1 GB, 640135028736 bytes 255 heads, 63 sectors/track, 77825 cylinders, total 1250263728 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x5b53cc54 Device Boot Start End Blocks Id System /dev/sda1 * 2048 409599 203776 7 HPFS/NTFS/exFAT /dev/sda2 409600 1153767021 576678711 7 HPFS/NTFS/exFAT /dev/sda3 1216962560 1250050047 16543744 7 HPFS/NTFS/exFAT /dev/sda4 1250050048 1250261679 105816 c W95 FAT32 (LBA) Disk /dev/sdb: 4005 MB, 4005527552 bytes 32 heads, 63 sectors/track, 3880 cylinders, total 7823296 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x20d8782d Device Boot Start End Blocks Id System /dev/sdb1 * 63 7822079 3911008+ c W95 FAT32 (LBA)

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  • Best tool to understand source

    - by cache
    I have a source code for a project. I am working on porting it to another device as the current source code is for a linux environment. I am having some error on the newly ported code. So i was thinking it would be best to once again understand the whole source code and this will help me localise the errors. Now the problem is that i tried using 'gdb' for linux to debug the code but it does not help. So is there any tool that I can use to trace the program line by line ? By doing so i can understand the program flow. Please Help !

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  • Grub not showing installed kernels

    - by Markus
    Although I have several kernel versions in /boot and having them in my grub.cfg, they are not displayed in the grub boot menu. Running update-grub seems to work, as it puts the kernels in the grub.cfg in /boot/grub. Issueing it gives the following output: Generating grub.cfg ... cat: /boot/grub/video.lst: Datei oder Verzeichnis nicht gefunden Found linux image: /boot/vmlinuz-3.2.0-31-generic Found initrd image: /boot/initrd.img-3.2.0-31-generic /usr/sbin/grub-probe: Fehler: no such disk. /usr/sbin/grub-probe: Fehler: no such disk. Found linux image: /boot/vmlinuz-3.2.0-30-generic Found initrd image: /boot/initrd.img-3.2.0-30-generic /usr/sbin/grub-probe: Fehler: no such disk. /usr/sbin/grub-probe: Fehler: no such disk. /usr/sbin/grub-probe: Fehler: no such disk. done I don't know how to fix that problem. Reinstalling grub via live cd did not help.

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  • What is the best freeware app for Windows to mount EXT4 partitions (from a GPT 4TB Disk) as RW, safely without corrupting the EXT4 partition?

    - by Bran
    My Computer is set up as Dualboot Windows and Ubuntu. I have 1 OS drive, and 1 hard drive with a /backup partition (which has all my family photos and data) and it is ext4. Also note... it is EXT4, and it is GPT, and it is 4TB size. Anyway, Windows can not mount the /backup ext4 partition. What software/freeware do you reccomend for Windows? Preferrably looking for someone with experiance using it for a long time and not have problems with EXT4 partition which is a 4TB, GPT Disk. Thank you for your advice and guidance! Always, appreciate everyones help at askubuntu, you guys are the best. Any ideas?

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  • Win7 Bluescreen: IRQ_NOT_LESS_OR_EQUAL | athrxusb.sys

    - by wretrOvian
    Hi I'd left my system on last night, and found the bluescreen in the morning. This has been happening occasionally, over the past few days. Details: ================================================== Dump File : 022710-18236-01.dmp Crash Time : 2/27/2010 8:46:44 AM Bug Check String : DRIVER_IRQL_NOT_LESS_OR_EQUAL Bug Check Code : 0x000000d1 Parameter 1 : 00000000`00001001 Parameter 2 : 00000000`00000002 Parameter 3 : 00000000`00000000 Parameter 4 : fffff880`06b5c0e1 Caused By Driver : athrxusb.sys Caused By Address : athrxusb.sys+760e1 File Description : Product Name : Company : File Version : Processor : x64 Computer Name : Full Path : C:\Windows\minidump\022710-18236-01.dmp Processors Count : 2 Major Version : 15 Minor Version : 7600 ================================================== HiJackThis ("[...]" indicates removed text; full log posted to pastebin): Logfile of Trend Micro HijackThis v2.0.2 Scan saved at 8:49:15 AM, on 2/27/2010 Platform: Unknown Windows (WinNT 6.01.3504) MSIE: Internet Explorer v8.00 (8.00.7600.16385) Boot mode: Normal Running processes: C:\Windows\DAODx.exe C:\Program Files (x86)\ASUS\EPU\EPU.exe C:\Program Files\ASUS\TurboV\TurboV.exe C:\Program Files (x86)\PowerISO\PWRISOVM.EXE C:\Program Files (x86)\OpenOffice.org 3\program\soffice.exe C:\Program Files (x86)\OpenOffice.org 3\program\soffice.bin D:\Downloads\HijackThis.exe C:\Program Files (x86)\uTorrent\uTorrent.exe R1 - HKCU\Software\Microsoft\Internet Explorer\[...] [...] O2 - BHO: Java(tm) Plug-In 2 SSV Helper - {DBC80044-A445-435b-BC74-9C25C1C588A9} - C:\Program Files (x86)\Java\jre6\bin\jp2ssv.dll O4 - HKLM\..\Run: [HDAudDeck] C:\Program Files (x86)\VIA\VIAudioi\VDeck\VDeck.exe -r O4 - HKLM\..\Run: [StartCCC] "C:\Program Files (x86)\ATI Technologies\ATI.ACE\Core-Static\CLIStart.exe" MSRun O4 - HKLM\..\Run: [TurboV] "C:\Program Files\ASUS\TurboV\TurboV.exe" O4 - HKLM\..\Run: [PWRISOVM.EXE] C:\Program Files (x86)\PowerISO\PWRISOVM.EXE O4 - HKLM\..\Run: [googletalk] C:\Program Files (x86)\Google\Google Talk\googletalk.exe /autostart O4 - HKLM\..\Run: [AdobeCS4ServiceManager] "C:\Program Files (x86)\Common Files\Adobe\CS4ServiceManager\CS4ServiceManager.exe" -launchedbylogin O4 - HKCU\..\Run: [uTorrent] "C:\Program Files (x86)\uTorrent\uTorrent.exe" O4 - HKUS\S-1-5-19\..\Run: [Sidebar] %ProgramFiles%\Windows Sidebar\Sidebar.exe /autoRun (User 'LOCAL SERVICE') O4 - HKUS\S-1-5-19\..\RunOnce: [mctadmin] C:\Windows\System32\mctadmin.exe (User 'LOCAL SERVICE') O4 - HKUS\S-1-5-20\..\Run: [Sidebar] %ProgramFiles%\Windows Sidebar\Sidebar.exe /autoRun (User 'NETWORK SERVICE') O4 - HKUS\S-1-5-20\..\RunOnce: [mctadmin] C:\Windows\System32\mctadmin.exe (User 'NETWORK SERVICE') O4 - Startup: OpenOffice.org 3.1.lnk = C:\Program Files (x86)\OpenOffice.org 3\program\quickstart.exe O13 - Gopher Prefix: O23 - Service: @%SystemRoot%\system32\Alg.exe,-112 (ALG) - Unknown owner - C:\Windows\System32\alg.exe (file missing) O23 - Service: AMD External Events Utility - Unknown owner - C:\Windows\system32\atiesrxx.exe (file missing) O23 - Service: ASUS System Control Service (AsSysCtrlService) - Unknown owner - C:\Program Files (x86)\ASUS\AsSysCtrlService\1.00.02\AsSysCtrlService.exe O23 - Service: DeviceVM Meta Data Export Service (DvmMDES) - DeviceVM - C:\ASUS.SYS\config\DVMExportService.exe O23 - Service: @%SystemRoot%\system32\efssvc.dll,-100 (EFS) - Unknown owner - C:\Windows\System32\lsass.exe (file missing) O23 - Service: ESET HTTP Server (EhttpSrv) - ESET - C:\Program Files\ESET\ESET NOD32 Antivirus\EHttpSrv.exe O23 - Service: ESET Service (ekrn) - ESET - C:\Program Files\ESET\ESET NOD32 Antivirus\x86\ekrn.exe O23 - Service: @%systemroot%\system32\fxsresm.dll,-118 (Fax) - Unknown owner - C:\Windows\system32\fxssvc.exe (file missing) O23 - Service: FLEXnet Licensing Service - Acresso Software Inc. - C:\Program Files (x86)\Common Files\Macrovision Shared\FLEXnet Publisher\FNPLicensingService.exe O23 - Service: FLEXnet Licensing Service 64 - Acresso Software Inc. - C:\Program Files\Common Files\Macrovision Shared\FLEXnet Publisher\FNPLicensingService64.exe O23 - Service: InstallDriver Table Manager (IDriverT) - Macrovision Corporation - C:\Program Files (x86)\Common Files\InstallShield\Driver\11\Intel 32\IDriverT.exe O23 - Service: @keyiso.dll,-100 (KeyIso) - Unknown owner - C:\Windows\system32\lsass.exe (file missing) O23 - Service: @comres.dll,-2797 (MSDTC) - Unknown owner - C:\Windows\System32\msdtc.exe (file missing) O23 - Service: @%SystemRoot%\System32\netlogon.dll,-102 (Netlogon) - Unknown owner - C:\Windows\system32\lsass.exe (file missing) O23 - Service: @%systemroot%\system32\psbase.dll,-300 (ProtectedStorage) - Unknown owner - C:\Windows\system32\lsass.exe (file missing) O23 - Service: Protexis Licensing V2 (PSI_SVC_2) - Protexis Inc. - c:\Program Files (x86)\Common Files\Protexis\License Service\PsiService_2.exe O23 - Service: @%systemroot%\system32\Locator.exe,-2 (RpcLocator) - Unknown owner - C:\Windows\system32\locator.exe (file missing) O23 - Service: @%SystemRoot%\system32\samsrv.dll,-1 (SamSs) - Unknown owner - C:\Windows\system32\lsass.exe (file missing) O23 - Service: @%SystemRoot%\system32\snmptrap.exe,-3 (SNMPTRAP) - Unknown owner - C:\Windows\System32\snmptrap.exe (file missing) O23 - Service: @%systemroot%\system32\spoolsv.exe,-1 (Spooler) - Unknown owner - C:\Windows\System32\spoolsv.exe (file missing) O23 - Service: @%SystemRoot%\system32\sppsvc.exe,-101 (sppsvc) - Unknown owner - C:\Windows\system32\sppsvc.exe (file missing) O23 - Service: Steam Client Service - Valve Corporation - C:\Program Files (x86)\Common Files\Steam\SteamService.exe O23 - Service: @%SystemRoot%\system32\ui0detect.exe,-101 (UI0Detect) - Unknown owner - C:\Windows\system32\UI0Detect.exe (file missing) O23 - Service: @%SystemRoot%\system32\vaultsvc.dll,-1003 (VaultSvc) - Unknown owner - C:\Windows\system32\lsass.exe (file missing) O23 - Service: @%SystemRoot%\system32\vds.exe,-100 (vds) - Unknown owner - C:\Windows\System32\vds.exe (file missing) O23 - Service: @%systemroot%\system32\vssvc.exe,-102 (VSS) - Unknown owner - C:\Windows\system32\vssvc.exe (file missing) O23 - Service: @%systemroot%\system32\wbengine.exe,-104 (wbengine) - Unknown owner - C:\Windows\system32\wbengine.exe (file missing) O23 - Service: @%Systemroot%\system32\wbem\wmiapsrv.exe,-110 (wmiApSrv) - Unknown owner - C:\Windows\system32\wbem\WmiApSrv.exe (file missing) O23 - Service: @%PROGRAMFILES%\Windows Media Player\wmpnetwk.exe,-101 (WMPNetworkSvc) - Unknown owner - C:\Program Files (x86)\Windows Media Player\wmpnetwk.exe (file missing) -- End of file - 6800 bytes CPU-Z ("[...]" indicates removed text; see full log posted to pastebin): CPU-Z TXT Report ------------------------------------------------------------------------- Binaries ------------------------------------------------------------------------- CPU-Z version 1.53.1 Processors ------------------------------------------------------------------------- Number of processors 1 Number of threads 2 APICs ------------------------------------------------------------------------- Processor 0 -- Core 0 -- Thread 0 0 -- Core 1 -- Thread 0 1 Processors Information ------------------------------------------------------------------------- Processor 1 ID = 0 Number of cores 2 (max 2) Number of threads 2 (max 2) Name AMD Phenom II X2 550 Codename Callisto Specification AMD Phenom(tm) II X2 550 Processor Package Socket AM3 (938) CPUID F.4.2 Extended CPUID 10.4 Brand ID 29 Core Stepping RB-C2 Technology 45 nm Core Speed 3110.7 MHz Multiplier x FSB 15.5 x 200.7 MHz HT Link speed 2006.9 MHz Instructions sets MMX (+), 3DNow! (+), SSE, SSE2, SSE3, SSE4A, x86-64, AMD-V L1 Data cache 2 x 64 KBytes, 2-way set associative, 64-byte line size L1 Instruction cache 2 x 64 KBytes, 2-way set associative, 64-byte line size L2 cache 2 x 512 KBytes, 16-way set associative, 64-byte line size L3 cache 6 MBytes, 48-way set associative, 64-byte line size FID/VID Control yes Min FID 4.0x P-State FID 0xF - VID 0x10 P-State FID 0x8 - VID 0x18 P-State FID 0x3 - VID 0x20 P-State FID 0x100 - VID 0x2C Package Type 0x1 Model 50 String 1 0x7 String 2 0x6 Page 0x0 TDP Limit 79 Watts TDC Limit 66 Amps Attached device PCI device at bus 0, device 24, function 0 Attached device PCI device at bus 0, device 24, function 1 Attached device PCI device at bus 0, device 24, function 2 Attached device PCI device at bus 0, device 24, function 3 Attached device PCI device at bus 0, device 24, function 4 Thread dumps ------------------------------------------------------------------------- CPU Thread 0 APIC ID 0 Topology Processor ID 0, Core ID 0, Thread ID 0 Type 0200400Ah Max CPUID level 00000005h Max CPUID ext. level 8000001Bh Cache descriptor Level 1, I, 64 KB, 1 thread(s) Cache descriptor Level 1, D, 64 KB, 1 thread(s) Cache descriptor Level 2, U, 512 KB, 1 thread(s) Cache descriptor Level 3, U, 6 MB, 2 thread(s) CPUID 0x00000000 0x00000005 0x68747541 0x444D4163 0x69746E65 0x00000001 0x00100F42 0x00020800 0x00802009 0x178BFBFF 0x00000002 0x00000000 0x00000000 0x00000000 0x00000000 0x00000003 0x00000000 0x00000000 0x00000000 0x00000000 0x00000004 0x00000000 0x00000000 0x00000000 0x00000000 0x00000005 0x00000040 0x00000040 0x00000003 0x00000000 [...] CPU Thread 1 APIC ID 1 Topology Processor ID 0, Core ID 1, Thread ID 0 Type 0200400Ah Max CPUID level 00000005h Max CPUID ext. level 8000001Bh Cache descriptor Level 1, I, 64 KB, 1 thread(s) Cache descriptor Level 1, D, 64 KB, 1 thread(s) Cache descriptor Level 2, U, 512 KB, 1 thread(s) Cache descriptor Level 3, U, 6 MB, 2 thread(s) CPUID 0x00000000 0x00000005 0x68747541 0x444D4163 0x69746E65 0x00000001 0x00100F42 0x01020800 0x00802009 0x178BFBFF 0x00000002 0x00000000 0x00000000 0x00000000 0x00000000 0x00000003 0x00000000 0x00000000 0x00000000 0x00000000 0x00000004 0x00000000 0x00000000 0x00000000 0x00000000 0x00000005 0x00000040 0x00000040 0x00000003 0x00000000 [...] Chipset ------------------------------------------------------------------------- Northbridge AMD 790GX rev. 00 Southbridge ATI SB750 rev. 00 Memory Type DDR3 Memory Size 4096 MBytes Channels Dual, (Unganged) Memory Frequency 669.0 MHz (3:10) CAS# latency (CL) 9.0 RAS# to CAS# delay (tRCD) 9 RAS# Precharge (tRP) 9 Cycle Time (tRAS) 24 Bank Cycle Time (tRC) 33 Command Rate (CR) 1T Uncore Frequency 2006.9 MHz Memory SPD ------------------------------------------------------------------------- DIMM # 1 SMBus address 0x50 Memory type DDR3 Module format UDIMM Manufacturer (ID) G.Skill (7F7F7F7FCD000000) Size 2048 MBytes Max bandwidth PC3-10700 (667 MHz) Part number F3-10600CL9-2GBNT Number of banks 8 Nominal Voltage 1.50 Volts EPP no XMP no JEDEC timings table CL-tRCD-tRP-tRAS-tRC @ frequency JEDEC #1 6.0-6-6-17-23 @ 457 MHz JEDEC #2 7.0-7-7-20-27 @ 533 MHz JEDEC #3 8.0-8-8-22-31 @ 609 MHz JEDEC #4 9.0-9-9-25-34 @ 685 MHz DIMM # 2 SMBus address 0x51 Memory type DDR3 Module format UDIMM Manufacturer (ID) G.Skill (7F7F7F7FCD000000) Size 2048 MBytes Max bandwidth PC3-10700 (667 MHz) Part number F3-10600CL9-2GBNT Number of banks 8 Nominal Voltage 1.50 Volts EPP no XMP no JEDEC timings table CL-tRCD-tRP-tRAS-tRC @ frequency JEDEC #1 6.0-6-6-17-23 @ 457 MHz JEDEC #2 7.0-7-7-20-27 @ 533 MHz JEDEC #3 8.0-8-8-22-31 @ 609 MHz JEDEC #4 9.0-9-9-25-34 @ 685 MHz DIMM # 1 SPD registers [...] DIMM # 2 SPD registers [...] Monitoring ------------------------------------------------------------------------- Mainboard Model M4A78T-E (0x000001F7 - 0x00A955E4) LPCIO ------------------------------------------------------------------------- LPCIO Vendor ITE LPCIO Model IT8720 LPCIO Vendor ID 0x90 LPCIO Chip ID 0x8720 LPCIO Revision ID 0x2 Config Mode I/O address 0x2E Config Mode LDN 0x4 Config Mode registers [...] Register space LPC, base address = 0x0290 Hardware Monitors ------------------------------------------------------------------------- Hardware monitor ITE IT87 Voltage 1 1.62 Volts [0x65] (VIN1) Voltage 2 1.15 Volts [0x48] (CPU VCORE) Voltage 3 5.03 Volts [0xBB] (+5V) Voltage 8 3.34 Volts [0xD1] (VBAT) Temperature 0 39°C (102°F) [0x27] (TMPIN0) Temperature 1 43°C (109°F) [0x2B] (TMPIN1) Fan 0 3096 RPM [0xDA] (FANIN0) Register space LPC, base address = 0x0290 [...] Hardware monitor AMD SB6xx/7xx Voltage 0 1.37 Volts [0x1D2] (CPU VCore) Voltage 1 3.50 Volts [0x27B] (CPU IO) Voltage 2 12.68 Volts [0x282] (+12V) Hardware monitor AMD Phenom II X2 550 Power 0 89.10 W (Processor) Temperature 0 35°C (94°F) [0x115] (Core #0) Temperature 1 35°C (94°F) [0x115] (Core #1)

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  • Stop squid caching 302 and 307 with deny_info

    - by 0xception
    TLDR: 302, 307 and Error pages are being cached. Need to force a refresh of the content. Long version: I've setup a very minimal squid instance running on a gateway which shouldn't not cache ANYTHING but needs to be solely used as a domain based web filter. I'm using another application which redirects un-authenticated users to the proxy which then uses the deny_info option redirects any non-whitelisted request to the login page. After the user has authenticated the firewall rule gets placed so they no longer get sent to the proxy. The problem is that when a user hits a website (xkcd.com) they are unauthenticated so they get redirected via the firewall: iptables -A unknown-user -t nat -p tcp --dport 80 -j REDIRECT --to-port 39135 to the proxy at this point squid redirects the user to the login page using a 302 (i've also tried 307, and i've also make sure the headers are set to no-cache and/or no-store for Cache-Control and Pragma). Then when the user logs into the system they get firewall rule which no longer directs them to the squid proxy. But if they go to xkcd.com again they will have the original redirection page cached and will once again get the login page. Any idea how to force these redirects to NOT be cached by the browser? Perhaps this is a problem w/ the browsers and not squid, but not sure how to get around it. Full squid config below. # # Recommended minimum configuration: # acl manager proto cache_object acl localhost src 127.0.0.1/32 ::1 acl to_localhost dst 127.0.0.0/8 0.0.0.0/32 ::1 acl localnet src 192.168.182.0/23 # RFC1918 possible internal network acl localnet src fc00::/7 # RFC 4193 local private network range acl localnet src fe80::/10 # RFC 4291 link-local (directly plugged) machines acl https port 443 acl http port 80 acl CONNECT method CONNECT # # Disable Cache # cache deny all via off negative_ttl 0 seconds refresh_all_ims on #error_default_language en # Allow manager access only from localhost http_access allow manager localhost http_access deny manager # Deny access to anything other then http http_access deny !http # Deny CONNECT to other than secure SSL ports http_access deny CONNECT !https visible_hostname gate.ovatn.net # Disable memory pooling memory_pools off # Never use neigh cache objects for cgi-bin scripts hierarchy_stoplist cgi-bin ? # # URL rewrite Test Settings # #acl whitelist dstdomain "/etc/squid/domains-pre.lst" #url_rewrite_program /usr/lib/squid/redirector #url_rewrite_access allow !whitelist #url_rewrite_children 5 startup=0 idle=1 concurrency=0 #http_access allow all # # Deny Info Error Test # acl whitelist dstdomain "/etc/squid/domains-pre.lst" deny_info http://login.domain.com/ whitelist #deny_info ERR_ACCESS_DENIED whitelist http_access deny !whitelist http_access allow whitelist http_port 39135 transparent ## Debug Values access_log /var/log/squid/access-pre.log cache_log /var/log/squid/cache-pre.log # Production Values #access_log /dev/null #cache_log /dev/null # Set PID file pid_filename /var/run/gatekeeper-pre.pid SOLUTION: I believe I might have found a solution to this. After days and days trying to figure it out, only through a random stumble I found client_persistent_connections off server_persistent_connections off This did the trick. So it wasn't so much cache as it was a single persistent connection messing things up. W000T!

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  • Why did my flash drive become "read only" and (how) can I fix it?

    - by Bob
    I have a brand new flash drive (one week old) that has become marked as read only, by Windows, Kubuntu and a bootable partitioner. Why did this happen? Is it fixable? If it is, how can I fix this? The problem Firstly, this drive is new. It's certainly not been used enough to die from normal wear and tear, though I would not discount defective components. The drive itself has somehow become locked in a read only state. Windows' Disk management: Diskpart: Generic Flash Disk USB Device Disk ID: 33FA33FA Type : USB Status : Online Path : 0 Target : 0 LUN ID : 0 Location Path : UNAVAILABLE Current Read-only State : Yes Read-only : No Boot Disk : No Pagefile Disk : No Hibernation File Disk : No Crashdump Disk : No Clustered Disk : No What really confuses me is Current Read-only State : Yes and Read-only : No. Attempted solutions So far, I've tried: Formatting it in Windows (in Disk management, the format options are greyed out when right clicking). DiskPart Clean (CLEAN - Clear the configuration information, or all information, off the disk.): DISKPART> clean DiskPart has encountered an error: The media is write protected. See the System Event Log for more information. There was nothing in the event log. Windows command line format >format G: Insert new disk for drive G: and press ENTER when ready... The type of the file system is FAT32. Verifying 7740M Cannot format. This volume is write protected. Windows chkdsk: see below for details Kubuntu fsck (through VirtualBox USB passthrough): see below for details Acronis True Image to format, to convert to GPT, to destroy and rebuild MBR, basically anything: failed (could not write to MBR) Details (and a nice story) Background This was a brand new, generic, 8GB flash drive I wanted to create a multiboot flash drive with. It came formatted as FAT32, though oddly a little larger than most 8 GIGAbyte flash drives I've come across. Approximately 127MB was listed as "used" by Windows. I never discovered why. The end usable space was about what I normally expect from a 8GB drive (approx 7.4 GIBIbytes). I had thrown quite a few Linux distros on, along with a copy of Hiren's. They would all boot perfectly. They were put on with YUMI. When I tried to put the Knoppix DVD on, YUMI added an odd video option to its boot comman which caused Knoppix to boot with a black screen on X. ttys 1 through 6 still worked as text only interfaces. A few days later, I took some time to take that odd video option off, making the boot command match the one that comes with Knoppix. On the attempt to boot, Knoppix reported some form of LZMA corruption. Leading up to the current issue I was thinking the Knoppix files may have been corrupted somehow, so I tried reloading it. The drive was nearly full (45MB free), so I deleted a generic ISO that also was not booting. That went fine. I then went through YUMI to 'uninstall' Knoppix, i.e. delete files and remove from the menus. The files went first, then the menus were cleared successfully. However, the free space was stuck at about 700MB, same as it was before removing Knoppix. In the old Knoppix folder, there was a 0 byte file named KNOPPIX that could not be deleted. I tried reinserting the drive to delete this file - without safely removing, if that made a difference (hey, first time for everything). Running the standard Windows chkdsk scan without /r or /f reported errors found. Running with /r just got it stuck. I decided to give fsck a shot, so I loaded up my Kubuntu VM and attached the drive to it with VirtualBox's USB 2.0 passthrough. I umounted it (/dev/sda1) and ran a fsck. There are differences between boot sector and its backup. I chose No action. It told me FATs differ and asked me to select either the first or second FAT. Whichever I selected, I got a notice of Free cluster summary wrong. If I chose Correct, it gave a list of incorrect file names. To try to fix something, at least, I ran it with the -p option. Halfway through fixing the files, the VM froze - I ended its process about ten minutes later. Cause? My next attempt was to use YUMI, again, to rebuild the whole drive. I used YUMI's built in reformat (to FAT32) option and installed a Kubuntu ISO (700MB). The format was successful, however, the extract and copy of Kubuntu (which YUMI uses a 7zip binary for) froze at about 60% done. After waiting for about fifteen minutes (longer than the 3.5GB Knoppix ISO took last time), I pulled the drive out. The drive at this point was already formatted, SYSLINUX already installed, just waiting on the unpacking of an ISO and the modifying of the boot menus. Plugging it back in, it came up as normal - however, any write action would fail. Disk management reported it as read only. On reconnect, it would come up as normal but a write operation would cause it to go read only again. After a few attempts, it started coming up as read only on insertion. Attempts to fix This is when I ran through the attempts listed above, to try and reformat it in case of a faulty format. However the inability to do so even on a bootable disk indicated something more serious is wrong. chkdsk now reports nothing is wrong, and fsck still reports MBR inconsistencies, but now always chooses first FAT automatically after telling me FATs differ. It still does the same Free cluster summary wrong afterwards. I cannot run with -p anymore because it is now marked as read only. It also managed to corrupt my VM's disk somehow on the first attempt (yes, I'm sure I chose sda, which is mapped to a 7.4GB drive - I triple checked). Thank god for snapshots? I'm just about out of ideas. To my inexperienced mind it looks like something in the drive's firmware set it to read only "permanently" somehow - is there any way to reset this? I don't particularly care about keeping data, considering I've reformatted it twice. Also, fixes that keep me in Windows are better; it reduces the risk of me accidentally nuking my main hard drive. Update 1: I pulled apart the drive out of curiosity. As you can see, there are no obvious write protect switches. There is an IC on the other side, ALCOR branded labelled AU6989HL, if that matters. If there appears to be no way to fix this, I'll probably pull out the (glued down) card and put it in a card reader to check if it's the card or the controller that died. Update 2: I've pulled the card off, Windows detects the drive as a card reader now. The contacts on the card don't appear to be used, and there are several rows of holes on the card itself. Putting it into the card reader only detects about 30MB total, RAW. It's probably either the reader incorrectly reporting the card as faulty (as if a real SD card's write protect was switched on) or a bad contact somewhere. If nothing else, I have a spare 8GB Micro SD card now... as soon as I figure out how to format it as 8GB.

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  • Need Varnish configuration advice

    - by Patrick
    Hello fellows, I need some advice here for default.vcl. Here's the rules: Only cache pages with urls that contains '/c/', the rest will pass Set the cache expiry to 3 hours Only cache and serve from cache if cookie 'abc' and cookie 'xyz' is empty Thank you!

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  • Solaris: Is it OK to disable font services?

    - by cjavapro
    Is it OK to disable these services? # svcs -l '*font*' fmri svc:/application/font/stfsloader:default name Standard Type Services Framework (STSF) Font Server loader enabled true state online next_state none state_time Sun May 30 17:58:14 2010 restarter svc:/network/inetd:default fmri svc:/application/font/fc-cache:default name FontConfig Cache Builder enabled true state online next_state none state_time Sun May 30 17:58:15 2010 logfile /var/svc/log/application-font-fc-cache:default.log restarter svc:/system/svc/restarter:default dependency require_all/none svc:/system/filesystem/local (online) dependency require_all/refresh file://localhost/etc/fonts/fonts.conf (online) dependency require_all/none file://localhost/usr/bin/fc-cache (online) #

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  • Need Varnish configuration advise

    - by Patrick
    Hello fellows, I need some advise here for default.vcl. Here's the rules: 1) Only cache pages with urls that contains '/c/', the rest will pass 2) Set the cache expiry to 3 hours 3) Only cache and server from cache if cookie 'abc' and cookie 'xyz' is empty Thank you!

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  • Preventing 304 Not Modified Requests with nginx

    - by ustun
    I am running nginx, and have the following block for expiration: expires 52w; However when I use Google Chrome Developer Tools to observe network traffic, some of the assets are loaded from cache (200-from cache) while most of the assets are making a request to the server (304 Not Modified). I want to load all assets from cache without communicating with the server if possible. (200-from cache) What would be the required change in my nginx configuration?

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  • How can I export images from MS SQL Server to a file on disk?

    - by rball
    I have a User table that has all of their avatars saved in an image field. I'd like to just take that out of the database and store it as a regular file on disk. I looked around and saw some code for textcopy, but that doesn't seem to be on my machine for some reason. Here is the code I wrote up anyway. Anyone know a way to get this done? DECLARE @exec_str varchar (255) SELECT @exec_str = 'textcopy /S (local)\SQLEXPRESS' + --' /U ' + @login + --' /P ' + @password + ' /D thedatabase' + ' /T User'+ ' /C AvatarImage' + ' /F "d:\Avatars\' + User.Name + '.jpg"' + ' /O' FROM [User] WHERE UserID = 2 EXEC master..xp_cmdshell @exec_str

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