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  • [AS 3.0] How to use the string.match method to find multiple occurrences of the same word in a strin

    - by Steven
    In Actionscript and Adobe Flex, I'm using a pattern and regexp (with the global flag) with the string.match method and it works how I'd like except when the match returns multiple occurrences of the same word in the text. In that case, all the matches for that word point only to the index for the first occurrence of that word. For example, if the text is "cat dog cat cat cow" and the pattern is a search for cat*, the match method returns an array of three occurrences of "cat", however, they all point to only the index of the first occurrence of cat when i use indexOf on a loop through the array. I'm assuming this is just how the string.match method is (although please let me know if i'm doing something wrong or missing something!). I want to find the specific indices of every occurrence of a match, even if it is of a word that was already previously matched. I'm wondering if that is just how the string.match method is and if so, if anyone has any idea what the best way to do this would be. Thanks.

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  • asp.net regular expression not working as expected

    - by Zaps
    Hi, I have a textbox and a regular expression validator applied to it. I want to make sure that the only allowed string inputted into the textbox are "Anything Entered" or "Something Else" or "Another String" otherwise I want an error to be displayed. This is the regular expression I have so far: ValidationExpression="(^Anything Entered)$|(^Something Else)$ |(^Another String)$" However when I enter the supposed valid strings the error is displayed. I cant figure out whats wrong with the expression. Any help would be greatly appreciated. Thanks, Zaps

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  • Using regular expressions with Dojo data.fetch?

    - by Dfowj
    I'm trying to use the below code to fetch a regular expression like this /[computer]{3,8}/(what i think is any words containing the letters in computer ranging from 3 to 8 letters long) from a database (which i know is being loaded correctly). When i fetch, i get 10 results, all the same word... "Adenauer" var base = "computer"; var baseRE = '/[' + base + ']{' + this.minLength + ',' + base.length + '}/'; this.dict.fetch({query: {word:baseRE}, onComplete: onLoadWords, onError: function(err) { console.log(err); }}); Any ideas what im doing wrong?

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • MySql Not Like Regexp?

    - by KnockKnockWhosThere
    I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

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  • How to check that a regular expression fall into infty loop or not?

    - by Sorush Rabiee
    I'm trying to learn and hopefully use regular expression with Qt. I found that some patterns cause handler to fall into loop. for example searching \b\b in a text, never will terminate. and number of these expressions is infinite (\b\b\b,\b\b\b\b and so on). I'd like to determine and control all invalid expressions. Is there an algorithm to distinguish valid and invalid expressions? If not, how can I prevent my program from falling into an infinite loop?

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  • Find all substrings between two strings

    - by Orsol
    I need to get all substrings from string. For ex: StringParser.GetSubstrings("[start]aaaaaa[end] wwwww [start]cccccc[end]", "[start]", "[end]"); that returns 2 string "aaaaaa" and "cccccc" Suppose we have only one level of nesting. Not sure about regexp, but I think it will be userful.

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  • How to pull the file name from a url using javascript/jquery?

    - by jim23
    A certain variable might contain a relative path or an absolute path. Either way, I need to be able to pull the filename from the variable: http://www.somesite.com/dir1/dir2/filename.gif /dir1/dir2/filename.gif The directory structure is also arbitrary. So basically given either of the url's above (with arbirtrary directory structure) I need to pull 'filename.gif'. Thanks in advance

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  • Simple Search and Replace use of Regular Expression

    - by nunos
    So, I am adapting some code I found online to suit my needs. However, my set_pixel function has two more parameters. Since there are lots of calls to this function even doing a quick paste over would be very tedious. So, I thought this would be a good time for me to learn some simple regular expressions. So, I have calls of this type: set_pixel(arg1, arg2); which I want to change to something like: set_pixel(arg1, arg2, arg3, arg4); Note: arg1 and and 2 should be preserved, whereas arg3 and arg4 are most of the time the same. How can I achieve this?

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  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

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  • I'm trying to match some numbers in a string using a regexpressions and am having difficulty with th

    - by Ryan
    here is the line i'm trying to parse [\\?\Volume{d3f7f470-526b-11df-92eb-001a647802d2}\] 85 90 NotFound I'm basically just trying to get the numbers that are outside of the brackets and ignore anything in between the brackets. My original syntax worked until I realized that sometimes there would be numbers in the brackets (I was just using "([0-99]{2})") any help would be greatly appreciated. Thanks

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  • Pulling international street addresses / phone numbers from free-form text

    - by spitzanator
    Hey, folks. I'm looking for some regular expressions to help grab street addresses and phone numbers from free-form text (a la Gmail). Given some text: "John, I went to the store today, and it was awesome! Did you hear that they moved to 500 Green St.? ... Give me a call at +14252425424 when you get a chance." I'd like to be able to pull out: 500 Green St. (recognized as a street address) +14252425424 (recognized as a phone number) What makes this problem easier is that I don't care about parsing text that gets pulled out. That is, I don't care that Green is the name of the road or that 425 is the area code. I just want to grab strings that "look like" addresses or telephone numbers. Unfortunately, this needs to work internationally, as best as possible. Anyone have any leads? Thanks!

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  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • Need to add specific characters to regular expression

    - by lordryan
    i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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  • Regular Expression

    - by equilibrium
    Ohh! this regular expression thing is eating my brain up. I have been reading it from Introduction to Automata Theory, Languages and Computer by Hopcroft, Motwani and Ullman. I have solved a few exercises too but could not solve the following even after trying for almost one hr. The problem is to write a regular expression that defines a language consisting of all strings of 0s and 1s except the substring 011. Is the answer (0+1)* - 011 correct ? If not what should be the correct answer for this?

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  • How can I handle validation of non-latin script input in PHP?

    - by Matt
    I am trying to adapt a php application to handle non-latin scripts (specifically: Japanese, simplified Chinese and Arabic). The app's data validation routines make frequent use of regular expressions to check input, but I am not sure how to adapt the \w character type to other languages without installing additional locales on the system (which I cannot rely on). Previous developers to have worked on the app have simply added needed characters to the regexes as the number of languages we supported grew (you frequently see "[\wÀÁÂÃÄÅÆÇÈÉ... etc" in the code), but I can't really do this for all the alphabets I need to support now. Does anybody out there have some advice on how to tackle this?

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  • How to match a variable list of items separated by commas

    - by user261915
    I want to turn something like this CS 240, CS 246, ECE 222, ... (more or less); Software Engineering students only into ('CS 240', 'CS 246', 'ECE 222', 'ECE 220') in Python, code that matches a single course looks like >>> re.search('([A-Z]{2,5} \d{3})', 'SE 112').groups() ('SE 112',) I prefer a regular expression only method because I have a bunch of other alternate reg exps using '|' to combine them. However, a method with split is acceptable.

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