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  • Defautlt Contoller in CodeIgniter

    - by gregavola
    Hello everyone, I am wondering if there is any other configuration options for a default controller. For example - if I have a controller called "site" and I set the default controller in the following file: application/config/routes.php to: $route['default_controller'] = "site"; I should be able to go to http://localhost and that brings up the index(); function in the site controller. However, if I try to do go to http://localhost/index.php/index2 to load the index2(); function I get a 404 error. If i change the URL to http://localhost/index.php/site/index2 it works fine - but I thought already set the default controller. Is there any way around this? Any thoughts?

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  • Use where clause with Like in codeigniter

    - by user2524013
    I am working on a project. I am implementing the Search functionality in my System. I will have to show the search record from two tables base on the current use login. I have tried the following code: function searchActivity($limit,$offset,$keyword1,$keyword2,$recruiter_id) { $q=$this->db->select('*')->from('tbl_activity')->limit($limit,$offset); $this->db->join('tbl_job', 'tbl_job.job_id = tbl_activity.job_id_fk', 'left outer'); $this->db->order_by("activity_id", "ASC"); $this->db->like('job_title',$keyword1,'both'); $this->db->or_like('job_title',$keyword2,'both'); $this->db->or_like('activity_subject',$keyword1,'both'); $this->db->or_like('activity_subject',$keyword2,'both'); $this->db->or_like('activity_details',$keyword1,'both'); $this->db->or_like('activity_details',$keyword2,'both'); $this->db->where('tbl_activity.recruiter_id_fk',$recruiter_id); $ret['rows']=$q->get()->result(); return $ret; } I want to show search results based on the current user id, which is currently store in $recruiter. Thanks in advance.

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  • Using Wildcards in CodeIgniter

    - by tpae
    Wildcards are cool. I am trying to do this: $route["(:any)/controller"] = "controller"; basically, I want to put the wildcard in the front. It doesn't quite work, and I don't know any work around.

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  • temp. download links (with codeigniter)

    - by Ayrton
    Hi everyone I was wondering how I could start generating temporarily download links based on files from a protected directory (e.g. /downloads/). These links need to be valid until someone used it 5 times or so or after a week or so, after that the link shouldn't be accessible anymore. Any help would be appreciated.

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  • removing index.php of codeigniter on local

    - by Aldi Aryanto
    i'm trying to remove index.php,in my localhost, but it seems doesn't working,its on http://localhost/testing i put .htacces in 'testing' directory under the htdocs LoadModule rewrite_module modules/mod_rewrite.so at apache/conf also already uncheck here my .htaccess RewriteEngine On RewriteBase /testing/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /testing/index.php/$1 [L] here my config $config['base_url'] = "http://localhost/testing"; $config['index_page'] = ''; $config['uri_protocol'] = 'AUTO'; when i access login controller, it's not found Not Found The requested URL /testing/login was not found on this server. I really don't know what to try next. Any help would be appreciated.

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  • Codeigniter passing variable to URL

    - by CyberJunkie
    I have a list of posts and an edit link for each. When clicking edit it goes to a page where I can edit the specific post I clicked on. For this I will have to pull from the db the id of the post. Would this be the correct way to do it? <a href="<?php echo site_url("post/edit/$row->id"); ?>">Edit</a> post is my controller, edit is my function, and $row->id should pull the id of the post.

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  • Add Form In Every Row with table helper Codeigniter

    - by wibi
    Hi i am creating table using table helper, but in every row i want to add form, in html like this : <table> <form action=""> <tr> <td><input type="text" name="name2"></td> </tr> </form> <form action=""> <tr> <td><input type="text" name="name2"></td> </tr> </form> </table> But i want in table helper: I have tried this one: $this->table->add_row( form_open('myAction'). form_input('name'.$i), form_submit('Submit') form_close() ); And I use firebugs to inspect element produces, like this: <table> <tr> <form action="myAction"> <td><input type="text" name="name1"></td> </form> <td><input type="submit"></td> </tr> </table> why tag doesn't show at the last tag , but show at the first tag . Thanks

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  • Reverse wildcard search in codeigniter

    - by Andy Platt
    I am implementing a snippet-based content management system into my current project. Snippets can be associated with a page either by exact match of the full url falling back to a wildcard match on a partial url or finally a default snippet. To implement this I have a created table of page associations with a wildcard flag, the system first checks the current url against the non-wildcard associations and if it doesn't find a match it checks against the partial url's where the wildcard flag is set. In order to achieve this I am getting all the partial url's from the database and putting them into an array then walking the array to check for a match against the current url: protected function _check_wildcard($url = NULL) { if($url) { $q = $this->db->where('wildcard' ,'Y') ->from('content') ->get(); $wildcards = $q->result_array(); foreach($wildcards AS $wildcard) { if(strpos($url,$wildcard['url']) > 0) { return $wildcard['snipppet_id']; } } } else { return NULL; } } Can anyone suggest a better way to do this - preferably one that doesn't involve having to constantly download the full list of all the wildcards each time I load a page as I am afraid that this will have a negative effect on the scalability of the system down the line?

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  • mysql codeigniter active record m:m deletion

    - by sea_1987
    Hi There, I have a table 2 tables that have a m:m relationship, what I can wanting is that when I delete a row from one of the tables I want the row in the joining table to be deleted as well, my sql is as follow, Table 1 CREATE TABLE IF NOT EXISTS `job_feed` ( `id` int(11) NOT NULL AUTO_INCREMENT, `body` text NOT NULL, `date_posted` int(10) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; Table 2 CREATE TABLE IF NOT EXISTS `job_feed_has_employer_details` ( `job_feed_id` int(11) NOT NULL, `employer_details_id` int(11) NOT NULL, PRIMARY KEY (`job_feed_id`,`employer_details_id`), KEY `fk_job_feed_has_employer_details_job_feed1` (`job_feed_id`), KEY `fk_job_feed_has_employer_details_employer_details1` (`employer_details_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; So what I am wanting to do is, if the a row is deleted from table1 and has an id of 1 I want the row in table to that also has that idea as part of the relationship also. I want to do this in keeping with codeigniters active record class I currently have this, public function deleteJobFeed($feed_id) { $this->db->where('id', $feed_id) ->delete('job_feed'); return $feed_id; }

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  • CodeIgniter subfolders and URI routing

    - by shummel7845
    I’ve read the manual on URI routing and views and something is not clicking with me. In my views folder, I have a subfolder called products. In there is a file called product_view. In my controller, I have: function index() { $data['title'] = 'Product Overview'; $data['main_content'] = 'products/product_view'; $this->load->view('templates/main.php', $data); } The template loads a header view, a footer view and a navigation view, plus the view as a main content variable. In my URI routing, I have: $route['products/product-overview'] = 'products/product_view']; This causes a 404 error when I try to go to domain.com/products/product-overview. Do I need to do something with my .htaccess? If so, what? Here is my .htaccess: Options +FollowSymLinks Options -Indexes DirectoryIndex index.php RewriteEngine on RewriteCond $1 !^(index\.php|resources|images|css|js|robots\.txt|favicon\.ico) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?/$1 [L,QSA] I’d appreciate some specific help, as the documentation isn’t specific on how to address this. I’ve done a little searching in the forums, and didn’t see anything, but I’m posting this while I keep looking.

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  • Displaying Data from a Join in Codeigniter

    - by Brad
    I am using a simple join to pull data from two databases. This is the join in the model function com_control(){ $this->db->select('*'); $this->db->from('comments'); $this->db->join('posts', 'comments.entry_id = posts.id'); $query = $this->db->get(); return $query->result; } My desired method of display is going to be in a table so I am starting out to use like this foreach($comm_control as $row){ $this->table->add_row( $row->entry_id, $row->comments.id, $row->comment, $row->title ); }//end of foreach My problem is the display of data from comments.id. What is the proper format to add the comment.id into the table rows? I need the ID from both tables for display, edit and delete further on in the table. The only display I get at this time for "comment.id" is the word id. The Any help would be appreciated.

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  • Codeigniter: State Machine how to

    - by Kevin Brown
    I created a db row called "activity_state" to denote which things a user has and hasn't completed. The problem is, I don't know how to use it... How can I use this single row to determine what a user has done? ie. have they completed their profile?, have they completed an assignment? Someone mentioned using it as a bitfield, but I'm unfamiliar with that. Is that a good idea? Any ideas?

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  • Multidimensional Array To Mysql Codeigniter

    - by rochellecanale
    A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

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  • Default Contoller in CodeIgniter

    - by gregavola
    I am wondering if there is any other configuration options for a default controller. For example - if I have a controller called "site" and I set the default controller in the following file: application/config/routes.php to: $route['default_controller'] = "site"; I should be able to go to http://localhost and that brings up the index(); function in the site controller. However, if I try to do go to http://localhost/index.php/index2 to load the index2(); function I get a 404 error. If I change the URL to http://localhost/index.php/site/index2 it works fine - but I thought already set the default controller. Is there any way around this?

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  • Codeigniter xss_clean dilemma

    - by Henson
    I know this question has been asked over and over again, but I still haven't found the perfect answer for my liking, so here it goes again... I've been reading lots and lots polarizing comments about CI's xss_filter. Basically majority says that it's bad. Can someone elaborate how it's bad, or at least give 1 most probable scenario where it can be exploited? I've looked at the security class in CI 2.1 and I think it's pretty good as it doesn't allow malicious strings like document.cookie, document.write, etc. If the site has basically non-html presentation, is it safe to use global xss_filter (or if it's REALLY affecting performance that much, use it on per form post basis) before inserting to database ? I've been reading about pros and cons about whether to escape on input/output with majority says that we should escape on output only. But then again, why allow strings like <a href="javascript:stealCookie()">Click Me</a> to be saved in the database at all? The one thing I don't like is javascript: and such will be converted to [removed]. Can I extend the CI's security core $_never_allowed_str arrays so that the never allowed strings return empty rather than [removed]. The best reasonable wrongdoing example of this I've read is if a user has password of javascript:123 it will be cleaned into [removed]123 which means string like this document.write123 will also pass as the user's password. Then again, what is the odds of that to happen and even if it happens, I can't think of any real harm that can do to the site. Thanks

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  • codeigniter and JSON

    - by ole
    Hello all i having a problem that it only get 1 value in my database and its my title and i want to show content and username from the same table to. here is my JSON kode <script type="text/javascript"> $.getJSON( 'ajax/forumThreads', function(data) { alert(data[0].overskrift); alert(data[0].indhold); } ); </script> my controller <?php class ajax extends Controller { function forumThreads() { $this->load->model('ajax_model'); $data['forum_list'] = $this->ajax_model->forumList(); if ($data['forum_list'] !== false) { echo json_encode($data['forum_list']); } } } my model fle <?php class ajax_model extends Model { function forumList() { $this->db->select('overskrift', 'indhold', 'brugernavn', 'dato'); $this->db->order_by('id', 'desc'); $this->db->limit(5); $forum_list = $this->db->get('forum_traad'); if($forum_list->num_rows() > 0) { return $forum_list->result_array(); } else { return false; } } }

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  • Codeigniter : database configuration

    - by nppCods
    I am beginner for CI so don’t have good knowledge. My problem is: I am not using any database. All the records are fetched from JSON. Therefore I don’t think I need to configure database… As said by CI, it doesn’t necessarily ask for database. So my database.php configuration is : $active_group = ‘default’; $active_record = FALSE; $db[‘default’][‘hostname’] = ‘’; $db[‘default’][‘username’] = ‘’; $db[‘default’][‘password’] = ‘’; $db[‘default’][‘database’] = ‘’; $db[‘default’][‘dbdriver’] = ‘mysql’; $db[‘default’][‘dbprefix’] = ‘’; $db[‘default’][‘pconnect’] = TRUE; $db[‘default’][‘db_debug’] = TRUE; $db[‘default’][‘cache_on’] = FALSE; $db[‘default’][‘cachedir’] = ‘’; $db[‘default’][‘char_set’] = ‘utf8’; $db[‘default’][‘dbcollat’] = ‘utf8_general_ci’; $db[‘default’][‘swap_pre’] = ‘’; $db[‘default’][‘autoinit’] = TRUE; $db[‘default’][‘stricton’] = FALSE; It works in my local system but doesn’t work in live server. I am so surprised. Then I provided hostname, username, password and dbdriver, it works. My question is that, is that necessary to provide all the details if I am not using database? Thank you for your suggestion.

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  • get value from database based on array in codeigniter

    - by Developer
    I have an array $user = array([0]=>1 [1]=>2 [2]=>3) which contains id's of certain users. I need to get the countries of these users from database. foreach($userid as $user){ $this->db->select('country'); $this->db->where('user_id',$user); $this->db->from('company'); $usercountry = $this->db->get(); $count = $usercountry->row(); $country = $count->country; } Suppose user1 has country ES, user2 has IN, user3 has US, user4 has UK. then if array contains 1,2,3. Then i need to get the countries ES,IN,US.

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  • update in codeigniter works but displays an error message

    - by Charmie
    i was just wondering what could be the problem with a working code yet displays an error message such as this: A PHP Error was encountered Severity: Notice Message: Array to string conversion Filename: database/DB_active_rec.php Line Number: 1407 im trying to update fields in my database. I have this code and every tutorial are just the same for batch upload. It works anyway but the thing is it display such an error. this what i have in my model: function update2($data){ $this->db->update_batch('users',$data, "id"); } This what i have in my controller: public function updateValues(){ $this->load->model('get_db'); $newRow = array( array( 'id' => '3', 'firstname' => 'Rapphie' ), array( 'id' => '2', 'firstname' => 'Charmie' ) ); $this->get_db->update2($newRow); echo "it has been updated"; } please help.

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  • Codeigniter: Using data in a controller

    - by Kevin Brown
    I'm new to php and CI, and I'm having some trouble in my controller. I feel that I'm doing this the wrong way, and it could be easier, I just don't know the syntax: $data['members'] = $this->home_model->getUser($id); $credit = $this->home_model->getCredit($id); if ($credit == '0'){stuff...} So I'm getting the user's data that has their the same information as "getCredit" does, but I don't know how to get the single variable that I need for my if statement... How can I just use the "getUser" function so that I'm not pulling redundant information?

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  • Codeigniter Active record help

    - by sea_1987
    Hello, I am trying to increment a INT column by 1 if a certain field is not null on an update request, currently I have this update too columns, public function updateCronDetails($transaction_reference, $flag, $log) { $data = array ( 'flag' => $flag, 'log' => "$log" ); $this->db->where('transaction_reference', $transaction_reference); $this->db->update('sy_cron', $data); } What I need to know is how I can check if the value being sent to the log field is NULL and if it is how could I increment a column called count by 1?

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  • empty() doesn't work with codeigniter input class

    - by BabyAzerty
    This is really weird. Whenever I call something like if(empty($this->input->post("foo")){//blabla} The whole PHP is "down" and I get a blank page from the website (even when I don't pass through this empty(input) line). I know this is not the right method and it is stupid, I change the code to if(!$this->input->post("foo")){//blabla} Better I guess ? Seriously, how come the empty(input) breaks down the entire PHP page ? (I can't get any echo "something").

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  • Restful client on Codeigniter issue

    - by user1852837
    This is weird. I don't know what is problem on my website. My website works on local server but not on live server. Login page works on first signin but after logout then re-login again message says: "invalid username and password" since it works on first attempt. I found out when I debugging that http://xxxxx.com/api/authentication/sign not found. It display 404 page not found. Sometimes you can login and sometimes not. In my local it works. I contact the web server admin and I ask what is the status of the session on the server and How does it execute it's web requests? (Sockets, file_get_contents, curl?). They said that No problems reproduced with Server Sessions and PHP Curl works fine. I know it's weird but can somebody here can figure it out what is the problem behind of it.

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