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  • Howto switch / chage user id witin a bash script to execute commands in the same script?

    - by a1an
    Is there a way to switch user identity within a script (executed as root as part of an installation process) to execute some commands without calling an external sctipt, then be back to root to run other commands? Sort of: #!/bin/bash some commands as root SWITCH_USER_TO user some commands as user including environment variables checks, without calling an external script SWITCH_USER_BACK some other stuff as root, maybe another user id change...

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  • How to map a user to a domain, with Usermin and Postfix?

    - by HappyDeveloper
    What I need is to create a couple of websites, each one with only one user, which is allowed to send mails from any address @ his own domain. Example: Site foo.com would have an user foo, which can send mails from [email protected]. Currently, when the user logins to Usermin, the default 'from' field is example-dns.net (editable) I want it to show an editable field for the user part, and @foo.com (non editable) So how can I do this? Is there some way to automate this?

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  • How do I add categories from another user in outllook 2003 to my list of categories in 2007?

    - by Ernst
    Hi, I'm sharing a contact list with another user on the network, but I'm using outlook 2007 and the other user is using outlook 2003. The other user has assigned many different categories, but I do not get those categories added to the list of categories I can choose from when adding/editing contacts, I can see certain contacts have those categories. How do I add those categories so I can also add them? The shared contacts originate from the other user. Thanks

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  • reading the file name from user input in MIPS assembly

    - by Hassan Al-Jeshi
    I'm writing a MIPS assembly code that will ask the user for the file name and it will produce some statistics about the content of the file. However, when I hard code the file name into a variable from the beginning it works just fine, but when I ask the user to input the file name it does not work. after some debugging, I have discovered that the program adds 0x00 char and 0x0a char (check asciitable.com) at the end of user input in the memory and that's why it does not open the file based on the user input. anyone has any idea about how to get rid of those extra chars, or how to open the file after getting its name from the user?? here is my complete code (it is working fine except for the file name from user thing, and anybody is free to use it for any purpose he/she wants to): .data fin: .ascii "" # filename for input msg0: .asciiz "aaaa" msg1: .asciiz "Please enter the input file name:" msg2: .asciiz "Number of Uppercase Char: " msg3: .asciiz "Number of Lowercase Char: " msg4: .asciiz "Number of Decimal Char: " msg5: .asciiz "Number of Words: " nline: .asciiz "\n" buffer: .asciiz "" .text #----------------------- li $v0, 4 la $a0, msg1 syscall li $v0, 8 la $a0, fin li $a1, 21 syscall jal fileRead #read from file move $s1, $v0 #$t0 = total number of bytes li $t0, 0 # Loop counter li $t1, 0 # Uppercase counter li $t2, 0 # Lowercase counter li $t3, 0 # Decimal counter li $t4, 0 # Words counter loop: bge $t0, $s1, end #if end of file reached OR if there is an error in the file lb $t5, buffer($t0) #load next byte from file jal checkUpper #check for upper case jal checkLower #check for lower case jal checkDecimal #check for decimal jal checkWord #check for words addi $t0, $t0, 1 #increment loop counter j loop end: jal output jal fileClose li $v0, 10 syscall fileRead: # Open file for reading li $v0, 13 # system call for open file la $a0, fin # input file name li $a1, 0 # flag for reading li $a2, 0 # mode is ignored syscall # open a file move $s0, $v0 # save the file descriptor # reading from file just opened li $v0, 14 # system call for reading from file move $a0, $s0 # file descriptor la $a1, buffer # address of buffer from which to read li $a2, 100000 # hardcoded buffer length syscall # read from file jr $ra output: li $v0, 4 la $a0, msg2 syscall li $v0, 1 move $a0, $t1 syscall li $v0, 4 la $a0, nline syscall li $v0, 4 la $a0, msg3 syscall li $v0, 1 move $a0, $t2 syscall li $v0, 4 la $a0, nline syscall li $v0, 4 la $a0, msg4 syscall li $v0, 1 move $a0, $t3 syscall li $v0, 4 la $a0, nline syscall li $v0, 4 la $a0, msg5 syscall addi $t4, $t4, 1 li $v0, 1 move $a0, $t4 syscall jr $ra checkUpper: blt $t5, 0x41, L1 #branch if less than 'A' bgt $t5, 0x5a, L1 #branch if greater than 'Z' addi $t1, $t1, 1 #increment Uppercase counter L1: jr $ra checkLower: blt $t5, 0x61, L2 #branch if less than 'a' bgt $t5, 0x7a, L2 #branch if greater than 'z' addi $t2, $t2, 1 #increment Lowercase counter L2: jr $ra checkDecimal: blt $t5, 0x30, L3 #branch if less than '0' bgt $t5, 0x39, L3 #branch if greater than '9' addi $t3, $t3, 1 #increment Decimal counter L3: jr $ra checkWord: bne $t5, 0x20, L4 #branch if 'space' addi $t4, $t4, 1 #increment words counter L4: jr $ra fileClose: # Close the file li $v0, 16 # system call for close file move $a0, $s0 # file descriptor to close syscall # close file jr $ra Note: I'm using MARS Simulator, if that makes any different

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  • faster implementation of sum ( for Codility test )

    - by Oscar Reyes
    How can the following simple implementation of sum be faster? private long sum( int [] a, int begin, int end ) { if( a == null ) { return 0; } long r = 0; for( int i = begin ; i < end ; i++ ) { r+= a[i]; } return r; } EDIT Background is in order. Reading latest entry on coding horror, I came to this site: http://codility.com which has this interesting programming test. Anyway, I got 60 out of 100 in my submission, and basically ( I think ) is because this implementation of sum, because those parts where I failed are the performance parts. I'm getting TIME_OUT_ERROR's So, I was wondering if an optimization in the algorithm is possible. So, no built in functions or assembly would be allowed. This my be done in C, C++, C#, Java or pretty much in any other. EDIT As usual, mmyers was right. I did profile the code and I saw most of the time was spent on that function, but I didn't understand why. So what I did was to throw away my implementation and start with a new one. This time I've got an optimal solution [ according to San Jacinto O(n) -see comments to MSN below - ] This time I've got 81% on Codility which I think is good enough. The problem is that I didn't take the 30 mins. but around 2 hrs. but I guess that leaves me still as a good programmer, for I could work on the problem until I found an optimal solution: Here's my result. I never understood what is those "combinations of..." nor how to test "extreme_first"

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  • Configuring xUnit test output in Hudson

    - by graham.reeds
    I have a simple PoC project in Hudson. The PoC has unit tests written via UnitTest++ and outputs the results as XML for consumption by xUnit to munge into jUnit format. Here are the salient relevant I have my project configured to use MSBuild to build the 2008 solution. The project contains both the dll it is to build and the unit tests which are run as a post-build step. My workspace in Hudson is set to c:\develop\money (Money is the name of the project) and in the Hudson console I can see the workspace folders, the solution file and output folders (/bin, /doc, etc). The test console app outputs its file 'money_unit_tests.xml' to the folder 'reports' (making c:\develop\money\reports). I've restarted Hudson since installing xUnit and setting the workspace. However when I start Hudson building I am given the following message: [xUnit] Starting to record. [xUnit] [UnitTest] - Use the embedded style sheet. [xUnit] [ERROR] - No test report file(s) were found with the pattern 'reports/money_unit_tests.xml' relative to 'C:\.hudson\jobs\Money\workspace' for the testing framework 'UnitTest'. Did you enter a pattern relative to the correct directory? Did you generate the result report(s) for 'UnitTest'? [xUnit] Stopping recording. Finished: FAILURE Why does Hudson seem to think the workspace is in C:.hudson... and not C:\Develop...? What can I do change it? If I can't change it, what can I do to mitigate these changes? (I don't exactly want to hardcode the output for the xml to C:.hudson...)

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  • Linq-to-Sql IIS7 Login failed for user ‘DOMAIN\MACHINENAME$’

    - by cfdev9
    I am encountering unexpected behaviour using Linq-to-sql DataContext. When I run my application locally it works as expected however after deploying to a test server which runs IIS7, I get an error Login failed for user ‘DOMAIN\MACHINENAME$’ when attempting to open objects from the DataContext. This code explains the error, which breaks on the very last line with the error "System.Data.SqlClient.SqlException: Login failed for user". var connStr ="Data Source=server;Initial Catalog=Test;User Id=testuser;Password=password"; //Test 1 var conn1 = new System.Data.SqlClient.SqlConnection(connStr); var cmdString = "SELECT COUNT(*) FROM Table1"; var cmd = new System.Data.SqlClient.SqlCommand(cmdString, conn1); conn1.Open(); var count1 = cmd.ExecuteScalar(); conn1.Close(); //Test 2 var conn2 = new System.Data.SqlClient.SqlConnection(connStr); var context = new TestDataContext(conn2); var count2 = context.Table1s.Count(); The connection string is not even using integrated security, so why is Linq-to-sql trying to connect as a specific user? If I change the server name in the connection string I get a different error so its using atleast part of the connection string, but apparently ignoring the UserId and Password. Very confused.

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  • Integration test failing through NUnit Gui/Console, but passes through TestDriven in IDE

    - by Cliff
    I am using NHibernate against an Oracle database with the NHibernate.Driver.OracleDataClientDriver driver class. I have an integration test that pulls back expected data properly when executed through the IDE using TestDriven.net. However, when I run the unit test through the NUnit GUI or Console, NHibernate throws an exception saying it cannot find the Oracle.DataAccess assembly. Obviously, this prevents me from running my integration tests as part of my CI process. NHibernate.HibernateException : The IDbCommand and IDbConnection implementation in the assembly Oracle.DataAccess could not be found. Ensure that the assembly Oracle.DataAccess is located in the application directory or in the Global Assembly Cache. If the assembly is in the GAC, use element in the application configuration file to specify the full name of the assembly.* I have tried making the assembly available in two ways, by copying it into the bin\debug folder and by adding the element in the config file. Again, both methods work when executing through TestDriven in the IDE. Neither work when executing through NUnit GUI/Console. The NUnit Gui log displays the following message. 21:42:26,377 ERROR [TestRunnerThread] ReflectHelper [(null)]- Could not load type Oracle.DataAccess.Client.OracleConnection, Oracle.DataAccess. System.BadImageFormatException: Could not load file or assembly 'Oracle.DataAccess, Version=2.111.7.20, Culture=neutral, PublicKeyToken=89b483f429c47342' or one of its dependencies. An attempt was made to load a program with an incorrect format. File name: 'Oracle.DataAccess, Version=2.111.7.20, Culture=neutral, PublicKeyToken=89b483f429c47342' --- System.BadImageFormatException: Could not load file or assembly 'Oracle.DataAccess' or one of its dependencies. An attempt was made to load a program with an incorrect format. File name: 'Oracle.DataAccess' I am running NUnit 2.4.8, TestDriven.net 2.24 and VS2008sp1 on Windows 7 64bit. Oracle Data Provider v2.111.7.20, NHibernate v2.1.0.4. Has anyone run into this issue, better yet, fixed it?

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  • User.IsInRole returning false

    - by Curtis
    My ASP.NET app is using windows authentication. If I run the following code: WindowsIdentity wi = (WindowsIdentity)User.Identity; foreach (IdentityReference r in wi.Groups) { ListBox1.Items.Add(r.Translate (typeof (NTAccount)).Value); } if (User.IsInRole ("Everyone")) Label1.Text = "Is in role"; The listbox will contain the name of every group the user belongs to. If I then call User.IsInRole, and pass in the name of any of those groups, I always get a false. Can anyone tell me what I am doing wrong? Thanks

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  • Facebook Graph API: user gender

    - by Mark
    The old Facebook API provided the user sex/gender as part of the default user data. Apparently the new Graph API does not provide that information, even though the documentation says that it does. I've heard people say that you need to request special permissions to get it and other pieces of data, but I have not been successful in getting it to work. Does anyone have an example, using the Facebook Graph API, of how to get the user's gender and/or location (city/state/country/whatever)?

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  • Development Environment in a VM against an isolated development/test network

    - by bart
    I currently work in an organization that forces all software development to be done inside a VM. This is for a variety of risk/governance/security/compliance reasons. The standard setup is something like: VMWare image given to devs with tools installed VM is customized to suit project/stream needs VM sits in a network & domain that is isolated from the live/production network SCM connectivity is only possible through dev/test network Email and office tools need to be on live network so this means having two separate desktops going at once Heavyweight dev tools in use on VMs so they are very resource hungry Some problems that people complain about are: Development environment runs slower than normal (host OS is windows XP so memory is limited) Switching between DEV machine and Email/Office machine is a pain, simple things like cut and paste are made harder. This is less efficient from a usability perspective. Mouse in particular doesn't seem to work properly using VMWare player or RDP. Need a separate login to Dev/Test network/domain Has anyone seen or worked in other (hopefully better) setups to this that have similar constraints (as mentioned at the top)? In particular are there viable options that would remove the need for running stuff in a VM altogether?

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  • Facebook: Get User's Birthday

    - by Sarfraz
    Hello, As I asked previously but without any luck about how to get current user's birthday. I would like to simply get the birthday of current logged in user (I am using facebook connect & php client library) using any possible way you guys could suggest. I have also heared about OAuth and Graph API but facebook documentation is very bad, I can not get a working example. Please show me any method to get current user's birthday. Thanks

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  • iphone zoom to user location on mapkit

    - by satyam
    I'm using map kit and showing user's location using "showsUserLocation" I"m using following code to zoom to user's location, but not zooming. Its zooming to some location in Africa, though the user location on map is showing correct. MKCoordinateRegion newRegion; MKUserLocation* usrLocation = mapView.userLocation; newRegion.center.latitude = usrLocation.location.coordinate.latitude; newRegion.center.longitude = usrLocation.location.coordinate.longitude; newRegion.span.latitudeDelta = 20.0; newRegion.span.longitudeDelta = 28.0; [self.mapView setRegion:newRegion animated:YES]; Why is user's location correctly showing and not zooming properly. Can some one correct me please?

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  • Delete a photo from the user's photo library?

    - by Jacob Relkin
    Hi, Is there a way I can delete an image that is loaded into my app from a UIImagePickerController? I want to be able to delete the image from the user's photo library when the user performs a specific action. I am prompting the user to choose a image from their library, then it gets loaded into my app at which point the app does some shnazzy animation, then actually deletes the image. Please help!

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  • Assigning a group while adding user in django-admin

    - by Lokharkey
    In my application, I have models that have the Users model as a Foreign key, eg: class Doctor(models.Model): username=models.ForeignKey(User, unique=True) ... In the admin site, when adding a new Doctor, I have the option of adding a new User next to the username field. This is exactly what I want, but in the dialog that opens, it asks for a username and password for the new user; I would also like to be able to assign a group to this new user. What would be the best way of doing this ? Thanks, lokharkey

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  • Android Activity is displayed after user unlocks the screen

    - by Dave
    Hi, I was wondering if anyone understood how to make your application be displayed when you unlock the screen. I have an application where the user turns on a Bluetooth device, it connects to the phone, and the user should be presented with a UI. Having them hunt for the app or using the notification menu is not a workable option (too much work and not the obvious behavior). The problem is that: When the screen is unlocked: - you can popup the activity from the background service when Bluetooth connects to a device - User is happy because the UI is right there When the screen is locked: - The application gets started but is destroyed - User unlocks the phone and nothing is there but the homescreen One work around would be to disable the keyguard when the application gets woken up but the nuclear option is a pretty bad option. PS: I know the standard Android assumption is that you shouldn't do this. In the normal case this behavior is fine, but in this case I explicitly did something I want the phone to respond without adding more work for the user to do. As per Google's guidelines if you don't like this behavior there can be an option for you to turn this off or you can not use the application.

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  • How can I effectively test a scripting engine?

    - by ChaosPandion
    I have been working on an ECMAScript implementation and I am currently working on polishing up the project. As a part of this, I have been writing tests like the following: [TestMethod] public void ArrayReduceTest() { var engine = new Engine(); var request = new ExecScriptRequest(@" var a = [1, 2, 3, 4, 5]; a.reduce(function(p, c, i, o) { return p + c; }); "); var response = (ExecScriptResponse)engine.PostWithReply(request); Assert.AreEqual((double)response.Data, 15D); } The problem is that there are so many points of failure in this test and similar tests that it almost doesn't seem worth it. It almost seems like my effort would be better spent reducing coupling between modules. To write a true unit test I would have to assume something like this: [TestMethod] public void CommentTest() { const string toParse = "/*First Line\r\nSecond Line*/"; var analyzer = new LexicalAnalyzer(toParse); { Assert.IsInstanceOfType(analyzer.Next(), typeof(MultiLineComment)); Assert.AreEqual(analyzer.Current.Value, "First Line\r\nSecond Line"); } } Doing this would require me to write thousands of tests which once again does not seem worth it.

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  • Printing Stdout In Command Line App Without Overwriting Pending User Input

    - by Chris S
    In a basic Unix-shell app, how would you print to stdout without disturbing any pending user input. e.g. Below is a simple Python app that echos user input. A thread running in the background prints a counter every 1 second. import threading, time class MyThread( threading.Thread ): running = False def run(self): self.running = True i = 0 while self.running: i += 1 time.sleep(1) print i t = MyThread() t.daemon = True t.start() try: while 1: inp = raw_input('command> ') print inp finally: t.running = False Note how the thread mangles the displayed user input as they type it (e.g. hell1o wo2rld3). How would you work around that, so that the shell writes a new line while preserving the line the user's currently typing on?

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  • user input question

    - by jdbeverly87
    My program checks to test if a word or phrase is a palindrome (reads the same both backward and forward, ex "racecar"). The issue I'm having is after someone enters in "racecar" getting it to actually test. In the below code, I marked where if I type in "racecar" and run, Java returns the correct answer so I know I'm right there. But what am I missing as far as entering it into the console. I think my code is ok, but maybe I have something missing or in the wrong spot? Not really looking for a new answer unless I'm missing something, but if possible perhaps a pro at this moving my code to the correct area bc I'm stuck! `import java.util.*; public class Palindrome { public static void main(String[] args) { String myInput; Scanner in = new Scanner(System.in); System.out.println("Enter a word or phrase: "); **//this asks user for input but doesn't check for whether or not it is a palindrome** myInput = in.nextLine(); in.close(); System.out.println("You entered: " + myInput); } { String s="racecar"; **//I can type a word here and it works but I need** int i; **//I need it to work where I ask for the input** int n=s.length(); String str=""; for(i=n-1;i>=0;i--) str=str+s.charAt(i); if(str.equals(s)) System.out.println(s+ " is a palindrome"); else System.out.println(s+ " is not a palindrome"); } }` I'm new at programming so I'm hoping what I got is ok. I know the palindrome test works I'm just needing helping having it test thru where I'm entering it into the console. Thanks

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  • Initiate User Scope Class at Session Start

    - by James Santiago
    I want to initiate a class for each user at the start of the user's session so that a single class can be used throughout the user's session. I checked out this post but I'm not sure where I should be placing this Sessionhandler class. Inside global.asax? How do I go about accomplishing this?

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  • Caching a user control

    - by Rishabh Ohri
    I have a user control which I want to Output cache( fragment cache) and set the dependency to a query. I mean that on change or modification of data returned by that query the cache should get invalidated. I have read that in the output cache directive in the user control Sqldependency = "CommandNotification" cannot be used. So, how should i proceed in order to add the sql query dependency to the fragment cached user control.

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  • How to inject a Session Bean into a Message Driven Bean?

    - by Hank
    Hi guys, I'm reasonably new to JEE, so this might be stupid.. bear with me pls :D I would like to inject a stateless session bean into a message-driven bean. Basically, the MDB gets a JMS message, then uses a session bean to perform the work. The session bean holds the business logic. Here's my Session Bean: @Stateless public class TestBean implements TestBeanRemote { public void doSomething() { // business logic goes here } } The matching interface: @Remote public interface TestBeanRemote { public void doSomething(); } Here's my MDB: @MessageDriven(mappedName = "jms/mvs.TestController", activationConfig = { @ActivationConfigProperty(propertyName = "acknowledgeMode", propertyValue = "Auto-acknowledge"), @ActivationConfigProperty(propertyName = "destinationType", propertyValue = "javax.jms.Queue") }) public class TestController implements MessageListener { @EJB private TestBean testBean; public TestController() { } public void onMessage(Message message) { testBean.doSomething(); } } So far, not rocket science, right? Unfortunately, when deploying this to glassfish v3, and sending a message to the appropriate JMS Queue, I get errors that glassfish is unable to locate the TestBean EJB: java.lang.IllegalStateException: Exception attempting to inject Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session into class mvs.test.TestController Caused by: com.sun.enterprise.container.common.spi.util.InjectionException: Exception attempting to inject Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session into class mvs.test.TestController Caused by: javax.naming.NamingException: Lookup failed for 'java:comp/env/mvs.test.TestController/testBean' in SerialContext [Root exception is javax.naming.NamingException: Exception resolving Ejb for 'Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session' . Actual (possibly internal) Remote JNDI name used for lookup is 'mvs.test.TestBean#mvs.test.TestBean' [Root exception is javax.naming.NamingException: Lookup failed for 'mvs.test.TestBean#mvs.test.TestBean' in SerialContext [Root exception is javax.naming.NameNotFoundException: mvs.test.TestBean#mvs.test.TestBean not found]]] So my questions are: - is this the correct way of injecting a session bean into another bean (particularly a message driven bean)? - why is the naming lookup failing? Thanks for all your help! Cheers, Hank

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  • Problems with zend-tool reporting that providers are not valid

    - by Mario
    I have recently setup XAMPP 1.7.3 and ZendFramework 1.10.4 on a new computer and many of the commands that I normally use now fail. Here are the steps I used to setup and test ZF. First I added the ZF library folder (C:\xampp\php\ZendFramework-1.10.4\library) to the include path in php.ini. Then I added the ZF bin folder (C:\xampp\php\ZendFramework-1.10.4\bin) to my Path system variable. To test that everything is configured correctly I ran the command "zf show version" from the command line. The result is "Zend Framework Version: 1.9.6". Immediately something appears to be wrong. The file that is downloaded is "ZendFramework-1.10.4.zip" and the reported version is 1.9.6. I have re-downloaded the latest version (1.10.4) and removed old copy. Still the incorrect version number problem persisted. Having done some research there is a bug in the ZF knowledgebase that version 1.10.3 reports a wrong version number. So that may explain the version number problem. Moving forward I tried to run some zf-tool commands and certain commands reports that the action or provider is not valid. Example: C:\xampp\htdocs>zf create project test Creating project at C:/xampp/htdocs/test C:\xampp\htdocs>cd test C:\xampp\htdocs\test>zf create controller Test Creating a controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf create action test Test Creating an action named test inside controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf enable layout An Error Has Occurred Action 'enable' is not a valid action. ... C:\xampp\htdocs\test>zf create form Test An Error Has Occurred Provider 'form' is not a valid provider. ... Can any one provide insight into these errors and how to correct them?

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