Search Results

Search found 9016 results on 361 pages for 'regex libraries'.

Page 140/361 | < Previous Page | 136 137 138 139 140 141 142 143 144 145 146 147  | Next Page >

  • Perl Matching ,Extracting , and printing emails

    - by user3448790
    How do I match an email using the The Official Standard: RFC 5322 in a html source code, after that i will extract the strings that are matched ONLY, and print out inly the emails, and not the whole source code? Is there any examples and output to illustrate this? Thnaks! elsif ($_ eq '-dDATA' or $_ eq '-ft') { opendir(DIR,'DATA'); my(@dir) = grep /\.htm/, readdir (DIR); closedir(DIR); my $value = join(@dir); print "$value\n"; foreach my $movies (@dir) { open (my $FHD, "<", "DATA/$movies") || die $!; print <$FHD>; } } }

    Read the article

  • Using BASH - Find CSS block or definition and print to screen

    - by Brian
    I have a number of .css files spread across some directories. I need to find those .css files, read them and if they contain a particular class definition, print it to the screen. For example, im looking for ".ExampleClass" and it exists in /includes/css/MyStyle.css, i would want the shell command to print .ExampleClass { color: #ff0000; }

    Read the article

  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

    Read the article

  • Erroneous Matches with Regular Expression

    - by Ballsacian1
    $regexp = '/(?:<input\stype="hidden"\sname="){1}([a-zA-Z0-9]*)(?:"\svalue="1"\s\/>)/'; $response = '<input type="hidden" name="7d37dddd0eb2c85b8d394ef36b35f54f" value="1" />'; preg_match($regexp, $response, $matches); echo $matches[1]; // Outputs: 7d37dddd0eb2c85b8d394ef36b35f54f So I'm using this regular expression to search for an authentication token on a webpage implementing Joomla in order to preform a scripted login. I've got all this working but am wondering what is wrong with my regular expression as it always returns 2 items. Array ( [0] => [1] => 7d37dddd0eb2c85b8d394ef36b35f54f) Also the name of the input I'm checking for changes every page load both in length and name.

    Read the article

  • ruby enclose selected whole words in brackets

    - by astropanic
    @string = "Sometimes some stupid people say some stupid words" @string.enclose_in_brackets("some") # => "Sometimes {some} stupid people say {some} stupid words" How should the method enclose_in_brackets look ? Please keep in mind, I want only enclose whole words, (I don't want "{Some}times {some} stupid....", the "sometimes" word should be left unchanged

    Read the article

  • Converting time period strings to value/unit pair

    - by randomtoor
    I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

    Read the article

  • Remove parameter from link

    - by goordis
    I have many links with parameter number - value is numbers between 1-1000 http://mysite.com?one=2&two=4&number=2 http://mysite.com?one=2&two=4&four=4&number=124 http://mysite.com?one=2&three=4&number=9 http://mysite.com?two=4&number=242 http://mysite.com?one=2&two=4&number=52 How can i remove from this parameter and value with PHP? I would like receive: http://mysite.com?one=2&two=4 http://mysite.com?one=2&two=4&four=4 http://mysite.com?one=2&three=4 http://mysite.com?two=4 http://mysite.com?one=2&two=4

    Read the article

  • Regular Expression to Match Specific "Values" in Isolated Group

    - by Gandarez
    If have this regular expression to test (\&TRUNC)[\(]{1,}(.+)[\)]{1,} And I have this "tester" ((((&TRUNC((1800,000 / 510)) * 510) * 920) + (2 * (510 * 700)) + ((&TRUNC((1800,000 / 510)) - 1) * 2 * 510 * 80)) / 1000000) * 85,715 My expected value is (inside the personal command "&TRUNC(command)") (1800,000 / 510) I got this value 1800,000 / 510)) * 510) * 920) + (2 * (510 * 700)) + ((&TRUNC((1800,000 / 510)) - 1) * 2 * 510 * 80)) / 1000000 How can I get only expected value in a separated group? PS:. The expressions inside the command called for me as "&TRUNC(command)" is variable.

    Read the article

  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

    Read the article

  • Trying to match what is before /../ but after / with regular expressions

    - by tim
    I am trying to match what is before /../ but after / with regular expressions, but i want it to look back and stop at the first / I feel like I am close but it just looks at the first slash and then takes everything after it like... input is this: this/is/a/./path/that/../includes/face/./stuff/../hat and my regular expression is #\/(.*)\.\.\/# matching /is/a/./path/that/../includes/face/./stuff/../ instead of just that/../ and stuff/../ how can i adapt what i'm doing to work?

    Read the article

  • Javascript simple regexp doesn't work

    - by bah
    Hi, I have this code, it looks alright and is really basic, but i can't make it work: function checkValid(elem){ var abc = elem.value; var re = "/[0-9]/"; var match = re.test(abc); alert(match); } It matches 0 and 9, but not 1 to 8, what's wrong here? Thanks.

    Read the article

  • HTACCESS redirection with a word replacement in url

    - by Marwen
    I'm having trouble with this reg expression which i belive is correct, but it is not working. What im trying to do is redirect bunch of urls containing a specific string like this: http://www.example.com/**undesired-string**_another-string to http://www.example.com/**new-string**_another-string and http://www.example.com/folder/**undesired-string**/another-string to http://www.example.com/folder/**new-string**/another-string So i have this code in the .htaccess: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteRule (.+)+(undesired-string)+(.+) $1new-string$2 [R=301,L] </IfModule> This should replace ANY undesired-string in any url to new-string, but it is not working, any idea why ? Thank you

    Read the article

  • Retrieve all hashtags from a tweet in a PHP function

    - by snorpey
    Hi. I want to retrieve all hashtags from a tweet using a PHP function. I know someone asked a similar question here, but there is no hint how exactly to implement this in PHP. Since I'm not very familiar with regular expressions, don't know how to write a function that returns an array of all hashtags in a tweet. So how do I do this, using the following regular expression: #\S*\w

    Read the article

  • Match Phrases (in array) in text string

    - by Tim Hanssen
    I'm using the Twitter API streaming to collect thousand of tweets every minute. They need to be matched to a list of keywords (can contain spaces). This is my current method: $text = preg_replace( '/[^a-z0-9]+/i', ' ', strtolower( $data['text'] ) ); $breakout = explode( " ", $text ); $result = array_intersect( $this->_currentTracks, $breakout ); I chop the tweet into words, and the matches them against my current keywords. This works well for all the keywords without a space ofc. If I wanted to find for example "Den Haag", It won't show up, because the string is exploded into words (based on the spaces). Any ideas about how I can do this in a quick way? Kind regards, Tim

    Read the article

  • Find Javascript Code inside String

    - by Ph.E
    Greetings friends, I am developing a web application that will allow the customer to enter a personalized message, which will then be converted to HTML. Well, the problem is that I can not allow the insertion of Javascript code. So I need a method that filters the text, searching for and remove it. I think the regular expressions to solve my problem, but I'm having difficulty building. Some of his friends could help me, or has already developed something for this. Thank you.

    Read the article

  • How to move many files in multiple different directories (on Linux)

    - by user1335982
    My problem is that I have too many files in single directory. I cannot "ls" the directory, cos is too large. I need to move all files in better directory structure. I'm using the last 3 digits from ID as folders in reverse way. For example ID 2018972 will gotta go in /2/7/9/img_2018972.jpg. I've created the directories, but now I need help with bash script. I know the IDs, there are in range 1,300,000 - 2,000,000. But I can't handle regular expressions. I wan't to move all files like this: /images/folder/img_2018972.jpg -> /images/2/7/9/img_2018972.jpg I will appreciate any help on this subject. Thanks!

    Read the article

  • JavaScript regular expressions to validate string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

    Read the article

  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

    Read the article

< Previous Page | 136 137 138 139 140 141 142 143 144 145 146 147  | Next Page >