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Search found 1848 results on 74 pages for 'printf'.

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  • Unsigned long with negative value

    - by egiakoum1984
    Please see the simple code below: #include <iostream> #include <stdlib.h> using namespace std; int main(void) { unsigned long currentTrafficTypeValueDec; long input; input=63; currentTrafficTypeValueDec = (unsigned long) 1LL << input; cout << currentTrafficTypeValueDec << endl; printf("%u \n", currentTrafficTypeValueDec); printf("%ld \n", currentTrafficTypeValueDec); return 0; } Why printf() displays the currentTrafficTypeValueDec (unsigned long) with negative value? The output is: 9223372036854775808 0 -9223372036854775808

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  • #pragma directive and its uses in c

    - by sandy101
    Hello , can anyone tell my what does the #pragma can do in the c language . what are its uses and why the above program is not giving the output 'inside v1'& 'inside v2' in the following program ... include void v1(); void v2(); pragma startup v1 pragma exit v2 int main() { printf("inside main\n"); return 0; } void v1() { printf("inside v1\n"); } void v2() { printf("inside v2\n"); } i also want to know what a are the uses of the #pragma directive .... plz help

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  • running a program in Unix vs in Windows

    - by Hristo
    I'm compiling a simple program written in C and I'm using Eclipse as an IDE, both in Windows 7 and on my MacBook Pro. Very simple program my friend wrote and asked me to help him with: int a = 0; char b[2]; printf("Input first class info:\n"); printf("Credit Hours: \n"); scanf("%d", &a); printf("Letter Grade: "); scanf("%s", b); So when I run this on my mac, each line prints and when I encounter the scanf(), I can input and continue as expected. In Windows, I have to input everything and then it will print all the lines. I'm not sure why this is happening... what is the difference b/w Windows and Mac here? Mac: Input first class info: Credit Hours: 4 Letter Grade: B+ Windows: 4 B+ Input first class info: Credit Hours: Letter Grade: Thanks, Hristo

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  • remote function with pthread

    - by user311130
    Hi all, I wrote some code in c, using pthread (I configured the linker and compiler in eclipse IDE first). #include <pthread.h> #include "starter.h" #include "UI.h" Page* MM; Page* Disk; PCB* all_pcb_array; void* display_prompt(void *id){ printf("Hello111\n"); return NULL; } int main(int argc, char** argv) { printf("Hello\n"); pthread_t *thread = (pthread_t*) malloc (sizeof(pthread_t)); pthread_create(thread, NULL, display_prompt, NULL); printf("Hello\n"); return 1; } that works fine. However, when I move display_prompt to UI.h no "Hello111 " output is printed. anyone know how to solve that? Elad

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  • C Check Substring of a String C

    - by user69514
    I'm trying to check whether or not the second argument in my program is a substring of the first argument. The problem is that it only work if the substring starts with the same letter of the string. EDIT: It must be done in C, not C++. Sorry #include <stdio.h> #include <string.h> int my_strstr( char const *s, char const *sub ) { char const *ret = sub; while ( ret = strchr( ret, *sub ) ) { if ( strcmp( ++ret, sub+1 ) == 0 ) return 1; } return 0; } int main(int argc, char **argv){ if (argc != 3) { printf ("Usage: check <string one> <string two>\n"); } int result = my_strstr(argv[1], argv[2]); if(result == 1){ printf("%s is a substring of %s\n", argv[2], argv[1]); } else{ printf("%s is not a substring of %s\n", argv[2], argv[1]); } return 0; }

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  • Forked Function not assigning pointer

    - by Luke Mcneice
    In the code below I have a function int GetTempString(char Query[]); calling it in main works fine. However, when calling the function from a fork the fork hangs (stops running, no errors, no output) before this line: pch = strtok (Query," ,"); the printf shows that the pointer to pch is null. Again this only happens when the fork is executing it. What am I doing doing wrong? int main() { if((Timer =fork())==-1) printf("Timer Fork Failed"); else if(Timer==0) { while(1) { sleep(2); GetTempString("ch 1,2,3,4"); } } else { //CODE GetTempString("ch 1,2,3,4"); } } int GetTempString(char Query[]) { char * pch; printf("DEBUG: '%s'-'%d'\n",Query,pch); pch = strtok (Query," ,");//* PROBLEM HERE* //while loop for strtok... return 1; }

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  • Unknown symbols when I read file

    - by Sergey Gavruk
    I read file, but in the end of file i get unknown symbols: int main() { char *buffer, ch; int i = 0, size; FILE *fp = fopen("file.txt", "r"); if(!fp){ printf("File not found!\n"); exit(1); } fseek(fp, 0, SEEK_END); size = ftell(fp); printf("%d\n", size); fseek(fp, 0, SEEK_SET); buffer = malloc(size * sizeof(*buffer)); while(((ch = fgetc(fp)) != NULL) && (i <= size)){ buffer[i++] = ch; } printf(buffer); fclose(fp); free(buffer); getch(); return 0; }

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  • Why my print current date time (C language) gives different answer

    - by vodkhang
    I want to get the current date (day, mon and year). I found out there are some functions in C to do that like ctime (get the string of time), localtime and gmtime. I tried with following code but the output are different. I get this output: The date and time is Tue Apr 20 2010 (which is correct) The year is : 110 The year is : 110. Does anybody know why? int main(int argc, char** argv) { time_t now; if((now = time(NULL)) == (time_t)-1) { puts("Failure in getting time"); } else { printf("The date and time is: %s\n", ctime(&now)); printf("The year is: %ld\n", localtime(&now)->tm_year); printf("The year is: %ld\n", gmtime(&now)->tm_year); } getchar(); }

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  • Printing the address of a struct object

    - by bdhar
    I have a struct like this typedef struct _somestruct { int a; int b; }SOMESTRUCT,*LPSOMESTRUCT; I am creating an object for the struct and trying to print it's address like this int main() { LPSOMESTRUCT val = (LPSOMESTRUCT)malloc(sizeof(SOMESTRUCT)); printf("0%x\n", val); return 0; } ..and I get this warning warning C4313: 'printf' : '%x' in format string conflicts with argument 1 of type 'LPSOMESTRUCT' So, I tried to cast the address to int like this printf("0%x\n", static_cast<int>(val)); But I get this error: error C2440: 'static_cast' : cannot convert from 'LPSOMESTRUCT' to 'int' What am I missing here? How to avoid this warning? Thanks.

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  • checking whether 4 points in a plane define a square ??

    - by osabri
    how to check whether 4 points in the plane define a square? what's the function which given a point and a value of the area of a square as input parameters returns four squares(define a corresponding type) with sides parallel to the x axis and y axis this how i start: #include <stdio.h> #include<math.h> struct point{ float x; float y; } typedef struct point POINT; struct square{ struct point p1; struct point p2; struct point p3; struct point p4; } typedef struct square SQUARE; int main() { int point; printf("point coordinate"); printf("\n\n"); printf("enter data\n");

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  • When should an array name be treated as a pointer and when does it just represent the array itself? [duplicate]

    - by user1087373
    This question already has an answer here: When is an array name or a function name 'converted' into a pointer ? (in C) 4 answers I just made a test program after reading the book and the result turned out confusing: #include <stdio.h> int main(void) { char text[] = "hello!"; printf("sizeof(text):%d sizeof(text+2):%d sizeof(text[0]):%d \n",(int)sizeof(text), sizeof(text+2), sizeof(text[0])); printf("text:%p sizeof(text):%d &text:%p sizeof(&text):%d \n",text, sizeof(text), &text, sizeof(&text)); printf("text+1:%p &text+1:%p \n", text+1, &text+1); return 0; } The result: sizeof(text):7 sizeof(text+2):4 sizeof(text[0]):1 text:0xbfc8769d sizeof(text):7 &text:0xbfc8769d sizeof(&text):4 text+1:0xbfc8769e &text+1:0xbfc876a4 What makes me feel confused are: why the value of 'sizeof(text)' is 7 whereas 'sizeof(text+2)' is 4 what's the difference between 'text' and '&text'?

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  • How does this iterative Tower of Hanoi work? C

    - by Nitesh Panchal
    Hello, while surfing google, i found this interesting solution to Tower Of Hanoi which doesn't even use stack. Can anybody explain me in brief, what is it actually doing? And this solution really acceptable? #include <stdio.h> #include <stdlib.h> int main() { int n, x; printf( "How many disks? " ); scanf( "%d", &n ); printf("\n"); for (x=1; x < (1 << n); x++) printf( "move from tower %i to tower %i.\n", (x&x-1)%3, ((x|x-1)+1)%3 ); return 0; }

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  • Question about variable definitions in functions.

    - by Kaan Tekelioglu
    Hi. #include <stdio.h> main() { int a; for(a=1; a<=4 && printf("%d ",a); a++) { int a; static int b=a; printf("%d ",(a++)-b); } getchar(); getchar(); } In this code, the printout is 1 0 2 1 3 2 4 3. I understand why the int a; part works differently then the int a which was defined outside the for function, and why static int b; is only defined once with the primary value of a ; but why does the (a++) part in printf affect proceeding values of a? Don't we redefine int a; each time the for function runs? Thanks in advance.

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  • reading a file that doesn't exist

    - by John
    Hi, I have got a small program that prints the contents of files using the system call - read. unsigned char buffer[8]; size_t offset=0; size_t bytes_read; int i; int fd = open(argv[1], O_RDONLY); do{ bytes_read = read(fd, buffer, sizeof(buffer)); printf("0x%06x : ", offset); for(i=0; i<bytes_read; ++i) { printf("%c ", buffer[i]); } printf("\n"); offset = offset + bytes_read; }while(bytes_read == sizeof(buffer)); Now while running I give a file name that doesn't exist. It prints some kind of data mixed with environment variables and a segmentation fault at the end. How is this possible? What is the program printing? Thanks, John

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  • Help with output generated by this C code using fork()

    - by Seephor
    I am trying to figure out the output for a block of C code using fork() and I am having some problems understanding why it comes out the way it does. I understand that when using fork() it starts another instance of the program in parallel and that the child instance will return 0. Could someone explain step by step the output to the block of code below? Thank you. main() { int status, i; for (i=0; i<2; ++i){ printf("At the top of pass %d\n", i); if (fork() == 0){ printf("this is a child, i=%d\n", i); } else { wait(&status); printf("This is a parent, i=%d\n", i); } } }

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  • Transferring data from 2d Dynamic array in C to CUDA and back

    - by Soumya
    I have a dynamically declared 2D array in my C program, the contents of which I want to transfer to a CUDA kernel for further processing. Once processed, I want to populate the dynamically declared 2D array in my C code with the CUDA processed data. I am able to do this with static 2D C arrays but not with dynamically declared C arrays. Any inputs would be welcome! I mean the dynamic array of dynamic arrays. The test code that I have written is as below. #include "cuda_runtime.h" #include "device_launch_parameters.h" #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> const int nItt = 10; const int nP = 5; __device__ int d_nItt = 10; __device__ int d_nP = 5; __global__ void arr_chk(float *d_x_k, float *d_w_k, int row_num) { int index = (blockIdx.x * blockDim.x) + threadIdx.x; int index1 = (row_num * d_nP) + index; if ( (index1 >= row_num * d_nP) && (index1 < ((row_num +1)*d_nP))) //Modifying only one row data pertaining to one particular iteration { d_x_k[index1] = row_num * d_nP; d_w_k[index1] = index; } } float **mat_create2(int r, int c) { float **dynamicArray; dynamicArray = (float **) malloc (sizeof (float)*r); for(int i=0; i<r; i++) { dynamicArray[i] = (float *) malloc (sizeof (float)*c); for(int j= 0; j<c;j++) { dynamicArray[i][j] = 0; } } return dynamicArray; } /* Freeing memory - here only number of rows are passed*/ void cleanup2d(float **mat_arr, int x) { int i; for(i=0; i<x; i++) { free(mat_arr[i]); } free(mat_arr); } int main() { //float w_k[nItt][nP]; //Static array declaration - works! //float x_k[nItt][nP]; // if I uncomment this dynamic declaration and comment the static one, it does not work..... float **w_k = mat_create2(nItt,nP); float **x_k = mat_create2(nItt,nP); float *d_w_k, *d_x_k; // Device variables for w_k and x_k int nblocks, blocksize, nthreads; for(int i=0;i<nItt;i++) { for(int j=0;j<nP;j++) { x_k[i][j] = (nP*i); w_k[i][j] = j; } } for(int i=0;i<nItt;i++) { for(int j=0;j<nP;j++) { printf("x_k[%d][%d] = %f\t",i,j,x_k[i][j]); printf("w_k[%d][%d] = %f\n",i,j,w_k[i][j]); } } int size1 = nItt * nP * sizeof(float); printf("\nThe array size in memory bytes is: %d\n",size1); cudaMalloc( (void**)&d_x_k, size1 ); cudaMalloc( (void**)&d_w_k, size1 ); if((nP*nItt)<32) { blocksize = nP*nItt; nblocks = 1; } else { blocksize = 32; // Defines the number of threads running per block. Taken equal to warp size nthreads = blocksize; nblocks = ceil(float(nP*nItt) / nthreads); // Calculated total number of blocks thus required } for(int i = 0; i< nItt; i++) { cudaMemcpy( d_x_k, x_k, size1,cudaMemcpyHostToDevice ); //copy of x_k to device cudaMemcpy( d_w_k, w_k, size1,cudaMemcpyHostToDevice ); //copy of w_k to device arr_chk<<<nblocks, blocksize>>>(d_x_k,d_w_k,i); cudaMemcpy( x_k, d_x_k, size1, cudaMemcpyDeviceToHost ); cudaMemcpy( w_k, d_w_k, size1, cudaMemcpyDeviceToHost ); } printf("\nVerification after return from gpu\n"); for(int i = 0; i<nItt; i++) { for(int j=0;j<nP;j++) { printf("x_k[%d][%d] = %f\t",i,j,x_k[i][j]); printf("w_k[%d][%d] = %f\n",i,j,w_k[i][j]); } } cudaFree( d_x_k ); cudaFree( d_w_k ); cleanup2d(x_k,nItt); cleanup2d(w_k,nItt); getch(); return 0;

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  • Write a function int mystrlen(char *s) that returns the number of characters in a string wuthout str

    - by henry
    heres what i did, i just have ne error that i cant figure out. int mystrlen(char string[]) { char string1[LENGHT], string2[LENGHT]; int len1, len2; char newstring[LENGHT*2]; printf("enter first string:\n"); len1 = mystrlen(string1); printf("enter second string:\n"); len2 = mystrlen(string2); if(len1 == EOF || len2 == EOF) exit(1); strcpy(newstring, string1); strcat(newstring, string2); printf("%s\n", newstring); return 0;

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  • Memory error, access violation.

    - by Ordo
    Hello! I'm learning C on my own and as a exercise i have written a program but it does not work. The program is splitted into 3 parts. A header file, a main file for executing the program a file to define the functions. I'm not using all the functions yet but that shouldn't be the problem. Here is my header file, nothing special in it. #ifndef EMPLOYEE_H #define EMPLOYEE_H struct Employee { char first[21]; char last[21]; char title[21]; int salary; }; struct Employee* createEmployee(char*, char*, char*, int); // Creates a struct Employee object on the heap. char* getfirstname (struct Employee*); char* getlastname (struct Employee*); char* gettitle (struct Employee*); int getsalary (struct Employee*); void setfirstname (struct Employee*, char*); void setlastname (struct Employee*, char*); void settitle (struct Employee*, char*); void setsalary (struct Employee*, int); void printEmployee(struct Employee*); #endif In this file i define the functions and how they work: #include "7.1.h" #include <stdio.h> #include <stdlib.h> #include <string.h> struct Employee* createEmployee(char* first, char* last, char* title, int salary) // Creates a struct Employee object on the heap. { struct Employee* p = (struct Employee*) malloc(sizeof(struct Employee)); if (p != NULL) { strcpy(p->first, first); strcpy(p->last, last); strcpy(p->title, title); p->salary, salary; } return p; } char* getfirstname (struct Employee* p) { if (p != NULL) return p ? p->first : ""; } char* getlastname (struct Employee* p) { if (p != NULL) return p ? p->last : ""; } char* gettitle (struct Employee* p) { if (p != NULL) return p ? p->title : ""; } int getsalary (struct Employee* p) { if (p != NULL) return p ? p->salary : 0; } void setfirstname (struct Employee* p, char* first) { if (p != NULL) strcpy(p->first, first); } void setlastname (struct Employee* p, char* last) { if (p != NULL) strcpy(p->last, last); } void settitle (struct Employee* p, char* title) { if (p != NULL) strcpy(p->title, title); } void setsalary (struct Employee* p, char* salary) { if (p != NULL) p->salary, salary; } void printEmployee(struct Employee* p) { if (p != NULL) { printf("%s, %s, %s, %d", p->first, p->last, p->salary, p->salary ); } } And the last file is used to executed the program/functions: #include "7.1.h" #include <stdio.h> #include <stdlib.h> int main () { char decision; struct Employee emp; struct Employee* emps[3]; for ( int i = 0; i < 1; i ++) { printf("Please type in the emplooyes data.\nFirstname:"); scanf("%s", emp.first); printf("Lastname:"); scanf("%s", emp.last); printf("Title:"); scanf("%s", emp.title); printf("Salary:"); scanf("%d", &emp.salary); emps[i] = createEmployee(emp.first, emp.last, emp.title, emp.salary); } printf("Do you want to print out your information? (Y/N):"); scanf("%c", &decision); if (decision == 'y' || decision == 'Y') { printEmployee(emps[1]); } } I don't know what the problem is. I 'm always getting the following error message after typing in first, last, title and salary for the first time. The error is written in german. It means: Unhandled exception at 0x102de42e (msvcr100d.dll) in 7.1.exe: 0xC0000005: Access violation when writing to 0xCCCCCCCC position. I could fix the first problem with the hints given below. Now when i want to print out the employee data using the function:printEmployee(emps[1]);, I get the same kind of error with access violation.

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  • strcat() won't exit

    - by Tristan Sebens
    I'm trying to implement a very basic server in C, one part of which is constructing HTTP headers. To do this I have written a class called header_builder, which basically constructs the headers for me. One of the most basic methods of this class is append_header_line, shown below: void append_header_line( const char *line, char *hdr ) { printf("Adding header line\n"); strcat( hdr, line ); printf("Line added. Adding ending.\n"); strcat( hdr, "\r\n" ); printf("Success\n"); } All it's supposed to do is tack the "line" parameter onto the end of the "hdr" parameter, and then add "\r\n" to the end of it all. The problem is that the first strcat call never exits. When I run this code, all it does is say: Adding header line Which means that the following lines never execute, and I can't figure out why. Any thoughts?

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  • Why PHP (script) serves more requests than CGI (compiled)?

    - by Lucas Batistussi
    I developed the following CGI script and run on Apache 2 (http://localhost/test.chtml). I did same script in PHP (http://localhost/verifica.php). Later I performed Apache benchmark using Apache Benchmark tool. The results are showed in images. include #include <stdlib.h> int main(void) { printf("%s%c%c\n", "Content-Type:text/html;charset=iso-8859-1",13,10); printf("<TITLE>Multiplication results</TITLE>\n"); printf("<H3>Multiplication results</H3>\n"); return 0; } Someone can explain me why PHP serves more requests than CGI script?

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  • How could my code compliled correctly without necessary headers?

    - by ZhengZhiren
    I use the functions fork(),exec()... But how can this program compiled without including some extra headers(like sys/types.h, sys/wait.h). I use ubuntu 10.04 with gcc version 4.4.3 #include <stdio.h> #include <stdlib.h> int main() { pid_t pid; printf("before fork\n"); pid = fork(); if(pid == 0) { /*child*/ if(execvp("./cpuid", NULL)) { printf("error\n"); exit(0); } } else { if(wait(NULL) != -1) { printf("ok\n"); } } return 0; }

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  • collect string in loop and printout all the string outside loop

    - by user1508163
    I'm newbie here and there is some question that I want have some lesson from you guys. For example: #include <stdio.h> #include<stdlib.h> #include<ctype.h> void main() { char name[51],selection; do { printf("Enter name: "); fflush(stdin); gets(name); printf("Enter another name?(Y/N)"); scanf("%c",&selection); selection=toupper(selection); }while (selection=='Y'); //I want to printout the entered name here but dunno the coding printf("END\n"); system("pause"); } As I know when the loops perform will overwrite the variable then how I perform a coding that will printout all the name user entered? I have already ask my tutor and he is ask me to use pointer, can anyone guide me in this case?

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  • how to make this piece of code work in C++?

    - by cambr
    #include<stdio.h> void print(int *arr[], int s1, int s2) { int i, j; printf("\n"); for(i = 0; i<s1; i++) { for(j = 0; j<s2; j++) { printf("%d, ", *((arr+i)+j)); } } printf("\n"); } int main() { int a[4][4] = {{0}}; print(a,4,4); } This works in C, but not in C++. error: cannot convert `int (*)[4]' to `int**' for argument `1' to `void print(int**, int, int)' Why does it not work in C++? What change is needed to be made?

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  • C++ - Creating folder method

    - by Matthew
    I have the following method in C++: void create_folder(LPCWSTR full_folder) //Method to create folder in case it does not exist { if(!CreateDirectory(full_folder,attr)) //Checking whether the folder already exists { switch (GetLastError()) { case ERROR_ALREADY_EXISTS: printf("The folder already exists!\n\n"); break; case NULL: printf("The folder does not exist!\n\n"); printf("The folder was created successfully!\n\n"); break; } } } In case the folder already exists, the correct message is displayed on the screen. However, if the folder does NOT exist, nothing is displayed on the screen, that is, the part identified by case NULL is not executed. How can I solve this problem? In other words, how can I get the code after the case NULL to run if the folder does not exist?

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