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• Oracle Linked Servers on Windows Server 2008 R2

  - by John Paul Cook

  Oracle hasn’t yet released versions of its client software for Windows Server 2008 R2. If you need to create an Oracle linked server, that’s a problem. You’ll see this installation block when attempting to install the Oracle client software for Windows Server 2008: It’s very simple to fix. Check the first checkbox to make the installer ignore the version check. Click Next and ignore the warning you’ll see. The installation should complete successfully. Windows does offer various strategies for mitigating...(read more)

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• How to display a dependent list box disabled if no child data exist

  - by frank.nimphius

  A requirement on OTN was to disable the dependent list box of a model driven list of value configuration whenever the list is empty. To disable the dependent list, the af:selectOneChoice component needs to be refreshed with every value change of the parent list, which however already is the case as the list boxes are already dependent. When you create model driven list of values as choice lists in an ADF Faces page, two ADF list bindings are implicitly created in the PageDef file of the page that hosts the input form. At runtime, a list binding is an instance of FacesCtrlListBinding, which exposes getItems() as a method to access a list of available child data (java.util.List). Using Expression Language, the list is accessible with #{bindings.list_attribute_name.items} To dynamically set the disabled property on the dependent af:selectOneChoice component, however, you need a managed bean that exposes the following two methods //empty – but required – setter method public void setIsEmpty(boolean isEmpty) {} //the method that returns true/false when the list is empty or //has values public boolean isIsEmpty() {   FacesContext fctx = FacesContext.getCurrentInstance();   ELContext elctx = fctx.getELContext();   ExpressionFactory exprFactory =                          fctx.getApplication().getExpressionFactory();   ValueExpression vexpr =                       exprFactory.createValueExpression(elctx,                         "#{bindings.EmployeeId.items}",                       Object.class);   List employeesList = (List) vexpr.getValue(elctx);                        return employeesList.isEmpty()? true : false;      } If referenced from the dependent choice list, as shown below, the list is disabled whenever it contains no list data <! --  master list --> <af:selectOneChoice value="#{bindings.DepartmentId.inputValue}"                                  label="#{bindings.DepartmentId.label}"                                  required="#{bindings.DepartmentId.hints.mandatory}"                                   shortDesc="#{bindings.DepartmentId.hints.tooltip}"                                   id="soc1" autoSubmit="true">      <f:selectItems value="#{bindings.DepartmentId.items}" id="si1"/> </af:selectOneChoice> <! --  dependent  list --> <af:selectOneChoice value="#{bindings.EmployeeId.inputValue}"                                   label="#{bindings.EmployeeId.label}"                                      required="#{bindings.EmployeeId.hints.mandatory}"                                   shortDesc="#{bindings.EmployeeId.hints.tooltip}"                                   id="soc2" disabled="#{lovTestbean.isEmpty}"                                   partialTriggers="soc1">     <f:selectItems value="#{bindings.EmployeeId.items}" id="si2"/> </af:selectOneChoice>

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• Why is a linked list implementation considered linear?

  - by VeeKay

  My apologies for asking such a simple question. Instead of posting such basic question in SO, I felt that this is more apt a question here. I tried finding an answer for this but none of them are logically appealing or convincing to my understanding. Typically, computer memory is always linear. So is the term non linear used for a data structure in a logical sense? If so, to logically achieve non linearity in a linear computer memory, we use pointers. Right? In that case, if pointers are virtual implementations for achieving non linearity, Why would a data structure like linked list be considered linear if in reality the nodes are never physically adjacent?

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• SUN Java and GPL V2 licence issue for linked applications

  - by user255607

  I have recently noticed that the Sun Java code has been released as GPL V2 code (see Google code repo). Does that mean that all applications written in Java and linked to Sun APIs (beans, and so on) are also in GPL ? If we strictly follow the GPL then this should be the case (Libs should be in LGPL, not GPL if we want to build proprietary software on top of it). Is there another commercial licence which can avoid such an issue ? I cannot believe this is the case. There must be an explanation on this. Regards, Apple92

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• How can I generate a list of appendices with LaTeX, seperate from table of contents (toc)

  - by None

  LaTeX' appendix environment formats sections differently and uses a different enumeration in the table of contents: \begin{appendix} \section{superuser} \dots{} .... Shows up as       A       superuser            11 in the \tableofcontents. Unfortunately, I have to use a different style: the appendix is not to show up in the table of contents, but in a seperate listing right before the appendix. I see the following options to solve this: suppress output in tableofcontents and somehow recreate the part on a different page generate a custom listing of specified / the following section manually create a list with the same formatting of the tableofcontents I use scrartcl as document class. PS: appedix / appendices is not a tag yet

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• Bad search result due to strange linked domains

  - by VDesign

  I have a website which is not scoring good in Google's search results. I use Majestic SEO and Open Site Explorer in order to have a view about my link profile. I now see different backlink domains, some of them already removed, that contains sexual content or other non relative content linking to my domain. How much influence does these strange linked domains have on my search result? Even if some of them are already removed for a couple of months. I have already disavow open sexual domains using the tool that Google provides.

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• C++ linked list based tree structure. Sanely copy nodes between lists.

  - by krunk

  edit Clafification: The intention is not to remove the node from the original list. But to create an identical node (data and children wise) to the original and insert that into the new list. In other words, a "move" does not imply a "remove" from the original. endedit The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

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• Problem with implementing removeAll for List of custom object

  - by Jay

  Hello everyone, I have a scenario in my code where I need to compare two Lists and remove from the first list, objects which are present in the second list. Akin to how the "removeAll" object works for List. Since my List is created on a custom object, the removeAll method won't work for me. I have tried various methods to make this work: - implemented equals() and hashCode for the custom object comprising the list - implemented the Comparable Interface for the custom object - implemented the Comparator Interface for the custom object I've even tried using the Apache Common's CollectionUtils and ListUtils methods (subtract, intersect, removeAll). None seem to work. I understand I will perhaps need to write some custom removal code. But not sure how to go about doing that. Any pointers helping me move in the right direction will be really appreciated. Thanks, Jay

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• Array Vs. Linked List

  - by Onorio Catenacci

  I apologize--this question may be a bit open-ended but I think there are probably definite, quantifiable answers to it so I'll post it anyway. A person I know is trying to learn C++ and software development (+1 to him) and he asked me why someone would want to use a linked list in preference to an array. Coding a linked list is, no doubt, a bit more work than using an array and he wondered what would justify the additional effort. I gave him the answer I know: insertion of new elements is trivial in linked list but it's a major chore in an array. But then I got to thinking about it a bit more. Besides the ease of insertion of a new element into a linked list are there other advantages to using a linked list to store a set of data vs. storing it in an array? As I said, I'm not meaning to start a long and drawn-out discussion. I'm just looking for other reasons that a developer might prefer a linked list to an array.

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• Convert a List of Options to an Option of List using Scalaz

  - by Rafael de F. Ferreira

  The following function transforms a list of Option[T] into a list of Some[T], in the case where all members are Some's, or None, in the case where there is at least one None member. I guess the code is clearer that this explanation: def lo2ol[T](lo: List[Option[T]]): Option[List[T]] = { lo.foldRight[Option[List[T]]](Some(Nil)){(o, ol) => (o, ol) match { case (Some(x), Some(xs)) => Some(x :: xs); case _ => None : Option[List[T]]; }}} I remember seeing somewhere a similar example, but using Scalaz to simplify the code. How would it look like?

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• converting a matrix to a list

  - by andrewj

  Suppose I have a matrix foo as follows: foo <- cbind(c(1,2,3), c(15,16,17)) > foo [,1] [,2] [1,] 1 15 [2,] 2 16 [3,] 3 17 I'd like to turn it into a list that looks like [[1]] [1] 1 15 [[2]] [1] 2 16 [[3]] [1] 3 17 You can do it as follows: lapply(apply(foo, 1, function(x) list(c(x[1], x[2]))), function(y) unlist(y)) I'm interested in an alternative method that isn't as complicated. Note, if you just do apply(foo, 1, function(x) list(c(x[1], x[2]))), it returns a list within a list, which I'm hoping to avoid.

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• sharepoint list relationship question

  - by Korey

  I have two custom lists in sharepoint with a one to many relationship on a column in both lists. So list A has text column 1 and list B has a lookup column 1' on list A's column 1. I want to display the rows in list A, where column 1 has a match on column 1' and a 2nd column in list B with a specific text string. I have Sharepoint Designer and am fumbling along with linked sources described here http://office.microsoft.com/en-us/sharepointdesigner/HA100991441033.aspx, but can't get exactly what I'm looking for.

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• Upgrading a SharePoint list instance that was deployed via feature

  - by Goldmember

  I'm curious how others address this issue. Using VSEWSS 1.3, I have created a site content type, a list definition (w event receivers), and a list instance. All of them are in the same WSP solution and each is activated individually via features. Now let's assume that all the features have been activated for some time, and the list instance contains a number of items (that can't be deleted). Now suppose I need to make a change to the schema.xml (inject some javascript, modify views, whatever) of the list. Is it even possible to "upgrade" the schema of the existing list instance? Otherwise I would think I'm stuck creating a new instance and copying items over.

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• Fill a array with List data with one more element

  - by marionmaiden

  Hello, By a question that I made, I figured out that tho copy elements from one list to an array I just need to use the method toArray() for this. But let's suppose I have a List with n objects. I want to copy then into a array sized n+1 and add into the first position another object and in the other n positions the n data of the list. This is the way I'm doing it for now, but I'm just wondering if there is a better way for do that: Object array[] = new Object[list.size() + 1]; Object chk = new Object(); array[0] = chk; for(int i = 1; i < array.length; i++){ array[i] = list.get(i); }

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• just-in-time list

  - by intuited

  I'd like to know if there is a class available, either in the standard library or in pypi, that fits this description. The constructor would take an iterator. It would implement the container protocol (ie _getitem_, _len_, etc), so that slices, length, etc., would work. In doing so, it would iterate and retain just enough values from its constructor argument to provide whatever information was requested. So if jitlist[6] was requested, it would call self.source.next() 7 times, save those elements in its list, and return the last one. This would allow downstream code to use it as a list, but avoid unnecessarily instantiating a list for cases where list functionality was not needed, and avoid allocating memory for the entire list if only a few members ended up being requested. It seems like a pretty easy one to write, but it also seems useful enough that it's likely that someone would have already made it available in a module.

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• Python: Repeat elements in a list comprehension?

  - by User

  I have the following list comprehension which returns a list of coordinate objects for each location. coordinate_list = [Coordinates(location.latitude, location.longitude) for location in locations] This works. Now suppose the location object has a number_of_times member. I want a list comprehension to generate n Coordinate objects where n is the number_of_times for the particular location. So if a location has number_of_times = 5 then the coordinates for that location will be repeated 5 times in the list. (Maybe this is a case for a for-loop but I'm curious if it can be done via list comprehensions)

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• python conditional list creation from 2D lists

  - by dls

  Say I've got a list of lists. Say the inner list of three elements in size and looks like this: ['apple', 'fruit', 1.23] The outer list looks like this data = [['apple', 'fruit', 1.23], ['pear', 'fruit', 2.34], ['lettuce', 'vegetable', 3.45]] I want to iterate through the outer list and cull data for a temporary list only in the case that element 1 matches some keyword (aka: 'fruit'). So, if I'm matching fruit, I would end up with this: tempList = [('apple', 1.23), ('pear', 2.34)] This is one way to accomplish this: tempList = [] for i in data: if i[1] == 'fruit': tempList.append(i[0], i[2]) is there some 'Pythonic' way to do this in fewer lines?

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• Fastest way to check a List<T> for a date

  - by fishhead

  I have a list of dates that a machine has worked on, but it doesn't include a date that machine was down. I need to create a list of days worked and not worked. I am not sure of the best way to do this. I have started by incrementing through all the days of a range and checking to see if the date is in the list by iterating through the entire list each time. I am looking for a more efficient means of finding the dates. class machineday { datetime WorkingDay; } class machinedaycollection : List<machineday> { }

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• Display/Hide part of a list

  - by superexsl

  Hi I have an (unordered)list (generated by a repeater) of items. However, I'd like to show the first three items, and have the rest hidden by the main content div. When a button is pressed, I would like the list's div to expand, pushing the main content div down and showing the rest of the list. I was thinking of using slideDown(), but that closes the entire div ( and I would like to show the first 3 items of the list). What would be the best way to achieve an effect like this? Is there a plugin that can easily show X items of a list and the display the rest upon request? Thanks

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• Best way to implement a List(Of) with a maximum number of items

  - by Ben

  I'm trying to figure out a good way of implementing a List(Of) that holds a maximum number of records. e.g. I have a List(Of Int32) - it's being populated every 2 seconds with a new Int32 item. I want to store only the most current 2000 items. How can I make the list hold a maximum of 2000 items, then when the 2001'th item is attempted to be added, the List drops the 2000'th item (resulting in the current total being 1999). Thing is, I need to make sure I'm dropping only the oldest item and adding a new item into the List. Ben

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• Using a Loop to add objects to a list(python)

  - by Will

  Hey guys so im trying to use a while loop to add objects to a list. Heres bascially what i want to do: (ill paste actually go after) class x: blah blah choice = raw_input(pick what you want to do) while(choice!=0): if(choice==1): Enter in info for the class: append object to list (A) if(choice==2): print out length of list(A) if(choice==0): break ((((other options)))) as im doing this i can get the object to get added to the list, but i am stuck as to how to add multiple objects to the list in the loop. Here is my actual code i have so far... print "Welcome to the Student Management Program" class Student: def init (self, name, age, gender, favclass): self.name = name self.age = age self.gender = gender self.fac = favclass choice = int(raw_input("Make a Choice: " )) while (choice !=0): if (guess==1): print("STUDENT") namer = raw_input("Enter Name: ") ager = raw_input("Enter Age: ") sexer = raw_input("Enter Sex: ") faver = raw_input("Enter Fav: ") elif(guess==2): print "TESTING LINE" elif(guess==3): print(len(a)) guess=int(raw_input("Make a Choice: ")) s = Student(namer, ager, sexer, faver) a =[]; a.append(s) raw_input("Press enter to exit") any help would be greatly appreciated!

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• Trim email list into domain list

  - by hanjaya

  The function below is part of a script to trim email list from a file into domain list and removes duplicates. /* define a function that can accept a list of email addresses */ function getUniqueDomains($list) { // iterate over list, split addresses and add domain part to another array $domains = array(); foreach ($list as $l) { $arr = explode("@", $l); $domains[] = trim($arr[1]); } // remove duplicates and return return array_unique($domains); } What does $domains[] = trim($arr[1]); mean? Specifically the $arr[1]. What does [1] mean in this context? How come variable $arr becomes an array variable?

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• Java, searching within a list of objects?

  - by Rick

  I'm a bit lost on the way to make this happen the fastest. I have a large list of objects that have basic variable attributes (with getters / setters) and I need to do a search in this list to find the objects within the list that match a given parameter I have found how to do a regular list search but I need to, for example search for the value of the result of doing a call getName() for each object in the list and get objects that have a result that matches my input. Something like below where the third argument is the result of the method call and the second is what I am trying to find. int index = Collections.binarySearch(myList, "value", getName()); Any advice is appreciated

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• C++ Generic List Assignment

  - by S73417H

  I've clearly been stuck in Java land for too long... Is it possible to do the C++ equivalent of the following Java code: // Method List<Bar> getBars() { return new LinkedList<Bar>(); } // Assignment statement. List<Foo> stuff = getBars(); Where Foo is a sub-class of Bar. So in C++.... std::list<Bar> & getBars() { std::list<Bar> bars; return bars; } std::list<Foo> stuff = getBars(); Hope that makes sense....

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• Recursive insert-method for a linked list

  - by user3726477

  I'm learning C# and I've made a recursive insert-method for a linked list: public static int recursiveInsert(ref int value, ref MyLinkedList list) { if (list == null) return new MyLinkedList(value, null); else { list.next = recursiveInsert(ref int value, ref list.next); return list; } } How would you modify this method to make the recursive call look like this: recursiveInsert(value, ref list.next) instead of: list.next = recursiveInsert(ref int value, ref list.next);

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