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  • php array regular expressions

    - by bell
    I am using regular expressions in php to match postcodes found in a string. The results are being returned as an array, I was wondering if there is any way to assign variables to each of the results, something like $postcode1 = first match found $postcode2 = second match found here is my code $html = "some text here bt123ab and another postcode bt112cd"; preg_match_all("/([a-zA-Z]{2})([0-9]{2,3})([a-zA-Z]{2})/", $html, $matches, PREG_SET_ORDER); foreach ($matches as $val) { echo $val[0]; } I am very new to regular expressions and php, forgive me if this is a stupid question. Thanks in advance

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  • replaceAll() method using parameter from text file

    - by Herman Plani Ginting
    i have a collection of raw text in a table in database, i need to replace some words in this collection using a set of words. i put all the term to be replace and its substitutes in a text file as below min=admin lelet=lambat lemot=lambat nii=nih ntu=itu and so on. i have successfully initiate a variabel of File and Scanner to read the collection of the term and its substitutes. i loop all the dataset and save the raw text in a string in the same loop i loop all the term collection and save its row to a string name 'pattern', and split the pattern into two string named 'term' and 'replacer' in this loop i initiate a new string which its value is the string from the dataset modified by replaceAll(term,replacer) end loop for term collection then i insert the new string to another table in database end loop for dataset i do it manualy as below replaceAll("min","admin") and its works but its really something to code it manually for almost 2000 terms to be replace it. anyone ever face this kind of really something.. i really need a help now desperate :( package sentimenrepo; import javax.swing.*; import java.sql.*; import java.io.*; //import java.util.HashMap; import java.util.Scanner; //import java.util.Map; /** * * @author herman */ public class synonimReplaceV2 extends SwingWorker { protected Object doInBackground() throws Exception { new skripsisentimen.sentimenttwitter().setVisible(true); Integer row = 0; File synonimV2 = new File("synV2/catatan_kata_sinonim.txt"); String newTweet = ""; DB db = new DB(); Connection conn = db.dbConnect("jdbc:mysql://localhost:3306/tweet", "root", ""); try{ Statement select = conn.createStatement(); select.executeQuery("select * from synonimtweet"); ResultSet RS = select.getResultSet(); Scanner scSynV2 = new Scanner(synonimV2); while(RS.next()){ row++; String no = RS.getString("no"); String tweet = " "+ RS.getString("tweet"); String published = RS.getString("published"); String label = RS.getString("label"); clean2 cleanv2 = new clean2(); newTweet = cleanv2.cleanTweet(tweet); try{ Statement insert = conn.createStatement(); insert.executeUpdate("INSERT INTO synonimtweet_v2(no,tweet,published,label) values('" +no+"','"+newTweet+"','"+published+"','"+label+"')"); String current = skripsisentimen.sentimenttwitter.txtAreaResult.getText(); skripsisentimen.sentimenttwitter.txtAreaResult.setText(current+"\n"+row+"original : "+tweet+"\n"+newTweet+"\n______________________\n"); skripsisentimen.sentimenttwitter.lblStat.setText(row+" tweet read"); skripsisentimen.sentimenttwitter.txtAreaResult.setCaretPosition(skripsisentimen.sentimenttwitter.txtAreaResult.getText().length() - 1); }catch(Exception e){ skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } }catch(Exception e){ skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } return row; } class clean2{ public clean2(){} public String cleanTweet(String tweet){ File synonimV2 = new File("synV2/catatan_kata_sinonim.txt"); String pattern = ""; String term = ""; String replacer = ""; String newTweet=""; try{ Scanner scSynV2 = new Scanner(synonimV2); while(scSynV2.hasNext()){ pattern = scSynV2.next(); term = pattern.split("=")[0]; replacer = pattern.split("=")[1]; newTweet = tweet.replace(term, replacer); } }catch(Exception e){ e.printStackTrace(); } System.out.println(newTweet+"\n"+tweet); return newTweet; } } }

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  • Why are these strings escaping from my regular expression in python?

    - by dohkoxar
    In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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  • Extract IP address from an html string (python)

    - by GoJian
    My Friends, I really want to extract a simple IP address from a string (actually an one-line html) using Python. But it turns out that 2 hours passed I still couldn't come up with a good solution. >>> s = "<html><head><title>Current IP Check</title></head><body>Current IP Address: 165.91.15.131</body></html>" -- '165.91.15.131' is what I want! I tried using regular expression, but so far I can only get to the first number. >>> import re >>> ip = re.findall( r'([0-9]+)(?:\.[0-9]+){3}', s ) >>> ip ['165'] In fact, I don't feel I have a firm grasp on reg-expression and the above code was found and modified from elsewhere on the web. Seek your input and ideas!

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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  • User oriented regex library for java

    - by Maxim Veksler
    Hello, I'm looking for a library that could perform "easy" pattern matching, a kind of pattern that can be exposed via GUI to users. It should define a simple matching syntax like * matches any char and alike. In other words, I want to do glob (globbing) like sun's implemented logic http://openjdk.java.net/projects/nio/javadoc/java/nio/file/PathMatcher.html but without relation to the file system. Ideas?

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  • Why this code does not do what I mean?

    - by Mike
    $w = 'self-powering'; %h = (self => 'self', power => 'pau?', ); if ($w =~ /(\w+)-(\w+)ing$/ && $1~~%h && $2~~%h && $h{$2}=~/?$/) { $p = $h{$1}.$h{$2}.'ri?'; print "$w:"," [","$p","] "; } I expect the output to be self-powering: selfpau?ri? But what I get is: self-powering: [ri?] My guess is something's wrong with the code $h{$2}=~/?$/ It seems that when I use $h{$2}!~/?$/ Perl will do what I mean but why I can't get "self-powering: selfpau?ri?"? What am I doing wrong? Any ideas? Thanks as always for any comments/suggestions/pointers :)

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  • replacing the beginning and end but not the same chars within a string

    - by Jordan Trainor
    lines = "some stuff\"some other \"stuff\"\""; lines = lines.Replace("\"", "\""); lines = lines.Replace("\"", "\""); in its current context and in its simplest form these two actions seem absolutely pointless but when I put this into code it will be not be pointless and will have a purpose other than replacing itself with itself. OK so I have the String lines that has 4 escaped quotation marks and I wish to replace the first quote with a quote and the end quote with a quote how would I accomplish this without replacing any of the inner quotes?

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  • Python regular expression

    - by user3692739
    I have this HTTP Request and I want to display only the Authorization section (base64 Value) : any help ? This Request is stored on a variable called hreq I have tried this : reg = re.search(r"Authorization:\sBasic\s(.*)\r", hreq) print reg.group() but doesn't work Here is the request : HTTP Request: Path: /dynaform/custom.js Http-Version: HTTP/1.1 Host: 192.168.1.254 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://domain.com/userRpm/StatusRpm.htm Authorization: Basic YWhtEWa6MDfGcmVlc3R6bGH I want to display the value YWhtEWa6MDfGcmVlc3R6bGH Please I need your help thanks in advance experts

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  • Are there any way to apply regexp in java ignoring letter case?

    - by Roman
    Simple example: we have string "Some sample string Of Text". And I want to filter out all stop words (i.e. "some" and "of") but I don't want to change letter case of other words which should be retained. If letter case was unimportant I would do this: str.toLowerCase().replaceAll ("a|the|of|some|any", ""); Is there an "ignore case" solution with regular expressions in java?

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  • How to sub with matched groups and variables in Python

    - by Syed
    Hi, new to python. This is probably simple but I haven't found an answer. rndStr = "20101215" rndStr2 = "20101216" str = "Looking at dates between 20110316 and 20110317" outstr = re.sub("(.+)([0-9]{8})(.+)([0-9]{8})",r'\1'+rndStr+r'\2'+rndStr2,str) The output I'm looking for is: Looking at dates between 20101215 and 20101216 But instead I get: P101215101216 The values of the two rndStr's doesn't really matter. Assume its random or taken from user input (I put static vals here to keep it simple). Thanks for any help.

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  • How do I test against a large number of regular expressions quickly and know which one matched?

    - by Jack
    I'm writing a program in .net where the user may provide a large number of regular expressions. For a given string, I need to figure out which regular expression matches that string (if more than one matches, I just need the first one that matches). However, if there are a large number of regular expressions this operation can take a very long time. I was somewhat hoping there would be something similar to flex for .net that would allow me to specify a large number of regular expressions yet quickly (O(n) according to Wikipedia for n = len(input string)) figure out which regular expression matches. Also, I would prefer not to implement my own regular expression engine :).

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  • Split text at the first instance of a letter

    - by Blankman
    I have a bunch of product sku's that look like: abc234 asdf234324 adc234-b result: abc 234 asdf 234324 adc 234-b I want to split the text at the first instance of a letter. When I say split, basically I want to have access to both parts of the text, maybe in an array? What's the best way to do this?

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  • Regular Expression Help

    - by Dave
    Looking for some help with a Regular Expression to do the following: Must be Alpha Char Must be at least 1 Char Must NOT be a specific value, e.g. != "Default" Thanks for any help, Dave

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  • Perl Regular Expression [] for <>

    - by bmucklow
    So I am trying to read an XML file into a string in Perl and send it as part of a SOAP message. I know this is not ideal as there are methods for SOAP sending files, however, I am limited to having to use the SOAP that is set up, and it is not set up for sending with file support. Therefore I need to parse out the markup tags < and replace them with []. What is the best way to do this?

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  • preg_match and long strings

    - by aleluja
    Hi, This is the preg_match i am trying to use to find specific text in text file. if (preg_match($regexp,$textFile,$result) > 0) { echo "Found ".$result[0]; } else { echo "Not found"; } However, the result is always Found and nothing more. The result array is empty. Now i read that preg_match can't work with long strings. My text file is about 300KB so thats 300000 characters i guess. I am 100% sure that the searched string is in the text file, and the fact that preg_match function returns value above 0 means it found it, but it didn't place it into the result array somehow. So my question would be, how do i make it work? regexp would be /[specific text]\{(\d*)\}/ so, of course i want to be able to get the number in the parentheses.

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  • How to replace all the blanks within square brackets with an underscore using sed?

    - by Ringerrr
    I figured out that in order to turn [some name] into [some_name] I need to use the following expression: s/\(\[[^ ]*\) /\1_/ i.e. create a backreference capture for anything that starts with a literal '[' that contains any number of non space characters, followed by a space, to be replaced with the non space characters followed by an underscore. What I don't know yet though is how to alter this expression so it works for ALL underscores within the braces e.g. [a few words] into [a_few_words]. I sense that I'm close, but am just missing a chunk of knowledge that will unlock the key to making this thing work an infinite number of times within the constraints of the first set of []s contained in a line (of SQL Server DDL in this case). Any suggestions gratefully received....

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  • Convert Json date string to JavaScript date object

    - by dagda1
    Hi, I have the following JSON object which has a date field in the following format: { "AlertDate": "\/Date(1277334000000+0100)\/", "Progress": 1, "ReviewPeriod": 12 } I want to write a regular expression or a function to convert it to a javascript object so that it is in the form: { "AlertDate": "AlertDate":new Date(1277334000000), "Progress": 1, "ReviewPeriod": 12 } The above date format fails validation in the JQuery parseJSON method. I would like to convert the 1277334000000+0100 into the correct number of milliseconds to create the correct date when eval is called after validation. Can anyone help me out with a good approach to solving this? Cheers Paul

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  • Get Youtube Video ID from html code with PHP

    - by asumaran
    I want to get all only youtube video ID from html code look the (or multiple) object/embed code for youtube video // html from database <p>loremm ipsum dolor sit amet enot <a href="link" attribute=""blah blah blah">anchor link</a> </p> <object width="425" height="344"> <param name="movie" value="http://www.youtube.com/v/Ou5eVl5eqtg&hl=es_ES&fs=1&"></param> <param name="allowFullScreen" value="true"></param> <param name="allowscriptaccess" value="always"></param> <embed src="http://www.youtube.com/v/Ou5eVl5eqtg&hl=es_ES&fs=1&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="344"> </embed> </object> <image src="path/to/image.ext" > <p>lorem ipsum dolor sit amet... blah</p> <p>lorem ipsum dolor sit amet... blah</p> <object width="425" height="344"> <param name="movie" value="http://www.youtube.com/v/Ou5eVl5eqtg&hl=es_ES&fs=1&"></param> <param name="allowFullScreen" value="true"></param> <param name="allowscriptaccess" value="always"></param> <embed src="http://www.youtube.com/v/Ou5eVl5eqtg&hl=es_ES&fs=1&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="344"> </embed> </object> <p>blah</p> blah<br/> blah<br/> blah<br/>

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  • JQuery - remove the chars not matching regEx

    - by JQueryBeginner
    Hi All, I am trying to use jquery for validating forms. This is the pattern that is allowed in a text box for a user. var pattern = /^[a-zA-Z0-9!#$&%*+,-./: ;=?@_]/g; If the user types anything else other than this then that has to be replaced with a "". $(document).ready(function() { $('#iBox').blur(function() { var jVal = $('#iBox').val(); if(jVal.match(pattern)) { alert("Valid"); } else { alert("New "+jVal.replace(!(pattern),"")); } }); }); }); But the replace function does not work this way.

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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