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  • OpenSSL in C++ email client - server closes connection with TLSv1 Alert message

    - by mice
    My app connects to a IMAP email server. One client configured his server to reject SSLv2 certificates, and now my app fails to connect to the server. All other email clients connect to this server successfully. My app uses openssl. I debugged by creating minimal openssl client and attempt to connect to the server. Below is the code with connects to the mail server (using Windows sockets, but same problem is with unix sockets). Server sends its initial IMAP greeting message, but after client sends 1st command, server closes connection. In Wireshark, I see that after sending command to server, it returns TLSv1 error message 21 (Encrypted Alert) and connection is gone. I'm looking for proper setup of OpenSSL for this connection to succeed. Thanks #include <stdio.h> #include <memory.h> #include <errno.h> #include <sys/types.h> #include <winsock2.h> #include <openssl/crypto.h> #include <openssl/x509.h> #include <openssl/pem.h> #include <openssl/ssl.h> #include <openssl/err.h> #define CHK_NULL(x) if((x)==NULL) exit(1) #define CHK_ERR(err,s) if((err)==-1) { perror(s); exit(1); } #define CHK_SSL(err) if((err)==-1) { ERR_print_errors_fp(stderr); exit(2); } SSL *ssl; char buf[4096]; void write(const char *s){ int err = SSL_write(ssl, s, strlen(s)); printf("> %s\n", s); CHK_SSL(err); } void read(){ int n = SSL_read(ssl, buf, sizeof(buf) - 1); CHK_SSL(n); if(n==0){ printf("Finished\n"); exit(1); } buf[n] = 0; printf("%s\n", buf); } void main(){ int err=0; SSLeay_add_ssl_algorithms(); SSL_METHOD *meth = SSLv23_client_method(); SSL_load_error_strings(); SSL_CTX *ctx = SSL_CTX_new(meth); CHK_NULL(ctx); WSADATA data; WSAStartup(0x202, &data); int sd = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP); CHK_ERR(sd, "socket"); struct sockaddr_in sa; memset(&sa, 0, sizeof(sa)); sa.sin_family = AF_INET; sa.sin_addr.s_addr = inet_addr("195.137.27.14"); sa.sin_port = htons(993); err = connect(sd,(struct sockaddr*) &sa, sizeof(sa)); CHK_ERR(err, "connect"); /* ----------------------------------------------- */ /* Now we have TCP connection. Start SSL negotiation. */ ssl = SSL_new(ctx); CHK_NULL(ssl); SSL_set_fd(ssl, sd); err = SSL_connect(ssl); CHK_SSL(err); // Following two steps are optional and not required for data exchange to be successful. /* printf("SSL connection using %s\n", SSL_get_cipher(ssl)); X509 *server_cert = SSL_get_peer_certificate(ssl); CHK_NULL(server_cert); printf("Server certificate:\n"); char *str = X509_NAME_oneline(X509_get_subject_name(server_cert),0,0); CHK_NULL(str); printf(" subject: %s\n", str); OPENSSL_free(str); str = X509_NAME_oneline(X509_get_issuer_name (server_cert),0,0); CHK_NULL(str); printf(" issuer: %s\n", str); OPENSSL_free(str); // We could do all sorts of certificate verification stuff here before deallocating the certificate. X509_free(server_cert); */ printf("\n\n"); read(); // get initial IMAP greeting write("1 CAPABILITY\r\n"); // send 1st command read(); // get reply to cmd; server closes connection here write("2 LOGIN a b\r\n"); read(); SSL_shutdown(ssl); closesocket(sd); SSL_free(ssl); SSL_CTX_free(ctx); }

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  • how to print a char from struct

    - by make
    Hi Could someone please tell us to print a char when receiving data as a struct? Here is an example: ... struct rcv{ int x1; float x2; char *x3; }; rcv data_rcv; ... if (recv(socket, &data_rcv, sizeof(data_rcv), 0) < 0) printf("recv() failed"); ... printf("x1 = %d\n", data_rcv.x1); printf("x2 = %f\n", data_rcv.x2); printf("x3 = %s\n", data_rcv.x3); // it doesn't print anything, why? ... Thanks for your replies-

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  • how to print a char od struct()

    - by make
    Hi Could someone please tell us to print a char when receiving data as a truct? here is an EXP: ... struct rcv{ int x1; float x2; char x3; }; rcv data_rcv; ... if (recv(socket, &data_rcv, sizeof(data_rcv), 0) < 0) printf("recv() failed"); ... printf("x1 = %d\n", data_rcv.x1); printf("x2 = %f\n", data_rcv.x2); printf("x3 = %s\n", data_rcv.x3); // it doesn't print anything, why? ... Thanks for your replies-

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  • C programing some errors :(

    - by Pedro
    Hi...this is a little code that i'm doing, but i have some errors...:S Hi have a txt file and i want to "convert to xml", but the program must know what is comments, and must organize... txt file: /* Licenciaturas na ESTG-IPVC 2009 – v1.1*/ - Info, <N Alunos> <hr>--------------------------------------------------- 3 <hr>--------------------------------------------------- - data, <course><Number>;<name>;<email> - disciplinas, <n disciplines>;<note>;[<note>;] </hr>--------------------------------------------------- LEI;7671;Name name name;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;nam1 nam2 nam3;[email protected]; 6;13;14;12;11;16;14; LEI;7701;xxxxx xxxx xxxx;[email protected]; 8;13;11;7;14;12;11;16;14; My code: int main(int argc, char *argv[]) { char first[60];//array char comment[60];//array char nome_int[60];//array char total[60];//array char course[60];//array int i; char notas[60]; char *number, *name, *mail, *total_disci; int total_cad; char disciplines[60]; printf("Int. the name of the file to convert\n"); scanf("%s",&nome_int); FILE *fp = fopen(nome_int, "r"); //open file FILE *conver = fopen("conver.xml","w");// opne output FILE *coment = fopen("coment.txt","w"); if (fp == NULL) { printf("File not found\n"); exit(1); } else { fgets(first, 60,fp); fputs(first,coment); while (!(feof(fp))){ fgets(first, 60, fp); if (first[0] == '-'){ fputs(first,coment); } for(i=1;fscanf(fp,"%s",total)!=-5;i++){ if(i==2){ printf("Total %s",total);//here the program stops } } fgets(course,60,fp); if(course[0]=='L'){ number = strchr(course, ';');//here course is an array but must be an appointer, what can i do? *number = '\0'; number++; name = strchr(number, ';'); *name = '\0'; name++; mail= strchr(name, ';'); *mail = '\0'; mail++; char *curso1; total_cad=atoi(total_disci); printf("Course: %s\n",course); printf("Number: %s\n",number); printf("Name: %s\n",name); printf("e-mail: %s\n",mail); } fgets(disciplines,60,fp);//here crash total_disci= strchr(mail, ';'); *total_disci = '\n'; total_disci++; printf("Total disciplines: %d\n",total_cad); } } fclose(fp); fclose(coment); fclose(conver); system("PAUSE"); return 0; } the convert file must be like this: <xml> <list_courses> <course> <sigla>LEI</sigla> <NAlunos>2</NAlunos> <list_students> <students> <number>7671</number> <name>name name name</name> <email>[email protected]</email> <stat>disaproved</stat> <media_notes>10</media_notes> <biggest_note>15</biggest_note> <small_nota>6</small_nota> </students> </list_students> </course> </list_courses> </xml> _______________________________________- now separated by only comment on what is what and converted to xml. also had to do was impressed that the program could name, email address, number, etc. .. here the main errors do not want to do for me, just want to see the errors, I spent the whole day right back from them and nothing ... someone who can help, please do it :)

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  • how free of memory happen in this case???

    - by Riyaz
    #include <stdio.h> void func(int arr[],int xNumOfElem) { int j; for(j=0; j<xNumOfElem; j++) { arr[j] = j + arr[j]; printf("%d\t",arr[j]); } printf("\n"); } int main() { int *a,k; a = (int*) malloc(sizeof(int)*10); for(k = 0; k<10; k++) { a[k] = k; printf("%d\t",a[k]); } printf("\n"); func(a,10); //Func call free(a); } Inside the the function "func" who will allocate/deallocate memory for dynamic array "arr". arr is an function argument.

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  • Pascals Triangle by recursion

    - by Olpers
    Note : My Class Teacher gave me this question as an assignment... I am not asked to do it but please tell me how to do it with recursion Binomial coefficients can be calculated using Pascal's triangle: 1 n = 0 1 1 1 2 1 1 3 3 1 1 4 6 4 1 n = 4 Each new level of the triangle has 1's on the ends; the interior numbers are the sums of the two numbers above them. Task: Write a program that includes a recursive function to produce a list of binomial coefficients for the power n using the Pascal's triangle technique. For example, Input = 2 Output = 1 2 1 Input = 4 Output = 1 4 6 4 1 done this So Far but tell me how to do this with recursion... #include<stdio.h> int main() { int length,i,j,k; //Accepting length from user printf("Enter the length of pascal's triangle : "); scanf("%d",&length); //Printing the pascal's triangle for(i=1;i<=length;i++) { for(j=1;j<=length-i;j++) printf(" "); for(k=1;k<i;k++) printf("%d",k); for(k=i;k>=1;k--) printf("%d",k); printf("\n"); } return 0; }

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  • Writing a printList method for a Scheme interpreter in C

    - by Rehan Rasool
    I am new to C and working on making an interpreter for Scheme. I am trying to get a suitable printList method to traverse through the structure. The program takes in an input like: (a (b c)) and internally represent it as: [""][ ][ ]--> [""][ ][/] | | ["A"][/][/] [""][ ][ ]--> [""][ ][/] | | ["B"][/][/] ["C"][/][/] Right now, I just want the program to take in the input, make the appropriate cell structure internally and print out the cell structure, thereby getting (a (b c)) at the end. Here is my struct: typedef struct conscell *List; struct conscell { char symbol; struct conscell *first; struct conscell *rest; }; void printList(char token[20]){ List current = S_Expression(token, 0); printf("("); printf("First Value? %c \n", current->first->symbol); printf("Second value? %c \n", current->rest->first->first->symbol); printf("Third value? %c \n", current->rest->first->rest->first->symbol); printf(")"); } In the main method, I get the first token and call: printList(token); I tested the values again for the sublists and I think it is working. However, I will need a method to traverse through the whole structure. Please look at my printList code again. The print calls are what I have to type, to manually get the (a (b c)) list values. So I get this output: First value? a First value? b First value? c It is what I want, but I want a method to do it using a loop, no matter how complex the structure is, also adding brackets where appropriate, so in the end, I should get: (a (b c)) which is the same as the input. Can anyone please help me with this?

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  • Strange (Undefined?) Behavior of Free in C

    - by Chris Cirefice
    This is really strange... and I can't debug it (tried for about two hours, debugger starts going haywire after a while...). Anyway, I'm trying to do something really simple: Free an array of strings. The array is in the form: char **myStrings. The array elements are initialized as: myString[index] = malloc(strlen(word)); myString[index] = word; and I'm calling a function like this: free_memory(myStrings, size); where size is the length of the array (I know this is not the problem, I tested it extensively and everything except this function is working). free_memory looks like this: void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { free(list[i]); } free(list); } Now here comes the weird part. if (size> strlen(list[i])) then the program crashes. For example, imagine that I have a list of strings that looks something like this: myStrings[0] = "Some"; myStrings[1] = "random"; myStrings[2] = "strings"; And thus the length of this array is 3. If I pass this to my free_memory function, strlen(myStrings[0]) > 3 (4 3), and the program crashes. However, if I change myStrings[0] to be "So" instead, then strlen(myStrings[0]) < 3 (2 < 3) and the program does not crash. So it seems to me that free(list[i]) is actually going through the char[] that is at that location and trying to free each character, which I imagine is undefined behavior. The only reason I say this is because I can play around with the size of the first element of myStrings and make the program crash whenever I feel like it, so I'm assuming that this is the problem area. Note: I did try to debug this by stepping through the function that calls free_memory, noting any weird values and such, but the moment I step into the free_memory function, the debugger crashes, so I'm not really sure what is going on. Nothing is out of the ordinary until I enter the function, then the world explodes. Another note: I also posted the shortened version of the source for this program (not too long; Pastebin) here. I am compiling on MinGW with the c99 flag on. PS - I just thought of this. I am indeed passing numUniqueWords to the free function, and I know that this does not actually free the entire piece of memory that I allocated. I've called it both ways, that's not the issue. And I left it how I did because that is the way that I will be calling it after I get it to work in the first place, I need to revise some of my logic in that function. Source, as per request (on-site): #include <stdio.h> #include <string.h> #include <ctype.h> #include <stdlib.h> #include "words.h" int getNumUniqueWords(char text[], int size); int main(int argc, char* argv[]) { setvbuf(stdout, NULL, 4, _IONBF); // For Eclipse... stupid bug. --> does NOT affect the program, just the output to console! int nbr_words; char text[] = "Some - \"text, a stdin\". We'll have! also repeat? We'll also have a repeat!"; int length = sizeof(text); nbr_words = getNumUniqueWords(text, length); return 0; } void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { // You can see that printing the values is fine, as long as free is not called. // When free is called, the program will crash if (size > strlen(list[i])) //printf("Wanna free value %d w/len of %d: %s\n", i, strlen(list[i]), list[i]); free(list[i]); } free(list); } int getNumUniqueWords(char text[], int length) { int numTotalWords = 0; char *word; printf("Length: %d characters\n", length); char totalWords[length]; strcpy(totalWords, text); word = strtok(totalWords, " ,.-!?()\"0123456789"); while (word != NULL) { numTotalWords ++; printf("%s\n", word); word = strtok(NULL, " ,.-!?()\"0123456789"); } printf("Looks like we counted %d total words\n\n", numTotalWords); char *uniqueWords[numTotalWords]; char *tempWord; int wordAlreadyExists = 0; int numUniqueWords = 0; char totalWordsCopy[length]; strcpy(totalWordsCopy, text); for (int i = 0; i < numTotalWords; i++) { uniqueWords[i] = NULL; } // Tokenize until all the text is consumed. word = strtok(totalWordsCopy, " ,.-!?()\"0123456789"); while (word != NULL) { // Look through the word list for the current token. for (int j = 0; j < numTotalWords; j ++) { // Just for clarity, no real meaning. tempWord = uniqueWords[j]; // The word list is either empty or the current token is not in the list. if (tempWord == NULL) { break; } //printf("Comparing (%s) with (%s)\n", tempWord, word); // If the current token is the same as the current element in the word list, mark and break if (strcmp(tempWord, word) == 0) { printf("\nDuplicate: (%s)\n\n", word); wordAlreadyExists = 1; break; } } // Word does not exist, add it to the array. if (!wordAlreadyExists) { uniqueWords[numUniqueWords] = malloc(strlen(word)); uniqueWords[numUniqueWords] = word; numUniqueWords ++; printf("Unique: %s\n", word); } // Reset flags and continue. wordAlreadyExists = 0; word = strtok(NULL, " ,.-!?()\"0123456789"); } // Print out the array just for funsies - make sure it's working properly. for (int x = 0; x <numUniqueWords; x++) { printf("Unique list %d: %s\n", x, uniqueWords[x]); } printf("\nNumber of unique words: %d\n\n", numUniqueWords); // Right below is where things start to suck. free_memory(uniqueWords, numUniqueWords); return numUniqueWords; }

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  • get return value from 2 threads in C

    - by polslinux
    #include <stdio.h> #include <stdlib.h> #include <pthread.h> #include <stdint.h> #include <inttypes.h> typedef struct tmp_num{ int tmp_1; int tmp_2; }t_num; t_num t_nums; void *num_mezzo_1(void *num_orig); void *num_mezzo_2(void *num_orig); int main(int argc, char *argv[]){ pthread_t thread1, thread2; int tmp=0,rc1,rc2,num; num=atoi(argv[1]); if(num <= 3){ printf("Questo è un numero primo: %d\n", num); exit(0); } if( (rc1=pthread_create( &thread1, NULL, &num_mezzo_1, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc1); exit(1); } if( (rc2=pthread_create( &thread2, NULL, &num_mezzo_2, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc2); exit(1); } t_nums.tmp_1 = 0; t_nums.tmp_2 = 0; pthread_join(thread1, (void **)(&t_nums.tmp_1)); pthread_join(thread2, (void **)(&t_nums.tmp_2)); tmp=t_nums.tmp_1+t_nums.tmp_2; printf("%d %d %d\n", tmp, t_nums.tmp_1, t_nums.tmp_2); if(tmp>2){ printf("Questo NON è un numero primo: %d\n", num); } else{ printf("Questo è un numero primo: %d\n", num); } exit(0); } void *num_mezzo_1(void *num_orig){ int cont_1; int *n_orig=(int *)num_orig; t_nums.tmp_1 = 0; for(cont_1=1; cont_1<=(*n_orig/2); cont_1++){ if((*n_orig % cont_1) == 0){ (t_nums.tmp_1)++; } } pthread_exit((void *)(&t_nums.tmp_1)); return NULL; } void *num_mezzo_2(void *num_orig){ int cont_2; int *n_orig=(int *)num_orig; t_nums.tmp_2 = 0; for(cont_2=((*n_orig/2)+1); cont_2<=*n_orig; cont_2++){ if((*n_orig % cont_2) == 0){ (t_nums.tmp_2)++; } } pthread_exit((void *)(&t_nums.tmp_2)); return NULL; } How this program works: i have to input a number and this program will calculate if it is a prime number or not (i know that it is a bad algorithm but i only need to learn pthread). The problem is that the returned values are too much big.For example if i write "12" the value of tmp tmp_1 tmp_2 into the main are 12590412 6295204 6295208.Why i got those numbers??

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  • Why do i get segfault at the end of the application after everything's beed done properly ?

    - by VaioIsBorn
    #include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char pass[] = "m4ak47"; printf("Vnesi password: \t"); scanf("%s", stole); if(strncmp(stole, pass, sizeof(pass)) != 0) { printf("wrong password!\n"); exit(0); } else printf("Password correct\n"); printf("some stuf here...\n\n"); return 0; } This program is working nice, but with one problem - if the password is correct then it DOES do the printing of 'some stuf here...' but it also shows me segmentation fault error at the end. Why ?

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  • How does C free() work?

    - by slee
    #include <stdio.h> #include <stdlib.h> int * alloc() { int *p = (int *)calloc(5,4); printf("%d\n",p); return p; } int main() { int *p = alloc(); free(p); printf("%d\n",p); p[0] = 1; p[1] = 2; printf("%d %d\n",p[0],p[1]); } As to the code segment, I allocate 5 ints,first. And then I free the memory. When I printf p, why does p sill have a value same to the memory address allocated first? And I also can assign value to p[0] and p[1]. Does this mean free() do nothing? Once I allocate memory, I can use later though I have freed it.

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  • C Program not running as intended, hangs after input

    - by user41419
    The program I am writing to take a number and display that number as a calculator would display it (shown below) is compiling with no issues, but when I try to run it, I am able to input my number, but nothing happens. It seems like it is "hanging", since no further output is shown as I would have expected. Might anyone know what the problem is? #include <stdio.h> #define MAX_DIGITS 20 char segments[10][7] = /* seven segment array */ {{'1','1','1','1','1','1','0'}, /* zero */ {'0','1','1','0','0','0','0'}, /* one */ {'1','1','0','1','1','0','1'}, /* two */ {'1','1','1','1','0','0','1'}, /* three */ {'0','1','1','0','0','1','1'}, /* four */ {'1','0','1','1','0','1','1'}, /* five */ {'1','0','1','1','1','1','1'}, /* six */ {'1','1','1','0','0','0','0'}, /* seven */ {'1','1','1','1','1','1','1'}, /* eight */ {'1','1','1','0','0','1','1'}};/* nine */ char digits[3][MAX_DIGITS * 4]; /* digits array */ int i, j; /* count variables */ int adjust; /* output formatting */ int main(void) { clear_digits_array(); int digit[20]; for (i = 0; i < 20; i++) { digit[i] = 0; } int count = 20; int position = 0; printf("Enter a number: "); int number = scanf("%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d%d", &digit[0], &digit[1], &digit[2], &digit[3], &digit[4], &digit[5], &digit[6], &digit[7], &digit[8], &digit[9], &digit[10], &digit[11], &digit[12], &digit[13], &digit[14], &digit[15], &digit[16], &digit[17], &digit[18], &digit[19]); //NOTHING HAPPENS AFTER HERE printf("Got input, number is %d", number); while (count > 0) { printf("Reading digits, count is %d", count); process_digit(digit[20 - count], position); position++; count--; } print_digits_array(); printf("\n"); return 0; } void clear_digits_array(void) { /* fill all positions in digits array with blank spaces */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { digits[i][j] = ' '; } } } void process_digit(int digit, int position) { /* check each segment to see if segment should be filled in for given digit */ for (i = 0; i < 7; i++) { printf("Processing digit %d at position %d, i is %d", digit, position, i); if (segments[digit][i] == 1) { switch (i) { case 0: digits[0][(position * 4) + 1] = '_'; break; case 1: digits[1][(position * 4) + 2] = '|'; break; case 2: digits[2][(position * 4) + 2] = '|'; break; case 3: digits[2][(position * 4) + 1] = '_'; break; case 4: digits[2][(position * 4) + 0] = '|'; break; case 5: digits[1][(position * 4) + 0] = '|'; break; case 6: digits[1][(position * 4) + 1] = '_'; break; } } } } void print_digits_array(void) { /* print each character in digits array */ for (i = 0; i < 3; i++) { for (j = 0; j < (MAX_DIGITS * 4); j++) { printf("%c", digits[i][j]); } printf("/n"); } }

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  • GCC compile time division error

    - by kartikmohta
    Can someone explain this behaviour? test.c: #include <stdio.h> int main(void) { printf("%d, %d\n", (int) (300.6000/0.05000), (int) (300.65000/0.05000)); printf("%f, %f\n", (300.6000/0.05000), (300.65000/0.05000)); return 0; } $ gcc test.c $ ./a.out 6012, 6012 6012.000000, 6013.000000 I checked the assembly code and it puts both the arguments of the first printf as 6012, so it seems to be a compile time bug.

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  • if non zero elements in same column count only once

    - by George
    I want to check the elements above the main diagonal and if I found non zero values , count one. If the non zero values are found in the same column ,then count just one ,not the number of the non zero values. For example , it should be count = 2 and not 3 in this example because 12 and 6 are in the same column. A= 1 11 12 4 5 6 0 7 0 #include <stdio.h> #include <stdlib.h> #include <math.h> int main( int argc, const char* argv[] ){ int Rows = 3 , Cols = 3; float *A = (float *) malloc ( Rows * Cols * sizeof (float) ); A[0] = 1.0; A[1] = 11.0; A[2] = 12.0; A[3] = 4.0; A[4] = 5.0; A[5] = 6.0; A[6] = 0.0; A[7] = 7.0; A[8] = 0.0; // print input matrix printf("\n Input matrix \n\n"); for ( int i = 0; i < Rows; i++ ) for ( int j = 0; j < Cols; j++ ) { printf("%f\t",A[ i * Cols + j ]); if( j == Cols-1 ) printf("\n"); } printf("\n"); int count = 0; for ( int j = 0 ; j < Cols; j++ ) { for ( int i = ( Rows - 1 ); i >= 0; i-- ) { // check the diagonal elements above the main diagonal if ( j > i ) { if ( ( A[ i * Cols + j ] != 0 ) ) { printf("\n Above nonzero Elmts = %f\n",( A[i * Cols + j] ) ); count++; } } } } printf("\ncount = %d\n",count ); return 0; }

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  • Weird behavior of fork() and execvp() in C

    - by ron
    After some remarks from my previous post , I made the following modifications : int main() { char errorStr[BUFF3]; while (1) { int i , errorFile; char *line = malloc(BUFFER); char *origLine = line; fgets(line, 128, stdin); // get a line from stdin // get complete diagnostics on the given string lineData info = runDiagnostics(line); char command[20]; sscanf(line, "%20s ", command); line = strchr(line, ' '); // here I remove the command from the line , the command is stored in "commmand" above printf("The Command is: %s\n", command); int currentCount = 0; // number of elements in the line int *argumentsCount = &currentCount; // pointer to that // get the elements separated char** arguments = separateLineGetElements(line,argumentsCount); printf("\nOutput after separating the given line from the user\n"); for (i = 0; i < *argumentsCount; i++) { printf("Argument %i is: %s\n", i, arguments[i]); } // here we call a method that would execute the commands pid_t pid ; if (-1 == (pid = fork())) { sprintf(errorStr,"fork: %s\n",strerror(errno)); write(errorFile,errorStr,strlen(errorStr + 1)); perror("fork"); exit(1); } else if (pid == 0) // fork was successful { printf("\nIn son process\n"); // if (execvp(arguments[0],arguments) < 0) // for the moment I ignore this line if (execvp(command,arguments) < 0) // execute the command { perror("execvp"); printf("ERROR: execvp failed\n"); exit(1); } } else // parent { int status = 0; pid = wait(&status); printf("Process %d returned with status %d.", pid, status); } // print each element of the line for (i = 0; i < *argumentsCount; i++) { printf("Argument %i is: %s\n", i, arguments[i]); } // free all the elements from the memory for (i = 0; i < *argumentsCount; i++) { free(arguments[i]); } free(arguments); free(origLine); } return 0; } When I enter in the Console : ls out.txt I get : The Command is: ls execvp: No such file or directory In son process ERROR: execvp failed Process 4047 returned with status 256.Argument 0 is: > Argument 1 is: out.txt So I guess that the son process is active , but from some reason the execvp fails . Why ? Regards REMARK : The ls command is just an example . I need to make this works with any given command . EDIT 1 : User input : ls > qq.out Program output : The Command is: ls Output after separating the given line from the user Argument 0 is: > Argument 1 is: qq.out In son process >: cannot access qq.out: No such file or directory Process 4885 returned with status 512.Argument 0 is: > Argument 1 is: qq.out

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  • ' \r ' vs ' \n ' in C

    - by MCP
    I'm writing a function that basically waits for the user to hit "enter" and then does something. What I've found that works when testing is the below: #include <stdio.h> int main() { int x = getc(stdin); if (x == '\n') { printf("carriage return"); printf("\n"); } else { printf("missed it"); printf("\n"); } } The question I have, and what I tried at first was to do: "if (x == '\r')" but in testing, the program didn't catch me hitting enter. The '\n' seems to correspond to me hitting enter from the console. Can someone explain the difference? Also, to verify, writing it as "if... == "\n"" would mean the character string literal? Ie the user would literally have to enter "\n" from the console, correct? Thanks!

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  • can't connect Java client to C server.

    - by nexes
    I have a very simple server written in C and an equally simple client written in Java. When I run them both on the same computer everything works, but when I try to run the server on computer A and the client on computer B, I get the error IOException connection refused from the java client. I can't seem to find out whats happening, any thoughts? I've even turned off the firewalls but the problem still persists. server. #include <stdio.h> #include <unistd.h> #include <string.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #define PORT 3557 #define BUF 256 int main(int argc, char *argv[]) { struct sockaddr_in host, remote; int host_fd, remote_fd; int size = sizeof(struct sockaddr);; char data[BUF]; host.sin_family = AF_INET; host.sin_addr.s_addr = htonl(INADDR_ANY); host.sin_port = htons(PORT); memset(&host.sin_zero, 0, sizeof(host.sin_zero)); host_fd = socket(AF_INET, SOCK_STREAM, 0); if(host_fd == -1) { printf("socket error %d\n", host_fd); return 1; } if(bind(host_fd, (struct sockaddr *)&host, size)) { printf("bind error\n"); return 1; } if(listen(host_fd, 5)) { printf("listen error"); return 1; } printf("Server setup, waiting for connection...\n"); remote_fd = accept(host_fd, (struct sockaddr *)&remote, &size); printf("connection made\n"); int read = recv(remote_fd, data, BUF, 0); data[read] = '\0'; printf("read = %d, data = %s\n", read, data); shutdown(remote_fd, SHUT_RDWR); close(remote_fd); return 0; } client. import java.net.*; import java.io.*; public class socket { public static void main(String[] argv) { DataOutputStream os = null; try { Socket socket = new Socket("192.168.1.103", 3557); os = new DataOutputStream(socket.getOutputStream()); os.writeBytes("phone 12"); os.close(); socket.close(); } catch (UnknownHostException e) { System.out.println("Unkonw exception " + e.getMessage()); } catch (IOException e) { System.out.println("IOException caught " + e.getMessage()); } } }

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  • compilation error

    - by Bond
    #include<dirent.h> #include<stdio.h> #include<stdlib.h> #include<sys/stat.h> int main () { struct dirent **namelist; int i,j; char userd[20]; struct stat statBuf; printf("Enter a directory %s\n",userd); scanf("%s",&userd); printf("the dir is %s\n",*userd); i=scandir(".",&namelist,0,alphasort); printf("enter a directory name %s",*userd); printf("scandir returned i=%d\n",&i); if (i<0) perror("Scandir failed to open directory I hope you understand \n"); else { for(j=0;j<i;j++) { printf("j=%d i=%d %s\n",j,i,namelist[j]->d_name); // lstat free(namelist[j]); } } free(namelist); } Can some one help to understand why am I getting warning in above code?

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  • Break the limit of threading, segmentation fault

    - by user353573
    use pthread_create to create limited number of threads running concurrently Successfully compile and run However, after adding function pointer array to run the function, Segmentation fault Where is wrong? workserver number: 0 Segmentation fault void* workserver(void arg) { int status; while(true) { printf("workserver number: %d\n", (int)arg); ( job_queue[(int)arg])(); sleep(3); status = pthread_mutex_lock(&data.mutex); if(status != 0) printf("%d lock mutex", status); data.value = 1; status = pthread_cond_signal(&data.cond); if(status != 0) printf("%d signal condition", status); status = pthread_mutex_unlock(&data.mutex); if(status != 0) printf("%d unlock mutex", status); } }

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  • how can I create macro definitions for the lines commented in the code.

    - by yaprak
    #include <stdio.h> //Here use a macro definition that assigns a value to SIZE (for example 5) int main() { int i; int array[SIZE]; int sum=0; for(i=0; i<SIZE; i++) { //Here use a macro definition named as CALCSUM to make the //following addition operation for the array printf("Enter a[%d] = ",i); scanf("%d", &array[i]); sum+=array[i]; //Here use a macro definition named as VERBOSE to print //what program does to the screen printf("The user entered %d\n", array[i]); // // //If the macro definition CALCSUM is not used, the program //should assign 0 to the i-th element of the array array[i]=0; //Here, again use VERBOSE to print what program does to the screen printf("a[%d] is assigned to zero\n", i); // // } //If CALCSUM is defined, print the summation of the array elements to the screen printf("Summation of the array is %d\n",sum); // //If CALCSUM is not defined, but VERBOSE mode is used, print the following printf("All the elements in the array are assigned to zero\n"); // printf("Program terminated\n"); return 0; } When CALCSUM is defined, the program will sum up the values of each element in the given array. If CALCSUM is not defined, each array element will be assigned to zero. Besides, when VERBOSE mode is defined, the program will make print statements pointed out active. [root@linux55]# gcc code.c [root@linux55]# ./a.out Program terminated [root@linux55]# gcc code.c -D CALCSUM [root@linux55]# ./a.out Enter a[0] = 3 Enter a[1] = 0 Enter a[2] = 2 Enter a[3] = 5 Enter a[4] = 9 Summation of the array is 19 Program terminated [root@linux55]# gcc code.c -D CALCSUM -D VERBOSE [root@linux55]# ./a.out Enter a[0] = 2 The user entered 2 Enter a[1] = 10 The user entered 10 Enter a[2] = 3 The user entered 3 Enter a[3] = 8 The user entered 8 Enter a[4] = 1 The user entered 1 Summation of the array is 24 Program terminated [root@linux55]# gcc code.c -D VERBOSE [root@linux55]# ./a.out a[0] is assigned to 0 a[1] is assigned to 0 a[2] is assigned to 0 a[3] is assigned to 0 a[4] is assigned to 0 All the elements in the array is assigned to zero Program terminated

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  • Conversion char[] to char*

    - by sijith
    may be this is a sizzle question but please help void Temp1::caller() { char *cc=Called(); printf("sdfasfasfas"); printf("%s",cc); } char *Temp1::Called() { char a[6]="Hello"; return &a; } Here how to print Hello using printf("%s",cc);

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  • replace new lines with comas in shell

    - by mpapis
    I want to replace new lines in text with coma or space but do not change the last new line. I know of this question: How to replace new lines with tab characters - but it does produce an tab on end instead of new line. So far I have come with: awk 'NR>1{printf","} {printf $1} END{printf"\n"}' Is there an easier way to do this? This is not an assignment, I am just curious want to level up my scripting.

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  • Difference between the address space of parent process and its child process in Linux?

    - by abbas1707
    Hi, I am confused about it. I have read that when a child is created by a parent process, child gets a copy of its parent's address space. What it means here by copy? If i use code below, then it prints same addresses of variable 'a' which is on heap in all cases. i.e in case of child and parent. So what is happening here? #include <sys/types.h> #include <stdio.h> #include <unistd.h> #include <stdlib.h> int main () { pid_t pid; int *a = (int *)malloc(4); printf ("heap pointer %p\n", a); pid = fork(); if (pid < 0) { fprintf (stderr, "Fork Failed"); exit(-1); } else if (pid == 0) { printf ("Child\n"); printf ("in child heap pointer %p\n", a); } else { wait (NULL); printf ("Child Complete\n"); printf ("in parent heap pointer %p\n", a); exit(0); } }

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  • C: Comparing two long integers (very strange)

    - by Kyle
    Hi, I have following situation (unix) : x is a long and has value 300 y is a long and has value 50000 if (x <= y) printf("Correct."); if (x > y) printf("Ouch."); Now I always get "Ouch". That means the program keeps telling me that 300 is greater than 50000! It only works again when I do if ((int)x <=(int) y) printf("Correct."); if ((int)x > (int)y) printf("Ouch."); So what is wrong with the comparison operators?

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