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  • Ruby hash value truthiness and symbols

    - by John Topley
    Could somebody please explain why the variable named foo remains true in the code below, even though it's set to false when the method is called? And why the symbol version behaves as expected? def test(options = {}) foo = options[:foo] || true bar = options[:bar] || :true puts "foo is #{foo}, bar is #{bar}" end >> test(:foo => false, :bar => :false) foo is true, bar is false I've only tried this using Ruby 1.8.7.

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  • Can i Use the value of a variable from within a ruby script inside ssh.exec()

    - by kamal
    If i have a # {} , like #{results}, in the snippet below: results = Array.new                                   f = open("/Users/kahmed/messages", "r")                                   f.each_line do |line|                                        results << "#{$.} #{line}" if line =~ /NFE/                                       put #{results}                                   end How can i use it in the following ssh.exec command Net::SSH.start( HOST, USER, :password = PASS ) do|ssh|                                   ssh.exec(#{results})

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  • Highest value datatype can store in c#

    - by user472832
    I am writing a small program for my assignment to find the primitive roots of a prime number. So far, the program works for smaller prime numbers till 13 and gives correct number of roots. But for higher primes numbers, it is showing only fewer primitive roots. And now i got stuck for the prime number 41, shows no primitive roots for it. I used DOUBLE datatype for the calculation, and again tried with the datatype DECIMAL, but no luck. Does anyone know about this kind of problem??? Thank you.

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  • How to compare 2 button title using index or tag value

    - by fasil moham
    Here my application i having set of button 12 buttons,button titles are hidden by default.Button titles are shown when it is clikced , -(IBAction)buttonAction:(id)sender { UIButton *button = (UIButton *)sender; int index = button.tag; [self showing:index]; //now, this method accepts a parameter. } -(void) showing:(NSInteger)index { UIButton* btn = nil; index = index - 1; NSArray* subViewArray = [self.view subviews]; NSInteger i = 0; for (UIView *view in subViewArray) { if ([view isKindOfClass:[UIButton class]]) { btn = (UIButton*) view; NSString* text; if (i == index) { text = [self.textArray objectAtIndex:i]; //put the array that you are using self.previousButtonTag = i; //make a class variable }else { text = @""; } i++; [btn setTitle:text forState:UIControlStateNormal]; } } } 1.I want to compare two button title values to check whether it is equal or not.Im facing the problem , 2.Only press button title only visible,when i click other button previous title is hided,I want to enable two button title on click and wen it is wrong it should be hided.Please suggest me the How to solve this issue,Please do the needfully

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  • How to remove the link if value is 0 using asp.net mvc

    - by kumar
    i have this code.. <table class="dashboard-table"> <thead> <tr> <th>&nbsp;</th> <th>Worked</th> </tr> </thead> <% foreach (var e in Model.ExceptionsByType) { %> <tr> <td> <%=Html.ActionLink(e.ExceptionTypeName, "VirtualScrollingDataRequested", Model.exceptionCategory.GetControllerName(), new { C_EXCPT_TYPE = e.ExceptionTypeID, GUI_SPEC_STAT_DSPL = 2, C_EXCPT_CATG = Model.exceptionCategory.Id, @ASSET_CLASS = string.Empty, @INST_MNEM = string.Empty, @_lock = "ALL" }, new { @title = e.BuildGridTitle(2, e.ExceptionTypeName) })%> </td> <td class="number"> <%=e.WorkedExceptions %> </td> </tr> <% } %> </table> e.WorkedExceptions is the count of exceptions.. I need to to the condition here if the e.workedexceptions == 0 I need to remove the link? please can any body hlep me out? thanks

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  • Passing trough a datagrid value

    - by Tonz
    I have a datagrid with 2 columns. One databound which display names and the other one is a hyperlink column. Column1 = databound column, Column2 = hyperlink column. column1: column2: --------------------- Name1 Modify Name2 Modify Next when i click on any of the values in Column2 i simply get redirected to a other page. This page contains 2 buttons/hyperlinks with Yes or No. (does not mather wich control, which one would bring the most easy to implement solution atm) When clicked on No it simply redirects back to the orignal page. Now the question is when i press "Yes" how exactly do i acces "Name1" (or Name2 if i press on the second modify)? Meaning if i press Yes i want to use this Name for certain opertions (xml). To put it short if i press on "modify" i want to be able to get that name associated with it (which is already displayed in the first bound column left of it). So the goal is to use that name in Xpath for example so i can make a query towards that node with that certain name. Hopefully this made some sence.

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  • I want to select the distict value from models field and then update them (django)

    - by qulzam
    I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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  • Reset JPA generated value between tests

    - by Rythmic
    I'm running spring + hibernate + JUnit with springJunit4runner and transactional set to default rollback I'm using in-memory derbydb as Database. Hibernate is used as a JPA Provider and I am successfully testing CRUD kinds of stuff. However, I have a problem with JPA and the behaviour of @GeneratedValue If I run one of my tests in isolation, two entitys are persisted with id 1 and 2. If i run the whole test suite the ids are instead 6 and 7. Spring does rollbacks just fine so there are only these two entitys in the database after addition and of course zero before. But behaviour of @GeneratedValue doesn't allow me to reliable findById unless I would return the Id from the dao.add(Entity e) //method I don't feel like doing that for the sake of testing, or is it a good practise to return the entity that was persisted so I should be doing it anyway?

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  • Fastest way to check for value existance.

    - by Itay Moav
    I have a list of values I have to check my input against it for existence. What is the faster way? This is really out of curiosity on how the internals work, not any stuff about premature optimization etc... 1. $x=array('v'=>'','c'=>'','w'=>); .. .. array_key_exists($input,$x); 2. $x=array('v','c','w'); .. .. in_array($input,$x);

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  • PHP: separate value in array according to alphabate order

    - by Sanjay
    hi, i want to find values in array according to alphabate and want to make list in of array values according to alphabate order. my array is like that: Array ( [0] = Array ( [0] = Adidas [1] = AKG [2] = Apple [3] = Barrats [4] = Canon [5] = Dell [6] = Dixons [7] = HTC [8] = Liverpool [9] = Microsoft [10] = Pirelli Tyres [11] = ) ) and i want to make a list of values according to alphabate like this: A Adidas AKG plz any idea?

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  • question on find value in array

    - by davit-datuashvili
    i have seen a few days ago such problem there is given two array find elements which are common of these array one of the solution was sort big array and then use binary search algorithm and also there is another algorithm- brute-force algorithm for (int i=0;i<array1.length;i++){ for (int j=0;j<array2.length;j++){ if (array1[i]==array2[j]){ //code here } } it's complexity is O(array1.length*array2.length); and i am interested the first method's complexity is also same yes? because we should sort array first and then use search method binary search algorithm's complexity is log_2(n) so it means that total time will be array.length*log_2(n) and about sort? please explain me which is better

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  • How to view the GDTR's value ?

    - by Mehdi Asgari
    Hi In the book "Rootkit Arsenal" page 84 (Chapter 3) mentions: ..., we can view the contents of the target machine's descriptor registers using the command with the 0x100 mask: kd rM 0x100 and a paragraph below: Note that the same task can be accomplished by specifying the GDTR components explicitly: kd r gdtr .... I run Windbg on my Win XP (inside VMWare) and choose the Kernel Debug - Local. My problem is in case of first command, windbg errors with: lkd rM 0x100 ^ Operation not supported in current debug session 'rM 0x100' and in the second command: lkd r gdtr ^ Bad register error in 'r gdtr' Can anyone guide me ?

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  • Windows batch/script code to conditionally process based on date value in text file

    - by CarolinaJay65
    I am using Windows XP. The code can be used in a batch file or vbs script. I intend to use Windows scheduler to run the program. I need code to read a date from a text file (could be the only line in the text file or the date could be included in the filename, I control the process that generates the file) The code would then need to evaluate the text file date against the current date to confirm that the text file date is from the prior month. I'm starting to build a process to be able to run 1st-of-the-month jobs once the monthly data has been refreshed. I'm new to building this kind of process using batch/script files. Thanks for your time

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  • How to pass value to another view-controllers?

    - by ICoder
    I want to pass localstringtextnote to Uploadviewcontroller by this way , UIViewController *controllerNew = [[UploadViewController alloc] initWithNibName:@"UploadView" bundle:nil owner:self]; controllerNew.localStringtextnote = localStringtextnote; [self.navigationController pushViewController:controllerNew animated:YES]; [controllerNew release]; but i got this error"@property localstringtextnote not fond in the object of type uiviewcontroller" or i want to pass through modalTransistionstyle UploadViewController *aSecondViewController = [[UploadViewController alloc] initWithNibName:@"UploadView" bundle:nil]; aSecondViewController.modalTransitionStyle = UIModalTransitionStyleCoverVertical; [self presentModalViewController:aSecondViewController animated:YES]; [UIView commitAnimations]; How to do this?Thanks in advance.

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  • CGRect var as property value?

    - by David.Chu.ca
    CGRect type is a structure type. If I want to define a property as this type, should I use assign or retain attribute for this type? @interface MyClass { CGRect rect; ... } @property (nonatomic, assign) rect; // or retain?

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  • How do I get the trackbar value?

    - by Ruth
    I feel a little silly asking this, seems pretty simple but I can't find the solution anywhere. I have a trackbar made in visual studio 2008 and I want to use it to adjust an image threshold but I can't find the code to retrieve the sliders/markers position. Any help would be much appreciated and I am using C++

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • Delphi static method of a class returning property value

    - by mitko.berbatov
    I'm making a Delphi VCL application. There is a class TStudent where I have two static functions: one which returns last name from an array of TStudent and another one which returns the first name of the student. Their code is something like: class function TStudent.FirstNameOf(aLastName: string): string; var i : integer; begin for i := 0 to Length(studentsArray) - 1 do begin if studentsArray[i].LastName = aLastName then begin result := studentsArray[i].FirstName; Exit; end; end; result := 'no match was found'; end; class function TStudent.LastNameOf(aFirstName: string): string; var i : integer; begin for i := 0 to Length(studentsArray) - 1 do begin if studentsArray[i].FirstName = aFirstName then begin result := studentsArray[i].LastName; Exit; end; end; result := 'no match was found'; end; My question is how can I avoid writing almost same code twice. Is there any way to pass the property as parameter of the functions.

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  • How to retrieve key and value from JSON object

    - by I Like PHP
    I have a JSON object in this format: { "supplier": { "mov_10": "love actually", "mov_1": "fare" }, "quantity": 20, "success": true, "length":2 } Now I want to create a select box below using the supplier object (using both the keys and values), like this: <select id="selectme"> <option id="mov_10">love actually</option> <option id="mov_1">fare</option> </select> So how do I create it? I just want to know how to reach mov_10 and mov_1 in the object. Sorry for my bad English, but please help me. Thanks.

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  • how to return value from groovy to java

    - by Sid
    Hi I am very new to groovy and having trouble with some parts. I have a jsp page tied to a servlet that runs groovy scripts. I am able to get to the groovy script from the servlet. But after the script runs how do I return the response from the groovy script back to the servlet to be displayed in the jsp page? My java servlet code is as follows: File file = new File("TestScript.groovy"); ClassLoader parent = getClass().getClassLoader(); GroovyClassLoader loader = new GroovyClassLoader(parent); Class groovyClass = loader.parseClass(file); Object[] args = {}; GroovyObject groovyObject = (GroovyObject) groovyClass.newInstance(); groovyObject.invokeMethod("runTest", args);

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  • NHibernate: Using value tables for optimization AND dynamic join

    - by Kostya
    Hi all, My situation is next: there are to entities with many-to-many relation, f.e. Products and Categories. Also, categories has hierachial structure, like a tree. There is need to select all products that depends to some concrete category with all its childs (branch). So, I use following sql statement to do that: SELECT * FROM Products p WHERE p.ID IN ( SELECT DISTINCT pc.ProductID FROM ProductsCategories pc INNER JOIN Categories c ON c.ID = pc.CategoryID WHERE c.TLeft >= 1 AND c.TRight <= 33378 ) But with big set of data this query executes very long and I found some solution to optimize it, look at here: DECLARE @CatProducts TABLE ( ProductID int NOT NULL ) INSERT INTO @CatProducts SELECT DISTINCT pc.ProductID FROM ProductsCategories pc INNER JOIN Categories c ON c.ID = pc.CategoryID WHERE c.TLeft >= 1 AND c.TRight <= 33378 SELECT * FROM Products p INNER JOIN @CatProducts cp ON cp.ProductID = p.ID This query executes very fast but I don't know how to do that with NHIbernate. Note, that I need use only ICriteria because of dynamic filtering\ordering. If some one knows a solution for that, it will be fantastic. But I'll pleasure to any suggestions of course. Thank you ahead, Kostya

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