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  • 500 error on function call in Codeigniter

    - by Ilia Lev
    I am using just installed CI 2.1.3 Following phpacademy tutorial I wrote in the routes.php: $route['default_controller'] = "site"; (instead of: $route['default_controller'] = "welcome";) and in controllers/site.php: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Site extends CI_Controller { public function index() { echo "default function started.<br/>"; } public function hello(){ echo "hello function started.<br/>"; } } After uploading it to the server and going to the [www.mydomain.ext] it works ok (writes: "default function started.") BUT if I add 'this-hello();' to the index() function it throws a 500 error. Why does it happen and how can I resolve this? Thank you in advance.

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  • Codeigniter how to access class variables

    - by Obay
    I thought this was going to be a no-brainer but I can't seem to access member variables: class MyObject extends Controller { private $START_OF_WEEK = 1; /* constructor here */ function index() { echo $this->$START_OF_WEEK; } } echo $this->$START_OF_WEEK; says Cannot access empty property How do I access member variables? Or... how do I declare them correctly?

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  • codeigniter: how to redirect after login to current controller (php_self in regular php)

    - by krike
    Well it's not really a problem but I check if the user exist and log them in and redirect to site/members_area, but I don't want to send the user to a specific page but i want to reload the current controller. So if I login in index/home I would like to be redirected at index/home, how should I proceed? in regular php I would put in the action to redirect to current page <?php echo $_SERVER['PHP_SELF']; ?> This is the code in the framework function validate_credentials() { $this->load->model('membership_model'); $query = $this->membership_model->validate(); if($query) // if the user's credentials validated... { $data = array( 'username' => $this->input->post('username'), 'is_logged_in' => true ); $this->session->set_userdata($data); redirect('site/members_area'); //<-- this line here should be dynamic } else // incorrect username or password { $this->index(); } }

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  • Problem with my Jquery loading in my Codeigniter views

    - by sico87
    Hello, I am working on a one page website that allows the users to add and remove pages from there navigation as and when they would like too, the way it works is that if the click 'Blog' on the main nav a 'Blog' section should appear on the page, if they then click 'News' the 'News' section should also be visible, however the way I have started to implement this it seems I can only have one section at a time, can my code be adpated to allow multiple sections to shown on the main page. Here is my code for the page that has the main menu and the users selections on it. <!DOCTYPE html> <head> <title>Development Site</title> <link rel="stylesheet" href="/media/css/reset.css" media="screen"/> <link rel="stylesheet" href="/media/css/generic.css" media="screen"/> <script type="text/javascript" src="/media/javascript/jquery-ui/js/jquery.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.core.js"></script> <script type="text/javascript" src="/media/javascript/jquery-ui/development-bundle/ui/ui.accordion.js"></script> <script type="text/javascript"> $(document).ready(function() { $('a.menuitem').click(function() { var link = $(this), url = link.attr("href"); $("#content_pane").load(url); return false; // prevent default link-behavior }); }); </script> </head> <body> <li><a class="menuitem" href="inspiration">Inspiration</a></li> <li><a class="menuitem" href="blog">Blog</a></li> <div id="content_pane"> </div> </body> </html>

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  • sending email with codeigniter

    - by Maru
    I have this MODEL and I get the email which I want to send class Cliente_Model extends CI_Model{ public function getInfo($id){ $this->db->select('*'); $this->db->from('pendientes'); $query = $this->db->get(); if($query->num_rows() > 0) { foreach ($query->result_array() as $row) { return $row['email']; } } else { return FALSE; } } } CONTROLLER $this->load->model('cliente_model', 'client'); $clientInfo = $this->client->getInfo($id); $this->email->from('[email protected]', 'Demo'); $this->email->to($clientInfo); $this->email->subject('Email Test'); $this->email->message('your user is '.$clientInfo.' and your password is '.$clave); $this->email->send(); and I need some help here, I can get the email and it can send it perfectly but in the message I need to send the password also and I don't know how I can get it from the model. thanks in advance!

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  • photo upload with codeigniter

    Hi friends, I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

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  • Codeigniter Form validation problem

    - by ben robinson
    Please please please can someone help me $this-load-library('form_validation'); $this-load-helper('cookie'); $data = array(); if($_POST) { // Set validation rules including additional validation for uniqueness $this-form_validation-set_rules('yourname', 'Your Name', 'trim|required'); $this-form_validation-set_rules('youremail', 'Your Email', 'trim|required|valid_email'); $this-form_validation-set_rules('friendname', 'Friends Name', 'trim|required'); $this-form_validation-set_rules('friendemail', 'Friends Email', 'trim|required|valid_email'); // Run the validation and take action if($this-form_validation-run()) { echo 'valid; } } else{ echo 'problem'; } Form validation is coming back with no errors can cany one see why?

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  • CodeIgniter helper inside controllers

    - by kapitanluffy
    can i call helper functions inside controller classes? let's say i have this controller with the _open_form method class User extends Controller { function _open_form($action){ print_r(form_open($action)); } } i tried echoing out the result of form_open() but it returns null. it seems that helper functions can't be called inside controllers if your wondering why i need to use it inside the controller instead in the view because we are required to use the given template parser xD

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  • How to make a proper index page for subdirectories in CodeIgniter

    - by iamdadude
    I'm building an app that has a section for consumers and businesses, and I want to separate the controllers folder appropriately, so it looks like this - http://domain.com/users/signup/ http://domain.com/business/signup/ I have it working by creating a separate folder for each section in the "controllers" folder, but I want to know how to make an appropriate page when the user visits the http://domain.com/users/. It currently just loads the homepage. How can I fix this?

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  • jquery ajax post not working with .load in codeigniter

    - by bravo
    i wish to .load multiple views result with jquery ajax the original code (js) $(document).ready(function(){ $("#uid").change( function(){ var uid=$("#uid").val(); $.ajax({ type: "POST", url: "<?= site_url('sp_profile/ajax_userdetail') ?>", dataType: "json", data: "uid="+uid, cache:false, success: function(data){ $("#content").html(data); } }); return false; }); }); this return only one result in what if i want to load 3 results like in <div id="content"></div> <div id="content1"></div> <div id="content2"></div> content could be userid content2 could be user first name content3 could be user last name my js should using .load instead of html right? let me know if i'm wrong. success: function(data){ $("#content").load("<?= site_url('sp_profile/ajax_userdetail')?>"); $("#content2").load("<?= site_url('sp_profile/ajax_userdetail')?>"); $("#content3").load("<?= site_url('sp_profile/ajax_userdetail')?>"); } i stuck with this thing for whole day.. please anyone show me the right way to do the controller and js code.

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  • Codeigniter multi language url

    - by Thang Bui
    Please help me. I search 2 hours but do not see any solutions for my case. My customer request me the multi language but they want the link as: http://site.com/controller_name/lang_code Or http://site.com/controller_name/paramenter1/parameter2/lang_code The language code is always at the last segment. It is stored in the session. The url maybe also http://site.com/controller_name/ Or http://site.com/controller_name/paramenter1/parameter2/ In this case. The language stored in session will be loaded, but the url don't need to display it. I try i18n library, but it cannnot solve my problem. Can anyone help me

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  • Problems uploading different file types in codeigniter

    - by Drew
    Below is my script that i'm using to upload different files. All the solutions I've found deal only with multiple image uploads. I am totally stumped for a solution on this. Can someone tell me what it is i'm supposed to be doing to upload different files in the same form? Thanks function do_upload() { $config['upload_path'] = './uploads/nav'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload('userfile')) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $soundfig['upload_path'] = './uploads/nav'; $soundfig['allowed_types'] = 'mp3|wav'; $this->load->library('upload', $soundfig); if ( ! $this->upload->do_upload('soundfile')) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data('userfile'); $sound = $this->upload->data('soundfile'); $full_path = 'uploads/nav/' . $data['file_name']; $sound_path = 'uploads/nav/' . $sound['file_name']; if($this->input->post('active') == '1'){ $active = '1'; }else{ $active = '0'; } $spam = array( 'image_url' => $full_path, 'sound' => $sound_path, 'active' => $active, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } } Here is my form: <?php echo form_open_multipart('upload/do_upload');?> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->name; ?></h2> <input type="file" name="userfile" size="20" /><br /> <input type="file" name="soundfile" size="20" /> <input type="hidden" name="oldfile" value="<?php echo $row->image_url; ?>" /> <input type="hidden" name="id" value="<?php echo $row->id; ?>" /> <br /><br /> <label>Url: </label><input type="text" name="url" value="<?php echo $row->url; ?>" /><br /> <input type="checkbox" name="active" value="1" <?php if($row->active == '1') { echo 'checked'; } ?> /><br /><br /> <input type="submit" value="submit" /> </form> <?php endforeach; ?> <?php endif; ?>

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  • Auto complete from database using CodeIgniter (Active Record)

    - by Ralph David Abernathy
    I have a form on my website in which one is able to submit a cat. The form contains inputs such as "Name" and "Gender", but I am just trying to get the auto completion to work with the "Name" field. Here is what my jquery looks like : $(document).ready(function() { $( "#tags" ).autocomplete({ source: '/Anish/auto_cat' }); }); Here is what my model looks like: public function auto_cat($search_term) { $this->db->like('name', $search_term); $response = $this->db->get('anish_cats')->result_array(); // var_dump($response);die; return $response; } } Here is my controller: public function auto_cat(){ $search_term = $this->input->get('term'); $cats = $this->Anish_m->auto_cat($search_term); } And here is my view: <head> <link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" /> <script src="http://code.jquery.com/jquery-1.9.1.js"></script> <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script> <link rel="stylesheet" href="/resources/demos/style.css" /> </head> <h1>Anish's Page</h1> <form action="/Anish/create" method="POST"> <div class="ui-widget"> <label for="tags">Name</label><input id="tags" type="text" name="name"> </div> <div> <label>Age</label><input type="text" name="age"> </div> <div> <label>Gender</label><input type="text" name="gender"> </div> <div> <label>Species</label><input type="text" name="species"> </div> <div> <label>Eye Color</label><input type="text" name="eye_color"> </div> <div> <label>Color</label><input type="text" name="color"> </div> <div> <label>Description</label><input type="text" name="description"> </div> <div> <label>marital status</label><input type="text" name="marital_status"> </div> <br> <button type="submit" class="btn btn-block btn-primary span1">Add cat</button> </form> <br/><br/><br/><br/> <table class="table table-striped table-bordered table-hover"> <thead> <tr> <th>Name</th> <th>Gender</th> <th>Age</th> <th>Species</th> <th>Eye Color</th> <th>Color</th> <th>Description</th> <th>Marital Status</th> <th>Edit</th> <th>Delete</th> </tr> </thead> <tbody> <?php foreach ($cats as $cat):?> <tr> <td> <?php echo ($cat['name']);?><br/> </td> <td> <?php echo ($cat['gender']);?><br/> </td> <td> <?php echo ($cat['age']);?><br/> </td> <td> <?php echo ($cat['species']);?><br/> </td> <td> <?php echo ($cat['eye_color']);?><br/> </td> <td> <?php echo ($cat['color']);?><br/> </td> <td> <?php echo ($cat['description']);?><br/> </td> <td> <?php echo ($cat['marital_status']);?><br/> </td> <td> <form action="/Anish/edit" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id_edit"> <button class="btn btn-block btn-info">Edit</button> </form> </td> <td> <form action="/Anish/delete" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id"> <button class="btn btn-block btn-danger">Delete</button> </form> </td> </tr> <?php endforeach;?> </tbody> </table> I am stuck. In my console, I am able to see this output when I type the letter 'a' if I uncomment the var_dump in my model: array(4) { [0]=> array(9) { ["id"]=> string(2) "13" ["name"]=> string(5) "Anish" ["gender"]=> string(4) "Male" ["age"]=> string(2) "20" ["species"]=> string(3) "Cat" ["eye_color"]=> string(5) "Brown" ["color"]=> string(5) "Black" ["description"]=> string(7) "Awesome" ["marital_status"]=> string(1) "0" } [1]=> array(9) { ["id"]=> string(2) "16" ["name"]=> string(5) "Anish" ["gender"]=> string(2) "fe" ["age"]=> string(2) "23" ["species"]=> string(2) "fe" ["eye_color"]=> string(2) "fe" ["color"]=> string(2) "fe" ["description"]=> string(2) "fe" ["marital_status"]=> string(1) "1" } [2]=> array(9) { ["id"]=> string(2) "17" ["name"]=> string(1) "a" ["gender"]=> string(1) "a" ["age"]=> string(1) "4" ["species"]=> string(1) "a" ["eye_color"]=> string(1) "a" ["color"]=> string(1) "a" ["description"]=> string(1) "a" ["marital_status"]=> string(1) "0" } [3]=> array(9) { ["id"]=> string(2) "18" ["name"]=> string(4) "Matt" ["gender"]=> string(6) "Female" ["age"]=> string(2) "80" ["species"]=> string(6) "ferret" ["eye_color"]=> string(4) "blue" ["color"]=> string(4) "pink" ["description"]=> string(5) "Chill" ["marital_status"]=> string(1) "0" } }

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  • AJAX contact form in CodeIgniter

    - by Ross
    Few questions: I'm using CI and JQuery AJAX. In my code below, I assemble dataString, which by default, is appended to the URL as a query string. I've changed the AJAX "type" to POST, so my question is - how do I access dataString in my CI app? It would seem I still have to use $name=$this->input->post('name') Which to me, makes setting dataString redundant? -- I've tried searching but can't really find anything concrete. Would it be possible to still make use of CIs validation library and AJAX? if($this->form_validation->run() == FALSE) { // what can i return so that my CI app shows errors? } Normally you would reload the contact form or redirect the user. In an ideal world I would like the error messages to be shown to the user. Jquery: $(document).ready(function($){ $("#submit_btn").click(function(){ var name = $("input#name").val(); var company = $("input#company").val(); var email = $("input#email").val(); var phone = $("input#phone").val(); var message = $("textarea#message").val(); var dataString = 'name=' + name + '&message=' + message + '&return_email=' + email + '&return_phone=' + phone + '&company=' + company; var response = $.ajax({ type: "POST", url: "newsite/contact_ajax/", data: dataString }).responseText; //$('#contact').hide(); //$('#contact').html('<h5>Form submitted! Thank you!</h5><h4>We will be in touch with you soon.</h4>'); //$('#contact').fadeIn('slow'); return false; }); }); hope i've been clear enough - if anyone has a decent example of a CI contact form that would be great. there's mixed stuff on the internet but nothing that hits all the boxes. thanks

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  • PHP & CodeIgniter Error: open_basedir restriction in effect

    - by iamdadude
    open_basedir restriction in effect. File(/var/www/vhosts/domain.com) is not within the allowed path(s): (/var/www/vhosts/domain.com/httpdocs:/tmp) How do I securely fix this? This is preventing me from listing and creating directories outside of the current directory. What I mean by securely is that I don't want to remove a piece of code from a configuration file and potentially make it easier for hackers to do whatever.

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  • url encoded forward slashes breaking my codeigniter app

    - by Ian Cook
    i’m trying to create a url string that works like this: /app/process/example.com/index.html so in other words, /app/process/$URL i then retrieve the url with $this->uri->segment(3); the forward slashes in the URL will of course be a problem accessing uri segments, so i’ll go ahead and url encode the URL portion: /app/process/example.com%2Findex.html .. but now I just get a 404 saying ... Not Found The requested URL /app/process/example.com/index.html was not found on this server. it appears that my url encoding of forward slashes breaks CI’s URI parser. what can i do to get around this problem?

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  • Codeigniter: Simple ajax submit not working

    - by Kevin Brown
    jQuery: $('#welcome-message').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit({}); $(this).fadeTo(400, 0, function () { // Links with the class "close" will close parent $(this).slideUp(400); }); return false; }); Controller: function welcome_message() { if(isset($_POST['welcome_message'])) { $this-_my_private_function(); } } private function _my_private_function() { $id = $this->session->userdata('id'); $profile['welcome_message'] = '0'; $this->db->update('be_user_profiles',$profile, array('user_id' => $id)); redirect('home', 'location'); } html: <?php print form_open('home/welcome_message',array('class'=>'horizontal','id'=>'welcome-message'))?> <p> Before you can complete the assessment, you need to complete your profile. Once that's done you'll be ready! After you have completed the assessment, you will be able to view the results from your profile. </p> <input type="checkbox" value="0" name="welcome_message" checked="false"> Don't show me this again </input> <p> <input class="button submit" type="submit" class="close-box" value="Close" /> </p> <?php print form_close()?> This should be working. My hypothesis is that the data isn't being passed to the function...but I really have no idea! It works when I visit the function in the url.

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  • Codeigniter - form not rendering on live server?

    - by pingu
    hi guys, I've written a small website with CI, which is all working fine on dev. However, when I copy the files over for live, everything works except for my form which is not being rendered. I am using <?php echo form_open('home'); ?> and <?php echo form_close(); ?> The form fields within the form, which I'm generating as follows are being rendered fine, but there is simply no form around them?! <?php $data = array( 'name'=> 'name', 'id'=> 'name', 'class'=>'textfield', 'value' => set_value('name') ); echo form_input($data); ?> Any ideas - I've used CI on a few apps, and this is the first time I've come across this issue. I've got all the helpers etc called correctly, as this is working perfectly in the development environment.

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  • Cannot exit in CodeIgniter constructor

    - by gzg
    I'm basically trying a session control. If the user is logged in, it's ok to move on. But if he's not logged in, then it will show a log-in screen and then die. However, when I use die or exit in the constructor, it does not show the log-in screen; it immediately dies. The code is as following: private $username = null; private $mongoid = null; private $neoid = null; public function __construct(){ parent::__construct(); // session to global $this->username = $this->session->userdata( 'username'); $this->mongoid = $this->session->userdata( 'mongoid'); $this->neoid = $this->session->userdata( 'neoid'); // check if user is logged in if( $this->username == "" || empty( $this->username)){ $this->load->view( 'access/login'); die; } } It shows the log-in page if die is not written there, but with die, it does not show. Why do I want to use die? Because if I don't use, it moves on the index function and I don't want it to execute index function if the user is not logged in. What is wrong here? What should I use to stop executing?

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  • How to change Controllers/Models source directory in CodeIgniter

    - by Ady Mareshal
    I need to load controllers and models from a different folder than the default one. I am using a Linux system. I am building a simple CI application for some people, for use on a shared hosting I own. But I want to give them access only to /views folder and some /config files. And this is why I need to store the controllers and models in a different folder on the same level as /public_html folder or maybe somewhere in the linux system. I consider this would be a better solution than encoding files

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  • Passing Results from SQL to Google Maps API in CodeIgniter

    - by Jason Shultz
    I'm hoping to use google maps on my site. My addresses are stored in a db. I’m pulling up a page where the information is all dynamic. For example: mysite.com/site/business/5 (where 5 is the id of the business). Let’s say I do a query like this: function addressForMap($id) { $this->db->select(‘b.id, b.busaddress, b.buscity, b.buszip’); $this->db->from(‘business as b’); $this->db->where(‘b.id, $id); } How can I output the info to the google maps api correctly so that it display’s the map appropriately? The API interface takes the results like this: $marker['address'] = 'Crescent Park, Palo Alto';

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  • rewrite rule for codeigniter

    - by John
    this is my controller in CI class Welcome extends Controller { function Welcome() { parent::Controller(); } function index() { } function bil($model='') { } I want to do a rewrite so that http://example.com/index.php/welcome/bil/model becomes http://example.com/model in my htaccess I have RewriteBase / RewriteCond $1 !^(index\.php|images|robots\.txt) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /index.php/welcome/$1 [L] #RewriteRule ^(.*)$ /index.php/welcome/bil/$1 [L] I thought it should be as easy as removing the /index.php/welcome/ part but when I uncomment the last line it get 500 internal server error

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