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  • How to find out where a thread lock happend?

    - by SchlaWiener
    One of our company's Windows Forms application had a strange problem for several month. The app worked very reliable for most of our customers but on some PC's (mostly with a wireless lan connection) the app sometimes just didn't respond anymore. (You click on the UI and windows ask you to wait or kill the app). I wasn't able to track down the problem for a long time but now I figured out what happend. The app had this line of code // don't blame me for this. Wasn't my code :D Control.CheckForIllegalCrossThreadCalls = false and used some background threads to modify the controls. No I found a way to reproduce the application stopping responding bug on my dev machine and tracked it down to a line where I actually used Invoke() to run a task in the main thread. Me.Invoke(MyDelegate, arg1, arg2) Obviously there was a thread lock somewhere. After removing the Control.CheckForIllegalCrossThreadCalls = false statement and refactoring the whole programm to use Invoke() if modifying a control from a background thread, the problem is (hopefully) gone. However, I am wondering if there is a way to find such bugs without debugging every line of code (Even if I break into debugger after the app stops responding I can't tell what happend last, because the IDE didn't jump to the Invoke() statement) In other words: If my apps hangs how can I figure out which line of code has been executed last? Maybe even on the customers PC. I know VS2010 offers some backwards debugging feature, maybe that would be a solution, but currently I am using VS2008.

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  • C#, Can I check on a lock without trying to acquire it?

    - by Biff MaGriff
    Hello, I have a lock in my c# web app that prevents users from running the update script once it has started. I was thinking I would put a notification in my master page to let the user know that the data isn't all there yet. Currently I do my locking like so. protected void butRefreshData_Click(object sender, EventArgs e) { Thread t = new Thread(new ParameterizedThreadStart(UpdateDatabase)); t.Start(this); //sleep for a bit to ensure that javascript has a chance to get rendered Thread.Sleep(100); } public static void UpdateDatabase(object con) { if (Monitor.TryEnter(myLock)) { Updater.RepopulateDatabase(); Monitor.Exit(myLock); } else { Common.RegisterStartupScript(con, AlreadyLockedJavaScript); } } And I do not want to do if(Monitor.TryEnter(myLock)) Monitor.Exit(myLock); else //show processing labal As I imagine there is a slight possibility that it might display the notification when it isn't actually running. Is there an alternative I can use? Edit: Hi Everyone, thanks a lot for your suggestions! Unfortunately I couldn't quite get them to work... However I combined the ideas on 2 answers and came up with my own solution.

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  • How should I lock the table in this VB6 / Access application?

    - by Brian Hooper
    I'm working on a VB6 application using an Access database. The application writes messages to a log table from time to time. Several instances of the application may be running simultaneously and to distinguish them they each have their own run number. The run number is deduced from the log table thus... Set record_set = New ADODB.Recordset query_string = "SELECT MAX(RUN_NUMBER) + 1 AS NEW_RUN_NUMBER FROM ERROR_LOG" record_set.CursorLocation = adUseClient record_set.Open query_string, database_connection, adOpenStatic, , adCmdText record_set.MoveLast If IsNull(record_set.Fields("NEW_RUN_NUMBER")) Then run_number = 0 Else run_number = record_set.Fields("NEW_RUN_NUMBER") End If command_string = "INSERT INTO ERROR_LOG (RUN_NUMBER, SEVERITY, MESSAGE) " & _ " VALUES (" & Str$(run_number) & ", " & _ " " & Str$(SEVERITY_INFORMATION) & ", " & _ " 'Run Started'); " database_connection.Execute command_string Obviously there is a small gap between the calculation of the run number and the appearance of the new row in the database, and to prevent another instance getting access between the two operations I'd like to lock the table; something along the lines of SET TRANSACTION READ WRITE RESERVING ERROR_LOG FOR PROTECTED WRITE; How should I go about doing this? Would locking the recordset do any good (the row in the record set doesn't match any particular row in the database)?

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  • Microbenchmark showing process-switching faster than thread-switching; what's wrong?

    - by Yang
    I have two simple microbenchmarks trying to measure thread- and process-switching overheads, but the process-switching overhead. The code is living here, and r1667 is pasted below: https://assorted.svn.sourceforge.net/svnroot/assorted/sandbox/trunk/src/c/process_switch_bench.c // on zs, ~2.1-2.4us/switch #include <stdlib.h> #include <fcntl.h> #include <stdint.h> #include <stdio.h> #include <semaphore.h> #include <unistd.h> #include <sys/wait.h> #include <sys/types.h> #include <sys/time.h> #include <pthread.h> uint32_t COUNTER; pthread_mutex_t LOCK; pthread_mutex_t START; sem_t *s0, *s1, *s2; void * threads ( void * unused ) { // Wait till we may fire away sem_wait(s2); for (;;) { pthread_mutex_lock(&LOCK); pthread_mutex_unlock(&LOCK); COUNTER++; sem_post(s0); sem_wait(s1); } return 0; } int64_t timeInMS () { struct timeval t; gettimeofday(&t, NULL); return ( (int64_t)t.tv_sec * 1000 + (int64_t)t.tv_usec / 1000 ); } int main ( int argc, char ** argv ) { int64_t start; pthread_t t1; pthread_mutex_init(&LOCK, NULL); COUNTER = 0; s0 = sem_open("/s0", O_CREAT, 0022, 0); if (s0 == 0) { perror("sem_open"); exit(1); } s1 = sem_open("/s1", O_CREAT, 0022, 0); if (s1 == 0) { perror("sem_open"); exit(1); } s2 = sem_open("/s2", O_CREAT, 0022, 0); if (s2 == 0) { perror("sem_open"); exit(1); } int x, y, z; sem_getvalue(s0, &x); sem_getvalue(s1, &y); sem_getvalue(s2, &z); printf("%d %d %d\n", x, y, z); pid_t pid = fork(); if (pid) { pthread_create(&t1, NULL, threads, NULL); pthread_detach(t1); // Get start time and fire away start = timeInMS(); sem_post(s2); sem_post(s2); // Wait for about a second sleep(1); // Stop thread pthread_mutex_lock(&LOCK); // Find out how much time has really passed. sleep won't guarantee me that // I sleep exactly one second, I might sleep longer since even after being // woken up, it can take some time before I gain back CPU time. Further // some more time might have passed before I obtained the lock! int64_t time = timeInMS() - start; // Correct the number of thread switches accordingly COUNTER = (uint32_t)(((uint64_t)COUNTER * 2 * 1000) / time); printf("Number of process switches in about one second was %u\n", COUNTER); printf("roughly %f microseconds per switch\n", 1000000.0 / COUNTER); // clean up kill(pid, 9); wait(0); sem_close(s0); sem_close(s1); sem_unlink("/s0"); sem_unlink("/s1"); sem_unlink("/s2"); } else { if (1) { sem_t *t = s0; s0 = s1; s1 = t; } threads(0); // never return } return 0; } https://assorted.svn.sourceforge.net/svnroot/assorted/sandbox/trunk/src/c/thread_switch_bench.c // From <http://stackoverflow.com/questions/304752/how-to-estimate-the-thread-context-switching-overhead> // on zs, ~4-5us/switch; tried making COUNTER updated only by one thread, but no difference #include <stdlib.h> #include <stdint.h> #include <stdio.h> #include <pthread.h> #include <unistd.h> #include <sys/time.h> uint32_t COUNTER; pthread_mutex_t LOCK; pthread_mutex_t START; pthread_cond_t CONDITION; void * threads ( void * unused ) { // Wait till we may fire away pthread_mutex_lock(&START); pthread_mutex_unlock(&START); int first=1; pthread_mutex_lock(&LOCK); // If I'm not the first thread, the other thread is already waiting on // the condition, thus Ihave to wake it up first, otherwise we'll deadlock if (COUNTER > 0) { pthread_cond_signal(&CONDITION); first=0; } for (;;) { if (first) COUNTER++; pthread_cond_wait(&CONDITION, &LOCK); // Always wake up the other thread before processing. The other // thread will not be able to do anything as long as I don't go // back to sleep first. pthread_cond_signal(&CONDITION); } pthread_mutex_unlock(&LOCK); return 0; } int64_t timeInMS () { struct timeval t; gettimeofday(&t, NULL); return ( (int64_t)t.tv_sec * 1000 + (int64_t)t.tv_usec / 1000 ); } int main ( int argc, char ** argv ) { int64_t start; pthread_t t1; pthread_t t2; pthread_mutex_init(&LOCK, NULL); pthread_mutex_init(&START, NULL); pthread_cond_init(&CONDITION, NULL); pthread_mutex_lock(&START); COUNTER = 0; pthread_create(&t1, NULL, threads, NULL); pthread_create(&t2, NULL, threads, NULL); pthread_detach(t1); pthread_detach(t2); // Get start time and fire away start = timeInMS(); pthread_mutex_unlock(&START); // Wait for about a second sleep(1); // Stop both threads pthread_mutex_lock(&LOCK); // Find out how much time has really passed. sleep won't guarantee me that // I sleep exactly one second, I might sleep longer since even after being // woken up, it can take some time before I gain back CPU time. Further // some more time might have passed before I obtained the lock! int64_t time = timeInMS() - start; // Correct the number of thread switches accordingly COUNTER = (uint32_t)(((uint64_t)COUNTER * 2 * 1000) / time); printf("Number of thread switches in about one second was %u\n", COUNTER); printf("roughly %f microseconds per switch\n", 1000000.0 / COUNTER); return 0; }

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  • Xorg server won't start after fresh install of Debian 5.04, screen goes blank (Intel Atom D510(Pinet

    - by Kamil Zadora
    Hello, I have installed Debian 5.04 Lenny on my new Intel D510MO motheboard. I fixed some issues with incorrect drive mapping (for some reason during installation my hdd was on sdb, after a restart it is under sda - fixed in grub), and now I am struggling with getting graphical enviroment up and running, I installed the graphical enviroment using the Debian installer. I am not an linux expert by any means, I assume that I need to edit the xorg.conf file. Any hints appreciated! UPDATE1: No change after dpkg-reconfigure xserver-xorg Here is my current xorg.conf: # xorg.conf (X.Org X Window System server configuration file) # # This file was generated by dexconf, the Debian X Configuration tool, using # values from the debconf database. # # Edit this file with caution, and see the xorg.conf manual page. # (Type "man xorg.conf" at the shell prompt.) # # This file is automatically updated on xserver-xorg package upgrades *only* # if it has not been modified since the last upgrade of the xserver-xorg # package. # # If you have edited this file but would like it to be automatically updated # again, run the following command: # sudo dpkg-reconfigure -phigh xserver-xorg Section "InputDevice" Identifier "Generic Keyboard" Driver "kbd" Option "XkbRules" "xorg" Option "XkbModel" "pc105" Option "XkbLayout" "pl" EndSection Section "InputDevice" Identifier "Configured Mouse" Driver "mouse" EndSection Section "Device" Identifier "Configured Video Device" EndSection Section "Monitor" Identifier "Configured Monitor" EndSection Section "Screen" Identifier "Default Screen" Monitor "Configured Monitor" EndSection UPDATE2: I have installed vnc4server package. I can connect over vnc from my windows 7 laptop and i see empty desktop with terminal window open. Seems that the xserver and gdm are running but they cant talk with my GPU. I am not sure if a can use any gui tool to configure it overthe vnc, as all I see is the terminal window, no taskbars etc. UPDATE3: My current Xorg.0.log http://pastebin.pl/18918 The graphic chipset integrated into the D510 processor is Intel 945GC

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  • Parallelism in .NET – Part 4, Imperative Data Parallelism: Aggregation

    - by Reed
    In the article on simple data parallelism, I described how to perform an operation on an entire collection of elements in parallel.  Often, this is not adequate, as the parallel operation is going to be performing some form of aggregation. Simple examples of this might include taking the sum of the results of processing a function on each element in the collection, or finding the minimum of the collection given some criteria.  This can be done using the techniques described in simple data parallelism, however, special care needs to be taken into account to synchronize the shared data appropriately.  The Task Parallel Library has tools to assist in this synchronization. The main issue with aggregation when parallelizing a routine is that you need to handle synchronization of data.  Since multiple threads will need to write to a shared portion of data.  Suppose, for example, that we wanted to parallelize a simple loop that looked for the minimum value within a dataset: double min = double.MaxValue; foreach(var item in collection) { double value = item.PerformComputation(); min = System.Math.Min(min, value); } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } This seems like a good candidate for parallelization, but there is a problem here.  If we just wrap this into a call to Parallel.ForEach, we’ll introduce a critical race condition, and get the wrong answer.  Let’s look at what happens here: // Buggy code! Do not use! double min = double.MaxValue; Parallel.ForEach(collection, item => { double value = item.PerformComputation(); min = System.Math.Min(min, value); }); This code has a fatal flaw: min will be checked, then set, by multiple threads simultaneously.  Two threads may perform the check at the same time, and set the wrong value for min.  Say we get a value of 1 in thread 1, and a value of 2 in thread 2, and these two elements are the first two to run.  If both hit the min check line at the same time, both will determine that min should change, to 1 and 2 respectively.  If element 1 happens to set the variable first, then element 2 sets the min variable, we’ll detect a min value of 2 instead of 1.  This can lead to wrong answers. Unfortunately, fixing this, with the Parallel.ForEach call we’re using, would require adding locking.  We would need to rewrite this like: // Safe, but slow double min = double.MaxValue; // Make a "lock" object object syncObject = new object(); Parallel.ForEach(collection, item => { double value = item.PerformComputation(); lock(syncObject) min = System.Math.Min(min, value); }); This will potentially add a huge amount of overhead to our calculation.  Since we can potentially block while waiting on the lock for every single iteration, we will most likely slow this down to where it is actually quite a bit slower than our serial implementation.  The problem is the lock statement – any time you use lock(object), you’re almost assuring reduced performance in a parallel situation.  This leads to two observations I’ll make: When parallelizing a routine, try to avoid locks. That being said: Always add any and all required synchronization to avoid race conditions. These two observations tend to be opposing forces – we often need to synchronize our algorithms, but we also want to avoid the synchronization when possible.  Looking at our routine, there is no way to directly avoid this lock, since each element is potentially being run on a separate thread, and this lock is necessary in order for our routine to function correctly every time. However, this isn’t the only way to design this routine to implement this algorithm.  Realize that, although our collection may have thousands or even millions of elements, we have a limited number of Processing Elements (PE).  Processing Element is the standard term for a hardware element which can process and execute instructions.  This typically is a core in your processor, but many modern systems have multiple hardware execution threads per core.  The Task Parallel Library will not execute the work for each item in the collection as a separate work item. Instead, when Parallel.ForEach executes, it will partition the collection into larger “chunks” which get processed on different threads via the ThreadPool.  This helps reduce the threading overhead, and help the overall speed.  In general, the Parallel class will only use one thread per PE in the system. Given the fact that there are typically fewer threads than work items, we can rethink our algorithm design.  We can parallelize our algorithm more effectively by approaching it differently.  Because the basic aggregation we are doing here (Min) is communitive, we do not need to perform this in a given order.  We knew this to be true already – otherwise, we wouldn’t have been able to parallelize this routine in the first place.  With this in mind, we can treat each thread’s work independently, allowing each thread to serially process many elements with no locking, then, after all the threads are complete, “merge” together the results. This can be accomplished via a different set of overloads in the Parallel class: Parallel.ForEach<TSource,TLocal>.  The idea behind these overloads is to allow each thread to begin by initializing some local state (TLocal).  The thread will then process an entire set of items in the source collection, providing that state to the delegate which processes an individual item.  Finally, at the end, a separate delegate is run which allows you to handle merging that local state into your final results. To rewriting our routine using Parallel.ForEach<TSource,TLocal>, we need to provide three delegates instead of one.  The most basic version of this function is declared as: public static ParallelLoopResult ForEach<TSource, TLocal>( IEnumerable<TSource> source, Func<TLocal> localInit, Func<TSource, ParallelLoopState, TLocal, TLocal> body, Action<TLocal> localFinally ) The first delegate (the localInit argument) is defined as Func<TLocal>.  This delegate initializes our local state.  It should return some object we can use to track the results of a single thread’s operations. The second delegate (the body argument) is where our main processing occurs, although now, instead of being an Action<T>, we actually provide a Func<TSource, ParallelLoopState, TLocal, TLocal> delegate.  This delegate will receive three arguments: our original element from the collection (TSource), a ParallelLoopState which we can use for early termination, and the instance of our local state we created (TLocal).  It should do whatever processing you wish to occur per element, then return the value of the local state after processing is completed. The third delegate (the localFinally argument) is defined as Action<TLocal>.  This delegate is passed our local state after it’s been processed by all of the elements this thread will handle.  This is where you can merge your final results together.  This may require synchronization, but now, instead of synchronizing once per element (potentially millions of times), you’ll only have to synchronize once per thread, which is an ideal situation. Now that I’ve explained how this works, lets look at the code: // Safe, and fast! double min = double.MaxValue; // Make a "lock" object object syncObject = new object(); Parallel.ForEach( collection, // First, we provide a local state initialization delegate. () => double.MaxValue, // Next, we supply the body, which takes the original item, loop state, // and local state, and returns a new local state (item, loopState, localState) => { double value = item.PerformComputation(); return System.Math.Min(localState, value); }, // Finally, we provide an Action<TLocal>, to "merge" results together localState => { // This requires locking, but it's only once per used thread lock(syncObj) min = System.Math.Min(min, localState); } ); Although this is a bit more complicated than the previous version, it is now both thread-safe, and has minimal locking.  This same approach can be used by Parallel.For, although now, it’s Parallel.For<TLocal>.  When working with Parallel.For<TLocal>, you use the same triplet of delegates, with the same purpose and results. Also, many times, you can completely avoid locking by using a method of the Interlocked class to perform the final aggregation in an atomic operation.  The MSDN example demonstrating this same technique using Parallel.For uses the Interlocked class instead of a lock, since they are doing a sum operation on a long variable, which is possible via Interlocked.Add. By taking advantage of local state, we can use the Parallel class methods to parallelize algorithms such as aggregation, which, at first, may seem like poor candidates for parallelization.  Doing so requires careful consideration, and often requires a slight redesign of the algorithm, but the performance gains can be significant if handled in a way to avoid excessive synchronization.

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  • Dual NVidia graphics cards in Ubuntu / xorg.conf mania

    - by John Zwinck
    I have two NVidia graphics cards: Quadro NVS 295 (PCI Express, dual DisplayPort outputs) GeForce FX 5200 (PCI, DVI and VGA outputs) I have three identical monitors, two on DisplayPort and one on DVI. I'm on Ubuntu Hardy (and cannot currently dist-upgrade for separate reasons). I use the "nvidia" driver. What's new is the GeForce card and the third monitor. I currently have the dual DisplayPort monitors working fine. Here are the display-related parts of my xorg.conf: Section "ServerLayout" Identifier "Default Layout" Screen "PCI-Express Screen" 0 0 # adding this makes X fail to start: Screen "PCI Screen" 0 Inputdevice "Generic Keyboard" Inputdevice "Configured Mouse" EndSection Section "Module" Load "glx" # not sure why/if this is needed EndSection Section "Monitor" Identifier "DELL 2408WFP" Option "DPMS" EndSection Section "Device" Identifier "NVIDIA Quadro NVS 295" Driver "nvidia" Option "RenderAccel" "true" Screen 0 BusID "PCI:2:0:0" EndSection Section "Device" Identifier "NVIDIA GeForce FX 5200" Driver "nvidia" Option "RenderAccel" "true" Screen 1 BusID "PCI:6:4:0" EndSection Section "Screen" Identifier "PCI-Express Screen" Device "NVIDIA Quadro NVS 295" Monitor "DELL 2408WFP" Defaultdepth 24 Option "TwinView" "True" Option "UseEdidFreqs" "True" Option "MetaModes" "1920x1200 +0+1200, 1920x1200 +0+0" EndSection Section "Screen" Identifier "PCI Screen" Device "NVIDIA GeForce FX 5200" Monitor "DELL 2408WFP" Defaultdepth 24 Option "TwinView" "True" Option "UseEdidFreqs" "True" Option "MetaModes" "1920x1200 +0+0" EndSection I use nvidia-settings to configure my monitors, and it does not show the second GPU. lspci, though, shows: 02:00.0 VGA compatible controller: nVidia Corporation Unknown device 06fd 06:04.0 VGA compatible controller: nVidia Corporation NV34 [GeForce FX 5200] Which is where I got the BusID settings for the two devices (when I just had one device, I didn't have any BusID listed...and adding the BusID hasn't broken anything). What am I missing? How can I make nvidia-settings show my second GPU so I can then configure its monitor?

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  • Permission issues causes Unity Segmentation fault

    - by Dj Gilcrease
    I upgraded from 13.04 to 13.10 and I can boot to the unity-greeter and login just fine, but after login I just get a black screen with a cursor. I have tried following http://help.ubuntu.com/community/BinaryDriverHowto/ATI http://help.ubuntu.com/community/RadeonDriver and the manual install of the downloaded AMD drivers. All have the same affect. Also I have read Black screen after login with cursor I get a black screen after logging in ubuntu 13.04 black screen after login Ubuntu 13.10 - Black screen after login session Ubuntu 13.04 - Black screen with unresponsive cursor Upgrade to Ubuntu 13.04 Problem - Boots into Blank Black Screen All of which were no further help then the two support articles about ATI drivers So I switched back to the default drivers and went a little further into debugging, when I do ctrl+alt+F1 and login and try unity --debug > unity_start.log then ctrl+alt+F8 the screen stays black with a cursor and when I switch back ctrl+alt+F1 the contents of the log output are http://pastebin.com/rdQG4Hb0 However when I try sudo unity --debug > unity_start_root.log then ctrl+alt+F8, unity starts and the output of the log is http://pastebin.com/Yv4RD2j7 The fact that it starts as root tells be it is either a permissions issue of some required file or there is some setting that is specific to my user that is causing the SIGSEGV. So to narrow this down I activated the guest account and tried to login and got the same black screens with only a mouse cursor, so this tells me that it is not a configuration issue, but a permissions issue, so how do I narrow down which file has the wrong permissions? Also is there anything further that may help debug this issue? Ok after a few more hours of googling I found that if I add myself to the video group I can login and see the desktop, but there are lots of other permission related issues, so I am thinking something went wonky with PolicyKit during the upgrade, is there a way to reset PolicyKit settings for a user?

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  • WPF Login Verification Using Active Directory

    - by psheriff
    Back in October of 2009 I created a WPF login screen (Figure 1) that just showed how to create the layout for a login screen. That one sample is probably the most downloaded sample we have. So in this blog post, I thought I would update that screen and also hook it up to show how to authenticate your user against Active Directory. Figure 1: Original WPF Login Screen I have updated not only the code behind for this login screen, but also the look and feel as shown in Figure 2. Figure 2: An Updated WPF Login Screen The UI To create the UI for this login screen you can refer to my October of 2009 blog post to see how to create the borderless window. You can then look at the sample code to see how I created the linear gradient brush for the background. There are just a few differences in this screen compared to the old version. First, I changed the key image and instead of using words for the Cancel and Login buttons, I used some icons. Secondly I added a text box to hold the Domain name that you wish to authenticate against. This text box is automatically filled in if you are connected to a network. In the Window_Loaded event procedure of the winLogin window you can retrieve the user’s domain name from the Environment.UserDomainName property. For example: txtDomain.Text = Environment.UserDomainName The ADHelper Class Instead of coding the call to authenticate the user directly in the login screen I created an ADHelper class. This will make it easier if you want to add additional AD calls in the future. The ADHelper class contains just one method at this time called AuthenticateUser. This method authenticates a user name and password against the specified domain. The login screen will gather the credentials from the user such as their user name and password, and also the domain name to authenticate against. To use this ADHelper class you will need to add a reference to the System.DirectoryServices.dll in .NET. The AuthenticateUser Method In order to authenticate a user against your Active Directory you will need to supply a valid LDAP path string to the constructor of the DirectoryEntry class. The LDAP path string will be in the format LDAP://DomainName. You will also pass in the user name and password to the constructor of the DirectoryEntry class as well. With a DirectoryEntry object populated with this LDAP path string, the user name and password you will now pass this object to the constructor of a DirectorySearcher object. You then perform the FindOne method on the DirectorySearcher object. If the DirectorySearcher object returns a SearchResult then the credentials supplied are valid. If the credentials are not valid on the Active Directory then an exception is thrown. C#public bool AuthenticateUser(string domainName, string userName,  string password){  bool ret = false;   try  {    DirectoryEntry de = new DirectoryEntry("LDAP://" + domainName,                                           userName, password);    DirectorySearcher dsearch = new DirectorySearcher(de);    SearchResult results = null;     results = dsearch.FindOne();     ret = true;  }  catch  {    ret = false;  }   return ret;} Visual Basic Public Function AuthenticateUser(ByVal domainName As String, _ ByVal userName As String, ByVal password As String) As Boolean  Dim ret As Boolean = False   Try    Dim de As New DirectoryEntry("LDAP://" & domainName, _                                 userName, password)    Dim dsearch As New DirectorySearcher(de)    Dim results As SearchResult = Nothing     results = dsearch.FindOne()     ret = True  Catch    ret = False  End Try   Return retEnd Function In the Click event procedure under the Login button you will find the following code that will validate the credentials that the user types into the login window. C#private void btnLogin_Click(object sender, RoutedEventArgs e){  ADHelper ad = new ADHelper();   if(ad.AuthenticateUser(txtDomain.Text,         txtUserName.Text, txtPassword.Password))    DialogResult = true;  else    MessageBox.Show("Unable to Authenticate Using the                      Supplied Credentials");} Visual BasicPrivate Sub btnLogin_Click(ByVal sender As Object, _ ByVal e As RoutedEventArgs)  Dim ad As New ADHelper()   If ad.AuthenticateUser(txtDomain.Text, txtUserName.Text, _                         txtPassword.Password) Then    DialogResult = True  Else    MessageBox.Show("Unable to Authenticate Using the                      Supplied Credentials")  End IfEnd Sub Displaying the Login Screen At some point when your application launches, you will need to display your login screen modally. Below is the code that you would call to display the login form (named winLogin in my sample application). This code is called from the main application form, and thus the owner of the login screen is set to “this”. You then call the ShowDialog method on the login screen to have this form displayed modally. After the user clicks on one of the two buttons you need to check to see what the DialogResult property was set to. The DialogResult property is a nullable type and thus you first need to check to see if the value has been set. C# private void DisplayLoginScreen(){  winLogin win = new winLogin();   win.Owner = this;  win.ShowDialog();  if (win.DialogResult.HasValue && win.DialogResult.Value)    MessageBox.Show("User Logged In");  else    this.Close();} Visual Basic Private Sub DisplayLoginScreen()  Dim win As New winLogin()   win.Owner = Me  win.ShowDialog()  If win.DialogResult.HasValue And win.DialogResult.Value Then    MessageBox.Show("User Logged In")  Else    Me.Close()  End IfEnd Sub Summary Creating a nice looking login screen is fairly simple to do in WPF. Using the Active Directory services from a WPF application should make your desktop programming task easier as you do not need to create your own user authentication system. I hope this article gave you some ideas on how to create a login screen in WPF. NOTE: You can download the complete sample code for this blog entry at my website: http://www.pdsa.com/downloads. Click on Tips & Tricks, then select 'WPF Login Verification Using Active Directory' from the drop down list. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **We frequently offer a FREE gift for readers of my blog. Visit http://www.pdsa.com/Event/Blog for your FREE gift!

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  • How can I back up my ubuntu system?

    - by Eloff
    I'm sure there's a lot of questions on here similar to this, and I've been reading them, but I still feel this warrants a new question. I want nightly, incremental backups (full disk images would waste a lot of space - unless compressed somehow.) Preferably rotating or deleting old backups when running out of space or after a fixed number of backups. I want to be able to quickly and painlessly restore my system from these backups. This is my first time running ubuntu as my main development machine and I know from my experience with it as a server and in virtual machines that I regularly manage to make it unbootable or damage it to the point of being unable to rescue it. So how would you recommend I do this? There are so many options out there I really don't know where to start. There seems to be a vocal school of thought that it's sufficient to backup your home directory and the list of installed packages from the package manager. I've already installed lots of things from source, or outside of the package manager (development tools, ides, compilers, graphics drivers, etc.) So at the very least, if I do not back up the operating system itself I need to grab all config files, all program binaries, all created but required files, etc. I'd rather backup too much than too little - an ubuntu install is tiny anyway. Also this drastically reduces the restore time, which would cost me more in my time than the extra storage space. I tried using Deja Dup to backup the root partition, excluding some things like /mnt /media /dev /proc etc. Although many websites assured me you can backup a running linux system this way - that seems to be false as it complained that it could not backup the following files: /boot/System.map-3.0.0-17-generic /boot/System.map-3.2.0-22-generic /boot/vmcoreinfo-3.0.0-17-generic /boot/vmlinuz-3.0.0-17-generic /boot/vmlinuz-3.2.0-22-generic /etc/.pwd.lock /etc/NetworkManager/system-connections/LAN Connection /etc/apparmor.d/cache/lightdm-guest-session /etc/apparmor.d/cache/sbin.dhclient /etc/apparmor.d/cache/usr.bin.evince /etc/apparmor.d/cache/usr.lib.telepathy /etc/apparmor.d/cache/usr.sbin.cupsd /etc/apparmor.d/cache/usr.sbin.tcpdump /etc/apt/trustdb.gpg /etc/at.deny /etc/ati/inst_path_default /etc/ati/inst_path_override /etc/chatscripts /etc/cups/ssl /etc/cups/subscriptions.conf /etc/cups/subscriptions.conf.O /etc/default/cacerts /etc/fuse.conf /etc/group- /etc/gshadow /etc/gshadow- /etc/mtab.fuselock /etc/passwd- /etc/ppp/chap-secrets /etc/ppp/pap-secrets /etc/ppp/peers /etc/security/opasswd /etc/shadow /etc/shadow- /etc/ssl/private /etc/sudoers /etc/sudoers.d/README /etc/ufw/after.rules /etc/ufw/after6.rules /etc/ufw/before.rules /etc/ufw/before6.rules /lib/ufw/user.rules /lib/ufw/user6.rules /lost+found /root /run/crond.reboot /run/cups/certs /run/lightdm /run/lock/whoopsie/lock /run/udisks /var/backups/group.bak /var/backups/gshadow.bak /var/backups/passwd.bak /var/backups/shadow.bak /var/cache/apt/archives/lock /var/cache/cups/job.cache /var/cache/cups/job.cache.O /var/cache/cups/ppds.dat /var/cache/debconf/passwords.dat /var/cache/ldconfig /var/cache/lightdm/dmrc /var/crash/_usr_lib_x86_64-linux-gnu_colord_colord.102.crash /var/lib/apt/lists/lock /var/lib/dpkg/lock /var/lib/dpkg/triggers/Lock /var/lib/lightdm /var/lib/mlocate/mlocate.db /var/lib/polkit-1 /var/lib/sudo /var/lib/urandom/random-seed /var/lib/ureadahead/pack /var/lib/ureadahead/run.pack /var/log/btmp /var/log/installer/casper.log /var/log/installer/debug /var/log/installer/partman /var/log/installer/syslog /var/log/installer/version /var/log/lightdm/lightdm.log /var/log/lightdm/x-0-greeter.log /var/log/lightdm/x-0.log /var/log/speech-dispatcher /var/log/upstart/alsa-restore.log /var/log/upstart/alsa-restore.log.1.gz /var/log/upstart/console-setup.log /var/log/upstart/console-setup.log.1.gz /var/log/upstart/container-detect.log /var/log/upstart/container-detect.log.1.gz /var/log/upstart/hybrid-gfx.log /var/log/upstart/hybrid-gfx.log.1.gz /var/log/upstart/modemmanager.log /var/log/upstart/modemmanager.log.1.gz /var/log/upstart/module-init-tools.log /var/log/upstart/module-init-tools.log.1.gz /var/log/upstart/procps-static-network-up.log /var/log/upstart/procps-static-network-up.log.1.gz /var/log/upstart/procps-virtual-filesystems.log /var/log/upstart/procps-virtual-filesystems.log.1.gz /var/log/upstart/rsyslog.log /var/log/upstart/rsyslog.log.1.gz /var/log/upstart/ureadahead.log /var/log/upstart/ureadahead.log.1.gz /var/spool/anacron/cron.daily /var/spool/anacron/cron.monthly /var/spool/anacron/cron.weekly /var/spool/cron/atjobs /var/spool/cron/atspool /var/spool/cron/crontabs /var/spool/cups

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  • how to run conky from terminal?

    - by Esmail0022
    http://www.unixmen.com/configure-con...t-howto-conky/ in this link there are 11 steps to get conky , i did all of them but the terminal show this message: The program 'conky' can be found in the following packages: * conky-cli * conky-std Try: sudo apt-get install and i try type this but saw this message: ismail@ismail-ASUS:~$ sudo apt-get install conky [sudo] password for ismail: E: Could not get lock /var/lib/dpkg/lock - open (11: Resource temporarily unavailable) E: Unable to lock the administration directory (/var/lib/dpkg/), is another process using it? Can you help me?

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  • How to change the screen resolution in VNC viewer for Ubuntu 12.04 without a monitor?

    - by user325320
    I have Ubuntu 12.04 installed on a machine and I always use it remotely from VNC. When I have monitor connected to this machine, I can change the resolution of my VNC viewer in the following line: $vnc4server --geometry 1440x900 This worked for me, but I always use this machine remotely, I unplug the monitor and reboot. and the above command line not work anymore. Then I tried xrandr SZ: Pixels Physical Refresh *0 1024 x 768 ( 260mm x 195mm ) *60 Current rotation - normal Current reflection - none Rotations possible - normal Reflections possible - none There is only one option available, so I tried to add a new one. $cvt 1440 900 # 1440x900 59.89 Hz (CVT 1.30MA) hsync: 55.93 kHz; pclk: 106.50 MHz Modeline "1440x900_60.00" 106.50 1440 1528 1672 1904 900 903 909 934 -hsync +vsync $xrandr --newmode "1440x900_60.00" 106.50 1440 1528 1672 1904 900 903 909 934 -hsync +vsync $xrandr --addmode S2 "1440x900_60.00" then I checked with xrandr again and can't see the new mode added. I try to execute the following command and get error says my RandR is too old. $xrandr --output S2 --mode 1440x900_60.00 xrandr: Server RandR version before 1.2 but this does not make sense to me, if I plug in the monitor back and run the xrandr command, it works again! It seems that Ubuntu must conntect to a real monitor before I can change my resolution in my VNC viewer. Can anyone help? UPDATE: Finally I solved this problem by changing to tightvncserver $tightvncserver -geometry 1440x900 works for me. Thanks everything answered my question

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  • Why does ATI 5570 HD video card driver installation cause Windows 7 To Blue Screen?

    - by Mort
    This one is for the hive mind. I have a brand new Dell Optiplex 760 workstation with 4 gigabytes of RAM running Windows 7 Professional (32bit). This is a new box with nothing installed other than what was provided for directly by Dell. I installed a Saphire ATI PCI Express 5570 HD. Upon trying to install the 10.4 Catalyst drivers the system will blue screen. It blue screens during the hardware detection phase of the installation process. I have already performed the following trouble shooting steps: Changed system RAM Installed only 2 gigabytes of RAM Installed different versions of Catalyst drivers (10.4 - 9.12) Tried to install video only component of driver (vs entire Catalyst suite) Made sure Windows 7 was fully updated Flashed mother board BIOS to current version Removed and re-seated video card Contacted ATI Support (We all know how this went......) Verified supply outputting properly The blue screen error (via Windows BugCheck entry in event log) is a 0x000000CA and refers to a plug and play error most likely caused by a bad driver. The problem is that the driver installation process never gets far enough to actually install a driver. The resolution center in Windows provides a solution of installing the 10.4 Catalyst driver to resolve issue (which fails). Looking for some alternate views to resolve.

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  • Safe mode boot with no change on screen but ongoing hard disk activity - why?

    - by omatai
    I have a machine with a dying hard drive - bad sectors are starting to multiply :-( The first sign (24 hours ago) was that it had an unmountable boot volume. At this time, I tried booting to safe mode with command prompt, which worked, after which I rebooted normally and ran a chkdsk. It has since been working as well as I could expect, but slowly getting less reliable. So I scheduled another chkdsk on both partitions (C: - boot, D: - data), having freed up a lot of space on both partitions to give Windows a little more scope for repairs (hopefully?). I then rebooted. On reboot, it protested about the unmountable boot volume again, so I booted to safe mode. I got the same list of drivers loaded as yesterday, and then no change to the screen for the past 2 hours. However, I see a flickering hard drive indicator light - not always on, but seldom ever off. What is happening? Is the chkdsk that runs in safe mode one which produces nothing on the screen and so chkdsk could be doing its thing... or is Windows still trying (but failing) to boot into Safe Mode?

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  • Ubuntu 10.04 LTS - Dual monitor works only sometimes (ATI multi-desktop)

    - by Beres Botond
    I've been using my laptop with an external LCD monitor attached to it at work (Philips 201E). And at home with a different external monitor (Samsung 2032BW). I have an ATI graphics card (HD3450), with Ati Catalyst drivers enabled and I'm using the Single display desktop (Multi-Desktop) seeting. At work I have the external monitor on the left and laptop on the right, while at home the other way around. So when I switch between the two setups, I just needed to go to Ati Catalyst Control Center, change the order of the displays, change the resolution (Home - 1680x1050, Work - 1440x900), reboot and it was all fine. But since a while it doesn't work properly anymore: At home it still works fine. At work it doesn't work. Sometimes it works for some reason, after a few resolution/setting changes in ACCC and reboots... it's very strange and annoying. With the home monitor I can see the whole bootup process on both monitors (laptop + LCD) and it always just works fine. With the work monitor on the external LCD monitor I just see "No video input" until I get to the login screen, then it shows up there as well. But after login it will either: Flicker a few times, but then work OK. Or (more often) Flicker once and then go back to "No video input" again. I usually end up rebooting a few times until it works. Does anyone have any idea for fixing it? This is my xorg.conf currently: Section "ServerLayout" Identifier "amdcccle Layout" Screen 0 "amdcccle-Screen[6]-0" 0 0 Screen "amdcccle-Screen[6]-1" 1280 0 EndSection Section "Files" EndSection Section "Module" Load "glx" EndSection Section "ServerFlags" Option "Xinerama" "off" EndSection Section "Monitor" Identifier "0-LVDS" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" Option "PreferredMode" "1280x768" Option "TargetRefresh" "60" Option "Position" "0 0" Option "Rotate" "normal" Option "Disable" "false" EndSection Section "Monitor" Identifier "0-CRT1" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" Option "TargetRefresh" "60" Option "Position" "0 0" Option "Rotate" "normal" Option "Disable" "false" Option "PreferredMode" "1440x900" EndSection Section "Device" Identifier "Default Device" Driver "fglrx" EndSection Section "Device" Identifier "amdcccle-Device[6]-0" Driver "fglrx" Option "Monitor-LVDS" "0-LVDS" BusID "PCI:6:0:0" EndSection Section "Device" Identifier "amdcccle-Device[6]-1" Driver "fglrx" Option "Monitor-CRT1" "0-CRT1" BusID "PCI:6:0:0" Screen 1 EndSection Section "Screen" Identifier "Default Screen" DefaultDepth 24 SubSection "Display" Virtual 2560 1024 EndSubSection EndSection Section "Screen" Identifier "amdcccle-Screen[6]-0" Device "amdcccle-Device[6]-0" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection Section "Screen" Identifier "amdcccle-Screen[6]-1" Device "amdcccle-Device[6]-1" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection

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  • Is it possible to make the Numpad 5 button work as the Numpad Down button while Num Lock is on?

    - by Eddy
    I hope someone can help me out with this; I use a laptop and I like to play games a lot that are arrow key dependent. So after a while of using my laptop, I accidentally broke the Down Arrow key. So I decided to try and find out how to make the Numpad5 button work as the Numpad Down button while Numlock is on. I was trying to use AutoHotkey, but so far I've had no luck. Can anyone help me out with this? So far the scripts I used that didn't work were Numpad5::NumpadDown or Numpad5::Down. Am I doing something wrong here?

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  • How do I detect if I'm in a 'full screen' bash shell or GUI terminal window?

    - by Nick T
    I have some code in my .bashrc that sets the terminal window title using the currently running command and it works great in Unity, where the terminal is in a window. However, when I'm logging in with the Ctrl + Alt + F1 terminal (whatever it's called), my prompt gets filled with garbage that is various escape sequences that set the (nonexistent) window title. How can I detect from within a bash script if I'm in one or the other?

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  • How can I screen clients that try to register multiple times?

    - by Aba Dov
    My company offers a bonus to every client that register. We would like to prevent people from abusing this by registering several times. we thought about filtering clients by ip (there is a problem with workplaces where all stations have the same ip) cookies (if cookies are not allowed we might lose a client) I would like your opinions on these two methods and will be glad to hear about new ones. thanks

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  • Are there any guidelines for laying out screen "real estate?"

    - by Corey
    I'm wondering if there is any information about creating a decent page layout so that your website will appeal to users of all resolutions. For example, the optimal width for pages. It seems like on my resolution, most websites have their content centered and covers about 80% of the page, which is easy on the eyes. Or maybe the height of the website's logo/header -- some sites I stumble upon have a huge logo with links or navigation under it, making it so that I need to scroll down to see the actual content, like articles or images (these sites don't keep me for very long). I understand that every user is different and may have browser extensions, page zoom or may be running some ancient system that displays in 640x480. I'm not looking for a "best" solution, but rather, some guidelines about designing to accommodate different resolutions. Basically, how can I make sure that I don't design a page where a paragraph might display in several easy-to-read lines on my resolution, but it turns into a single line on a 1920x1080 resolution and makes it hard for the user to follow?

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  • How can I display eth0's IP address at the login screen on Precise Server?

    - by Andrew Stebenne
    The server I administrate, inconveniently enough, has a dynamic IP address assigned by DHCP. The convenient counterbalance, though, is that it happens to be set up about two feet from where I sit. I know how to edit /etc/issue to show different values before the login prompt is delivered to the display, but I'd like to know if it's possible for /etc/issue to display the current IP address of eth0 (re-evaluated at boot time) so that I can see it and then ssh in without having to log in to run ifconfig.

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  • How can I set a second screen (DISPLAY=:0.1) as the default gnome display?

    - by Pedro Silva
    Due to various reasons, I have my main monitor set as the secondary display in xorg.conf. I would like to have gnome initialize metacity, gnome-panel as running primarily on :0.1, instead of :0.0. Is this possible at all? To clarify, this is a laptop with its LCD turned off. My main monitor is connected to the VGA out and is driven by the nouveau driver for NVIDIA; a secondary monitor is on a displaylink usb-vga donverter. The seconday monitor is set in xorg.conf as the primary display (no way around it). I can do things like DISPLAY=:0.1 gnome-terminal to run applications on the main monitor. My question is whether it is possible to do this (GNOME-) system-wide.

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  • Linux server apache httpd processes take i/o wait to close to 100% and lock down server

    - by user3682065
    For about 5 days now, and seemingly out of the blue, my linux server has started locking up from time to time. The pattern is always the same as far as I can tell from top and iotop commands around the time it starts happening: One or more httpd processes (usually one) hang and start using up 100% of CPU power, the %wa goes close to 100% and in the iotop I see several httpd processes with 99.99% in the IO column. I'm also running an SVN server on this machine through apache and the one way that I've been consistently able to reproduce this is to do an SVN commit of new files or an SVN update from the repository on this server (I am the only one using this SVN repository). This will always reproduce this scenario successfully, but until very recently I had no problems at all checking in/out of SVN. But sometimes it just happens for no detectable reason at all it seems. So it seems like there is some issue with my Apache that leads it to have processes use up a lot of read/write upon certain triggers. I was wondering if anyone could help me uncover that issue. EDIT: OK now it's happening again: This is top: [root@server ~]# top top - 10:56:54 up 2:59, 5 users, load average: 171.46, 70.35, 27.01 Tasks: 328 total, 2 running, 326 sleeping, 0 stopped, 0 zombie Cpu(s): 1.9%us, 2.0%sy, 0.0%ni, 0.0%id, 96.1%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 2021144k total, 1968192k used, 52952k free, 2500k buffers Swap: 4194288k total, 2938584k used, 1255704k free, 39008k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 10390 apache 20 0 2774m 936m 6200 D 2.0 47.4 1:52.27 httpd 2149 root 20 0 927m 13m 1040 S 0.7 0.7 1:50.46 namecoind 11 root 20 0 0 0 0 R 0.3 0.0 0:30.10 events/0 23 root 20 0 0 0 0 S 0.3 0.0 0:17.88 kblockd/1 2049 root 20 0 382m 4932 2880 D 0.3 0.2 0:03.67 httpd 2144 root 20 0 1702m 69m 1164 S 0.3 3.5 5:19.68 bitcoind 6325 root 20 0 15164 1100 656 R 0.3 0.1 0:11.09 top 10311 apache 20 0 387m 9496 7320 D 0.3 0.5 0:01.89 httpd 10313 apache 20 0 391m 10m 7364 D 0.3 0.5 0:02.40 httpd 10466 apache 20 0 399m 12m 7392 D 0.3 0.7 0:02.41 httpd 10599 apache 20 0 391m 9324 7340 D 0.3 0.5 0:00.15 httpd 10628 apache 20 0 384m 7620 4052 D 0.3 0.4 0:00.01 httpd 10633 apache 20 0 384m 7048 3504 D 0.3 0.3 0:00.01 httpd 10634 apache 20 0 384m 8012 4048 D 0.3 0.4 0:00.02 httpd 10638 apache 20 0 400m 22m 9.8m D 0.3 1.1 0:01.93 httpd 10640 apache 20 0 385m 8288 4028 D 0.3 0.4 0:00.03 httpd 10641 apache 20 0 401m 21m 6376 D 0.3 1.1 0:01.45 httpd 10759 apache 20 0 385m 8816 3480 D 0.3 0.4 0:01.45 httpd 10773 apache 20 0 384m 8044 3464 D 0.3 0.4 0:00.02 httpd This is an iotop snapshot: Total DISK READ: 5.93 M/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO> COMMAND 10732 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 58.48 % httpd 876 be/3 root 0.00 B/s 52.68 K/s 0.00 % 52.98 % [jbd2/dm-1-8] 10906 be/4 root 124.17 K/s 0.00 B/s 0.00 % 23.03 % sh -c [ -x /usr/local/psa/admin/sbin/backupmng ] && /usr/local/psa/admin/sbin/backupmng >/dev/null 2>&1 2156 be/4 root 206.94 K/s 0.00 B/s 0.00 % 21.15 % bitcoind 10904 be/4 mysql 0.00 B/s 0.00 B/s 0.00 % 18.94 % mysqld --basedir=/usr --datadir=/var/lib/mysql --user=mysql --log-error=/var/log/mysqld.log --pid-file=/var/run/mysqld/mysqld.pid --socket=/var/lib/mysql/mysql.sock 10773 be/4 apache 7.53 K/s 0.00 B/s 0.00 % 14.77 % httpd 10641 be/4 apache 15.05 K/s 0.00 B/s 0.00 % 11.57 % httpd 10399 be/4 apache 1057.29 K/s 0.00 B/s 43.16 % 10.56 % httpd 10682 be/4 sw-cp-se 158.03 K/s 0.00 B/s 0.00 % 7.45 % sw-engine-cgi -c /usr/local/psa/admin/conf/php.ini -d auto_prepend_file=auth.php3 -u psaadm 10774 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 6.53 % httpd 10624 be/4 apache 0.00 B/s 0.00 B/s 0.00 % 5.53 % httpd 10356 be/4 apache 899.26 K/s 0.00 B/s 35.52 % 4.01 % httpd 10795 be/4 apache 0.00 B/s 0.00 B/s 0.00 % 3.93 % httpd 10804 be/4 apache 7.53 K/s 0.00 B/s 0.00 % 3.08 % httpd 4379 be/4 root 2.89 M/s 0.00 B/s 99.99 % 0.00 % namecoind 10619 be/4 apache 462.80 K/s 0.00 B/s 7.80 % 0.00 % httpd 10636 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 0.00 % httpd 10716 be/4 mysql 105.35 K/s 0.00 B/s 5.92 % 0.00 % mysqld --basedir=/usr --datadir=/var/lib/mysql --user=mysql --log-error=/var/log/mysqld.log --pid-file=/var/run/mysqld/mysqld.pid --socket=/var/lib/mysql/mysql.sock 1988 be/4 root 18.81 K/s 0.00 B/s 0.00 % 0.00 % spamd_full.sock I also ran lsof -p for pid 10390 which was way up top under the top command and this is the bottom line where I can sort of see what request this was and it says CLOSE_WAIT: httpd 10390 apache 34u IPv6 315879 0t0 TCP default-domain.com:https->crawl-66-249-65-91.googlebot.com:42907 (CLOSE_WAIT) I'm still not sure what exactly is causing this all to happen though? I killed that service but %wa and load average remain high, I also stopped mysqld and other services. It really only goes down once I stop httpd altogether, and even then I can't start it without finding remaining hanging httpd processes via "netstat -tulpn", killing those or doing "killall -9 httpd" and after waiting a while for it to cycle through all those then doing /etc/init.d/httpd start

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  • how to install vlc player from tar file

    - by mohit
    After getting vlc-2.0.3tar.gz I extracted it and then tried the ./install, but it gave me an error. Then i did ./configure and got this.. configure: error: No package 'dbus-1' found. Then tried this: apt-get install dbus-1 But I got this: E: Could not get lock /var/lib/dpkg/lock - open (11: Resource temporarily unavailable) E: Unable to lock the administration directory (/var/lib/dpkg/), is another process using it? What do I do next?

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