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  • preg_match not defined in php4 in openwrt?

    - by user2723949
    I have installed the packages PHP4 and PHP4-CGI in openwrt through command line (opkg install) when I tried this simple code by putting this in the openwrt www folder, <?php $subject = "abcdef"; $pattern = '/^def/'; preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE, 3); print_r($matches); ?> I got this error Fatal error: Call to undefined function: preg_match() in /www/phptest.php on line 4 but php manual says preg_match() is defined in php4 also.. What might be the reason for this error? Is there any other PHP module that is to be installed? Or is there any alternate method for preg_match?

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  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • Joining a one-to-many association with a many-to-many association in Rails 3

    - by Maz
    Hi all, I have a many-to-many association between a User class and a Table class. Additionally, i have a one-to-many association between the User and the Table (one User ultimately owns the table). I am trying to access all of the tables which the user may access (essintally joining both associations). Additionally, it would be nice to do this this with named_scope (now scope) Here's what I have so far: class User < ActiveRecord::Base acts_as_authentic attr_accessible :email, :password, :password_confirmation has_many :feedbacks has_many :tables has_many :user_table_permissions has_many :editableTables, :class_name => "Table", :through => :user_table_permissions def allTables editableTables.merge(tables) end end Thanks.

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  • What is the fastest way to validate that a field has no more than n words?

    - by James A. Rosen
    I have a Ruby-on-Rails model: class Candidate < ActiveRecord::Base validates_presence_of :application_essay validate :validate_length_of_application_essay protected def validate_length_of_application_essay return if application_essay.blank? # don't add a second error message if they didn't fill it out errors.add(:application_essay, :too_long), unless ... end end Without dropping into C, what is the fastest way to check that the application_essay contains no more than 500 words? You can assume that most essays will be at least 200 words, are unlikely to be more than 5000 words, and are in English (or the pseudo-English sometimes called "business-ese"). You can also classify anything you want as a "word" as long as your classification would be immediately obvious to a typical user. (NB: this is not the place to debate what a "typical user" is :) )

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  • Django: text fixture fails to load

    - by Esteban Feldman
    Hi all, Did a dumpdata of my project, then in my new test I added it to fixtures. from django.test import TestCase class TestGoal(TestCase): fixtures = ['test_data.json'] def test_goal(self): """ Tests that 1 + 1 always equals 2. """ self.failUnlessEqual(1 + 1, 2) When running the test I get: Problem installing fixture 'XXX/fixtures/test_data.json': DoesNotExist: XXX matching query does not exist. But manually doing loaddata works fine does not when the db is empty. I do a dropdb, createdb a simple syncdb the try loaddata and it fails, same error. Any clue? Python version 2.6.5, Django 1.1.1

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  • How can I construct and parse a JSON string in Scala / Lift

    - by David Carlson
    I am using JsonResponse to send some JSON to the client. To test that I am sending the correct response it seemed natural to me to parse the resulting JSON and validate against a data structure rather than comparing substrings. But for some reason I am unable to parse the JSON I just constructed: def tryToParse = { val jsObj :JsObj = JsObj(("foo", "bar")); // 1) val jsObjStr :String = jsObj.toJsCmd // 2) jsObjStr is: "{'foo': 'bar'}" val result = JSON.parseFull(jsObjStr) // 3) result is: None // the problem seems to be caused by the quotes: val works = JSON.parseFull("{\"foo\" : \"bar\"}") // 4) result is: Some(Map(foo -> bar)) val doesntWork = JSON.parseFull("{'foo' : 'bar'}") // 5) result is: None } How do I programmatically construct a valid JSON message in Scala/Lift that can also be parsed again?

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  • How can I tell Phusion Passenger which python to use?

    - by Mike
    I'm using Phusion Passenger with a ruby app and I'd also like to set it up to work with an django appengine app I'm working on. Googling for "passenger_wsgi.py" I was able to get the following very simple non-django app working on passenger: passenger_wsgi.py: def application(environ, start_response): response_headers = [('Content-type','text/plain')] start_response('200 OK', response_headers) return ['Hello World!\n'] However, if I add the line import django.core.handlers.wsgi into the mix, I get 'An error occurred importing your passenger_wsgi.py'. By printing out the sys.path I've discovered that at least part of the reason is because Passenger is using the wrong python installation on my machine. How can I configure Passenger (on apache) to use /opt/local/bin/python2.5 instead of the system default python?

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  • django getting current user id

    - by dana
    hello, i have a mini app where users can login, view their profile, and follow each other. 'Follow' is a relation like a regular 'friend' relationship in virtual communities, but it is not necessarily reciprocal, meaning that one can follow a user, without the need that the user to be following back that person who follows him. my problem is: if i am a logged in user, and i navigate to a profile X, and push the button follow, how can i take the current profile id ?(current profile meaning the profile that I, the logged in user, am viewing right now.) the view: def follow(request): if request.method == 'POST': form = FollowForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.initiated_by = request.user u = User.objects. what here? new_obj.follow = u new_obj.save() return HttpResponseRedirect('.') else: form = FollowForm() return render_to_response('followme/follow.html', { 'form': form, }, context_instance=RequestContext(request)) thanks in advance!

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  • In Sinatra, best way to serve iPhone layout vs. normal layout?

    - by Doug
    I'm writing a Sinatra app which needs to render different layouts based on whether the user is using an iPhone or a regular browser. I can detect the browser type using Rack-Mobile-Detect but I'm not sure of the best way to tell Sinatra which layout to use. Also, I have a feeling that how I choose to do this may also break page caching. Is that true? Example code: require 'sinatra/base' require 'haml' require 'rack/mobile-detect' class Orca < Sinatra::Base use Rack::MobileDetect helpers do def choose_layout if request.env['X_MOBILE_DEVICE'] == :iPhone # use iPhone layout else # use normal layout end end end before do # should I use a before filter? choose_layout() end get '/' do haml :home # with proper layout end end #Class Orca

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  • Suggestions on how to track tag count for a particular object

    - by Robin Fisher
    Hi, I'm looking for suggestions on how to track the number of tags associated with a particular object in Rails. I'm using acts_as_taggable_on and it's working fine. What I would like to be able to do is search for all objects that have no tags, preferably through a scope i.e. Object.untagged.all My first thought was to use an after_save callback to update an attribute called "taggings_count" in my model: def update_taggings_count self.taggings_count = self.tag_list.size self.save end Unfortunately, this does the obvious thing of putting me in an infinite loop. I need to use an after_save callback because the tag_list is not updated until the main object is saved. Would appreciate any suggestions as I'm on the verge of rolling my own tagging system. Regards Robin

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  • Ruby: rules for implicit hashes

    - by flyer
    Why second output shows me only one element of Array? Is it still Array or Hash already? def printArray(arr) arr.each { | j | k, v = j.first printf("%s %s %s \n", k, v, j) } end print "Array 1\n" printArray( [ {kk: { 'k1' => 'v1' }}, {kk: { 'k2' => 'v2' }}, {kk: { 'k3' => 'v3' }}, ]) print "Array 2\n" printArray( [ kk: { 'k1' => 'v1' }, kk: { 'k2' => 'v2' }, kk: { 'k3' => 'v3' }, ]) exit # Output: # # Array 1 # kk {"k1"=>"v1"} {:kk=>{"k1"=>"v1"}} # kk {"k2"=>"v2"} {:kk=>{"k2"=>"v2"}} # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}} # Array 2 # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}}

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  • Rails - how do you create a user index page like stack overflows with multiple tabs whilst keeping t

    - by adam
    On stackoverflow in the users profile area there are many tabs which all display differing information such as questions asked and graphs. Its the same view though and im wondering hows its best to achieve this in rails whilst keeping the controller skinny and logic in the view to a minimum. def index @user = current_user case params[:tab_selected] when "questions" @data = @user.questions when "answers" @sentences = @user.answers else @sentences = @user.questions end respond_to do |format| format.html # index.html.erb nd end but how do i process this in the index view without a load of if and else statments. And if questions and answers are presented differently whats the best way to go about this.

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  • PyParsing: Is this correct use of setParseAction()?

    - by Rosarch
    I have strings like this: "MSE 2110, 3030, 4102" I would like to output: [("MSE", 2110), ("MSE", 3030), ("MSE", 4102)] This is my way of going about it, although I haven't quite gotten it yet: def makeCourseList(str, location, tokens): print "before: %s" % tokens for index, course_number in enumerate(tokens[1:]): tokens[index + 1] = (tokens[0][0], course_number) print "after: %s" % tokens course = Group(DEPT_CODE + COURSE_NUMBER) # .setResultsName("Course") course_data = (course + ZeroOrMore(Suppress(',') + COURSE_NUMBER)).setParseAction(makeCourseList) This outputs: >>> course.parseString("CS 2110") ([(['CS', 2110], {})], {}) >>> course_data.parseString("CS 2110, 4301, 2123, 1110") before: [['CS', 2110], 4301, 2123, 1110] after: [['CS', 2110], ('CS', 4301), ('CS', 2123), ('CS', 1110)] ([(['CS', 2110], {}), ('CS', 4301), ('CS', 2123), ('CS', 1110)], {}) Is this the right way to do it, or am I totally off? Also, the output of isn't quite correct - I want course_data to emit a list of course symbols that are in the same format as each other. Right now, the first course is different from the others. (It has a {}, whereas the others don't.)

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  • Django - Passing arguments to models through ForeignKey attributes

    - by marshall
    I've got a class like this: class Image (models.Model): ... sizes = ((90,90), (300,250)) def resize_image(self): for size in sizes: ... and another class like this: class SomeClassWithAnImage (models.Model): ... an_image = models.ForeignKey(Image) what i'd like to do with that class is this: class SomeClassWithAnImage (models.Model): ... an_image = models.ForeignKey(Image, sizes=((90,90), (150, 120))) where i'm can specify the sizes that i want the Image class to use to resize itself as a argument rather than being hard coded on the class. I realise I could pass these in when calling resize_image if that was called directly but the idea is that the resize_image method is called automatically when the object is persisted to the db. if I try to pass arguments through the foreign key declaration like this i get an error straight away. is there an easy / better way to do this before I begin hacking down into django?

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  • HTTPS and HTTParty - Timeout and EOF

    - by ferparra
    Hi all, I'm trying to post something to an HTTPS resource, but it seems it doesn't work. My code look something like this: require 'httparty' class MyClass include HTTParty base_uri "https://mydomain.com:8085/search" basic_auth 'admin', 'changeme' format :xml def mymethod self.class.post('/job', :query => {:search => "*"}) end end As you can see, I've defined an URI with 'https' included, so it should set the use_ssl property for the Net::HTTPS library automatically. For some reason, Net::HTTP is requested, and I never get in touch with the server, so I end up with an EOF. Any clues?

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  • link_to for calling an action, instead of a button_to

    - by Brian Roisentul
    I'd like to call an action with a link_to button without being redirected to another page(I don't want ajax). For you to have an idea, I'm trying to accomplish a sort "link button" in a search page. So, when the link is clicked, the page should be refreshed showing the list ordered as I tell it in the action. If I do the following in my view, it will ask me for a template called as the action, and I don't want it: <%= link_to 'M&Aacute;S RELEVANTES', search_filter_relevance_path %> My routes file looks like this: map.search_filter_relevance "/anuncios/buscar", :controller => 'announcements', :action => 'search_filter_relevance' And my controller looks like this(I haven't developed the functionality yet): def search_filter_relevance end Any help on this will be appreciated.

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  • Observer not clearing cache in Rails 2.3.2 - please help.

    - by Jason
    Hi, We are using Rails 2.3.2, Ruby 1.8 & memcache. In my Posts controller I have: cache_sweeper Company::Caching::Sweepers::PostSweeper, :only => [:save_post] I have created the following module: module Company module Caching module Sweepers class PostSweeper < ActionController::Caching::Sweeper observe Post def after_save(post) Rails.cache.delete("post_" + post.permalink) end end end end end but when the save_post method is invoked, the cache is never deleted. Just hoping someone can see what I am doing wrong here. Thanks.

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  • changing order of items in tkinter listbox

    - by user1104854
    Is there an easier way to change the order of items in a tkinter listbox than deleting the values for specific key, then re-entering new info? For example, I want to be able to re-arrange items in a listbox. If I want to swap the position of two, this is what I've done. It works, but I just want to see if there's a quicker way to do this. def moveup(self,selection): value1 = int(selection[0]) - 1 #value to be moved down one position value2 = selection #value to be moved up one position nameAbove = self.fileListSorted.get(value1) #name to be moved down nameBelow = self.fileListSorted.get(value2) #name to be moved up self.fileListSorted.delete(value1,value1) self.fileListSorted.insert(value1,nameBelow) self.fileListSorted.delete(value2,value2) self.fileListSorted.insert(value2,nameAbove)

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  • Query for model by key

    - by Jason Hall
    What I'm trying to do is query the datastore for a model where the key is not the key of an object I already have. Here's some code: class User(db.Model): partner = db.SelfReferenceProperty() def text_message(self, msg): user = User.get_or_insert(msg.sender) if not user.partner: # user doesn't have a partner, find them one # BUG: this line returns 'user' himself... :( other = db.Query(User).filter('partner =', None).get() if other: # connect users else: # no one to connect to! The idea is to find another User who doesn't have a partner, that isn't the User we already know. I've tried filter('key !=, user.key()), filter('__key__ !=, user.key()) and a couple others, and nothing returns another User who doesn't have a partner. filter('foo !=, user.key()) also returns nothing, for the record.

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  • acts_as_taggable_on and auto_complete returning no results

    - by Sean Johnson
    I'm using acts_as_taggable_on in a model, and am trying to implement the auto_complete plugin. It seems as though I have everything hooked up correctly, but the search isn't returning any results. Here's what I have so far: In the view: <%= text_field_with_auto_complete(:link, :tag_list, {}, {:tokens => ','}) %> In the controller: def auto_complete_for_link_tag_list @tags = Link.tag_counts_on(:tags).where('tags.name LIKE ?', params[:link][:tag_list]) render :inline => "<%= auto_complete_result(@tags, 'name') %>", :layout => false logger.info "#{@tags.size} tags found." end The logger keeps returning 0 tags, and nothing shows up in the view (yeah, the layout includes the javascript defaults). Any thoughts or advice would be awesome.

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  • Optimizing BeautifulSoup (Python) code

    - by user283405
    I have code that uses the BeautifulSoup library for parsing, but it is very slow. The code is written in such a way that threads cannot be used. Can anyone help me with this? I am using BeautifulSoup for parsing and than save into a DB. If I comment out the save statement, it still takes a long time, so there is no problem with the database. def parse(self,text): soup = BeautifulSoup(text) arr = soup.findAll('tbody') for i in range(0,len(arr)-1): data=Data() soup2 = BeautifulSoup(str(arr[i])) arr2 = soup2.findAll('td') c=0 for j in arr2: if str(j).find("<a href=") > 0: data.sourceURL = self.getAttributeValue(str(j),'<a href="') else: if c == 2: data.Hits=j.renderContents() #and few others... c = c+1 data.save() Any suggestions? Note: I already ask this question here but that was closed due to incomplete information.

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  • Rails Association issue with NoMethodError in event_controller

    - by pmanning
    Kinda a noob trying to understand I think I need to define rsvps but not sure what to put... I'm trying to add a Join/Unjoin button to user created Events, similar to a Follow/Unfollow button for Users. NoMethodError in Events#show undefined method `model_name' for NilClass:Class in line #1 _unjoin.html.erb 1: <%= form_for(current_user.rsvps.find_by_joined_id(@event), 2: html: { method: :delete }) do |f| %> 3: <%= f.submit "Leave", class: "btn btn-large" %> 4: <% end %> events_controller.rb def show @event = Event.find(params[:id]) @user = current_user end Here's the models rsvp.rb class Rsvp < ActiveRecord::Base attr_accessible :joined_id belongs_to :joiner, class_name: "User" belongs_to :joined, class_name: "User" validates :joiner_id, presence: true validates :joined_id, presence: true end user.rb has_many :rsvps, foreign_key: "joiner_id", dependent: :destroy has_many :joined_events, through: :rsvps, source: :joined has_many :reverse_rsvps, foreign_key: "joined_id", class_name: "Rsvp", dependent: :destroy has_many :joiners, through: :reverse_rsvps, source: :joiner event.rb belongs_to :user has_many :rsvps, foreign_key: "joiner_id", dependent: :destroy has_many :joined_events, through: :rsvps, source: :joined has_many :reverse_rsvps, foreign_key: "joined_id", class_name: "Rsvp", dependent: :destroy has_many :joiners, through: :reverse_rsvps, source: :joiner

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  • Django paging object has issues with Postgresql QuerySets

    - by pivotal
    I have some django code that runs fine on a SQLite database or on a MySQL database, but it runs into problems with Postgres, and it's making me crazy that no one has has this issue before. I think it may also be related to the way querysets are evaluated by the pager. In a view I have: def index(request, page=1): latest_posts = Post.objects.all().order_by('-pub_date') paginator = Paginator(latest_posts, 5) try: posts = paginator.page(page) except (EmptyPage, InvalidPage): posts = paginator.page(paginator.num_pages) return render_to_response('blog/index.html', {'posts' : posts}) And inside the template: {% for post in posts.object_list %} {# some rendering jazz #} {% endfor %} This works fine with SQLite, but Postgres gives me: Caught TypeError while rendering: 'NoneType' object is not callable To further complicate things, when I switch the Queryset call to: latest_posts = Post.objects.all() Everything works great. I've tried re-reading the documentation, but found nothing, although I admit I'm a bit clouded by frustration at this point. What am I missing? Thanks in advance.

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  • Rails 3 respond_to: default format?

    - by bdorry
    I am converting a Rails 2 application to Rails 3. I currently have a controller set up like the following: class Api::RegionsController < ApplicationController respond_to :xml, :json end with and an action that looks like the following: def index @regions = Region.all respond_with @regions end The implementation is pretty straightforward, api/regions, api/regions.xml and api/regions.json all respond as you would expect. The problem is that I want api/regions by default to respond via XML. I have consumers that expect an XML response and I would hate to have them change all their URLs to include .xml unless absolutely necessary. In Rails 2 you would accomplish that by doing this: respond_to do |format| format.xml { render :xml => @region.to_xml } format.json { render :json => @region.to_json } end But in Rails 3 I cannot find a way to default it to an XML response. Any ideas?

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