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  • Why does this symfony code not work?

    - by morpheous
    I am trying to pass parameters from one action (foo) to another (foobar). In action foo, I set the arguments thus: $request->getParameterHolder()->set('arg1', 'alice'); $request->getParameterHolder()->set('arg2', 'bob'); In action foobar, I try to retrieve the params thus: $arg1 = $request->getParameter('arg1'); $arg2 = $request->getParameter('arg2'); $this->forward404Unless($arg1 && $arg2); //always forwarded Note: I am aware that I can save the params into the user session variable - but I dont want to do that. I want to pass them as parameters - any ideas how to get this to work?

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  • Why can't I handle a KeyboardInterrupt in python?

    - by Josh
    I'm writing python 2.6.6 code on windows that looks like this: try: dostuff() except KeyboardInterrupt: print "Interrupted!" except: print "Some other exception?" finally: print "cleaning up...." print "done." dostuff() is a function that loops forever, reading a line at a time from an input stream and acting on it. I want to be able to stop it and clean up when I hit ctrl-c. What's happening instead is that the code under except KeyboardInterrupt: isn't running at all. The only thing that gets printed is "cleaning up...", and then a traceback is printed that looks like this: Traceback (most recent call last): File "filename.py", line 119, in <module> print 'cleaning up...' KeyboardInterrupt So, exception handling code is NOT running, and the traceback claims that a KeyboardInterrupt occurred during the finally clause, which doesn't make sense because hitting ctrl-c is what caused that part to run in the first place! Even the generic except: clause isn't running. EDIT: Based on the comments, I replaced the contents of the try: block with sys.stdin.read(). The problem still occurs exactly as described, with the first line of the finally: block running and then printing the same traceback.

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  • Why does R sometimes stop displaying output?

    - by Winston C. Yang
    Sometimes R stops displaying output. I type the number 1, followed by the return key, and nothing appears. This situation occurred after I pressed the "STOP" icon in the window, which is for stopping long calculations. I'm using R 2.11.0 on a Mac. Does pressing "STOP" cause R to stop displaying output? How do I get R to display output again?

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  • Why does this threading approach not work?

    - by Tomas Lycken
    I have a wierd problem with threading in an ASP.NET application. For some reason, when I run the code in the request thread, everything works as expected. But when I run it in a separate thread, nothing happens. This is verified by calling the below handler with the three flags "on", "off" and "larma" respectively - in the two first cases everything works, but in the latter nothing happens. What am I doing wrong here? In the web project I have a generic handler with the following code: If task = "on" Then Alarm.StartaLarm(personId) context.Response.Write("Larmet är PÅ") ElseIf task = "off" Then Alarm.StoppaLarm(personId) context.Response.Write("Larmet är AV") ElseIf task = "larma" Then Alarm.Larma(personId) context.Response.Write("Larmar... (stängs av automagiskt)") Else context.Response.Write("inget hände - task: " & task) End If The Alarm class has the following methods: Private Shared Sub Larma_Thread(ByVal personId As Integer) StartaLarm(personId) Thread.Sleep(1000 * 30) StoppaLarm(personId) End Sub Public Shared Sub StartaLarm(ByVal personId As Integer) SandSMS(True, personId) End Sub Public Shared Sub StoppaLarm(ByVal personId As Integer) SandSMS(False, personId) End Sub Public Shared Sub SandSMS(ByVal setOn As Boolean, ByVal personId As Integer) ... End Sub

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  • Why wouldn't an S3 ACL "stick"?

    - by Chris Phillips
    We would like to set an ACL to allow access to one of our buckets with a partner account. We've tested the process on a test account and everything works fine. On our production account/buckets, however, we can set the ACL and see the update but as soon as we attempt to access the bucket from the other account we get a forbidden response. Afterwards, when we look at the ACL list for the bucket, the permission is gone. We've tried using both Amazon's new S3 tool in the AWS Management Console and CloudBerry Explorer and both tools exhibit exactly the same behavior. Using the same process to update an ACL from our test account works as expected ( the ACL update "sticks" ). What would cause the ACL to not "stick"? Does anyone have any ideas on how to fix/workaround the problem?

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  • Why is the main method not covered?

    - by Mike.Huang
    main method: public static void main(String[] args) throws Exception { if (args.length != EXPECTED_NUMBER_OF_ARGUMENTS) { System.err.println("Usage - java XFRCompiler ConfigXML PackageXML XFR"); } String configXML = args[0]; String packageXML = args[1]; String xfr = args[2]; AutoConfigCompiler compiler = new AutoConfigCompiler(); compiler.setConfigDocument(loadDocument(configXML)); compiler.setPackageInfoDoc(loadDocument(packageXML)); // compiler.setVisiblityDoc(loadDocument("VisibilityFilter.xml")); compiler.compileModel(xfr); } private static Document loadDocument(String fileName) throws Exception { TXDOMParser parser = (TXDOMParser) ParserFactory.makeParser(TXDOMParser.class.getName()); InputSource source = new InputSource(new FileInputStream(fileName)); parser.parse(source); return parser.getDocument(); } testcase: @Test public void testCompileModel() throws Exception { // construct parameters URL configFile = Thread.currentThread().getContextClassLoader().getResource("Ford_2008_Mustang_Config.xml"); URL packageFile = Thread.currentThread().getContextClassLoader().getResource("Ford_2008_Mustang_Package.xml"); File tmpFile = new File("Ford_2008_Mustang_tmp.xfr"); if(!tmpFile.exists()) { tmpFile.createNewFile(); } String[] args = new String[]{configFile.getPath(),packageFile.getPath(),tmpFile.getPath()}; try { // test main method XFRCompiler.main(args); } catch (Exception e) { assertTrue(true); } try { // test args length is less than 3 XFRCompiler.main(new String[]{"",""}); } catch (Exception e) { assertTrue(true); } tmpFile.delete(); } Coverage outputs displayed as the lines from String configXML = args[0]; in main method are not covered.

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  • Why doesn't this PHP execute?

    - by cam
    I copied the code from this site exactly: http://davidwalsh.name/web-service-php-mysql-xml-json as follows, /* require the user as the parameter */ if(isset($_GET['user']) && intval($_GET['user'])) { /* soak in the passed variable or set our own */ $number_of_posts = isset($_GET['num']) ? intval($_GET['num']) : 10; //10 is the default $format = strtolower($_GET['format']) == 'json' ? 'json' : 'xml'; //xml is the default $user_id = intval($_GET['user']); //no default /* connect to the db */ $link = mysql_connect('localhost','username','password') or die('Cannot connect to the DB'); mysql_select_db('db_name',$link) or die('Cannot select the DB'); /* grab the posts from the db */ $query = "SELECT post_title, guid FROM wp_posts WHERE post_author = $user_id AND post_status = 'publish' ORDER BY ID DESC LIMIT $number_of_posts"; $result = mysql_query($query,$link) or die('Errant query: '.$query); /* create one master array of the records */ $posts = array(); if(mysql_num_rows($result)) { while($post = mysql_fetch_assoc($result)) { $posts[] = array('post'=>$post); } } /* output in necessary format */ if($format == 'json') { header('Content-type: application/json'); echo json_encode(array('posts'=>$posts)); } else { header('Content-type: text/xml'); echo '<posts>'; foreach($posts as $index => $post) { if(is_array($post)) { foreach($post as $key => $value) { echo '<',$key,'>'; if(is_array($value)) { foreach($value as $tag => $val) { echo '<',$tag,'>',htmlentities($val),'</',$tag,'>'; } } echo '</',$key,'>'; } } } echo '</posts>'; } /* disconnect from the db */ @mysql_close($link); } And the php doesn't execute, it just displays as plain text. What's the dealio? The host supports PHP, I use it to run a Wordpress blog and other things.

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  • Why is Rails date comparison not working?

    - by revgum
    What am I missing here, it's driving me crazy.. >> user.current_login_at.utc > 24.hours.ago.utc => false >> 24.hours.ago.utc => Mon May 17 18:46:16 UTC 2010 >> user.current_login_at.utc => Mon May 17 15:47:44 UTC 2010 user.current_login_at was 27 hours ago, yet the greater than comparison says it was not greater than 24 hours ago. It leaves me scratching my head..

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  • How and why is ap defined as liftM2 id in Haskell

    - by luke_randall
    Whilst trying to better understand Applicative, I looked at the definition of <*, which tends to be defined as ap, which in turn is defined as: ap :: (Monad m) => m (a -> b) -> m a -> m b ap = liftM2 id Looking at the type signatures for liftM2 and id, namely: liftM2 :: (Monad m) => (a1 -> a2 -> r) -> m a1 -> m a2 -> m r id :: a -> a I fail to understand how just by passing in id, the relevant part of the type signature seems to transform from (a1 -> a2 -> r) -> m a1 to m (a -> b). What am I missing here?

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  • can anyone explain the why the the 1st example gets different results than the following 2

    - by klumsy
    $b = (2,3) $myarray1 = @(,$b,$b) $myarray1[0].length #this will be 1 $myarray1[1].length $myarray2 = @( ,$b ,$b ) $myarray2[0].length #this will be 2 $myarray[1].length $myarray3 = @(,$b ,$b ) $myarray3[0].length #this will be 2 $myarray3[1].length UPDATE I think on #powershell IRC we have worked it out, Here is another example that demonstrates the danger of breaking with the comma on the following line rather than the top line when listing multiple items in an array over multiple lines. $b = (1..20) $a = @( $b, $b ,$b, $b, $b ,$b) for($i=0;$i -lt $a.length;$i++) { $a[$i].length } "--------" $a = @( $b, $b ,$b ,$b, $b ,$b) for($i=0;$i -lt $a.length;$i++) { $a[$i].length } produces 20 20 20 20 20 20 -------- 20 20 20 1 20 20 I'm curious how people will explain this. I think i understand it now, but would have trouble explaining it in a concise understandable fashion, though the above example goes somewhat towards that goal.

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  • why my image path is not taken?

    - by udaya
    Hi I am getting the image path from database in this foreach foreach($image as $row){ $value = $row['dPath']; $imgpath =base_url()."images/".$value;//this is not taken $imgpath = base_url()."images/con_icon.jpg";//this$imgpath is taken echo $value; when i give $imgpath as $imgpath = base_url()."images/con_icon.jpg"; it is accepted in <img src="<?php echo $imgpath; ?>" and image is displayed But when i give $imgpath as $imgpath =base_url()."images/".$value; but echo $value; results con_icon.jpg The image is not displayed what is the problem

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  • Why doesn't MySQL support millisecond / microsecond precision?

    - by Byron Whitlock
    So I just found the most frustrating bug ever in MySQL. Apparently the TIMESTAMP field, and supporting functions do not support any greater precision than seconds!? So I am using PHP and Doctrine, and I really need those microseconds (I am using the actAs: [Timestampable] property). I found a that I can use a BIGINT field to store the values. But will doctrine add the milliseconds? I think it just assigns NOW() to the field. I am also worried the date manipulation functions (in SQL) sprinkled through the code will break. I also saw something about compiling a UDF extension. This is not an acceptable because I or a future maintainer will upgrade and poof, change gone. Has anyone found a suitable workaround?

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  • Why my image is up side down?

    - by Tattat
    This is my drawInContext method: UIImage *img = [UIImage imageWithContentsOfFile: [[NSBundle mainBundle] pathForResource:@"myImage" ofType:@"png"]]; CGRect cropRect = CGRectMake(0, 0, 175, 175); CGImageRef imageRef = CGImageCreateWithImageInRect([img CGImage], cropRect); CGRect imageRect; imageRect.origin = CGPointMake(0, 0); imageRect.size = CGSizeMake(175, 175); CGContextDrawImage(UIGraphicsGetCurrentContext(), imageRect, imageRef); CGImageRelease(imageRef); My image is upside down, how can I change it? What's wrong with my code? How can I change the image become normal?? thx .

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  • Why won't my control accept keyboard input?

    - by Mason Wheeler
    I've built a custom control that I'm trying to send input to. It will accept mouse input and report MouseDown, MouseMove and MouseUp correctly, but for whatever reason, it won't accept keyboard input. When I click on it, it doesn't receive focus, and any keys I press get interpreted by whatever control had the focus already. This is probably something really simple. The first place I thought to look was in the ControlStyle property, but the only thing I can see in the helpfile about keyboard input is csNoStdEvents, which disables it, and my control doesn't have that. So what do I need to do to make it so my control can receive input focus?

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  • Why isn't my File.Move() working?

    - by yeahumok
    I'm not sure what exactly i'm doing wrong here...but i noticed that my File.Move() isn't renaming any files. Also, does anybody know how in my 2nd loop, i'd be able to populate my .txt file with a list of the path AND sanitized file name? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Text.RegularExpressions; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { //recurse through files. Let user press 'ok' to move onto next step string[] files = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); //End section //Regex -- find invalid chars string pattern = " *[\\~#%&*{}/<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); List<string> filePath = new List<string>(); //clean out file -- remove the path name so file name only shows string result; foreach(string fileNames in fileDrive) { result = Path.GetFileName(fileNames); filePath.Add(result); } StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); //Sanitize and remove invalid chars foreach(string Files2 in filePath) { try { string sanitized = regEx.Replace(Files2, replacement); sw.Write(sanitized + "\r\n"); System.IO.File.Move(Files2, sanitized); System.IO.File.Delete(Files2); } catch (Exception ex) { Console.Write(ex); } } sw.Close(); } } } I'm VERY new to C# and trying to write an app that recurses through a specific drive, finds invalid characters (as specified in the RegEx pattern), removes them from the filename and then write a .txt file that has the path name and the corrected filename. Any ideas?

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  • Why isn't the boost::shared_ptr -> operator inlined?

    - by Alan
    Since boost::shared_ptr could be called very frequently and simply returns a pointer, isn't the -> operator a good candidate for being inlined? T * operator-> () const // never throws { BOOST_ASSERT(px != 0); return px; } Would a good compiler automatically inline this anyway? Should I lose any sleep over this? :-)

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  • Why doesn't my Perl script start under FastCGI?

    - by Sam
    I am getting this error in error_log one of my Perl CGI application. I am pretty sure I haven't changed my script at all and all of a sudden i have started getting this error. This is what I see in error_log: [Wed Jul 8 15:18:20 2009] [warn] FastCGI: server "/local/web/test/cgi-bin/test.pl" (pid 17033) terminated by calling exit with status '255' [Wed Jul 8 15:18:20 2009] [warn] FastCGI: server "/local/web/test/cgi-bin/test.pl" has failed to remain running for 30 seconds given 3 attempts, its restart interval has been backed off to 600 seconds (The snippet was edited for clarity) Also, the AddHandler line for FastCGI exists in the config file. Can any tell me the possible reasons for this error? There is nothing recorded in Apache logs.

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  • Why it's important to specify the complete class name in your association when using namespaces

    - by Carmine Paolino
    In my Rails application there is a model that has some has_one associations (this is a fabricated example): class Person::Admin < ActiveRecord::Base has_one :person_monthly_revenue has_one :dude_monthly_niceness accepts_nested_attributes_for :person_monthly_revenue, :dude_monthly_niceness end class Person::MonthlyRevenue < ActiveRecord::Base belongs_to :person_admin end class Dude::MonthlyNiceness < ActiveRecord::Base belongs_to :person_admin end The application talks to a backend that computes some data and returns a piece of JSON like this: { "dude_monthly_niceness": { "february": 1.1153232569518972, "october": 1.1250217200558268, "march": 1.3965786869658541, "august": 1.6293418014601631, "september": 1.4062771500697835, "may": 1.7166279693955291, "january": 1.0086401628086725, "june": 1.5711510228365859, "april": 1.5614525597326563, "december": 0.99894169970474289, "july": 1.7263264324994585, "november": 0.95044938418509506 }, "person_monthly_revenue": { "february": 10.585596551505297, "october": 10.574823016656749, "march": 9.9125274764852787, "august": 9.2111604702328922, "september": 9.7905249446675153, "may": 9.1329712474607962, "january": 10.479614016604238, "june": 9.3710235926961936, "april": 9.5897372624830304, "december": 10.052587677671438, "july": 8.9508877843925561, "november": 10.925339756096172 }, } To deserialize it, I use ActiveRecord's from_json, but instead of a Person::Admin object with all the associations in place, I get this error: >> Person::Admin.new.from_json(json) NameError: uninitialized constant Person::Admin::DudeMonthlyNiceness Am I doing something wrong? Is there a better way to deserialize data? (I can modify the backend easily) UPDATE: the original title was "How to deserialize from json to ActiveRecord objects with associations?" but it ended up being my mistake in specifying associations so I changed the title.

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  • Why Is Apache Giving 403?

    - by ThinkCL
    I am getting 403 Errors from Apache when I send too many, 12, synchronous HTTP Posts via a desktop app I am building in XCode / Objective-C. The 12 POST requests are just a few kb each and go out instantly one after the other and the Apache Error Log shows... client denied by server configuration: /the-path/the-file.php Apache 2.0 PHP 5 and I have this same setup working fine on my local machine. The error is coming from a VPS with my host, which runs very fast and smooth and has plenty of resources. To debug I threw a sleep(1); function (stalls script execution by 1 second) into the php file and that fixed it. This makes me think that I am breaking some limit for too many requests for a single IP in a certain amount of time. I have googled and combed PHP ini and Apache configs, but I cannot find what that directive/setting might be. I should mention that the although it varies the first 4 or 5 POSTS usually work then it starts returning the 403 error intermittently after that. Just really acting like its bogging down. Any ideas?

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  • Why won't this sql update query work?

    - by Wesley
    I have a table that has 5,000(table1) lines in it. Currently, 3,000 of them are filled up with data. The remaining values are currently null. In a separate table(table2), I have the remaining 2,000 rows of data. I am simply trying to take the values in table2 and put them in table1, but this statement isn't working: Update table1 Set field1 = (Select field1 From table2 Where table1.id = table2.id) Where Exists(Select field1 From table2 Where table1.id = table2.id) It looks like this should be working, but I am getting an error from Base, the db program I am using that just says error Near " ": syntax error...any help?? Thanks!

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  • Why I can't use template table in dynamic query SQL SERVER 2005

    - by StuffHappens
    Hello! I have the following t-sql code which generates an error Declare @table TABLE ( ID1 int, ID2 int ) INSERT INTO @table values(1, 1); INSERT INTO @table values(2, 2); INSERT INTO @table values(3, 3); DECLARE @field varchar(50); SET @field = 'ID1' DECLARE @query varchar(MAX); SET @query = 'SELECT * FROM @table WHERE ' + @field + ' = 1' EXEC (@query) The error is Must declare the table variable "@table". What's wrong with the query. How to fix it?

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