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  • Xampp error on windows

    - by Deepak Kumar
    My problem is when i use xampp i see many error and when i use my web it has no error Notice: Undefined index: action in C:\xampp\htdocs\xyz\index.php on line 3 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 11 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 34 Notice: A session had already been started - ignoring session_start() in C:\xampp\htdocs\xyz\data.php on line 2 Notice: Undefined index: r in C:\xampp\htdocs\xyz\data.php on line 4 Notice: Undefined index: ucNick in C:\xampp\htdocs\xyz\data.php on line 8 I have tried many time changing things in Setting, Security, Privileges etc but nothing changed, I want to know if im missing something out Thanks

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  • how store date in myqsl database?

    - by Syom
    i have date in dd/mm/yyyy format. how can i store it in databse, if i fant to do some operations on them after? for example i must find out the rows, where date > something what type i must set to date field? thanks

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  • Only first word of two strings gets added to db

    - by dkgeld
    When trying to add words to a database via php, only the first word of both strings gets added. I send the text via this code: public void sendTextToDB() { valcom = editText1.getText().toString(); valnm = editText2.getText().toString(); t = new Thread() { public void run() { try { url = new URL("http://10.0.2.2/HB/hikebuddy.php?function=setcomm&comment="+valcom+"&name="+valnm); h = (HttpURLConnection)url.openConnection(); if( h.getResponseCode() == HttpURLConnection.HTTP_OK){ is = h.getInputStream(); }else{ is = h.getErrorStream(); } h.disconnect(); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); Log.d("Test", "CONNECTION FAILED 1"); } } }; t.start(); } When tested with spaces and commas etc. in a browser, the php function adds all text. The strings also return the full value when inserted into a dialog. How do I fix this? Thank you.

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  • how store date in mysql database?

    - by Syom
    i have date in dd/mm/yyyy format. how can i store it in databse, if i fant to do some operations on them after? for example i must find out the rows, where date > something what type i must set to date field? thanks

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  • how to select all the data from many tables?

    - by Syom
    how to select all the data from many tables? i try `"SELECT * FROM `table1`, `table2`"` , but result none understandable for me. it returns only some rows from table1, and 3 times all the data from table2. i've red one same question here, but don't understand the answer. so could you help me? thanks in advance. update: when i try (SELECT * FROM `videos`) UNION (SELECT * FROM `users`) it returns #1222 - The used SELECT statements have a different number of columns

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  • How to query one table and add rows to another using that first query? MySQL

    - by Nickelbids
    Hello, I have some users setup in a MySQL table with different variables. I am trying to figure out what would be the best way to do this. Basically I want to award all of my registered and active users with bids which are stored in another table. So for the Table "users" I have ran this query: SELECT * FROM users WHERE active = 1 AND admin = 0 ORDER BY users.id ASC Which will show all active users who are not administrators. Now I would like to give each one of these users which are identified by the "ID" field in another table. So in the "bids" table I would need to add a new row for each one of those users with all of the same values except for the "user_id" field which will basically match the "id" field of the table "users" What would be the best approach for this. There are approximately 6,000+ users coming up in the first query. Please be gentle as I am not a programmer. Just need some friendly advice.

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  • User monthly payment system

    - by SomCollection
    I want to create a monthly payment system for community members, at this point I have figured out that I need the following tables in my mysql database. Edited Users table user_id, first_name, last_name Payment table payment_id,user_id,amount,due_date,payment_date,total What I need to display list of users who did not pay 6th of every month. How do I do this? And once the last day of the month is reached, how do I move to the next month?

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  • Can't create/write to file (Errcode: 22)

    - by magdmartin
    Quite new with SQL I'm looking to export some data from a MySQL database into a csv file. I'm working locally (localhost). Here is my SQL statement: SELECT DISTINCT * INTO OUTFILE 'C:\Users\Martin\Downloads\result.csv' FROM provider, location, provider_has_location WHERE provider.idprovider = provider_has_location.provider_idprovider AND location.idLocation = provider_has_location.location_idLocation LIMIT 20 MySQL return the following error: Can't create/write to file 'C:UsersMartinDownloads esult.csv' (Errcode: 22) Thanks for your help.

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  • PHP vs Phpmyadmin

    - by user330306
    Hi there, I've got this code which i execute on phpmyadmin which works 100% Create Temporary Table Searches ( id int, dt datetime); Create Temporary Table Searches1 ( id int, dt datetime, count int); insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; insert into Searches1(id, dt, count) select b.savedSearchesId, (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', count(b.savedSearchesId) as 'cnt' from tblSavedSearchesDetails b group by b.savedSearchesId; insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); update tblSavedSearchResults inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; However when i put the same code in php as below it generates an error $dba = DbConnect::CreateDbaInstance(); $query = ""; $query.="Create Temporary Table Searches ( id int, dt datetime); "; $query.="Create Temporary Table Searches1 ( id int, dt datetime, count int); "; $query.="insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; "; $query.="insert into Searches1(id, dt, count) "; $query.="select "; $query.=" b.savedSearchesId, "; $query.=" (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', "; $query.=" count(b.savedSearchesId) as 'cnt' "; $query.="from tblSavedSearchesDetails b "; $query.="group by b.savedSearchesId; "; $query.="insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) "; $query.="select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); "; $query.="update tblSavedSearchResults "; $query.="inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id "; $query.="Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; "; $dba->DbQuery($query) or die(mysql_error()); I get the following error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Create Temporary Table Searches1 ( id int, dt datetime, count int) insert into S' at line 1 Please if someone could assist me with this ... Thanks

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  • Developed android application cannot connect to phpmyadmin

    - by user1850936
    I am developing an app with eclipse. I tried to store the data that key in by user into database in phpmyadmin. Unfortunately, after the user has clicked on submit button, there is no response and data is not stored in my database. Here is my java file: import java.util.ArrayList; import java.util.List; import org.apache.http.NameValuePair; import org.apache.http.message.BasicNameValuePair; import org.json.JSONObject; import android.app.Activity; import android.app.AlertDialog; import android.content.DialogInterface; import android.content.Intent; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.RadioButton; import android.content.res.Configuration; public class UserRegister extends Activity { JSONParser jsonParser = new JSONParser(); EditText inputName; EditText inputUsername; EditText inputEmail; EditText inputPassword; RadioButton button1; RadioButton button2; Button button3; int success = 0; private static String url_register_user = "http://10.20.92.81/database/add_user.php"; private static final String TAG_SUCCESS = "success"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_user_register); inputName = (EditText) findViewById(R.id.nameTextBox); inputUsername = (EditText) findViewById(R.id.usernameTextBox); inputEmail = (EditText) findViewById(R.id.emailTextBox); inputPassword = (EditText) findViewById(R.id.pwTextBox); Button button3 = (Button) findViewById(R.id.regSubmitButton); button3.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); if (name.contentEquals("")||username.contentEquals("")||email.contentEquals("")||password.contentEquals("")) { AlertDialog.Builder builder = new AlertDialog.Builder(UserRegister.this); builder.setMessage(R.string.nullAlert) .setTitle(R.string.alertTitle); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { } }); AlertDialog dialog = builder.show(); } // creating new product in background thread RegisterNewUser(); } }); } public void RegisterNewUser() { try { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); // Building Parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("name", name)); params.add(new BasicNameValuePair("username", username)); params.add(new BasicNameValuePair("email", email)); params.add(new BasicNameValuePair("password", password)); // getting JSON Object // Note that create product url accepts POST method JSONObject json = jsonParser.makeHttpRequest(url_register_user, "GET", params); // check log cat for response Log.d("Send Notification", json.toString()); success = json.getInt(TAG_SUCCESS); if (success == 1) { // successfully created product Intent i = new Intent(getApplicationContext(), StudentLogin.class); startActivity(i); finish(); } else { // failed to register } } catch (Exception e) { e.printStackTrace(); } } @Override public void onConfigurationChanged(Configuration newConfig) { super.onConfigurationChanged(newConfig); } } my php file: <?php $response = array(); require_once __DIR__ . '/db_connect.php'; $db = new DB_CONNECT(); if (isset($_GET['name']) && isset($_GET['username']) && isset($_GET['email']) && isset($_GET['password'])) { $name = $_GET['name']; $username = $_GET['username']; $email = $_GET['email']; $password = $_GET['password']; // mysql inserting a new row $result = mysql_query("INSERT INTO register(name, username, email, password) VALUES('$name', '$username', '$email', '$password')"); // check if row inserted or not if ($result) { // successfully inserted into database $response["success"] = 1; $response["message"] = "You are successfully registered to MEMS."; // echoing JSON response echo json_encode($response); } else { // failed to insert row $response["success"] = 0; $response["message"] = "Oops! An error occurred."; // echoing JSON response echo json_encode($response); } } else { // required field is missing $response["success"] = 0; $response["message"] = "Required field(s) is missing"; // echoing JSON response echo json_encode($response); } ?> the log cat is as follows: 11-25 10:37:46.772: I/Choreographer(638): Skipped 30 frames! The application may be doing too much work on its main thread.

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  • Disadvantages of a fake phpMyAdmin honeypot that causes ip blacklisting and robots.txt disallow/exclusion of the honeypot?

    - by Tchalvak
    I'm trying to figure out whether I should set up a honeypot system with a fake phpMyAdmin (site gets hits all the time with people spidering for insecurities with that app). My thought was to create a honeypot php script that would mimic a phpMyAdmin login, and then blacklist ips that hit that url (and aren't already whitelisted). I would then add the appropriate urls to the robots.txt so that spiders that actually respect my robots.txt wouldn't be caught by the blacklist. Are there disadvantages to this approach, do legit robots sometimes not respect robots.txt in certain circumstances, are there any problems with this that I should consider in advance?

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  • Reset ID autoincrement ? phpmyadmin

    - by Marcelo
    Hi, I was testing some data in my tables of my database, to see if there was any error, now I cleaned all the testing data, but my id (auto increment) does not start from 1 anymore, can (how do) I reset it ? Sorry for any mistake in English, and thanks for the attention.

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  • HOW TO FIX "The requested URL /phpMyAdmin was not found on this server"

    - by user1392840
    I have install apache,php and mysql on Mac 10.8.1. After this, in my web brower i type this, it give the error message Not Found The requested URL /News-2012-Academy-Awards-53.html was not found on this server. Apache/2.2.22 (Unix) mod_fastcgi/2.4.6 mod_ssl/2.2.22 OpenSSL/0.9.8r DAV/2 PHP/5.3.13 with Suhosin-Patch mod_wsgi/3.3 Python/2.7.2 Server at clontarf.girlsacademy.com.au Port 80" Please help me to solve it.

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  • phpmyadmin shows numbers or blob for mysql's utf8_bin callation columns?

    - by marc40000
    Hi ! I have a table with a varchar column. Its collation is set to utf8_bin. My software using this table and column works perfectly. But when I look at the content in phpmyadmin, I only see some hex values or [Blob xB]. Can I make phpmyadmin show the content correctly? Besides, when I set the collation to utf8_general_ci or utf8_unicode_ci, the phpmyadmin shows the content correctly. Thx Marc [edit]Hah, I found out, there is a small "+Options" link above every table in phpmyadmin. It opens several options including "Show BLOB contents" - which makes the [blob] to readable text when enabled and "Show binary contents as HEX" which shows the hex codes as text when disabled. No idea why there are two options though and why sometimes there is a [Blob] and sometimes hex values. Well. Now I'm still wondering: Setting these options get lost when I go to another table. I have to set them every time I go there. Is there a way to save those options? [/edit]

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  • PHP pages are not parsed by Apache on CentOS

    - by Ram
    I have installed Centos 5.x, Apache 2.2, PHP 5.3 and MySQL 5.5. I also installed phpMyAdmin. I am able to access phpMyAdmin through the browser without any issues. However, when I create a simple index.php with phpinfo() function in the default directory, that page is served without php parsing. As we all know, phpMyAdmin is a php application. This is working fine from the same server but not the simple php page from the doc root directory ??!!!. Of course, I tried moving this page into phpMyAdmin folder and tried accessing it, but no success. Please note that I updated httpd.conf file with appropriate directives based on the php installation guide.Following directives were added to httpd.conf. AddTyoe application/x-httpd-php LoadModule php5_module /usr/lib/httpd/modules/libphp5.so <FilesMatch "\.php$"> SetHandler application/x-httpd-php </FilesMatch> File locations are: docroot - /var/www/html phpMyAdmin folder - /var/www/html/phpMyAdmin File privileges are: [root@linuxdev1 html]# ls -Z -rwxr-xr-x root root index.php drwxr-xr-x root root phpMyAdmin -rw-r--r-- root root phpMyAdmin-3.4.3.2-english.tar.gz drwxr-xr-x root root test1 Any help is appreciated.

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  • PHP pages are not parsed by Apache on CentOS

    - by infotoknowledge
    I have installed Centos 5.x, Apache 2.2, PHP 5.3 and MySQL 5.5. I also installed phpMyAdmin. I am able to access phpMyAdmin through the browser without any issues. However, when I create a simple index.php with phpinfo() function in the default directory, that page is served without php parsing. As we all know, phpMyAdmin is a php application. This is working fine from the same server but not the simple php page from the doc root directory ??!!!. Of course, I tried moving this page into phpMyAdmin folder and tried accessing it, but no success. Please note that I updated httpd.conf file with appropriate directives based on the php installation guide. docroot - /var/www/html phpMyAdmin folder - /var/www/html/phpMyAdmin Any help is appreciated.

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  • How to set password for phpMyAdmin with default install of WAMP2?

    - by Danjah
    I just installed it fresh, previously there would be no password at all and I'd be prompted to set one for security purposes, this time I'm just hit with an error: "Cannot connect: invalid settings. phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server." I've changed nothing, but I did install over the top of an older version of WAMP2. That older install did not have a root password. Please don't hit me, but if there's a text fie I can update somewhere instead of getting a cmd line action wrong... I'd really like to be pointed in that direction. I've just tried editing 'my.ini' and uncommented the password line out, so password is blank, but no luck. I don't mind setting a password and such, but right now I just want to get up and running, password or no.

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  • phpMyAdmin says mcrypt is missing, but it's not; cannot log in

    - by GradysGhost
    I've just compiled a web stack on Solaris 10. This is a fairly standard Apache 2 / MySQL 5 / PHP 5 stack with all the most recent stable versions. I dropped phpMyAdmin on the server and set up httpd.conf to get that online. When I browse to the page, login fails, and a persistent message appears beneath the login form: The mcrypt extension is missing. Please check your PHP configuration. However, I compiled PHP with the --with-mcrypt flag. A file, info.php: <?php phpinfo(); ?> shows that mcrypt support is enabled. Running: php -m on the command line shows that mcrypt is loaded. Google hasn't been much help, and I was hoping someone around these parts could throw some help my way. If I need to provide any further detail, please let me know what you need to know.

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