Search Results

Search found 18648 results on 746 pages for 'left join'.

Page 142/746 | < Previous Page | 138 139 140 141 142 143 144 145 146 147 148 149  | Next Page >

  • Javascript stockticker : not showing data on php page

    - by developer
    iam not getting any javascript errors , code is getting rendered properly only, but still server not displaying data on the page. please check the code below . <style type="text/css"> #marqueeborder { color: #cccccc; background-color: #EEF3E2; font-family:"Lucida Console", Monaco, monospace; position:relative; height:20px; overflow:hidden; font-size: 0.7em; } #marqueecontent { position:absolute; left:0px; line-height:20px; white-space:nowrap; } .stockbox { margin:0 10px; } .stockbox a { color: #cccccc; text-decoration : underline; } </style> </head> <body> <div id="marqueeborder" onmouseover="pxptick=0" onmouseout="pxptick=scrollspeed"> <div id="marqueecontent"> <?php // Original script by Walter Heitman Jr, first published on http://techblog.shanock.com // List your stocks here, separated by commas, no spaces, in the order you want them displayed: $stocks = "idt,iye,mill,pwer,spy,f,msft,x,sbux,sne,ge,dow,t"; // Function to copy a stock quote CSV from Yahoo to the local cache. CSV contains symbol, price, and change function upsfile($stock) { copy("http://finance.yahoo.com/d/quotes.csv?s=$stock&f=sl1c1&e=.csv","stockcache/".$stock.".csv"); } foreach ( explode(",", $stocks) as $stock ) { // Where the stock quote info file should be... $local_file = "stockcache/".$stock.".csv"; // ...if it exists. If not, download it. if (!file_exists($local_file)) { upsfile($stock); } // Else,If it's out-of-date by 15 mins (900 seconds) or more, update it. elseif (filemtime($local_file) <= (time() - 900)) { upsfile($stock); } // Open the file, load our values into an array... $local_file = fopen ("stockcache/".$stock.".csv","r"); $stock_info = fgetcsv ($local_file, 1000, ","); // ...format, and output them. I made the symbols into links to Yahoo's stock pages. echo "<span class=\"stockbox\"><a href=\"http://finance.yahoo.com/q?s=".$stock_info[0]."\">".$stock_info[0]."</a> ".sprintf("%.2f",$stock_info[1])." <span style=\""; // Green prices for up, red for down if ($stock_info[2]>=0) { echo "color: #009900;\">&uarr;"; } elseif ($stock_info[2]<0) { echo "color: #ff0000;\">&darr;"; } echo sprintf("%.2f",abs($stock_info[2]))."</span></span>\n"; // Done! fclose($local_file); } ?> <span class="stockbox" style="font-size:0.6em">Quotes from <a href="http://finance.yahoo.com/">Yahoo Finance</a></span> </div> </div> </body> <script type="text/javascript"> // Original script by Walter Heitman Jr, first published on http://techblog.shanock.com // Set an initial scroll speed. This equates to the number of pixels shifted per tick var scrollspeed=2; var pxptick=scrollspeed; var marqueediv=''; var contentwidth=""; var marqueewidth = ""; function startmarquee(){ alert("hi"); // Make a shortcut referencing our div with the content we want to scroll marqueediv=document.getElementById("marqueecontent"); //alert("marqueediv"+marqueediv); alert("hi"+marqueediv.innerHTML); // Get the total width of our available scroll area marqueewidth=document.getElementById("marqueeborder").offsetWidth; alert("marqueewidth"+marqueewidth); // Get the width of the content we want to scroll contentwidth=marqueediv.offsetWidth; alert("contentwidth"+contentwidth); // Start the ticker at 50 milliseconds per tick, adjust this to suit your preferences // Be warned, setting this lower has heavy impact on client-side CPU usage. Be gentle. var lefttime=setInterval("scrollmarquee()",50); alert("lefttime"+lefttime); } function scrollmarquee(){ // Check position of the div, then shift it left by the set amount of pixels. if (parseInt(marqueediv.style.left)>(contentwidth*(-1))) marqueediv.style.left=parseInt(marqueediv.style.left)-pxptick+"px"; //alert("hikkk"+marqueediv.innerHTML);} // If it's at the end, move it back to the right. else{ alert("marqueewidth"+marqueewidth); marqueediv.style.left=parseInt(marqueewidth)+"px"; } } window.onload=startmarquee; </script> </html> Below is the server displayed page. I have updated with screenshot with your suggestion, i made change in html too, to check what is showing by child dev

    Read the article

  • Deletion procedure for a Binary Search Tree

    - by Metz
    Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

    Read the article

  • how to use multiple tab controls, and to be able to call a selected tab control with buttons.

    - by mojotaker
    Please I am trying to assign each button on the left its own Tab control. That is for example, when the Intake form button is pushed, it will have its own set of tabs (its own tabcontrols) am i supposed to place multiple tab controls on the artboard, or is there a way to programatically change the names of the tabs, and there contents, when a button is pushed on the left ? thank you in advance. and here is a link hxxp://img709.imageshack.us/img709/554/tabcontrol.gif here is the code so far <Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" x:Class="service.MainWindow" x:Name="Window" Title="MainWindow" Width="687" Height="480" mc:Ignorable="d"> <Window.Resources> <Storyboard x:Key="OnLoaded1"/> </Window.Resources> <Window.Triggers> <EventTrigger RoutedEvent="FrameworkElement.Loaded"> <BeginStoryboard Storyboard="{StaticResource OnLoaded1}"/> </EventTrigger> </Window.Triggers> <Grid x:Name="LayoutRoot" Margin="0,0,-16,1"> <Grid.ColumnDefinitions> <ColumnDefinition Width="0*"/> <ColumnDefinition/> </Grid.ColumnDefinitions> <DockPanel Margin="8,8,0,7" LastChildFill="False" Grid.Column="1" HorizontalAlignment="Left" Width="660"> <Menu VerticalAlignment="Top" Width="657" Height="32"> <MenuItem x:Name="file" Header="File"/> <MenuItem x:Name="edit" Header="Edit"> <MenuItem Width="100" Height="100" Header="MenuItem"/> </MenuItem> <MenuItem x:Name="view" Header="View"/> <MenuItem x:Name="preferences" Header="Preferences"/> <MenuItem x:Name="help" Header="Help"/> </Menu> </DockPanel> <TabControl x:Name="tabwin" Margin="137.224,46,19,7" Grid.Column="1"> <TabItem x:Name="intakeformsub" Header="Elegibility Form"> <Grid HorizontalAlignment="Left" Width="490"/> </TabItem> <TabItem Header="TabItem"> <Grid/> </TabItem> <TabItem Header="TabItem"> <Grid/> </TabItem> <TabItem Header="TabItem"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="0.567*"/> <ColumnDefinition Width="0.433*"/> </Grid.ColumnDefinitions> </Grid> </TabItem> <TabItem Header="TabItem"> <Grid/> </TabItem> <TabItem Header="TabItem"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="0.735*"/> <ColumnDefinition Width="0.265*"/> </Grid.ColumnDefinitions> </Grid> </TabItem> <TabItem Header="TabItem"> <Grid/> </TabItem> <TabItem Header="TabItem"> <Grid/> </TabItem> </TabControl> <Grid x:Name="___buttontab" Margin="11.205,61,0,0" Grid.Column="1" HorizontalAlignment="Left" Width="122.019" VerticalAlignment="Top" Height="276"> <Button VerticalAlignment="Top" Height="36" Content="Button"/> <Button Margin="0,40,0,0" Content="Oasis Assessments" VerticalAlignment="Top" Height="36"/> <Button Margin="0,80,0,0" VerticalAlignment="Top" Height="36" Content="Plan of Care"/> <Button Margin="0,120,0,0" VerticalAlignment="Top" Height="36" Content="Medication Profile" RenderTransformOrigin="0.421,5.556"/> <Button Margin="0,0,0,80" VerticalAlignment="Bottom" Height="36" Content="Clinical Notes"/> <Button Margin="0,0,0,40" VerticalAlignment="Bottom" Height="36" Content="Infection Control"/> <Button x:Name="intakeformbtn" VerticalAlignment="Top" Height="36" Content="Intake Form" Click="intakeform"> <Button.BindingGroup> <BindingGroup/> </Button.BindingGroup> </Button> <Button VerticalAlignment="Bottom" Height="36" Content="Discharge Summary"/> </Grid> <ProgressBar HorizontalAlignment="Left" Margin="8,0,0,7" VerticalAlignment="Bottom" Width="104.795" Height="19" Grid.Column="1"/> </Grid> </Window>

    Read the article

  • Fast rectangle to rectangle intersection

    - by Jeremy Rudd
    What's a fast way to test if 2 rectangles are intersecting? A search on the internet came up with this one-liner (WOOT!), but I don't understand how to write it in Javascript, it seems to be written in an ancient form of C++. struct { LONG left; LONG top; LONG right; LONG bottom; } RECT; bool IntersectRect(const RECT * r1, const RECT * r2) { return ! ( r2->left > r1->right || r2->right left || r2->top > r1->bottom || r2->bottom top ); }

    Read the article

  • javascript robot

    - by sarah
    hey guys! I need help making this robot game in javascript (notepad++) please HELP! I'm really confused by the functions <html> <head><title>Robot Invasion 2199</title></head> <body style="text-align:center" onload="newGame();"> <h2>Robot Invasion 2199</h2> <div style="text-align:center; background:white; margin-right: auto; margin-left:auto;"> <div style=""> <div style="width: auto; border:solid thin red; text-align:center; margin:10px auto 10px auto; padding:1ex 0ex;font-family: monospace" id="scene"></pre> </div> <div><span id="status"></span></div> <form style="text-align:center"> PUT THE CONTROL PANEL HERE!!! </form> </div> <script type="text/javascript"> // GENERAL SUGGESTIONS ABOUT WRITING THIS PROGRAM: // You should test your program before you've finished writing all of the // functions. The newGame, startLevel, and update functions should be your // first priority since they're all involved in displaying the initial state // of the game board. // // Next, work on putting together the control panel for the game so that you // can begin to interact with it. Your next goal should be to get the move // function working so that everything else can be testable. Note that all nine // of the movement buttons (including the pass button) should call the move // function when they are clicked, just with different parameters. // // All the remaining functions can be completed in pretty much any order, and // you'll see the game gradually improve as you write the functions. // // Just remember to keep your cool when writing this program. There are a // bunch of functions to write, but as long as you stay focused on the function // you're writing, each individual part is not that hard. // These variables specify the number of rows and columns in the game board. // Use these variables instead of hard coding the number of rows and columns // in your loops, etc. // i.e. Write: // for(i = 0; i < NUM_ROWS; i++) ... // not: // for(i = 0; i < 15; i++) ... var NUM_ROWS = 15; var NUM_COLS = 25; // Scene is arguably the most important variable in this whole program. It // should be set up as a two-dimensional array (with NUM_ROWS rows and // NUM_COLS columns). This represents the game board, with the scene[i][j] // representing what's in row i, column j. In particular, the entries should // be: // // "." for empty space // "R" for a robot // "S" for a scrap pile // "H" for the hero var scene; // These variables represent the row and column of the hero's location, // respectively. These are more of a conveniece so you don't have to search // for the "H" in the scene array when you need to know where the hero is. var heroRow; var heroCol; // These variables keep track of various aspects of the gameplay. // score is just the number of robots destroyed. // screwdrivers is the number of sonic screwdriver charges left. // fastTeleports is the number of fast teleports remaining. // level is the current level number. // Be sure to reset all of these when a new game starts, and update them at the // appropriate times. var score; var screwdrivers; var fastTeleports; var level; // This function should use a sonic screwdriver if there are still charges // left. The sonic screwdriver turns any robot that is in one of the eight // squares immediately adjacent to the hero into scrap. If there are no charges // left, then this function should instead pop up a dialog box with the message // "Out of sonic screwdrivers!". As with any function that alters the game's // state, this function should call the update function when it has finished. // // Your "Sonic Screwdriver" button should call this function directly. function screwdriver() { // WRITE THIS FUNCTION } // This function should move the hero to a randomly selected location if there // are still fast teleports left. This function MUST NOT move the hero on to // a square that is already occupied by a robot or a scrap pile, although it // can move the hero next to a robot. The number of fast teleports should also // be decreased by one. If there are no fast teleports left, this function // should just pop up a message box saying so. As with any function that alters // the game's state, this function should call the update function when it has // finished. // // HINT: Have a loop that keeps trying random spots until a valid one is found. // HINT: Use the validPosition function to tell if a spot is valid // // Your "Fast Teleport" button s

    Read the article

  • How to layout view right aligned and bottom of an LinearLayout

    - by michael
    Hi I am trying to layout 1 textview (upText) left aligned and 1 textview (downText) and an image view (image) both on the same line and right aligned. how can I do that? I tried that, but both 'textview' and image view at left aligned. <TextView android:id="@+id/uptext" android:layout_width="fill_parent" android:layout_height="wrap_content" android:gravity="left"/> <TextView android:id="@+id/downtext" android:layout_width="fill_parent" android:layout_height="wrap_content" android:singleLine="true" android:gravity="right|bottom"/> <ImageView android:id="@+id/image" android:layout_width="wrap_content" android:layout_height="wrap_content" android:gravity="right|bottom"/> </LinearLayout>

    Read the article

  • Using PHP Sockets as a "Relay"

    - by Trikks
    Hi! I'm trying to create a left php socket-server < right relation with php sockets. Let's say that I have a server-daemon on the left side, like a vnc-server that connects to the socket-server. On the right side I've got a client that want to connect to the left server-daemon, but it has to be done through the socket-server. The server environment is a fully featured Linux or Mac OS X Server host with php5.3. Any idéas? Thanks / Trikks

    Read the article

  • Delphi: How to diagnose sluggish UI?

    - by Ian Boyd
    i have a form, which you can pretend is laid out like Windows Explorer: panel on the left splitter client panel +------------+#+-----------------------+ | |#| | | |#| | | |#| | | |#| | | Left |#| Client | | |#| | | |#| | | |#| | | |#| | | |#| | +------------+#+-----------------------+ ^ | +----splitter The the left and client area panels are each rich with controls. The problem is that using the splitter is very sluggish. i would expect that a modern 2 GHz computer can re-display the form as fast as a human can push the mouse around. But that's definitely not the case, and it takes about 200-300 ms before the form is fully re-adjusted. The form has about 100 visual controls on it, no code, or custom controls. How do i go about tracing who's the cause of the sluggishness?

    Read the article

  • javascript open window references

    - by duckofrubber
    Hi, I'm having some issues understanding how to reference new browser windows after opening them. As an example, if I created 3 new windows from a main one (index.html): var one = window.open( 'one.html', 'one',"top=10,left=10,width=100,height=100,location=no,menubar=no,scrollbars=no,status=no,toolbar=no,resizable=no"); var two = window.open( 'two.html', 'two',"top=100,left=10,width=100,height=100,location=no,menubar=no,scrollbars=no,status=no,toolbar=no,resizable=no"); var three = window.open( 'three.html', 'three',"top=200,left=10,width=100,height=100,location=no,menubar=no,scrollbars=no,status=no,toolbar=no,resizable=no"); two.focus(); How could I programmatically focus on (or just refer to) browser "three" if browser "two" is currently in focus?

    Read the article

  • How to make my robot move in a rectangular path along the black tape?

    - by Sahat
    I am working on a robot, it's part of the summer robotics workshop in our college. We are using C-STAMP micro controllers by A-WIT. I was able to make it move, turn left, turn right, move backward. I have even managed to make it go along the black tape using a contrast sensor. I send the robot at 30-45 degrees toward the black tape on the table and it aligns itself and starts to move along the black tape. It jerks a little, probably due to my programming logic below, it's running a while loop and constantly checking if statements, so it ends up trying to turn left and right every few milliseconds, which explains the jerking part. But it's okay, it works, not as smooth as I want it to work but it works! Problem is that I can't make my robot go into a rectangular path of the black tape. As soon as it reaches the corner it just keeps going straight instead of making a left/right turn. Here's my attempt. The following code is just part of the code. My 2 sensors are located right underneath the robot, next to the front wheel, almost at the floor level. It has "index" value ranging from 0 to 8. I believe it's 8 when you have a lot of light coming into the sensor , and 0 when it's nearly pitch black. So when the robot moves into the black-tape-zone, the index value drops, and based on that I have an if-statement telling my robot to either turn left or right. To avoid confusion I didn't post the entire source code, but only the logical part responsible for the movement of my robot along the black tape. while(1) { // don't worry about these. // 10 and 9 represent Sensor's PIN location on the motherboard V = ANALOGIN(10, 1, 0, 0, 0); V2 = ANALOGIN(9, 1, 0, 0, 0); // i got this "formula" from the example in my Manual. // V stands for voltage of the sensor. // it gives me the index value of the sensor. 0 = darkest, 8 = lightest. index = ((-(V - 5) / 5) * 8 + 0.5); index2 = ((-(V2 - 5) / 5) * 8 + 0.5); // i've tweaked the position of the sensors so index > 7 is just right number. // the robot will move anywhere on the table just fine with index > 7. // as soon as it drops to or below 7 (i.e. finds black tape), the robot will // either turn left or right and then go forward. // lp & rp represent left-wheel pin and right-wheel pin, 1 means run forever. // if i change it from 1 to 100, it will go forward for 100ms. if (index > 7 && index2 > 7) goForward(lp, rp, 1); if (index <= 7) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); // this is the tricky part. i've added this code last minute // trying to make my robot turn, but i didn't work. if (index > 4) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); } } else if (index2 <= 7) { turnRight(lp, rp, 1); goForward(lp, rp, 1); // this is also the last minute addition. it's same code as above // but it's for the 2nd sensor. if (index2 > 4) { turnRight(lp, rp, 1); goForward(lp, rp, 1); } } I've spent the entire day trying to figure it out. I've pretty much exhausted all avenues. Asking for the solution on stackoverflow is my very last option now. Thanks in advance! If you have any questions about the code, let me know, but comments should be self-explanatory.

    Read the article

  • Playing with Graphics in Flex

    - by Anoop
    Hi All, I was just going through one code used to draw one chart. This code is written in the updateDisplayList of the itemrenderer of column chart. I am not good at the graphics part of flex. Can anybody please explain me what this code is doing. I can see the final output, but am not sure how is this achieved. var rc:Rectangle = new Rectangle(0, 0, width , height ); var g:Graphics = graphics; g.clear(); g.moveTo(rc.left,rc.top); g.beginFill(fill); g.lineTo(rc.right,rc.top); g.lineTo(rc.right,rc.bottom); g.lineTo(rc.left,rc.bottom); g.lineTo(rc.left,rc.top); g.endFill(); Regards, PK

    Read the article

  • Null Values And The T-SQL IN Operator

    - by Jesse
    I came across some unexpected behavior while troubleshooting a failing test the other day that took me long enough to figure out that I thought it was worth sharing here. I finally traced the failing test back to a SELECT statement in a stored procedure that was using the IN t-sql operator to exclude a certain set of values. Here’s a very simple example table to illustrate the issue: Customers CustomerId INT, NOT NULL, Primary Key CustomerName nvarchar(100) NOT NULL SalesRegionId INT NULL   The ‘SalesRegionId’ column contains a number representing the sales region that the customer belongs to. This column is nullable because new customers get created all the time but assigning them to sales regions is a process that is handled by a regional manager on a periodic basis. For the purposes of this example, the Customers table currently has the following rows: CustomerId CustomerName SalesRegionId 1 Customer A 1 2 Customer B NULL 3 Customer C 4 4 Customer D 2 5 Customer E 3   How could we write a query against this table for all customers that are NOT in sales regions 2 or 4? You might try something like this: 1: SELECT 2: CustomerId, 3: CustomerName, 4: SalesRegionId 5: FROM Customers 6: WHERE SalesRegionId NOT IN (2,4)   Will this work? In short, no; at least not in the way that you might expect. Here’s what this query will return given the example data we’re working with: CustomerId CustomerName SalesRegionId 1 Customer A 1 5 Customer E 5   I was expecting that this query would also return ‘Customer B’, since that customer has a NULL SalesRegionId. In my mind, having a customer with no sales region should be included in a set of customers that are not in sales regions 2 or 4.When I first started troubleshooting my issue I made note of the fact that this query should probably be re-written without the NOT IN clause, but I didn’t suspect that the NOT IN clause was actually the source of the issue. This particular query was only one minor piece in a much larger process that was being exercised via an automated integration test and I simply made a poor assumption that the NOT IN would work the way that I thought it should. So why doesn’t this work the way that I thought it should? From the MSDN documentation on the t-sql IN operator: If the value of test_expression is equal to any value returned by subquery or is equal to any expression from the comma-separated list, the result value is TRUE; otherwise, the result value is FALSE. Using NOT IN negates the subquery value or expression. The key phrase out of that quote is, “… is equal to any expression from the comma-separated list…”. The NULL SalesRegionId isn’t included in the NOT IN because of how NULL values are handled in equality comparisons. From the MSDN documentation on ANSI_NULLS: The SQL-92 standard requires that an equals (=) or not equal to (<>) comparison against a null value evaluates to FALSE. When SET ANSI_NULLS is ON, a SELECT statement using WHERE column_name = NULL returns zero rows even if there are null values in column_name. A SELECT statement using WHERE column_name <> NULL returns zero rows even if there are nonnull values in column_name. In fact, the MSDN documentation on the IN operator includes the following blurb about using NULL values in IN sub-queries or expressions that are used with the IN operator: Any null values returned by subquery or expression that are compared to test_expression using IN or NOT IN return UNKNOWN. Using null values in together with IN or NOT IN can produce unexpected results. If I were to include a ‘SET ANSI_NULLS OFF’ command right above my SELECT statement I would get ‘Customer B’ returned in the results, but that’s definitely not the right way to deal with this. We could re-write the query to explicitly include the NULL value in the WHERE clause: 1: SELECT 2: CustomerId, 3: CustomerName, 4: SalesRegionId 5: FROM Customers 6: WHERE (SalesRegionId NOT IN (2,4) OR SalesRegionId IS NULL)   This query works and properly includes ‘Customer B’ in the results, but I ultimately opted to re-write the query using a LEFT OUTER JOIN against a table variable containing all of the values that I wanted to exclude because, in my case, there could potentially be several hundred values to be excluded. If we were to apply the same refactoring to our simple sales region example we’d end up with: 1: DECLARE @regionsToIgnore TABLE (IgnoredRegionId INT) 2: INSERT @regionsToIgnore values (2),(4) 3:  4: SELECT 5: c.CustomerId, 6: c.CustomerName, 7: c.SalesRegionId 8: FROM Customers c 9: LEFT OUTER JOIN @regionsToIgnore r ON r.IgnoredRegionId = c.SalesRegionId 10: WHERE r.IgnoredRegionId IS NULL By performing a LEFT OUTER JOIN from Customers to the @regionsToIgnore table variable we can simply exclude any rows where the IgnoredRegionId is null, as those represent customers that DO NOT appear in the ignored regions list. This approach will likely perform better if the number of sales regions to ignore gets very large and it also will correctly include any customers that do not yet have a sales region.

    Read the article

  • PHP Moving mySQL Tree Node

    - by TK
    I am having trouble trying to move sub nodes or parent nodes up or down... not that good at math. CREATE TABLE IF NOT EXISTS `pages` ( page-id mediumint(8) unsigned NOT NULL AUTO_INCREMENT, page-left mediumint(8) unsigned NOT NULL, page-right smallint(8) unsigned NOT NULL, page-title text NOT NULL, page-content text NOT NULL, page-time int(11) unsigned NOT NULL, page-slug text NOT NULL, page-template text NOT NULL, page-parent mediumint(8) unsigned NOT NULL, page-type text NOT NULL, PRIMARY KEY (page-id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 ; INSERT INTO pages (page-id, page-left, page-right, page-title, page-content, page-time, page-slug, page-template, page-parent, page-type) VALUES (17, 1, 6, '1', '', 0, 'PARENT', '', 0, ''), (18, 2, 5, '2', '', 0, 'SUB', '', 17, ''), (19, 3, 4, '3', '', 0, 'SUB-SUB', '', 18, ''), (20, 7, 8, '5', '', 0, 'TEST', '', 0, ''); As example how would I move TEST up above PARENT and say move SUB down below SUB-SUB by playing with the page-left/page-right IDs? Code is not required just help with the SQL concept or math for it, would help me understand how to move it better...

    Read the article

  • Lightbox scrolling issue with IE7 & 8

    - by BlazeK
    The lightbox that i am using works great with all browsers except for IE. In IE, its giving me triple scrolls. http://obliqueinteractive.com/demo/monster/ CSS code for the iframe: #wrap { float:left; width:800px; height:500px; overflow-x: hidden; overflow-y: scroll; } #content-wrap { float:left; width:700px; padding-left:50px; } Why is IE adding additional scrolls to the lightbox window? any suggestions?

    Read the article

  • Slider with keypress control bugs when keys pressed to quickly.

    - by Jaybuz
    Hello, I've made a slider that uses the left and right arrow keys to move the slide but when pressed to quickly it will bug a little and I was wondering if it's possible to limit the amount of presses in say a second. You can see it here: {link} $('#slider-nav div').click(function() { $('#slider-nav div').removeClass('selected').addClass(''); $('#slider-nav div:eq('+($.jcarousel.intval($(this).text())-1)+')').addClass('selected'); }) // Allow left and right keys to control slider $(document.documentElement).keypress(function(e) { var code = (e.keyCode ? e.keyCode : e.which); var direction = null; // handle cursor keys if (code == 37) { // left key direction = 'prev'; } else if (code == 39) { // right key direction = 'next'; } if (direction != null) { $('#slider-nav div.selected')[direction]().click(); } });

    Read the article

  • sharepoint online quick launch

    - by Brian
    Hello, we are converting from sharepoint 2003 to sharepoint on line. I am having trouble reproducing a specific behavior in the online version. If a choose a list, I get a "select a view" navigation on the left hand side of the page showing the available views. When a new view is created, it automatically appears on this navigation list. In the online sharepoint, instead there is a view dropdown. I know I can manually setup links on the quick launch but I'm looking for an automatic way to do this. Can the online sharepoint be set up so that when views are added they automatically appear as left-hand links? Or can the "views" dropdown be moved to the left side which would be an acceptable work around? Please note I am unfamiliar with SP designer and I do work with .NET but I dont want to go that route just for this issue - thanks.

    Read the article

  • Why won't my span do a JQuery event click when I click it?

    - by alex
    .tablePlayButton { display: block; width: 16px; background: transparent; margin-top:2px; margin-right: -10px; margin-left: 2px; height:17px; } tr:hover .tablePlayButton { background: url(ton.png) top left no-repeat; } tr:hover .tablePlayButton:active { background-position: bottom left; } tr:hover .tablePlayButton.playing, .tablePlayButton.playing { background: url(ton2.png) top right no-repeat; } tr:hover .tablePlayButton.playing:active, .tablePlayButton.playing:active { background-position: bottom right; } I draw the span like this: <span class="tablePlayButton"></span> It's got a little button. WHen I click it, nothing happens: $(".tablePlayButton").click(function(){ alert('hi'); });

    Read the article

  • jQuery inserting comment help

    - by StealthRT
    Hey all, i am trying to learn how to insert a comment within some html code without having to refresh the page. I know jQuery is capable of inserting a comment into a div area but i am having problems finding an example like that with fading in. Here is my comment code: <div id="CommentBox122" style="width:80%; padding:2px; margin-left:25px;"> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <div id="stylized" class="myform" align="center"> <form id="CommentForm122" name="CommentForm122"> <div align="center" style="text-align:center; color:#F00; font-family:Arial, Helvetica, sans-serif; font-weight:bold;">Would you like to leave a comment, Robert?</div> <textarea name="txtComment" class="box" id="txtComment"></textarea> <input name="txtpostid" type="text" id="txtpostid" style="visibility:hidden; display:none; height:0px; width:0px;" value="Demo43639" /> <div class="buttons" align="center"> <button type="button" id="Button122" name="Button122" class="positive" onclick="doStuff();"><img name="Submit" src="img\buttonimgComment.png" alt="" />Post Comment</button> </div> </form> </div> </div> The code i need to insert again would be: <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> But again, i am unable to find an example using jQuery to automatically insert that part of the code under the other "table /table" box.. So after its inserted by jQuery, the code should look like this: <div id="CommentBox122" style="width:80%; padding:2px; margin-left:25px;"> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <table width="650px" border="0" cellpadding="0" cellspacing="5" style="margin-left:20px; background-color: #F8F8F8; border-bottom:#CCC solid 1px;"><tr> <td width="10%" rowspan="2" align="center" class="Commentimage"><img src="img/avatar/gkrgimmkdhmggfh.jpg" height="60" /></td> <td width="90%" class="Commentposted">Posted by me on Saturday, May 01, 2010 @ 4:37: PM</td></tr> <tr><td class="Commentsaying">this is a test comment</td></tr> </table> <div id="stylized" class="myform" align="center"> <form id="CommentForm122" name="CommentForm122"> <div align="center" style="text-align:center; color:#F00; font-family:Arial, Helvetica, sans-serif; font-weight:bold;">Would you like to leave a comment, Robert?</div> <textarea name="txtComment" class="box" id="txtComment"></textarea> <input name="txtpostid" type="text" id="txtpostid" style="visibility:hidden; display:none; height:0px; width:0px;" value="Demo43639" /> <div class="buttons" align="center"> <button type="button" id="Button122" name="Button122" class="positive" onclick="doStuff();"><img name="Submit" src="img\buttonimgComment.png" alt="" />Post Comment</button> </div> </form> </div> </div> As always, any help would be great! :o) David

    Read the article

  • Can this rectangle to rectangle intersection code still work?

    - by Jeremy Rudd
    I was looking for a fast performing code to test if 2 rectangles are intersecting. A search on the internet came up with this one-liner (WOOT!), but I don't understand how to write it in Javascript, it seems to be written in an ancient form of C++. Can this thing still work? Can you make it work? struct { LONG left; LONG top; LONG right; LONG bottom; } RECT; bool IntersectRect(const RECT * r1, const RECT * r2) { return ! ( r2->left > r1->right || r2->right left || r2->top > r1->bottom || r2->bottom top ); }

    Read the article

  • Need help from CSS purist!

    - by Darcy
    I'm beginning to use CSS more and more but I'm not sure if I'm using it as intended in all cases. I have classes named things like 'box' that will wrap the content inside it with a border, which seems like good CSS to me. On the other hand I have classes like 'margin-right-5' and 'float-left' that sets the css to margin-right: 5px and float:left respectively. I'm wondering if this is good practice. Then in my markup I'd do something like: <div class="box float-left margin-right-5"> <!-- CONTENT HERE --> </div> Sometimes I may want to float right or not have a margin at all and still use the 'box' class, so I use several classes in order to make the css more flexible. Am I destroying the principles of CSS?

    Read the article

  • Slide navigation problem multiple div movement

    - by littleMan
    I have almost figured it out but still doesn't quite work the way i want it to. my problem is this part. It scrolls the first element to the left but the second element just appears and doesn't scroll does anyone know what todo here. var i = jQuery('.wikiform .wizard .view').size(); jQuery('.wikiform .navigation input[name^=Next]').click(function () { jQuery('.wikiform .wizard .view').each(function (j) { jQuery(this).animate({ marginLeft: -(current.next().width() * (i - j)) }, 750); /*line above Im having problems with ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ */ current = current.next(); j++; }); }); my complete code down below test it out and see what Im doing wrong (function ($) { $.fn.WikiForm = function (options) { this.Mode = options.mode || 'CancelOk' || 'Ok' || 'Wizard'; var current = jQuery('.wikiform .view:first'); function positionForm() { jQuery('body') .css('overflow-y', 'hidden'); jQuery('<div id="overlay"></div>') .insertBefore('.wikiform') .css('top', jQuery(document).scrollTop()) .animate({ 'opacity': '0.8' }, 'slow'); jQuery('.wikiform') .css('height', jQuery('.wikiform .wizard .view:first').height() + jQuery('.wikiform .navigation').height()) .css('top', window.screen.availHeight / 2 - jQuery('.wikiform').height() / 2) .css('width', jQuery('.wikiform .wizard .view:first').width()) .css('left', -jQuery('.wikiform').width()) .animate({ marginLeft: jQuery(document).width() / 2 + jQuery('.wikiform').width() / 2 }, 750); jQuery('.wikiform .wizard') .css('overflow', 'hidden') .css('height', jQuery('.wikiform .wizard .view:first').height()); } if (this.Mode == "Wizard") { return this.each(function () { positionForm(); //alert(current.next().width()); var i = jQuery('.wikiform .wizard .view').size(); jQuery('.wikiform .navigation input[name^=Next]').click(function () { jQuery('.wikiform .wizard .view').each(function (j) { jQuery(this).animate({ marginLeft: -(current.next().width() * (i - j)) }, 750); current = current.next(); j++; }); }); jQuery('.wikiform .navigation input[name^=Back]').click(function () { }); }); } else if (this.Mode == "CancelOk") { return this.each(function () { }); } else { return this.each(function () { }); } }; })(jQuery); $(document).ready(function () { jQuery(window).bind("load", function () { jQuery(".wikiform").WikiForm({ mode: 'Wizard', speed:750, ease:"expoinout" }); }); }); <style type="text/css"> body { margin:0px; } #overlay { background-color:Black; position:absolute; top:0; left:0; height:100%; width:100%; } .wikiform { background-color:Green; position:absolute; } .wikiform .wizard { clear: both; } .wizard { position: relative; left: 0; top: 0; width: 100%; list-style-type: none; } .wizard .view { float:left; } .view .form { } .navigation { float:right; clear:left } #view1 { background-color:Aqua; width:300px; height:300px; } #view2 { background-color:Fuchsia; width:300px; height:300px; } </style> <title></title></head><body><form action="" method=""><div id="layout"><div id="header"> Header </div> <div id="content" style="height:2000px"> Content </div> <div id="footer"> Footer </div> </div> <div id="formView1" class="wikiform"> <div class="wizard"> <div id="view1" class="view"> <div class="form"> Content 1 </div> </div> <div id="view2" class="view"> <div class="form"> Content 2 </div> </div> </div> <div class="navigation"> <input type="button" name="Back" value=" Back " /> <input type="button" name="Next " class="Next" value=" Next " /> <input type="button" name="Cancel" value="Cancel" /> </div> </div>

    Read the article

  • Best way to move an image across part of the screen?

    - by rushonerok
    I have a Silverlight WP7 app and an image on my page that I want to appear to slide across the screen. What is the best way of doing this? I wrote this real quick but the UI doesn't update until the entire method is done. private void SpinImg(Image img, double left) { for(int i = 1; i <= 10000; i++) { img.Margin = new Thickness(left, img.Margin.Top + 1, 0, 0); if(img.Margin.Top > 314) { //move it to the top img.Margin = new Thickness(left, -105, 0, 0); } int wait = 1000 / i; Thread.Sleep(wait); } }

    Read the article

  • [BST] Deletion procedure

    - by Metz
    Hi all. Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. Thank you. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

    Read the article

  • Absolute position and floating

    - by Ruth Rettigo
    Hi, Do you have any idea, how to style this layout without specifing exact height for "Element 1"? Code Element1 { positon: relative; width: 100%; height: auto; /* I don't want to specify exact height */ } Inner1 { position: absolute; top: xyz px; left: xyz px; } Inner2 { position: absolute; top: xyz px; left: xyz px; } Element2 { float: left; width: 100%; } Example +--------------------------------------------------+ |Element1 | | +--------+ | | +--------+ |Inner2 | | | |Inner1 | +--------+ | | +--------+ | | | | | +--------------------------------------------------+ +--------------------------------------------------+ |Element2 | | | | | +--------------------------------------------------+

    Read the article

  • How do I use "this" in a member function?

    - by Peter Stewart
    I've written a member function of class Node to read a tree of Nodes in postfix order. It will be called by the Node instance which is the root node of the tree. So: N.postfix(); these appear to be illeagal: *this->left.postfix(); *this->right.postfix(); What is the proper way to do this? class Node { public: const char *cargo; int depth; Node *left; Node *right void Node::postfix() { if (this==__nullptr) { return; } else { *this->left.postfix(); *this->right.postfix(); out<<*this->cargo<<"\n"; return; } };

    Read the article

< Previous Page | 138 139 140 141 142 143 144 145 146 147 148 149  | Next Page >