Search Results

Search found 1343 results on 54 pages for 'burning the codeigniter'.

Page 18/54 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • Codeigniter: validation problem

    - by krike
    For some reason a user can login with any password, first I thought I forgot to check for the password but I didn't... and I just cant find the problem here is the model: /*#######################################################*/ function validate() /*#######################################################*/ { $this->db->where('username', $this->input->post('username')); $this->db->where('password', md5($this->input->post('password'))); $q = $this->db->get('user_extra'); if($q->num_rows() == 1): return true; else: return false; endif; }//end of function validate() The controller /*#######################################################*/ function validate_credentials() /*#######################################################*/ { $this->load->model('membership_model'); $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Name', 'trim|required'); $this->form_validation->set_rules('password', 'password', 'trim|required'); if(!$this->membership_model->validate()): $this->form_validation->set_message('check_login', 'Login not correct, please try again.'); endif; if($this->form_validation->run() == FALSE): $this->index(); else: $this->membership_model->userinfo($this->input->post('username')); //should redirect to last view redirect($this->session->flashdata('redirect_url')); endif; }// end of validate_credentials()

    Read the article

  • Passing arguments and conditions to model in codeigniter

    - by stormdrain
    I'm adding some models to a project, and was wondering if there is a "best practice" kind of approach to creating models: Does it make sense to create a function for each specific query? I was starting to do this, then had the idea of creating a generic function that I could pass parameters to. e.g: Instead of function getClients(){ return $this->db->query('SELECT client_id,last FROM Names ORDER BY id DESC'); } function getClientNames($clid){ return $this->db->query('SELECT * FROM Names WHERE client_id = '.$clid); } function getClientName($nameID){ return $this->db->query('SELECT * FROM Names WHERE id ='.$nameID); } } Something like function getNameData($args,$cond){ if($cond==''){ $q=$this->db->query('SELECT '.$args.' FROM Names'); return $q; }else{ $q=$this->db->query('SELECT '.$args.' FROM Names WHERE '.$cond); return $q; } } where I can pass the fields and conditions (if applicable) to the model. Is there a reason the latter example would be a bad idea? Thanks!

    Read the article

  • CodeIgniter - the right way to create "block" elements on web page

    - by kikkoman90
    Hello. I've been searching for a solutions for this problem a while but haven't seen any "valid mvc" solution for this. I hope I can explain my problem clearly enough for you guys. I need to create a dynamic block of HTML on my website. (eg. a block containing user's latest blog comments). I have a template view file (a file containing header, content container and a footer) where I need to add some content AND this block element. The problem is that I don't want to duplicate this block code on every controller. It just feels stupid and I'm sure there's a better way to do this than just duplicating same stuff all over again on all the controller files? I can add view inside another view just fine, but what bugs me is how to actually generate that dynamic content to this block's view-file. I can't call controller from view file, controller from controller filem or model from view file because what I understand that just isn't the "mvc" way? Anyone got any tricks or tips for this?

    Read the article

  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

    Read the article

  • Codeigniter: how should I restructure db schema?

    - by Kevin Brown
    I don't even know if that's the right term. May it be known that I'm a major novice! I have three tables: users, profiles, and survey. Each one has user_id as it's first field, (auto-increment for users), and they're all tied by a foreign key constraint, CASCADE on DELETE. Currently, for each user, let's say user_id 1, they have a corresponding db entry in the other tables. For profiles it lists all their information, and the survey table holds all their survey information. Now I must change things...darn scope creep. Users need the ability to have multiple survey results. I imagine that this would be similar to a comment table for a blog... My entire app runs around the idea that a single user is linked to a constraining profile and survey. How should I structure my db? How should I design my app's db so that a user can have multiple tests/profiles for the test? Please assist! Any advice, information and personal-knowledge is appreciated! Right now the only way I know how to accompany my client is to create a pseudo-user for each test (so unnecessary) and list them in a view table (called "your tests")-- these are obtained from the db by saying: where user_id=manager_id

    Read the article

  • Codeigniter: user defined helper function does not load.

    - by cbrandolino
    Hi everybody. I made a custom helper extending the system string_helper.php. I placed it in my /application/helpers folder, called MY_string_helper.php as required, unit-tested its functions. Now, when I try to call one of its functions from a model, it does not work. The functions in the default string helper work, instead. It looks like my extension is not loaded for some reasons. Thanks a lot, and happy holidays.

    Read the article

  • codeigniter differentiate field names in JOINed tables

    - by Patrick
    Hi, I need to retrieve data from two tables. the first is a list of events, the second is a list of venues. I have a fields with the same name in both tables: events.venue (which is an ID) and venues.venue is the name of the place, say "blues bar". The tables can be joined on events.venue = venues.id. Snippet of my model: $this->db->select('events.*, venues.*'); $this->db->join('venues', 'events.venue = venues.id'); if ($date != 'all') { $this->db->where('date', $date); } if ($keyword) { $this->db->like('description', $keyword); $this->db->or_like('band', $keyword); $this->db->or_like('venue', $keyword); $this->db->or_like('genre', $keyword); } $Q = $this->db->get('events'); if ($Q->num_rows() > 0) { foreach ($Q->result() as $row) { $data[] = $row; } } $Q->free_result(); return $data; Snippet of the View: foreach ($events as $row) { echo "<p>{$row->band} ({$row->genre})<br />"; echo "Playing at: {$row->venue}<br /></p>"; // echoes "blues bar" //more here... } 2 Questions: 1) Why does $row-venue echo venues.venue, instead of events.venue? B) how can I differentiate them? eg. What if I want to echo both events.venue and venues.venue? I can probably do something like "SELECT venues.venue as name_of_the_venue", but how can I do this when I've already selected *?

    Read the article

  • CodeIgniter URI segments captured as variables?

    - by Zen Savona
    well, i have a function within a controller called test, and i can access it by going to http://localhost/nwk/control/test this is my function. I want to use the data given in the next segment from the "test" as a php variable. so if i put function test() { $var $this->uri->segment(3); echo $var; } according to the user guide if I enter control/test/data, my variable should be equal to 'data'? doesn't seem to be working. Am I missing something here?

    Read the article

  • CodeIgniter -- unable to use an object

    - by Smandoli
    THE SUMMARY: When I call .../index.php/product, I receive: Fatal error: Call to a member function get_prod_single() on a non-object in /var/www/sparts/main/controllers/product.php on line 16 The offending Line 16 is: $data['pn_oem'] = $this->product_model->get_prod_single($product_id); Looks like I don't know how to make this a working object. Can you help me? THE CODE: In my /Models folder I have product_model.php: <?php class Product_model extends Model { function Product_model() { parent::Model(); } function get_prod_single($product_id) { //This will be a DB lookup ... return 'foo'; //stub to get going } } ?> In my /controllers folder I have product.php: <?php class Product extends Controller { function Product() { parent::Controller(); } function index() { $this->load->model('Product_model'); $product_id = 113; // will get this dynamically $data['product_id'] = $product_id; $data['pn_oem'] = $this->product_model->get_prod_single($product_id); $this->load->view('prod_single', $data); } } ?>

    Read the article

  • Logging in to Wordpress through CodeIgniter DX Authentication

    - by whobutsb
    Hello All, I'm about to start a very large project of rebuilding my companies intranet. The plan is to have most of the intranet live in a CI application. I chose to use CI because i'm very familiar with all the CI methods. Some sections of the intranet are going to be wordpress blogs. For example the Human Resources Dept. and the Marketing Dept will have their own wordpress blogs. Ideally my plan is to log on to the intranet, with a CI authentication library like DXAuth by querying the Active Directory of the company. When I return the AD information for the user I will by saving their group memberships into a session. It would be fantastic if I could have that session information of the user be used by wordpress to log the user as an editor if they are a member of the Marketing Group. And allow users who are not members of the group be able to comment on that blog, with out logging into wordpress. My question is if there are any CI classes or Wordpress Plugins, or tutorals out there, of this sort of integration with the two systems. Thank you for your help!

    Read the article

  • Codeigniter - Active record - sql - complex join

    - by Jack
    I have a function that retrieves all tags from a table: function global_popular_tags() { $this->db->select('tags.*, COUNT(tags.id) AS count'); $this->db->from('tags'); $this->db->join('tags_to_work', 'tags.id = tags_to_work.tag_id'); $this->db->group_by('tags.id'); $this->db->order_by('count', 'desc'); $query = $this->db->get()->result_array(); return $query; } I have another table called 'work'. The 'work' table has a 'draft' column with values of either 1 or 0. I want the COUNT(tags.id) to take into account whether the work with the specific tag is in draft mode (1) or not. Say there are 10 pieces of work tagged with, for example, 'design'. The COUNT will be 10. But 2 of these pieces of work are in draft mode, so the COUNT should really be 8. How do I manage this?

    Read the article

  • CodeIgniter - Calling a function from inside a view

    - by Chris
    Hey, Is it possible to call a function which is located in a controller from a view. This is what i have in my controller, as an example function checkKeyExists($userid, $key){ } Then inside my view i have the following if(checkKeyExists($row->id, $role->key)){ } But when i run it, it says that checkKeyExists is not defined. If anyone can let me know how i could do this, that would be great. Cheers

    Read the article

  • Using PHP interfaces in Codeigniter

    - by John Stewart
    I am trying to find out how can I used PHP interfaces in my MVC design. I want to make sure that the design enforces an interface so that any new module would follow that. For example: <?php interface BaseAPI { public function postMessage($msg); } class ServiceAPI implements BaseAPI { public function postMessage($msg) { return $msg; } } class Service_Two_API implements BaseAPI { public function postMessage($msg) { return "can't do this: ".$msg; } } ?> I want to do this in CI. Is it possible? how should I design it?

    Read the article

  • CodeIgniter URI routing (dynamic, multilingual)

    - by koteko
    I'm trying to redirect all routs to one main controller. Here is my routes.php $route['default_controller'] = "main"; $route['scaffolding_trigger'] = ""; //$route['(\w{2})/(.*)'] = '$2'; //$route['(\w{2})'] = $route['default_controller']; $route['(en|ge)/(:any)'] = $route['default_controller']."/index/$1"; $route['(:any)'] = $route['default_controller']."/index/$1"; I need language id to be passed with every link (like: http://site.com/en/hello-world) Here is my main controller: class Main extends Controller { function __construct() { parent::Controller(); } function index($page_type=false, $param=false) { die($page_type.' | '.$param.'| Aaa!'); } } I want to check if predefined file type exists (like: http://site.com/en/archive/05-06-2010 - here predefined type would be archive) then do something. If not then search in the database for slug. If not found then go to 404. The problem is that I can't get index function parameters ($page_type, $param). Thanks for help.

    Read the article

  • CodeIgniter: help with this query

    - by iamjonesy
    Hi, I have just started my first CI app. I have a view that displays some posts. Each post can have multiple comments and I want to display the total number of comments next to each post. So far all my db call are in my controller (will be changing this). function index(){ $data['query'] = $this->db->get('posts'); $this->load->view('blog_view', $data); } In my view: <?php foreach($query->result() as $row): <div class="post-box"> <p><?php echo $row->body; ?><small>&nbsp;added by <?php echo $row->username; ?> on <?php echo date ('d/m/Y',strtotime($row->created)); ?>&nbsp;<a href="<?php echo base_url(); ?>blog/comments/<?php echo $row->id; ?>"><img src="<?php echo base_url(); ?>images/comments_icon.png" />&nbsp;0</a></small></p> </div> <?php endforeach; ?> I want to get the total number of comments where comment.post_id = the current record's id. and display it next to the comments icon. Any help with this most appreciated, Billy

    Read the article

  • Redirect in codeigniter after login

    - by edelweiss
    Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

    Read the article

  • Running CodeIgniter cron on localhost

    - by stef
    I'm trying to get a cron job to run every 5 min on my localhost. Using the Cronnix app I entered the following command 0,5 * * * * root curl http://localhost:8888/site/ > /dev/null The script runs fine when I visit http://localhost:8888/site/ in my browser. I've read some stuff about getting CI to run on Cron, using wget and various other options but none make a lot of sense. In another SO post I found the following command wget -O - -q -t 1 http://www.example.com/cron/run What is the "-O - -q -t 1" syntax exactly? Are there other options?

    Read the article

  • Codeigniter - selecting children and parents from db

    - by Tomek Buszewski
    I want to pull from my database records corresponding to parent_id, like this: function getChildren($id, $parent_id) { $q = $this->db->select('id, name, slug, plat'); $q = $this->db->from('games'); $q = $this->db->where('parent_id',$id); $q = $this->db->or_where('id',$parent_id); $q = $this->db->get(); return $q->result_array(); } It - if it's a children game - get parent_id and search for a game with such id and for other games that has parent_id same as this one. If it's the parent game, it only looks for games with parent_id same as it's id. The problem is... it's not always working. I have four games in db: id | parent_id | title 15 | 0 | Abe 19 | 15 | Abe 20 | 0 | RE2 21 | 20 | RE2 DS First two works, last two - only children (id = 21) shows parent.

    Read the article

  • MVC - thin controller idea - Codeigniter/Zend

    - by user505988
    Hi, Could some one possibly clarify this for me. In the MVC paradigm, the idea is to keep the controller as thin as possible, it is also true that the model is the bit that communicates with data sources such as the database, XML-RPC etc and this is where the business logic should go. Is the POST and GET data a 'data source' and should that kind of data be handled by the model or should it be by the controller. I would normally call a method in the model and pass it the post data, the data would be quality checked by the controller and the model method would simply do the insertion or whatever. Should it be though that controller just calls the model method if a post has occured and it is responsible for sanity check, data checks etc.

    Read the article

  • codeigniter problem at localhost.

    - by sabuj
    Previously i installed CI in xampp. After that i installed wamp on for xampp but the project don't run accurately. It shows the following error- Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, admin@localhost and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. Please give me a solution.....

    Read the article

  • Getting the hang of CodeIgniter - Templating / loading views

    - by kilrizzy
    Attempting to learn CI and going through the docs to get a better understanding. Without getting a separate library, I could make a template by including a list of views like so: $this->load->view('header'); $this->load->view('navigation'); $this->load->view('sidenav_open'); $this->load->view('blocks/userinfo'); $this->load->view('blocks/stats'); $this->load->view('sidenav_close'); $this->load->view('content',$data); $this->load->view('footer'); This makes sense but would I actually have that on each of my controllers (pages)? Not sure if there is a way to include this in the initial controller (welcome) and then in the others somehow reference it? Or perhaps there is something I am missing completely

    Read the article

  • Use where clause with Like in codeigniter

    - by user2524013
    I am working on a project. I am implementing the Search functionality in my System. I will have to show the search record from two tables base on the current use login. I have tried the following code: function searchActivity($limit,$offset,$keyword1,$keyword2,$recruiter_id) { $q=$this->db->select('*')->from('tbl_activity')->limit($limit,$offset); $this->db->join('tbl_job', 'tbl_job.job_id = tbl_activity.job_id_fk', 'left outer'); $this->db->order_by("activity_id", "ASC"); $this->db->like('job_title',$keyword1,'both'); $this->db->or_like('job_title',$keyword2,'both'); $this->db->or_like('activity_subject',$keyword1,'both'); $this->db->or_like('activity_subject',$keyword2,'both'); $this->db->or_like('activity_details',$keyword1,'both'); $this->db->or_like('activity_details',$keyword2,'both'); $this->db->where('tbl_activity.recruiter_id_fk',$recruiter_id); $ret['rows']=$q->get()->result(); return $ret; } I want to show search results based on the current user id, which is currently store in $recruiter. Thanks in advance.

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >