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  • I need to add ranges and if a range is missed while adding i should display a message

    - by sabita
    EXAMPLE :if i add a range {1,10} and another range{15,20} i should get a message saying the ranges from 11 to 14 are missing. for (int i = 0; i < weightdata.Count; i++) { if ((i == 0 && i<weightdata.Count-1) && ((MaximumValue < weightdata[i].MinRange && BaseAmount < weightdata[i].BaseAmount)|| (MaximumValue>weightdata[i].MinRange && MaximumValue<weightdata[i+1].MinRange && BaseAmount>weightdata[i].BaseAmount &&BaseAmount>weightdata[i].BaseAmount))) { hdnflag.Value = ""; flag = false; if (weightdata[i].MinRange - MaximumValue > 1) { AlertMsg = string.Format(MinSpeedReqMsg.ErrorMessage, MaximumValue,weightdata[i].MinRange); flag = true; } break; } else if ((i == weightdata.Count - 1 && weightdata[i].MaxRange != null) && ((MinimumValue > weightdata[i].MaxRange && BaseAmount > weightdata[i].BaseAmount))) { hdnflag.Value = ""; flag = false; if (MinimumValue - weightdata[i].MaxRange > 1) { AlertMsg = string.Format(MinSpeedReqMsg.ErrorMessage, MaximumValue, weightdata[i].MinRange); flag = true; } break; } else if ((i > 0 && i < weightdata.Count - 1) && (MinimumValue > weightdata[i].MaxRange && MaximumValue < weightdata[i + 1].MinRange && MaximumValue > weightdata[i].MaxRange && BaseAmount > weightdata[i].BaseAmount && BaseAmount < weightdata[i + 1].BaseAmount)) { hdnflag.Value = ""; flag = false; if (MinimumValue - weightdata[i].MaxRange > 1) { AlertMsg =string.Format(MinSpeedReqMsg.ErrorMessage ,weightdata[i].MaxRange, MinimumValue); flag = true; } break; }

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  • Time Zone conversion form stringdate

    - by Kishore
    Hi, I have a stringdate 16-MAY-2010 23:04:44 which i need to convert to gmt time zone that is the out put required is 17-May-2010 12:03:03. I used date formatters to convert but the result i am getting is not in the format i required.I am sending the code please let me know if i am doing correct or not Here is the code: NSString *timeStamp = [format stringFromDate:[NSDate date]]; NSString *output = [timeConv dateStringFromString:timeStamp]; (NSString *)dateStringFromString:(NSString *)sourceString { NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease]; [dateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4]; [dateFormatter setDateFormat:@"dd-MMMM-yyyy HH:MM:ss"]; NSTimeZone *gmt = [NSTimeZone timeZoneWithAbbreviation:@"GMT"]; [dateFormatter setTimeZone:gmt]; NSDate *date = [dateFormatter dateFromString:sourceString]; return [dateFormatter stringFromDate:date]; } The out put i am getting is the same old time without conversion. so please let me know the correct solution.

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  • How can one configure Hudson to integrate with Sventon?

    - by mark
    Dear ladies and sirs. Hudson ver. 1.353 Sventon ver. 2.14 I just cannot figure out how to configure Hudson to work with Sventon. It seems that the path format that Hudson expects from Sventon is not the format used by Sventon. Any ideas? Thanks. UPDATE Given an SVN repository with the name of windows, the Sventon URL path to the repository is http://dev-builder:8080/svn/repos/windows/list/ However, Hudson expects something like http://dev-builder:8080/svn/repobrowser.svn?name=windows Can anyone explain how this should be configured?

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  • Convert unusual string into date time

    - by BlueChippy
    I have a system that outputs dates in the format "1{yy}{MM}{dd}" and I am trying to find a good way to parse it back into a real date. At the moment I am using this: var value = "1110825"; var z = Enumerable.Range(1,3).Select(i => int.Parse(value.Substring(i, 2))).ToList(); var d = new DateTime(2000 + z[0], z[1], z[2]); but I'm sure there's a cleaner/more efficient way to do it? I've tried DT.ParseExact, but can't find a suitable format string to use.

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  • How do you ensure a mimetype in asp.net?

    - by Sem Dendoncker
    Hello, I have the following code to export a zip file: byte[] buffer = FileUtil.FileToByteArray(zipLocation, true); // push the memory data to the client. _ctx.Response.ContentType = "application/zip"; _ctx.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", String.Format("map{0}.zip", mapId))); _ctx.Response.BinaryWrite(buffer); This code works great. After every export I get a perfectly made zipfile. The problem however is that when I try to import it, the mimetype sometimes is "application/empty". Now I wonder how can I ensure that the mimetype is always added? Cheers, M.

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  • Override decimal ToString() method

    - by Jimbo
    I have a decimal datatype with a precision of (18, 8) in my database and even if its value is simply 14.765 it will still get displayed as 14.76500000 when I use Response.Write to return its value into a webpage. Is it possible to override its default ToString method to return the number in the format #,###,##0.######## so that it only displays relevant decimal places? UPDATE I'm assuming that when one outputs number on a page like <%= item.price %> (where item.price is a number) that the number's ToString method is being called? I'm trying to avoid having to change every instance where the value is displayed by defaulting the ToString() format somehow.

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  • Managing test data for Junit tests.

    - by nobody
    Hi, We are facing one problem in managing test data(xmls which is used to create mock objects). The data which we have currently has been evolved over a long period of time. Each time we add a new functionality or test case we add new data to test that functionality. Now, the problem is when the business requirement changes the format( like length or format of a variable) or any change which the test data doesn't support , we need to change the entire test data which is 100s of MBs in size. Could anyone suggest a better method or process to overcome this problem? Any suggestion would be appreciated.

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  • String as \x03\x00\x00\x00 to integer

    - by marta
    Helo: I have a question, that I solved in c, but now I want to do it in hava: I have a String like: '\x03\x00\x00\x00' This is representing an hexadecimal value of a integer. I transform to 0x03\0x00... And now I want to obtain the integer, but I don't know how to do it in java could someone give me some idea ? Thanks in advance (Is it some way to use this format ('\x03\x00\x00\x00' ) directly without use byte[] arrays? and in C can I use this format directly to build a integer (int)?)

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  • RFC822 Timezone Parsing in Java

    - by Jamen
    Hi, I have a JS date that is being converted by Dojo into RFC822 format. The function call - dojo.date.toRfc3339(jsDate), generates the following date - 2007-02-26T20:15:00+02:00. I have an application that uses a Java date SimpleDateFormat to parse in the dates generated above. I am having problems parsing this date format due to the timezone. I have attempted to use yyyy-mm-DD'T'hh:mm:ssZ This fails as the 'Z' for timezone doesn't expect a ':' character. Does anyone know how I would specify a pattern to handle a RFC822 date with the ':'? Thanks Jamen

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  • issue with c# xml documentation

    - by galford13x
    I have the following comment. /// <summary> /// MSDN Time Format compatible with <see cref="DateTime.ParseExact(string, string, IFormatProvider)"/> /// </summary> /// <returns>MSDN Time Format compatible with <see cref="DateTime.ParseExact(string, string, IFormatProvider)"/></returns> but I'm not sure why I receive the following warning Warning 7 XML comment on 'MSLab.DateTime.SystemTimeProvider.GetTimeFormat()' has cref attribute 'DateTime.ParseExact(string, string, IFormatProvider)' that could not be resolved F:\My Documents\Visual Studio 2010\Projects\MSLab\trunk\MSLab\MSLab\DateTime\SystemTimeProvider.cs 110 57 MSLab

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  • inputMismatchException Java reading doubles from plain text file

    - by user939287
    Using double variable = inputFile.nextDouble(); Gives the mismatch error and I can't figure out why... Anyone know what's up? The input file is just a bunch of doubles like 5.0... Okay here is the code snippet String fileName; Scanner scanner = new Scanner(System.in); System.out.println("\nEnter file name that contains the matrix and vector: "); fileName = scanner.nextLine(); Scanner inputFile = new Scanner(fileName); double a1 = inputFile.nextDouble(); the input file is a plain text document .txt in this format 5.0 4.0 -3.0 4.0 2.0 5.0 6.0 5.0 -2.0 -13.0 4.0 12.0 I don't understand why it wouldn't take those as doubles... As far as what its expecting the format of the file to be... I suppose binary? isn't that the default? I didn't specify in the code...

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  • Read video information(date created)?

    - by Lynx
    In window, i can get the date created of the video from properties(right click). I have a few idea on this but i dont know how to do it. 1. Get the video information directly from video(like in windows), 2. By extracting the video name to get the date created(The video's name is in date format, which is the time it created). And i also using taglib-sharp to get the video duration and resolution, but i cant find any sample code on how to get the video creation date. Note: video name in date format - example, 20121119_125550.avi Edit Found this code and so far its working string fileName = Server.MapPath("//video//20121119_125550.avi"); FileInfo fileInfo = new FileInfo(fileName); DateTime creationTime = fileInfo.CreationTime; Output: 2012/11/19 12:55:50 For the file's name, i will add another string in name. For example User1-20121119_125550.avi.avi, so it will get complicated after that.

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  • Creating methods with infinite overloads ? (.NET)

    - by MarceloRamires
    In C# you can do this: foo = string.Format("{0} {1} {2} {3} ...", "aa", "bb", "cc" ...); This method Format() accepts infinite parameters, being the first one how the string should be formatted and the rest are values to be put in the string. Today I've come to a situation where I had to get a set of strings and test them, then I remembered this language functionality, but I had no clue. After a few unsuccessful web searches, I've realised it would be more prudent to just get an array, which didn't make me quite satisfied. Q: How do I make a function that accepts infinite parameters? And how do I use it ?

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  • C# + String Formatting

    - by user208662
    Hello, I feel like I'm trying to do something simple but I am not getting the result I want. I want to display a basic number, that will always be positive. I do not want any leading zeros but I want thousands separators. For instance, for the following inputs, I want the following outputs: 3 -> 3 30 -> 30 300 -> 300 3000 -> 3,000 30000 -> 30,000 300000 -> 300,000 Currently, in an attempt to do this, I'm using the following formatting code: string text = "*Based on " + String.Format("{0:0,0}", total) + " entries"; Currently, the output looks like this: 3 -> 03 3000 -> 3,000 You can see how a leading "0" is added when the thousands separator is not necessary. How do I properly format my numbers? Thank you

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  • What are these folders for? Can I remove them? How?

    - by Water Cooler v2
    In a folder on the SVN server/repository that is designated for our project, there have appeared the following folders: branches/ conf/ db/ hooks/ locks/ tags/ trunk/ README.txt (file) format (file) We have all the code in the trunk folder. There were, as far as I can remember, only 3 or 4 folders earlier. Within the trunk folder, too, there are now these folders. OurCode/ conf/ db/ hooks/ locks/ README.txt (file) format (file) I understand many of these folders or files are not necessary, but I can't be too sure. My questions are: 1) What are each of these files and/or folders for? 2) Which are the ones that are not necessary? 3) How may I remove them from the server repository?

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  • Perl date function/module able to understand full unabbreviated months.

    - by s2cuts
    Let's say I read in a string from somewhere that contains a date, and it's date format doesn't abbreviate the month. Is there a module that can handle reading it in, and then outputting it to whichever format I choose? I've taken a quick look through CPAN, and every date module I looked at didn't seem to accommodate an unabbreviated month. Thanks for any help EDIT: As an example, say we have a string like this; "2 February 1988". Now we want to convert it into "1988-02-02" (YYYY-MM-DD).

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  • Ruby: Parse Excel 95-2003 files?

    - by Larry K
    Is there a way to read Excel 97-2003 files from Ruby? Background I'm currently using the Ruby Gem parseexcel -- http://raa.ruby-lang.org/project/parseexcel/ But it is an old port of the perl module. It works fine, but the latest format it parses is Excel 95. And guess what? Excel 2007 will not produce the Excel 95 format. John McNamara has taken over duties as the maintainer for the Perl Excel parser, see http://search.cpan.org/~jmcnamara/Spreadsheet-ParseExcel-0.55/lib/Spreadsheet/ParseExcel.pm The current version will parse Excel 95-2003 files. But is there a port to Ruby? My other thought is to build some Ruby to Perl glue code to enable use of the Perl library itself from Ruby. Eg, see http://stackoverflow.com/questions/451636/whats-the-best-way-to-export-utf8-data-into-excel/620612#620612 (I think it would be much faster to write the glue code than to port the parser.) Thanks, Larry

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  • problem in extracting the data from text file

    - by parijat24
    hello , i am new to python , and I want to extract the data from this format FBpp0143497 5 151 5 157 PF00339.22 Arrestin_N Domain 1 135 149 83.4 1.1e-23 1 CL0135 FBpp0143497 183 323 183 324 PF02752.15 Arrestin_C Domain 1 137 138 58.5 6e-16 1 CL0135 FBpp0131987 60 280 51 280 PF00089.19 Trypsin Domain 14 219 219 127.7 3.7e-37 1 CL0124 to this format FBpp0143497 5 151 Arrestin_N 1.1e-23 FBpp0143497 183 323 Arrestin_C 6e-16 I have written code in hope that it works but it does not work , please help! file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') rec = file.read() for line in rec : field = line.split("\t") print field print field[:] print '>',field[0] print field[1], field[2], field[6], field[12] the hmmtext file is FBpp0143497 5 151 5 157 PF00339.22 Arrestin_N Domain 1 135 149 83.4 1.1e-23 1 CL0135 FBpp0143497 183 323 183 324 PF02752.15 Arrestin_C Domain 1 137 138 58.5 6e-16 1 CL0135 FBpp0131987 60 280 51 280 PF00089.19 Trypsin Domain 14 219 219 127.7 3.7e-37 1 CL0124

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  • c# FormatException was unhandled

    - by poco
    I'm parsing chat from a game and i get this string "?68 00 00 37 00 45 00 00" recipe = recipe.Replace("?", ""); string[] rElements = new string[8]; rElements = recipe.Split(' '); int num = int.Parse(rElements[0]); I get a Format exception on that last line that i don't understand. It says that input string is not in the right format. I have checked the debugger and the first element says it is "68". Anyone have any clue what is happening?

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  • ajax request internal server error

    - by joe
    Everything is working good on local but when i try same codes in production, i get 500 (Internal Server Error) error. entries.controller def set_spam @entry = Entry.find(params[:entry_id]) @entry.spam = params[:what] == "spam" ? true : false @entry.save respond_to do |format| format.js end end application.js $(".entry-actions .spams img").click(function () { $.post("/set-spam", { entry_id: $(this).attr("entry_id"), what: $(this).attr("class") } ); return false; }); view <div class="spams"> <img title="spam" class="spam" src="/images/pixel.gif" entry_id="<%= entry.id %>" /> </div> route post "/set-spam" => "entries#set_spam"

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  • How do I create a sqlite 3 (.sl3) database file?

    - by BC
    I have a *.sqlite file... but I need the database in *.sl3 format? What software/tool can I us to create that? What are the steps? This is to be used in an iPhone app. Original developer used an .sl3 file, now that I have updated the DB - I can't seem to export/generate a .sl3 file I have tried just changing the extension - all the way to inserting the *.sqlite file in XCode and pointing the app delegates to the new DB file format... doesn't work. Thanks in advance...

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  • Is there a way to substr a value returned by toShortString()?

    - by Jym Khana
    I am working with openlayers and I can get a point on a map but I can't get the individual coords. feat = drawLayer.features[0]; var geom = feat.geometry; var loca = geom.toShortString(); var long = loc.substr(0,9); alert(geom.toShortString());//returns the correct coords in xx.xxx,xx.xxx format alert(loca);//returns 2 very large numbers in xx.xxx,xx.xxx format alert(long);//returns the first, incorrect number What exaclty am I doing wrong and how can I correct it? Thanks

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