Search Results

Search found 40479 results on 1620 pages for 'binary files'.

Page 138/1620 | < Previous Page | 134 135 136 137 138 139 140 141 142 143 144 145  | Next Page >

  • Uploading many large files to a remote server

    - by TiernanO
    I am in the process of creating an offsite backup, and need to do a initial load of data. Currently, that's about 400Gb, give or take 10Gb or so... The backup system is producing files which are about 4Gb each, and has some other, smaller related files also. So, i need to transfer all 400ish gigs to a remote server, but how? What is the best method? I have full remote access to the server, so i can install anything i need to install. There are Windows, Linux and a Solaris VM running on the box itself, so any of those can be used there, and i have Windows and Linux at home. I have 2 internet connections in house, 10Mb/s uploading on each, so something that could potentially split the number of connections would be handy (kind of like GetRight, but in reverse... PutRight?).

    Read the article

  • List all files from a directory recursively with Java

    - by Hultner
    Okay I got this function who prints the name of all files in a directory recursively problem is that it's very slow and it gets the stuff from a network device and with my current code it has to access the device time after time. What I would want is to first load all the files from the directory recursively and then after that go through all files with the regex to filter out all the files I don't want. Unless anyone got a better suggestion. I've never before done anything like this. public static printFnames(String sDir){  File[] faFiles = new File(sDir).listFiles();  for(File file: faFiles){ if(file.getName().matches("^(.*?)")){   System.out.println(file.getAbsolutePath()); }   if(file.isDirectory()){     printFnames(file.getAbsolutePath());   }  } } This is just a test later on I'm not going to use the code like this, instead I'm going to add the path and modification date of every file which matches an advanced regex to an array.

    Read the article

  • Another "Trouble copying music files from HD to 16GB thumb drive"

    - by Ron
    I have a brand new HP Quad Core - 6GB Ram - running 64-bit Windows 7. Running Norton Internet 2010. I try copying music files from HD to 16 GB thumbdrive and get blue screen after a few files have transfered over to thumbdrive. Computer blinks once and boom - blue screen and then reboots. This is really aggravating. I stopped anti-virus, pulled other USB attached devices - still does same thing. Any solutions out there?

    Read the article

  • Cisco NAC: help with enabling FTP or moving update files

    - by kyoung
    Hi, So this is a LINUX question, and a Cisco NAC question. I'm trying to update our server from 4.1 to 4.7, and i need to move some tarball files to the NAC. the NAC Appliance runs some strange stripped down version of Fedora Core 4 copying the upgrade: The instructions say to FTP the file to the NAC appliance, however whenever i use WinSCP with root credentials, i get a notice informing me the connection was actively refused. I can't for the life of me find any .conf files that sound like winners, so I don't know how to change the settings, however the ftp command does seem to work. what exactly should I do here?

    Read the article

  • Looking for a way execute a task on all files in a directory (recursively) on Windows

    - by stzzz1
    I have a huge number of mp4 video files that needs to have a volume boost. I need a way to execute a ffmpeg audio filter on all files in a specified base directory (and in subdirectories as well). My problem is that I'm working on a Windows computer and I have no knowledge of its shell syntax. I would like to do the equivalent of what this bash script does : TARGET_FILES=$(find /path/to/dir -type f -name *.mp4) for f in $TARGET_FILES do ffmpeg -i $f -af 'volume=4.0' output.$f done I spent quite some time this afternoon looking for a solution but the recursive nature of what I need (that is so simple with find!) isn't too clear. Any help would be greatly appreciated!

    Read the article

  • write a batch file to copy files from one folder to another folder

    - by user73628
    I am having a storage folder on network in which all users will store their active data on a server now that server is going to be replaced by new one due to place problem so I need to copy sub folders files from the old server storage folder to new server storage folder. I have below ex: from \Oldeserver\storage\data & files to \New server\storage\data & files.

    Read the article

  • Scalable (half-million files) version control system

    - by hashable
    We use SVN for our source-code revision control and are experimenting using it for non-source-code files. We are working with a large set (300-500k) of short (1-4kB) text files that will be updated on a regular basis and need to version control it. We tried using SVN in flat-file mode and it is struggling to handle the first commit (500k files checked in) taking about 36 hours. On a daily basis, we need the system to be able to handle 10k modified files per commit transaction in a short time (<5 min). My questions: Is SVN the right solution for my purpose. The initial speed seems too slow for practical use. If Yes, is there a particular svn server implementation that is fast? (We are currently using the gnu/linux default svn server and command line client.) If No, what are the best f/oss/commercial alternatives Thanks

    Read the article

  • How do I list all the files for a commit in git

    - by Philip Fourie
    I need to write a script that retrieves all files that were committed for a given SHA1. I have difficulty getting a nice formatted list of all files that were part of the commit. I have tried: git show a303aa90779efdd2f6b9d90693e2cbbbe4613c1d Although listing the files it also includes additional diff information that I don't need. I am hoping there is a simple git command that will provide such a list without me having to parse it from the above command.

    Read the article

  • Makefile option/rule to handle missing/removed source files

    - by b3nj1
    http://stackoverflow.com/questions/239004/need-a-makefile-dependency-rule-that-can-handle-missing-files gives some pointers on how to handle removed source files for generating .o files. I'm using gcc/g++, so adding the -MP option when generating dependencies works great for me, until I get to the link stage with my .a file... What about updating archives/libraries when input sources go away? This works OK for me, but is there a cleaner way (ie, something as straightforward as the g++ -MP option)? #BUILD_DIR is my target directory (includes Debug/Release and target arch) #SRC_OUTS are my .o files LIBATLS_HAS = $(shell nm ${BUILD_DIR}/libatls.a | grep ${BUILD_DIR} | sed -e 's/.*(//' -e 's/).*://') LIBATLS_REMOVE = $(filter-out $(notdir ${SRC_OUTS}), ${LIBATLS_HAS}) ${BUILD_DIR}/libatls.a: ${BUILD_DIR}/libatls.a(${SRC_OUTS}) ifneq ($(strip ${LIBATLS_REMOVE}),) $(AR) -d $@ ${LIBATLS_REMOVE} endif

    Read the article

  • Permissions error for a signed Java applet when including external JAR files

    - by sri
    I have a signed Java applet. And it works fine. But now I have to integrate some 3rd party JAR files with it. When I test it from Eclipse, the whole thing works correctly. But when I test it as an applet, it gives me a FilePermission error. I thought this was because those 3rd party JAR files don't have a java.policy.applet within them. But manually adding the policy file doesn't get rid of the error. What am I missing? Thanks! ============================ All the 3rd party JAR files sit on the server filesystem like so: A.jar, B.jar, C.jar. And I include them in the applet tag like so: <applet archive="my.jar,A.jar,B.jar,C.jar"> </applet> Also, in the MANIFEST/MANIFEST.MF file in my.jar, I include those JAR files like so: Class-Path: A.jar,B.jar,C.jar

    Read the article

  • Sending files through ssh

    - by Frion3L
    I need to send files to a server using ssh. I have never used ssh so this is being really frustrating to me. Mention the client (me) is using windows and the server is using Ubuntu. I connected to the server using ssh2 ip, and then loging with an account I have. Now, I would like to send my files to a folder in the server, so, I moved to the folder and I used this command: scp test.txt user_name@host_direction server_folder_destination And it always return that it can't do 'stat' over test.txt, the file doesn't exist, and so. I'm assuming ssh2 can't see the file in my computer root (C:), so I tried to specifie more and added: C:\test.txt, but apear the same error. I don't know what is happening. Any hints please? Thanks

    Read the article

  • Files copying between servers by creation time

    - by driftux
    My bash scripting knowledge is very weak that's why I'm asking help here. What is the most effective bash script according to performance to find and copy files from one LINUX server to another using specifications described below. I need to get a bash script which finds only new files created in server A in directories with name "Z" between interval from 0 to 10 minutes ago. Then transfer them to server B. I think it can be done by formatting a query and executing it for each founded new file "scp /X/Y.../Z/file root@hostname:/X/Y.../Z/" If script finds no such remote path on server B it will continue copying second file which directory exists. File should be copied with permissions, group, owner and creation time. X/Y... are various directories path. I want setup a cron job to execute this script every 10 minutes. So the performance is very important in this case. Thank you.

    Read the article

  • How to choose my own filename format for subscribed podcast files?

    - by user14068
    I subscribe to several podcasts where the filenames of the downloaded mp3 files have no particular pattern to them. When I copy the directory of accumulated mp3 files into my mp3 player, the files play in alphabetical order. What I really want is to play the files chronologically by release date. I currently use iTunes on Windows XP to download the files. What I do now is manually rename the files, adding the date in YYYYMMDD format to the start of each filename so that an alphabetical listing of files will correspond to their chronological order when I listen to them later in PocketTunes on my Palm Centro. Is there some way to get the release date into the filename automatically? If so, I could automate or possibly skip the file renaming step. I would switch from iTunes to something else if that would solve my problem. The file creation time on my local disk isn't a reliable indicator because sometimes I download a few days worth of content at one time, and the files don't necessarily get downloaded in chronological order.

    Read the article

  • Can Flash player play .m3u audio files from a remote location

    - by undefined
    Is it possible to play a .m3u file streamed from a remote location through Flash Player in a browser? I have a player that loads and plays .mp3 files but also want to be able to play .m3u files. I have looked at the as3plsreader on google code but I think this is only for AIR and desktop files. anyone tried this or know where I should start looking for an answer? If I wasnt to use flash, what other ways could I get remote m3u files to play in a browser?

    Read the article

  • python processs complete list files matched

    - by thomytheyon
    Hi All, I'm trying to get a simple code working, unfortunatly im a python beginner. My script should return a list of files that doesn't match a pattern, more information here : http://stackoverflow.com/questions/2910106/python-grep-reverse-matching/2910288#2910288 My code is running but doesn't process the complete list of files found as it should : import sys,os filefilter = ['.xml','java','.jsp','lass'] path= "/home/patate/code/project" s = "helloworld" for path, subdirs, files in os.walk(path): for name in files: if name[-4:] in filefilter : f = str(os.path.join(path, name)) with open(f) as fp: if s in fp.read(): print "%s has the string" % f else: print "%s doesn't have the string" % f This code return : /home/patate/code/project/blabla/blabla/build.xml doesn't have the string None If i change f = str(os.path.join(path, name)) for print str(os.path.join(path, name)) I can see the whole list being printed. How can i process the whole list as i which to ? :( Thanks again.

    Read the article

  • Controlling access to large files in Apache

    - by obeattie
    Hi there, I am looking to control access to some large files (we're talking many GB here) by the use of signed URLs. The files are currently restricted by LDAP Basic authentication (mod_auth_ldap), but I need to change this to verify the signature (passed as a query parameter in the URL). Basically, I just need to run a script to verify the signature, and allow the request to proceed as if authentication had succeeded. My initial thought to this was just to use a simple CGI script, but as the files are so large I'm concerned about performance. So, really, this question is (probably) more like "are there any performance implications of streaming large files from a CGI script via Apache?"… and if so, "is there a better way of doing this (short of writing a dedicated authentication module)?" If this makes any sense, help would be much appreciated :) P.S. I wasn't sure exactly what to search for for this (10 minutes of Googling were fruitless), so I may very well be duplicating someone else's post.

    Read the article

  • Playing audio files from system directory

    - by zx
    hi, I have audio files in var/ This is the file name 2-3109999999-3246758493-1271129518-1271129505.6.wav Format 2=campaign id 3109999999=caller id 3246758493=number called 1271129518=timestamp call ended 1271129505=timestamp call started 6=call id If I were to pass just the number called which was 3246758493, how can I find all the files without defining all the other variables(such as timestamp, etc) and just the files that have that number in the filename?

    Read the article

  • Windows DIR listing switch to exclude files in hidden folders

    - by Jason
    I'm trying to get a list of files from a directory excluding files in hidden folders. With the following command, hidden folders are traversed even though I've set /A:-H to exclude hidden directories. Is there a different switch to stop them from being traversed too? dir "C:\SVN" /A:-H /w /b /s Alternatively, for this use case I know the name of the hidden folders I want to exclude, so if there is a way to exclude the folders by name ("\.svn\") that might have to suffice. Thanks!

    Read the article

  • Is there any diff tool for XML files?

    - by qedi
    Are there any good (Linux) tools for diffing two XML files? Ideally, I would like to be able configure it to some things strict, or loosen some things, like whitespace, or attribute order. I'll often care that the files are functionally the same, but diff by itself, would be annoying to use, especially if the XML file doesn't have a lot of linebreaks. For example, the following should really be okay to me: <tag att1="one" att2="two"> content </tag> <tag att2="two" att1="one"> content </tag>

    Read the article

  • Windows Server 2008 scheduled tasks cannot create files

    - by Nick Cartwright
    We have a series of tasks which, when run interactively over the command line run fine creating temporary files and (importantly) logs and backups. When we schedule the task with Administrator privileges to run at the highest priority, however, no logs or temporary files are created! All the directories have read/write privileges as administrator. Has anyone else experienced this?? We are running Windows 2008 Server & the job is configured for 'Windows Vista or Windows Server 2008'. Any help would be much appreciated! OK - so we installed Z-Cron and it works perfectly.... Still a really really strange error from Windows 2008 Task Scheduler, but a solution is perhaps not quite so urgent now we have Z-Cron working!

    Read the article

  • Python - open text file, but specify name when executing command

    - by Dunnolol
    I have a directory of text files that all end in the extension .txt My goal is to print the contents of the text file. I wish to be able use the wildcard *.txt to be able to specific the text file name I wish to open (I'm thinking along the lines of something like "F:\text*.txt" ?), split the lines of the text file, then print the output. Here is an example of what I want to do, but I want to be able to change "somefile" when executing my command. f = open('F:\text\somefile.txt', 'r') for line in f: print line,

    Read the article

< Previous Page | 134 135 136 137 138 139 140 141 142 143 144 145  | Next Page >