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  • Why does Jcreator show iIlegal start of expression?

    - by Inusual Whisper Sinclair
    I am new at programming and currently in our classes we are learning java. I am trying to create a routine in which I need to use String variables only. Below it is the code in which I am working with: public static void main(String[] args) throws java.io.IOException { BufferedReader in = new BufferedReader(new InputStreamReader(System. in )); PrintStream out = System.out; String hair.equals("damagedHair"); cutHair(marvin); cleanHair(michelle); for (int i = 0; i < 2; i++) { static void cutHair(String marvin) { String cabello; marvin.equals(hair); if (marvin.equals("damagedHair")) { cabello.equals("newHaircut"); result(hair); } static void cleanHair(String michelle) { String hair; michelle.equals(hair); if (michelle.equals(newHaircut)) { hair.equals("putShampooAndConditioner"); result(hair); } static void result(String pHair) {; PrintStream out = System.out; out.println("============="); out.println(pHair); out.println("============="); } } Jcreator is giving me an error that says Illegal start of expression and also java 50 error ';' expected. I am not sure why is this coming up and I am a little confused as to whether I am doing something I am not supposed to and how to correct it. Sorry about the double posting, this is the right message. Need some help from you guys to figure this out. Thanks in advanced!

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  • Long string insertion with sed

    - by Luis Varca
    I am trying to use this expression to insert the contents of one text file into another after a give string. This is a simple bash script: TEXT=`cat file1.txt` sed -i "/teststring/a \ $TEXT" file2.txt This returns an error, "sed: -e expression #1, char 37: unknown command: `M'" The issue is in the fact that the contents of file1.txt are actually a private certificate so it's a large amount of text and unusual characters which seems to be causing an issue. If I replace $TEXT with a simple ASCII value it works but when it reads the large content of file1.txt it fails with that error. Is there some way to carry out this action? Is my syntax off with sed or my quote placement wrong?

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  • How to solve this problem with a 'tuned' prompt in ZSH?

    - by Mnementh
    I have an adjusted prompt in my ZSH-configuration. Main feature is, that this prompt is colored red, so that I can easily it distinguish from the outputs of programs. My prompt is defined as follows: PROMPT=$'\e[0;31m%n@%m:%~> \e[0m' This works mostly fine, but sometimes my cursor switches to another position on tab-completion and some characters are left behind on the screen and mangle up the commandline. That is a little annoyance, but if someone knows a solution for this, I would appreciate it.

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  • How to define trees with more than one type in ML programing language

    - by user550413
    Well, I am asked to do the next thing: To define a binary tree which can contain 2 different types: ('a,'b) abtree and these are the requirements: Any inner vertex (not a leaf) must be of the type 'a or 'b and the leafs have no value. For every path in the tree all 'a values must appear before the 'b value: examples of paths: 'a->'a->'a-'b (legal) 'a->'b->'b (legal) 'a->'a->'a (legal) 'b->'b->'b (legal) 'a->'b->'a (ILLEGAL) and also I need to define another tree which is like the one described above but now I have got also 'c and in the second requirement it says that for every path I 'a values appear before the 'b values and all the 'b values appear before the 'c values. First, I am not sure how to define binary trees to have more than 1 type in them. I mean the simplest binary tree is: datatype 'a tree = leaf | br of 'a * 'a tree * 'a tree; And also how I can define a tree to have these requirements. Any help will be appreciated. Thanks.

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  • ADO program to list members of a large group.

    - by AlexGomez
    Hi everyone, I'm attempting to list all the members in a Active Directory group using ADO. The problem I have is that many of these groups have over 1500 members and ADSI cannot handle more than 1500 items in a multi-valued attribute. Fortunately I came across Richard Muller's wonderful VBScript that handles more than 1500 members at http://www.rlmueller.net/DocumentLargeGroup.htm I modified his code as shown below so that I can list ALL the groups and its memberships in a certain OU. However, I'm keeping getting the exception shown below: "ADODB.Recordset: Item cannot be found in the collection corresponding to the requested name or ordinal." My program appears to get stuck at: strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) All I am doing above is issuing the query to get back a recordset consisting of the ADsPath for each group in the OU. It then walks through the recordset and grabs the ADsPath for the first group and store its in a variable named strPath; we then use the value of that variable to bind to the group account for that group. It really should work! Any idea why the code below doesn't work for me? Any pointers will be great appreciated. Thanks. Option Explicit Dim objRootDSE, strDNSDomain, adoCommand Dim adoConnection, strBase, strAttributes Dim strFilter, strQuery, adoRecordset Dim strDN, intCount, blnLast, intLowRange Dim intHighRange, intRangeStep, objField Dim objGroup, objMember, strName ' Determine DNS domain name. Set objRootDSE = GetObject("LDAP://RootDSE") 'strDNSDomain = objRootDSE.Get("DefaultNamingContext") strDNSDomain = "XXXXXXXX" ' Use ADO to search Active Directory. Set adoCommand = CreateObject("ADODB.Command") Set adoConnection = CreateObject("ADODB.Connection") adoConnection.Provider = "ADsDSOObject" adoConnection.Open = "Active Directory Provider" adoCommand.ActiveConnection = adoConnection adoCommand.Properties("Page Size") = 100 adoCommand.Properties("Timeout") = 30 adoCommand.Properties("Cache Results") = False ' Specify base of search. strBase = "<LDAP://" & strDNSDomain & ">" ' Specify the attribute values to retrieve. strAttributes = "member" ' Filter on objects of class "group" strFilter = "(&(objectClass=group)(samAccountName=*))" ' Enumerate direct group members. ' Use range limits to handle more than 1000/1500 members. ' Setup to retrieve 1000 members at a time. blnLast = False intRangeStep = 999 intLowRange = 0 IntHighRange = intLowRange + intRangeStep Do While True If (blnLast = True) Then ' If last query, retrieve remaining members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange _ & "-*;subtree" Else ' If not last query, retrieve 1000 members. strQuery = strBase & ";" & strFilter & ";" _ & strAttributes & ";range=" & intLowRange & "-" _ & intHighRange & ";subtree" End If adoCommand.CommandText = strQuery Set adoRecordset = adoCommand.Execute adoRecordset.MoveFirst intCount = 0 Do Until adoRecordset.EOF strPath = adoRecordset.Fields("ADsPath").Value Set objGroup = GetObject(strPath) For Each objField In adoRecordset.Fields If (VarType(objField) = (vbArray + vbVariant)) _ Then For Each strDN In objField.Value ' Escape any forward slash characters, "/", with the backslash ' escape character. All other characters that should be escaped are. strDN = Replace(strDN, "/", "\/") ' Check dictionary object for duplicates. 'If (objGroupList.Exists(strDN) = False) Then ' Add to dictionary object. 'objGroupList.Add strDN, True ' Bind to each group member, to find member's samAccountName Set objMember = GetObject("LDAP://" & strDN) ' Output group cn, group samaAccountName and group member's samAccountName. Wscript.Echo objMember.samAccountName intCount = intCount + 1 'End if Next End If Next adoRecordset.MoveNext Loop adoRecordset.Close ' If this is the last query, exit the Do While loop. If (blnLast = True) Then Exit Do End If ' If the previous query returned no members, then the previous ' query for the next 1000 members failed. Perform one more ' query to retrieve remaining members (less than 1000). If (intCount = 0) Then blnLast = True Else ' Setup to retrieve next 1000 members. intLowRange = intHighRange + 1 intHighRange = intLowRange + intRangeStep End If Loop

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  • Meaning of "*" in Windows 7 Explorer Search?

    - by Pumbaa80
    I have a folder containing files like radiobutton-clicked.png radiobutton-foobar.png radiobutton-foobarbaz.png ... etc. This is what happens when I search in Windows Explorer: radio: all files found radio*: all files found *button: all files found *radiobutton*: all files found radiobutton*: no results radiobutton: no results radio*button: all files found So what the hell does the * precisely do? Is there some documentation on this? And why does radio and radio*button work as a search term, but radiobutton not? Edit: I know that * is usually supposed to be a wildcard matching 0 or more characters. But obviously it doesn't in this case.

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  • NHibernate correct way to reattach cached entity to different session

    - by Chris Marisic
    I'm using NHibernate to query a list of objects from my database. After I get the list of objects over them I iterate over the list of objects and apply a distance approximation algorithm to find the nearest object. I consider this function of getting the list of objects and apply the algorithm over them to be a heavy operation so I cache the object which I find from the algorithm in HttpRuntime.Cache. After this point whenever I'm given the supplied input again I can just directly pull the object from Cache instead of having to hit the database and traverse the list. My object is a complex object that has collections attached to it, inside the query where I return the full list of objects I don't bring back any of the sub collections eagerly so when I read my cached object I need lazy loading to work correctly to be able to display the object fully. Originally I tried using this to re-associate my cached object back to a new session _session.Lock(obj, LockMode.None); However when accessing the page concurrently from another instance I get the error Illegal attempt to associate a collection with two open sessions I then tried something different with _session.Merge(obj); However watching the output of this in NHProf shows that it is deleting and re-associating my object's contained collections with my object, which is not what I want although it seems to work fine. What is the correct way to do this? Neither of these seem to be right.

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  • Error message when renaming files on a network drive stored in Windows 7 favorites

    - by paulmorriss
    I have a network drive mapped to a share on a Window Server 2003. I have a shortcut to this drive stored in my Windows 7 favorites. When I double click the shortcut and then rename a file on the drive, if the file is longer than 8 chars or contains spaces then I get this error The drive that this file or folder is stored on does not allow long file names, or names containing blanks or any of the following characters:... If I get to the network drive by click on it in the tree under computer then it works fine. Is there a way to get round this?

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  • Why is TRest in Tuple<T1... TRest> not constrained?

    - by Anthony Pegram
    In a Tuple, if you have more than 7 items, you can provide an 8th item that is another tuple and define up to 7 items, and then another tuple as the 8th and on and on down the line. However, there is no constraint on the 8th item at compile time. For example, this is legal code for the compiler: var tuple = new Tuple<int, int, int, int, int, int, int, double> (1, 1, 1, 1, 1, 1, 1, 1d); Even though the intellisense documentation says that TRest must be a Tuple. You do not get any error when writing or building the code, it does not manifest until runtime in the form of an ArgumentException. You can roughly implement a Tuple in a few minutes, complete with a Tuple-constrained 8th item. I just wonder why it was left off the current implementation? Is it possibly a forward-compatibility issue where they could add more elements with a hypothetical C# 5? Short version of rough implementation interface IMyTuple { } class MyTuple<T1> : IMyTuple { public T1 Item1 { get; private set; } public MyTuple(T1 item1) { Item1 = item1; } } class MyTuple<T1, T2> : MyTuple<T1> { public T2 Item2 { get; private set; } public MyTuple(T1 item1, T2 item2) : base(item1) { Item2 = item2; } } class MyTuple<T1, T2, TRest> : MyTuple<T1, T2> where TRest : IMyTuple { public TRest Rest { get; private set; } public MyTuple(T1 item1, T2 item2, TRest rest) : base(item1, item2) { Rest = rest; } } ... var mytuple = new MyTuple<int, int, MyTuple<int>>(1, 1, new MyTuple<int>(1)); // legal var mytuple2 = new MyTuple<int, int, int>(1, 2, 3); // illegal

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  • problem with using polish keyboard with synergy 1.4.2

    - by Lukasz
    I installed synergy on Windows 7 as server and on Windows Vista as client. On both I can use polish keyboard using local keyboard. When I am using remote keyboard via synergy polish characters are not working (I mean in example S + Alt Gr or S + left Alt + left ctrl) I've used synergy about 1 year ago and I cannot recall that kind of problem so I think the problem is only in current version. Searching through your web site and googled I found only identical problem 5 years ago with information that it was solved. Please help me to sort it out.

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  • The Coolest Server Names

    - by deadprogrammer
    These days server naming is a bit of a lost art. Most large organizations don't allow for fanciful names and name their servers with jumbles of digits and letters. In the olden days just about every system administrator came up with a unique naming scheme, well, sometimes unique - many just settled for Star Trek characters. To this day my favorite server name is Qantas - a Unix server that Joel Spolsky has or used to have. Why Qantas? You'd have to ask Rainman. So my question is this - what is the coolest server name or naming convention that you encountered? Let the geekfest begin. This question is marked "community wiki", so I am not getting any "rep" from it.

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  • Mount encrypted hfs in ubuntu

    - by pagid
    I try to mount an encrypted hfs+ partition in ubuntu. An older post described quite good how to do it, but lacks the information how to use encrypted partitions. What I found so far is: # install required packages sudo apt-get install hfsprogs hfsutils hfsplus loop-aes-utils # try to mount it mount -t hfsplus -o encryption=aes-256 /dev/xyz /mount/xyz But once I run this I get the following error: Error: Password must be at least 20 characters. So I tried to type it in twice, but that results in this: ioctl: LOOP_SET_STATUS: Invalid argument, requested cipher or key (256 bits) not supported by kernel Any suggestions? Thx Edit: One thing I'm not sure about is whether I use the right password. My assumption is that it is my default one for these situations. But I'm not sure whether Max OSX choose another password (internally) for that.

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  • Why is music tagging software so inconsistent?

    - by Billy ONeal
    Hello :) A few years ago I spent an insane amount of time using the excellent Tag&Rename program. However, I find that for random, inexplicable reasons, some music tools simply disregard my tags, and drop or destroy the album art, or have strange handling around some characters. For example, "AC/DC" is poorly handled by most music players when I use Tag&Rename to write the tags. Is there a piece of software that works like Tag&Rename but is more compatible, or is there a way to ensure Tag&Rename writes more compatible tags?

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  • Check a list of passwords strength

    - by user144705
    Is there any way to check a list of passwords whether they strong or not? I have a list of passwords, around 2000, and want to check them against this policy Password must contain a minimum of eight (8) characters Password must contain at least one letter Password must contain at least one number Password must contain at least one punctuation character And count how many compliant with that policy before we save them. Is there any tool, script or maybe rules in excel to do this instead of doing it manually? Could you please help me?

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  • Word 2010 - Styled paragraph separating into separate numbered lines

    - by chez
    USING WORD 2010 I have a style "Heading 4 Par" which is a style based on Heading 4. It is a numbered style. My problem is when I apply the "Heading 4 Par" to say a 3 lined paragraph it separates each of the lines in the paragraph and numbers it. I always show the formatting characters and as far as I can see there is only ONE paragraph mark situated at the end of what is supposed to be a paragraph. eg. Original: 7.4 Text.... text con't..... Text... After Applying Format: 7.4 Text... 7.4 text con't... 7.4 text con't. After I've applied the format it behaves as though each line should be the start of a new paragraph but there is no paragraph mark to show this. This is driving me crazy! Help!

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  • iPhone code forUIImageViewControllerPickerSourceTypeCamera

    - by aman-gupta
    - (IBAction)pickAndDecode:(id) sender { UIImagePickerControllerSourceType sourceType; int i = [sender tag]; switch (i) { case 0: sourceType = UIImagePickerControllerSourceTypeCamera; break; case 1: sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum; break; case 2: sourceType = UIImagePickerControllerSourceTypePhotoLibrary; break; default: sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum; } [self pickAndDecodeFromSource:sourceType]; } - (void) updateToolbar { self.cameraBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeCamera]; self.savedPhotosBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeSavedPhotosAlbum]; self.libraryBarItem.enabled = [UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypePhotoLibrary]; self.archiveBarItem.enabled = true; self.actionBarItem.enabled = (self.result != nil) && ([self.result actions] != nil) && ([self.result actions].count > 0); } - (void)pickAndDecodeFromSource:(UIImagePickerControllerSourceType) sourceType { [self reset]; // Create the Image Picker if ([UIImagePickerController isSourceTypeAvailable:sourceType]) { UIImagePickerController* picker = [[UIImagePickerController alloc] init]; picker.sourceType = sourceType; picker.delegate = self; picker.allowsImageEditing = YES; // [[NSUserDefaults standardUserDefaults] boolForKey:@"allowEditing"]; // Picker is displayed asynchronously. [self presentModalViewController:picker animated:YES]; } else { NSLog(@"Attempted to pick an image with illegal source type '%d'", sourceType); } } Where I Put this line in my above codes; [picker setShowsCameraControls:FALSE]; please help me so that i can change the real view of iPhone camera according to my view which i have designed

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  • Issue changing mysql password on Debian

    - by Sean
    I installed mysql on my Debian server. I couldn't get into the database because it kept saying I put in the wrong password so I looked on the internet and found that I could log onto mysql using the command sudo mysql --defaults-file=/etc/mysql/debian.cnf From there I went typed use mysql;then mysql> UPDATE user SET password=PASSWORD('password') WHERE user='root'; Which I know switched the password because I typed the command select Host, User, Password from user; And it showed the encrypted characters had changed for all three of the root user categories. But I am still not able to login to mysql using mysql -u root -p

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  • How can I add leading zeros between delimiters in Excel 2010

    - by Gregory Biernacki
    I am trying to convert a list of property id numbers that has a standard format of 0000-A-00000-00-00, where my worksheet has the various combinations of 1-A-123 10-B-1234 Ideally they would read as follows 0001-A-00123-0000-00 0010-B-01234-0000-00 I've tried using the custom number formatting but it doesn't like the letter in the middle of the number. I didn't know if my only option was to break them apart and then put them back together again. I would accept a solution that merely put the leading zeros at the front of the number, (max is 4 characters) so the result could look like 0001-A-123

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  • Is there an FTP client for Windows 7 with a text-based UI? (not text-prompt based, like ftp.exe)

    - by Alan B
    Is there such as thing as a text-mode FTP client for Windows 7 ? By 'text-mode' I mean one that runs in a CMD.EXE window as opposed to a Windows GUI application. It also needs to be something along the lines of FileZilla, i.e. menu-driven as opposed to command-entry clients like NcFTP or indeed the built-in one. edit: To avoid confusion, what I mean is an application similar to that pictured (ZTreeWin File Manager), which runs from CMD.EXE and uses text characters for its UI, within the CMD.EXE window. The built-in FTP client, and things like NcFTP offer a prompt at which you issue commands. That's not what I'm looking for.

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  • Language bar switched input types on me.

    - by Elijah
    I learned Japanese, but I'm not native to Japan, so I never had a Japanese keyboard. I used to use the language bar to go back and forth between English and Japanese, simply typing the words in romaji and having windows convert it into either hiragana, katakana and sometimes Kanji. Suddenly, my input type changes. I am no longer able to simply type in English, it changed my keyboard into a native Japanese keyboard, and what's worse it doesn't even allow me to write in hiragana, which I would need way more than katakana. Can anyone tell me how to restore it to the old setting where I simply chose what the output dialect would be, and typed the words phonetically in english and have it translate the sounds for me into japanese characters?

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  • Keyboard Slow on a high power machine.

    - by Tim Pierson
    I am having a terrible time with my high powered machine. The keyboard is not displaying the keys as quickly as I type. Sometimes I have to wait up to a minute for the key to display. When I type ahead it sometimes loses characters. I am not sure where to start looking for this problem. It started about a month ago and I still have not figured out why. It does not always do it. But acts up about 2-3 minutes out of ever hour of use or thereabout. How can I look to isolate and find the problem, and solve it?

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  • Highlight identical strings in vi(m)

    - by Boldewyn
    One feature of Notepad++, which I find really useful and haven't found elsewhere, is the highlighting of other text that is identical to the one currently selected. Is there something similar possible with vi(m)? (Of course, there is. But how do I achieve it?) That is, any of those: If I am in Visual Mode and have text selected: Highlight identical text If I have searched /foo, highlight all instances of foo. If I am at the beginning of a string (series of characters, numbers or underscores), highlight all other matching strings (prefered solution). The last one is similar to the closing parentheses matching and IMHO the most useful. Edit: For my second use case, I found a solution (that is, Google found it...): :set hls However, the others remain.

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  • HQL query problem

    - by yigit
    Hi all, I'm using this hql query for my filters. Query perfectly working except width (string) part. Here is the query, public IList<ColorGroup> GetDistinctColorGroups(int typeID, int finishID, string width) { string queryStr = "Select distinct c from ColorGroup c inner join c.Products p " + "where p.ShowOnline = 1 "; if (typeID > 0) queryStr += " and p.ProductType.ID = " + typeID; if (finishID > 0) queryStr += " and p.FinishGroup.ID = " + finishID; if (width != "") queryStr += " and p.Size.Width = " + width; IList<ColorGroup> colors = NHibernateSession.CreateQuery(queryStr).List<ColorGroup>(); return colors; } ProductType and Size have same mappings and relations. This is the error; NHibernate.QueryException: illegal syntax near collection: Size [Select distinct c from .Domain.ColorGroup c inner join c.Products p where p.ShowOnline = 1 and p.ProductType.ID = 1 and p.FinishGroup.ID = 5 and p.Size.Width = 4] Any ideas ?

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  • How to display password policy information for a user (Ubuntu)?

    - by C.W.Holeman II
    Ubuntu Documentation Ubuntu 9.04 Ubuntu Server Guide Security User Management states that there is a default minimum password length for Ubuntu: By default, Ubuntu requires a minimum password length of 4 characters Is there a command for displaying the current password policies for a user (such as the chage command displays the password expiration information for a specific user)? > sudo chage -l SomeUserName Last password change : May 13, 2010 Password expires : never Password inactive : never Account expires : never Minimum number of days between password change : 0 Maximum number of days between password change : 99999 Number of days of warning before password expires : 7 This is rather than examining various places that control the policy and interpreting them since this process could contain errors. A command that reports the composed policy would be used to check the policy setting steps.

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  • How to sort a file with string lines by the number of a specific symbol in the line?

    - by SpacyRicochet
    Say I have a large plaintext file with a string on every line. The string only consists of alphabetical characters, except for underscores _, which divide the strings in syllables. I want to sort the text file by the amount underscores in the string. Bonus points for putting every group of X underscores in their own file. Example: hel_lo hi su_per_u_ser o_ver_flow would sort into: hi hel_lo o_ver_flow su_per_u_ser I've tried doing this with regex, but I've yet to find a proper way of counting the underscores (regex confuses me thoroughly). Anyone know how I could handle this?

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