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  • How to Impersonate a user for a file copy over the network when dns or netbios is not available

    - by Scott Chamberlain
    I have ComputerA on DomainA running as userA needing to copy a very large file to ComputerB on WorkgroupB which has the ip of 192.168.10.2 to a windows share that only userB has write access to. There is no netbios or dns resolving so the computer must be refrenced by IP I first I tried AppDomain.CurrentDomain.SetPrincipalPolicy(System.Security.Principal.PrincipalPolicy.WindowsPrincipal); WindowsIdentity UserB = new WindowsIdentity("192.168.10.2\\UserB", "PasswordB"); //Execption WindowsImpersonationContext contex = UserB.Impersonate() File.Copy(@"d:\bigfile", @"\\192.168.10.2\bifgile"); contex.Undo(); but I get a System.Security.SecurityException "The name provided is not a properly formed account name." So I tried AppDomain.CurrentDomain.SetPrincipalPolicy(System.Security.Principal.PrincipalPolicy.WindowsPrincipal); WindowsIdentity webinfinty = new WindowsIdentity("ComputerB\\UserB", "PasswordB"); //Execption But I get "Logon failure: unknown user name or bad password." error instead. so then I tried IntPtr token; bool succeded = LogonUser("UserB", "192.168.10.2", "PasswordB", LogonTypes.Network, LogonProviders.Default, out token); if (!succeded) { throw new Win32Exception(Marshal.GetLastWin32Error()); } WindowsImpersonationContext contex = WindowsIdentity.Impersonate(token); (...) [DllImport("advapi32.dll", SetLastError = true)] static extern bool LogonUser( string principal, string authority, string password, LogonTypes logonType, LogonProviders logonProvider, out IntPtr token); but LogonUser returns false with the win32 error "Logon failure: unknown user name or bad password" I know my username and password are fine, I have logged on to computerB as that user. Any reccomandations

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  • dbExpress error in Delphi 2010

    - by JosephStyons
    The below code works in Delphi 2007, but it gives me this error in Delphi 2010: --------------------------- Error --------------------------- Cannot load oci.dll library (error code 127). The oci.dll library may be missing from the system path or you may have an incompatible version of the library installed. --------------------------- OK Details >> --------------------------- The exception is raised when I set "connected" to "true". I have tried placing a copy of "oci.dll" in the same folder as the .exe file, but I get the same message. I also get this message when using the form designer and a visible TSQLConnection component. Any thoughts? function TDBExpressConnector.GetConnection(username, password, servername: string) : TSQLConnection; begin //take a username, password, and server //return a connected TSQLConnection try FSqlDB := TSQLConnection.Create(nil); with FSqlDB do begin Connected := False; DriverName := 'Oracle'; GetDriverFunc := 'getSQLDriverORACLE'; KeepConnection := True; LibraryName := 'dbxora30.dll'; ConnectionName := 'OracleConnection';; Params.Clear; Params.Add('DriverName=Oracle'); Params.Add('DataBase=' + servername); Params.Add('User_Name=' + username); Params.Add('Password=' + password); Params.Add('RowsetSize=20'); Params.Add('BlobSize=-1'); Params.Add('ErrorResourceFile='); Params.Add('LocaleCode=0000'); Params.Add('Oracle TransIsolation=ReadCommited'); Params.Add('OS Authentication=False'); Params.Add('Multiple Transaction=False'); Params.Add('Trim Char=False'); Params.Add('Decimal Separator=.'); LoginPrompt := False; Connected := True; end; Result := FSqlDB; except on e:Exception do raise; end; //try-except end;

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  • iPhone Keychain Questions

    - by AO
    Some questions: * Is there some way to view the data present in the iPhone keychain? * The items an application adds, cannot be accessed by any other application, can it? * What is the purpose of the identifier and access group in the initialization? My guess is that the identifier is simply used to find items but I'm a little bit unsure of the access group. If the access group is assigned nil, all applications can access the items? If the access group is assigned X, could the items be accessed by another application with the same string X as access group or what is the purpose of the access group in this case? * Is the data in the keychain removed when the application is removed? If not, how do I achieve that? And finally: I can't get the KeychainItemWrapper (Apple example) to work. I've added the KeychainItemWrapper files to my project and when running it on the phone, an exception is thrown by SecItemAdd, saying that one or more parameters were not valid (result code -50). The code triggering the SecItemAdd follows: KeychainItemWrapper* wrapper = [[KeychainItemWrapper alloc] initWithIdentifier:@"something" accessGroup:@"com.company.whatever"]; [wrapper setObject:@"this is my password" forKey:@"password"]; NSLog(@"Password: %@", [wrapper objectForKey:@"password"]); The code can be found at http://developer.apple.com/iphone/library/samplecode/GenericKeychain/index.html

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  • Memory allocation error from MySql ODBC 5.1 driver in C# application on insert statement

    - by Chinjoo
    I have a .NET Wndows application in C#. It's a simple Windows application that is using the MySql 5.1 database community edition. I've downloaded the MySql ODBC driver and have created a dsn to my database on my local machine. On my application, I can perform get type queries without problems, but when I execute a given insert statement (not that I've tried doing any others), I get the following error: {"ERROR [HY001] [MySQL][ODBC 5.1 Driver][mysqld-5.0.27-community-nt]Memory allocation error"} I'm running on a Windows XP machine. My machine has 1 GB of memory. Anyone have any ideas? See code below OdbcConnection MyConn = DBConnection.getDBConnection(); int result = -1; try { MyConn.Open(); OdbcCommand myCmd = new OdbcCommand(); myCmd.Connection = MyConn; myCmd.CommandType = CommandType.Text; OdbcParameter userName = new OdbcParameter("@UserName", u.UserName); OdbcParameter password = new OdbcParameter("@Password", u.Password); OdbcParameter firstName = new OdbcParameter("@FirstName", u.FirstName); OdbcParameter LastName = new OdbcParameter("@LastName", u.LastName); OdbcParameter sex = new OdbcParameter("@sex", u.Sex); myCmd.Parameters.Add(userName); myCmd.Parameters.Add(password); myCmd.Parameters.Add(firstName); myCmd.Parameters.Add(LastName); myCmd.Parameters.Add(sex); myCmd.CommandText = mySqlQueries.insertChatUser; result = myCmd.ExecuteNonQuery(); } catch (Exception e) { //{"ERROR [HY001] [MySQL][ODBC 5.1 Driver][mysqld-5.0.27-community-nt]Memory // allocation error"} EXCEPTION ALWAYS THROWN HERE } finally { try { if (MyConn != null) MyConn.Close(); } finally { } }

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  • ant deploy to oc4j problem

    - by senzacionale
    BUILD FAILED C:\Projekti\Projekt ANT\build.xml:337: Problem: failed to create task or type antlib:oracle:deploy Cause: The name is undefined. Action: Check the spelling. Action: Check that any custom tasks/types have been declared. Action: Check that any / declarations have taken place. No types or tasks have been defined in this namespace yet This appears to be an antlib declaration. Action: Check that the implementing library exists in one of: -C:\Projekti\Apache ANT\apache-ant-1.8.1\bin..\lib -C:\Documents and Settings\MitjaG.ant\lib -a directory added on the command line with the -lib argument CODE: <target name="deploy" depends="init, ear"> <oracle:deploy moduletype="ear" host="${oc4j.host}" port="${oc4j.admin.port}" userid="${oc4j.admin.user}" password="${oc4j.admin.password}" file="${dest.dir}/${package.name}/${view.dir}/${deploy.dir}/${ear.file}" deploymentname="${app.name}" logfile="${log.dir}/deploy-ear.log"/> <oracle:bindWebApp host="${oc4j.host}" port="${oc4j.admin.port}" userid="${oc4j.admin.user}" password="${oc4j.admin.password}" deploymentname="${app.name}" webmodule="${web.name}" websitename="${oc4j.binding.module}" contextroot="/${app.name}" /> </target> I google and search for whole day but i can not find solution. There is no good docs for oc4j and ant except this from 2005: http://www.it-eye.nl/weblog/2005/08/15/how-to-using-ant-to-deploy-to-oc4j-dp4/

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  • Best way for a remote web app to authenticate users in my current web app?

    - by jklp
    So a bit of background, I'm working on an existing web application which has a set of users, who are able to log in via a traditional login screen with a user name and password, etc. Recently we've managed to score a client (who have their own Intranet site), who are wanting to be able to have their users log into their Intranet site, and then have their users click a link on their Intranet which redirects to our application and logs them into it automatically. I've had two suggestions on how to implement this so far: Create a URL which takes 2 parameters (which are "username" and "password") and have the Intranet site pass those parameters to us (our connection is via TLS so it's all encrypted). This would work fine, but it seems a little "hacky", and also means that the logins and passwords have to be the same on both systems (and having to write some kind of web service which can update the passwords for users - which also seems a bit insecure) Provide a token to the Intranet, so when the client clicks on a link on the Intranet, it sends the token to us, along with the user name (and no password) which means they're authenticated. Again, this sounds a bit hacky as isn't that essentially the same as providing everyone with the same password to log in? So to summarise, I'm after the following things: A way for the users who are already authenticated on the Intranet to log into our system without too much messing around, and without using an external system to authenticate, i.e. LDAP / Kerberos Something which isn't too specific to this client, and can easily be implemented by other Intranets to log in

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  • Sending data through POST request from a node.js server to a node.js server

    - by Masiar
    I'm trying to send data through a POST request from a node.js server to another node.js server. What I do in the "client" node.js is the following: var options = { host: 'my.url', port: 80, path: '/login', method: 'POST' }; var req = http.request(options, function(res){ console.log('status: ' + res.statusCode); console.log('headers: ' + JSON.stringify(res.headers)); res.setEncoding('utf8'); res.on('data', function(chunk){ console.log("body: " + chunk); }); }); req.on('error', function(e) { console.log('problem with request: ' + e.message); }); // write data to request body req.write('data\n'); req.write('data\n'); req.end(); This chunk is taken more or less from the node.js website so it should be correct. The only thing I don't see is how to include username and password in the options variable to actually login. This is how I deal with the data in the server node.js (I use express): app.post('/login', function(req, res){ var user = {}; user.username = req.body.username; user.password = req.body.password; ... }); How can I add those username and password fields to the options variable to have it logged in? Thanks

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  • AlertDialog in if-stetement doesn't show()

    - by Steffen Kern
    I have the following code: public void button_login(View view) { // Instantiate an AlertDialog.Builder with its constructor AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { /* User clicked OK button */ } }); // Preserve EditText values. EditText ET_username = (EditText) findViewById(R.id.username); EditText ET_password = (EditText) findViewById(R.id.password); String str_username = ET_username.toString(); String str_password = ET_password.toString(); // Intercept missing username and password. if(str_username.length() == 0) { builder.setMessage(R.string.hint_username_empty); AlertDialog dialog = builder.create(); dialog.show(); } } I have an activity that includes the two EditText-Views and a button. When I click the button the shown method will be called. My problem: The AlertDialog doesnt show up! When I put the create and show at beginning like this: // Instantiate an AlertDialog.Builder with its constructor AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { /* User clicked OK button */ } }); builder.setMessage(R.string.hint_username_empty); AlertDialog dialog = builder.create(); dialog.show(); // Preserve EditText values. EditText ET_username = (EditText) findViewById(R.id.username); EditText ET_password = (EditText) findViewById(R.id.password); String str_username = ET_username.toString(); String str_password = ET_password.toString(); // Intercept missing username and password. if(str_username.length() == 0) { } } Then the Dialog shows up. Any ideas why the dialog doesnt show up in the first place? Greetz, Steffen

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  • unable to send email using REST API build in php?

    - by Pushpendra Kuntal
    i am designing REST API in php. I want to send a page to send email. This is my code to send email: $app->get('/sendemail', function () { <?php require_once "Mail.php"; $from = "Sandra Sender <[email protected]>"; $to = "Ramona Recipient <[email protected]>"; $subject = "Hi!"; $body = "Hi,\n\nHey Kuntal, you done it..."; $host = "my host"; $username = "myuserid"; $password = "password"; $headers = array ('From' => $from, 'To' => $to, 'Subject' => $subject); $smtp = Mail::factory('smtp', array ('host' => $host, 'auth' => true, 'username' => $username, 'password' => $password)); $mail = $smtp->send($to, $headers, $body); if (PEAR::isError($mail)) { echo("<p>" . $mail->getMessage() . "</p>"); } else { echo("<p>Message successfully sent!</p>"); } ?> }); My code of sending email is working if i check this into my separate file. But this code is not working in API. please suggest me what should i do for this?

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  • A Question about .net Rfc2898DeriveBytes class?

    - by IbrarMumtaz
    What is the difference in this class? as posed to just using Encoding.ASCII.GetBytes(string object); I have had relative success with either approach, the former is a more long winded approach where as the latter is simple and to the point. Both seem to allow you to do the same thing eventually but I am struggling to the see the point in using the former over the latter. The basic concept I have been able to grasp is that you can convert string passwords into byte arrays to be used for e.g a symmetric encryption class, AesManaged. Via the RFC class but you get to use SaltValues and password when creating your rfc object. I assume its more secure but still thats an uneducated guess at best ! Also that it allows you to return byte arrays of a certain size, well something like that. heres a few examples to show you where I am coming from? byte[] myPassinBytes = Encoding.ASCII.GetBytes("some password"); or string password = "P@%5w0r]>"; byte[] saltArray = Encoding.ASCII.GetBytes("this is my salt"); Rfc2898DeriveBytes rfcKey = new Rfc2898DeriveBytes(password, saltArray); The 'rfcKey' object can now be used towards setting up the the .Key or .IV properties on a Symmetric Encryption Algorithm class. ie. RijndaelManaged rj = new RijndaelManaged (); rj.Key = rfcKey.Getbytes(rj.KeySize / 8); rj.IV = rfcKey.Getbytes(rj.Blocksize / 8); 'rj' should be ready to go ! The confusing part ... so rather than using the 'rfcKey' object can I not just use my 'myPassInBytes' array to help set-up my 'rj' object???? I have tried doing this in VS2008 and the immediate answer is NO ! but have you guys got a better educated answer as to why the RFC class is used over the other alternative I have mentioned above and why????

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  • Very simply, how can check if a user exists against my MySQL database?

    - by Sergio Tapia
    Here's what I have but nothing is output to the screen. :\ <html> <head> </head> <body> <? mysql_connect(localhost, "sergio", "123"); @mysql_select_db("multas") or die( "Unable to select database"); $query="SELECT * FROM usuario"; $result=mysql_query($query); $num=mysql_numrows($result); $i=0; $username=GET["u"]; $password=GET["p"]; while ($i < $num) { $dbusername=mysql_result($result,$i,"username"); $dbpassword=mysql_result($result,$i,"password"); if(($username == $dbusername) && ($password == $dbpassword)){ echo "si"; } $i++; } ?> </body> </html> I'm iterating through all users and seeing if there is a match for user && password. Any guidance?

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  • why javamail fails with an authentication Exception ?

    - by saravana
    package com.bcs; import java.util.Properties; import javax.mail.Message; import javax.mail.MessagingException; import javax.mail.Session; import javax.mail.Transport; import javax.mail.internet.InternetAddress; import javax.mail.internet.MimeMessage; public class SendMailTLS { public static void main(String[] args) { String host = "smtp.gmail.com"; int port = 587; String username = "[email protected]"; String password = "bar"; Properties props = new Properties(); props.put("mail.smtp.auth", "true"); props.put("mail.smtp.starttls.enable", "true"); Session session = Session.getInstance(props); try { Message message = new MimeMessage(session); message.setFrom(new InternetAddress("")); message.setRecipients(Message.RecipientType.TO, InternetAddress.parse("")); message.setSubject("Testing Subject"); message.setText("Dear Mail Crawler," + "\n\n No spam to my email, please!"); Transport transport = session.getTransport("smtp"); transport.connect(host, port, username, password); Transport.send(message); System.out.println("Done"); } catch (MessagingException e) { throw new RuntimeException(e); } } } I have given all the necessary inputs . But still it fails with Exception in thread "main" java.lang.RuntimeException: javax.mail.AuthenticationFailedException: failed to connect, no password specified? at com.bcs.SendMailTLS.main(SendMailTLS.java:43) Caused by: javax.mail.AuthenticationFailedException: failed to connect, no password specified? at javax.mail.Service.connect(Service.java:329) at javax.mail.Service.connect(Service.java:176) at javax.mail.Service.connect(Service.java:125) at javax.mail.Transport.send0(Transport.java:194) at javax.mail.Transport.send(Transport.java:124) at com.bcs.SendMailTLS.main(SendMailTLS.java:38) I am new to java mail.Any help would be greatly appreciated.

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  • rails inverting to_xml and getting the original model

    - by djacobs7
    I did this: [User.first, User.last].to_xml and got this: <users type="array"> <user> <created-at type="datetime">2010-03-16T06:40:51Z</created-at> <id type="integer">3</id> <password-hash></password-hash> <salt></salt> <updated-at type="datetime">2010-03-16T06:40:51Z</updated-at> <username nil="true"></username> </user> <user> <created-at type="datetime">2010-03-23T03:58:15Z</created-at> <id type="integer">7</id> <password-hash></password-hash> <salt></salt> <tutorial-state nil="true"></tutorial-state> <updated-at type="datetime">2010-03-23T03:58:15Z</updated-at> <username nil="true"></username> </user> </users> How can I take that string of xml and invert it to get the original activerecord objects back?

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  • HTTP Basic authentication using Authlogic or authenticate_or_request_with_http_basic for API call?

    - by Gaius Parx
    I have a Rails 2.3.x app that implements the act_as_authentic in User model and a UserSession model as per Authlogic Github example. I am implementing an API to allow access from iPhone. Will be using HTTP Basic authentication via https (will not implement single access token). Each API call requires a username/password for the access. I am able to access the API by calling http://username:password@localhost:3000/books.xml for example. Authlogic will not persist if using the single access token. But I am using HTTP Basic which I think Authlogic will create session for the API calls, which is not used for my API methods. So for each API call I made, new session object is created. Thus appear to me that this would load up the server resource pretty quickly. Sounds like a bad idea. The alternative is to use the Rails authenticate_or_request_with_http_basic for API controllers. Example adding a before_filter: def require_http_auth_user authenticate_or_request_with_http_basic do |username, password| if @current_user = User.find_by_email(username) @current_user.valid_password?(password) else false end end end This will bypass the Authlogic UserSession and just use the User model. But this will involve using separate authentication codes in the app. Anyone has any comments and can share their experience? Thanks

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  • C# Switch-case Loop for Datagridview cells

    - by Nail Yener
    Hi, I am working on a form with datagridview and webbrowser controls. I have three columns as URL, username and password in datagridview. What I want to do is to automate the login for some websites that I use frequently. For that reason I am not sure if this is the right approach but I created the below code. The problem is with the argument of switch. I will click the row on datagridview and then click the login_button so that the username and password info will be passed to the related fields on the webpage. Why I need a switch-case loop is because all the webpages have different element IDs for username and password fields. As I said, I am not sure if datagridview allows switch-case, I searched the net but couldn't find any samples. private void login_button_Click(object sender, EventArgs e) { switch (dataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex].Value.ToString()) { case "http://www.website1.com": webBrowser1.Document.GetElementById("username").InnerText = dataGridView1.Rows[3].Cells[3].Value.ToString(); webBrowser1.Document.GetElementById("password").InnerText = dataGridView1.Rows[3].Cells[4].Value.ToString(); return; case "http://www.website2.com": webBrowser1.Document.GetElementById("uname").InnerText = dataGridView1.Rows[4].Cells[3].Value.ToString(); webBrowser1.Document.GetElementById("pswd").InnerText = dataGridView1.Rows[4].Cells[4].Value.ToString(); return; } HtmlElementCollection elements = this.webBrowser1.Document.GetElementsByTagName("Form"); foreach (HtmlElement currentElement in elements) { currentElement.InvokeMember("Login"); } }

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  • how to display the decrypted and splited Strings in order?

    - by sebby_zml
    Hi everyone, i need some help and guidance in displaying the splitted Strings in order. let say, i have username, password, nonceInString. i had successfully encrypted and decrypted those. then i split the decrypted data. it was done, too. i want to display the decrypted data in order. something like this. userneme: sebastian password: harrypotter nonce value: sdgvay1saq3qsd5vc6dger9wqktue2tz* i tried the following code, but it didn't display like i wish to. pls help. thanks a lot in advance. String codeWord = username + ";" + password + ";" + nonceInString; String encryptedData = aesEncryptDecrypt.encrypt(codeWord); String decryptedData = aesEncryptDecrypt.decrypt(encryptedData); String[] splits = decryptedData.split(";"); String[] variables = {"username", "password", "nonce value"}; for (String data : variables){ for (String item : splits){ System.out.println( data + ": "+ item); } }

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  • MySQL Access denied error

    - by dancingbush
    I am trying to install mySQL on a Mac OS 10.8 and set up a user account. NOTE I am a abs beginner when it comes to using the command line in Terminal window. I used these instructions to install: http://www.macminivault.com/mysql-mountain-lion/ I set my own password for all users here: GRANT ALL ON *.* TO 'root'@'localhost' IDENTIFIED BY 'mypass' WITH GRANT OPTION; quit Every time i try to execute mySQL as a root user on the command line i get this: Ciarans-MacBook-Pro:~ callanmooneys$ mysql -u root ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) I read around on the net and tried various things including tried this to change password: mysqladmin -u root -pyourcurrentmysqlrootpassword password yournewmysqlrootpassword, it returns -> -> USE mysql -> If i simply type 'mysql' and launch the mySQL monitor then try to crete a user account: mysql> USE mysql ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'mysql' mysql> Also tried answers on forum: access is denied for user 'root'@localhost mysql error 1045 returned '[email protected] command not found And MySQL - ERROR 1045 - Access denied: Ciarans-MacBook-Pro:~ callanmooneys$ mysqld_safe --skip-grant-tables 131105 21:44:41 mysqld_safe Logging to '/usr/local/mysql/data/Ciarans-MacBook-Pro.local.err'. 131105 21:44:41 mysqld_safe Starting mysqld daemon with databases from /usr/local/mysql/data /usr/local/mysql/bin/mysqld_safe: line 129: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied /usr/local/mysql/bin/mysqld_safe: line 166: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied 131105 21:44:41 mysqld_safe mysqld from pid file /usr/local/mysql/data/Ciarans-MacBook-Pro.local.pid ended /usr/local/mysql/bin/mysqld_safe: line 129: /usr/local/mysql/data/Ciarans-MacBook-Pro.local.err: Permission denied Ciarans-MacBook-Pro:~ callanmooneys$ mysql -u root ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2) Ciarans-MacBook-Pro:~ callanmooneys$ Feedback appreciated.

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  • Problem between Glassfish and Spring Security Basic Authentication

    - by Raspayu
    Hi! I am enabling a simple HTTP Basic Authentication with Spring security in my project. My environment is an Glassfish Server (bundled with Netbeans), and almost everything works perfect: I have set up it to just ask for authentication with the POST method, with hardcoded users with "user-service", and it works with user names with no special characters. The problem comes when I set up an user with "@" or "." Here is the spring-security related part of my servlet.xml: <security:http> <security:intercept-url method="POST" pattern="/**" access="ROLE_USER" /> <security:http-basic/> </security:http> <security:authentication-manager alias="authenticationManager"> <security:authentication-provider user-service-ref="uservice"/> </security:authentication-manager> <security:user-service id="uservice"> <security:user name="[email protected]" password="pswd1" authorities="ROLE_USER" /> <security:user name="[email protected]" password="pswd2" authorities="ROLE_USER" /> <security:user name="pepe" password="pepito" authorities="ROLE_USER" /> </security:user-service> I have looked also for what did the browser send to the listening port, and it sends right the par "username:password" in base 64, so i think the problem is in my server(Glassfish v3). Does anyone have any idea? Thanks in advance! Raspayu

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  • Odd behaviour with PHP's in_array function.

    - by animuson
    I have a function that checks multiple form items and returns either boolean(true) if the check passed or the name of the check that was run if it didn't pass. I built the function to run multiple checks at once, so it will return an array of these results (one result for each check that was run). When I run the function, I get this array result: Array ( [0] => 1 [1] => password [2] => birthday ) // print_r array(3) { [0]=> bool(true) [1]=> string(8) "password" [2]=> string(8) "birthday" } // var_dump The 'username' check passed and the 'password' and 'birthday' checks both failed. Then I am using simple in_array statements to determine which ones failed, like so: $results = $ani->e->vld->simulate("register.php", $checks); die(var_dump($results)); // Added after to see what array was being returned if (in_array("username", $results)) // do something if (in_array("password", $results)) // do something if (in_array("birthday", $results)) // do something The problem I'm having is that the 'username' line is still executing, even those 'username' is not in the array. It executes all three statements as if they were all true for some reason. Why is this? I thought maybe that the bool(true) was automatically causing the function to return true for every result without checking the rest of the array, but I couldn't find any documentation that would suggest that very odd functionality.

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  • AES Encryption Java Invalid Key length

    - by wuntee
    I am trying to create an AES encryption method, but for some reason I keep getting a 'java.security.InvalidKeyException: Key length not 128/192/256 bits'. Here is the code: public static SecretKey getSecretKey(char[] password, byte[] salt) throws NoSuchAlgorithmException, InvalidKeySpecException{ SecretKeyFactory factory = SecretKeyFactory.getInstance("PBEWithMD5AndDES"); // NOTE: last argument is the key length, and it is 256 KeySpec spec = new PBEKeySpec(password, salt, 1024, 256); SecretKey tmp = factory.generateSecret(spec); SecretKey secret = new SecretKeySpec(tmp.getEncoded(), "AES"); return(secret); } public static byte[] encrypt(char[] password, byte[] salt, String text) throws NoSuchAlgorithmException, InvalidKeySpecException, NoSuchPaddingException, InvalidKeyException, InvalidParameterSpecException, IllegalBlockSizeException, BadPaddingException, UnsupportedEncodingException{ SecretKey secret = getSecretKey(password, salt); Cipher cipher = Cipher.getInstance("AES"); // NOTE: This is where the Exception is being thrown cipher.init(Cipher.ENCRYPT_MODE, secret); byte[] ciphertext = cipher.doFinal(text.getBytes("UTF-8")); return(ciphertext); } Can anyone see what I am doing wrong? I am thinking it may have something to do with the SecretKeyFactory algorithm, but that is the only one I can find that is supported on the end system I am developing against. Any help would be appreciated. Thanks.

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  • Wordpress - Set Published Date

    - by danit
    Using this function: function wpPostXMLRPC($title,$body,$rpcurl,$username, $password,$category,**$pubdate**,$keywords='',$encoding='UTF-8') { $title = htmlentities($title,ENT_NOQUOTES,$encoding); $keywords = htmlentities($keywords,ENT_NOQUOTES,$encoding); $content = array( 'title'=>$title, 'description'=>$body, 'mt_allow_comments'=>1, // 1 to allow comments 'mt_allow_pings'=>0, // 1 to allow trackbacks 'post_type'=>'post', 'post_status' => 'draft', **'post_date' =>$pubdate,** 'mt_keywords'=>$keywords, 'categories'=>array($category) ); $params = array(0,$username,$password,$content,true); $request = xmlrpc_encode_request('metaWeblog.newPost',$params); $ch = curl_init(); curl_setopt($ch, CURLOPT_POSTFIELDS, $request); curl_setopt($ch, CURLOPT_URL, $rpcurl); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_TIMEOUT, 1); $results = curl_exec($ch); curl_close($ch); return $results; } My Code: $title = $correctdataandtime; $body = '<a href="' . $links['alternate'] . '" />' . '<img src="' . $links['image'] . '" />' . '</a>'; $pubdate = date("Y-m-d H:i:s", $datetime); //Default Settings $rpcurl = 'http://vl3.co.uk/xmlrpc.php'; $username = 'admin'; $password = '3cdsbvre'; $category = '1'; //default is 1, enter a number here. $keywords = 'Twitter';//keywords comma seperated. $encoding ='UTF-8';//utf8 recommended wpPostXMLRPC($title,$body,$rpcurl,$username,$password,$pubdate,$category,$keywords,$encoding); Output of $pubdate is: 2010-04-05 19:25:31 However it still sets the published date as the date and time when i run the script.

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  • Android accessibility focus - clicking a view changes focus to previous view

    - by benkdev
    I'm using android TalkBack to test my application for accessibility use. When I swipe to select a view and double tap, the focus returns the the view above it. Usually when swiping to a view and double clicking it, onClick is called. What am I doing wrong? <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@color/all_white" > <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/header" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/green_bar" android:scaleType="center" /> <ImageView android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/blue_bar" android:scaleType="center" /> <EditText android:id="@+id/username" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/username" android:focusable="true" android:nextFocusDown="@id/password" /> <EditText android:id="@+id/password" android:inputType="textPassword" android:layout_width="325dp" android:layout_height="wrap_content" android:hint="@string/password" android:focusable="true" android:nextFocusUp="@id/username" android:nextFocusDown="@id/login" /> <Button android:id="@+id/login" android:onClick="doLogin" android:focusable="true" android:layout_width="325dp" android:layout_height="wrap_content" android:text="@string/login" android:nextFocusUp="@id/password" android:nextFocusDown="@id/create_trial_account" /> <Button android:id="@+id/create_trial_account" android:layout_width="100dip" android:layout_height="wrap_content" android:text="@string/new_user" android:onClick="createAccount" android:focusable="true" android:nextFocusUp="@id/login" /> <TextView android:id="@+id/copyright" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/copyright" /> <TextView android:id="@+id/buildNumber" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout>

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  • Flex - Issues retrieving an XMLList

    - by BS_C3
    Hello! I'm having a problem retrieving a XMLList and I don't understand why. I have an application that is running properly. It uses some data from two xml files called division.xml and store.xml. I noticed that I have some data in division.xml that should be in store.xml, so I did a copy/paste of the data from one file to the other. This is the data I copied: <stores> <store> <odeis>101</odeis> <name></name> <password></password> <currency></currency> <currSymbol></currSymbol> </store> <store> <odeis>102</odeis> <name></name> <password></password> <currency></currency> <currSymbol></currSymbol> </store> </stores> In the application, I list all odeis codes and I need to retrieve the block store corresponding to the selected odeis code. Before moving the data into store.xml, this is how I retrieved the block: var node:XMLList = divisionData.division.(@name==HomePageData.instance.divisionName).stores.store.(odeis == HomePageData.instance.storeCodeOdeis) This is how I retrieve it after copying the data into store.xml: var node:XMLList = storeData.stores.(@name==HomePageData.instance.divisionName).store.(odeis == HomePageData.instance.storeCodeOdeis) And I'm currently getting the following error: ReferenceError: Error #1065: The variable odeis is not defined. Could anyone enlighten me? Cause I really have no clue of why it is not working... Thanks for any tips you can give. Regards, BS_C3

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  • Use SQL Result to Query second time and grab more results via php

    - by maxwell
    I am grabbing a list of school names from a database. When the user clicks on the school name, i want the code to fetch 2-3 other attributes related to the school name that the user has clicked on. My code for the single school name list: $query = mysql_query("Select schoolname, product, username, password from credentials c join products p on p.productid = c.productid join schools s on s.schoolid = c.schoolid join icons i on i.productid = p.productid order by s.schoolname"); echo '<ul>'; while($row = mysql_fetch_array($query)) { echo "<li> <a href='#'>" . $row['schoolname'] . "</a> </li>"; } echo ''; Current Output: School A School A School B School B School B School C School C Expected Output: School name displayed only once (distinct won't work because each school name has 2-3 product credentials School A School B School C Ability for User to click on a school. then the school names underneath will move down (toggle effect) and user can see product, username and password displayed for the school clicked (for example: user clicked on School A) School A productname1, username, password productname2, username, password School B School C

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  • Athentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "string0826" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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