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  • parallel_for_each from amp.h – part 1

    - by Daniel Moth
    This posts assumes that you've read my other C++ AMP posts on index<N> and extent<N>, as well as about the restrict modifier. It also assumes you are familiar with C++ lambdas (if not, follow my links to C++ documentation). Basic structure and parameters Now we are ready for part 1 of the description of the new overload for the concurrency::parallel_for_each function. The basic new parallel_for_each method signature returns void and accepts two parameters: a grid<N> (think of it as an alias to extent) a restrict(direct3d) lambda, whose signature is such that it returns void and accepts an index of the same rank as the grid So it looks something like this (with generous returns for more palatable formatting) assuming we are dealing with a 2-dimensional space: // some_code_A parallel_for_each( g, // g is of type grid<2> [ ](index<2> idx) restrict(direct3d) { // kernel code } ); // some_code_B The parallel_for_each will execute the body of the lambda (which must have the restrict modifier), on the GPU. We also call the lambda body the "kernel". The kernel will be executed multiple times, once per scheduled GPU thread. The only difference in each execution is the value of the index object (aka as the GPU thread ID in this context) that gets passed to your kernel code. The number of GPU threads (and the values of each index) is determined by the grid object you pass, as described next. You know that grid is simply a wrapper on extent. In this context, one way to think about it is that the extent generates a number of index objects. So for the example above, if your grid was setup by some_code_A as follows: extent<2> e(2,3); grid<2> g(e); ...then given that: e.size()==6, e[0]==2, and e[1]=3 ...the six index<2> objects it generates (and hence the values that your lambda would receive) are:    (0,0) (1,0) (0,1) (1,1) (0,2) (1,2) So what the above means is that the lambda body with the algorithm that you wrote will get executed 6 times and the index<2> object you receive each time will have one of the values just listed above (of course, each one will only appear once, the order is indeterminate, and they are likely to call your code at the same exact time). Obviously, in real GPU programming, you'd typically be scheduling thousands if not millions of threads, not just 6. If you've been following along you should be thinking: "that is all fine and makes sense, but what can I do in the kernel since I passed nothing else meaningful to it, and it is not returning any values out to me?" Passing data in and out It is a good question, and in data parallel algorithms indeed you typically want to pass some data in, perform some operation, and then typically return some results out. The way you pass data into the kernel, is by capturing variables in the lambda (again, if you are not familiar with them, follow the links about C++ lambdas), and the way you use data after the kernel is done executing is simply by using those same variables. In the example above, the lambda was written in a fairly useless way with an empty capture list: [ ](index<2> idx) restrict(direct3d), where the empty square brackets means that no variables were captured. If instead I write it like this [&](index<2> idx) restrict(direct3d), then all variables in the some_code_A region are made available to the lambda by reference, but as soon as I try to use any of those variables in the lambda, I will receive a compiler error. This has to do with one of the direct3d restrictions, where only one type can be capture by reference: objects of the new concurrency::array class that I'll introduce in the next post (suffice for now to think of it as a container of data). If I write the lambda line like this [=](index<2> idx) restrict(direct3d), all variables in the some_code_A region are made available to the lambda by value. This works for some types (e.g. an integer), but not for all, as per the restrictions for direct3d. In particular, no useful data classes work except for one new type we introduce with C++ AMP: objects of the new concurrency::array_view class, that I'll introduce in the post after next. Also note that if you capture some variable by value, you could use it as input to your algorithm, but you wouldn’t be able to observe changes to it after the parallel_for_each call (e.g. in some_code_B region since it was passed by value) – the exception to this rule is the array_view since (as we'll see in a future post) it is a wrapper for data, not a container. Finally, for completeness, you can write your lambda, e.g. like this [av, &ar](index<2> idx) restrict(direct3d) where av is a variable of type array_view and ar is a variable of type array - the point being you can be very specific about what variables you capture and how. So it looks like from a large data perspective you can only capture array and array_view objects in the lambda (that is how you pass data to your kernel) and then use the many threads that call your code (each with a unique index) to perform some operation. You can also capture some limited types by value, as input only. When the last thread completes execution of your lambda, the data in the array_view or array are ready to be used in the some_code_B region. We'll talk more about all this in future posts… (a)synchronous Please note that the parallel_for_each executes as if synchronous to the calling code, but in reality, it is asynchronous. I.e. once the parallel_for_each call is made and the kernel has been passed to the runtime, the some_code_B region continues to execute immediately by the CPU thread, while in parallel the kernel is executed by the GPU threads. However, if you try to access the (array or array_view) data that you captured in the lambda in the some_code_B region, your code will block until the results become available. Hence the correct statement: the parallel_for_each is as-if synchronous in terms of visible side-effects, but asynchronous in reality.   That's all for now, we'll revisit the parallel_for_each description, once we introduce properly array and array_view – coming next. Comments about this post by Daniel Moth welcome at the original blog.

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  • issue with std::advance on std::sets

    - by tim
    I've stumbled upon what I believe is a bug in the stl algorithm advance. When I'm advancing the iterator off of the end of the container, I get inconsistent results. Sometimes I get container.end(), sometimes I get the last element. I've illustrated this with the following code: #include <algorithm> #include <cstdio> #include <set> using namespace std; typedef set<int> tMap; int main(int argc, char** argv) { tMap::iterator i; tMap the_map; for (int i=0; i<10; i++) the_map.insert(i); #if EXPERIMENT==1 i = the_map.begin(); #elif EXPERIMENT==2 i = the_map.find(4); #elif EXPERIMENT==3 i = the_map.find(5); #elif EXPERIMENT==4 i = the_map.find(6); #elif EXPERIMENT==5 i = the_map.find(9); #elif EXPERIMENT==6 i = the_map.find(2000); #else i = the_map.end(); #endif advance(i, 100); if (i == the_map.end()) printf("the end\n"); else printf("wuh? %d\n", *i); return 0; } Which I get the following unexpected (according to me) behavior in experiment 3 and 5 where I get the last element instead of the_map.end(). [tim@saturn advance]$ uname -srvmpio Linux 2.6.18-1.2798.fc6 #1 SMP Mon Oct 16 14:37:32 EDT 2006 i686 athlon i386 GNU/Linux [tim@saturn advance]$ g++ --version g++ (GCC) 4.1.1 20061011 (Red Hat 4.1.1-30) Copyright (C) 2006 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. [tim@saturn advance]$ g++ -DEXPERIMENT=1 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=2 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=3 advance.cc [tim@saturn advance]$ ./a.out wuh? 9 [tim@saturn advance]$ g++ -DEXPERIMENT=4 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=5 advance.cc [tim@saturn advance]$ ./a.out wuh? 9 [tim@saturn advance]$ g++ -DEXPERIMENT=6 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=7 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ From the sgi website (see link at top), it has the following example: list<int> L; L.push_back(0); L.push_back(1); list<int>::iterator i = L.begin(); advance(i, 2); assert(i == L.end()); I would think that the assertion should apply to other container types, no? What am I missing? Thanks!

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  • Cron Tips for not running cron jobs on holidays (the monday of a three day weekend)

    - by Poul
    We have about a one hundred machine set-up with each machine running cron jobs like starting and stopping services and archiving these services' log files at the end of the day to a centralized repository. One headache we have is the three-day weekend (we're closed on holidays). We don't want the services starting up on those days and connecting to our business partner's machines. We currently do this by manually commenting out the most critical jobs and letting a bunch of errors happen all day. Not ideal. Basically if a job has '1-5' set in the day field we want this to mean 'work days' and not Monday to Friday'. We have a database that keeps track of which days are indeed 'work days' So, is it possible to override Cron's day-matching algorithm, or is there some other way to easily set a cron setting to avoid things starting up on a Monday holiday? Thanks!

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  • AAC 256kbit to MP3 320kbit conversion. I know it's lossy, but how?

    - by Fabian Zeindl
    Has anyone ever transcoded music from a high-quality aac to an mp3 (or vice-versa). The internet is full of people who say this should never be done, but apart from the theoretical standpoint that you can only lose information, does it matter in practise? is the difference perceivable, except on studio-equipment? does the re-encoding actually lose much information? If, p.e., high frequences are chopped away by the initial compression, those frequencies aren't there anymore, so this part of the compression-algorithm won't touch the data during the second compression. Am i wrong?

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  • Is SHA-1 secure for password storage?

    - by Tgr
    Some people throw around remarks like "SHA-1 is broken" a lot, so I'm trying to understand what exactly that means. Let's assume I have a database of SHA-1 password hashes, and an attacker whith a state of the art SHA-1 breaking algorithm and a botnet with 100,000 machines gets access to it. (Having control over 100k home computers would mean they can do about 10^15 operations per second.) How much time would they need to find out the password of any one user? find out the password of a given user? find out the password of all users? find a way to log in as one of the users? find a way to log in as a specific user? How does that change if the passwords are salted? Does the method of salting (prefix, postfix, both, or something more complicated like xor-ing) matter? Here is my current understanding, after some googling. Please correct in the answers if I misunderstood something. If there is no salt, a rainbow attack will immediately find all passwords (except extremely long ones). If there is a sufficiently long random salt, the most effective way to find out the passwords is a brute force or dictionary attack. Neither collision nor preimage attacks are any help in finding out the actual password, so cryptographic attacks against SHA-1 are no help here. It doesn't even matter much what algorithm is used - one could even use MD5 or MD4 and the passwords would be just as safe (there is a slight difference because computing a SHA-1 hash is slower). To evaluate how safe "just as safe" is, let's assume that a single sha1 run takes 1000 operations and passwords contain uppercase, lowercase and digits (that is, 60 characters). That means the attacker can test 1015*60*60*24 / 1000 ~= 1017 potential password a day. For a brute force attack, that would mean testing all passwords up to 9 characters in 3 hours, up to 10 characters in a week, up to 11 characters in a year. (It takes 60 times as much for every additional character.) A dictionary attack is much, much faster (even an attacker with a single computer could pull it off in hours), but only finds weak passwords. To log in as a user, the attacker does not need to find out the exact password; it is enough to find a string that results in the same hash. This is called a first preimage attack. As far as I could find, there are no preimage attacks against SHA-1. (A bruteforce attack would take 2160 operations, which means our theoretical attacker would need 1030 years to pull it off. Limits of theoretical possibility are around 260 operations, at which the attack would take a few years.) There are preimage attacks against reduced versions of SHA-1 with negligible effect (for the reduced SHA-1 which uses 44 steps instead of 80, attack time is down from 2160 operations to 2157). There are collision attacks against SHA-1 which are well within theoretical possibility (the best I found brings the time down from 280 to 252), but those are useless against password hashes, even without salting. In short, storing passwords with SHA-1 seems perfectly safe. Did I miss something?

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  • How secure is the encryption used by Microsoft Office 2007?

    - by ericl42
    I've read various articles about Microsoft's Office 2007 encryption and from what I gather 2007 is secure using all default options due to it using AES, and 2000 and 2003 can be configured secure by changing the default algorithm to AES. I was wondering if anyone else has read any other articles or know of any specific vulnerabilities involved with how they implement the encryption. I would like to be able to tell users that they can use this to send semi-sensitive documents as long as they use AES and a strong password. Thanks for the information.

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  • SASL + postfixadmin - SMTP authentication with hashed password

    - by mateo
    Hi all, I'm trying to set up the mail server. I have problem with my SMTP authentication using sasl. I'm using postfixadmin to create my mailboxes, the password is in some kind of md5, postfixadmin config.inc.php: $CONF['encrypt'] = 'md5crypt'; $CONF['authlib_default_flavor'] = 'md5raw'; the sasl is configured like that (/etc/postfix/sasl/smtpd.conf): pwcheck_method: auxprop auxprop_plugin: sql sql_engine: mysql mech_list: plain login cram-md5 digest-md5 sql_hostnames: 127.0.0.1 sql_user: postfix sql_passwd: **** sql_database: postfix sql_select: SELECT password FROM mailbox WHERE username = '%u@%r' log_level: 7 If I want to authenticate (let's say from Thunderbird) with my password, I can't. If I use hashed password from MySQL I can authenticate and send an email. So I think the problem is with hash algorithm. Do you know how to set up the SASL (or postfixadmin) to work fine together. I don't want to store my passwords in plain text...

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  • The best cross platform (portable) arbitrary precision math library

    - by Siu Ching Pong - Asuka Kenji
    Dear ninjas / hackers / wizards, I'm looking for a good arbitrary precision math library in C or C++. Could you please give me some advices / suggestions? The primary requirements: It MUST handle arbitrarily big integers (my primary interest is on integers). In case that you don't know what the word arbitrarily big means, imagine something like 100000! (the factorial of 100000). The precision MUST NOT NEED to be specified during library initialization / object creation. The precision should ONLY be constrained by the available resources of the system. It SHOULD utilize the full power of the platform, and should handle "small" numbers natively. That means on a 64-bit platform, calculating 2^33 + 2^32 should use the available 64-bit CPU instructions. The library SHOULD NOT calculate this in the same way as it does with 2^66 + 2^65 on the same platform. It MUST handle addition (+), subtraction (-), multiplication (*), integer division (/), remainder (%), power (**), increment (++), decrement (--), gcd(), factorial(), and other common integer arithmetic calculations efficiently. Ability to handle functions like sqrt() (square root), log() (logarithm) that do not produce integer results is a plus. Ability to handle symbolic computations is even better. Here are what I found so far: Java's BigInteger and BigDecimal class: I have been using these so far. I have read the source code, but I don't understand the math underneath. It may be based on theories / algorithms that I have never learnt. The built-in integer type or in core libraries of bc / Python / Ruby / Haskell / Lisp / Erlang / OCaml / PHP / some other languages: I have ever used some of these, but I have no idea on which library they are using, or which kind of implementation they are using. What I have already known: Using a char as a decimal digit, and a char* as a decimal string and do calculations on the digits using a for-loop. Using an int (or a long int, or a long long) as a basic "unit" and an array of it as an arbitrary long integer, and do calculations on the elements using a for-loop. Booth's multiplication algorithm What I don't know: Printing the binary array mentioned above in decimal without using naive methods. Example of a naive method: (1) add the bits from the lowest to the highest: 1, 2, 4, 8, 16, 32, ... (2) use a char* string mentioned above to store the intermediate decimal results). What I appreciate: Good comparisons on GMP, MPFR, decNumber (or other libraries that are good in your opinion). Good suggestions on books / articles that I should read. For example, an illustration with figures on how a un-naive arbitrarily long binary to decimal conversion algorithm works is good. Any help. Please DO NOT answer this question if: you think using a double (or a long double, or a long long double) can solve this problem easily. If you do think so, it means that you don't understand the issue under discussion. you have no experience on arbitrary precision mathematics. Thank you in advance! Asuka Kenji

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  • How to give ASP.NET access to a private key in a certificate in the certificate store?

    - by thames
    I have an ASP.NET application that accesses private key in a certificate in the certificates store. On Windows Server 2003 I was able to use winhttpcertcfg.exe to give private key access to the NETWORK SERVICE account. How do I give permissions to access a Private Key in a certificate in the certificate store (Local Computer\Personal) on a Windows Server 2008 R2 in an IIS 7.5 website? I've tried giving Full Trust access to "Everyone", "IIS AppPool\DefaultAppPool", "IIS_IUSRS", and everyother security account I could find using the Certificates MMC (Server 2008 R2). However the below code demonstrates that the code does not have access to the Private Key of a certificate that was imported with the private key. The code instead throws and error everytime the private key property is accessed. Default.aspx <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <%@ Import Namespace="System.Security.Cryptography.X509Certificates" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <asp:Repeater ID="repeater1" runat="server"> <HeaderTemplate> <table> <tr> <td> Cert </td> <td> Public Key </td> <td> Private Key </td> </tr> </HeaderTemplate> <ItemTemplate> <tr> <td> <%#((X509Certificate2)Container.DataItem).GetNameInfo(X509NameType.SimpleName, false) %> </td> <td> <%#((X509Certificate2)Container.DataItem).HasPublicKeyAccess() %> </td> <td> <%#((X509Certificate2)Container.DataItem).HasPrivateKeyAccess() %> </td> </tr> </ItemTemplate> <FooterTemplate> </table></FooterTemplate> </asp:Repeater> </div> </form> </body> </html> Default.aspx.cs using System; using System.Security.Cryptography; using System.Security.Cryptography.X509Certificates; using System.Web.UI; public partial class _Default : Page { public X509Certificate2Collection Certificates; protected void Page_Load(object sender, EventArgs e) { // Local Computer\Personal var store = new X509Store(StoreLocation.LocalMachine); // create and open store for read-only access store.Open(OpenFlags.ReadOnly); Certificates = store.Certificates; repeater1.DataSource = Certificates; repeater1.DataBind(); } } public static class Extensions { public static string HasPublicKeyAccess(this X509Certificate2 cert) { try { AsymmetricAlgorithm algorithm = cert.PublicKey.Key; } catch (Exception ex) { return "No"; } return "Yes"; } public static string HasPrivateKeyAccess(this X509Certificate2 cert) { try { string algorithm = cert.PrivateKey.KeyExchangeAlgorithm; } catch (Exception ex) { return "No"; } return "Yes"; } }

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  • Corrupted .WAR file after transfer from 32-64 bit Windows Server to Desktop or vice versa

    - by Albert Widjaja
    Hi All, Does anyone experience this problem of corrupted .WAR file after it has been copied over the network share ? this is .WAR file (Web Archive) the J2EE application file (.WAR file is compressed with the same zip algorithm i think ?) Scenario 1: Windows Server 2008 x64 transfer into Windows XP using RDP client (Local Devices and Resources) Scenario 2: Windows XP 32 bit transfer into Windows Server 2003 x64 using shared network drive (port 445 SMB ?) for both of the scenario it always failed / corrupted (the source code seems to be duplicated at the end of line when you open up in the Eclipse / Java IDE). but when in both scenario i compressed the file into .ZIP file everything is OK. can anyone explains why this problem happens ? Thanks, Albert

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  • Creating hard drive backup images efficiently

    - by Arrieta
    We are in the process of pruning our directories to recuperate some disk space. The 'algorithm' for the pruning/backup process consists of a list of directories and, for each one of them, a set of rules, e.g. 'compress *.bin', 'move *.blah', 'delete *.crap', 'leave *.important'; these rules change from directory to directory but are well known. The compressed and moved files are stored in a temporary file system, burned onto a blue ray, tested within the blue ray, and, finally, deleted from their original locations. I am doing this in Python (basically a walk statement with a dictionary with the rules for each extension in each folder). Do you recommend a better methodology for pruning file systems? How do you do it? We run on Linux.

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  • Incremental PCA

    - by smichak
    Hi, Lately, I've been looking into an implementation of an incremental PCA algorithm in python - I couldn't find something that would meet my needs so I did some reading and implemented an algorithm I found in some paper. Here is the module's code - the relevant paper on which it is based is mentioned in the module's documentation. I would appreciate any feedback from people who are interested in this. Micha #!/usr/bin/env python """ Incremental PCA calculation module. Based on P.Hall, D. Marshall and R. Martin "Incremental Eigenalysis for Classification" which appeared in British Machine Vision Conference, volume 1, pages 286-295, September 1998. Principal components are updated sequentially as new observations are introduced. Each new observation (x) is projected on the eigenspace spanned by the current principal components (U) and the residual vector (r = x - U(U.T*x)) is used as a new principal component (U' = [U r]). The new principal components are then rotated by a rotation matrix (R) whose columns are the eigenvectors of the transformed covariance matrix (D=U'.T*C*U) to yield p + 1 principal components. From those, only the first p are selected. """ __author__ = "Micha Kalfon" import numpy as np _ZERO_THRESHOLD = 1e-9 # Everything below this is zero class IPCA(object): """Incremental PCA calculation object. General Parameters: m - Number of variables per observation n - Number of observations p - Dimension to which the data should be reduced """ def __init__(self, m, p): """Creates an incremental PCA object for m-dimensional observations in order to reduce them to a p-dimensional subspace. @param m: Number of variables per observation. @param p: Number of principle components. @return: An IPCA object. """ self._m = float(m) self._n = 0.0 self._p = float(p) self._mean = np.matrix(np.zeros((m , 1), dtype=np.float64)) self._covariance = np.matrix(np.zeros((m, m), dtype=np.float64)) self._eigenvectors = np.matrix(np.zeros((m, p), dtype=np.float64)) self._eigenvalues = np.matrix(np.zeros((1, p), dtype=np.float64)) def update(self, x): """Updates with a new observation vector x. @param x: Next observation as a column vector (m x 1). """ m = self._m n = self._n p = self._p mean = self._mean C = self._covariance U = self._eigenvectors E = self._eigenvalues if type(x) is not np.matrix or x.shape != (m, 1): raise TypeError('Input is not a matrix (%d, 1)' % int(m)) # Update covariance matrix and mean vector and centralize input around # new mean oldmean = mean mean = (n*mean + x) / (n + 1.0) C = (n*C + x*x.T + n*oldmean*oldmean.T - (n+1)*mean*mean.T) / (n + 1.0) x -= mean # Project new input on current p-dimensional subspace and calculate # the normalized residual vector g = U.T*x r = x - (U*g) r = (r / np.linalg.norm(r)) if not _is_zero(r) else np.zeros_like(r) # Extend the transformation matrix with the residual vector and find # the rotation matrix by solving the eigenproblem DR=RE U = np.concatenate((U, r), 1) D = U.T*C*U (E, R) = np.linalg.eigh(D) # Sort eigenvalues and eigenvectors from largest to smallest to get the # rotation matrix R sorter = list(reversed(E.argsort(0))) E = E[sorter] R = R[:,sorter] # Apply the rotation matrix U = U*R # Select only p largest eigenvectors and values and update state self._n += 1.0 self._mean = mean self._covariance = C self._eigenvectors = U[:, 0:p] self._eigenvalues = E[0:p] @property def components(self): """Returns a matrix with the current principal components as columns. """ return self._eigenvectors @property def variances(self): """Returns a list with the appropriate variance along each principal component. """ return self._eigenvalues def _is_zero(x): """Return a boolean indicating whether the given vector is a zero vector up to a threshold. """ return np.fabs(x).min() < _ZERO_THRESHOLD if __name__ == '__main__': import sys def pca_svd(X): X = X - X.mean(0).repeat(X.shape[0], 0) [_, _, V] = np.linalg.svd(X) return V N = 1000 obs = np.matrix([np.random.normal(size=10) for _ in xrange(N)]) V = pca_svd(obs) print V[0:2] pca = IPCA(obs.shape[1], 2) for i in xrange(obs.shape[0]): x = obs[i,:].transpose() pca.update(x) U = pca.components print U

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  • HAProxy NGInx SSL setup

    - by Niclas
    I've been looking around different setups for a server cluster supporting SSL and I would like to benchmark my idea with you. Requirements: All servers in the cluster should be under the same full domain name. (http and https) Routing to subsystems is done on URI matching in HA proxy. All URIs have support for SSL support. Wish: Centralizing routing rules ---<----http-----<-- | | Inet -->HA--+---https--->NGInx_SSL_1..N | | +---http---> Apache_1..M | +---http---> NodeJS Idea: Configure HA to route all SSL traffic (mode=tcp,algorithm=Source) to an NGInx cluster turning https traffic into http. Re-pass the http traffic from NGInx to the HA for normal load-balancing which performs load balancing based on HA config. My question is simply: Is this the best way to to configure based on requirements above?

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  • Using SSLv3 - Enabling Strong Ciphers Server 2008

    - by Igor K
    I've disabled SSLv2 and SSLv3 is on. However I cannot connect to a remote server which fails with The client and server cannot communicate, because they do not possess a common algorithm Ran an SSL check (http://www.serversniff.net/sslcheck.php) on the remote server and ours, and noticed none of the ciphers they accept we have on our server. How can this be configured? (Windows Web Server 2008) Remote Server Accepted SSL ciphers: DHE-RSA-AES256-SHA AES256-SHA EDH-RSA-DES-CBC3-SHA DES-CBC3-SHA DHE-RSA-AES128-SHA AES128-SHA Our server by default accepts: DES-CBC3-SHA RC4-SHA RC4-MD5

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  • 284 GiB of data, 217.4 GiB of space

    - by Malfist
    I want to reinstall my OS, but I don't have the hard drive space to backup any more (I have a RAID 1 array, so I haven't done it for a while). In my /home I have 284.8 GiB of data, and I have a spare 250 GB (or 217.4 GiB) hard drive that I've been using for backup. What type of compression algorithm (if any) is capable of this type of compression? I don't care about the time, I have a quad core though, so something that utilizes all 4 cores would be great. I have tried 7zip with no success. Ran on one core for two days and failed because of lack of space. Any ideas?

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  • ublas::bounded_vector<> being resized?

    - by n2liquid
    Now, seriously... I'll refrain from using bad words here because we're talking about the Boost fellows. It MUST be my mistake to see things this way, but I can't understand why, so I'll ask it here; maybe someone can enlighten me in this matter. Here it goes: uBLAS has this nice class template called bounded_vector<> that's used to create fixed-size vectors (or so I thought). From the Effective uBLAS wiki (http://www.crystalclearsoftware.com/cgi-bin/boost_wiki/wiki.pl?Effective_UBLAS): The default uBLAS vector and matrix types are of variable size. Many linear algebra problems involve vectors with fixed size. 2 and 3 elements are common in geometry! Fixed size storage (akin to C arrays) can be implemented efficiently as it does not involve the overheads (heap management) associated with dynamic storage. uBLAS implements fixed sizes by changing the underling storage of a vector/matrix to a "bounded_array" from the default "unbounded_array". Alright, this bounded_vector<> thing is used to free you from specifying the underlying storage of the vector to a bounded_array<> of the specified size. Here I ask you: doesn't it look like this bounded vector thing has fixed size to you? Well, it doesn't have. At first I felt betrayed by the wiki, but then I reconsidered the meaning of "bounded" and I think I can let it pass. But in case you, like me (I'm still uncertain), is still wondering if this makes sense, what I found out is that the bounded_vector<> actually can be resized, it may only not be greater than the size specified as template parameter. So, first off, do you think they've had a good reason not to make a real fixed<< size vector or matrix type? Do you think it's okay to "sell" this bounded -- as opposed to fixed-size -- vector to the users of my library as a "fixed-size" vector replacement, even named "Vector3" or "Vector2", like the Effective uBLAS wiki did? Do you think I should somehow implement a vector with fixed size for this purpose? If so, how? (Sorry, but I'm really new to uBLAS; just tried it today) I am developing a 3D game. Should uBLAS be used for the calculations involved in this ("hey, geometry!", per Effective uBLAS wiki)? What replacement would you suggest, if not? -- edit And just in case, yes, I've read this warning: It should be noted that this only changes the storage uBLAS uses for the vector3. uBLAS will still use all the same algorithm (which assume a variable size) to manipulate the vector3. In practice this seems to have no negative impact on speed. The above runs just as quickly as a hand crafted vector3 which does not use uBLAS. The only negative impact is that the vector3 always store a "size" member which in this case is redundant [or isn't it? I mean......]. I see it uses the same algorithm, assuming a variable size, but if an operation were to actually change its size, shouldn't it be stopped (assertion)? ublas::bounded_vector<float,3> v3; ublas::bounded_vector<float,2> v2; v3 = v2; std::cout << v3.size() << '\n'; // prints 2 Oh, come on, isn't this just plain betrayal?

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  • Windows Server 2008 Antivirus Software with an API

    - by Dave Jellison
    I'm looking for an Antivirus package that is compliant with Windows Server 2008. That's not the hard part. What I need is an API layer on the Antivirus that i can call from managed .net code. For example: I am developing an Asp.Net (C#) website that allows users to upload files to the web server which the web site resides on. We have full control of the server so there are no security/rights issues on the server. I need to be able to run the antivirus algorithm on the newly uploaded files without (hopefully) shelling out to a command-ilne version of the software. Does anyone know of such a package?

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  • linux/shell: change a file's modify timestamp relatively?

    - by index
    My Canon camera produces files like IMG_1234.JPG and MVI_1234.AVI. It also timestamps those files. Unfortunately during a trip to another timezone several cameras were used, one of which did not have the correct time zone set - meta data mess.. Now I would like to correct this. Proposed algorithm: 1 read file's modify date 2 add delta, i.e. hhmmss (preferred: change timezone) 3 write new timestamp Unless someone knows a tool or a combination of tools that do the trick directly, maybe one could simplify the calculation using epoch time (seconds since ..) and whip up a shell script. Any help appreciated!

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  • if there are multiple kernel module can drive the same device, what is the rule to choose from them?

    - by Dyno Fu
    both pcnet32 and vmxnet can drive the device. $ lspci -k ... 02:01.0 Ethernet controller: Advanced Micro Devices [AMD] 79c970 [PCnet32 LANCE] (rev 10) Subsystem: Advanced Micro Devices [AMD] 79c970 [PCnet32 LANCE] Flags: bus master, medium devsel, latency 64, IRQ 19 I/O ports at 2000 [size=128] [virtual] Expansion ROM at dc400000 [disabled] [size=64K] Kernel driver in use: vmxnet Kernel modules: vmxnet, pcnet32 both kernel modules are loaded, $ lsmod | grep net pcnet32 32644 0 vmxnet 17696 0 mii 5212 1 pcnet32 as you see, kernel driver in use is vmxnet. is there any policy/algorithm in kernel how to choose from the candidates?

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  • Changing encryption settings for Microsoft Office 2010/2013

    - by iridescent
    Although there are Office 2013 settings to change how encryption is performed, when you encrypt Open XML Format files (.docx, .xslx, .pptx, and so on) the default values — AES (Advanced Encryption Standard), 128-bit key length, SHA1, and CBC (cipher block chaining) — provide strong encryption and should be fine for most organizations. Quoted from http://technet.microsoft.com/en-us/library/cc179125.aspx . I can't figure out where is the setting to change how encryption is performed. Is there any possible to change the encryption algorithm being used instead of the default AES-128 ? Thanks.

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  • DDNS Not Creating Journal (Dhcpd and Named)

    - by user130094
    * EDIT 1 * After monkeying with additional debug logging I see some log entries of interest. 27-Jul-2012 23:45:26.537 general: error: zone example.lan/IN/internal: journal rollforward failed: no more 27-Jul-2012 23:45:26.537 general: error: zone example.lan/IN/internal: not loaded due to errors. ^^^ If I can remedy the above messages I think I'll be good to go ^^^ * EDIT 2 * Grasping at straws I touched a forward and a reverse zone journal file and restarted named. Boom! Works. Despite documentation stating the files are created automatically and what I have seen before... dunno why but that did the trick. Also re-checked perms on the dir the files live in. As certain as I was, they were correct with named having rw. CentOS 6 (final) dhcpd 4.1.1-P1 named BIND 9.8.2rc1-RedHat-9.8.2-0.10.rc1.el6 Basic DHCP and DNS functionality are in place on 192.168.111.2. Clients are assigned addresses as intended and can resolve local DNS names as well as Internet names. My problem is that named's zone journal files are not created. chroot: /var/named/chroot I tried placing the zone files in various directories (/var/named/data, /var/named, /var/named/dynamic - no matter which dir with named owning and wide open perms I now get nowhere). Along the way I, at one point, got a permission denied when named tried to create the journal. Resolved the issue by: chown --recursive named:named /var/named chmod --recursive 777 /var/named The journal was then created and here's where things fell apart. I attempted to tame permissions to something more sane and broke it. Once changed and having restarted named it threw an error indicating the journal was out of sync (or something to that affect)... didn't matter since this is a new setup so I deleted it and now it is not recreated. Now though I see no errors in /var/log/messages, my chrooted /var/log/named.log, or chrooted /var/log/named.debug. I increased the debug level with 'rndc trace' - no love. Increased trace to 10, still nothing. SELinux is disabled... [root@server temp]# sestatus SELinux status: disabled dhcpd.conf... allow client-updates; ddns-update-style interim; subnet 192.168.111.0 netmask 255.255.255.224 { ... key dhcpudpate { algorithm hmac-md5; secret LDJMdPdEZED+/nN/AGO9ZA==; } zone example.lan. { primary 192.168.111.2; key dhcpudpate; } } named.conf... key dhcpudpate { algorithm hmac-md5; secret "LDJMdPdEZED+/nN/AGO9ZA=="; }; zone "example.lan" { type master; file "/var/named/dynamic/example.lan.db"; allow-transfer { none; }; allow-update { key dhcpudpate; }; notify false; check-names ignore; }; The following shows /var/log/named.log output of named starting up - no errors. 27-Jul-2012 21:33:39.349 general: info: zone 111.168.192.in-addr.arpa/IN/internal: loaded serial 2012072601 27-Jul-2012 21:33:39.349 general: info: zone example.lan/IN/internal: loaded serial 2012072501 27-Jul-2012 21:33:39.350 general: info: zone example2.lan/IN/internal: loaded serial 2012072501 27-Jul-2012 21:33:39.350 general: info: zone example3.lan/IN/internal: loaded serial 2012072601 27-Jul-2012 21:33:39.350 general: info: zone example4.lan/IN/internal: loaded serial 2012072501 27-Jul-2012 21:33:39.351 general: info: zone example5.lan/IN/internal: loaded serial 2012072501 27-Jul-2012 21:33:39.351 general: info: managed-keys-zone ./IN/internal: loaded serial 0 27-Jul-2012 21:33:39.351 general: info: zone example.lan/IN/external: loaded serial 2012072501 27-Jul-2012 21:33:39.352 general: info: zone example1.lan/IN/external: loaded serial 2012072501 27-Jul-2012 21:33:39.352 general: info: zone example2.lan/IN/external: loaded serial 2012072501 27-Jul-2012 21:33:39.352 general: info: zone example3.lan/IN/external: loaded serial 2012072501 27-Jul-2012 21:33:39.353 general: info: managed-keys-zone ./IN/external: loaded serial 0 27-Jul-2012 21:33:39.353 general: notice: running 27-Jul-2012 21:34:03.825 general: info: received control channel command 'trace 10' 27-Jul-2012 21:34:03.825 general: info: debug level is now 10 ...and /var/log/messages for a named start... Jul 27 23:02:04 server named[9124]: ---------------------------------------------------- Jul 27 23:02:04 server named[9124]: BIND 9 is maintained by Internet Systems Consortium, Jul 27 23:02:04 server named[9124]: Inc. (ISC), a non-profit 501(c)(3) public-benefit Jul 27 23:02:04 server named[9124]: corporation. Support and training for BIND 9 are Jul 27 23:02:04 server named[9124]: available at https://www.isc.org/support Jul 27 23:02:04 server named[9124]: ---------------------------------------------------- Jul 27 23:02:04 server named[9124]: adjusted limit on open files from 4096 to 1048576 Jul 27 23:02:04 server named[9124]: found 2 CPUs, using 2 worker threads Jul 27 23:02:04 server named[9124]: using up to 4096 sockets Jul 27 23:02:04 server named[9124]: loading configuration from '/etc/named.conf' Jul 27 23:02:04 server named[9124]: using default UDP/IPv4 port range: [1024, 65535] Jul 27 23:02:04 server named[9124]: using default UDP/IPv6 port range: [1024, 65535] Jul 27 23:02:04 server named[9124]: listening on IPv4 interface eth0, 192.168.111.2#53 Jul 27 23:02:04 server named[9124]: generating session key for dynamic DNS Jul 27 23:02:04 server named[9124]: sizing zone task pool based on 12 zones Jul 27 23:02:04 server named[9124]: set up managed keys zone for view internal, file 'dynamic/3bed2cb3a3acf7b6a8ef408420cc682d5520e26976d354254f528c965612054f.mkeys' Jul 27 23:02:04 server named[9124]: set up managed keys zone for view external, file 'dynamic/3c4623849a49a53911c4a3e48d8cead8a1858960bccdea7a1b978d73ec2f06d7.mkeys' Jul 27 23:02:04 server named[9124]: command channel listening on 127.0.0.1#953 What can I do to troubleshoot this further? It almost seems as though dhcpd is not triggering the update. Maybe I should troubleshoot here and, if so, how? Many thanks.

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  • How secure is Microsoft 2007's encryption?

    - by ericl42
    I've read some various articles about Microsoft's encryption, and from what I gather, 2007 is secure using all default options due to it using AES, and 2000 and 2003 can be configured secure by changing the default algorithm to AES. I was wondering if anyone else has read any other articles or know of any specific vulnerabilities involved with how they implement the encryption. I would like to be able to tell users that they can use this to send semi sensitive documents as long as they use AES and a strong password. Thanks for the information.

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  • Reshape linux md raid5 that is already being reshaped?

    - by smammy
    I just converted my RAID1 array to a RAID5 array and added a third disk to it. I'd like to add a fourth disk without waiting fourteen hours for the first reshape to complete. I just did this: mdadm /dev/md0 --add /dev/sdf1 mdadm --grow /dev/md0 --raid-devices=3 --backup-file=/root/md0_n3.bak The entry in /proc/mdstat looks like this: md0 : active raid5 sdf1[2] sda1[0] sdb1[1] 976759936 blocks super 0.91 level 5, 64k chunk, algorithm 2 [3/3] [UUU] [>....................] reshape = 1.8% (18162944/976759936) finish=834.3min speed=19132K/sec Now I'd like to do this: mdadm /dev/md0 --add /dev/sdd1 mdadm --grow /dev/md0 --raid-devices=4 --backup-file=/root/md8_n4.bak Is this safe, or do I have to wait for the first reshape operation to complete? P.S.: I know I should have added both disks first, and then reshaped from 2 to 4 devices, but it's a little late for that.

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  • Roguelike FOV problem

    - by Manderin87
    I am working on a college compsci project and I would like some help with a field of view algorithm. I works mostly, but in some situations the algorithm sees through walls and hilights walls the player should not be able to see. void cMap::los(int x0, int y0, int radius) { //Does line of sight from any particular tile for(int x = 0; x < m_Height; x++) { for(int y = 0; y < m_Width; y++) { getTile(x,y)->setVisible(false); } } double xdif = 0; double ydif = 0; bool visible = false; float dist = 0; for (int x = MAX(x0 - radius,0); x < MIN(x0 + radius, m_Height); x++) { //Loops through x values within view radius for (int y = MAX(y0 - radius,0); y < MIN(y0 + radius, m_Width); y++) { //Loops through y values within view radius xdif = pow( (double) x - x0, 2); ydif = pow( (double) y - y0, 2); dist = (float) sqrt(xdif + ydif); //Gets the distance between the two points if (dist <= radius) { //If the tile is within view distance, visible = line(x0, y0, x, y); //check if it can be seen. if (visible) { //If it can be seen, getTile(x,y)->setVisible(true); //Mark that tile as viewable } } } } } bool cMap::line(int x0,int y0,int x1,int y1) { bool steep = abs(y1-y0) > abs(x1-x0); if (steep) { swap(x0, y0); swap(x1, y1); } if (x0 > x1) { swap(x0,x1); swap(y0,y1); } int deltax = x1-x0; int deltay = abs(y1-y0); int error = deltax/2; int ystep; int y = y0; if (y0 < y1) ystep = 1; else ystep = -1; for (int x = x0; x < x1; x++) { if ( steep && getTile(y,x)->isBlocked()) { getTile(y,x)->setVisible(true); getTile(y,x)->setDiscovered(true); return false; } else if (!steep && getTile(x,y)->isBlocked()) { getTile(x,y)->setVisible(true); getTile(x,y)->setDiscovered(true); return false; } error -= deltay; if (error < 0) { y = y + ystep; error = error + deltax; } } return true; } If anyone could help me make the first blocked tiles visible but stops the rest, I would appreciate it. thanks, Manderin87

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  • Service haproxy error

    - by user128296
    I want to configure Haproxy for outgoing mail load balancing. my configuration file /etc/haproxy.cfg is. global maxconn 4096 # Total Max Connections. This is dependent on ulimit daemon nbproc 4 # Number of processing cores. Dual Dual-core Opteron is 4 cores for example. defaults mode tcp listen smtp_proxy 199.83.95.71:25 mode tcp option tcplog balance roundrobin # Load Balancing algorithm ## Define your servers to balance server r23.lbsmtp.org 74.117.x.x:25 weight 1 maxconn 512 check server r15.lbsmtp.org 199.71.x.x:25 weight 1 maxconn 512 check And when i start service haproxy i get this error. Starting HAproxy: [ALERT] 244/172148 (7354) : cannot bind socket for proxy smtp_proxy. Aborting. Please tell me where i am doing mistake.help will appreciated.

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