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  • How to read a string one letter at a time in python

    - by dan
    I need to convert a string inputed by a user into morse code. The way our professor wants us to do this is to read from a morseCode.txt file, seperate the letters from the morseCode into two lists, then convert each letter to morse code (inserting a new line when there is a space). I have the beginning. What it does is reads the morseCode.txt file and seperates the letters into a list [A, B, ... Z] and the codes into a list ['– – . . – –\n', '. – . – . –\n'...]. We haven't learned "sets" yet, so I can't use that. How would I then take the string that they inputed, go through letter by letter, and convert it to morse code? I'm a bit caught up. Here's what I have right now (not much at all...) morseCodeFile = open('morseCode.txt', 'r') letterList = [] codeList = [] line = morseCodeFile.readline() while line != '': letterList.append(line[0]) codeList.append(line[2:]) line = morseCodeFile.readline() morseCodeFile.close() userInput = input("Enter a string to be converted to morse code or press <enter> to quit ")

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  • Write xml file using lxml library in Python

    - by systempuntoout
    I'm using lxml to create an XML file from scratch; having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • Most efficient way to search the last x lines of a file in python

    - by Harley
    I have a file and I don't know how big it's going to be (it could be quite large, but the size will vary greatly). I want to search the last 10 lines or so to see if any of them match a string. I need to do this as quickly and efficiently as possible and was wondering if there's anything better than: s = "foo" last_bit = fileObj.readlines()[-10:] for line in last_bit: if line == s: print "FOUND"

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  • Xml comparison in Python

    - by Gregg Lind
    Building on another SO question, how can one check whether two well-formed XML snippets are semantically equal. All I need is "equal" or not, since I'm using this for unit tests. In the system I want, these would be equal (note the order of 'start' and 'end'): <?xml version='1.0' encoding='utf-8' standalone='yes'?> <Stats start="1275955200" end="1276041599"> </Stats> # Reodered start and end <?xml version='1.0' encoding='utf-8' standalone='yes'?> <Stats end="1276041599" start="1275955200" > </Stats> I have lmxl and other tools at my disposal, and a simple function that only allows reordering of attributes would work fine as well!

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  • python object AttributeError: type object 'Track' has no attribute 'title'

    - by ccwhite1
    I apologize if this is a noob question, but I can't seem to figure this one out. I have defined an object that defines a music track (NOTE: originally had the just ATTRIBUTE vs self.ATTRIBUTE. I edited those values in to help remove confusion. They had no affect on the problem) class Track(object): def __init__(self, title, artist, album, source, dest): """ Model of the Track Object Contains the followign attributes: 'Title', 'Artist', 'Album', 'Source', 'Dest' """ self.atrTitle = title self.atrArtist = artist self.atrAlbum = album self.atrSource = source self.atrDest = dest I use ObjectListView to create a list of tracks in a specific directory ....other code.... self.aTrack = [Track(sTitle,sArtist,sAlbum,sSource, sDestDir)] self.TrackOlv.AddObjects(self.aTrack) ....other code.... Now I want to iterate the list and print out a single value of each item list = self.TrackOlv.GetObjects() for item in list: print item.atrTitle This fails with the error AttributeError: type object 'Track' has no attribute 'atrTitle' What really confuses me is if I highlight a single item in the Object List View display and use the following code, it will correctly print out the single value for the highlighted item list = self.TrackOlv.GetSelectedObject() print list.atrTitle

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  • Can't parse XML effectively using Python

    - by Harshit Sharma
    import urllib import xml.etree.ElementTree as ET def getWeather(city): #create google weather api url url = "http://www.google.com/ig/api?weather=" + urllib.quote(city) try: # open google weather api url f = urllib.urlopen(url) except: # if there was an error opening the url, return return "Error opening url" # read contents to a string s = f.read() tree=ET.parse(s) current= tree.find("current_condition/condition") condition_data = current.get("data") weather = condition_data if weather == "<?xml version=": return "Invalid city" #return the weather condition #return weather def main(): while True: city = raw_input("Give me a city: ") weather = getWeather(city) print(weather) if __name__ == "__main__": main() gives error , I actually wanted to find values from google weather xml site tags

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  • Help with copy and deepcopy in Python

    - by Az
    Hi there, I think I tried to ask for far too much in my previous question so apologies for that. Let me lay out my situation in as simple a manner as I can this time. Basically, I've got a bunch of dictionaries that reference my objects, which are in turn mapped using SQLAlchemy. All fine with me. However, I want to make iterative changes to the contents of those dictionaries. The problem is that doing so will change the objects they reference---and using copy.copy() does no good since it only copies the references contained within the dictionary. Thus even if copied something, when I try to, say print the contents of the dictionary, I'll only get the latest updated values for the object. This is why I wanted to use copy.deepcopy() but that does not work with SQLAlchemy. Now I'm in a dilemma since I need to copy certain attributes of my object before making said iterative changes. In summary, I need to use SQLAlchemy and at the same time make sure I can have a copy of my object attributes when making changes so I don't change the referenced object itself. Any advice, help, suggestions, etc.?

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  • Python: split a list based on a condition?

    - by Parand
    What's the best way, both aesthetically and from a performance perspective, to split a list of items into multiple lists based on a conditional? The equivalent of: good = [x for x in mylist if x in goodvals] bad = [x for x in mylist if x not in goodvals] is there a more elegant way to do this? Update: here's the actual use case, to better explain what I'm trying to do: # files looks like: [ ('file1.jpg', 33L, '.jpg'), ('file2.avi', 999L, '.avi'), ... ] IMAGE_TYPES = ('.jpg','.jpeg','.gif','.bmp','.png') images = [f for f in files if f[2].lower() in IMAGE_TYPES] anims = [f for f in files if f[2].lower() not in IMAGE_TYPES]

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  • Python - Strange Behavior in re.sub

    - by Greg
    Here's the code I'm running: import re FIND_TERM = r'C:\\Program Files\\Microsoft SQL Server\\90\\DTS\\Binn\\DTExec\.exe' rfind_term = re.compile(FIND_TERM,re.I) REPLACE_TERM = 'C:\\Program Files\\Microsoft SQL Server\\100\\DTS\\Binn\\DTExec.exe' test = r'something C:\Program Files\Microsoft SQL Server\90\DTS\Binn\DTExec.exe something' print rfind_term.sub(REPLACE_TERM,test) And the result I get is: something C:\Program Files\Microsoft SQL Server@\DTS\Binn\DTExec.exe something Why is there an @ sign?

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  • Copy string - Python

    - by Francisco Aleixo
    Ok guys I imagine this is easy but I can't seem to find how to copy a string. Simply COPY to the system like CTRL+C on a text. Basically I want to copy a string so I can for example, lets say, paste(ctrl+v). Sorry for such a trivial question, haha.

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  • In Python, urllib2 giving error

    - by pythBegin
    I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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  • python, wrapping class returning the average of the wrapped members

    - by João Portela
    The title isn't very clear but I'll try to explain. Having this class: class Wrapped(object): def method_a(self): # do some operations return n def method_b(self): # also do some operations return n I wan't to have a class that performs the same way as this one: class Wrapper(object): def __init__(self): self.ws = [Wrapped(1),Wrapped(2),Wrapped(3)] def method_a(self): results=[Wrapped.method_a(w) for w in self.ws] sum_ = sum(results,0.0) average = sum_/len(self.ws) return average def method_b(self): results=[Wrapped.method_b(w) for w in self.ws] sum_ = sum(results,0.0) average = sum_/len(self.ws) return average obviously this is not the actual problem at hand (it is not only two methods), and this code is also incomplete (only included the minimum to explain the problem). So, what i am looking for is a way to obtain this behavior. Meaning, whichever method is called in the wrapper class, call that method for all the Wrapped class objects and return the average of their results. Can it be done? how? Thanks in advance. ps-didn't know which tags to include...

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  • Windows path in python

    - by Gareth
    Hi all. What is the best way to represent a windows directory, for example "C:\meshes\as"? I have been trying to modify a script but it never works because I can't seem to get the directory right, I assume because of the '\' acting as escape character? Thanks, Gareth

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  • Python Post Upload JPEG to Server?

    - by iJames
    It seems like this answer has been provided a bunch of times but in all of it, I'm still getting errors from the server and I'm sure it has to do with my code. I've tried HTTP, and HTTPConnection from httplib and both create quite different terminal outputs in terms of formatting/encoding so I'm not sure where the problem lies. Does anything stand out here? Or is there just a better way? Pieced together from an ancient article because I really needed to understand the basis of creating the post: http://code.activestate.com/recipes/146306-http-client-to-post-using-multipartform-data/ Note, the jpeg is supposed to be "unformatted". The pseudocode: boundary = "somerandomsetofchars" BOUNDARY = '--' + boundary CRLF = '\r\n' fields = [('aspecialkey','thevalueofthekey')] files = [('Image.Data','mypicture.jpg','/users/home/me/mypicture.jpg')] bodylines = [] for (key, value) in fields: bodylines.append(BOUNDARY) bodylines.append('Content-Disposition: form-data; name="%s"' % key) bodylines.append('') bodylines.append(value) for (key, filename, fileloc) in files: bodylines.append(BOUNDARY) bodylines.append('Content-Disposition: form-data; name="%s"; filename="%s"' % (key, filename)) bodylines.append('Content-Type: %s' % self.get_content_type(fileloc)) bodylines.append('') bodylines.append(open(fileloc,'r').read()) bodylines.append(BOUNDARY + '--') bodylines.append('') #print bodylines content_type = 'multipart/form-data; boundary=%s' % BOUNDARY body = CRLF.join(bodylines) #conn = httplib.HTTP("www.ahost.com") # In both this and below, the file part was garbling the rest of the body?!? conn = httplib.HTTPConnection("www.ahost.com") conn.putrequest('POST', "/myuploadlocation/uploadimage") headers = { 'content-length': str(len(body)), 'Content-Type' : content_type, 'User-Agent' : 'myagent' } for headerkey in headers: conn.putheader(headerkey, headers[headerkey]) conn.endheaders() conn.send(body) response = conn.getresponse() result = response.read() responseheaders = response.getheaders() It's interesting in that the real code I've implemented seems to work and is getting back valid responses, but the problem it it's telling me that it can't find the image data. Maybe this is particular to the server, but I'm just trying to rule out that I'm not doing some thing exceptionally stupid here. Or perhaps there's other methodologies for doing this more efficiently. I've not tried poster yet because I want to make sure I'm formatting the POST correctly first. I figure I can upgrade to poster after it's working yes?

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  • Please explain this python behavior

    - by StackUnderflow
    class SomeClass(object): def __init__(self, key_text_pairs = None): ..... for key, text in key_text_pairs: ...... ...... x = SomeClass([1, 2, 3]) The value of key_text_pairs inside the init is None even if I pass a list as in the above statement. Why is it so?? I want to write a generic init which can take all iterator objects... Thanks

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  • python multithreading for dummies

    - by albruno
    trying to find a simple example that clearly shows a single task being divided for multi-threading. Quite frankly... many of the examples are overly sophisticated thus.... making the flow tougher to play with... anyone care to share their breakthrough sample or point to an example? As well, what is the best docs? many google lookups are too specific (for me at this stage) Thanks in advance.

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  • Python + PostgreSQL + strange ascii = UTF8 encoding error

    - by Claudiu
    I have ascii strings which contain the character "\x80" to represent the euro symbol: >>> print "\x80" € When inserting string data containing this character into my database, I get: psycopg2.DataError: invalid byte sequence for encoding "UTF8": 0x80 HINT: This error can also happen if the byte sequence does not match the encodi ng expected by the server, which is controlled by "client_encoding". I'm a unicode newbie. How can I convert my strings containing "\x80" to valid UTF-8 containing that same euro symbol? I've tried calling .encode and .decode on various strings, but run into errors: >>> "\x80".encode("utf-8") Traceback (most recent call last): File "<pyshell#14>", line 1, in <module> "\x80".encode("utf-8") UnicodeDecodeError: 'ascii' codec can't decode byte 0x80 in position 0: ordinal not in range(128)

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  • Python: query a class's parent-class after multiple derivations ("super()" does not work)

    - by henry
    Hi, I have built a class-system that uses multiple derivations of a baseclass (object-class1-class2-class3): class class1(object): def __init__(self): print "class1.__init__()" object.__init__(self) class class2(class1): def __init__(self): print "class2.__init__()" class1.__init__(self) class class3(class2): def __init__(self): print "class3.__init__()" class2.__init__(self) x = class3() It works as expected and prints: class3.__init__() class2.__init__() class1.__init__() Now I would like to replace the 3 lines object.__init__(self) ... class1.__init__(self) ... class2.__init__(self) with something like this: currentParentClass().__init__() ... currentParentClass().__init__() ... currentParentClass().__init__() So basically, i want to create a class-system where i don't have to type "classXYZ.doSomething()". As mentioned above, I want to get the "current class's parent-class". Replacing the three lines with: super(type(self), self).__init__() does NOT work (it always returns the parent-class of the current instance - class2) and will result in an endless loop printing: class3.__init__() class2.__init__() class2.__init__() class2.__init__() class2.__init__() ... So is there a function that can give me the current class's parent-class? Thank you for your help! Henry -------------------- Edit: @Lennart ok maybe i got you wrong but at the moment i think i didn't describe the problem clearly enough.So this example might explain it better: lets create another child-class class class4(class3): pass now what happens if we derive an instance from class4? y = class4() i think it clearly executes: super(class3, self).__init__() which we can translate to this: class2.__init__(y) this is definitly not the goal(that would be class3.__init__(y)) Now making lots of parent-class-function-calls - i do not want to re-implement all of my functions with different base-class-names in my super()-calls.

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  • python unittest howto

    - by zubin71
    I`d like to know how I could unit-test the following module. def download_distribution(url, tempdir): """ Method which downloads the distribution from PyPI """ print "Attempting to download from %s" % (url,) try: url_handler = urllib2.urlopen(url) distribution_contents = url_handler.read() url_handler.close() filename = get_file_name(url) file_handler = open(os.path.join(tempdir, filename), "w") file_handler.write(distribution_contents) file_handler.close() return True except ValueError, IOError: return False

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